After 11,460 years, half of the remaining 6 grams will have decayed, leaving 3 grams, and after 17,190 years, half of the remaining 3 grams will have decayed, leaving 1.5 grams. Over time, the number of radioactive atoms in a sample will decrease as they decay into more stable elements.
What is meant by half life of a substance?The half-life of a radioactive substance is the amount of time it takes for half of the initial amount of radioactive atoms to decay. Over time, the amount of radioactive atoms in a sample will decrease.
Why is radioactive dating useful?Radioactive dating is a useful tool for scientists to determine the age of rocks, fossils, and other materials by measuring the amount of radioactive isotopes and their decay products in the sample. This helps them to learn more about the history of the earth.
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what is the relation between the conic definition and the points definition of a parabola
It is the line on a parabola whose distance from any point is equal to the distance from that point to the focus.
It is the line whose distance from any point on the conic makes a constant ratio with the distance between that point and the focus when the conic is defined in polar terms.
What is parabola?
A parabola is an approximately U-shaped, mirror-symmetrical plane curve in mathematics.
It corresponds to a number of seemingly unrelated mathematical descriptions, all of which can be shown to define the same curves. A parabola can be described using a point and a line.
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which one of the following is part of the basic physical movements of a job?
The cost of staffing work schedules is a topic covered by the economics subfield of ergonomics. An operations chart, often known as a right-hand/left-hand chart, highlights unnecessary movement and downtime.
Employees' working conditions may impact their quality of life, but it has little bearing on how well they perform or how safe they are.
Extent flexibility is the type of flexibility required when a profession necessitates extremely wide motions.
In jobs dispersed over longer time periods, extent flexibility is essential whereas dynamic flexibility is needed for shorter time periods.
Simple movements, using movement as the main method in physical education.
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there are five different common overcurrent protection trip types that a circuit breaker may incorporate. which type is intended for overcurrents that can persist for many seconds to minutes without damaging the conductors or electrical equipment and is considered overload and low-level fault protection?
Overcurrent refers to a sudden and rapid increase in current over a short period of time (also known as a short circuit or ground fault) (fractions of a second).
Fuse or circuit breakers are used to safeguard equipment and circuits from overcurrent conditions.
The current value is much higher than the nominal line current and can range from six times to hundreds of times higher than the typical rated current value.
Thermal energy: High current levels generate a lot of heat, which can harm cables and equipment. I2t (current squared times time) can be used to express thermal energy;
Mechanical forces: Busbars and other equipment may become warped or experience other issues due to the high-fault currents' ability to produce strong magnetic fields.
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A mass M is split into two parts m and (M−m), which are, then separated by a certain distance. The ratio m/M which maximizes the gravitational force between the parts isA. 1:4B. 1:3C. 1:2D. 1:1
The ratio of m/M which maximizes the gravitational force between the parts is calculated to be 1:2.
A mass is split into two parts, m and (M - m).
Let the distance by which they are separated is r.
The gravitational force between two parts is given by,
F = G m (M - m)/r²
To get the maximum value of gravitational force, we should differentiate F.
dF/dm = 0
d/dm [G m (M - m)/r²] = 0
d/dm (mM - m²) = 0
M - 2m = 0
m = M/2
m:M = 1:2
Thus, the force between them is maximum when the ratio between m and M is 1:2.
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f the spring constant is 200 n/m and applied force is -50 n, how much will the spring be stretched or displaced?
The spring will be stretched or displaced by -0.25 m. A negative displacement indicates that the spring is being compressed rather than stretched.
The amount of displacement, x, of a spring can be calculated using the equation:
x = F / k
where k is the spring constant and F is the applied force. In this case, the applied force is -50 N and the spring constant is 200 N/m. Plugging in the values, we get:
x = -50 N / 200 N/m = -0.25 m
The equation used to calculate the displacement of a spring is based on Hooke's Law, which states that the force required to stretch or compress a spring is proportional to the amount of displacement.
The proportionality constant, k, is called the spring constant, and it is unique to each spring and determines the stiffness of the spring. The higher the spring constant, the more force is required to produce a given amount of displacement.
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when charging the guide block sphere, why do we have to remove our finger before removing the charged rod? in other words, would the sphere be charged if we removed the rod before removing our finger? why or why not?
Answer:
if the finger were removed "after" removing the charged rod then any charge due to the charged rod will be removed by the finger, and there will be no net charge on the sphere.
What is missing from the graph? consistent intervals grid lines variables a best-fit line
A best-fit line is missing from the graph above.
About GraphicsThe definition of graphics is a combination of numbers, letters, symbols, pictures, symbols, sayings, paintings, which are presented in one medium to convey concepts and ideas from the sender to the target in the process of conveying information.
There is also another understanding of graphics, which is a framework for forming table visualization objects. Tables consisting of numbers can be presented or can be displayed in the form of images, can be in the form of lines, circles, bars etc.
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Consider the parallel reactions shown below. The activation energies are 45.3 kJ mol-1 for k1 and 69.8 kJ mol-1 for k2. If the rate constants are equal at 320 K, at what temperature will k1/k2 =2.00?
The required temperature at which the ratio of rate constants become two is 298 K.
The Arrhenius equation for changing A into B is as follows:
k₁ = A₁ e⁻^(Ea)₁/RT
The equation becomes for converting A to C is,
k₂ = A₂ e⁻^(Ea)₂/RT
These equations allow for the following expression for the ratio of rate constants of the parallel reactions,
k₁/ k₂ = A₁ e⁻^[(Ea)₁/RT]/A₂ e⁻^[(Ea)₂/RT] = A₁/A₂ e^[(Ea)₂ - (Ea)₁]/RT
Substituting the known values in the ratio, we get,
k₁/ k₂ = A₁/A₂ e^[(Ea)₂ - (Ea)₁]/RT = A₁/A₂ e^[69.8 × 10³- 45.3 × 10³]/8.314 T
⇒ A₁/A₂ e^ (2.95 × 10³/T)
The rate constants are equal when the reaction is carried out at 350 K. Therefore, the ratio of rate constants becomes one.
Now, the equation can be given as,
1 = A₁/A₂ e^ (2.95 × 10³/320)
1 = A₁/A₂ e^9.21
1 = A₁/A₂ (9.985 × 10³)
A₁/A₂ = 1/(9.985 × 10³) = 1.001 × 10⁻⁴
The temperature at which the rate constant (K) ratio becomes 2 can be calculated as,
2 = (1.001 × 10⁻⁴) e^(2.95 × 10³/T)
e^(2.95 × 10³/T) = 1.997 × 10⁴
Therefore, 2.95 × 10³/T = ln(1.997 × 10⁴) = 9.902
The temperature (T) at which the ratio becomes 2 can be calculated as,
T = 2.95 × 10³/9.902 = 297.6 K ≈ 298 K
Thus, the temperature at which the ratio of rate constants becomes two is 298 K.
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The adiabatic approximation makes which assumption?
1. The particles do not move from near the peaks towards the bottom of pressure waves.
2. The temperature is the same in a trough as in a peak of a pressure wave.
3. No energy is exchanged between the particle in the trough and particle at the peak of a pressure wave.
With a brief explanation please.
The adiabatic approximation makes assumption of option 3. No energy is exchanged between the particle in the trough and particle at the peak of a pressure wave.
The term "adiabatic approximation" in quantum mechanics relates to Schrödinger equation responses that utilize a time-scale distinction between fast and slow levels of freedom and use this to identify approximations as product states in the fast and slow levels of freedom.
Energy, which is observable in the execution of labour as well as in the form of heat and light, is the quantitative quality that is transmitted to a body or to a physical system in physics.
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what is the vapor pressure of sicl4 in mmhg at 30.0 ∘c ? the vapor pressure of sicl4 is 100 mmhg at 5.4 ∘c , and δhvap = 30.2 kj/mol .
Using the Clausius-Clapeyron equation, at 30°C, the vapor pressure of SiCl4 was found to be 205.4 mmHg.
The Clausius-Clapeyron equation can be used to describe the effect of temperature on the vapor pressure of a volatile compound. The heat of vaporization must be known in order to use the Clausius-Clapeyron equation. The Clausius-Clapeyron equation is shown in the attached picture.
According to question:-
T1 = 5.4 ∘c = 278.55 K
P1 = 100 mmHg
T2 = 30.0 ∘c = 303 K
δHvap = 30.2 kj/mol = 30200 J/mol
Also, we know that R (gas constant) = 8.314 J/mol-K
This is a straightforward application of the Clausius-Clapeyron equation to determine the vapor pressure of a compound at various temperatures. We can rewrite the equation to get: P2 = P1 . eˣ
where x = δHvap/R [1/T1 - 1/T2]
Hence, we get, x = 30200/8.314 [1/278.55 - 1/303]
x = 3632.42 [0.0035 - 0.0033]
x = 3632.42 [0.0002]
x = 0.726
Putting this value in modified Clausius-Clapeyron equation :
P2 = P1 . e⁰·⁷²⁶
P2 = 100 . e⁰·⁷²⁶
P2 = 100 x 2.054
P2 = 205.4 mmHg
Hence, at 30°C, the vapor pressure of SiCl4 is 205.4 mmHg.
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4x consider the differential equation with initial condition . a. use euler's method with two steps to estimate when : (be sure not to round your calculations at each step!) now use four steps: (be sure not to round your calculations at each step!) b. what is the solution to this differential equation (with the given initial condition)? c. what is the magnitude of the error in the two euler approximations you found? magnitude of error in euler with 2 steps
At two steps the approximate solution is 3.25, and after four steps, it is 4.5
To find an approximate solution to the given differential equation with the given initial condition, you can use Euler's method with two steps.
At t = 2, the approximate solution is 3.25, and after four steps, it is 4.5. The difference between the two estimates, which is 1.25, would reflect the size of the mistake in the two Euler approximations you discovered.
The idea of numerical errors must be understood in order to fully investigate Euler's method. Numerical mistakes happen during the numerical solution of a differential equation when the approximate solution is not sufficiently close to the genuine solution. Numerous variables, such as the chosen numerical approach, the number of steps executed, the step size, and the precision of the beginning circumstances, might contribute to these inaccuracies.
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Let's say that the total energy of the skater is 100 J. a. If Potential Energy at the top of the ramp is 100 J, how much Kinetic energy does the skater have?
Answer:
At a start, the potential energy = mgh and kinetic energy = zero because its velocity is zero. Total energy of the object = mgh. As it falls, its potential energy will change into kinetic energy. If v is the velocity of the object at a given instant, the kinetic energy = 1/2mv2.
Have a Nice Day.
A ball thrown straight up takes 2.25 s to reach a height of 36.8 m (a) What was the initial speed? b What is its speed at this height? (c) How much higher will the ball go?
The balls initial speed is 27.3 and final speed is zero and the height till which ball has gone is 38m.
Ball height at a specific time, x = 36.8m.
The ball's height-achieving time was 2.25 seconds.
Gravitational acceleration is 9.8[tex]\frac{m}{s^{2} }[/tex], or g.
Let's assume that [tex]v_{o}[/tex] represents the ball's starting speed. The height x with time t and initial speed [tex]v_{o}[/tex] can be related using the equation of kinematics as follows:
[tex]s=ut+\frac{1}{2}at^{2}[/tex]
The ball will decelerate so that it acts in the opposite direction to that with initial velocity since it is moving upward under the influence of gravity. This deceleration will be equivalent to the size of the acceleration caused by gravity.
Consequently, a = -g.
If we suppose that the ball was thrown upward at time t = 0, then [tex]x_{o}[/tex] = 0. Replace the starting circumstances and the the following supplied values in the equation above:
[tex]36.8=u(2.25)+\frac{1}{2}(-g)2.25^{2}[/tex]
Therefore, on solving we get
u=27.3[tex]\frac{m}{s}[/tex]
The ball's final speed (v) is zero when it reaches the highest point, let's say h. The greatest height can be calculated using the same initial speed, v0, as follows:
We have the kinematics equation as
[tex]v^{2} -v_{o} ^{2} =2ax[/tex]
Where v denotes the object's end speed, a denotes its acceleration, [tex]v_{o}[/tex] denotes the object's starting speed, and t is the study period.
The ball's maximum height is reached when x = h, v = 0 m/s, and a = -g.
Replace the specified numbers in the aforementioned equation to obtain
[tex]h=\frac{0-27.3}{-2g}[/tex]
On solving we get, h=38m
As a result, the ball soars to a height of 38 m.
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A 13,735.85 W crane raised a crate in 172.95 s. How much work did the crane do?
The work that have been done by the crane is 2.4 MJ.
What is the work done?We have to note that the work that has been done is the same as the energy. That we say that the work and the energy are dimensionally equivalent. The statement that I have just made here is going to guide us in the question that we want to solve here.
Thus we know that;
Energy = Work = power * time
This is so because we define the power as the rate of doing work.
Thus we have the work as; 13,735.85 W * 172.95 s
= 2.4 MJ
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=
a system of two wheels fixed to each other is free to rotate about a frictionless axis through the common center of the wheels and perpendicular to the page. four forces are exerted tangentially to the rims of the wheels, as shown below what is the magnitude of the net torque on the system about the axis? select all that apply
The torque on the system of two wheels fixed to each other rotated about the frictionless axis is 2FR.
The force that can cause an object to rotate along an axis is measured as torque. There are four forces shown in the diagram. The forces on the outer wheel of radius 3R are, 2F, F, and F. And the forces on the inner wheel of radius 2R are F.
To calculate the total torque, calculate the torque due to each force and add the values. Use the formula, [tex]\tau = \vec{R} \times \vec{F}[/tex].
[tex]\tau = (3R)(2F)(\hat{j} \times \hat{i}) + (3R)(F)(-\hat{i} \times -\hat{j}) + (3R)(F)(-\hat{j} \times \hat{i}) + (2R)(F)(-\hat{j} \times \hat{i})\\\tau = -(6RF)\hat{k} + (3RF)\hat{k} + (3RF)\hat{k} + (2RF)\hat{k} \\\tau = 2RF\hat{k}[/tex]
The magnitude of torque is, 2FR in the z-direction.
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the racer continues at this velocity to the finish line. if he was 300 m from the finish line when he started to accelerate, how much time (in s) did he save
The amount of time that the racer saved by the acceleration is 5.27 s.
From the question, we are given that Initial velocity = 11.5 m/s, Acceleration rate = 0.5 m/s², and Time = 7s.
First, calculate the final velocity of the racer using the equation of motion:
v = u + a * t
v = 11.5 + 0.5 * 7 = 15 m/s
Use the formula as follows to calculate the distance :
s = v * t + 1/2 * a * t²
s = 11.5 * 7 + 1/2 * 0.5 * 7²
s = 92.75 m
Then calculate the distance traveled by the racer with the final velocity:
d = 300 - 92.75
= 207.25 m
After that, calculate the time spent traveling the 207.25m distance:
t = 207.25 / 15 = 13.82 s
And the total time spent traveling the whole 300 m distance:
t = 7 + 13.82 = 20.82 s
From here, we can calculate the time required to travel 300m with the initial velocity:
t0 = d / v0
t0 = 300 / 11.5 = 26.09 s
Therefore, the amount of time saved due to acceleration is:
t = 26.09 - 20.82
t = 5.27 s
Your question seems to be incomplete. The completed version is most likely as follows:
A bicycle racer sprints at the end of a race to clinch a victory. The racer has an initial velocity of 11.5 m/s and accelerates at the rate of 0.500 m/s2 for 7.00 s. The racer continues at this velocity to the finish line. If he was 300 m from the finish line when he started to accelerate, how much time did he save?
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galileo's contributions to astronomy included group of answer choices discovering the laws of planetary motion discovering the law of gravity making observations and conducting experiments that dispelled scientific objections to the sun-centered model. sending a spacecraft to jupiter.
Galelio's contribution to astronomy is to make observations and experiments that overcome scientific objections to the heliocentric model.
Galileo's telescopic discoveries helped prove that the Sun was the center of the solar system, not the Earth. His observations strongly supported the heliocentric model previously proposed by astronomers such as Nicolaus Copernicus. Heliocentricity (also called the heliocentric model) is an astronomical model in which the Earth and planets revolve around the Sun at the center of the universe. Historically, heliocentrism contrasted with geocentrism, which places the earth at the center. He had discovered that the Sun has dark-colored spots which are called sunspots.
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In one hour, 500x10^3 ft-lbr of work is done. What is the average power in kilowatts? Please answer these nroblems showing each sten in how to solve them
In one hour, 500x10^3 ft-lbr of work is done. 0.189 kW is the average power in kilowatts.
To find the average power in kilowatts when 500,000 ft-lbf of work is done in one hour, we'll first convert the work from foot-pounds to joules and then use that value to find the average power in kilowatts.
= 1 ft-lb
= 1.356 J
500,000 ft-lbf of work is equivalent to:-
= 500,000 ft-lbf x 1.356 J/ft-lb
= 678,000 J
Now, we'll use this value to find the average power in kilowatts:
= (work,J) ÷ (time,s)
= (average power in watts)
= 1 hr = 3600 sec,
= 678,000 J / 3600 seconds
= 189 W
Finally, we'll convert the average power in watts to kilowatts:
= (average power in W) / 1000
= (average power in kW)
= 189 W / 1000
= 0.189 kW
Hence, the average power in kilowatts when 500,000 ft-lbf of work is done in one hour is 0.189 kW.
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If the local government in Parksville, British Columbia, decided to put on a public Canada Day parade, how would the parade be classified?A) a public goodB) rival in consumptionc) a common resourced) excludable
The Canada Day parade organized by the local government in Parksville, British Columbia would likely be classified as a public good.
The Canada Day parade organized by the local government in Parksville, British Columbia provides a valuable public service. It is a non-excludable and non-rivalrous good that can benefit all members of the community. As a non-excludable good, everyone is free to take part in the parade regardless of their ability to pay.
Similarly, it is a non-rivalrous good, which means that one person's consumption does not reduce the amount available for another. In this way, the Canada Day parade serves as an excellent example of a public good.
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what will h be for water at 20°c if w = 0.5 mm?
The capillary height change h can be calculated as h = 2Ycos(θ) / (ρg), so the h will be 30mm.
Consider the balance of forces operating on a fluid in a narrow cylindrical tube to calculate the capillary height change h. The surface tension of the fluid, represented by Y, operates at the fluid-air contact to reduce the fluid's surface area. The force of gravity, denoted by [tex]\rho gh[/tex], acts downward and attempts to increase the volume of the fluid. The contact angle, denoted by [tex]\theta[/tex], is the angle formed by the liquid-air interface and the solid surface.
The equation for the capillary height change is [tex]h=\frac{2Ycos\theta}{\rho g}[/tex],
For water at 20°c, Y≈0.0728 N/m, [tex]\rho g \approx 9790[/tex] [tex]N/m^{3}[/tex], and [tex]\theta \approx 0^\circ[/tex].
Thus, for W = 0.5 mm, then the capillary height change h can be found by multiplying the above result by [tex]\frac{W}{2}[/tex].
[tex]h = \frac{{2(0.728N/m)\cos \theta ^\circ }}{{(9790N/{m^3})(0.0005m)}} \approx 0.030m \approx 30mm[/tex]
Hence, h will be 30mm.
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The given question is incorrect. The correct question is given as:
Derive an expression for the capillary height change h, as shown, for a fluid of surface tension Y and contact angle [tex]\theta[/tex] between two parallel plates W apart. Evaluate h for water at 20°c if W = 0.5 mm.
you apply a constant horizontal force (directed to the right) on the left cylinder. let a be the acceleration you give to the system. for what range of a will all three cylinders remain in contact with each other?
The range of acceleration (a) for which all three cylinders will remain in contact with each other is determined by the maximum and minimum static friction forces between the cylinders.
The maximum static friction force between two cylinders is given by the formula:
f_max = μ_s * N
where μ_s is the coefficient of static grating between the two surfaces and N is the typical power following up on the chambers (equivalent to the gravitational power following up on every chamber). Assuming that the even power applied on the left chamber is more prominent than the most extreme static grating power between any two chambers, they will begin to slide on one another, and the framework won't stay in touch. Consequently, the speed increase ought to be to such an extent that:
f_max >= m * a
where m is the all out mass of the framework. Settling for a, we get:
a <= μ_s * g
where g is the speed increase because of gravity. Subsequently, the scope of speed increase (a) for which every one of the three chambers will keep in touch with one another is from 0 to μ_s * g.
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if i have two charges, both positive, what happens to the net potential energy if i bring in a 3rd equal charge to form an equilateral triangle?
The net potential energy decreases when a third equal positive charge is brought in to form an equilateral triangle with the two original charges because the charges are now closer to each other, reducing their potential energy due to their repulsive electrostatic force.
When two positive charges are brought close to each other, the net potential energy between them increases due to their repulsive electrostatic force. However, when a third equal positive charge is introduced and they form an equilateral triangle, the net potential energy decreases.
This happens because the charges are now more evenly distributed and the repulsive forces between them are reduced. As a result, the total potential energy of the system decreases, which is a measure of the work required to bring the charges to their current positions. To put it simply, the equilateral arrangement of the charges reduces the overall repulsion between them, leading to a decrease in potential energy.
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mr kim is driving in his tesla at a velocity of 20m/s. he then slams the accelerator and hits a velocity of 80m/s. by what factor has mr. kim and his tesla changed their kinetic energy?
Answer: The kinetic energy has increased 16 times.
Explanation:
Kinetic energy is the energy of an object in motion, and is calculated using the formula: kinetic energy = 1/2 * mass * velocity^2.
When Mr. Kim's Tesla was traveling at a velocity of 20 m/s, its kinetic energy was: 1/2 * mass * 20^2 = 1/2 * mass * 400 = 200 * mass joules.
When he accelerated to a velocity of 80 m/s, the kinetic energy of the Tesla increased to: 1/2 * mass * 80^2 = 1/2 * mass * 6400 = 3200 * mass joules.
To find the factor by which the kinetic energy has changed, we can divide the final kinetic energy by the initial kinetic energy:
3200 * mass joules / 200 * mass joules = 16.
Therefore, Mr. Kim and his Tesla have changed their kinetic energy by a factor of 16. This means that the kinetic energy has increased 16 times.
At a location where g = 9.80 m/s2, an object is thrown vertically down with an initial speed of 1.00 m/s. after 5.00 s the object will have traveled:
The distance travelled by the object with a given initial speed is calculated to be 0.05 m.
The initial speed u is given as 1 m/s
Acceleration due to gravity g is taken as 9.8 m/s²
After 5 s, the distance travelled by the object = ?
Time t = 5 s
The object's final velocity, v, is zero.
From the equations of motion, let us find out the distance travelled by the object.
v² - u² = 2 a s
0 - 1² = 2 × 9.8 × s
19.6 s = -1
s = - 0.05 m
The negative sign represents the opposite direction.
Thus, the distance travelled is 0.05 m.
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describe the processes occurring in a nebula and explain why rocky planets are formed closer to the center of the solar system.
The processes occurring in a nebula include gravitational collapse, fragmentation, and accretion. Rocky planets, such as Earth, are formed closer to the center of the solar system because the temperature in the inner regions is high.
A nebula is a cloud of gas and dust in space where stars and planets are formed.
Gravitational collapse refers to the contraction of a cloud of gas and dust under its own gravity, which causes the material to become denser and hotter. This process leads to the formation of a dense core, known as a protostar.
Rocky planets, such as Earth, are formed closer to the center of the solar system because the temperature in the inner regions is higher, allowing the metals and silicates that make up rocky planets to condense and form solid bodies. In contrast, the outer regions are cooler and dominated by lighter elements, such as hydrogen and helium, which form gas giants like Jupiter. This is why the inner region of the solar system is dominated by rocky planets and the outer region by gas giants.
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prisms are capable of separating white light into separate colors because: prisms are capable of separating white light into separate colors because: a. the material used has a low refractive index. b. the material used is dispersive. c. the prism has a specific shape. both a
Prisms are capable of separating white light into separate colors. prisms are capable of separating white light into separate colors. a and b options are correct. The options are a. the material used has a low refractive index. b. the material used is dispersive.
The separation of white light into its component colors is called refraction, and it occurs because the different colors of light are bent at different angles as they pass through the prism. This is due to the fact that different colors of light have different wavelengths, and therefore different refractive indices, so they bend differently as they pass through the prism. The material used for the prism, being dispersive, exacerbates this effect, which leads to the separation of the colors of light. The specific shape of the prism is also important, as it determines how much refraction occurs and how the light is separated.
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A 77 g piece of ice at 0° C is placed in a beaker containing 545 g of water at 82° C. Assuming all the ice melts and disregarding the beaker, what is the final temperature of the mixture
Water contains almost one thousand times more matter than the same volume of air would ... The density of sodium metal at 0oC is 0.968g/cm3 , and 968kg/m3 .
what is the final temperature of the mixture?
If a mixture is having the same substance of the same mass then the mean of two temperatures is said to be the final temperature.Calculate the final temperature of the water mixture using the equation T(final) = (m1_T1 + m2_T2) / (m1 + m2), where m1 and m2 are the weights of the water in the first and second containers, T1 is the temperature of the water in the first container and T2 is the temperature of the water in the second container.The thermal energy of the warm water is not enough to melt all of the ice (only 93% of it), so the final temperature of the ice/water mixture will be 0ºC.Add the change in temperature to your substance's original temperature to find its final heat. For example, if your water was initially at 24 degrees Celsius, its final temperature would be: 24 + 6, or 30 degrees Celsius.
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3.96 A tank contains 2 m? of air at -93°C and a gage pressure of 1.4 MPa. Determine the mass of air, in kg. The local atmospheric pressure is 1 atm. use the compressibility chart
The mass of air is 58.110kg for a tank containing 2 m³ of air at -93°C and a gauge pressure of 1.4 MPa.
The ideal gas law equation is given below:
PV = nRT
where P is the absolute pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the absolute temperature.
Given: the volume of the tank, V = 2 m³
temperature of the air in the tank, T = -93°C
T = 273 - 93 K
T = 180K
Gauge pressure, P1 = 1.4 MPa.
Atmospheric pressure, P2 = 1 atm
1 atm = 101.325 kPa
P2 = 0.101 MPa
total pressure P = P1 + P2
P = 1.4 + 0.101
P = 1.501 MPa
Using the ideal gas equation,
PV = nRT
n = PV/RT
n = 1.501 MPa × 2 / 8.314 × 180
n = 2005.9 mol
mass of air = n × molar mass of air
mass of air = 2005.9 × 28.97 g/mol
mass of air = 58.110 kg
Therefore, the mass of air is 58.110kg.
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Conduct online research to learn about new developments in forensic science and the scientists responsible for these developments. This can include new methods, technology, instruments, and so on.
New advancements in forensic science and the scientists responsible for these advancements are detailed below.
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An engine raises 100kg of water through a height of 60m in 20secs.What is the power of the engine
