The X-component of the force on particle A when it is at X = 0.15 M is most nearly to 20N.
The term "components of the force" refers to these force-related elements. The x-component pushes right or left, while the y-component pushes up or down. These two components are referred to as pushing. The mathematical components behave on the coordinate axes like shadows of the force vector. The x-component extends from the vector's tail to the point where the reference line intersects the x-axis along the x-axis. The vector's y-component extends along the y-axis from the vector's tail to the point where the reference line intersects the y-axis. The horizontal and vertical forces that combine to create a force are represented by the components of a force. The elements of a vector are what I want to discuss. Components are two parallel vectors that add to the provided vector; therefore, let's begin with an illustration.
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Answer:
20 N (E)
Explanation:
We are given potential energy from the graph, so to find the x-component, we can determine the work. We also know that the slope of potential energy is work, so we can do:
Δ∪= -W
Δ∪= -FΔx
F= - du/dx
To find du/dx, we find the slope at x = 0.15 m
du/dx = (-3 - - 0)/(0.25-0.1) = -20 N
Now replace
F= - du/dx
F= - - 20
F = 20 N
Note that it is positive 20 N
I hope this helped :)
your friend anna explains that she believes that everything in the universe is in a constant state of change, so nothing is the same from one moment to the next. which famous philosopher would anna most agree with?
Anna mostly agrees with Heraclitus
Heraclitus of Ephesus was a Greek philosopher who lived before Socrates. He was from the city of Ephesus, which was a part of the Persian Empire at the time.
The life of Heraclitus is largely unknown. He only produced one piece, of which only fragments have survived. Based on interpretations of the preserved fragments, it is now believed that the majority of the ancient stories about him are fabrications. Since antiquity, his paradoxical philosophy, love of wordplay, and appreciation for cryptic expressions have earned him the moniker "the obscure." He was regarded as a miser who suffered from depression. In contrast to the ancient philosopher Democritus, who was referred to as "the laughing philosopher," he became known as "the weeping philosopher" as a result.
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a photographer in a helicopter ascending vertically at a constant rate of 1.2m/s accidentally drops a camera out the winder when the helicopter is 62m above the ground. how long will it take the camera to reach the ground
The time by the camera to reach the ground is 3.43 seconds, if it was initially coming down at the speed of 1.2 m/s.
Initial speed of the camera, u = 1.2 m/s
Acceleration due to gravity, g = 9.81 m/s²
Height of falling, h = 62 m
Let the time taken by the camera, = t
Now, by the second equation of motion
h = ut + 0.5gt²
62 = 1.2×t + 0.5×9.81×t²
4.905t² + 1.2t - 62 = 0
On solving we get, t = 3.435 sec and - 3.68
Ignoring the negative value, t = 3.435 seconds
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a red blood cell contains 2.7 107 free electrons. what is the total charge of these electrons in the red blood cell?
The total charge of these electrons in the red blood cell - 4.3 × 10⁻¹² Coulombs. The result is obtained by multiplying the number of electrons by the charge or each electrons.
What is charge?Charge is a physical property of subatomic particles that causes objects experience a attractive force toward one another.
An electron has the charge of - 1.602 × 10⁻¹⁹ Coulombs. If there are n electron, the charge is
q = ne
Where
q = chargen = number of electrone = charge of an electronA red blood cell contains 2.7 × 10⁷ electrons.
Find the total charge!
The total charge of the electrons in the red blood cell is
q = ne
q = 2.7 × 10⁷ × (- 1.602 × 10⁻¹⁹)
q = - 4.3 × 10⁻¹² Coulombs
Hence, in the red blood cell, the total charge of the electrons is - 4.3 × 10⁻¹² Coulombs.
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If the eastward component of vector is equal to the westward component of vector and their northward components are equal. Which one of the following statements about these two vectors is correct?1) Vector is parallel to vector2) Vectors and point in opposite directions3) Vector is perpendicular to vector4) The magnitude of vector is equal to the magnitude of vector .5) The magnitude of vector is twice the magnitude of vector .
The magnitude of vector A must be equal to the magnitude of vector B
When two vectors are equivalent, what happens?Vector equals vector b. For two vectors to be equal, their magnitudes and directions must be the same. A vector’s components can never have a magnitude bigger than the vector itself. This is demonstrated by Pythagorean’s Thereom. There is a possibility that a component of a vector has the same magnitude as the vector itself. E.g. A=2x + 0y.
According to the parallelogram rule, if two vectors are placed such that they have the same beginning point and then completed into a parallelogram, the total of the vectors is the directed diagonal that starts at the same position as the vectors.
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as you increase the temperature of a gas in a sealed, rigid container, what happens to the density of the gas? would the results be the same if you did the same experi- ment in a container with a piston at constant pressure? explain.
When the temperature of a gas is raised in a tightly sealed, rigid container, the gas's density will not change. In contrast, when the piston is kept at the same temperature in a container, density decreases.
Charles Law: At constant pressure, the volume occupied by the fixed amount of gas is directly proportional to its absolute temperature.
A gas's mass per unit volume is its density. Volume is directly proportional to temperature, as stated by Charles's law. Volume increases as temperature rises. However, in a rigid container, the gas's mass is unaffected by changes in temperature and volume. As a result, even as the temperature rises, density does not change.
The pressure in a container with a piston stays the same. As a result, according to Charles' law, gas density decreases as temperature rises during heating.
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what are the electric potential and the magnitude of the electric field at the center of the square due to all four charges?
The electric potential at the center of the square due to all four charges is 0 volts.
The magnitude of the electric field at the center of the square due to all four charges is 2.83 E₀ N/C.
The complete question is in the attachment. The electric potential from a charge V = kQ/r
k = electrostatic constant = 9 × 10⁹ Nm²/C²q = charge (C)r = distance (m)V = the electric potential (V)The electric potential from four charges
V = V₁ + V₂ + V₃ + V₄
V₁ = V₂ = V₃ = V₄ = V₀The sign of charges is also a sign of electric potential.Q₁ = Q₂ = - QV = V₁ + V₂ + V₃ + V₄
V = - V₀ + (- V₀) + V₀ + V₀
V = 0 Volts
The magnitude of the electric field from a charge E = (k × Q) ÷ r²
E = The magnitude of electric fields (N/C)The direction of the electric field at a point from positive charges away from positive charges.The direction of the electric field at a point from negative charges to negative chargesAt P
Q₁ a negative charge.E₁₃ = E₁ + E₃ = E₀ + E₀ = 2E₀
E₂₄ = E₂ + E₄ = E₀ + E₀ = 2E₀
The angle between E₁₃ and E₂₄ = 90°
E² = E₁₃² + E₂₄² = (2E₀)² + (2E₀)² = 4E₀² + 4E₀² = 8E₀²
[tex]E \:=\: \sqrt{8E_0^2}[/tex]
E = 2√2 E₀
E = 2.83 E₀ N/C
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what step of the scientific method involves looking closely at the physical universe for the purpose of gathering knowledge? reading quiz h abeke 10th grade
The step of the scientific method that involves looking closely at the physical universe for the purpose of gathering knowledge is called observation.
Observation is an essential component of the scientific method and involves the collection of data through the use of the senses, instruments, or other methods. The goal of observation is to gather accurate and reliable information about the natural world, which can then be used to develop hypotheses, test theories, and ultimately deepen our understanding of the universe.
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if the distance to a star was suddenly cut in half, how many times brighter would the star appear?
If the distance to a star was suddenly cut in half, the star would appear 4 times brighter.
We know the expression between the intensity of star and the distance as, I ∝ 1/r²
where,
r is the distance
I is the intensity of light
Here, it is given that the distance is cut down by half, so, r becomes r/2.
Placing it in the above relation, we have, I ∝ 1/(r/2)²
⇒ I ∝ 4/r²
So, the relation says, the intensity becomes 4 times when the distance is reduced to half.
Thus, the star appears to be four times brighter.
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A police siren emits a sound wave of frequency 440 Hz. The speed of sound is 330 m/s. If police jeep moving with speed 20 m/s is following a heavy truck moving with 10 m/s, then frequency of echo from truck heard by a policeman inside the jeep is nearly A.440 HzB.467 HzC.450 HzD.480 Hz
The frequency of the echo from the truck heard by the policeman inside the jeep would be approximately 450 Hz,.
The frequency of the echo heard by the policeman inside the jeep would be different from the frequency of the sound wave emitted by the police siren due to the Doppler effect. The Doppler effect states that the frequency of a wave changes if the source or the observer is in motion relative to the medium through which the wave is traveling.
In this case, the speed of the truck relative to the air is 10 m/s and the speed of the jeep relative to the truck is 20 m/s, so the relative speed of the truck with respect to the air is 10 - 20 = -10 m/s.
The frequency of the echo from the truck heard by the policeman inside the jeep would be given by the following formula:
f = f0 * (v + vr) / (v + vs)
where f0 is the frequency of the sound wave emitted by the police siren, v is the speed of sound, vr is the relative speed of the truck with respect to the air, and vs is the speed of the jeep with respect to the air.
Plugging in the values, we get:
f = 440 Hz * (330 m/s - 10 m/s) / (330 m/s - 20 m/s)
f = 440 Hz * 320 m/s / 310 m/s
f = 440 Hz * 1.03226
f = 453.7 Hz
Therefore, the frequency of the echo from the truck heard by the policeman inside the jeep would be approximately 453.7 Hz, which is closest to option C (450 Hz).
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over 10 seconds, a train accelerates constantly from rest at a rate 3 m/s2. how far does the train travel during this time period.
Over 10 seconds, a train accelerates constantly from rest at a rate 3 m/s². The distance covered by the train is 150 m.
Let us assume that, the distance covered by the train is s.
It is given that,
Time of travel, t = 10s.
The acceleration of the train, a = 3 m/s².
The initial velocity of the train, u = 0.
It is known that, [tex]s=ut+\frac{1}{2}at^2[/tex].
[tex]\Rightarrow s=[(0)(10)+\frac{1}{2}(3)(10)^2]m\\\Rightarrow s=[0+\frac{1}{2}\times3\times100]m[/tex]
⇒ s = (1/2) × 300 m
⇒ s = 150 m
Hence, the distance covered by the train is 150 m.
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fill in the blanks.
a.Pressure is the..............applied per unit area.
b.The pressure..................as the depth of liquid increases.
a spinning disk has a mass of 0.5 kg and a radius of 0.2 m. the disk is spinning at an angular velocity of 2 rad/s. what is the angular momentum of the disk? (i
Angular momentum in the absence of any external torque remains constant.
What is the angular momentum of the disk?
Suppose we have a disk of radius r and mass m travelling at velocity v. I want to calculate the instantaneous angular momentum with axis through the edge of the disc (on the circumference). Angular momentum =Iω. I=12mr2+mr2=32mr2 by the parallel axis theorem.The angular momentum of a particle rotating about an axis is defined as the moment of the linear momentum of the particle about that axis. It is measured as the product of linear momentum and the perpendicular distance of its line of action from the axis of rotation.Angular momentum is basically the product of the moment of inertia of an object and its angular velocity. Furthermore, both the quantities must be about the equal and the same axis i.e. the rotation line.
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4. An astronaut at rest in space with mass 84 kg fires a thruster that expels 35 g of hot gas at 875 m/s. What is the velocity of the astronaut after firing the thruster?
Answer:
The impulse (change in momentum) experienced by the astronaut is given by the product of the force applied and the time over which it is applied. The force applied is given by the rate at which mass is expelled multiplied by the velocity at which it is expelled, which is (35 g * 875 m/s) = 30.625 N.
The impulse experienced by the astronaut is equal to the change in momentum, which is given by the initial mass multiplied by the final velocity, so we can set up the following equation:
m_initial * v_initial = m_final * v_final
where m_initial = 84 kg (mass of astronaut) and m_final = 84 kg (mass of astronaut + 35 g of hot gas).
Solving for v_final, we get:
v_final = m_initial * v_initial / m_final
= 84 kg * 0 m/s / 84 kg
= 0 m/s
So the astronaut's velocity does not change after the thruster is fired because the velocity of the expelled gas is in the opposite direction to the astronaut's motion, they are canceling out.
Compare the different preure that reult a you add air to a balloon
and a you add air to a teel tank
When you add air to a balloon, the pressure inside the balloon increases, causing it to expand.
This is because the air pressure outside the balloon is greater than the air pressure inside the balloon. On the other hand, when you add air to a steel tank, the pressure inside increases as well, but the steel tank is able to withstand much higher pressure than a balloon, so the pressure inside the steel tank will not increase as quickly.
When air is added to a balloon, the air pressure inside the balloon increases and causes the balloon to expand. This is because the air pressure outside the balloon is greater than the air pressure inside the balloon, so the pressure inside the balloon increases faster than the pressure inside the steel tank.
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In a continous Series, the average weight. of Some Students is 45kg and the Sum of their weight is 540kg. find the number of students
In a continuous series, some students have average weights of 45 kg, and the total of their weights is 540 kg. How many students are there? Ans: 12.
How do you find the average of a continuous series?The process is straightforward: you locate the midpoint from X, multiply the results by F, add them up to find summation fm, where m stands for the midpoint from X, and then divide the total by summation F.In continuous series, the observations are presented in several class intervals rather than by a single number, and the frequency corresponds to the number of data falling within that class interval.Finding a function's average value requires taking its integral across the interval and dividing it by the interval's length.Any value x at which a continuous probability distribution's probability density function reaches its locally maximum value is sometimes regarded as the distribution's mode.To learn more about average refer to:
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Which equation can be used to calculate the time of impact when you have the impulse and force applied to an object?
Answer:
t=J/F
Explanation:
We know that impulse is given by J = Ft
where F is the force applied and t is the time of impact
Rearranging the equation, we get,
t = J/F
1. If a 5 tons beam is raised 6 meters, what is it's potential energy? If it is raised another 8 meters in 6 seconds, what is the work done?
If a 5 tons beam is raised 6 meters, then its potential energy is 294kJ and if it is raised another 8 meters in 6 seconds, the work done is 392kJ
Given the weight of beam(m) = 5tons
The height the beam raised (h) = 6m
We know that potential energy is equal to the weigh raised to a certain height such that PE = mgh where g is the gravitational acceleration.
We know that an object can store energy depending on its position. When a bow and arrow are employed, the kinetic energy of the arrow is provided by the energy accumulated when the bow is drawn.
PE = 5 x 1000 x 9.8 x 6 = 294000J = 294kJ (1 ton = 1000kg)
Hence the potential energy required is 294kJ
In the other case the height the beam raised = 8m
Time taken to raise = 6s.
But potential energy is irrelevant to time. So,
PE = 5000 x 9.8 x 8 = 392 KJ
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9. A 45.0 kg ice skater stands at rest on the ice. A friend tosses the skater a 5.0 kg ball. The skater and the ball then move backwards across the ice with a speed of 0.5 m/s. What was the speed of the ball at the moment just before the skater caught it?
Answer:
The speed of the ball at the moment just before the skater caught it can be found using the conservation of momentum principle. According to the principle, the total momentum of the system before the collision (ball moving towards skater) is equal to the total momentum of the system after the collision (ball and skater moving backwards).
The momentum of the ball before the collision is m_ball * v_ball, where m_ball is the mass of the ball and v_ball is the speed of the ball. The momentum of the skater before the collision is 0, since she is at rest.
The momentum of the ball and skater after the collision is (m_ball + m_skater) * v_after, where v_after is the final speed of the ball and skater moving backwards.
So, we can set up the equation:
m_ball * v_ball = (m_ball + m_skater) * v_after
We know that the final speed of the ball and skater is 0.5 m/s and we know the masses of the ball and skater.
Solving for v_ball:
v_ball = (m_ball + m_skater) * v_after / m_ball
v_ball = (5.0 kg + 45.0 kg) * 0.5 m/s / 5.0 kg
v_ball = 9.0 m/s
Therefore, the speed of the ball at the moment just before the skater caught it was 9.0 m/s.
What is refraction? please answer it help me
Answer: Refraction is the bending of light (it also happens with sound, water and other waves) as it passes from one transparent substance into another.
Explanation:
The picture shows two teenagers riding identical skateboards.
The skateboards are moving at the same speed and the teenagers have the same mass.Explain why the teenagers don’t have the same momentum
The teenagers do not have the same momentum because momentum is a vector quantity, meaning it has both a magnitude and a direction. While the skateboards are moving at the same speed, they could be moving in different directions,
which would result in different momentum values. Additionally, the teenagers themselves could be moving at different speeds in relation to the skateboards, which would also affect their momentum. Even though the teenagers have the same mass, their momentum will be different based on their velocity or direction of motion.
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2. A 1250 kg car is moving down the highway with a velocity of 32.0 m/s when it bumps into the car ahead of it which has a mass of 875 kg and a velocity of 25.0 m/s. After the collision, the two cars stick together. What will be the resulting velocity of the two cars together? How much energy will be lost in this collision?
Answer:
The resulting velocity of the two cars together can be calculated using the law of conservation of momentum, which states that the total momentum of the system before the collision is equal to the total momentum after the collision. The momentum of the first car before the collision is 1250 kg * 32 m/s = 40,000 kg m/s and the momentum of the second car before the collision is 875 kg * 25 m/s = 21,875 kg m/s. The total momentum before the collision is 61,875 kg m/s.
After the collision, the two cars stick together, so the final velocity of the two cars together is the same. Therefore, the momentum of the two cars together after the collision is (1250 kg + 875 kg) * v = 2125 kg * v = 61,875 kg m/s. Solving for v, the final velocity of the two cars together is v = 61,875 kg m/s / 2125 kg = 29.2 m/s.
The energy lost in the collision can be calculated using the equation E = 1/2 * m * v^2, where m is the mass of the system and v is the change in velocity. The mass of the system is 2125 kg and the change in velocity is 32 m/s - 29.2 m/s = 2.8 m/s. Therefore, the energy lost in the collision is E = 1/2 * 2125 kg * (2.8 m/s)^2 = 1/2 * 2125 kg * 7.84 m^2/s^2 = 6614.4 J (Joules).
Answer:
Energy lost in the collision = approximately 6.14 x 10^6 Joules.
Explanation:
The resulting velocity of the two cars together can be found using the principle of conservation of momentum. The total momentum before the collision is the momentum of the first car plus the momentum of the second car, and this total momentum will be equal to the total momentum after the collision.
Momentum = mass x velocity
Total momentum before collision = (1250 kg x 32.0 m/s) + (875 kg x 25.0 m/s) = 40,000 kg m/s
Total momentum after collision = (1250 kg + 875 kg) x velocity = 2125 kg x velocity = 40,000 kg m/s
Velocity = 40,000 kg m/s / 2125 kg = 18.84 m/s
To find the energy lost in the collision, we can use the equation for the change in kinetic energy (1/2 * m * (vf^2 - vi^2))
Change in kinetic energy = 1/2 * (1250 kg + 875 kg) * (18.84 m/s - (32.0 m/s + 25.0 m/s))^2 = 1/2 * 2125 kg * (-33.16 m/s)^2
= 1/2 * 2125 kg * 1103.69 m^2/s^2
Energy lost in the collision = approximately 6.14 x 10^6 Joules.
How long will it take for the plutonium to no longer exist?
Answer: Plutonium has a half life of 24,000 years meaning for plutonium to decay naturally, it would take 240,000 years.
Answer:
The time required for a radioactive substance to lose 50 percent of its radioactivity by decay is known as the half-life. Plutonium-238, plutonium-239, and plutonium-240 are isotopes of plutonium, and have half-lives of 87 years for plutonium-238, 24,065 years for plutonium-239, and 6,537 years for plutonium-240.
Explanation:
phase of matter that consists of charged particles
The plasma state of matter is made up of electrically charged particles of gaseous matter.
What is the state of the matter?In physics, the term "state of matter" refers to one of the various states in which matter can exist. The solid, liquid, gas, and plasma states of matter can all be observed in daily life.
A gas of ionised atoms that conducts electricity and has almost equal amounts of positively and negatively charged particles is referred to as plasma in physics. That is a common name for the fourth state of matter, which is distinct from the solid, liquid, and gaseous states.
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Complete Question"
What state of matter consists of electrically charged particles ?
hree thin rods of length l are arranged in an inverted u. the two rods on the arms of the u each have mass m; the third rod has mass 3m. where is the center of mass of the assembly?
The y coordinate of the center of mass of the system is located at L/5. In this system, the two rods on the arms of u each have a mass of m; the third rod has a mass of 3m.
Substitute 0 for x₁, L/2 for x₂, and L for x₃ in the equation
Xcom = Mx₁+(3M)x₂+Mx₃/M+3M+M
Xcom = M(0)+(3M)(L/2)+M(L) / M+3M+M
= 5ML/2(5M)
= L/2
Therefore, the x coordinate of the center of mass of the system is located at L/2.
Similarly, substitute -L/2 for y₁, 0 for y₂, and -L/2 for y₃ in the equation,
Ycom = My₁+(3M)y₂+My₃ / M+3M+M,
Ycom = M(-L/2)+(3M)(0)+M(-L/2) / M+3M+M
= -ML/5ML
= -L/5
The negative sign highlights the fact that the point is in the downward direction relative to the origin. Therefore, the y coordinate of the center of mass of the system is located at L/5.
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what is the resolving power of the medium power objective if the condensor numerical aperture is 1.25, the medium power objective numerical aperture is 0.75, and the wavelength of light used is 520 nm?
The resolving power of the medium power objective in this case is 346.67 nm.
The resolving power of a microscope objective is a measure of its ability to distinguish two closely spaced objects. It is determined by the wavelength of light used and the numerical aperture (NA) of the objective. The NA is a measure of the ability of the objective to gather light from a sample and focus it onto the image plane. The higher the NA, the greater the resolving power. In this case, the NA of the medium power objective is 0.75 and the wavelength of light used is 520 nm. Using these values, we can calculate the resolving power as:
Resolving power = λ / (2 × NA)
Resolving Power = 520 nm / (2 × 0.75)
Resolving power = 520 nm / 1.5
Resolving power = 346.67 nm
So the resolving power of the medium power objective in this case is 346.67 nm.
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How long will it take for the plutonium to no longer exist?
It will take 8 years for the plutonium to no longer exists.
Plutonium is extremely uncommon. On Earth, there are only traces of it. Currently, NASA only has roughly 77 pounds of plutonium-238 available. Other radioactive isotopes can also be used as a heat source for an RTG, but plutonium-238 is a particularly effective one.
It decays more rapidly as it ages due to its half-life. Therefore, even when they are not consuming any of it, their supply is gradually running out. It will only take 8 years for NASA to run out of plutonium and the prospect of finding more in time for their next deep space mission is dim.
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a long, straight uniformly charged wire has a net charge per unit length of 2.58 coulombs/meter. what is the magnitude of the electric force in newtons exerted by this wire on a proton that is located a perpendicular distance 6.09 meters away from the wire?
The magnitude of the electric force in newtons exerted by this wire on a proton is 5.99 x 10¹⁰ N.
What is the magnitude of the electric force?
The magnitude of the electric force in newtons exerted by this wire on a proton that is located a perpendicular distance 6.09 meters away from the wire is calculated as follows;
F = Eq
where;
E is the electric field strengthq is the chargeF = ( kq² ) / r
where;
k is coulombs' constantr is the position of the chargeF = ( 9 x 10⁹ x ( 2.58 x 6.09 )² ) / ( 6.09² )
F = 5.99 x 10¹⁰ N
Thus, the electric force exerted by the charge is a function of the charge magnitude and the distance of the charge.
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Find the magnitude of the total electric force exerted on the charge q1.
The magnitude of the total electric force acting on q₁ charge is 1.487 Newton.
What is electric force?
Electric force is the attracting or repulsive interaction between any two charged things. Similar to any force, Newton's laws of motion describe how it affects the target body and how it does so.
The magnitude of the total electric force acting on q₁ charge is = kq₁/d²√(q₂² +q₃²)
= {8.99 × 10⁹ × (2.1 × 10⁻⁶)² √(2.0² + 3.0²) } ÷ (0.31)² Newton
= 1.487 Newton.
Hence, the magnitude of the total electric force acting on q₁ charge is 1.487 Newton.
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how much compression is exerted on the radius at the elbow joint when the biceps brachii, oriented at a 30° angle to the radius, exerts a tensile force of 200 n
The compression exerted on the radius at the elbow joint is approximately 70 N.
To calculate the compression exerted on the radius at the elbow joint, we must consider the vector components of the tensile force exerted by the biceps brachii.
The biceps brachii muscle is oriented at a 30° angle to the radius, which means that the force it exerts can be divided into two components: one perpendicular to the radius (the compression force), and one parallel to the radius (the tensile force).
Using trigonometry, we can calculate the perpendicular component of the force as follows:
compression force = 200 N * cos(30°) = 173 N
This means that the compression force is 173 N. However, it's important to note that this is an idealized calculation and does not take into account the effects of other muscles and tendons that may be present at the elbow joint, which can affect the actual compression force.
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The internal energy of an ideal gas is changed by adding heat Q to the system and also by doing work W on the gas. What is the change in internal energy of the gas?
A)Q - 4.186W
B)Q - W
C)Q + W
D)W - Q
E) 4.186Q - W
When an ideal gas's internal energy is altered by both doing work W on the gas and introducing heat Q to the system, the result is Q - W.
Given the heat added = Q
Since the work is done on the system = W
We know that the change in internal energy is represented s:
ΔU = Q - W
The function's initial and final states determine the change in internal energy (U), whereas Q and W also depend on the path taken. The internal energy increases when the temperature does, and vice versa. The system's internal energy grows by the amount, U = Q, when the amount of heat Q is introduced to it while the system remains motionless. In the case of an endothermic reaction, the system produces heat and q has a positive sign. The system loses energy whenever it performs any work, hence the sign of w is negative.
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