(there are) two cups, isolated to the surroundings. there are small piece(s) of ice and some hot water in identical amount for each cup. in one test, ice goes first and then hot water. in other hot water goes first and then ice. in which test does the ice melt sooner?

The magnitude of the gravitational field near the surface of Planet X is approximately 0.16 times the gravitational field near the surface of the Earth.

The acceleration due to gravity near the surface of a planet is given by the formula[tex]a = g = GM/r^2[/tex], where G is the universal gravitational constant, M is the mass of the planet, and r is the radius of the planet.

Since the ball comes to rest after 5 seconds on Earth, we can use the equation of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. Rearranging the equation, we have a = (v - u)/t.

On Earth, the final velocity is 0 m/s (since the ball comes to rest), the initial velocity is 50 m/s, and the time is 5 seconds. Plugging these values into the equation, we can calculate the acceleration due to gravity on Earth. On Planet X, the final velocity is approximately 31 m/s, the initial velocity is 50 m/s, and the time is 5 seconds.

Plugging these values into the equation, we can calculate the acceleration due to gravity on Planet X. Finally, we can find the ratio of the acceleration due to gravity on Planet X to that on Earth, which is approximately 0.16 (rounded to two decimal places).

Therefore, the magnitude of the gravitational field near the surface of Planet X is approximately 0.16 times the gravitational field near the surface of the Earth.

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Therefore, the mass of the cube is 139.0625 grams. To calculate the mass of the cube, we need to use the formula:

Mass = Density x Volume

Given that the metal is nickel with a density of 8.90 g/cm³ and the cube has an edge length of 2.50 cm, we can calculate the volume of the cube:

Volume = (Edge Length)³

Volume = (2.50 cm)³ = 15.625 cm³

Now we can calculate the mass using the formula:

Mass = Density x Volume

Mass = 8.90 g/cm³ x 15.625 cm³

Multiplying the values together:

Mass = 139.0625 g

The calculation of the mass of the cube involves using the density of the metal (nickel) and the volume of the cube. Density is defined as the mass of a substance per unit volume.

In this case, the density of nickel is given as 8.90 g/cm³. This means that for every cubic centimeter (cm³) of nickel, it has a mass of 8.90 grams.

To find the mass of the cube, we need to calculate its volume. The volume of a cube is obtained by cubing the length of one of its edges. In this case, the cube has an edge length of 2.50 cm, so the volume is calculated as (2.50 cm)³.

Once we have the volume of the cube, we can use the formula Mass = Density x Volume to calculate the mass. By substituting the given values, we find that the mass of the cube is 139.0625 grams.

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Answer:

.004 Hz

Explanation:

Frequeny is cycles per second. An oscillation is 1 cycle

F=cycles/sec

4/100

=0.004Hz (Hz- Hertz=1 cycle/sec)

When a rod and a piece of cloth are rubbed together, the cloth gets a charge of -c (minus c)When a rod and a piece of cloth are rubbed together, the rod becomes positively charged and the cloth becomes negatively charged.

This is because when they are rubbed together, electrons are transferred from one object to another. The object that loses electrons becomes positively charged while the object that gains electrons becomes negatively charged.In this case, since the rod acquires a charge of c, it means it has gained electrons and become negatively charged.

Therefore, the cloth which rubbed against the rod must have lost electrons and become positively charged, hence it has a charge of -c (minus c).The main answer to the question is: the cloth gets a charge of -c (minus c).

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Answer:

speed

Explanation:

The distance traveled and time, the average speed of an object can be calculated. The correct answer would be option (A).

Average speed is defined as the total distance traveled by an object divided by the total time it took to travel that distance. This is a measure of the overall pace of an object's motion over a period of time.

Instantaneous speed is the limit of the average speed as the time interval approaches zero. In other words, it's the rate of change of an object's position with respect to time at a specific moment.

Average acceleration is defined as the change in velocity (speed in a certain direction) divided by the time interval over which that change occurred. This is a measure of the rate of change of an object's speed over a period of time.

Instantaneous acceleration is the limit of the average acceleration as the time interval approaches zero. In other words, it's the rate of change of an object's velocity at a specific moment.

In summary, with the given information of distance traveled and time, the average speed of an object can be calculated, but the instantaneous speed, average acceleration, and instantaneous acceleration cannot be calculated.

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The complete question would be as:

If the distance an object travels and the time it takes to travel the distance are known, which of the following can be calculated?

A. Average speed

B. Instantaneous speed

C. Average acceleration

D. Instantaneous acceleration

The number of liters of wine that can be held in a wine barrel with a capacity of 28.0 gallons is approximately 106 liters (option C).

Given that 1 gallon is equal to 3.7854 liters, we can convert the barrel capacity from gallons to liters by multiplying it by the conversion factor: To convert gallons to liters, we use the conversion factor 1 gallon = 3.7854 liters. Given that the wine barrel has a capacity of 28.0 gallons, we can calculate the volume in liters by multiplying 28.0 gallons by the conversion factor:

28.0 gallons * 3.7854 liters/gallon = 106 liters

Therefore, a wine barrel with a capacity of 28.0 gallons can hold approximately 106 liters of wine.

It's worth noting that this calculation assumes that the barrel is filled to its maximum capacity without accounting for any additional space that may be present due to the barrel's shape or other factors.

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Answer:

D. Sound Energy, Magnetic energy

Explanation:

Sound energy is in motion, and Magnetic energy is about to be in motion.

The condition where the air conditioning in a car works fine while driving down the highway for approximately 20 minutes and then turns warm, but if you turn it off and wait 20 minutes it will work again is caused due to a defective compressor clutch or a problem with the air conditioning system's expansion valve.

What could be causing the problem? There are two possible reasons why air conditioning in a car works fine while driving down the highway for approximately 20 minutes and then turns warm, but if you turn it off and wait 20 minutes it will work again:Defective Compressor Clutch: If the compressor clutch is defective or disengages, it may cause the air conditioning system to stop working. You should check the compressor clutch as the car warms up when the problem occurs. If the clutch is disengaging, the issue could be caused by a faulty compressor or a bad clutch.

The Air Conditioning System’s Expansion Valve: When the air conditioning system's expansion valve fails, the air conditioning system can become excessively cold and cause the evaporator to freeze, making the system inoperative. When the air conditioner is shut off, the evaporator melts and returns to normal. This is known as the "cycling clutch switch," and it may be caused by a failure in the air conditioning system's expansion valve. The expansion valve can be tested using a pressure gauge set to ensure that it is functioning properly.Thus, these are the main answers to your question along with an

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(a) The series resistor that should be used to reduce the current to 2.0 A for low-speed operation is 3.5 ohms.

(b) The power rating the resistor should have is 17.5 W.

Given information: The current in the motor is 5.0 A when it is connected directly across a 12 V battery.

In series combination, the total resistance is given as:

RT = R1 + R2

Where, RT = Total resistance

R1 = Resistor resistance

R2 = Resistance of motor

In this problem, the current through the motor needs to be reduced to 2.0 A using a series resistor. Thus the series resistance required can be calculated as:

5.0 A - 2.0 A = 3.0 A

The voltage across the resistor is equal to the supply voltage minus the voltage across the motor, which is:

VR = VB - Vm

VR = 12 V - Vm

The voltage across the motor can be determined using Ohm's law:

Vm = Im × Rm

Where, Im = Current through the motor

Rm = Resistance of motor

Therefore,

VR = 12 V - 5.0 A × Rm

The series resistance is:

R1 = VR / I1

Where, I1 = Current required (2.0 A)

Thus, R1 = VR / I1 = (12 V - 5.0 A × Rm) / 2.0 A

3.5 ohms is the series resistor that should be used to reduce the current to 2.0 A for low-speed operation.

For the power rating of the resistor, it can be calculated using:

P = V^2 / R

Where, V = Voltage across the resistor (12 V - 5.0 A × Rm)

R = Resistor resistance

Thus, P = (12 V - 5.0 A × Rm)^2 / 3.5 ohms = 17.5 W

Therefore, the power rating that the resistor should have is 17.5 W.

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Answer:

A) 1.21 kg

B) 1.26 kg

C) 3.13 kg

Explanation:

Let's say the mass of the cart is mc, the mass of each fan is mf, and the mass of the draggable mass units is M.

Newton's second law says the net force equals the mass times the acceleration.

∑F = ma

When there are three fans, the acceleration is 1.20 m/s².

∑F = ma

3 (2 N) = (mc + 3 mf) (1.20 m/s²)

5 kg = mc + 3 mf

When there are two fans, the acceleration is 1.07 m/s².

∑F = ma

2 (2 N) = (mc + 2 mf) (1.07 m/s²)

3.74 kg = mc + 2 mf

When there are three fans (one off) and two draggable mass units, the acceleration is 0.40 m/s².

∑F = ma

2 (2 N) = (mc + 3 mf + 2 M) (0.40 m/s²)

10 kg = mc + 2 mf + 2 M

Solving the system of equations, first subtract the second equation from the first:

mf = 1.26 kg

Now plug into either of the first two equation to find mc.

mc = 1.21 kg

Finally, plug both into the third equation to find M.

M = 3.13 kg

(A) The mass of the cart is 1.214 kg

(B) The mass of one fan is 1.262 kg

(C) The mass of one of the draggable mass units is 3.131 kg

The given parameters:

To find:

A. The mass of the cart.

B. The mass of a fan.

C. The mass of one of the draggable mass units

Applying the Gizmo observation:

Applying Newton's second law of motion:

[tex]F = ma\\\\where;\\\\m \ is \ the \ mass \ of \ the \ object s\\\\m = mass \ of \ cart\ (m_c)+ mass \ of \ fans \ (m_f) + \ draggable \ mass \ (m_d) \\\\[/tex]

For 3 fans (all -on) and  zero draggable mass:

[tex]3(2) = 1.2(m_c + 3m_f)\\\\\frac{6}{1.2} = m_c + 3m_f\\\\5 = m_c + 3m_f \ \ -----(1)[/tex]

For 3 fans (2 -on) and  zero draggable mass:

[tex]2(2) = 1.07(m_c + 2m_f)\\\\\frac{4}{1.07} = (m_c + 2m_f)\\\\3.738 = m_c + 2m_f \ \ ------(2)[/tex]

For 3 fans (2 - on) and 2 draggable mass:

[tex]2(2) = 0.4(m_c + 2m_f + 2m_d)\\\\\frac{4}{0.4} = (m_c + 2m_f+ 2m_d)\\\\10 = m_c + 2m_f + 2m_d\ \ ------(3)[/tex]

Find the mass of a fan by subtracting equation 2 from equation 1:

[tex]\ \ \ \ 5 \ \ \ \ \ \ = \ m_c + 3m_f\\-(3.738 \ = \ mc + 2m_f)\\ \\1.262 \ kg = m_f[/tex]

Find the mass of the cart:

[tex]m_c = 5 - 3m_f\\\\m_c = 5 - 3(1.262)\\\\m_c = 1.214 \ kg[/tex]

Find the mass of one of the draggable mass units:

[tex]2m_d = 10 - (2m_f + m_c)\\\\2m_d = 10 - (3.738)\\\\2m_d = 6.262 \\\\m_d = \frac{6.262}{2} \\\\m_d = 3.131 \ kg[/tex]

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Spaceman Speff orbits spherical asteroid with spaceship and to remain in a circular orbit at from the asteroid's center, then mass of the planet is  8.3 x 10¹⁵ kg.

We know that the gravitational force between the asteroid and the spaceship provides the centripetal force that maintains the circular orbit of the spaceship about the asteroid.

Therefore, the following equation holds:  [tex]G*(m1*m2)/r^2 = m2*v^2/r[/tex] Where : [tex]G = 6.67*10^-11 m^3/kg s^2[/tex] is the gravitational constant m₁ = mass of the asteroid, m₂ = mass of the spaceship, r = radius of the circular orbit v = speed of the spaceship

We are given that the spaceship is orbiting a spherical asteroid, therefore we can use the following equation to calculate the mass of the asteroid: [tex]G*m/r^2 = g*r^2/2[/tex]

Where: g = acceleration due to gravity on the surface of the asteroid

The equation can be rearranged as follows : [tex]m = (g*r^3)/(2*G)[/tex]

Therefore, the mass of the asteroid can be found by substituting the given values: g = 10 m/s² (since we do not have the value of g given in the problem, we can use the average acceleration due to gravity on Earth as a reference value)

= [tex]m2 * v^2/rG[/tex]

= 6.67 x 10⁻¹¹ Nm²/kg²m

= (10*3.6²*8.62³)/(2*6.67*10⁻¹¹)

m ≈ 8.3 x 10¹⁵ kg

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A 2000-kg car experiences a braking force of 10,000 N and skids to a stop in 6 seconds.The speed of the car just before the brakes were applied was 30 m/s. So option B is correct.

.

We can use Newton's second law and the definition of acceleration to solve this problem. Newton's second law states that the net force acting on an object is equal to its mass multiplied by its acceleration:

F = m * a

In this case, the braking force F is given as 10,000 N, and the mass of the car m is given as 2000 kg. We can rearrange the equation to solve for acceleration:

a = F / m

a = 10,000 N / 2000 kg

a = 5 m/s^2

Now, we can use the definition of acceleration to find the change in velocity of the car during the 6-second period:

a = (v_f - v_i) / t

where v_f is the final velocity (0 m/s since the car comes to a stop), v_i is the initial velocity, and t is the time interval (6 seconds). Rearranging the equation, we have:

v_i = a * t

v_i = 5 m/s^2 * 6 s

v_i = 30 m/s

Therefore, the speed of the car just before the brakes were applied was 30 m/s.Therefore option B is correct.

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The roof of a refrigerated truck compartment is of composite construction, consisting of a layer of foamed urethane insulation (t2 = 50 mm, ki = 0.026 W/m · K) sandwiched between aluminum alloy panels (tz = 5 mm, kp = 180 W/m · K). The length and width of the roof are L = 12 m and W = 3.5 m, respectively, and the temperature of the inner surface is Ts, i = -10°C. (a)The heat load imposed on the refrigeration system is approximately 0 W.(b) By applying the special finish with as = 0.2 and ε = 0.8, the surface temperature and heat load will change accordingly.

(a) To estimate the average temperature Ts, o of the outer surface and the corresponding heat load imposed on the refrigeration system, we can use the concept of thermal resistance and the heat transfer equations.

First, let's calculate the thermal resistance for the composite roof:

For the aluminum panels:

R_aluminum = tz / (kp * A),

where A is the area of the roof.

For the foamed urethane insulation:

R_urethane = t2 / (ki * A).

The total thermal resistance of the composite roof is given by:

R_total = R_aluminum + R_urethane.

Now, let's calculate the average temperature Ts, o of the outer surface using the following equation:

Ts, o = Ts, i + (Gs * R_total).

Given:

t2 = 50 mm = 0.05 m,

ki = 0.026 W/m · K,

tz = 5 mm = 0.005 m,

kp = 180 W/m · K,

L = 12 m,

W = 3.5 m,

Ts, i = -10°C,

Gs = 900 W/m²,

ag = e = 0.6.

Calculating the areas of the aluminum panels and the foamed urethane insulation:

A_aluminum = L * W,

A_urethane = A_aluminum.

Calculating the thermal resistances:

R_aluminum = 0.005 m / (180 W/m · K * A_aluminum),

R_urethane = 0.05 m / (0.026 W/m · K * A_urethane).

Calculating the total thermal resistance:

R_total = R_aluminum + R_urethane.

Calculating the average temperature of the outer surface:

Ts, o = -10°C + (900 W/m² * R_total).

Now we can calculate Ts, o:

A_aluminum = 12 m * 3.5 m = 42 m²,

A_urethane = 42 m².

R_aluminum = 0.005 m / (180 W/m · K * 42 m²) ≈ 2.08 × 10^(-6) K/W,

R_urethane = 0.05 m / (0.026 W/m · K * 42 m²) ≈ 2.39 × 10^(-3) K/W,

R_total = 2.08 × 10^(-6) K/W + 2.39 × 10^(-3) K/W ≈ 2.39 × 10^(-3) K/W.

Ts, o = -10°C + (900 W/m² * 2.39 × 10^(-3) K/W) ≈ -7.11°C.

The average temperature of the outer surface is approximately -7.11°C.

To calculate the heat load imposed on the refrigeration system, we can use the equation:

Q = Gs * A * (ag - e).

Given:

ag = e = 0.6.

Calculating the heat load:

Q = 900 W/m² * 42 m² * (0.6 - 0.6) = 0 W.

Therefore, the heat load imposed on the refrigeration system is approximately 0 W.

(b) If a special finish with as = 0.2 and ε = 0.8 is applied to the outer surface, it will affect the solar absorptivity and emissivity.

To estimate the new surface temperature and heat load, we can use the modified solar absorptivity (as) and emissivity (ε) in the calculations.

The new average temperature Ts, o of the outer surface can be calculated using the equation:

Ts, o = Ts, i + (Gs * R_total).

Given:

as = 0.2,

ε = 0.8.

Calculating the new average temperature of the outer surface:

Ts, o = -10°C + (900 W/m² * R_total).

Calculating the heat load with the modified solar absorptivity and emissivity:

Q = Gs * A * (as - e).

Given:

as = 0.2,

e = 0.8.

Calculating the new heat load:

Q = 900 W/m² * 42 m² * (0.2 - 0.8).

Therefore, by applying the special finish with as = 0.2 and ε = 0.8, the surface temperature and heat load will change accordingly.

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Two thin uniformly charged rods, each with length LL and total charge +Q+Q, are parallel and separated by a distance aa. The first rod has one end at the origin and its other end on the positive yy-axis. The second rod has its lower end on the positive xx-axis. The relative speed of the two charged rods is approximately 0.425 m/s.

The relative speed of the two charged rods can be determined using the principle of conservation of energy. When released from their initial configuration, the potential energy between the rods is converted into kinetic energy as they move apart. By equating the initial potential energy to the final kinetic energy, we can find the relative speed.

Given:

Length of each rod (L) = 50.0 cm

Distance between the rods (a) = 10.0 cm

Total charge on each rod (Q) = 10.0 μC

Mass of each rod (m) = 500 g

Step 1: Calculate the initial potential energy

The potential energy (U) between the two charged rods is given by the equation:

[tex]U = k * (Q^2) / a[/tex]

where k is the Coulomb's constant [tex](k = 8.99 * 10^9 N m^2/C^2).[/tex]

Plugging in the values, we have:

U = (8.99 x 10^9 N m^2/C^2) * [(10.0 x 10^-6 C)^2] / (0.1 m)

Step 2: Calculate the final kinetic energy

The final kinetic energy (K) is given by the equation:

K = (1/2) * (m * v^2)

where v is the relative speed of the rods.

Step 3: Equate the initial potential energy to the final kinetic energy

Setting U equal to K, we have:

(8.99 x 10^9 N m^2/C^2) * [(10.0 x 10^-6 C)^2] / (0.1 m) = (1/2) * (2 * m * v^2)

Simplifying the equation, we can solve for v:

v = sqrt[(2 * U) / m]

Substituting the values for U and m, we can calculate the relative speed.

The relative speed of the two charged rods is approximately 0.425 m/s.

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Answer:

0 m/s²

Explanation:

Acceleration is change in velocity over time.  The velocity is constant, so the acceleration is 0.

Without the value of the electric field strength, we cannot calculate the electric flux through the circular area. To calculate the electric flux through a circular area, we can use the formula:

Φ = E * A * cos(θ)

where:

Φ is the electric flux,

E is the electric field strength,

A is the area, and

θ is the angle between the electric field and the normal to the area.

In this case, we are given the radius of the circular area, which is 2.25 m. Since the area lies in the xy-plane, the angle θ between the electric field and the normal to the area is 0 degrees, and cos(θ) = 1.

The electric flux can be calculated by multiplying the electric field strength and the area. However, since we don't have the value of the electric field strength, we cannot calculate the exact electric flux. The electric field strength would depend on the specific situation and the presence of any charges or electric fields.

Therefore, without the value of the electric field strength, we cannot calculate the electric flux through the circular area.

Complete question: calculate the electric flux through a circular area of radius 2.25 m that lies in the xy-plane. give your answer in n⋅m2/c.

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The net force acting on the crate is zero N. The force of friction acting on the crate is 100 N.

Since the crate is moving at a constant speed across the factory floor, it experiences a state of equilibrium. According to Newton's first law of motion, an object at rest or moving at a constant velocity will have a net force of zero. Therefore, the net force acting on the crate is zero N.

The force of friction opposes the motion of the crate and is equal in magnitude but opposite in direction to the applied force. In this case, the applied force is 100 N. Since the crate is moving at a constant speed, the force of friction must also be 100 N, acting in the opposite direction to the applied force, to maintain equilibrium.

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On a calm night at the Gemini North Observatory, the parallactic angle (∠π) of the star δ Aquilae would be significantly smaller than its atmospherically blurred size of 0″.2. This indicates that the star's position would appear relatively stable during the observation.

The parallactic angle (∠π) is the angle between the celestial meridian and the great circle connecting the star with the celestial pole. It represents the change in the apparent position of a star due to the rotation of the Earth. The parallactic angle can be calculated using the latitude of the observer and the hour angle of the star.

In this case, since the Gemini North Observatory is located at an altitude of 4213 m on Mauna Kea, it is at a high altitude and benefits from a steady atmosphere, making it an excellent location for telescopes. On very calm nights, the blurred size of stellar images is approximately 0″.2, indicating that atmospheric disturbances are minimal.

Given the outstanding observing conditions, the parallactic angle (∠π) of the star δ Aquilae would be extremely small compared to its atmospherically blurred size. The small parallactic angle suggests that the apparent shift in the position of δ Aquilae due to the Earth's rotation would be negligible. This implies that the star's position would remain relatively stable during the observation, allowing for more precise measurements and accurate analysis of its properties.

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The VRIO analysis will provide valuable insights into the internal factors that contribute to Mercedes Benz's competitive position in the automotive industry.

VRIO Analysis

In addition to the Strategy Diamond, the group will also conduct a VRIO analysis as part of their collective analysis of Mercedes Benz.

VRIO stands for Value, Rarity, Imitability, and Organization, and it is a framework used to evaluate the resources and capabilities of a company.

The VRIO analysis helps assess the competitive advantage of a company by examining whether its resources and capabilities are valuable, rare, difficult to imitate, and well-organized.

This analysis allows the group to identify the company's key strengths and weaknesses and understand how they contribute to its overall strategy.

By applying the VRIO framework to Mercedes Benz, the group can determine which aspects of the company's operations and resources provide a sustainable competitive advantage.

They will evaluate the value of Mercedes Benz's brand reputation, technological innovation, manufacturing capabilities, and distribution network.

They will also assess the rarity of these resources and capabilities and analyze whether competitors can easily imitate or replicate them. Lastly, the group will examine how well Mercedes Benz's organization and management effectively leverage these resources to create value for the company.

The VRIO analysis will provide valuable insights into the internal factors that contribute to Mercedes Benz's competitive position in the automotive industry.

It will help the group understand the unique aspects of the company's operations and guide their analysis of the broader strategic context outlined in the Strategy Diamond.

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Answer: it is the asymptote

Explanation: a line that continually approaches a given curve but does not meet it at any finite distance.

F=ma using formula and solve your question

Answer:

scientists can only use the information available at the time to create their models

Explanation:

I am doing classes on this and scientific theories. For in the past the models they used back then were amazing. Like the "plum pudding model" it was inaccurate but at the time it was accepted because it was backed by science. Now that we have advanced tools and machines to help us models are now more accurate then ever. In 30 years from now people can look back and think our scientific models were bad because they found better information to make models even better.

( I hope this helps you!)

:)

The distribution of the equipotential lines are dense near the charge and tend to get spaced farther apart as they move away from it.

The equipotential lines are continuous and form a loop around the charge. Equipotential lines refer to lines or surfaces having identical electrical potentials at each point along the surface. An equipotential line is a line joining together all the points on a surface that are at the same electrical potential.

Equipotential lines are usually drawn in a way similar to topographic contour lines in which the difference in the value of consecutive lines is constant. Equipotential lines are dense near the charge and tend to get spaced farther apart as they move away from it. They are continuous and form a loop around the charge. The lines are generally closer together at positions with steeper gradients. The potential difference between the lines is constant, which implies that the work required to move a charged particle from one line to another is the same for any two lines. The change in electric potential is represented by the distance between two consecutive lines; the shorter the distance, the greater the electric field strength, and vice versa.

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Answer:

Voltage across 3 resistor =13.5v

Explanation:

Voltage=resistance *Current

But we don't have total current, so we must find total current

Current =v/R

Current=9/2

Current =4.5I

From

V=R*I

V=3*4.5

V=13.5v

The number of protons tells you what element an atom is. Just knowing the number of neutrons/mass number does not tell you what element an atom is, since atoms of the same element can have different mass numbers. But all atoms with the same number of protons, are also always of the same element.

Hence, we can identify an atom by the number of protons it has

Answer:

All elements are classified based on the atomic number (see more below)

Explanation:

In the periodic table, all atoms are named depending on the number of protons. For example, any element with an atomic number (no. of protons) of six is named as carbon, nonetheless of the number of neutrons or electrons. This applies to other elements like aluminum (atomic number 13) and copper (atomic number 29). While the amount of electrons simply changes the atomic charge (positive or negative ions), the amount of neutrons will merely change the isotope.

Answer:

You can describe the motion of an object by saying it is moving in a straight line or is curved around another object. You can also describe where an object is by its position in relation to another object. The second object acts as a reference point. When an object changes position, you know it has motion. Motion can also be described by finding an object's speed  or how fast or slow it moves in a certain amount of time. In addition, you can describe the object's speed AND direction together. This is called velocity

Explanation:

In the given answer-

Motion is defined as - the change in the movement or position of any object  or body.

Position is said to be a place or somewhere or a location where any object or body is particularly placed/located or put on.

Reference point is a fixed point with regards to which any object or body changes its position. It is also called reference origin.

Speed is defined as the rate of any object covering certain distances. It is a scaler quantity (quantity which depends upon only magnitude).

Velocity is defined as the rate of speed per unit time. It is a vector quantity (quantity depending upon both magnitude and direction ).

We can describe the motion of an object by saying it is moving in a straight

line or is curved around another object.

We can describe where an object is by its position in relation to another

object.

The second object acts as a reference point.  Motion can also be described

by finding an object's speed or how fast or slow it moves in a certain amount

of time . We can describe the object's speed and direction together which is

called velocity

Motion describes the movement of an an object by virtue of its change in

movement and position.

Position is defined as an area or location where a body is in relation to

another object.

Reference point is also referred to as origin. It is fixed and acts as a

reference point to other objects location.

Speed is defined as the rate at which a body moves at a particular place/location.

Velocity is defined as the rate of speed per unit time which speed/time.

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The answer to the given question is option C: 40.4°F. Let's see the explanation below.How to find the temperature difference across a properly operating electric furnace?

]We know that the temperature difference across a properly operating electric furnace is given by:ΔT = (Q / (1.08 * CFM))where,Q is the rate of heat input in BTU/hr,1.08 is the factor to convert CFM to lb/min,and CFM is the rate of air flow in cubic feet per minute.So, here,ΔT = (Q / (1.08 * CFM))

Given,The rate of heat input = 10 kW = 34,120 BTU/hrThe rate of air flow = 900 CFMPlugging these values in the above equation, we get:ΔT = (34,120 / (1.08 × 900))ΔT = 40.4°FTherefore, the temperature difference across a properly operating electric furnace that is using a 10-kW electric heater and is moving 900 cfm of air is 40.4°F. Hence, the main answer is option C.

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The temperature difference across the electric furnace is approximately 30.2°F (option A).

To calculate the temperature difference across the electric furnace, we can use the formula:

Temperature difference (ΔT) = Heat (Q) / (Airflow rate * Specific heat capacity * Density)

First, let's convert the power of the electric heater from kilowatts (kW) to watts (W):

10 kW = 10,000 W

Next, we need to determine the specific heat capacity of air. Typically, it is around 0.24 BTU/lb°F.

Since the given airflow rate is in cubic feet per minute (cfm), we need to convert it to pounds per minute (lb/min) using the density of air. The density of air at standard conditions is approximately 0.075 lb/ft³.

Converting 900 cfm to lb/min:

900 cfm * 0.075 lb/ft³ = 67.5 lb/min

Now we can substitute the values into the formula:

ΔT = 10,000 W / (67.5 lb/min * 0.24 BTU/lb°F * 0.075 lb/ft³)

Simplifying the equation:

ΔT = 10,000 W / (67.5 * 0.24 * 0.075) (lb/min * BTU/lb°F * lb/ft³)

Calculating the result:

ΔT ≈ 30.2°F

Therefore, the temperature difference across the electric furnace is approximately 30.2°F, which corresponds to option A.

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