Therefore, they
experience a
and produce
surface tension.

Answer:

Explanation:fog

Answer:

which language is this

Explanation:

Answer:

[tex]thank \: you[/tex]

Question:-

Convert 4cm to m

Solution:-

Lets do

First note down the below formula

[tex]\boxed{\sf 1m=10^{2}cm}[/tex]

Then

[tex]\boxed{\sf 1cm=10^{-2}cm}[/tex]

Now we are given 4cm

So convert

[tex]\\ \sf\longmapsto 4\times 10^{-2}m[/tex]

If we simplify to decimal

[tex]\\ \sf\longmapsto 4cm=0.04m[/tex]

Hence done .

The work done on the luggage by the force is 62.78 J

The given parameters;

mass of the luggage, m = 20 kg

coefficient of friction, μ = 0.4

distance moved by the object, d = 0.8 m

To find:

The work done on the luggage by the force is calculated as;

Work-done = F x d

work done = ma x d

[tex]work -done = m\times \mu \times g \times d\\\\work-done = 20 \times 0.4 \times 9.81 \times 0.8\\\\work-done = 62.78 \ J[/tex]

Thus, the work done on the luggage by the force is 62.78 J

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Explanation:

Answer:

c. Should uncontrolled nuclear reactions be used for military applications?

Explanation:

The question on wether to use technology for military applications, is not a science question but a moral dilemma

The question that can not be answered by science is the question; "Should uncontrolled nuclear reactions be used for military applications?".

Science is empirical in its approach. This implies that the questions that are answered by science are questions that are testable and can be be verified in a laboratory.

Science does not answer questions that deal with the opinions of various individuals. That is completely outside the purview of scientific investigation.

Hence, science does not answer the question; Should uncontrolled nuclear reactions be used for military applications?

This question deals with moral values and the opinions of people about a matter and not empiricism.

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Answer:

490 meters

Explanation:

hope this helps!

Answer:

[tex]v_{1} = 19 m/s[/tex]

Explanation:

[tex]v_{1} = \frac{(v_{2} + u)}{2}[/tex], where [tex]v_1[/tex] = avg. velocity, [tex]v_2[/tex] = final velocity, and [tex]u[/tex] = initial velocity.

Answer:

scientists might modify or revise a hypothesis after a trial run that didn't go how they thought.

Answer:

No because the heat that moved out of the water to make ice caused an even greater disorder in the environment around it.

Explanation:

1. Acceleration is the change in velocity of an object per unit time.

2. 36 km/h

= 36000 m/60×60 s

= 36000 m/3600 s

= 10 m/s

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Answer:

m uncertainty percentage :

+- 2.5

+- 7.5

+- 12 5

+- 17.5

+- 25

+- 30

M uncertainty percentage = 16.5

m + M uncertainty percentage;

+- 19

+- 24

+- 29

+-34

+- 41.5

+- 46.5

ex 50 × 5 ÷100 = 2.5

The racer is running at a speed of approximately 96.943 meters per second at 350 meters after the parachute is opened.

According to this question, the drag race accelerates and later decelerates uniformly and we can determine the final speed of the vehicle by the following kinematic formula:

[tex]v = \sqrt{v_{o}^{2}+2\cdot a\cdot s}[/tex] (1)

Where:

Acceleration phase

If we know that [tex]v_{o} = 0\,\frac{m}{s}[/tex], [tex]a = 17\,\frac{m}{s^{2}}[/tex] and [tex]s = 402\,m[/tex], then the final speed of the drag racer is:

[tex]v = \sqrt{\left(0\,\frac{m}{s} \right)^{2} + 2\cdot \left(17\,\frac{m}{s^{2}} \right)\cdot (402\,m)}[/tex]

[tex]v \approx 116.910\,\frac{m}{s}[/tex]

Deceleration phase

If we know that [tex]v_{o} \approx 116.910\,\frac{m}{s}[/tex], [tex]a = -6.10\,\frac{m}{s^{2}}[/tex] and [tex]s = 350\,m[/tex], then the final speed of the drag racer is:

[tex]v = \sqrt{\left(116.910\,\frac{m}{s} \right)^{2} + 2\cdot \left(-6.10\,\frac{m}{s^{2}} \right)\cdot (350\,m)}[/tex]

[tex]v \approx 96.943\,\frac{m}{s}[/tex]

The racer is running at a speed of approximately 96.943 meters per second at 350 meters after the parachute is opened.

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The lithosphere is the solid layer of Earth, the hydrosphere is the water-based part, and the atmosphere is the air, they work together to shape the biosphere.

The lithosphere is the soil part that composes the Earth's planet (i.e., the soil), the hydrosphere refers to oceans and all water bodies, while the atmosphere is the layer of air. These three layers interact with biotic factors to shape the biosphere.

In conclusion, the lithosphere is the solid layer of Earth, the hydrosphere is the water-based part, and the atmosphere is the air, they work together to shape the biosphere.

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Explanation:

Here,

initial velocity(u)=25m/s

final velocity (v)=0m/s

time taken(t)= 5 second

Now,

Answer:

[tex]{ \sf{F=Ee}}[/tex]

Explanation:

F » Force

E » Electric field intensity

e » magnitude of charge

The work-energy theorem explains the idea that the net work - the total work done by all the forces combined - done on an object is equal to the change in the kinetic energy of the object. After the net force is removed (no more work is being done) the object's total energy is altered as a result of the work that was done.

This idea is expressed in the following equation:

is the total work done

is the change in kinetic energy

is the final kinetic energy

is the initial kinetic energy

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Answer:

  distance traveled

Explanation:

Assuming he ends where he started, his displacement is zero, while his distance traveled is 17 +13 +137 = 167 km. He would want to be paid by distance traveled.

Answer:

Explanation:

ASSUMING that velocity is constant during the 3 seconds,

or that we are satisfied with AVERAGE momentum

p = mv = 24(7/3) = 56 kg•m/s

Answer:

kinetic energy = 1/2mv²

k.E =1/2 X 0.5 X 3²

k.e = 9/4

K.E = 2.25j

Answer:

f = c / y      where y is the wavelength

f1 = 3 *10E8 m/s / .001 m = 3 * 10E11 / s

f2 = 3 * 10E8 m/s / 1 m = 3 * 10E8 / s

Explanation:

acceleration = change in velocity / change in time

a = v2-v1

- - - - - -

t

V1 = 0 ( since she stopped)

V2 = 9 m/s

t =15s

a = 9 - 0

- - - -

15

= 0.6m/s^2

Answer:

It is necessary to search for new sources of energy because the sources we have now are non-renewable and exhaustible. The usage of these sources are increasing day by day and if this continues then one day we wlii be left with none so it is necessary to search for new sources of energy

The magnitude of the electric field due to the proton in a hydrogen atom at a distance of 5.29 x 10-11 m, the expected position of the electron in the atom will be a) 1012 N/C

Electric field is defined as the electric force per unit charge. The direction of the field is taken to be the direction of the force it would exert on a positive test charge.

electric field = k * q / r^2

given

distance (r) =  5.29 x 10-11 m

q of proton = + 1.602 * 10 ^ -19 C

k = 9 * 10 ^9 Nm^2 / C^2

Electric field = (9 * 10 ^9 Nm^2 / C^2 *  1.602 * 10 ^ -19 C )/  (5.29 x 10-11 m)^2

                    = 14.418 * 10 ^ (-10) / 27.98 * 10 ^ (-22)

                   = 0.5153 * 10 ^12 N/C

correct option a) 1012 N/C

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Scobie will take 10 days to drive around Earth's equator.

To calculate the time that takes Scobie to drive around Earth's equator we need to find the distance, which is given by the equation of a circumference:

[tex] d = 2\pi r [/tex]

Where:

r: is the Earth's radius = 6371 km

Then, the distance is:

[tex] d = 2\pi r = 2\pi*6371 km = 40030.2 km [/tex]

Now, if we divide the above distance by the speed of the car we can find the time:

[tex] t = \frac{d}{v} = \frac{40030.2 km}{160.0 km/h} = 250.2 h*\frac{1 d}{24 h} = 10 d [/tex]

Therefore, Scobie will take 10 days to drive around Earth's equator.

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Answer:

please in english......................................

Explanation:

We have that the time the dive lasted was

[tex]T=0.076771 hours[/tex]

From the Question we are told that

Fall distance 19.5 miles

Velocity v= 254 mi/hr

Generally the equation for the Time   is mathematically given as

[tex]T=\frac{v}{d}\\\\T=\frac{19.5}{254}[/tex]

[tex]T=0.076771 hours[/tex]

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Answer:

Final velocity (v) of an object equals initial velocity (u) of that object plus acceleration (a) of the object times the elapsed time (t) from u to v. Use standard gravity, a = 9.80665 m/s2, for equations involving the Earth's gravitational force as the acceleration rate of an object.

Explanation: