The proportion as a percentage is calculated as: 37.65%.
How to Write a Proportion as a Percentage?To write a proportion as a percentage, divide the numerator by the denominator and multiply by 100. The resulting decimal value is the percentage.
Therefore, to write the proportion as a percentage, we need to divide the number of Year 8 pupils in the music club by the total number of pupils and multiply by 100:
(32 / 85) x 100 = 37.65%
So, the proportion of Year 8 pupils in the music club is 37.65%.
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Meryl pays £400 into her sister's South African bank account. How much money did her sister receive if the current exchange rate is £1 = R19,29?
The price of one currency in respect to another is referred to as its exchange rate.
What is meant by current exchange rate?An exchange rate in the world of finance is the price at which one currency will be exchanged for another. The majority of the time, currencies are national ones, but they can also be supra-national ones like the euro or sub-national ones like Hong Kong.
A currency's price in relation to another is known as its exchange rate. You can have fixed or fluctuating exchange rates. While a country's central bank controls fixed exchange rates, the process of supply and demand on the open market controls floating exchange rates.
The rate at which one currency can be exchanged for another between countries or economic zones is known as the exchange rate. It is crucial in assessing trade and capital movement dynamics and is used to calculate the value of various currencies in respect to one another.
Convert the currency:
£ 400 × R 19.29/£2 = R 7,716
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$375,000 zero interest loan
Quarterly payments of $18,000 for 5 years
Market rate of interest is 10%
1. What amount should be recorded for the asset purchase?
2. And what amount should be recorded for the liability used to purchase it?
The amount that should be recorded for the asset purchase is $375,000. This is the amount of the loan that is being used to purchase the asset.
The amount that should be recorded for the liability used to purchase the asset is also $375,000. This is the amount of the loan that is being taken on to purchase the asset.
I need help with this x4 + 2x3 + x + 2
The factor of the expression could be [tex](x + 1)(x + 2)((x^2 -x + 1)[/tex]
What is factorization?Factorization is expressing a mathematical quantity in terms of multiples of smaller units of similar quantities.
factorization is the method of breaking a number into smaller numbers that multiplied together will give that original form.
We are given a expression as;
[tex]x^4 + 2x^3 + x + 2[/tex]
Thus,
[tex](x^4 + 2x^3) + (x + 2)[/tex]
Factor out x^3
[tex]x^3(x + 2) + (x + 2)[/tex]
Then;
[tex](x^3 + 1)(x + 2)[/tex]
Therefore, the factor of the given expression is;
[tex](x + 1)(x + 2)(x^2 -x + 1)[/tex]
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4. Determine the equation of the parabola with x-intercepts
a) -4 and 3, and that passes through (2, 7)
b) 0 and 8, and that passes through (-3, -6)
c) √7 and - √7, and that passes through (-5, 3)
5. Determine the equation of the parabola with vertex
a) (-2, 5) and that passes through (4, -8)
Answer:
4.
a.) -7/6 (x + 4)(x - 3) = y
b.) -6/121 (x-8)^2 = y
c.) 1/6 (x-sqrt 7)(x + sqrt 7) = y
5.
a.) -13/36 (x+2)^2 + 5 = y
Step-by-step explanation:
4. The intercept form of a quadratic equation is
[tex]y=a(x-p)(x-q)[/tex], where a is a number determining things like if the parabola opens up or down and how wide or narrow the parabola, while p and q are the x-intercepts.
Because we're given the x-intercepts and a point on the parabola, we can simply plug everything in and solve for a to find the equation of the parabola:
a.):
[tex]y=a(x-(-4))(x-3)\\y=a(x+4)(x-3)\\\\7=a(2+4)(2-3)\\7=a(6)(-1)\\7=-6a\\-7/6=a\\\\y=-7/6(x+4)(x-3)[/tex]
b.):
[tex]y=a(x-8)^2\\\\-6=a(-3-8)^2\\-6=a(-11)^2\\-6=121a\\-6/121=a\\\\y=-6/121(x-8)^2[/tex]
c.):
[tex]y=a(x-\sqrt{7})(x-(-\sqrt{7}))\\ y=a(x-\sqrt{7})(x+\sqrt{7})\\ \\ 3=a(-5-\sqrt{7})(-5+\sqrt{7})\\ 3=a(25-5\sqrt{7}+5\sqrt{7}-7)\\ 3=a(25-7)\\ 3=18a\\ 3/18=1/6=a\\ \\ 1/6(x-\sqrt{7})(x+\sqrt{7})=y[/tex]
5. The vertex form of a quadratic equation is
[tex]y=a(x-h)^2+k[/tex], where a is the same type of number as in the intercept form and (h, k) is the vertex.
Like the intercept form of the equation, we're given everything except a and thus we can plug in what we have and solve for a:
[tex]y=a(x-(-2))^2+5\\y=a(x+2)^2+5\\\\-8=a(4+2)^2+5\\-8=a(6)^2+5\\-8=36a+5\\-13=36a\\-13/36=a\\\\y=-13/36(x+2)^2+5[/tex]
27. (a) Verify that if c is a constant, then the function defined piecewise by So = for x =c, y(x) = (x – c)2 for x > 0 satisfies the differential equation y' = 2 y for all x (in- cluding the point x = c). Construct a figure illustrating the fact that the initial value problem y' = 2/7, y(0) = 0 has infinitely many different solutions. (b) For what values of b does the initial value problem y' = 2/y, y(0) = b have (i) no solution, (ii) a unique solution that is defined for all x?
(a) Verifying that y(x) = (x - c)^2 satisfies the differential equation y' = 2y:
To verify that the function y(x) = (x - c)^2 satisfies the differential equation y' = 2y, we can find the derivative y' and substitute it back into the equation:
y' = d/dx [(x - c)^2] = 2(x - c)
So, y' = 2y if and only if 2(x - c) = 2y, which can be simplified to x - c = y.
Therefore, y(x) = (x - c)^2 satisfies the differential equation y' = 2y for all x, including x = c.
(b) Values of b for which the initial value problem y' = 2/y, y(0) = b has no solution or a unique solution:
(i) No solution: If b = 0, the initial value y(0) = 0 and the denominator of the right-hand side of the differential equation y' = 2/y would be 0, making the equation undefined at that point. Therefore, the initial value problem y' = 2/y, y(0) = 0 has no solution.
(ii) Unique solution defined for all x: For all other values of b (b ≠ 0), the initial value problem y' = 2/y, y(0) = b has a unique solution that can be found using standard methods of solving initial value problems. This solution will be defined for all x.
The figure illustrating the fact that the initial value problem y' = 2/7, y(0) = 0 has infinitely many different solutions would show a family of curves that are all solutions to the differential equation y' = 2/7, with different starting values y(0) leading to different curves. This demonstrates that there are infinitely many different solutions to the initial value problem.
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Use the distributive property to remove the parentheses. -(-2y-4u+2)
Answer:
below
Step-by-step explanation:
This is the same as (-1)(-2y-4u+2) = 2y + 4u - 2
Please help me with the following question.
a) The percentage of test takers that scored 1420 or higher is of: 2.87%.
b) The percentage of test takers that scored 800 or lower is of: 10.03%.
c) The percentage of students between 1500 and 1600 is given as follows: 0.8%.
d) The number of students eligible for the honors program is given as follows: 1040 students.
How to obtain probabilities using the normal distribution?The z-score of a measure X of a variable that has mean symbolized by [tex]\mu[/tex] and standard deviation symbolized by [tex]\sigma[/tex] is obtained by the rule presented as follows:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The z-score represents how many standard deviations the measure X is above or below the mean of the distribution, depending if the obtained z-score is positive or negative.Using the z-score table, the p-value associated with the calculated z-score is found, and it represents the percentile of the measure X in the distribution.The mean and the standard deviation for this problem are given as follows:
[tex]\mu = 1050, \sigma = 195[/tex]
The proportion of scores of 1420 or higher is one subtracted by the p-value of Z when X = 1420, hence:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
Z = (1420 - 1050)/195
Z = 1.9
Z = 1.9 has a p-value of 0.9713.
1 - 0.9713 = 0.0287 = 2.87%.
The proportion of test takers that scored 800 or lower is the p-value of Z when X = 800, hence:
Z = (800 - 1050)/195
Z = -1.28.
Z = -1.28 has a p-value of 0.1003.
The proportion between 1500 and 1600 is the p-value of Z when X = 1600 subtracted by the p-value of Z when X = 1500, hence:
Z = (1600 - 1050)/195
Z = 2.82
Z = 2.82 has a p-value of 0.9976.
Z = (1500 - 1050)/195
Z = 2.31
Z = 2.31 has a p-value of 0.9896.
Hence:
0.9976 - 0.9896 = 0.008 = 0.8%.
The proportion above 1550 is one subtracted by the p-value of Z when X = 1550, hence:
Z = (1550 - 1050)/195
Z = 2.56
Z = 2.56 has a p-value of 0.9948.
Hence:
1 - 0.9948 = 0.0052.
Out of 200,000 students, the number is given as follows:
0.0052 x 200,000 = 1040 students.
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what is the constant in 8b + 3.2
what is the correct answer
The required meaning of the word sped is A special education student.
What is a noun?The noun is defined as any word used to identify any of class of people, places, or things are called noun.
Here,
Sped is a noun word that tends is meaning toward education, which has meaning as special education student. The plural of sped is speds while in british english sped is used as a verb past tense and past participle of speed.
Thus, the required meaning of the word sped is A special education student.
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solve the equation x−2=−9
Answer:
Step-by-step explanation:
x-2=-9
Add 2 on both sides
x=-7
Answer:
[tex]x=11[/tex]
Step-by-step explanation:
x−2=9
Add 2 to both sides.
x=9+2
Add 9 and 2 to get 11.
x=11
pls tell me if wrong
Let A, and A2 be subsets of a set U. Draw a Venn diagram of this situation and shade in the subsets Ain A2, Ag n A2. Ain As, and A§n AS . Use the resulting diagram and the definition of partition to convince yourself that the subset of these four subsets that are nonempty form a partition of U.
Set A is a subset of set B if every element of A is also an element of B
In a Venn diagram, what is a subset?If every element of set A is also an element of set B, then set A is a subset of set B. This is expressed in symbols as A B or. For example, suppose you’re representing all of the nations in the globe, and set A represents Finland and Greece, while set B represents all of Europe.
If a set A is a subset of a larger set B, the circle representing set A is drawn within the circle representing set B.
If sets A and B share certain components, we can symbolize them by drawing two overlapping circles.
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identify the nominal categorical variables in this study. (select all that apply.) A. voting yes percentage B. country C. issue type D. city E. year F. there are no nominal categorical variables.
Nominal categorical data is a categorical variable with two or more values, with no order. The examples of nominal categorical data here are the issue type, country, city.
Categorical data can be divided as two as per the variables. They are nominal and ordinal. In nominal categorical data, there will be two or more data points, but they are not ranked. The hair color can be red/blond/brown/black etc. But these cannot be ranked by taking one over the other.
In ordinal categorical data, there we can assign an order on the data points. Like grading system in marks of students, size comparison like large, medium, small. Here we could rank these in order.
Year can sometimes be nominal and sometimes ordinal. It is as per the context. If we are using it to calculate time it is ordinal.
So here we could not rank of variables in country, issue type, city. So all are nominal categorical data.
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the first 4 terms in a sequence are 8,5,2,-1... What is the recursive equation?
Consider the initial value problem
2 t y^{\,\prime} = 8 y, \ \ \ y(-1) = 2.
Find the value of the constant C and the exponent r so that y = C t^r is the solution of this initial value problem.
y = help (formulas)
Determine the largest interval of the form a < t < b on which the existence and uniqueness theorem for first order linear differential equations guarantees the existence of a unique solution.
help (inequalities)
What is the actual interval of existence for the solution (from part a)?
The actual interval of existence for the solution is all real numbers, including t = 0.
a. The characteristic equation for the differential equation is
2t dy/dt = 8y,
which gives us
dy/dt = 4/t y.
Separating variables, we have
dy/y = 4/t dt,
which integrates to
ln|y| = 4 ln|t| + C,
where C is an arbitrary constant of integration.
Taking the exponential of both sides, we obtain
|y| = Ce^(4ln|t|),
which gives us
y = C t^4.
Using the initial condition y(-1) = 2, we can find the value of C:
y(-1) = C(-1)^4
2 = C(-1)^4
C = -2.
So the solution to the initial value problem is
y(t) = -2 t^4.
b. The largest interval of the form a < t < b on which the existence and uniqueness theorem for first order linear differential equations guarantees the existence of a unique solution is t ≠ 0, since the coefficient of the differential equation is undefined at t = 0.
c. The actual interval of existence for the solution is all real numbers, including t = 0.
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Which expression is equivalent to (16x^4)^1/2
The expression that is equivalent to (16x^4)^1/2 is (64x^6)1/3.
What are equivalent expressions?Equivalent expressions are expressions that accomplish the same thing even when they have distinct appearances. Two algebraic expressions that are equivalent share a similar value whenever we enter exact same thing for the variable.
Given that;
[tex](16x^4)^{\frac{1}{2}}[/tex]
[tex]=\sqrt{16x^4}[/tex]
= 4x²
From the given options, (64x^6)^1/3 verifies the identity and shows that it is equivalent to (16x^4)^1/2.
[tex](16x^4)^{\frac{1}{2}} = (64x^6)^{\frac{1}{3}}[/tex]
[tex](16x^4)^{\frac{1}{2}} = (4^3)^{\frac{1}{3}} (x^6)^{\frac{1}{3}}[/tex]
[tex]4x^2= (4) (x^6)^{\frac{1}{3}}[/tex]
[tex]4x^2=4x^2[/tex]
Therefore, we can conclude that the expression that is equivalent to (16x^4)^1/2 is (64x^6)1/3
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How do I complete this
Answer:
Point A: y = 552
Point B: y = 123
Step-by-step explanation:
y = -13x - 46
A: x = -46
y = -13(-46) - 46 ==> plugin -46 for x in y = -13x - 46
y = 598 - 46
y = 552
A: x = -13
y = -13(-13) - 46 ==> plugin -13 for x in y = -13x - 46
y = 169 - 46
y = 123
i don’t have a question
Answer: Oh well how you doing?
Step-by-step explanation:
If needed call prevention hotline... if you know what I mean
Answer:
that’s brazy
Step-by-step explanation:
Can someone help me with question number 3 and 4 please?
3) The components of composition between two functions are [tex]f(n) = n^{2}+ 5^{n}[/tex] and g(n) = n² + 1.
4) The composition between functions g(n) = √(4 + n + √n) and h(n) = n⁴ + 8 is the function (g ° h)(n) = √[4 + n⁴ + 8 + √(n⁴ + 8)].
How to apply composition between functions
In this problem we find two cases of composition between functions, that is, a operation between two functions, so that the input of the first function (f(x)) is substituted by the entire second function (g(x)), that is:
f ° g(x) = f [g(x)]
Case 3 - If we know that [tex](f\,\circ \,g) (n) = (n^{2}+1)^{2}+5^{n^{2}+1}[/tex], then the components of the composition of functions are:
[tex]f(n) = n^{2}+ 5^{n}[/tex]
g(n) = n² + 1
Case 4 - If we know that g(n) = √(4 + n + √n) and h(n) = n⁴ + 8, then the composition between the two functions is:
(g ° h)(n) = √[4 + n⁴ + 8 + √(n⁴ + 8)]
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The function f(x) = 1.1x³-36x² +260x + 550 below models the number of discharges from the military, f(x), of active-duty gay service members under the "don't ask, don't tell years after 1994. Complete parts a and b.
The slope of the secant line is 137.
What is the rate of change of discharges between 1994 and 1995?The rate of change of discharges between 1994 and 1995 can be determined by taking the first derivative of the function, f'(x) = 3.3x² - 72x + 260. When x = 1994, the rate of change is -6. This means that the discharges decreased by 6 from 1994 to 1995.
The average rate of change of discharges from 1994 to 2000 can be determined by taking the average of the first derivative of the function for x = 1994 and x = 2000. When x = 1994, the first derivative is -6 and when x = 2000, the first derivative is 148. The average rate of change of discharges from 1994 to 2000 is therefore 71.
f(0) = 1.2 (0)3-36 (0)2+262/0)+570 = 570
+(4) = 1-2(4)3-36(4)2 +262 (4) +570 = 1118.8
Slope of the secant line = [tex]\dfrac{1118.8 - 570}{4-0}[/tex]
Slope of the secant line = 137
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Please answer all questions (If correct will give brainliest)
1. Prove or Disprove the figure defined by points A,B,C, and D is a rhombus.
2. Prove or Disprove that point (4.00,4.50) lies on circle O centered at the origin.
3. Prove the diagonals of the rhombus ABCD bisect each other.
The coordinates (4.0 , 4.5) to the center is not the distance of radius
How to show that diagonals of the rhombus ABCD bisect each other?From the circle formula centered at origin: x² + y² = r²
Where r is the radius of the circle. and by substitution for the various values of x, y and r we have
x² + y² = 6² = 36
Also, substituting the values of the lengths of the line we have
(4)² + (4.5)² = 16 + 20.25 = 36.25 ≠ 36
This proves the diagonals of the rhombus ABCD bisect each other
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1kg/2.2lbs = X/165lbs
The answer is X=165 lbs (or) 74.84 kg.
Solution:
Given,
1kg/2.2lbs = X/165lbs,
So we get 1kg×165lbs= 2.2lbs×X,
By converting kg to lbs ∵ 1 kg= 2.2 lbs,
X=165 lbs.
∴ Hence X=165 lbs
q>d, if = 3 pls tell me the right answer
Sorry but i can't really read the writing so... Maybe try take a pic again
the length of a rectangle is (2x + 3) ft. and the width is (x - 4) ft. Find the perimeter and area in terms of x.
The perimeter of the rectangle is (6x - 2)ft and the area of the rectangle is (2x^2 - 5x - 12) square ft.
What is a rectangle?
A rectangle is a sort of quadrilateral with parallel sides that are equal to one another and four vertices that are all 90 degrees apart. Because of this, it is also known as an equiangular quadrilateral.
We are given that the length of a rectangle is (2x + 3) ft. and the width is
(x - 4) ft.
We know that perimeter of rectangle = 2(Length + Width)
So,
⇒Perimeter = 2(2x + 3 + x - 4)
⇒Perimeter = 2(3x - 1)
⇒Perimeter = (6x - 2)ft
We know that area of rectangle = Length * Width
So,
⇒Area = (2x + 3) * (x - 4)
⇒Area = 2x^2 - 8x + 3x - 12
⇒Area = (2x^2 - 5x - 12) square ft
Hence, the perimeter of the rectangle is (6x - 2)ft and the area of the rectangle is (2x^2 - 5x - 12) square ft.
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The perimeter of a triangular park shown on the right is 11x-6.
What is the missing length?
A piecewise function f (x) is defined by f of x is equal to the piecewise function of 2 to the power of the quantity x plus 1 end quantity minus 3 for x is less than or equal to 2 and the quantity 10 over x for x is greater than 2
Part A: Based on the graph of f (x), what is the range? (5 points)
Part B: Determine the asymptotes of f (x). (5 points)
Part C: Describe the end behavior of f (x). (5 points)
Part A: The range of a function is the set of all possible outputs (y-values) for the given domain of the function. In this case, the domain of f(x) is all real numbers. We can find the range of f(x) by analyzing the two different parts of the piecewise function:
For x <= 2, f(x) = 2^(x+1) - 3. The minimum possible output for this function is y = -1 (when x = -1) and the maximum possible output is y = 3 (when x = 0).
For x > 2, f(x) = 10/x. The minimum possible output for this function is y = 0 (as x approaches infinity) and the maximum possible output is y = 10 (when x = 2)
So, the range of f(x) is [-1, 10].
Part B: The asymptotes of a function are the lines that the graph of the function approaches but never touches. In this case, the graph of f(x) has a vertical asymptote at x = 0, because the function is not defined at x=0.
Part C: The end behavior of a function is the behavior of the function as the input (x) approaches positive or negative infinity. In this case, the function f(x) = 10/x as x > 2, as x approaches positive infinity the output(y) approaches 0, and as x approaches negative infinity the output(y) does not exist. Therefore, the end behavior of f(x) is that it approaches 0 as x approaches positive infinity.
Refer to the accompanying data set and use the 30 screw lengths to construct a frequency distribution. Begin with a lower class limit of 2.720 in., and use a class width of 0.010 in. The screws were labeled as having a length of 2 3/4 in. Click on icon to view the data. Complete the frequency distribution below. Data Table 2.720-1 1-0 1-1 Screw Lengths (inches) 2.753 2.752 2.752 2.735 2.733 2.747 2.751 2.723 2.754 2.751 2.754 2.742 2.748 2.737 2.751 2.752 2.764 2.744 2.744 2.748 2.741 2.762 2.758 2.756 2.747 2.736 2.752 2.736 2.759 2.746 Type integers or decimals rounded to the nearest th Print Done
The frequency distribution table is given as
Length (in) Frequency
2.720 - 2.729 1
2.730 - 2.739 5
2.740 - 2.749 9
2.750 - 2.759 13
2.760 - 2.769 2
Given that the sample of the 30 screw lengths
2.753 2.762 2.752 2.735 2.733 2.747 2.751 2.723 2.754 2.751 2.754 2,742 2.748 2.737 2.751 2.752 2.764 2,744 2.744 2,748 2.741 2.762 2.758 2.756 2.747 2.736 2.752 2.736 2.759 2.746
For constructing a frequency distribution :
Lower class limit = 2.720 in.
Class width = 0.010 in
Frequency Distribution Table :
Length (in) Frequency
2.720 - 2.729 1
2.730 - 2.739 5
2.740 - 2.749 9
2.750 - 2.759 13
2.760 - 2.769 2
Total 30
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Please help me with this question.
What is the triangle's base, b?
A=1/2bh and b=2A/h so
b=2A/h =2(12cm^2)/3cm=8cm
In order to find the base
We apply the area of a triangle formula to find the base
We know the formula to find the area of a triangle is,
[tex]A =\frac{1}{2}XbXh[/tex]
Here the area and the height is given
So the base is
[tex]12 = \frac{1}{2} X bX3[/tex]
Substituting the values we get
[tex]\frac{12X2}{3} = b[/tex]
[tex]8cm = b[/tex]
[tex](\frac{3p}{7}+\frac{7}{6p})^2 -(\frac{3p}{7}-\frac{7}{6p})^2[/tex]
Solve with steps please
ty :)
Answer:
The expression simplifies to:
[tex](\frac{3p^2 + 49}{42p})^2 -(\frac{3p^2 - 49}{42p})^2[/tex]
Using the difference of squares identity, the expression further simplifies to:
[tex]\frac{98p}{42p^2} = \frac{98}{42p}[/tex]
Step-by-step explanation:
Consider the following input-output table. Row P Q R S
1 1 1 1 0
2 1 1 0 1
3 1 0 1 0
4 q 0 0 0
5 0 1 1 0
6 0 1 0 1
7 0 0 1 0
8 0 0 0 0
The output column, S, was created from the student ID 21444368 using the algorithm: - If ID digit n (left-to-right) is an even integer, place a 0 in S, row n (top-down) - If ID digit n (left-to-right) is an odd integer, place a 1 in S, row n (top-down) Create a similar table, but with S reflecting the result of the algorithm applied to your student ID (do this on scratch paper). On the quiz essay: 1. Record your student ID's column S as an ordered, horizontal list. For the example given, the list would be S=(0,1,0,0,0,1,0,0). 2. Write the disjunctive normal expression that would implement your student ID input/output table. Do not reduce the expression. Use the words "or." and "not" for the operators, and the letters P,Q,R, and S for the variables. For full credit show parentheses where required.
The output column, S, of the given input-output table was created from the student ID 21444368 using an algorithm where if the student ID digit is an even integer, a 0 is placed in the corresponding row of column S, and if the student ID digit is an odd integer, a 1 is placed in the corresponding row of column S.
Student ID: 81725225
P Q R S
1 1 1 0
1 1 0 1
1 0 1 1
0 1 0 0
0 0 1 1
0 1 1 0
0 0 0 1
Student ID: 81725225
P: The first digit of my student ID is 8 so it is an even integer, therefore I place a 0 in row 1 of column P.
Q: The second digit of my student ID is 1 so it is an odd integer, therefore I place a 1 in row 2 of column Q.
R: The third digit of my student ID is 7 so it is an odd integer, therefore I place a 1 in row 3 of column R.
S: The fourth digit of my student ID is 2 so it is an even integer, therefore I place a 0 in row 4 of column S.
The resulting table is:
P Q R S
1 1 1 0
1 1 0 1
1 0 1 1
0 1 0 0
0 0 1 1
0 1 1 0
0 0 0 1
The output column, S, of the given input-output table was created from the student ID 21444368 using an algorithm where if the student ID digit is an even integer, a 0 is placed in the corresponding row of column S, and if the student ID digit is an odd integer, a 1 is placed in the corresponding row of column S. The same algorithm was applied to my student ID 81725225, resulting in the table shown above.
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