If the basketball weighed more after it was inflated with air than when it was deflated, this show that gas is matter because it takes up space and has mass.
Generally matter can be described as a physical substance. Descriptively it can be said that anything that takes up space and has mass is called as matter.
Clearly, an inflated basketball is bigger in size than a deflated basketball. So, it can be said that with the help of air the inflated basketball has gained size. The basketball weighed more after it was inflated with air than when it was deflated, meaning the air has mass.
Therefore, this show that gas is matter because it takes up space and has mass.
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How much tension must a cable withstand if it is used to accelerate a 1800- kg car vertically upward at 0.60 m/s2
Answer:
Approximately [tex]1.9\times 10^{4}\; {\rm N}[/tex] (rounded up) assuming that [tex]g = (-9.81)\; {\rm N \cdot kg^{-1}}[/tex] (downwards.)
Explanation:
The car is accelerating at a constant [tex]a = 0.60\; {\rm m\cdot s^{-2}}[/tex] (positive since the car is accelerating upwards.) Hence, the net force on this car will be:
[tex]\begin{aligned}F_{\text{net}} &= m\, a \\ &= 1800\; {\rm kg} \times 0.60\; {\rm m\cdot s^{-2}} \\ &= 1080\; {\rm N}\end{aligned}[/tex].
Note that since net force points in the same direction as acceleration (upwards,) [tex]F_{\text{net}}[/tex] is also positive.
The main forces on this car are:
Weight (downward).Tension from the cable (upward): [tex]F(\text{tension})[/tex].With a mass of [tex]m = 1800\; {\rm kg}[/tex], the weight on this car will be [tex]m\, g = 1800\; {\rm kg} \times (-9.81)\; {\rm N \cdot kg} = (-17658)\; {\rm N}[/tex] (negative since weight points downwards to the ground.)
The net force on this car is the sum of the external forces:
[tex]F_{\text{net}} = F(\text{tension}) + m\, g[/tex].
It is shown that [tex]F_{\text{net}} = 1080\; {\rm N}[/tex] while [tex]m\, g = (-17658)\; {\rm N}[/tex]. Substitute both values into the equation and solve for [tex]F(\text{tension})[/tex]:
[tex]1080\; {\rm N} = F(\text{tension}) + (-17658)\; {\rm N}[/tex].
[tex]\begin{aligned}F(\text{tension}) &= 1080\; {\rm N} + 17658\; {\rm N} \approx 1.9\times 10^{4}\; {\rm N} \end{aligned}[/tex] (rounded up.)
A 487 kg bear grasping a vertical tree slides
down at constant velocity.
The acceleration of gravity is 10 m/s².
What is the friction force that acts on the
bear?
Answer in units of N.
Answer:
4870 N
Explanation:
Since he is not accelerating
the force is equal to his weight mg = 487 * 10 = 4870 N
I need this answer, urgently
If the mass of an object is 2 kg, the gravitational field strength is 4 ms and the
change in height is 2 m, what is the change in gravitational potential energy stored?
The change in gravitational potential energy stored in 16 Jule.
What is gravitational potential energy?
In classical mechanics, of the gravtitational potential at in a location is equal to the work per unit mass that's would be needed to Move an object to that locations from a fixed references location. It is analogous to the electric potential with the mass playing the role of charge.
Sol-As per the given question ∆PE = mgh
M= skg
g= 4m/s^2
∆h = 2m
∆PE = 2m×4m×2m
= 16 Joules.
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A football player runs due east for 30 yards then cuts up the field due north for a
distance of 35 yards before running into the end zone.
What is the total displacement of the football player?
Total displacement of the football player is 49.09 yards.
What is Displacement?Displacement is defined as the change in position of an object. It is a vector quantity and has a direction and magnitude.
A football player runs due east for 30 yards then cuts up the field due north for a distance of 35 yards before running into the end zone.
Total displacement of the football player is 49.09 yards.
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A football player runs due east for 30 yards then cuts up the field due north for a
distance of 35 yards before running into the end zone.
What is the total displacement of the football player?
You may find out an object's total displacement—or how far it is from its point of origin—by using the football player's total displacement, d=46.10yd,definite integral of velocity function of an item.
Is the overall displacement equivalent to the distance?It's common for people to believe that distance & displacement are really just different labels for the same thing. Displacement and distance are different ideas, though. The overall distance traveled by an object during its voyage will be more than the displacement between those two points if it changes direction.
How is displacement volume calculated?In terms of its density and volume, the displaced fluid's mass can be stated as m = V. W = mg, where g is the acceleration due to gravity, is the weight of the fluid that has been displaced. As a result, W = Vg can be used to indicate the weight of the displaced fluid.
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Part G
List several examples of applied force, normal force, and friction?
Examples of following forces mentioned -
Normal Force :- Book kept on the table , Girl standing on floor, ...infact every object experience a normal force in the universe.Applied Force :- this term literally means force responsible for the movements in the object or changes in the object , like throwing stones , playing ball , pushing an object , moving a pen from desk to chair..etc...Friction force :-Force responsible for the resistance in the flow of system's work , For example air resistance a type of obstruction experienced in air when a Paper ball is thrown from terrace of a society , Viscosity of honey is also an example of liquid friction / viscous drag...Sometimes friction is useful for the stability of universe. But some times its necessary. It is due to this force we walk without collapsing into the core of earth as earth is a market of gravitational field. To substantiate the field effect , friction is necessary to necessitate the life in planet. Rubbing of hands in winter season is also another example.To Know more about different forces -
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Below are three different arrangements of two mirrors near a source of
light. For each arrangement, a light ray is drawn from the source to the
first mirror. In which of these arrangements would the light eventually
travel parallel to, but in the opposite direction to, the original light. [This
type of device is called a retro-reflector.]
A.
B.
C.
In arrangement B) , mirrors are placed mutually perpendicular to each other .
A retroreflector is a device or surface that reflects radiation back to its source with minimum scattering.
When two mirrors are placed perpendicular to each other , and if a light ray that strikes an object consisting of two mutually perpendicular reflective surfaces is reflected back exactly parallel to the direction to the source it came from.
out of all arrangements , it can be observed that in arrangement B) , mirrors are placed mutually perpendicular to each other .
hence , correct option will be
option B
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Assuming we have a 1 cm long empty solenoid with a 1 mA current flowing through it, how many loops do we need to have in the solenoid to generate a 1 T magnetic field inside the solenoid? Give your answers as integers rounded up
N =
What if we had an iron core inside the solenoid with relative permeability of 64,000 ? How many loops would we need in this case?
N =
(a) To generate a 1 T magnetic field inside the solenoid, we need 7.96 x 10⁶ turns.
(b) If we had an iron core inside the solenoid with relative permeability of 64,000, the number of turns would be 124 turns.
What is the number of turns of the solenoid?
The number of turns of the solenoid is determined by applying the following equation for magnetic field strength at the center of the solenoid.
B = μnI
where;
μ is the permeability of free space = 4π x 10⁻⁷ T/AI is the current = 1 mA = 0.001 AB is magnetic field strength = 1 Tn is number of turns per lengthn = B/ μI
N/L = B/μI
N = (BL)/μI
where;
L is the length of the solenoidn = (1 x 0.01) / (4π x 10⁻⁷ x 0.001)
n = 7.96 x 10⁶ turns
If we had an iron core inside the solenoid with relative permeability of 64,000, the number of turns would be calculated as;
N = (BL)/(μI x μr)
where;
μr is the relative permeabilityN = (1 x 0.01) / (4π x 10⁻⁷ x 0.001 x 64,000)
N = 124 turns
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34. An object with mass 5.00 kg is being pushed up an inclined plane with a constant force F. The plane makes an angle of 30.0with respect to the horizontal . The object is moving with constant velocity . The coefficient of kinetic friction between the object and the surface is 0.300 . What is the magnitude of this force ?
The magnitude of the force is 12.73N.
What is force?
this can be defined as a push or pull in a particular direction. It is calculated using the formula:
F=m*a
Where,
m=mass of the object
a=acceleration
What is magnitude of force?
This is the quantity or strength of the force. It is calculated using the formular:
Normal Force, N=m*g*Cos θ
From the question given:
m =5.00kg
Cos θ= 30°
g=9.8m/s²
Coefficient of Friction, μ=Frictional force/Normal force
=F/N
coefficient kinetic friction, μ=0.300
Magnitude of Force F= Coefficient of Friction*Normal Force
=μN
=μmg Cos θ
F= 0.300*5.00*9.8*Cos30°
F=0.300*5.00*9.8*0.8660
The magnitude of Force,F=12.73N
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In the article the study author recommends going on a photo hunt what was the purpose of this activity with choices becoming less introvered
Becoming less neurotic
Becoming more extroverted
Becoming more assertive
In the article the study author recommends going on a photo hunt and the purpose of this activity is Becoming more assertive.
What is the reason why the author gave the recommedation about going for the photo hunt ?The reason why the author gave the recommedation about going for the photo hunt is that the activity can bring about assertiveness which has not been seen in the participants before.
It should be noted that with the assertion, there will be display of confident as well as forceful personality as they are taking part in the photo hunt, because it involves the activity whereby the participants will be competing with themselves in the collection of the greatest number of objects which is been goteen from the predetermined list.
In conclsion, the recomedation about going to the photo hunts by te author was made so that they can become more assertive.
Therefore , the last option is correct.
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A ball at the end of a string of length 2m rotates at a constant speed in a horizontal circle. It makes 7 rev/s.
What is the period of the ball’s motion? Answer in units of s.
The period of the ball's motion is 0.142 s and the frequency of the motion is 7 Hz.
What is the period of the ball's motion?The period of the ball's motion is calculated by applying the following kinematic equation as shown below.
v = 2πr/T
ωr = 2πr/T
ω = 2π/T
T = 2π/ω
where;
T is the period of the ball's motionω is the angular speed of the ballThe angular speed of the ball = 7 rev/s = 7 rev/s x 2π rad/rev = 14π rad/s
T = 2π/14π
T = 1/7 s = 0.142 s
The frequency of the ball's motion is the inverse of the period of the motion and can be calculated as follows;
f = 1/T
f = (1) / (1/7) = 7 Hz
Thus, the period of the ball's motion is determined from the angular speed of the ball while the frequency of the ball's motion is the reciprocal of the period of the motion.
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In the lab downstairs physics majors use a rotating mirror to measure the speed of light within a few percent of the actual value they switch the mirror from rotating clockwise at 115 rad/s to counter clockwise at 115 rad/s over the course of 85 seconds. Assume constant angular acceleration.
QUESTION: how many revolutions does the rotating mirror go through when it gets to a 0 angular velocity along the way to new speed. SHOW WORKING OUT
The number of complete cycles the rotating mirror goes through before the angular velocity gets to zero is approximately 1166.8 revs
What is angular velocity?Angular velocity is the ratio of the angle turned to the time taken.
The kinematic equation for angular velocity are presented as follows;
ω = ω₀ + α·t
θ = θ₀ + ω₀·t + 0.5·α·t²
Where;
θ₀ = The initial angle turned = 0
ω₀ = The initial angular velocity of the mirrors = 115 rad/s clockwise
α = The angular acceleration = (115 - (-115))rad/s/(85 s) = -46/17 m/s²
t = The duration of the motion;
When the angular velocity, ω is zero, we get;
0 = 115 - 46/17·t
t = 85/2
Which indicates;
θ = 0 + 115× (85/2) + 0.5×(46/17) ×(85/2)² = 7331.25
θ = 7331.25 radians
θ = 7331.25/(2×π) ≈ 1166.8 rev
The mirrors would have turned through approximately 1166.8 revolutions when the angular gets to zero
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what is the conclusion for the physics lesson acceleration and free falling objects grade 9
The simple conclusion I can make from the task given above is that all the objects in the universe possess constant acceleration under the influence of a free fall is actually due to gravity.
How objects free falling objects has the same acceleration under the influence of gravity.It has been practically proven that all objects or bodies; regardless of their masses have the same acceleration as long as they are under a free fall as a result of the Earth's gravitational force.
So therefore, it can now be deduced with understanding that all free falling objects have the same acceleration due to gravity.
Complete question:
What conclusion can you make on acceleration and free falling objects grade?
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this diagram shows an amusement park roller coaster ride.(a) on what part of the ride is the car moving slowest?(b)on what part of the ride is the car moving fastest?(c)The car become stuck at point p which is 50 meters above the ground.To the relief of the presenters the car eventually move again and passes point R at 20m/s.Approximately how height is point R?The car and its passengers have a combined mass of 700kg.
Answer:
KE + PE = constant conservation of energy
At 50 m KE = zero and PE = m g h
PE = 700 kg* 9.80 m/s^2 * 50 m = 343,000 Joules
PE + KE = 343,000 J
At point R
PE = 343,000 J - 1/2 * 700 kg * 400 m^2 / s^2 = 203,000 J
m g h = 203,000 J at point R
h = 203,000 J / (700 kg * 9.80 m/s^2 = 29.6 m height of point R
Check:
343,000 = 700 * 9.80 * 29.6 + 350 * 400 = 343,000
Adding PE and KE at point R
What do astronomers refer to as the retrograde motion of the planets? A. apparent movement of the planets eastward in a single night B. apparent movement of the planets westward in a single night C. apparent movement of the planets eastward from night to night D. apparent movement of the planets westward from night to night
Astronomers refer to as retrograde motion of the planets to an apparent movement of the planets westward from night to night.
What is a retrograde motion?The retrograde movement or the retrogradation of the planets is the apparent movement that a planet makes in the opposite direction to the other bodies that make up the system where it is.
This movement is actually an optical illusion that occurs due to the difference in speed between the different planets, looking as if one of them were moving backwards from east to west.
Therefore, we can confirm that the correct answer is option D. apparent movement of the planets westward from night to night.
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The force acting on a particle varies as in the figure below. (The x axis is marked in increments of 10.0 m.)
Find the work done by the force as the particle moves across the following distances.
(a) from x = 0 m to x = 80.0 m
(b) from x = 80.0 m to x = 120.0 m
(c) from x = 0 m to x = 120.0 m
The amount of work that the force does as the particle crosses the 21.0 J. Work done refers to the amount of energy used by a force that move an object.
What exactly does science work on?A force's output is defined as the product of the force's component acting in the displacement's direction and its magnitude. Formula. The following formula can be used to determine work: multiply force by distance traveled inside the direction of force. W = F × d.
What type of work is done?A force is said to have completed its work when it exerts itself on an object and the object really moves in the direction of the applied force. A product of the force as well as the object's displacement in the force's direction is the work that the force produces.
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Answer:
Explanation:
The work is numerically equal to the area of the figure lying under the graph of the function.
(a)
A₁ = (1/2)·80·6 = 240 J
(b)
A₂ = (1/2)·40·3 = 60 J
(c)
A = A₁ + A₂ = 240 + 60 = 300 J
Pls helpppppppppppppppp
Answer:
Explanation:
velocity describes the directional speed of an object in motion as an indication of its rate of change in position (includes magnitude but not the direction) while acceleration is the change in velocity (inculdes direction and magintude)
If 30% of the nitrogen atoms have a mass of 15amu and 70% of the nitrogen atom isotopes have an atomic mass of 14 amu. What is the average mass?
The average mass of nitrogen isotopes is 14.3 amu.
What is average mass?By adding the relative average atomic masses of each atom in the system, the mass of an ion or molecule is computed and weighted for its isotopic composition. Hydrogen, for instance, has an average atomic mass of 1.00797 Da, while carbon's is 12.01115 Da.
Given parameter:
30% of the nitrogen atoms have a mass = 15amu.
70% of the nitrogen atom isotopes have an atomic mass = 14 amu.
So, average mass of nitrogen = 15 amu × 30% + 14 amu × 70%
= 14.3 amu.
Hence, the average mass of the nitrogen is 14.3 amu.
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White's style is directed at all but one of the following. Which one?
White's narrative approach encourages families to option a. create alternative accounts of their lives.
What is the narrative therapy approach?A type of therapy called narrative therapy seeks to detach the patient from the issue, allowing them to externalize their problems rather than keep them inside. It depends on the person's own abilities and sense of purpose to get them through challenging situations.
Note that Writing or reading stories with problems and answers related to the person's circumstances might be part of a narrative approach. The goal of narrative techniques is to give children a different means of expressing their feelings through words.
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See full question below
White's narrative approach encourages families to:
a. create alternative accounts of their lives
b. gain awareness of the origins of their problem
c. attend to reflecting team observations
d. develop a problem-saturated perspective
calculate the density of 1mole of oxygen ata pressure of 4×10^-4Nm^-2 and a temprature of 273.2°K
The density of 1 mole of oxygen at a pressure of 4×10⁻⁴ Nm⁻² and a temprature of 273.2 K is 2.82×10⁻⁶ g/m³
How to determine the density of oxygenWe'll begin by obtaining the volume of the oxygen. This can be obtained as follow:
Number of mole (n) = 1 molePressure (P) = 4×10⁻⁴ Nm⁻²Temperature (T) = 273.2 K Gas constant (R) = 8.314 m³Nm⁻²/KmolVolume = ?PV = nRT
Divide both sides by P
V = nRT / P
V = (1 × 8.314 × 273.2) / 4×10⁻⁴
V = 5678462 m³
Finally, we shall determine the density of the oxygen. This can be obtained as follow:
Mass of 1 mole of oxygen = 16 gVolume of 1 mole of oxygen = 5678462 m³Density of oxygen =?Density = mass / volume
Density of oxygen = 16 / 5678462
Density of oxygen = 2.82×10⁻⁶ g/m³
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A boy standing on top of a cliff throws a rock horizontally. The rock hits the ground 2.5 seconds later. How high is the cliff?
Answer:
30 . 7 m
Explanation:
It takes 2.5 seconds for the rock to fall the vertical height
d = 1/2 a t^2
d = 1/2 ( 9.81)(2.5^2) = 30.7 m
500 N of force on a large box for 45 seconds, but it does not move.
How much work is being done?
What is the power?
The work done will be zero, since the object does not move. Also, the power will be zero since the work done is zero because the force must be applied in the direction of motion.
What is work done?Scientifically, the formula for the work done is given by: W = F * d. In this case, the force acting on the block is constant, but the direction of the force and the direction of displacement due to this force are it's different. where force F acts on displacement d at angle θ.The work done by a force is defined as the product of the displacement component of the force and the magnitude of that displacement. method. Work can be calculated by multiplying the force by the displacement in the direction of the force as There are many examples of work in our daily life. For example, a horse pulling a plow in a field, a father pushing his shopping cart in the mall, a student lifting a bag full of books on his back or shoulder.To learn more about work done from the given link :
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A force of 10 N acts on a toy car of mass 2kg. What is the acceleration if the force is doubled?
Explanation:
According to newton's second law.
The acceleration of the car would be 10 m/s² if the force (10 N) on it is doubled.
We know that the acceleration of an object can be calculated using the formula ⇒ a = F/m (i)
Here, the force experienced by the car is ⇒ F = 10 N
If this force is doubled we would have ⇒ 2×10 ⇒ 20 N (ii)
The mass of the car is ⇒ m = 2 kg (iii)
Now, putting the values of the doubled force and mass (ii and iii) in (i), we get ⇒ a = 20/2
a = 10 m/s²
Therefore, the car has an acceleration of 10 m/s² when the force on it is doubled.
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A physicist steps on a piece of gum. The gum exerts a constant non conservative force of 3 newtons as she picks up her foot. If her foot is 1 kg how much force would she have to exert to accelerate her foot vertically at 6 m/s2?
A) 15 newtons
B) 18 newtons
C) 28 newtons
D) 22 newtons
E) 25 newtons
The Force exerted by the physicist as she steps on a piece of gum is 18 Newtons and the right option is B) 18 Newtons.
What is force?Force can be defined as the product of mass and acceleration. The S.I unit of force is Newton (N) or kilogram- meter-per-seconds (kgm/s).
To calculate the amount of force she would exert, we use the formula below.
Formula:
F = F'+mg+ma............. Equation 1Where:
F = Amount of force she would exertF' = The gum's non conservative forcem = Mass of her foota = Accelerationg =Acceleration due to gravityFrom the question
Given:
F' = 3 Nm = 1 kga = 6 m/sg = 9 m/s²Substitute these values into equation 1
F = 3+(1×9)+(1×6)F = 3+9+6F = 18 NewtonsHence, the force exerted by the physicist is 18 N.
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In a barfight, one person swings a punch with their bare hand and knocks another person over a table in spectacular fashion. The person who threw the punch remains stationary, their hand undamaged.
Why does this defy physics? Give Equations/Laws to justify your answer
The person who threw the punch remains stationary, and their hand undamaged because the impulse received by the opponent is greater than the reaction force experienced by the person who threw the punch.
What is Newton's third law of motion?Newton's third law of motion states that for every action, there is an equal and opposite reaction. That is, action force and reaction force are equal and opposite.
Mathematically, the Newton's third law of motion can be stated as follows;
Fa = Fb
where;
Fa is the action force applied Fb is the reaction force received due to the applied forceIn a barfight, when one person swings a punch with their bare hand and knocks another person over a table in spectacular fashion. The person who threw the punch remains stationary, their hand undamaged because the impulse received by the opponent is greater than the reaction force experienced by the person who threw the punch.
The force applied by the person who threw the punch maybe equal and opposite to reaction he received but the impulse experienced by the opponent is greater.
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Patrick walks 6 meters to the south, 3 meters west, 2 meters to the north, and 5 meters to the east. Which of the following is true?
A. His displacement was 4 meters.
B. His distance traveled was 6 meters.
C. His distance traveled was 16 meters.
D.His displacement was 17 meters.
The best graph to use if I want to compare the price of six different cars would be a
The best graph to use if I want to compare the price of six different cars would be a bar graph
A bar graph is a graphical representation of the given data . It uses bars that extend to different heights to depict value .
Bar graphs are used to compare different type of things between different groups or to see changes over a period of time. Hence , bar graph will fits the best if one want to compare the price of six different cars .
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Please help, this question is on viscosity!
A steel ball of mass m falls in a viscous liquid with a terminal velocity v. Another steel ball of mass 64 m will fall through the same liquid with a terminal velocity
(1) v
(2) 4 v
(3) 8 v
(4) 16 v
(5) 2 v
how does Cavendish's experiment disprove the idea that only planet-sized masses cause gravitational attraction?
It is evident from Isaac Newton's equation for universal gravitation that ANY TWO masses will act as an easily calculable attractive force on one another. Cavendish proved that this was accurate (for masses that he gathered in his shed).
What is Cavendish's experiment?The Cavendish experiment was the first to accurately determine the gravitational constant and the force of gravity between masses in a laboratory setting. Cavendish's work does not directly mention the gravitational constant due to the unit norms in use at the time. Instead, the outcome was initially stated as Earth's specific gravity, or alternatively, as Earth's mass. The first precise values for these geophysical constants came from his experiment.
Thus, by measuring the universal gravitational constant though experiment, Cavendish's experiment makes easy to calculate gravitational attraction force for minute objects also.
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