The value of x from the given similar triangles is 10 units.
The given triangles are similar.
Here, 3x/(4x+2) = 20/28
3x/(4x+2) = 5/7
7×3x = 5(4x+2)
21x=20x+10
21x-20x=10
x=10 units
Therefore, the value of x from the given similar triangles is 10 units.
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Out of a pool of 26 men and 29 women what is the probability of 12 women jurors being chosen?
The probability of 12 women jurors being chosen is approximately 0.000342 or 0.0342%.
To calculate the probability of selecting 12 women jurors out of a pool of 26 men and 29 women, we need to consider the total number of possible combinations and the specific combination of interest.
The total number of ways to choose 12 individuals from a pool of 55 (26 men + 29 women) is given by the combination formula:
C(55, 12) = 55! / (12! * (55-12)!) = 22579284062370.
The number of ways to choose 12 women from a pool of 29 is given by the combination formula:
C(29, 12) = 29! / (12! * (29-12)!) = 7726160.
Therefore, the probability of selecting 12 women jurors is the ratio of the number of ways to choose 12 women to the total number of possible combinations:
P(12 women jurors) = C(29, 12) / C(55, 12) ≈ 7726160 / 22579284062370 ≈ 0.000342.
Hence, the probability of 12 women jurors being chosen is approximately 0.000342 or 0.0342%.
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A population of values has a normal distribution with �=189.7 and �=96.7. You intend to draw a random sample of size �=62.
Find the probability that a single randomly selected value is between 189.7 and 213.
P(189.7 < X < 213) =
Find the probability that a sample of size �=62 is randomly selected with a mean between 189.7 and 213.
P(189.7 < M < 213) =
Enter your answers as numbers accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
The probability that a sample of size n = 62 is randomly selected with a mean between 189.7 and 213 is approximately 0.9702.
To find the probability that a single randomly selected value is between 189.7 and 213, we can use the standard normal distribution.
Step 1: Calculate the z-scores for the given values using the formula:
z = (x - μ) / σ
For 189.7:
z1 = (189.7 - 189.7) / 96.7 = 0
For 213:
z2 = (213 - 189.7) / 96.7 ≈ 0.2417
Step 2: Utilize a standard typical conveyance table or number cruncher to find the probabilities comparing to the z-scores.
P(189.7 < X < 213) = P(0 < Z < 0.2417) ≈ 0.0939
Therefore, the probability that a single randomly selected value is between 189.7 and 213 is approximately 0.0939.
To find the probability that a sample of size n = 62 is randomly selected with a mean between 189.7 and 213, we use the central limit theorem. Under specific circumstances, the testing dispersion of the example mean methodologies a typical conveyance
Step 1: Calculate the standard error of the mean (σ_m) using the formula:
σ_m = σ / sqrt(n)
σ_m = 96.7 / sqrt(62) ≈ 12.2878
Step 2: Convert the given qualities to z-scores utilizing the equation:
z = (x - μ) / σ_m
For 189.7:
z1 = (189.7 - 189.7) / 12.2878 = 0
For 213:
z2 = (213 - 189.7) / 12.2878 ≈ 1.8967
Step 3: Utilize a standard typical conveyance table or mini-computer to find the probabilities relating to the z-scores.
P(189.7 < M < 213) = P(0 < Z < 1.8967) ≈ 0.9702
Therefore, the probability that a sample of size n = 62 is randomly selected with a mean between 189.7 and 213 is approximately 0.9702.
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cm 84. A father's age was three times and two times of his son at 2040 and 2050 respectively. What will be the birth year of son? a. 2030 b. 2035 c. 2031 d. 2032 100
Answer:
(a)2030
Step-by-step explanation:
I'm assuming the 100 at the end of the question is a typo.
In 2040, the son's age can be written as [tex]\frac{x}{3}[/tex], where x equals the age of his father. In 2050, the son's age can be written as [tex]\frac{x-10}{2}[/tex] (as ten years is added between 2040 and 2050). When equated to each other--> [tex]\frac{x-10}{2}[/tex] = [tex]\frac{x}{3}[/tex], we can first simplify by multiplying both sides to reach the least common denomination 6, giving us 3(x-10)=2x --->3x-30=2x--->x=30 is the dad's age. The son's age in 2040, 30/3, is equal to 10 years, meaning he was born in the year 2030 (a).
calcula el cuádruple de la parte decimal sumando con el doble de la parte entera del siguiente número decimal : 123,45
The expression that we need to solve is 4*45 + 2*123 , and that is equal to 426.
How to find the number?
Here we want to calculate the quadruple of the decimal part by adding twice the integer part of the following decimal number: 123.45
The decimal part of this number is 45
The integer part of this number is 123.
Then the expression that we need to solve is:
4*45 + 2*123 = 426
That is the value of the mathematical sentence.
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I need help with this!
The length AC in the kite is 8.7 cm.
How to find the side AC in the kite?A kite is a quadrilateral that has two pairs of consecutive equal sides and
perpendicular diagonals. Therefore, let's find the length AC in the kite.
Hence, using Pythagoras's theorem, let's find CE.
Therefore,
7² - 4² = CE²
CE = √49 - 16
CE = √33
CE = √33
Let's find AE as follows:
5²- 4² = AE²
AE = √25 - 16
AE = √9
AE = 3 units
Therefore,
AC = √33 + 3
AC = 5.74456264654 + 3
AC = 8.74456264654
AC = 8.7 units
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enter the number that belongs in the green box
The angle opposite to side BC in triangle ABC is approximately 38.213 degrees.
We have,
To find the angle opposite to side BC in triangle ABC, we can use the Law of Cosines.
The Law of Cosines states that in a triangle with sides of lengths a, b, and c, and the angle opposite to side c being denoted as C, the following equation holds:
c² = a² + b² - 2ab x cos(C)
In this case,
Side a is BC with length 12, side b is AC with length 20, and side c is AB with length 11. We want to find the angle C, which is opposite to side BC.
Plugging the given values into the Law of Cosines equation:
11² = 12² + 20² - 2 x 12 x 20 x cos C
121 = 144 + 400 - 480 x cos C
121 = 544 - 480 x cos C
480 x cos C = 544 - 121
480 x cos C = 423
cos C = 423/480
Now, we can find the angle C by taking the inverse cosine (arccos) of (423/480):
C = arccos(423/480)
Using a calculator, we find that C is approximately 38.213 degrees.
Therefore,
The angle opposite to side BC in triangle ABC is approximately 38.213 degrees.
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The mean rounded to the nearest 10th of the following data set is 15, 16, 17, 23, 11, 19, 20, 15, 18, 22, 15, 19
Answer:
17.5
Step-by-step explanation:
You can find the mean of a data set by adding all numbers in the data set together and dividing by the amount of numbers in the given data set.
In this case, your data set is:
15 , 16 , 17 , 23 , 11 , 19 , 20 , 15 , 18 , 22 , 15 , 19 (12 numbers).
Firstly, add all the numbers together: [tex]15 + 16 + 17 + 23 + 11 + 19 + 20 + 15 + 18 + 22 + 15 + 19 = 210[/tex]
Next, divide 210 (total sum) with the amount of terms in total (12):
[tex]\frac{(210)}{(12)} = 17.5[/tex]
17.5 is already in the tenth digit place value, and so you do not need to round.
17.5 is your answer.
~
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How many ways can you arange 2 Letters picked
from A, B, C, D? order matters
When selecting 2 letters from the set {A, B, C, D}, considering that the order matters, we can use the concept of permutations to calculate the number of possible arrangements.
The number of ways to arrange 2 letters from a set of 4 can be calculated using the formula for permutations:
P(n, r) = n! / (n - r)!
Where n is the total number of items (in this case, 4) and r is the number of items being selected (in this case, 2).
Using this formula, the number of ways to arrange 2 letters from A, B, C, D is:
P(4, 2) = 4! / (4 - 2)!
= 4! / 2!
= (4 x 3 x 2 x 1) / (2 x 1)
= 24 / 2
= 12
Therefore, there are 12 possible ways to arrange 2 letters selected from A, B, C, D when considering that the order matters.
~~~Harsha~~~
Answer:
Step-by-step explanation:
When selecting 2 letters from the set {A, B, C, D} and considering that the order matters, we can determine the number of possible arrangements using the concept of permutations.
The number of ways to arrange 2 letters from a set of 4 can be calculated using the formula for permutations:
P(n, r) = n! / (n - r)!
where P(n, r) represents the number of permutations of r objects chosen from a set of n objects.
In this case, we have n = 4 (the total number of letters) and r = 2 (the number of letters to be selected).
Using the formula, we can calculate:
P(4, 2) = 4! / (4 - 2)!
= 4! / 2!
= (4 × 3 × 2 × 1) / (2 × 1)
= 24 / 2
= 12
Therefore, there are 12 different ways to arrange 2 letters chosen from the set {A, B, C, D} when the order matters.
If I have 7.55 how many dimes and quarters is it
Answer:
To convert 7.55 dollars into dimes and quarters, we need to make use of the fact that there are 10 dimes in a dollar and 4 quarters in a dollar. Here's how to do it:
Step-by-step explanation:
1. First, convert the dollar amount into cents: 7.55 dollars x 100 cents/dollar = 755 cents.
2. Next, use long division to find how many quarters are in 755 cents: 755 ÷ 25 = 30 with a remainder of 5.
3. The quotient of 30 tells us that we can use 30 quarters, which equals $7.50.
4. The remainder of 5 cents is less than a quarter, so we cannot use another quarter. Instead, we can use 1 dime, which is worth 10 cents.
Therefore, 7.55 dollars is equivalent to 30 quarters and 1 dime.
What is the numerical probability of selecting 10 men and 2 women out of 26 men and 29 women?
Hello!
men = 10/26 = 5/13
women = 2/29
P = 5/13 x 2/29 = 10/377
The following cylinder has a volume of 627.8 cm3 and a height of 19.5 cm
What is the radius of the cylinder?
Use 3.14 for π and round your answer to the nearest tenth.
5.7
3.2
1.7
10.1
Answer:
Step-by-step explanation:
To find the radius of the cylinder, we can use the formula for the volume of a cylinder:
Volume = π * radius^2 * height
Given:
Volume = 627.8 cm^3
Height = 19.5 cm
π (pi) = 3.14
Substituting the given values into the formula:
627.8 = 3.14 * radius^2 * 19.5
Simplifying the equation:
627.8 = 60.93 * radius^2
To solve for the radius, we can divide both sides of the equation by 60.93:
radius^2 = 627.8 / 60.93
radius^2 = 10.29
Taking the square root of both sides:
radius ≈ √10.29
Rounding to the nearest tenth:
radius ≈ 3.2
Therefore, the approximate radius of the cylinder is 3.2 cm.
Answer:
3.2
Step-by-step explanation:
The volume of a cylinder is:
Vol = pi•r^2•h
Fill in what is given.
627.8 = pi•r^2•19.5
use 3.14 for pi.
627.8 = 3.14•r^2•19.5
simplify.
627.8 = 61.23r^2
divide by 61.23
10.253 = r^2
sqrt both sides
sqrt10.253 = r
3.2 = r
how many terms are in the following Expression 2x³-4x²+2x-x-3
In the given expression, 2x³-4x²+2x-x-3, there are five terms. An expression is a mathematical phrase that can be constructed using variables, constants, and operators.
It can include any mathematical operations such as addition, subtraction, multiplication, and division. Additionally, an expression can be made up of one or more terms.In the given expression, 2x³-4x²+2x-x-3, there are five terms. The terms are:2x³: This is the first term in the expression.
It is a cubic term, which means it has an exponent of 3.4x²: This is the second term in the expression. It is a quadratic term, which means it has an exponent of 2.2x: This is the third term in the expression. It is a linear term, which means it has an exponent of 1.-x:
This is the fourth term in the expression. It is also a linear term, but it has a negative coefficient.-3: This is the fifth term in the expression. It is a constant term since it does not have any variable attached to it.In summary, the given expression has five terms, which are 2x³, -4x², 2x, -x, and -3.
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In a sample of 560 adults, 336 had children. Construct a 95% confidence interval for the true population proportion of adults with children.
Give your answers as decimals, to three places
< p
Answer:
[tex]\{0.559,0.641\}[/tex]
Step-by-step explanation:
[tex]\displaystyle CI_{95\%}=\frac{336}{560}\pm1.96\sqrt{\frac{\frac{336}{560}(1-\frac{336}{560})}{560}}\approx\{0.559,0.641\}[/tex]
Question One:
If a raw score corresponds to a z-score of 1.75, what does that tell you about that score in relation to the mean of the distribution?
Question Two:
What if the raw score corresponds to a z-score of -0.85?
Question One:A positive z-score indicates that the raw score is above the mean, while a negative z-score indicates that the raw score is below the mean.
Question Two: , the raw score is relatively lower than the mean.
If a raw score corresponds to a z-score of 1.75, it tells us that the raw score is 1.75 standard deviations above the mean of the distribution. In other words, the raw score is relatively higher than the mean. The z-score provides a standardized measure of how many standard deviations a particular value is from the mean.
A positive z-score indicates that the raw score is above the mean, while a negative z-score indicates that the raw score is below the mean.
Question Two:
If a raw score corresponds to a z-score of -0.85, it tells us that the raw score is 0.85 standard deviations below the mean of the distribution. In other words, the raw score is relatively lower than the mean. The negative sign indicates that the raw score is below the mean.
To understand the meaning of a z-score, it is helpful to consider the concept of standard deviation. The standard deviation measures the average amount of variability or spread in a distribution. A z-score allows us to compare individual data points to the mean in terms of standard deviations.
In the case of a z-score of -0.85, we can conclude that the raw score is located below the mean and is relatively lower compared to the rest of the distribution. The negative z-score indicates that the raw score is below the mean and is within the lower portion of the distribution. This suggests that the raw score is relatively smaller or less than the average value in the distribution.
By using z-scores, we can standardize and compare values across different distributions, allowing us to understand the position of a raw score relative to the mean and the overall distribution.
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A square garden has a length of (x+3) ft and a width of (x+2) ft. what is the perimeter and area of the garden?
Answer:
Perimeter:[tex]4x+10[/tex] feet
Area:[tex]x^{2}+5x+6[/tex] feet
Step-by-step explanation:
The perimeter is equal to 2*width +2*length. The width is x+2 and the length is x+3, therefore the perimeter is equal to 2x+4+2x+6 which equals 4x+10.
The area is equal to width*length
(x+3)(x+2)=[tex]x^{2}+2x+3x+6=x^{2}+5x+6[/tex]
PLS HELP THANK YOUUUUUUU
An area is formed by a square, ABCB, and a semi circle. BD is the diameter of the semi circle.The radius of the semi circle is 4m. The area is going to be covered completely with lawn seed. A box of lawn seed covers 25m^2. How many boxes of lawn seed will be needed?
The number of boxes of lawn seed that will be needed will be 4.
How to calculate the number of boxesFrom the information, an area is formed by a square, ABCB, and a semi circle. BD is the diameter of the semi circle.The radius of the semi circle is 4m. The area is going to be covered completely with lawn seed.
The area of the square is s²
= 4²
= 16 m²
The area of the semi-circle is (πr²)/2:
= (π*4²)/2
= 8π m²
The total area is 16 + 8π m²
The number of boxes of lawn seed needed is (16 + 8π)/25 = (8 + 4π)/25
≈ 3.44 boxes
≈ 4 boxes
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210 students appeared in the se examination from a certain of these 56 students failed the examinations and the ratio of those who passed with I,II and III divisions respectively is 5:10:7. find the number of students who passed with I,II and III divisions respectively
The number of students who passed with I, II, and III divisions are 35, 70, and 49, respectively.
We have,
Let's denote the number of students who passed with I, II, and III divisions as x, y, and z, respectively.
Given that the total number of students who appeared in the examination is 210, and 56 students failed, we can calculate the number of students who passed:
Number of students who passed = Total students - Number of students who failed
= 210 - 56
= 154
According to the given ratio, the number of students who passed with I, II, and III divisions are in the ratio of 5:10:7.
We can express this ratio in terms of x, y, and z as:
x : y : z = 5 : 10 : 7
To find the actual number of students who passed with I, II, and III divisions, we can set up the following equation based on the ratio:
5k + 10k + 7k = 154
22k = 154
k = 154 / 22
k = 7
Now, we can find the number of students who passed with I, II, and III divisions:
Number of students who passed with I division = 5k = 5 x 7 = 35
Number of students who passed with II division = 10k = 10 x 7 = 70
Number of students who passed with III division = 7k = 7 x 7 = 49
Therefore,
The number of students who passed with I, II, and III divisions are 35, 70, and 49, respectively.
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what is 3 to power of 2 -4 to the power of 5=
Step-by-step explanation:
Unclear what you are asking
here is one possibility
3^2 - 4^5
9 - 1024 = - 1015
Here is another possibility
(3^(2-4) )^5 = = (3^(-2))^5 = 3 ^-10 = 1/59049
State if the triangles in each pair are similar. If so, state how you know they are similar and
complete the similarity statement.
1)
16
ADEF-
12
18
24
D
12
similar; AA similarity; AJKL
similar; SAS similarity; AKLJ
not similar
no
The triangle ∆DEF is similar by the SSS similarly to the triangle ∆JKL
What are similar trianglesSimilar triangles are two triangles that have the same shape, but not necessarily the same size. This means that corresponding angles of the two triangles are equal, and corresponding sides are in proportion.
To know if the triangles DEF and JKL are similar, we check if their sides corresponds in the same ratio, that is;
JK/DE = KL/EF = JL/DF
JK/DE = 9/12 = 3/4
KL/EF = 18/24 = 3/4
JL/DF = 12/16 = 3/4
Therefore, the triangle ∆DEF is similar by the SSS similarly to the triangle ∆JKL
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i am going toget a detention if i dont do this please help me
challenging was 0.92, with a margin of error of 0.07.
Construct a confidence interval for the proportion of math majors that stated the curriculum was challenging.
The confidence interval using a margin of error of 0.07 is (0.85,0.99)
Confidence IntervalSample proportion = 0.92
Margin of error = 0.07
Lower bound of the confidence interval = Sample proportion - Margin of error
Lower bound = 0.92 - 0.07 = 0.85
Upper bound of the confidence interval = Sample proportion + Margin of error
Upper bound = 0.92 + 0.07 = 0.99
Confidence interval = [Lower bound, Upper bound]
Confidence interval = [0.85, 0.99]
Therefore, the confidence interval for the proportion of math majors who found the curriculum challenging is approximately 0.85 to 0.99.
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What is the product?
(4x)(-3x³)(-7x³)
O -84x¹2
O-84x24
O 84x¹2
O 84x24
Answer:
-84x^7
Step-by-step explanation:
The product of (4x)(-3x³)(-7x³) is -84x^8.
To calculate the product, we multiply the coefficients together and add the exponents of the variables:
4 * (-3) * (-7) = 84
x^1 * x^3 * x^3 = x^(1+3+3) = x^7
Combining the coefficient and the variable, we get -84x^7.
The figure above shows a store's supply-demand graph for coffee makers. If the store sells $600 worth of coffee makers, which of the following is a valid possible price for them?
A. $15
B. $30
C. $40
D. $55
The possible price for the items if the store sells $600 is (c) $40
How to determine the possible price for the items?From the question, we have the following parameters that can be used in our computation:
The supply-demand graph
If the store sells $600, then there is a supply worth of $600
The equation of the supply line is calculated as
y = mx + c
Where
c = y = 0
i.e. c = 100
So, we have
y = mx + 100
Using another point on the graph, we have
30m + 10 = 400
So, we have
m = 13
This means that
y = 13x + 100
For a supply of 600, we have
13x + 100 = 600
So, we have
13x = 500
Divide by 13
x = 38.4
Approximate
x = 40
Hence, the possible price for the items is (c) $40
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Heather has a bag with 8 balls numbered 1 through 8. She is playing a game of chance.
This game is this: Heather chooses one ball from the bag at random. She wins $1 if the number 1 is selected, $2 if the number 2 is selected, $5 if the number 3 is selected, $6 if the number 4 is selected,$8 if the number 5 is selected, and $10 if the number 6 is selected. She loses $13 if 7 or 8 is selected.(a) Find the expected value of playing the game.
(b) What can Heather expect in the long run, after playing the game many times?
(She replaces the ball in the bag each time.)
Heather can expect to gain money.
Heather can expect to lose money.
Heather can expect to break even (neither gain nor lose money).
(a) The expected value of playing the game is 0.
(b) Heather can expect to break even in the long run.
To find the expected value of playing the game, we need to calculate the weighted average of the possible outcomes.
Expected value calculation:
The probability of selecting each ball is the same since Heather replaces the ball in the bag each time.
The probability of selecting any particular number is 1/8.
Expected value = (Probability of outcome 1 × Value of outcome 1) + (Probability of outcome 2 × Value of outcome 2) + ... + (Probability of outcome 8 × Value of outcome 8)
Expected value = (1/8 × 1) + (1/8 × 2) + (1/8 × 5) + (1/8 × 6) + (1/8 × 8) + (1/8 × 10) + (1/8 × (-13)) + (1/8 × (-13))
Expected value = (1/8) + (2/8) + (5/8) + (6/8) + (8/8) + (10/8) + (-13/8) + (-13/8)
Expected value = 26/8 - 26/8
Expected value = 0
Since the expected value of playing the game is 0 On average, she neither gains nor loses money over multiple plays of the game.
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A group of ten students recorded the number of minutes they spent on one math homework problem. The mean amount of time was 9 minutes, but the MAD was 7 minutes. Draw a dot plot to represent a data set that matches this description. Be sure to include a title and label your axis.
Answer:
Here is an example of a dot plot (in text, did as best as I could to represent it) that matches the description you provided:
Number of Minutes Spent on Math Homework Problem
|
10| o
9| o
8|
7| o
6|
5| o
4|
3| o
2|
1| o
0|___________________
1 2 3 4 5 6 7 8 9 10
Students
This dot plot shows the number of minutes spent on a math homework problem by ten students. The mean amount of time is represented by the dot at the y-value of 9, and the MAD (Mean Absolute Deviation) is represented by the spread of the data around the mean.
the three consecutive term of geometric series be increased by their middle term, then prove that the resulting term will be in Harmonic series.
Let x, xr , xr² be the terms of GP.
After the increase, the terms are : x+xr , xr+xr , xr²+xr
or in simplified manner : x(1+r), 2xr, xr (r+1) .
For these terms to be in Harmonic Progression, their reciprocals should be in Arithmetic Progression .
Thus,
Arithmetic mean of first and last terms should be equal to the middle term.
First term = 1/[x(1+r)] ; Middle term= 1/(2xr) ; Last term = 1/[xr(r+1)]
Assume,
A = Arithmetic mean of first and last term
A= [1/[x(1+r)]+[1/[xr(r+1)] /2
A= (1/2)[(r+1)/(xr(1+r))]
A= (1/2)(1/xr)
A= 1/(2xr)
A = Middle term
Thus, the reciprocals are in AP.
Hence x(1+r), 2xr, xr(r+1) in HP.
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¿De cuántas maneras es posible formar los grupos del torneo de liga de futbol de primera división? Recordemos que en la primera división del futbol en México participan 18 equipos, y para el torneo de la liga se forman dos grupos de cinco equipos y dos grupos de 4 equipos. Se sugiere que al resolverlo se vaya restando la cantidad de equipos que se han considerado para el primer grupo, después para el segundo grupo y así para cada grupo. Finalmente aplicar la regla del producto para encontrar las diferentes formas.
Note that his is solved using the principle of Combination, and there are 771, 891, 120 different ways to form the groups for the first division soccer league tournament in Mexico.
How is this so ?Let 's compute the number of ways to form the groups using combinations.
First group - 5 teams
C(18, 5) = 18! / (5! * (18-5)!) = 8568
Second group - 5 teams
C(13, 5) = 13! / (5! * (13-5)!) = 1,287
Third group - 4 teams
C(8, 4) = 8! / (4! * (8-4)!) = 70
Fourth group - 4 teams
C(4, 4) = 4! / (4! * (4-4)!) = 1
Now, applying the product rule
Total ways = 8568 x 1,287 x 70 x 1 = 771891120
Therefore, there are 771, 891, 120 different ways to form the groups for the first division soccer league tournament in Mexico.
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Translation
In how many ways is it possible to form the groups of the first division soccer league tournament? Let's remember that 18 teams participate in the first division of soccer in Mexico, and for the league tournament, two groups of five teams and two groups of 4 teams are formed. It is suggested that when solving it, the number of teams that have been considered for the first group be subtracted, then for the second group and so on for each group. Finally apply the product rule to find the different shapes.
Give a rational Number between 4/7 and 6/11
Hello!
4/7 = 44/77
6/11 = 42/77
42/77 < 43/77 < 44/77
the rationnal number between 4/7 and 6/11 is 43/77
Kristin left the movie theater and traveled
toward the lake at an average speed of 33
km/h. Jennifer left sometime later
traveling in the opposite direction with an
average speed of 45 km/h. After Kristin
had traveled for two hours they were 156
km apart. How long did Jennifer travel?
AnswerTherefore, Jennifer traveled for 2 hours.
Step-by-step explanation:
Let x be the time Jennifer traveled.
Kristin traveled for 2 hours at 33 km/h, so she had traveled 66 km when Jennifer started traveling.
After x hours, Jennifer had traveled 45x km.
The total distance between them was 156 km.
So, we have:
66 km + 45x km = 156 km
Simplifying the equation, we get:
45x km = 90 km
x = 2 hours
Therefore, Jennifer traveled for 2 hours.