Answer: 8w
Explanation:
A 4.0-kg mass is placed at (3.0, 4.0) m, and a 6.0-kg mass is placed at (3.0, -4.0) m. what is the moment of inertia of this system of masses about the z-axis?
The moment of inertia of this system of masses about the z-axis is 99 kg[tex]m^{2}[/tex].
Given,
Mass of first object, [tex]m_{1}[/tex] = 4 kg at (3, 4) m
Mass of second object, [tex]m_{2}[/tex] = 6 kg at 3, -4) m
The moment of inertia (I) of a system of particles is given as,
I = [tex]m_{i}x_{i} ^{2}[/tex]
Here, I = [tex]m_{1}x_{1} ^{2}[/tex] + [tex]m_{2}x_{2} ^{2}[/tex]
Moment of inertia, I = (4×[tex]3^{2}[/tex] )+ (6×[tex]3^{2}[/tex])
= (5×9) + (6×9)
= 45 + 54
I = 99 kg[tex]m^{2}[/tex]
Hence, the moment of inertia will be 99 kg[tex]m^{2}[/tex].
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remarks notice the use of 2.01 m in the denominator of the last calculation, rather than 2.00 m. this is because, in effect, the strut was compressed back to the original length from the length to which it would have expanded. (the difference is negligible, however.) the answer exceeds the ultimate compressive strength of steel and underscores the importance of allowing for thermal expansion. of course, it's likely the strut would bend, relieving some of the stress (creating some shear stress in the process). finally, if the strut is attached at both ends by bolts, thermal expansion and contraction would exert sheer stresses on the bolts, possibly weakening or loosening them over time. question which of the following combinations of properties will result in the smallest expansion of a substance due to the absorption of a given amount q of thermal energy? small specific heat, large coefficient of expansion small specific heat, small coefficient of expansion large specific heat, small coefficient of expansion large specific heat, large coefficient of expansion practice it use the worked example above to help you solve this problem. a steel strut near a ship's furnace is 1.90 m long, with a mass of 1.67 kg and a cross-sectional area of 1.00 10-4 m2. during operation of the furnace, the strut absorbs thermal energy in a net amount of 2.50 105 j. (a) find the change in temperature of the strut.
To find the change in temperature of the strut, we need to use the equation for the heat capacity of a solid:
q = C * m * ΔT
Where q is the amount of thermal energy absorbed by the strut, C is the specific heat capacity of steel, m is the mass of the strut, and ΔT is the change in temperature of the strut. Substituting the given values into the equation, we get:
2.50 105 j = 0.47 J/g*C * 1.67 kg * ΔT
Solving for ΔT, we get:
ΔT = (2.50 105 j) / (0.47 J/gC * 1.67 kg) = 461.37 gC
The change in temperature of the strut is 461.37 g*C.
To find the expansion of the strut due to the absorption of thermal energy, we need to use the equation for thermal expansion:
ΔL = L * α * ΔT
Where ΔL is the change in length of the strut, L is the original length of the strut, α is the coefficient of thermal expansion of steel, and ΔT is the change in temperature of the strut. Substituting the given values into the equation, we get:
ΔL = 1.90 m * 1.2 10-5/C * 461.37 g*C = 0.0011 m
The expansion of the strut due to the absorption of thermal energy is 0.0011 m.
To find the compressive stress on the strut, we need to use the equation for stress:
σ = F / A
Where σ is the compressive stress on the strut, F is the compressive force on the strut, and A is the cross-sectional area of the strut. Since the strut is attached at both ends and is not allowed to move, the compressive force on the strut is equal to the force due to the thermal expansion of the strut:
F = k * ΔL
Where k is the spring constant of the strut, which is determined by the stiffness of the strut and its attachment points. Substituting this expression for F into the equation for stress, we get:
σ = (k * ΔL) / A
Substituting the given values into the equation, we get:
σ = (k * 0.0011 m) / (1.00 10-4 m2) = 11.00 kN/m2
The compressive stress on the strut is 11.00 kN/m2.
The smallest expansion of a substance due to the absorption of a given amount of thermal energy will occur when the substance has a small specific heat capacity and a small coefficient of thermal expansion.
This is because a small specific heat capacity means that the substance requires less thermal energy to raise its temperature by a given amount, and a small coefficient of thermal expansion means that the substance will experience less expansion per unit increase in temperature.
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What is the wavelength of a sound wave with a frequency of 500 Hz?.
The wavelength of sound wave is 0.662 m.
The wavelength of a wave, specifically the points of an electromagnetic wave, is the separation between successive crests. The relationship between wavelength and frequency is close. The wavelength gets shorter the higher the frequency.
We are given that,
Frequency = f = 500hz
Speed of sound = v = 331.2m/s
Thus to calculate the wavelength of sound by the formula,
λ = v/f
λ = (331.2 m/s) / (500 Hz)
λ = 0.662m
Therefore, the wavelength of sound wave would be 0.662 m.
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Simple Way to Measure Magnetic Fields The induced emf in the loop is measured to be V. What is the magnitude B of the magnetic field that the loop was in? Express your answer in terms of some or all of the variables A, C, and V. A loop of wire is at the edge of a region of space containing a uniform magnetic field B. The plane of the loop is perpendicular to the magnetic field. Now the loop is pulled out of this region in such a way that the area A of the coil inside the magnetic field region is dA decreasing at the constant rate c. That is, -C, with c > 0. For the case of a square loop of side length L being pulled out of the magnetic field with constant speed v (see the figure), what is the rate of change of area dA с
The Value of the Magnetic Field (B) is V/c
a)Induced Emf in the loop is given
[tex]V = -\frac{d\phi }{dt}[/tex]
since [tex]\phi =BA[/tex]
[tex]V=-\frac{d}{dt}(BA)=-B\frac{dA}{dt}[/tex]
given dA/dt = -c
V=-B(-c)=Bc
=>[tex]B=\frac{V}{c}[/tex]
b) since induced emf V=BLv
B=(BLv)/c
c=Lv
The magnetic influence on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is moving through a magnetic field. Nearly a magnetic dipole, the Earth's magnetic field (and surface magnetic field) has two poles, one at the planet's geographic north pole (see Magnetic North Pole) and the other near its geographic south pole (see Magnetic South Pole).
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On the surface of planet x, a body with a mass of 10. Kilograms weighs 40. Newtons. The magnitude of the acceleration due to gravity on the surface of planet x is.
The acceleration due to gravity on the surface of planet X is 4 N/kg.
What is acceleration due to gravity?Acceleration due to gravity is the acceleration gained by an object due to gravitational force.
To calculate the magnitude of the acceleration due to gravity on the surce of planet X, we use the formula below.
Formula:
g = W/m............ Equation 1Where:
g = Acceleration due to gravity of the bodyW = Weight of the bodym = Mass of the body.From the question,
Given:
W = 40 Newtonsm = 10 kilogramsSubstitute these values into equation 1
g = 40/10g = 4 N/kgHence, the acceleration due to gravity is 4 N/kg.
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in march 1958, fluorescent dye was injected into the northernmost of the blue sinks. it was detected 28 hr. later in sulphur springs on the hillsborough river to the south (see sketch map). use these data to calculate the approximate velocity of flow in this portion of the floridan aquifer system (show your work): 1. in feet/hour: 2. in miles/hour: 3. in meters/hour:
The Floridan aquifer system's approximate Velocity flow rate in this area
1. in feet/hour - 440 feet/hour
2. in miles/hour - 0.083 miles/hour
3. in meters/hour - 134.11 meters/hour
According to the computer display:
1 mile on the ground equals 1.2 cm on the map.
Distance between Blue sinks (as marked by you) and Sulphur springs = 2.8 cm
Then, 2.8 cm on the map = (1/1.2)*2.8 miles = 2.33 miles
Now,
The velocity of flow in Floridan Aquifer = distance/time = 2.33 miles/ 28 hours = 0.083 miles per hour
Velocity in feet per hour = 0.083*5280 feet/hour = 440 feet/hour
Velocity in meters per hour = 0.083 * 1609.344 meters/hour = 134.11 meters/hour.
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a raft with a mass 50 kg and a volume of 0.250 m3 has a weight placed on top of it. how much mass does the weight have to have so that the raft is just barely submerged in pure water
The weight placed on top of the raft so that the raft is barely submerged in pure water is 200Kg.
Mass of raft (mₓ) = 50Kg
Volume of raft (V) = 0.250 m³
Density of pure water (d) = 1000 Kg/m³
Let, weight placed on top of the raft be = m
Using Archimedes Principle and Buoyant Force,
= mg + mₓ × g = V × d × g
= mg + 50 × g = 0.250 × 1000 × g
Taking g common on both sides
= g (m+50) = g(0.250 × 1000)
= m+50 = 250
= m = 200Kg
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suppose a popular fm radio station broadcasts radio waves with a frequency of 104 mhz . calculate the wavelength of these radio waves.
The wavelength of these radio waves are 2.88 m
What are radio waves ?In the electromagnetic spectrum, radio waves have the longest wavelengths. These waves, which fall under the category of electromagnetic radiation, range in frequency from 300 GHz to 3 kHz, though they are sometimes classified as microwaves above 3 GHz.
The given frequency is 104 mhz
Any radiation in the electromagnetic spectrum, including radio waves, travels at a speed of 3.00 x 10^8 m/s in vacuum.
Consequently, the following equation can be used to determine the wavelength:
c = wavelength × frequency
frequency is given in mHz thus we convert it into Hz
and get 104 × 10 ^6
this implies
wavelength = [tex]\frac{3 X 10^8}{104 X 10^6}[/tex]
wavelength = 0.0288× [tex]10^{2}[/tex] m
= 2.88 m
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what is the volume flow rate through the nozzle in l/min ? assume that the water level in the tank is held constant. express your answer in liters per minute.
The volume flow rate through the nozzle in l/min is the amount ( in liter) of fluid travelling through a specific cross sectional area in a unit of time (in minute).
What is volume flow rate?Volume flow rate may sound dull to you when you first hear it, but it is what keeps you alive. In a moment, I'll explain how, but let's first establish volume flow rate. The amount of fluid travelling through a specific cross sectional area in a unit of time is known as the volume flow rate of a fluid. The region across which something is flowing is frequently described using the fancy term "cross sectional area."
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What is 20 miles per hour in feet per second? round to the nearest tenth if necessary.
29.33 ft/sec is speed in feet per second.
20 miles= 105600 ft
1 hour= 3600 second
speed= distance/time
speed=105600/3600
speed=29.33 ft/sec
It is possible to express how much an object's location shifts over time or how much it shifts per unit of time using a scalar variable called speed. It is frequently abbreviated to "s." The distance traveled by an object divided by the duration of the period gives the average speed of the object over the period.
The speed-related metric is time divided by distance. While the meter per second (m/s) is the SI unit of speed, the kilometer per hour (kph) is the most widely used unit in daily life (kph).
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Answer:
figure itout 20
Explanation:
20 -0
why does nuclear fusion require high temperatures and high densities? (select all that apply.)
The nuclear fusion reaction occurs at temperatures approximately 107 degrees Celsius. It takes this high temperature for the nuclei to begin travelling at high speeds, increasing their kinetic energy.
Why are high temperatures required for nuclear fusion?Nuclear fusion is a nuclear reaction that occurs when two light nuclei collide to form a single, heavier nucleus. Because the mass of the new nucleus is smaller than the sum of the original masses, fusion releases energy. According to the concept of mass-energy equivalence, this mass difference indicates that some of the "lost" mass has been turned into energy. Fusion necessitates both extremely high temperatures in order to provide enough energy to hydrogen atoms to overcome proton repulsion. Microwaves or lasers must be employed to heat hydrogen atoms to the required temperatures.
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we actually made an approximation in this lab that the tension (force pulling the cart) is equal to the weight of the washers. make a fbd and write an equation for the washers as they accelerate. based on that equation, explain why is it a reasonable approximation.
The tension (force pulling the cart) is equal to the weight (W) of the washers.
According to the Newton's second law of motion force exerted on a object is directly proportional to the rate of change of momentum and can be written as:
F = [tex]\frac{dp}{dt}[/tex]
Or, F = ma
Where mass multiplied with acceleration due to gravity (a=g) can also be represented as Weight (W) of the object.
So, F = Weight of the object (W)
Hence, the tension (force pulling the cart) is equal to the weight of the washers.
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How much force in newtons is required to accelerate a shootout weighing 4 kg at 21m/s
84 Newton of force is required to accelerate a shootout.
F = ma
F = force,
m = mass, given = 4kg
a = acceleration, given = 21 m/[tex]s^{2}[/tex]
Put these values in formula, F = ma
F = 4 × 21
F = 84 N
Hence, 84 Newton of force is required to accelerate a shootout.
A push or pull of an object is called force. The unit of force is kg m/[tex]s^{2}[/tex] or newton and is represented by N.
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Constants Part A A string is wrapped several times around the rim of a small hoop with a radius of 0.0800 m and a mass of 0.190 kg. The free end of the string is held in place and the hoop is released from rest (see Figure 1)). Calculate the angular speed of the rotating hoop after it has descended 0.550 m Express your answer in radians per second to three significant figures. Figure < 1of1 4.104 rad/s Submit Previous Answers Request Answer X Incorrect: Try Again; 5 attempts remaining 0.0800 m
Previous question
After descending 0.550 m, the rotating hoop moves at a angular speed of 2.3 m/s for a Part A. A little hoop with a radius of 0.0800 m and a mass of 0.190 kg has its rim wrapped in a string multiple times.
As we can see, angular speed is the rate at which an object changes its angles over time, as measured in radians. For angular speed, there is simply a magnitude (a value). It's vital to remember that angular velocity and angular speed both employ the same formula.
In classical geometry, a circle's or sphere's radius (PL: radii) is any line segment that connects the object's Centre to its perimeter; in more contemporary usage, it is also the length of those line segments. Is called as radius.
MR^2 W^2 = Mgy1
W = (Gy1)^1/2/R
W =( (9.80)(0.550))^1/2/0.0800M =29.02 rad/sec
v = Rw = (0.0800*29.01) = 2.3m/s
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Sam, whose mass is 75 kg, straps on his skis and starts down a 50-m-high, 20 ^\circ frictionless slope. A strong headwind exerts a horizontal force of 200 N on him as he skies.
a)Find Sam's speed at the bottom using work and energy.
b)Find Sam's speed at the bottom using Newton's laws.
Thanks!
Sam's speed at the bottom is computed using the Work-Energy Theorem is 15.73m/s.
Sam is moving at a speed of 15.73 m/s near the base of the inclination plane.
Sam's weight is 75 kg, and his height is 50 metres. The slope's inclination is 200 degrees, and its horizontal force is 200 N.
The following formula is used to compute Sam's gravitational potential;
P.E = mgh
P.E = 75 x 9.8 x 50
P.E = 36,750
Friction's work is estimated as follows;
W=F x d
The following formula is used to determine Sam's horizontal distance:
d = 50/tan20,
d = 137.35 metres.
Friction's work is estimated as follows;
W = 200 x 137.36
W = 27,472 J
Sam's speed at the bottom is computed using the Work-Energy Theorem as follows;
W = K.E
36750 - 27472 = 1/2 x 75 x (v)2 - (0)2
v= 15.73m/s
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consider two identical spheres rolling without slipping across rigid horizontal surfaces. sphere 1 has a coefficient of static friction
sphere 1 has a coefficient of static friction because Rolling motion, which combines rotational and translational motion, is something we regularly see all the time.
Consider a variety of situations that involve wheels, such as a car driving down a highway, a plane landing, or a robotic explorer investigating a distant planet. Understanding the pressures and torques associated with rolling motion is crucial in a variety of situations. People have seen rolling motion without slipping ever since the invention of the wheel. As an example, consider the contact between a car's tires and the road's surface. If the driver depresses the accelerator to the floor and the tires spin but the car doesn't move ahead, there must be kinetic friction between the wheels and the road surface. If the driver gently presses the pedal, the car will go ahead and keep the tires from slipping. The fact that the bottom of the wheel is truly at rest with respect to the ground, demonstrating static friction between the tires and the road, most people find weird.
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Do scientific models always have limitations?.
Yes, scientific models have limitations as it is simpler that the original objects.
Models cannot include all the info on the objects that they represent. as an instance, maps cannot consist of all of the details of the functions of the earth including mountains, valleys, and so forth. Hence they have limitations of their own respectively.
All models have barriers because they are now not representative of every feasible state of affairs. They use modern expertise and clinical statistics, but as the ones are subject to exchange, the models based totally on that know-how and statistics are a problem to alternate as properly. Scientific models always have some limitations they will never be completely accurate.
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Steam (18kg/kmol) at 1600psi and 1000°F enters a turbine operating at steady state as shown. P. = 1600 psi Turbine 22% of the entering mass flow is extracted by duct T = 1000° F 2 at 160psi and 450°F. The rest of the steam exits 2 3 Pz = 1 psi at duct 3 at 1psi and 102°F. The turbine develops a power output of 9x108 Btu/hr. Heat transfer to T, = 102°F P2 = 160 psi the surroundings accounts for 7% of the power T, = 450°F output. Neglecting kinetic and potential energy effects and assuming that steam behaves as ideal gas at constant y=1.35, a) Determine the fluid's specific gas constant in Btu/lb/°R. b) Determine the mass flow rate of the steam entering the turbine in lb/hr (Answer: 2.738x10 lb/hr) c) How would your result in part b) change if the inlet pressure is 1700psi and WHY?
The fluid specific gas constant of the steam from the turbine is 0.1103 But/lb/°R, the mass flow rate is 2.7380 lb/ hr and the enthalpy and mass flow rate remain constant and volume changes if there is change in inlet pressure.
(a) Power output = 9 × 10⁸ Btu/hr
Heat transfer to the surrounding accounts = 7% of heat transfer of the output
Gas constant = y = 1.35
Temperature T₁ = 1000° F
Temperature T₂ = 450° F
Temperature T₃ = 120° F
Mass of steam = 18 Kg/Kmol
The fluid specific gas constant = R =
= R = Rₙ / m
= R = 1.986 / 18
= R = 0.1103 But/lb/°R
(b) Mass flow rate of the turbine during entry = Q =
= Q = 7% of the power output
= Q = ( 7 × 9 × 10 ⁸ )/ 100
= Q = 63 × 10 ⁶ Btu/hr
Now power developed by the turbine before steam = m×(h₁ - h₂)
= m × (h₁ - 0.22m)
Power developed by the turbine after steam = m×(h₂ - h₃)
= 0.78m × (h₂ - h₃)
Total Power = m×(h₁ - h₂) + 0.78m × (h₂ - h₃)
Applying the thermodynamics formula,
= [m×(h₁ - h₂) + 0.78m × (h₂ - h₃)] - Q = W
= [m × ( CₐT₁ - CₐT₂) + 0.78m × ( CₐT₂ - CₐT₃)] - Q = W
And we know that , R = Cₐ - Cₙ
and, γ = Cₐ / Cₙ
= Cₐ = (R × γ) / (γ - 1)
= Cₐ = 0.4228 Btu/lb°F
Substituting this in [m × ( CₐT₁ - CₐT₂) + 0.78m × ( CₐT₂ - CₐT₃)] - Q = W
= [m × ( CₐT₁ - CₐT₂) + 0.78m × ( CₐT₂ - CₐT₃)] = W + Q
= m = 963000000 / 347.30
= m = 2.7380 lb/hr
(c)If there is change in the inlet pressure then the volume changes but the enthalpy and mass flow rate remain constant.
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at the time the hypothesis was suggested, what major problem was identified with the idea that the sun was powered by gravitational contraction?
This process would power the Sun for only about 25 million years, but geologists already had evidence the Earth was much older than that.
gravity, additionally called gravitation, in mechanics, the frequent force of appeal performing among all be counted. it's far by way of far the weakest recognized force in nature and for this reason, plays no position in figuring out the inner houses of everyday matter.
The gravitational attraction among the authentic gaseous matter inside the Universe allowed it to coalesce and form stars which finally condensed into galaxies, so gravity is liable for some of the huge-scale structures in the Universe. Gravity has a countless range, although its outcomes become weaker as items get farther away. Gravity is maximum accurately described by way of the overall concept of relativity (proposed by way of Albert Einstein in 1915), which describes gravity now not as a pressure, but as the curvature of spacetime, because of the uneven distribution of mass, and causing loads to transport alongside geodesic strains. the character and mechanism of gravity became explored by way of a wide variety of historical scholars.
In Greece, Aristotle believed that objects fell closer to the Earth due to the fact the Earth turned into the center of the Universe and attracted all of the mass in the Universe in that direction of it. He additionally idea that the velocity of a falling item must boom with its weight, an end which was later shown to be false. while Aristotle's view become extensively conventional throughout historical Greece, there have been other thinkers which include Plutarch who efficaciously expected that the appeal of gravity was not specific to the Earth.
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What is the example of conjunctive adverb?.
A Conjunctive adverb is a word that connects to complete clauses with each other and define their relationship.
An adverb is a word or phrase that defines and qualifies the quality of the verb. That means it tell us that how and when the things are happening for the particular adjective or verb. For an example, fast running. Here, the word fast is the adverb because the word fast is telling us about the nature of running which is fast.
A conjunctive adverb is a word that connects two sentences together.
For an example, He is said since I told him about college.
Here, "He is said" since "I told him".
So, the world "since" is the conjunctive adverb because it is connecting the two complete different sentence.
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How do you find the distance between two objects in physics?.
Because the distance between them is great. The only small mistake that can be made is forgetting to take some square root since what we are trying to do is variable RS-squared.
The distance between two non-pointing objects is usually defined as the minimum distance between pairs of points from the two objects. Formulas are known to calculate the distance between different kinds of objects such as the Distance from point to the line.
The distance between two points is called the line length. Segments of the same length are called congruent segments. You can calculate the distance between two points by drawing a line with a ruler. The distance between two points is the length of the line segment connecting the two points on the plane.
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3. you were able to partially polarize the light reflected off a plate of glass. what happened to the light which passed through the glass?
Polarization occurs to light that passes through the filter. The axes of polarisation of the various light wavelengths will rotate to varying degrees in different sectors of the taped glass.
How does polarised lighting function?A linear polarizer absorbs the orthogonal plane and transmits light that is uniformly vibrating in one plane. We frequently use a concept known as the vibrational pattern to describe a single plane or beam of polarised light. The light is linearly polarised if the vibrations are only in one direction.
What makes polarised light unique?Light becomes polarized—all of it is in one directional field—when it bounces off a surface, like water.
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which has the greater momentum, a concrete truck at rest or a concrete truck moving slowly up a steep hill?
Answer:
Since momentum is the product if mass and velocity therefore a concrete truck at rest has no velocity i.e mass × 0m/s = 0kg m/s
Whereas the momentum of a concrete truck slowly moving up a steep hill will defined by a given value greater than 0
a potter's wheel is spinning with an initial angular velocity of 14 rad/s . it rotates through an angle of 80.0 rad in the process of coming to rest.
The factors remain unrealistic and constant Centre of mass and gravity.
Given - The initial angular velocity is 14rad/s with an angle of rotation is 80rad.
To find out the distance formula.
[tex]Wo-w=\frac{x}{rotation}---[1]\\ \\Q=\frac{1}{4\pi \alpha \beta } -------[2][/tex]
The Rotational effect of wheel has a displacement with angle factor.
The velocity breaking and reducing the speed.
[tex]Q= \lim_{w \to \infty} W_o-w[/tex]
[tex]w=\pi \alpha +Q\\\\w-Q=\alpha \\\\w-Q=\left \{ {{y=x} \atop {y\neq x}} \right.[/tex]
The effect reduced to the decrement in displacement .
This is results in constant angle shift and uniform motion.
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Can scientific models ever be changed?.
Yes, scientific models can be changed.
A scientific model is a bodily and/or mathematical and/or conceptual representation of a system of ideas, occasions or procedures. Scientists are seeking to perceive and recognize patterns in our world through drawing on their scientific understanding to offer motives that enable the styles to be anticipated.
Models are beneficial gear in studying science which may be used to enhance reasons, generate discussion, make predictions, provide visual representations of summary standards and generate intellectual models.
Benefits of modelling and simulation :
* Can be more secure and less expensive than the real international.
* Able to test a product or device works earlier than building it.
* Can use it to discover unexpected troubles.
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 Option analysis involves gathering significant amounts of information, synthesizing the data, and using the data in models applied in option analysis Consider the case of Smith and Thomas Co Smith and Thomas Co. is considering a project for a new cloud-based online storage system for companies and individuals to back up their data. The cost of the project is exist45 million, but the future cash flows depend on how this new cloud-based online storage will compete with existing companies that offer online data backup The company believes that this project has a strong selling feature but is uncertain that it would earn cash flows as projected. The team proposing this project has come up with the following data: The project team also noted that the company has an option to wait for one year in order to see its competitors' positions and observe how the market responds. This will help in getting more information about market demand and in figuring out which set of cash flows will occur Analysts used different approaches to evaluate the project, but the management team insists that the Black-Scholes option pricing model (OPM) will help them make a more informed decision. The model requires five inputs (1) the risk-free rate (2) the time until the option expires: (3) the strike price: (4) the current price of the stock, which in this case would be a proxy for the value of the underlying asset: and (5) the variance of the project's expected return You need to calculate both the value of the underlying asset in the project and its rate of return. For smith and The mass Co., the underlying asset is the project itself. The current value of the project will be the value of its expected cash flows resin Based on the data given, calculate the value of the project, its return, and the standard deviation of the returns (using the direct method) if the company decides to wait for a year. (Cash flow values in the table are in millions.) Analysts will use these values in the Black-Scholes model, which is represented by the following formula: Based on the data collected and results from the calculations, estimate the input values to be used in the Black-Scholes OPM:
1. Risk-free rate 5%
2. Time until the option expires 4 yrs.
3. Strike price: $ 45mn.
4. For calculating project value & standard deviation, we need to fill in the inputs in the below table. For calculating the PV of cash flows, use discounting rate of 13%. Standard deviation: stdev(5.85,4.55,2.6) = 1.64%
5. Sum of expected cash flows at t = 0: 37.61+18.28+4.18 = $ 60.07
The above-numbered figures are the inputs for the Black Scholes model.
The Black-Scholes model is used to determine the fair value of options contracts. This formula can estimate how the price of financial instruments such as futures and stocks change over time. Black-Scholes is used to determine the fair or theoretical value of a call or put option based on six variables including volatility option type underlying price time strike price and the risk-free rate pricing model.
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coma
as the comet accelerates toward the Sun, its surface temperature increases, and ices begin to vaporize into gas that easily escapes the comet's weak gravity
some of the escaping gas drags away dust particles from the nucleus, and the gas and dust create a huge, dusty atmosphere called...
As the comet accelerates toward the Sun, dust particles from nucleus, gas and dust create a huge, dusty atmosphere called a coma
The comet, sometimes known as the "dirty snowball," is fully frozen in essence when it is far from the Sun. We refer to this frozen core as the comet's nucleus when it approaches the sun from the inside. A comet's surface temperature rises as it moves closer to the Sun, and its ices start to evaporate into gas that can readily escape the comet's weak gravity.
The gas and dust combine to form a massive, dusty environment known as a coma when some of the departing gas pushes dust particles away from the nucleus. As the comet moves deeper into the inner solar system, more gas and dust are pushed away from the Sun, generating the comet's tails. The coma also expands throughout this process. The length of a comet's tail can reach hundreds of millions of kilometres.
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rank from least amount of gravitational potential energy to most amount of gravitational potential energy. to rank items as equivalent, overlap them
According to the given statement rank from least amount of Gravitational potential energy.
What kinds of energy are there?Chemical, electrochemical, radiation, muscular, thermal, and nuclear fuel are the six main types of energy. Different forms including electrochemical, acoustic, electromagnetic, and others might be addressed in other studies.
Why is energy so crucial?Energy is a major factor in our everyday routines even though it is an essential need for humans. Our human-made structures are not only heated by energy, but also cooled by it. To lift you finger, climb out of bed, or even stroll down main sidewalk, you need energy.
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assume that light is incident normal to the surface of a film of thickness d . how much farther does the light reflected from the back surface travel than the light reflected from the front surface? express your answer in terms of d .
Therefore the difference in the optical path between the reflected ray on the surface and the end film is Λ = 2 t.
Light or seen mild is electromagnetic radiation that may be perceived by means of the human eye. seen mild is typically defined as having wavelengths inside the range of 400 seven hundred nanometres, corresponding to frequencies of 750420 terahertz, among the infrared and the ultraviolet.
As an adjective, mild is something that is not heavy, burdensome, or somber. A knapsack may be mild, as should a topic of verbal exchange, or a chunk of tune. as an instance, The manner is long, however, the burden is light.
Inside the Bible, mild has continually been an image of holiness, goodness, expertise, information, grace, hope, and God's revelation. via evaluation, darkness has been associated with evil, sin, and despair.
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determine the focal length of a lens in a camera if the film is 36.9 mm away from the lens and the object distance is 59.2 cm.
The focal length of the lens is 39.3 mm. The result is obtained by using the thin lens equation.
What is the Thin Lens Equation?The Thin Lens Equation is the equation used on a thin positive or negative lens.
[tex]\frac{1}{f} = \frac{1}{d_{1} } + \frac{1}{d_{2} }[/tex]
Where
f = focal lengthd₁ = object distanced₂ = image distanceWe have a camera with the film 36.9 mm away from the lens and the object distance is 59.2 cm. Determine the focal length!
Let's convert the object distance's unit!
59.2 cm = 592 mm
The distance of the film from the lens is the image distance. So, the focal length is
[tex]\frac{1}{f} = \frac{1}{d_{1} } + \frac{1}{d_{2} }[/tex]
[tex]\frac{1}{f} = \frac{1}{592 } + \frac{1}{36.9 }[/tex]
[tex]\frac{1}{f} = \frac{(592-36.9)}{21844.8 }[/tex]
[tex]\frac{1}{f} = \frac{555.1}{21844.8 }[/tex]
[tex]f = \frac{21844.8}{555.1}[/tex]
f = 39.3 mm
Hence, the focal length of a lens in the camera is 39.3 mm.
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