. There are two elements named after the US state that they were discovered in. Who are they?

Answer:

The answer is True

Explanation:

I got it right on my quiz, hope this helps!

Answer:

[tex]n_{ FeC_2O_4\ 2H_2O}=0.020molFeC_2O_4\ 2H_2O[/tex]

Explanation:

Hello.

In this case, since the chemical reaction for the first step is:

[tex]Fe(NH_4)_2(SO_4)_2\ 6H_2O + H_2C_2O_4 \rightarrow FeC_2O_4\ 2H_2O + H_2SO_4 + (NH_4)_2SO_4 + 4H_2O[/tex]

Whereas we can see a 1:1 molar ratio between FeC2O4·2H2O(s) and H2C2O4, thus, we compute the moles of yielded FeC2O4·2H2O(s) in the first step as shown below:

[tex]n_{ FeC_2O_4\ 2H_2O}=0.01814L*1.1\frac{molH_2C_2O_4 }{L} *\frac{1molFeC_2O_4\ 2H_2O}{1molH_2C_2O_4} \\\\n_{ FeC_2O_4\ 2H_2O}=0.020molFeC_2O_4\ 2H_2O[/tex]

Best regards.

Answer:

Phosphate ion

Explanation:

Answer:

[tex]\boxed {\tt 116}[/tex]

Explanation:

To find the mass number of an isotope, add the number of neutrons and protons.

[tex]mass \ number = neutrons + protons[/tex]

There are 66 neutrons and 50 protons in the this isotope of tin.

[tex]mass \ number = 66+50[/tex]

Add 66 and 50.

[tex]mass \ number = 116[/tex]

The mass number of this tin isotope is 116.

Answer:

The the empirical formula for magnesium chloride based on this experiment will be [tex]MgCl_{2}[/tex]

Explanation:

Given that,

Mass of Mg = 0.50 g

Mass of magnesium chloride found = 1.99 g

Let the formula of magnesium chloride be [tex]Mg_{x}Cl_{y}[/tex]

We know that,

Molar mass of Mg= 24 g/mol

Molar mass of magnesium chloride = (24x+35.5y) g/mol

We need to calculate the moles of Mg

Using formula of moles

[tex]Number\ of\ moles=\dfrac{mass}{molar\ mass\ of\ Mg}[/tex]

Put the value into the formula

[tex]Number\ of\ moles=\dfrac{0.50}{24}[/tex]

[tex]Number\ of\ moles=0.020\ mole[/tex]

We need to calculate the mole of magnesium chloride

Using formula of moles

[tex]Number\ of\ moles=\dfrac{mass}{molar\ mass\ of\ magnesium\ chloride}[/tex]

Put the value into the formula

[tex]Number\ of\ moles=\dfrac{1.99}{24x+35.5y}\ mole[/tex]

The reaction will be,

[tex]Mg+HCl\Rightarrow Mg_{x}Cl_{y}+H_{2}[/tex]

We need to calculate the value of x and y

Using number of moles of Mg in reactant and product

Moles of Mg atom in reactant=Moles of Mg atom in product

[tex]\dfrac{0.50}{24}=x\times\dfrac{1.99}{24x+35.5y}[/tex]

[tex]0.020(24x+35.5y)=x\times1.99[/tex]

[tex]0.48x+0.71y=1.99x[/tex]

[tex]0.71y=(1.99-0.48)x[/tex]

[tex]\dfrac{x}{y}=\dfrac{0.71}{1.99-0.48}[/tex]

[tex]\dfrac{x}{y}=0.47\approx0.5[/tex]

[tex]\dfrac{x}{y}=\dfrac{1}{2}[/tex]

Hence, The the empirical formula for magnesium chloride based on this experiment will be [tex]MgCl_{2}[/tex]

Answer:

Mass of  Cl₂ produced is 12.78 g .

Explanation:

Given data:

Mass of HCl = 30.0 g

Mass of MnO₂ = 16 g

Mass of Cl₂ produced = ?

Solution:

Balance chemical equation:

MnO₂ + 4HCl        →        MnCl₂ + Cl₂ + 2H₂O

Number of moles of HCl:

Number of moles = mass / molar mass

Number of moles =  30 g/ 36.46 g/mol

Number of moles = 0.82 mol

Number of moles of MnO₂:

Number of moles = mass / molar mass

Number of moles =  16 g/ 87 g/mol

Number of moles = 0.18 mol

Now we will compare the moles of Cl₂  with MnO₂ and HCl.

                  MnO₂               :                Cl₂

                       1                   :                   1

                      0.18               :                0.18

                   HCl                  :                   Cl₂  

                      4                    :                     1

                     0.82               :                 1/4×0.82 = 0.205 mol

The number of moles of Cl₂ formed by HCl are less it will limiting reactant.

Mass of Cl₂ formed:

Mass = number of moles × molar mass  

Mass = 0.18 mol × 71 g/mol

Mass = 12.78 g

Answer:

it will affect the mass by changing in pressure will affect the volume (and therefore density) of gases, but will not noticeably affect the volume (or density) of solids and liquids. For gases: An increase in pressure leads to a decrease in volume and an increase in density. A decrease in pressure leads to an increase in volume and an decrease in density.

Explanation:

As the volume increases the mass of the liquid also increases as there is an increase in pressure.

Pressure is defined as the force applied on an object perpendicular to it's surface per unit area over which it is distributed.Gauge pressure is a pressure which is related with the ambient pressure.

There are various units by which pressure is expressed most of which are derived units which are obtained from unit of force divided by unit of area . The SI unit of pressure is pascal .

It is a scalar quantity which is related to the vector area element with a normal force acting on it.It is distributed over solid boundaries and across arbitary sections of fluid normal to the boundaries at every point.As the pressure increases, the volume decreases as they are inversely proportional at constant temperature.

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Answer: The element having number of protons 120 will belong to Group 2, Period 8 and has an atomic number of 120.

Explanation:

We are given:

Number of protons = 120

Atomic number is equal to the number of protons present in neutral atom.

Atomic number of element = 120

Electronic configuration of element: [tex]1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^{10}5p^66s^24f^{14}5d^{10}6p^67s^25f^{14}6d^{10}7p^68s^2[/tex]

Electronic configuration of element in terms of noble gas: [tex][Og]8s^2[/tex]

As, the last electron is entering in s-orbital. So, it is an s-block element and there are 2 electrons in the outermost shell. So, it will belong to Group-2.

And, the value of Principal Quantum number (n) for this element is '8'. Therefor, it will belong to Period 8.

Hence, the element having number of protons 120 will belong to Group 2, Period 8 and has an atomic number of 120.

Answer:

a = 3H²o

b = 20.3 grams

ç = (NO³)³

Answer:

a. => LR is HNO₃

b. => 13.88 grams Fe(NO₃)₃

c. => 29.1%

Explanation:

a. Limiting Reactant:

Note => Determining LR is quite simple if you'll convert all data to moles and divide each mole value by the respective coefficient. The smaller value is the limiting reactant.

Given:   Fe      +                   6HNO₃ ⇒ Fe(NO₃)₃ + 3NO₂ + 3H₂O

          20.3g                          21.4g

         = 20.3g/56g/mole     =21.4g/63g/mole

         = 0.363 mole              = 0.340 mole

Divide by coefficient 1         Divide by coefficient 6

= 0.363/1 = 0.363                  = 0.340/6 = 0.057

Since 0.057 is the smaller value then HNO₃ is the limiting reactant. However, one must use the calculated mole values when applying to equation stoichometry.

b. Grams of Fe(NO₃)₃ Produced:

Problems like this can be greatly simplified if data is 1st converted to moles and solved with respect to equation reaction ratios. Then convert mole value to needed dimension.

Fe     +   6HNO₃ ⇒ Fe(NO₃)₃ + 3NO₂ + 3H₂O

Rxn Ratio between LR and Fe(NO₃)₃ => 1:6

0.340 mole HNO₃  =>  1/6(0.340mole Fe(NO₃)₃ Produced = 0.057mole Fe(NO₃)₃ x 242 g/mole = 13.8 grams of Fe(NO₃)₃ produced

c. Percent Yield:

Given:  Fe     +   6HNO₃ ⇒ Fe(NO₃)₃ + 3NO₂ + 3H₂O

Measured Lab Yield = 4.02 grams (given in problem)

Theoretical Yield = 13.8 grams (calculated in part b)

%Yield = (Lab Yield/Theoretical Yield)100%

= (4.02/13.8)100% = 29.1% (w:w)*

*w:w means calculation was based on weight values and not volume values.

Answer:

3Fe + 2O2 → Fe3O4

Explanation:

Answer:

7.335 moles of  Cl₂ are required to react with 4.89 miles of Al.

Explanation:

Given data:

Moles of Al = 4.89 mol

Number of moles of Cl₂ required = ?

Solution:

Chemical equation:

2Al + 3Cl₂    →   2AlCl₃

Now we will compare the moles of Al and chlorine from balance chemical equation.

                            Al           :         Cl₂

                             2           :           3

                            4.89      :         3/2×4.89 =7.335 mol

Thus, 7.335 moles of  Cl₂ are required to react with 4.89 miles of Al.        

Answer:

A hydrated compound loses water of crystallisation when it is heated. ... We can use difference in the mass between the hydrated and anhydrous compound to calculate the mass of water of crystallisation removed by heating. Heat to constant mass to ensure all of the water of crystallisation is removed.

Explanation:

Answer:

1450 k

Explanation:

We are given:

V1 = 250 mL                        V2 = 500 mL

T1 = 725k                             T2 = T

V1 / T1 = V2 / T2

Now, replacing the values:

250 / 725 = 500 / T

T = 500 * 725 / 250

T = 2 * 725

T = 1450 k

Answer:

the atomic mass of magnesium from the Periodic Table is the average sum of it's three most abundant isotopes.

Explanation:

We are told that the atomic mass of magnesium from the Periodic Table is

24.31 amu.

Now, this atomic mass is simply the weighted average of the individual isotopes.

This is because the common isotopes of magnesium are 24Mg, 25Mg, and

26Mg and they are respectively 79%, 10%, and 11% in abundance. The weighted average of these 3 listed isotopes of magnesium add up to 24.3 amu.

Thus, the atomic mass of magnesium from the Periodic Table is the average sum of it's three most abundant isotopes.

Taking into account the definition of isotopes and atomic mass of an element, the atomic mass of magnesium from the Periodic Table is  24.31 amu and represent the weighted average of the individual isotopes.

In first place you must know that isotopes are atoms whose atomic nuclei have the same number of protons but different numbers of neutrons.

So, the relative atomic mass is an average of the atomic masses of the different isotopes in a sample, considering the contribution of each isotope.

This is, the atomic mass of an element is the weighted average mass of its natural isotopes. Therefore, the atomic mass of an element is not a whole number.

In summary, the atomic mass of magnesium from the Periodic Table is  24.31 amu. This mass represent the weighted average of the individual isotopes.

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Answer:

1.A 2.D

Explanation:

Answer:

The correct answer is C

Answer:

A

Explanation:

power house of the cell mitochondria

nucleus present in every cell

cell membrane gives protection

When 325 grams of CHCl3 is produced, approximately 297.54 grams of HCl are also produced.

To determine the amount of HCl produced when 325 grams of CHCl3 (chloroform) is produced, we need to use the balanced chemical equation for the reaction:

CH4 + 3Cl2 -> CHCl3 + 3HCl

From the balanced equation, we can see that the stoichiometric ratio between CHCl3 and HCl is 1:3. This means that for every 1 mole of CHCl3, 3 moles of HCl are produced.

To calculate the number of moles of CHCl3, we need to divide the given mass (325 grams) by its molar mass:

Molar mass of CHCl3 = 12.01 g/mol (C) + 1.01 g/mol (H) + 3 x 35.45 g/mol (Cl) = 119.38 g/mol

Moles of CHCl3 = 325 g / 119.38 g/mol = 2.72 mol

Since the stoichiometric ratio between CHCl3 and HCl is 1:3, the number of moles of HCl produced is three times that of CHCl3:

Moles of HCl = 2.72 mol x 3 = 8.16 mol

To calculate the mass of HCl, we multiply the number of moles by its molar mass:

Molar mass of HCl = 1.01 g/mol (H) + 35.45 g/mol (Cl) = 36.46 g/mol

Mass of HCl = 8.16 mol x 36.46 g/mol = 297.54 g

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Answer:

Explanation:

_____ grams of cobalt(II) oxide

Answer:

Explanation:

The density of a substance can be found by using the formula

[tex]density = \frac{mass}{volume} \\[/tex]

From the question

mass of cube = 150 g

volume = 16.7 cm³

We have

[tex]density = \frac{150}{16.7} \\ = 8.98203592...[/tex]

We have the final answer as

Hope this helps you

Answer:

1.875 gallons

Explanation:

Answer:

Copper phosphide, Cu3P, also copper(I) phosphide, cuprous phosphide, cuprophosphorus and phosphor copper, is a compound of copper and phosphorus, a phosphide of copper.

Explanation:

B) Oil spills in the environment might be cleaned up quicker.

Answer:

B is the right Choice

Explanation:

Answer:

magnetite

Explanation:

proportion of iron in haematite = 3.5/5 x 100% = 70%

proportion of iron in magnetite = 7.2/10 x 100% = 72%

Answer:

The most stable resonance structure shown in fig (II).

Explanation:

Given that,

If oxygen is the central atom in the CON– ion

We know that,

Resonance :

The movement of electron is called resonance.

If the electronegativity is more of element then the element is more stable.

We need to find the most stable resonance structure

According to figure,

Electronegativity of N is more than C

So, N is the more stable in fig (II).

Hence, The most stable resonance structure shown in fig (II).

The most stable resonance structure is the resonance structure in which nitrogen has a formal charge of -2.

There are molecules and ions in which a single structure does not sufficiently explain the observed properties of the molecule or ion. In such cases, bonding can not be explained in terms of one single structure, the actual structure of the compound lies somewhere between many contributing structures.

For the ion CON–, the most stable resonance structure is the resonance structure in which the nitrogen atom which is more electronegative has a formal charge of -2 and less electronegative carbon has a formal charge of -1 as shown.

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Answer:

2Ag⁺ (aq) + 2OH⁻ (aq) → Ag₂O (s) + H₂O (l)

Explanation:

Step 1: RxN

2AgNO₃ + 2NaOH → Ag₂O + 2NaNO₃ + H₂O

Step 2: Define states of matter

2AgNO₃ (aq) + 2NaOH (aq) → Ag₂O (s) + 2NaNO₃ (aq) + H₂O (l)

Step 3: Total Ionic Equation

2Ag⁺ (aq) + 2NO₃⁻ (aq) + 2Na⁺ (aq) + 2OH⁻ (aq) → Ag₂O (s) + 2Na⁺ (aq) + 2NO₃⁻ (aq) + H₂O (l)

Step 4: Cancel out spectator ions

2Ag⁺ (aq) + 2OH⁻ (aq) → Ag₂O (s) + H₂O (l)

Answer:

36.08%

Explanation:

We are given the overall formula of the compound as: CuSO4•5H2O

Now, atomic mass of the elements are;

Cu = 63.55 g/mol

S = 32.07 g/mol

O = 16 g/mol

H20 = 18.02 g/mol

Now, let's calculate the total mass of the compound:

(63.55 g/mol) + (32.07 g/mol) + 4(16 g/mol) + 5(18.02 g /mol) = 249.72 g/mol

From the above, water in the compound is 5(H20)

Thus, total water atomic mass = 5 × 18.02 = 90.1 g/mol

Thus, percentage of water = (atomic mass of water/total mass of compound) × 100%

Percentage of water = (90.1/249.72) × 100% = 36.08%