Answer: 2.79 hours.
Step-by-step explanation:
Given that the function for the learning process is T(x) = 2 + 0.3 1 x , where T(x) is the time, in hours, required to produce the xth unit
To calculate the time for the new worker to produce 10 units, substitute 10 for x in the equation above.
T(x) = 2 + 0.31 (10)
T(x) = 2 + 3.1
T(x) = 5.1 hours
To calculate the time for the new worker to produce 19 units, substitute 19 for x in the equation above.
T(x) = 2 + 0.31(19)
T(x) = 2 + 5.89
T(x) = 7.89 hours
The time required for a new worker to produce units 10 through 19 will be
7.89 - 5.1 = 2.79 hours
The upper-left coordinates on a rectangle are (-1,4), and the upper-right coordinates are (3,4). The rectangle
has a perimeter of 24 units.
Draw the rectangle on the coordinate plane below.
Answer:
Step-by-step explanation:
Note that the perimeter of a rectangle P = 2(Length + Breadth)
The distance between the upper-left coordinates on a rectangle and the upper-right coordinates is the breadth of the rectangle. To get the breadth of the rectangle, we will use tgw formula for calculating the distance between two points as shown.
D = √(y2-y1)²+(x2-x1)²
Given the coordinates (-1,4) and (3,4), the distance between the coordinates where x1 = -1, y1 = 4, x2 = 3 and y2 = 4 will be expressed as.
B = √(4-4)²+(3-(-1))²
B = √0+4²
B = √16
B = 4
Hence the breadth of the rectangle is 4 units.
Substituting the breadth into the formula for calculating the perimeter will give;
P = 2(L+B)
24 = 2(L+4)
L+4 = 24/2
L+4 =12
L = 12-4
L = 8
Hence the length of the rectangle is 8 units.
The diagram of the rectangle on a coordinate is as given in the attachment below.
Question: The hypotenuse of a right triangle has a length of 14 units and a side that is 9 units long. Which equation can be used to find the length of the remaining side?
Answer:
The hypotenuse is the longest side in a triangle.
a^2=b^2+c^2.
14^2=9^2+c^2.
c^2=196-81.
c^2=115.
c=√115.
c=10.72~11cm
Find the surface area of the triangular prism.
Answer:
169 [tex]cm^{2}[/tex]
Step-by-step explanation:
Surface area (SA) = 2B + PH
SA = 2 ([tex]\frac{1}{2}[/tex] x 9 x 6) + (7+7+9) 5
= 2 (27) + (23) 5
= 54 + 115
SA = 169 [tex]cm^{2}[/tex]
which graph shows a reflection across the line Y = X
Answer:
B
Step-by-step explanation:
"A" is not a reflection, it looks like a translation.
"C" is not a reflection, it is a rotation.
So, B is a reflection.
Answer:
[tex]\large \boxed{\mathrm{Graph \ C}}[/tex]
Step-by-step explanation:
The reflection is across the line y = x.
All options show reflection. Option C shows reflection across the line y = x.
In the reflection, the points on the triangle will also be reflected.
Point S is reflected across the line y=x, the reflected point is S’.
Point R is reflected across the line y=x, the reflected point is R’.
Point Q is reflected across the line y=x, the reflected point is Q’.
Select the correct answer. If , which statement is true? if g(x) = f(1/3x)
A. The graph of function f is stretched vertically by a scale factor of 3 to create the graph of function g.
B. The graph of function f is stretched horizontally by a scale factor of 3 to create the graph of function g.
C. The graph of function f is compressed horizontally by a scale factor of to create the graph of function g.
D. The graph of function f is compressed vertically by a scale factor of to create the graph of function g.
Answer:
B. The graph of function f is stretched horizontally by a scale factor of 3 to create the graph of function g.
Step-by-step explanation:
The rules for linear transformations are that
g(x) = a·f(b·(x-c)) +d
stretches the graph vertically by a factor of "a" (before the shift)
compresses the graph horizontally by a factor of "b" (before the shift)
shifts it to the right by amount "c"
shifts it up by amount "d".
Your equation has b=1/3, so the graph is compressed by a factor of 1/3, which is equivalent to a stretch by a factor of 3.
The appropriate choice of description is ...
b) the graph of g(x) is horizontally stretched by a factor of 3
Answer:
B
Step-by-step explanation:
Correct on Plato
Solve the equation for x. √x+5-3=4
Answer:
x=4
Step-by-step explanation:
To solve for x, we must get x by itself on one side of the equation.
[tex]\sqrt{x} +5-3=4[/tex]
First, we can combine like terms on the left side. Subtract 3 from 5.
[tex]\sqrt{x} +(5-3)=4[/tex]
[tex]\sqrt{x} +2=4[/tex]
2 is being added on to the square root of x. The inverse of addition is subtraction. Subtract 2 from both sides of the equation.
[tex]\sqrt{x} +2-2=4-2[/tex]
[tex]\sqrt{x} = 4-2[/tex]
[tex]\sqrt{x} =2[/tex]
The square root of x is being taken. The inverse of a square root is a square. Square both sides of the equation.
[tex](\sqrt{x} )^{2} =2^2[/tex]
[tex]x=2^2[/tex]
Evaluate the exponent.
2^2= 2*2 =4
[tex]x=4[/tex]
Let's check our solution. Plug 4 in for x and solve.
[tex]\sqrt{x} +5-3=4[/tex]
[tex]\sqrt{4} +5-3=4[/tex]
[tex]2+5-3=4[/tex]
[tex]7-3=4[/tex]
[tex]4=4[/tex]
Our solution checks out, so we know x=4 is correct.
Ajar contains 4 red marbles numbered 1 to 4 and 10 blue marbles numbered 1 to 10. A marble is
drawn at random from the jar. Find the probability of the given event.
(a) The marble is red
Your answer is:
(b) The marble is odd-numbered
Your answer is:
(C) The marble is red or odd-numbered
Your answer is:
(d) The marble is blue or even-numbered
Your answer is:
Question Help M Message instructor
Answer:
a)2/7
b)1/2
c)9/14
d)6/7
Step-by-step explanation:
The jar contains 4 red marbles, numbered 1 to 4 which means
Red marbles = (R1) , (R2) , (R3) , (R4)
It also contains 10 blue marbles numbered 1 to 10 which means
Blue marbles = (B1) , (B2) , (B3) , (B4) , (B5) , (B6) , (B7) , (B8) , (B9) , (B10) .
We can calculate total marbles = 4red +10 blues
=14marbled
Therefore, total marbles= 14
The marbles that has even number = (R2) , (R4) ,(B2) , (B4) , (B6) , (B8) , (B10) =7
Total number of Blue marbles = 10
Blue and even marbles = 5
(a) The marble is red
P(The marble is red)=total number of red marbles/Total number of marbles
=4/14
=2/7
(b) The marble is odd-numbered
Blue marbles with odd number= (B1) , (B3) , (B5) , (B7) , (B9) ,
Red marbles with odd number = (R1) , (R3)
Number of odd numbered =(5+2)=7
P(marble is odd-numbered )= Number of odd numbered/ Total number of marbles
P(marble is odd-numbered )=7/14
=1/2
(C) The marble is red or odd-numbered?
Total number of red marbles = 14
Number of red and odd marbles = 2
The marbles that has odd number = (R1) , (R3) ,(B1) , (B3) , (B5) , (B7) , (B9) =7
n(red or even )= n(red) + n(odd)- n(red and odd)
=4+7-2
=9
P(red or odd numbered)= (number of red or odd)/(total number of the marble)
= 9/14
(d) The marble is blue or even-numbered?
Number of Blue and even marbles = 5
Total number of Blue marbles = 10
Number of blue that are even= 5
The marbles that has even number = (R2) , (R4) ,(B2) , (B4) , (B6) , (B8) , (B10)
=7
n(Blue or even )= n(Blue) + n(even)- n(Blue and even)
= 10+7-5 =12
Now , the probability the marble is blue or even numbered can be calculated as
P(blue or even numbered)= (number of Blue or even)/(total number of the marble)
= 12/14
= 6/7
classify the following triangle
Charlie needs a $275,000 mortgage and he'd like to pay it off in 30 years. He is considering two banks. Bank A: 3.5% with monthly payments of $1234.87 Bank B: 4% with monthly payments of $1312.89 Charlie doesn't think a 0.5% difference is that much. What is the difference between these two bank loans with total interest paid over the life of the loan?
Answer:
Difference in interest= $41,250
Step-by-step explanation:
To calculate the interest paid on each bank loan we use the following formula
Interest = Principal * Rate * Time
For Bank A
Interest = 275,000 * 0.035 * 30
Interest = $288,750
For Bank B
Interest = 275,000 * 0.04 * 30
Interest = $330,000
Therefore
Difference in interest= 330,000 - 288,750
Difference in interest= $41,250
Therefore if the mortgage is taken from Bank B he will pay an extra $41,250 on the loan.
The 0.5% difference in rates has a large impact over the 30 year term loan
The denominator of a fraction is 30 more than the numerator. The value of the fraction is 3/5. Find the fraction.
Answer:
45
------
75
Step-by-step explanation:
Let x be the value of the numerator and x+30 be the value of the denominator
This is equal to 3/5
x 3
-------- = -------
x+30 5
Using cross products
5x = 3(x+30)
Distribute
5x = 3x+90
Subtract 3x from each side
2x = 90
Divide by 2
x = 45
The fraction is
45
-----
30+45
45
------
75
[tex]\dfrac{x}{x+30}=\dfrac{3}{5}\\\\5x=3(x+30)\\5x=3x+90\\2x=90\\x=45\\\\\dfrac{x}{x+30}=\dfrac{45}{45+30}=\dfrac{45}{75}[/tex]
HELP ASAP ROCKY!!! will get branliest.
Answer:
y = 8x + 70
Step-by-step explanation:
Start with the third line.
x = 3, y = 94
Subtract 1 from x and 8 from y:
x = 2, y = 86; this is the second line
Subtract 1 from x and 8 from y:
x = 1, y = 78; this is the first line
Subtract 1 from x and 8 from y:
x = 0; y = 70
For selling 0 games, she earns $70.
y = mx + b
y = mx + 70
For each game she sells, her commission is $8.
y = 8x + 70
For what values of y: Is the value of the fraction 5−2y 12 always greater than the value of 1−6y?
Answer:
[tex](5 - 2y) \div 12 > 1 - 6y[/tex]
[tex]5 - 2y > 12 - 72y[/tex]
[tex] - 7 > - 70y[/tex]
[tex]7 < 70y[/tex]
[tex]y > 1 \div 10 = 0.1[/tex]
xThe closing price of Schnur Sporting Goods Inc. common stock is uniformly distributed between $18 and $28 per share. What is the probability that the stock price will be: More than $20? (Round your answer to 4 decimal places.)
Answer:
The probability is [tex]P(X > 20 ) = 0.8[/tex]
Step-by-step explanation:
From the question we are told that
The closing price of Schnur Sporting Goods Inc. common stock is uniformly distributed between $18 and $28 per share.
Given that the stock is uniformly distributed then the probability that the stock price will be more than $20 is mathematically evaluated as
[tex]P(X > 20 ) = 1 - P(X < 20 )[/tex]
Since it is uniformly distribute between $18 and $28 per share then we can solve is as follows
=> [tex]P(X > 20 ) = 1 - [\frac{ 20 - 18 }{28 -18} ][/tex]
=> [tex]P(X > 20 ) = 0.8[/tex]
Which of the following classifications of polygons could be a valid description? an equilateral scalene triangle an obtuse scalene triangle a square trapezoid a rectangular kite
Answer:
B. An obtuse scalene triangle
Step-by-step explanation:
Polygons are plane figures bounded by three or more straight sides. Examples are: trigon, quadragon, hexagon, nonagon etc. They are named with respect to their number of sides.
An obtuse triangle has one of its angles greater than [tex]90^{0}[/tex] but less than [tex]180^{0}[/tex]. While a scalene triangles has non of its sides to be equal in length.
The valid description of the classes of polygons is: an obtuse scalene triangle. Which implies that the triangle has one of its angles to be obtuse, and non of its sides equal.
Joey’s pizza sells large cheese pizzas for $12.00. Each additional topping costs $0.50. Basketball Boosters bought 12 large pizzas, each with 3 toppings. There are 8 slices per pizza. How much does it cost per slice? Round to the nearest cent.
Answer:
So first you do $0.50 x 3 = 1.5
then you add that to $12.00
$12.00 + 1.5 = 13.5
13.5 is the cost of one pizza.
Since they bought 12:
The total cost of the 12 pizza is $162 <== not important
13.5 divided by 8 is 1.687
round 1.56875 to the nearest cent 1.7 = $2
so each slice costs $2
A plan for a dog park has a grassy section and a sitting section as shown in the figure. Which equation can be used to find the area of the grassy section?
Answer:
length times width
Step-by-step explanation:
Find the equation of the para bola that has zeros of x = -2 and x = 3 and a y-intercept of (0,-30)
Answer:
y = 5x^2-5x-30
Step-by-step explanation:
A parabola with x-intercepts at (-2,0) and (3,0) has the equation
y = a(x+2)(x-3)
where a is to be determined.
We know that it passes through the point (0,-30), so
-30 = a(0+2)(0-3) = -6a
Therefore solve for a to get
a = 5
y = 5(x+2)(x-3)
y = 5(x^2-x+6)
y = 5x^2-5x-30
BRAINLIST AND A THANK YOU AND 5 stars WILL BE REWARDED PLS ANSER
Answer:
The first picture's answer would be (6, 21)
Step-by-step explanation:
You have to find the points on the 8th and the 9th day, and then you would add them together, and then divide by two finding the average, which would be 24 and 18, so when added, you get 42, divided by 2 you get 21. You look on the graph for the point with 21, and you find it is on 6.
Calculate two iterations of Newton's Method for the function using the given initial guess. (Round your answers to four decimal places.) f(x) = x2 − 8, x1 = 2
Answer:
The first and second iteration of Newton's Method are 3 and [tex]\frac{11}{6}[/tex].
Step-by-step explanation:
The Newton's Method is a multi-step numerical method for continuous diffentiable function of the form [tex]f(x) = 0[/tex] based on the following formula:
[tex]x_{i+1} = x_{i} -\frac{f(x_{i})}{f'(x_{i})}[/tex]
Where:
[tex]x_{i}[/tex] - i-th Approximation, dimensionless.
[tex]x_{i+1}[/tex] - (i+1)-th Approximation, dimensionless.
[tex]f(x_{i})[/tex] - Function evaluated at i-th Approximation, dimensionless.
[tex]f'(x_{i})[/tex] - First derivative evaluated at (i+1)-th Approximation, dimensionless.
Let be [tex]f(x) = x^{2}-8[/tex] and [tex]f'(x) = 2\cdot x[/tex], the resultant expression is:
[tex]x_{i+1} = x_{i} -\frac{x_{i}^{2}-8}{2\cdot x_{i}}[/tex]
First iteration: ([tex]x_{1} = 2[/tex])
[tex]x_{2} = 2-\frac{2^{2}-8}{2\cdot (2)}[/tex]
[tex]x_{2} = 2 + \frac{4}{4}[/tex]
[tex]x_{2} = 3[/tex]
Second iteration: ([tex]x_{2} = 3[/tex])
[tex]x_{3} = 3-\frac{3^{2}-8}{2\cdot (3)}[/tex]
[tex]x_{3} = 2 - \frac{1}{6}[/tex]
[tex]x_{3} = \frac{11}{6}[/tex]
prove:
[tex] \frac{1}{secθ + \tanθ} - \frac{1}{cosθ} = \frac{1}{cosθ} - \frac{1}{secθ - tanθ} [/tex]
Answer:
I hope you are searching for this......
A random sample of 12 second-year university students enrolled in a business statistics course was drawn. At the course's completion, each student was asked how many hours he or she spent doing homework in statistics. The data are listed below. 20, 29, 28, 22, 26, 22, 22, 18, 23, 21, 20, 27 It is known that the population standard deviation is 7. The instructor has recommended that students devote 2 hours per week for the duration of the 12-week semester, for a total of 24 hours. Test to determine whether there is evidence at the 0.07 significance level that the average student spent less than the recommended amount of time. Fill in the requested information below.A. The value of the standardized test statistic:Note: For the next part, your answer should use interval notation. An answer of the form (−[infinity],a) is expressed (-infty, a), an answer of the form (b,[infinity]) is expressed (b, infty), and an answer of the form (−[infinity],a)∪(b,[infinity]) is expressed (-infty, a)U(b, infty). B. The rejection region for the standardized test statistic:C. The p-value isD. Your decision for the hypothesis test: A. Reject H0. B. Do Not Reject H1. C. Do Not Reject H0. D. Reject H1.
Answer:
Reject H₀.
Step-by-step explanation:
In this case, we need to test whether the average student spent less than the recommended amount of time doing homework in statistics.
The provided data is:
S = {20, 29, 28, 22, 26, 22, 22, 18, 23, 21, 20, 27}
Compute the sample mean:
[tex]\bar x=\frac{1}{n}\sum X=\frac{1}{12}\cdot [20+29+...+27]=23.167[/tex]
The population standard deviation is σ = 7.
The hypothesis for the test is:
H₀: The average student does not spent less than the recommended amount of time doing homework, i.e. μ ≥ 24.
Hₐ: The average student spent less than the recommended amount of time doing homework, i.e. μ < 24.
(A)
Compute the standardized test statistic value as follows:
[tex]z=\frac{\bar x-\mu}{\sigma/\sqrt{n}}[/tex]
[tex]=\frac{23.167-24}{7/\sqrt{12}}\\\\=-0.412[/tex]
Thus, the standardized test statistic value is -0.412.
(B)
The significance level of the test is:
α = 0.07
The critical value of z is:
z₀.₀₇ = -1.476
The rejection region is:
(-∞, -0.1476)
(C)
Compute the p-value as follows:
[tex]p-value=P(Z<-0.412)=0.34[/tex]
*Use a z-table.
Thus, the p-value is 0.34.
(D)
Since, p-value = 0.34 > α = 0.07, the null hypothesis was failed to be rejected at 7% level of significance.
Thus, the correct option is (A).
Which are perfect squares? Check all that apply. 9 , 24 , 16 , 200 , 169 , 625
Answer:
A. 9
C. 16
E. 169
F. 625
Step-by-step explanation:
i will give brainliest and 5 stars if you help ASAP
Answer:
[tex] Area = 240 m^2 [/tex]
Step-by-step explanation:
The area of the right triangle above = [tex] \frac{1}{2}*base*height [/tex].
Where,
base = 16 m
height = 30 m
Plug in the above values into the area formula:
[tex] Area = \frac{1}{2}*16*30 [/tex]
[tex] Area = 8*30 [/tex]
[tex] Area = 240 m^2 [/tex]
Refer to the attachment for solution.
A simple random sample of 60 households in city 1 is taken. In the sample, there are 45 households that decorate their houses with lights for the holidays. A simple random sample of 50 households is also taken from the neighboring city 2. In the sample, there are 40 households that decorate their houses. What is a 95% confidence interval for the difference in population proportions of households that decorate their houses with lights for the holidays
Answer:
The calculated value of z = - 0.197 falls in the critical region therefore we reject the null hypothesis and conclude that at the 5% significance level there is significant difference in population proportions of households that decorate their houses with lights for the holidays
Step-by-step explanation:
We formulate the null and alternative hypotheses as
H0: p1= p2 there is no difference in population proportions of households that decorate their houses with lights for the holidays
against Ha : p1≠ p2 (claim) ( two sided)
The significance level is set at ∝= 0.05
The critical value for two tailed test at alpha=0.05 is ± 1.96
or Z∝= 0.05/2= ± 1.96
The test statistic is
Z = p1-p2/√pq(1/n1 +1/n2)
p1= proportions of households decorating in city 1 = 45/60=0.75
p2= proportions of households decorating in city 2 = 40/50= 0.8
p = the common proportion on the assumption that the two proportion are same.
p = [tex]\frac{n_1p_1 +n_2p_2}{n_1+n_2}[/tex]
Calculating
p =60 (0.75) + 50 (0.8) / 110
p= 45+ 40/110= 85/110 = 0.772
so q = 1-p= 1- 0.772= 0.227
Putting the values in the test statistic and calculating
z= 0.75- 0.8/ √0.772*0.227( 1/60 + 1/50)
z= -0.05/√ 0.175244 ( 110/300)
z= -0.05/0.25348
z= -0.197
The calculated value of z = - 0.197 falls in the critical region therefore we reject the null hypothesis and conclude that at the 5% significance level there is significant difference in population proportions of households that decorate their houses with lights for the holidays
A deli sandwich shop is offering either a ham or turkey sandwich, either tomato or vegetable soup, and either coffee or milk for their lunch special. What is the probability that a customer will choose vegetable soup as part of the chosen combination?
Answer:
Ok, the first step is to count all the possible selections that we have and the number of options in each selection:
1) Sandwich: 2 options, ham or turkey.
2) Soup, 2 options, tomato or vegetable.
3) Drink, 2 options, coffee or milk.
(i assume that the sandwich and the soup are separated selections)
Now, if the customer chooses at random, the probability that in one given selection he selects a given outcome is equal to the number of options that match the outcome divided by the total number of options for that selection.
Then in the soup selection we have: options that match the outcome (one, is the vegetable soup). Total number of options = 2.
Then the probability is:
P = 1/2 = 0.5
or 0.5*100% = 50% in percentage form.
Answer:
1/2
Step-by-step explanation:
How many multiples of 4, that are smaller than 1,000, do not contain any of the digits 6, 7, 8, 9 or 0? I really need a answer.
Answer:
Step-by-step explanation:
We could start by listing multiples of 4 and looking for patterns. Do
you know what a multiple of a number is? It's that number multiplied
by another number. So the first multiple of 4 is 4x1, the second
multiple of 4 is 4x2=8, the third multiple of 4 is 4x3=12, etc.
Let's make a table of multiples of 4 from 1 to 100, with columns A-E
across the top and rows 1-5 down the left-hand side:
A B C D E
1 4 8 12 16 20
2 24 28 32 36 40
3 44 48 52 56 60
4 64 68 72 76 80
5 84 88 92 96 100
Now let's look at these multiples, remembering that there will be nine
more tables like this one from 101-1000.
Let's look for 6,7,8,9, and 0 in the columns first. Aha! We can erase
all of columns B, D, and E because there's a 6 or an 8 or a 0 in each
number in those columns. Now we're left with just:
A C
1 4 12
2 24 32
3 44 52
4 64 72
5 84 92
Now let's look at the rows. Wow! We can eliminate rows 4 and 5 because
they have 6, 7, 8, or 9, leaving:
A C
1 4 12
2 24 32
3 44 52
Just 6 numbers left!
So if from 1-100 there are 6 multiples of four that do not contain any
of the digits 6, 7, 8, 9, or 0, how many multiples of four like this
are there from 1-1000?
What is the solution to this ?
Answer:
[tex]\boxed{\sf C. \ x\geq -4}[/tex]
Step-by-step explanation:
[tex]-8x+4\leq 36[/tex]
[tex]\sf Subtract \ 4 \ from \ both \ sides.[/tex]
[tex]-8x+4-4 \leq 36-4[/tex]
[tex]-8x\leq 32[/tex]
[tex]\sf Divide \ both \ sides \ by \ -8.[/tex]
[tex]\frac{-8x}{-8} \leq \frac{32}{-8}[/tex]
[tex]x\geq -4[/tex]
The quotient of 8 and the difference of three and a number.
Answer: 8÷(3-x)
Answer:
Below
Step-by-step explanation:
● 8 ÷ (3-x)
Dividing by 3-x is like multiplying by 1/(3-x)
● 8 × (1/3-x)
● 8 /(3-x)
HELPPPPP ASAPPPP
Select the correct answer.
A volleyball player sets a volleyball straight up into the air. The height of the volleyball, h(t), is modeled by this equation, where e represents the
time, in seconds, after that ball was set.
= -16t2 + 20t + 6
The volleyball reaches its maximum height after 0.625 seconds. What is the maximum height of the volleyball
A. 11.625 feet
B. 12.25 feet
C. 8.5 feet
D. 1.625 feet
Answer:
The maximum height of the volleyball is 12.25 feet.
Step-by-step explanation:
The height of the volleyball, h(t), is modeled by this equation, where t represents the time, in seconds, after that ball was set :
[tex]h(t)=-16t^2+20t+6[/tex] ....(1)
The volleyball reaches its maximum height after 0.625 seconds.
For maximum height,
Put [tex]\dfrac{dh}{dt}=0[/tex]
Now put t = 0.625 in equation (1)
[tex]h(t)=-16(0.625)^2+20(0.625)+6\\\\h(t)=12.25\ \text{feet}[/tex]
So, the maximum height of the volleyball is 12.25 feet.
Answer:
The correct answer is B. 12.25 feet.
Step-by-step explanation:
I got it right on the Edmentum test.
The probability that a company will launch the product A and B are 0.45 and 0.60 respectively, in main while, probability that both products launched, is 0.35. what is the probability that Neither will of these products launch ? At least one product will be launched ?
Answer:
a) what is the probability that Neither will of these products launch ?
= 0.30
b) At least one product will be launched ?
= 0.70
Step-by-step explanation:
From the above question, we have the following information:
P(A) = 0.45
P(B) = 0.60
P(A ∩ B) = P(A and B) launching = 0.35
Step 1
We find the Probability that A or B will launch
P (A ∪ B) = P(A) + P(B) - P(A ∩ B)
= 0.60 + 0.45 - 0.35
= 1.05 - 0.35
= 0.70
a) what is the probability that Neither will of these products launch ?
1 - Probability ( A or B will launch)
= 1 - 0.70
= 0.30
b)At least one product will be launched?
This is equivalent to the probability that A or B will be launched
P (A ∪ B) = P(A) + P(B) - P(A ∩ B)
= 0.60 + 0.45 - 0.35
= 1.05 - 0.35
= 0.70
