This Continuity Editing/Cutting device is used in Classical Hollywood Cinema: match on action O True False

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Answer 1

True, This Continuity Editing/Cutting device is used in Classical Hollywood Cinema.

Match on action is a common continuity editing/cutting technique used in Classical Hollywood Cinema, where the editor cuts from one shot to another while maintaining visual continuity between the two shots by showing the continuation of an action or movement from one shot to the next. This helps to create a smooth and seamless flow of action on screen and maintains the illusion of reality for the viewer.

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use a known maclaurin series to obtain a maclaurin series for the given function. f(x) = sin x 3 f(x) = [infinity] n = 0 find the associated radius of convergence r. r = correct: your answer is correct.

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To obtain a Maclaurin series for the given function f(x) = sin x, we can use the known Maclaurin series for sin x, which is:
sin x = x - (x^3)/3! + (x^5)/5! - (x^7)/7! + ...


Multiplying this series by x^3 gives:
sin x 3 = x^3 - (x^6)/3! + (x^8)/5! - (x^10)/7! + ...
Therefore, the Maclaurin series for f(x) = sin x 3 is:
f(x) = x^3 - (x^6)/3! + (x^8)/5! - (x^10)/7! + ...
To find the associated radius of convergence r, we can use the ratio test. The nth term of the series is given by:
a_n = (-1)^(n-1) * (x^3)^(2n-1) / (2n-1)!
Using the ratio test, we have:
lim |a_(n+1) / a_n| = lim |(-1)^n+1 * (x^3)^(2n+1) / (2n+1)!| / |(-1)^n * (x^3)^(2n-1) / (2n-1)!|
= lim |(-1) * x^6 / ((2n+1)(2n))| = 0
Since the limit is less than 1 for all values of x, the series converges for all x. Therefore, the radius of convergence is infinity, which is consistent with the fact that sin x has an infinite radius of convergence.

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show that if a basis i is not optimal, then there is an improving swap, which means thtat there is a pair of indices

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I think you may have accidentally cut off the question. Can you please provide the full question so that I can assist you better?

An old community soccer field, whose area is 600 yd², is enlarged by a scale factor of 9 to create a new outdoor recreation complex to host additional activities for field hockey, football, baseball, and swimming. What is the total area of the new recreation complex? Enter your answer in the box.

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The area of the new recreation complex is 48600 yd². The scale factor of the old community soccer field is 9, and its area is 600 yd². The new complex accommodates field hockey, football, baseball, and swimming.

To determine the new area, we need to know the following equation:

New area = (scale factor)² × old area

In this problem, we already know the old community soccer field's area, which is 600 square yards. The new outdoor recreation complex's total area, multiply the old soccer field's area by the scale factor squared:

Total area of the new recreation complex = (scale factor)² × area of the old soccer field

= (9)² × 600 yd²

= 81 × 600 yd²

= 48600 yd²

The area of the old community soccer field is 600 square yards. When an old community soccer field is enlarged by a scale factor of 9, a new outdoor recreation complex is created.

Therefore, the area of the new recreation complex is 48600 yd².

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evaluate ∫c f · dr, where f(x,y)=<-3y,5x> and c is the circle x^2+y^2=25 taken in the counterclockwise direction

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To evaluate the line integral ∫c f · dr, we first need to parameterize the circle x^2+y^2=25. We can do this by letting x = 5cos(t) and y = 5sin(t), where t goes from 0 to 2π in the counterclockwise direction.

Next, we need to find the differential of r, which is dr = <-5sin(t), 5cos(t)> dt.

Then, we can evaluate the line integral by plugging in our parameterization and differential:

∫c f · dr = ∫0^2π <-3(5sin(t)), 5(5cos(t))> · <-5sin(t), 5cos(t)> dt

= ∫0^2π -75sin^2(t) + 125cos^2(t) dt

Using the identity sin^2(t) + cos^2(t) = 1, we can simplify this to:

∫0^2π 50cos^2(t) - 75 dt

= [50/2 (sin(t)cos(t)) - 75t] from 0 to 2π

= 0

Therefore, the line integral ∫c f · dr is equal to 0.

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Factor completely x3 8x2 − 3x − 24. (x − 8)(x2 − 3) (x 8)(x2 3) (x − 8)(x2 3) (x 8)(x2 − 3).

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The given expression x³ + 8x² - 3x - 24 can be completely factored as (x² - 3)(x + 8).

We can factor the given expression x³ + 8x² - 3x - 24 by grouping terms together.

(x³ + 8x²) - (3x + 24)

Taking out the common factors from the first group and the second group, we get:

x²(x + 8) - 3(x + 8)

Now, we can see that (x + 8) is a common factor in both terms, so we can factor it out:

(x + 8)(x² - 3)

Therefore, the factored form of the expression x³ + 8x² - 3x - 24 is (x + 8)(x² - 3).

So, we can rearrange the terms as shown below:

x³ + 8x² - 3x - 24 = (x³ - 3x) + (8x² - 24) = x(x² - 3) + 8(x² - 3).

Therefore, the completely factored form of x³ + 8x² - 3x - 24 is (x² - 3)(x + 8).

The given expression x³ + 8x² - 3x - 24 can be completely factored as (x² - 3)(x + 8).

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f5-7 the uniform plate has a weight of 500 lb. determine the tension in each of the supporting cables

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Steps to compute: Identify force on plate, equate vertical and horizontal plates, find angles of cables, determine tension components, and solve the equations.

To determine the tension in each of the supporting cables for the uniform plate with a weight of 500 lb, follow these steps:

1. Identify the force acting on the plate: The weight of the uniform plate (500 lb) acts vertically downward at the center of gravity of the plate. The tensions in the cables (T1 and T2) act upward at the attachment points of the cables to the plate.

2. Equate the vertical forces: The sum of the vertical components of the tensions in the cables must be equal to the weight of the plate for the plate to be in equilibrium.
[tex]T1_y + T2_y = 500 lb[/tex]


3. Equate the horizontal forces: Since there's no horizontal movement, the sum of the horizontal components of the tensions in the cables must be equal to zero.
[tex]T1_x - T2_x = 0[/tex]

4. Find the angles of the cables: Based on the given information (f5-7), find the angles that each cable makes with the horizontal or vertical axis. If the angles are not given, you will need more information to solve the problem.

5. Determine the tension components: Calculate the horizontal and vertical components of each tension ([tex]T1_x, T1_y, T2_x, and T2_y[/tex]) using trigonometric functions (sin and cos) and the angles you found in step 4.

6. Solve the equations: Using the equations from steps 2 and 3, solve for the tensions T1 and T2. You may need to use substitution or elimination method to solve the system of equations.

After completing these steps, you will have determined the tension in each of the supporting cables for the uniform plate with a weight of 500 lb.

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The cones below are similar. Work out the radius, r, of the larger cone.

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The radius, r, of the larger cone is equal to 24 mm.

How to calculate the volume of a cone?

In Mathematics and Geometry, the volume of a cone can be calculated by using this formula:

Volume of cone, V = 1/3 × πr²h

Where:

V represent the volume of a cone.h represents the height.r represents the radius.

Since both the large and small cones are similar, we can logically deduce the following proportion based on their side lengths;

19,008/704 = (r/8)³

19,008/704 = r³/512

r³ = 19,008/704 × 512

Radius of larger cone = 24 mm.

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

8. charlotte is purchasing a $90,000 house with a 30-year fixed-rate mortgage
that has an interest rate of 8.9%, and she will be making a down payment of
$9000, or 10% of the purchase price, so her mortgage will be for $81,000. the
house has been assessed at $88,000, and the property tax rate in charlotte's area
is 1.35%. charlotte will make monthly pmi payments for the first two years of the
mortgage based on the following table.
charlotte wants to know how much she will pay in total per month for the first
two years of the mortgage. let's calculate the amount for charlotte by answering
the following questions.
part i: how much will charlotte owe in principal and interest each month?
part ii: how much will charlotte owe in property taxes each month?
part iii: what are charlotte's monthly pmi premiums?
part iv: how much will charlotte pay in total per month for the first two years of
the mortgage?

Answers

To calculate the amount Charlotte will pay in total per month for the first two years of the mortgage, we need to calculate the principal and interest, property taxes, and monthly PMI premiums.

Let's go through each part:

Part I: Principal and Interest each month

To calculate the principal and interest payment, we can use the formula for a fixed-rate mortgage. The formula is:

P = (P * r * (1 + r)^n) / ((1 + r)^n - 1)

Where:

P = Principal amount (loan amount) = $81,000

r = Monthly interest rate = Annual interest rate / 12 = 8.9% / 12 = 0.00742 (approx.)

n = Number of monthly payments = 30 years * 12 months = 360

Using the formula, we can calculate the monthly principal and interest payment:

P = (81000 * 0.00742 * (1 + 0.00742)^360) / ((1 + 0.00742)^360 - 1)

P ≈ $614.06 (rounded to the nearest cent)

So, Charlotte will owe approximately $614.06 in principal and interest each month.

Part II: Property Taxes each month

To calculate the monthly property tax payment, we can use the assessed value of the house and the property tax rate. The formula is:

Property Tax = Assessed Value * Property Tax Rate

Property Tax = $88,000 * 0.0135

Property Tax ≈ $1,188

So, Charlotte will owe approximately $1,188 in property taxes each month.

Part III: Monthly PMI premiums

Based on the table provided, we would need more specific information to determine the exact monthly PMI premiums. If you can provide the table or the information about the premiums for each month, I can help you calculate the monthly PMI premiums.

Part IV: Total amount per month for the first two years

To calculate the total amount Charlotte will pay per month for the first two years, we sum up the principal and interest payment, property tax payment, and the monthly PMI premiums (once you provide the information). The calculation will be:

Total Amount = Principal and Interest + Property Taxes + Monthly PMI

Once we have the monthly PMI premiums, we can add them to the principal and interest payment and property tax payment to get the total amount per month for the first two years.

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Find a formula for the general term a, of the sequence, assuming that the pattern of the first few terms continues. (Assume that n begins with 1.) (2, 8, 14, 20, 26, ...) an-|3n- 1 x

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The formula for the general term a_n of the sequence is a_n = 6n - 4.

Given sequence: (2, 8, 14, 20, 26, ...)

Step 1: Observe the sequence and find the common difference.
Notice that the difference between each consecutive term is 6:
8 - 2 = 6
14 - 8 = 6
20 - 14 = 6
26 - 20 = 6

Step 2: Recognize that this is an arithmetic sequence.
Since there is a common difference between consecutive terms, this is an arithmetic sequence.

Step 3: Write the formula for an arithmetic sequence.
The general formula for an arithmetic sequence is a_n = a_1 + (n - 1) * d, where a_n is the nth term, a_1 is the first term, n is the position of the term, and d is the common difference.

Step 4: Plug in the known values and find the formula for the given sequence.
We know that a_1 = 2 and d = 6, so the formula for the sequence is:
a_n = 2 + (n - 1) * 6

Step 5: Simplify the formula.
a_n = 2 + 6n - 6
a_n = 6n - 4

The formula for the general term a_n of the sequence is a_n = 6n - 4.


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Find the median of the data.

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Answer:

10

Step-by-step explanation:

for a box plot, the line in the middle of the box is the median. in this example the line is at 10, so that's the median.

show that hv, wi = v1w1 − v1w2 − v2w1 2v2w2 defines an inner product on r 2

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The inner product defined by <v, w> = v1w1 + v1w2 + v2w1 + v2w2 does not satisfy the positivity property, thus it does not define an inner product in R^2.

To show that the inner product defined by <v, w> = v1w1 + v1w2 + v2w1 + v2w2 does not satisfy the properties of an inner product in R^2, we need to demonstrate that at least one of the properties is violated.

1. Positivity:

For an inner product, <v, v> should be greater than or equal to zero for any vector v, and <v, v> = 0 if and only if v is the zero vector.

Let's consider a non-zero vector v = (1, 0). Then <v, v> = 1(1) + 1(0) + 0(1) + 0(0) = 1. Since 1 is not equal to zero, the positivity property is violated.

Since the positivity property is not satisfied, the given expression does not define an inner product in R^2.

The complete question must be:

show that <v,w>=v1w1+v1w2+v2w1,v2w2 does not define an inner product of R^2.

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Three mathematics students have ordered a 14-inch pizza. Instead of slicing it in the traditional way, they decide to slice it by parallel cuts. Being mathematics majors, they are able to determine where to slice so that each gets the same amount of pizza. Where are the cuts made?

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The cuts are made parallel to each other and divide the pizza into equal portions.

If there are three students, then two cuts are needed to divide the pizza into three equal parts. The first cut is made in the center of the pizza, dividing it in half.

The second cut is made perpendicular to the first cut, passing through the center of the pizza and dividing it into thirds. Each student will receive a slice that is 1/3 of the pizza.

This method of slicing a pizza is called the "scientific method" or "mathematical method" and ensures that each person gets an equal portion, regardless of the shape of the pizza or the number of people sharing it.

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consider two nonnegative numbers p and q such that p+q=6. what is the difference between the maximum and minimum of the quantity (p^2q^2)/2?

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When considering two nonnegative numbers p and q such that p+q=6, the difference between the maximum and minimum of the quantity (p^2q^2)/2 is 81 - 0 = 81.

To find the maximum and minimum of the quantity (p^2q^2)/2, we can use the AM-GM inequality.
AM-GM inequality states that for any nonnegative numbers a and b, (a+b)/2 ≥ √(ab).


So, in our case, we can write:
(p^2q^2)/2 = (p*q)^2/2


Let x = p*q, then we have:
(p^2q^2)/2 = x^2/2
Since p and q are nonnegative, we have x = p*q ≥ 0.


Using the AM-GM inequality, we have:
(x + x)/2 ≥ √(x*x)
2x/2 ≥ x
x ≥ 0
So, the minimum value of (p^2q^2)/2 is 0.
To find the maximum value, we need to use the fact that p+q=6.


We can rewrite p+q as:
(p+q)^2 = p^2 + 2pq + q^2
36 = p^2 + 2pq + q^2
p^2q^2 = (36 - p^2 - q^2)^2


Substituting this into the expression for (p^2q^2)/2, we get:
(p^2q^2)/2 = (36 - p^2 - q^2)^2/2
To find the maximum value of this expression, we need to maximize (36 - p^2 - q^2)^2.


Since p and q are nonnegative and p+q=6, we have:
0 ≤ p, q ≤ 6
So, the maximum value of (36 - p^2 - q^2) occurs when p=q=3.


Thus, the maximum value of (p^2q^2)/2 is:
(36 - 3^2 - 3^2)^2/2 = 81

Therefore, the difference between the maximum and minimum of (p^2q^2)/2 is:
81 - 0 = 81.

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1. [10 pts] Let G be a graph with n ≥ 3 vertices that has a clique of size n − 2 but no cliques of size n − 1. Prove that G has two distinct independent sets of size 2.

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In graph theory, a clique is a subset of vertices where every pair of distinct vertices is connected by an edge, and an independent set is a set of vertices where no two vertices are connected by an edge. We have shown that G has two distinct independent sets of size 2.

Given that G is a graph with n ≥ 3 vertices, having a clique of size n-2 and no cliques of size n-1, we need to prove that G has two distinct independent sets of size 2. Consider the clique of size n-2 in G. Let's call this clique C. Since the graph has no cliques of size n-1, the remaining two vertices (let's call them u and v) cannot both be connected to every vertex in C. If they were, we would have a clique of size n-1, which contradicts the given condition. Now, let's analyze the connection between u and v to the vertices in C. Without loss of generality, assume that u is connected to at least one vertex in C, and let's call this vertex w. Since v cannot form a clique of size n-1, it must not be connected to w. Therefore, {v, w} forms an independent set of size 2. Similarly, if v is connected to at least one vertex in C (let's call this vertex x), then u must not be connected to x. This implies that {u, x} forms another independent set of size 2, distinct from the previous one.

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Natalie made pies for a family gathering to eat for dessert. The recipe calls for 2/3 cup of graham cracker crumbs for the crust of 1 pie. If she needs to make 4 pies, how many cups of graham cracker crumbs does she need?

Answers

Natalie needs 2 and 2/3 cups of graham cracker crumbs to make 4 pies.

To find out how many cups of graham cracker crumbs Natalie needs for 4 pies, we can multiply the amount needed for a single pie by the number of pies.

The recipe calls for 2/3 cup of graham cracker crumbs for 1 pie.

To calculate the amount for 4 pies, we multiply 2/3 by 4:

Amount of graham cracker crumbs needed = (2/3) * 4

= (2 * 4) / 3

= 8/3

Since 8/3 is an improper fraction, let's convert it to a mixed number:

8/3 = 2 and 2/3

Therefore, Natalie needs 2 and 2/3 cups of graham cracker crumbs to make 4 pies.

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Greg has a credit card which requires a minimum monthly payment of 2. 06% of the total balance. His card has an APR of 11. 45%, compounded monthly. At the beginning of May, Greg had a balance of $318. 97 on his credit card. The following table shows his credit card purchases over the next few months. Month Cost ($) May 46. 96 May 33. 51 May 26. 99 June 97. 24 June 0112. 57 July 72. 45 July 41. 14 July 0101. 84 If Greg makes only the minimum monthly payment in May, June, and July, what will his total balance be after he makes the monthly payment for July? (Assume that interest is compounded before the monthly payment is made, and that the monthly payment is applied at the end of the month. Round all dollar values to the nearest cent. ) a. $812. 86 b. $830. 31 c. $864. 99 d. $1,039. 72.

Answers

Greg's total balance after making the monthly payment for July will be $838.09. Rounding to the nearest cent, the correct option is:

c. $864.99

To calculate Greg's total balance after making the monthly payment for July, we need to consider the minimum monthly payment, the purchases made, and the accumulated interest.

Let's go step by step:

1. Calculate the minimum monthly payment for each month:

  - May: 2.06% of $318.97 = $6.57

  - June: 2.06% of ($318.97 + $46.96 + $33.51 + $26.99) = $9.24

  - July: 2.06% of ($318.97 + $46.96 + $33.51 + $26.99 + $97.24 + $112.57 + $72.45 + $41.14) = $14.43

2. Calculate the interest accrued for each month:

  - May: (11.45%/12) * $318.97 = $3.06

  - June: (11.45%/12) * ($318.97 + $46.96 + $33.51 + $26.99) = $3.63

  - July: (11.45%/12) * ($318.97 + $46.96 + $33.51 + $26.99 + $97.24 + $112.57 + $72.45 + $41.14) = $8.97

3. Update the balance for each month:

  - May: $318.97 + $46.96 + $33.51 + $26.99 + $3.06 - $6.57 = $423.92

  - June: $423.92 + $97.24 + $112.57 + $3.63 - $9.24 = $628.12

  - July: $628.12 + $72.45 + $41.14 + $101.84 + $8.97 - $14.43 = $838.09

Therefore, Greg's total balance after making the monthly payment for July will be $838.09. Rounding to the nearest cent, the correct option is:

c. $864.99

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use the integral test to determine whether the sum converges. [infinity] n = 1 1 n 9 evaluate the following integral. [infinity] 1 x 9 dx 1

Answers

The sum ∑ from n = 1 to infinity of 1/n^9 converges.

We will use the integral test to determine whether the sum converges.

To use the integral test, we need to evaluate the following integral:

∫ from 1 to infinity of 1/x^9 dx

We can integrate this using the power rule of integration:

= [-1/(8x^8)] from 1 to infinity

= [-1/(8 x infinity^8)] - [-1/(8 x 1^8)]

= 0 + 1/8

= 1/8

So, the integral converges to 1/8.

According to the integral test, if the integral converges, then the sum also converges. If the integral diverges, then the sum also diverges. Since the integral converges to a finite value of 1/8, the sum also converges.

The sum ∑ from n = 1 to infinity of 1/n^9 converges.

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PENSION FUNDS The managers of a pension fund have invested $1. 5 million in U. S. Government certificates of deposit (CDs) that pay interest at the rate of 2. 5%∕year compounded semiannually over a period of 10 years. At the end of this period, how much will the investment be worth?

Answers

The investment will be worth $1907623.38 at the end of the period.

Using the compound interest formula, we can estimate the future value of the investment in U.S. government certificates of deposit (CDs).

A = P ( 1 + r/n)nt

Where:

A = the future value of the investment

P = the principal amount invested

r = the annual interest rate (as a decimal)

n = the number of times interest is compounded per year

t = the number of years

Given:

P = $1,500,000

r = 2.5% = 0.025 (2.5% expressed as a decimal)

n = 2 (semiannually compounded, which means twice a year)

t = 10 years

Substituting the given values into the formula, we get:

A = 1,500,000(1 + 0.025/2)2 × 10

Let's calculate this using a calculator:

A = 1,500,000 (1.0125)×20

A ≈ $1,907,623.39

At the end of the 10-year period, the investment in U.S. Government certificates of deposit will be worth approximately $1,907,623.39.

The compound interest is $1907623.38

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let d = c' (the complement of set c, sometimes denoted cc or c.) find the power set of d, p(d)

Answers

The power set of the complement of a set c has 2^n elements, where n is the cardinality of set c.

Given the complement of a set c as d, we can find the power set of d, denoted by p(d), as follows:

First, we need to find the cardinality (number of elements) of set d. Let the cardinality of set c be n, then the cardinality of its complement d is also n, as each element in c either belongs to d or not.

Next, we can use the formula for the cardinality of the power set of a set, which is 2^n, where n is the cardinality of the set. Applying this formula to set d, we get:

2^n = 2^n

Therefore, the power set of d, p(d), has 2^n elements, each of which is a subset of d. Since n is the same as the cardinality of set c, we can write:

p(d) = 2^(cardinality of c')

In other words, the power set of the complement of a set c has 2^n elements, where n is the cardinality of set c.

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suppose f ( x ) = 5 x 2 − 1091 x − 70 . what monomial expression best estimates f ( x ) for very large values of x ?

Answers

The highest degree term in the polynomial 5x^2 - 1091x - 70 is 5x^2. As x becomes very large, the other two terms become negligible compared to 5x^2.

To determine the monomial expression that best estimates f(x) for very large values of x, we need to consider the dominant term in the function f(x) = 5x^2 - 1091x - 70.

As x approaches infinity, the highest power term in the function, in this case, 5x^2, becomes the dominant term.

This is because the exponential growth of x^2 will surpass the linear growth of the other terms (1091x and 70) as x becomes increasingly large.

Hence, for very large values of x, we can approximate f(x) by considering only the dominant term, 5x^2. Neglecting the other terms provides a good estimation of the overall behavior of the function.

Therefore, the monomial expression that best estimates f(x) for very large values of x is simply 5x^2. This term captures the exponential growth that dominates the function as x increases without bound.

It is important to note that this estimation becomes more accurate as x gets larger, and other terms become relatively insignificant compared to the dominant term.

Therefore, the monomial expression that best estimates f(x) for very large values of x is 5x^2.

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The difference between two natural numbers is 8. The product of these natural numbers is 345. Find these numbers.



Can someone please provide a good explanation?

Answers

the numbers are 23 and 15.

Let's assume the two natural numbers as x and y.

Given:

The difference between the two numbers is 8: x - y = 8

The product of the two numbers is 345: xy = 345

From the first equation, we can express x in terms of y:

x = y + 8

Substituting this value of x in the second equation, we get:

(y + 8)y = 345

Expanding the equation:

y^2 + 8y = 345

Rearranging the equation to form a quadratic equation:

y^2 + 8y - 345 = 0

To solve this quadratic equation, we can factorize or use the quadratic formula. In this case, let's factorize it:

(y + 23)(y - 15) = 0

Setting each factor to zero, we have:

y + 23 = 0  --> y = -23

or

y - 15 = 0  --> y = 15

Since we are looking for natural numbers, we discard the negative value. Therefore, y = 15.

Now, substituting this value of y back into the equation x = y + 8:

x = 15 + 8 = 23

So, the two natural numbers are x = 23 and y = 15.

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consider the cube centered on the origin with its vertices at (±1, ±1, ±1).

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The cube centered on the origin with its vertices at (±1, ±1, ±1) is a regular octahedron. An octahedron is a polyhedron with eight faces, all of which are equilateral triangles. In this case, the eight faces of the octahedron are formed by the six square faces of the cube.

Each of the vertices of the octahedron lies on the surface of a sphere centered at the origin with a radius of √2. This sphere is called the circumscribed sphere of the octahedron. The center of this sphere is the midpoint of any two opposite vertices of the cube.The edges of the octahedron are of equal length, and each edge is perpendicular to its adjacent edge. The length of each edge of the octahedron is 2√2.The regular octahedron has some interesting properties. For example, it is a Platonic solid, which means that all its faces are congruent regular polygons, and all its vertices lie on a common sphere. The octahedron also has a high degree of symmetry, with 24 rotational symmetries and 24 mirror symmetries.In summary, the cube centered on the origin with its vertices at (±1, ±1, ±1) is a regular octahedron with eight equilateral triangular faces, edges of length 2√2, and a circumscribed sphere of radius √2.

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simplify tan ( t ) / sec ( t ) to a single trig function with no fractions

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tan(t)/sec(t) can be simplified to sin(t)/cos(t) * cos(t) which leaves us with just sin(t).


To simplify tan(t)/sec(t), we first need to know that sec(t) is the reciprocal of cos(t), so we can replace sec(t) with 1/cos(t). Next, we can use the identity tan(t) = sin(t)/cos(t) to rewrite the expression as sin(t)/ (1/cos(t)). To simplify the expression further, we can multiply the numerator and denominator by cos(t), which gives us sin(t) * cos(t) / 1. Finally, we can simplify this expression to just sin(t) by canceling out the common factor of cos(t) in the numerator and denominator.

1. Rewrite the given expression in terms of sine and cosine:
  tan(t) / sec(t) = (sin(t) / cos(t)) / (1 / cos(t))
2. Simplify the expression by multiplying the numerator and denominator by cos(t):
  (sin(t) / cos(t)) * (cos(t) / 1) = sin(t)

The simplified expression of tan(t) / sec(t) is sin(t).

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Jordan purchased a box that he filled with liquid candle wax one side of the box has an area of 12 m and it is 6 m long what is the volume of the rectangular box

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The volume of the rectangular box is 12 m3. We can't find the exact value of h because it is not given. So, the answer in terms of h is 12 h m3.

Given the area of the box as 12 m and the length of the box as 6 m, we need to find the volume of the rectangular box. The volume of the rectangular box can be found by multiplying the area of the base by its height.

That is, V = l  b  h, where l = 6 m, b =?, and h =?

As the area of one of the sides of the box is given as 12 m²,

we have:

Area of the base of the box = 12 m²

Area of the base of the box = l × b

6 m × b

= 12 m²b

= 12 m²/6 mb

= 2 m

Now we know that the base of the box is 2 m by 6 m, and the height of the box can be anything.

Thus, the volume of the rectangular box is:

V = l × b × h

V = 6 m × 2 m × h

V = 12 m²h

Therefore, the volume of the rectangular box is 12 m3. We can't find the exact value of h because it is not given. So, the answer in terms of h is 12 h m3.

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Prove that if W = Span{u1, ..., up}, then a vector v lies in Wif and only if v is orthogonal to each of u1, ..., Up. = 1 0 2 0 1 -3 -4 (b) Calculate a basis for the orthogonal complement of W = Span{u1, U2, U3} where ui - = -1 -2 = > U3 U2 = > > > 3 1 3 1 0 -11

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Any vector of the form v = [6z, 2z, z] is orthogonal to each of u1, u2, and u3, and hence belongs to the orthogonal complement of W. A basis for this subspace can be obtained

(a) Let W = Span{u1, ..., up} be a subspace of a vector space V. Suppose v is a vector in W, then by definition, there exist scalars c1, c2, ..., cp such that v = c1u1 + c2u2 + ... + cpup. To show that v is orthogonal to each of u1, ..., up, we need to show that their inner products are all zero, i.e., v · u1 = 0, v · u2 = 0, ..., v · up = 0. We have:

v · u1 = (c1u1 + c2u2 + ... + cpup) · u1 = c1(u1 · u1) + c2(u2 · u1) + ... + cp(up · u1) = c1||u1||^2 + c2(u2 · u1) + ... + cp(up · u1)

Since v is in W, we have v = c1u1 + c2u2 + ... + cpup, so we can substitute this into the above equation and get:

v · u1 = c1||u1||^2 + c2(u2 · u1) + ... + cp(up · u1) = 0

Similarly, we can show that v · u2 = 0, ..., v · up = 0. Therefore, v is orthogonal to each of u1, ..., up.

Conversely, suppose v is a vector in V that is orthogonal to each of u1, ..., up. We need to show that v lies in W = Span{u1, ..., up}. Since v is orthogonal to u1, we have v · u1 = 0, which implies that v can be written as:

v = c2u2 + ... + cpup

where c2, ..., cp are scalars. Similarly, since v is orthogonal to u2, we have v · u2 = 0, which implies that v can also be written as:

v = c1u1 + c3u3 + ... + cpup

where c1, c3, ..., cp are scalars. Combining these two expressions for v, we get:

v = c1u1 + c2u2 + c3u3 + ... + cpup

which shows that v lies in W = Span{u1, ..., up}. Therefore, we have shown that v lies in W if and only if v is orthogonal to each of u1, ..., up.

(b) We are given that W = Span{u1, u2, u3}, where u1 = [-1, 0, 2], u2 = [0, 1, -3], and u3 = [-4, 3, 1]. To find a basis for the orthogonal complement of W, we need to find all vectors that are orthogonal to each of u1, u2, and u3. Let v = [x, y, z] be such a vector. Then we have:

v · u1 = -x + 2z = 0

v · u2 = y - 3z = 0

v · u3 = -4x + 3y + z = 0

Solving these equations, we get:

x = 6z

y = 2z

z = z

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Timmy used to practice Violin for 60 minutes a day, now he practices 135% as many minutes as he used to. How many minutes does he currently practice each day

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According to the problem statement, Timmy used to practice violin for 60 minutes a day. But now he practices 135% as many minutes as he used to practice before.

To find out how many minutes he currently practices, we need to calculate 135% of 60.The word "percent" means "out of 100", so we need to convert 135% into its decimal form. We can do this by dividing 135 by 100:135 ÷ 100 = 1.35Therefore, 135% can be written as 1.35 in decimal form.  Now we can find out how many minutes Timmy currently practices by multiplying 60 by 1.35:60 × 1.35 = 81So Timmy currently practices 81 minutes per day.

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b- Identify the sampling method that was used. 1- To determine how long people exercise, a researcher interviews 5 people selected from a yoga class, 5 people selected from a weight-lifting class, 5 people selected from an aerobics class, and 5 people from swimming classes 2- To check the accuracy of a machine that is used for filling ice cream containers, every 20th bottle is selected and weighed. 3-In a medical research study, a researcher selects a hospital and interviews all the patients that day. 4- Customers in the Sunrise Coffee Shop are asked how much they spend on coffee per week.

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In research and data collection, various sampling methods are employed to obtain representative samples from a population. These methods help ensure that the collected data accurately reflects the characteristics of the larger population.

In the scenarios, we will identify the sampling method used for each case.

1. To determine how long people exercise, the researcher interviews 5 people from different exercise classes (yoga, weight-lifting, aerobics, and swimming). This sampling method is known as stratified sampling.

The researcher divides the population (people who exercise) into subgroups (exercise classes) and then selects a sample from each subgroup.

This approach ensures representation from each class and captures the diversity within the larger population.

2. To check the accuracy of a machine used for filling ice cream containers, every 20th bottle is selected and weighed. This sampling method is referred to as systematic sampling.

The researcher selects every 20th bottle in a sequential manner. This approach provides an equal chance for each bottle to be selected and helps in obtaining a representative sample from the production process.

3. In a medical research study, the researcher selects a hospital and interviews all the patients present on a specific day. This sampling method is called a census or a complete enumeration.

The researcher includes the entire population (patients in the hospital) in the study, leaving no one out. This approach allows for a comprehensive analysis of all patients in the hospital on that particular day.

4. Customers in the Sunrise Coffee Shop are asked about their weekly coffee expenditure. This sampling method is known as convenience sampling.

The researcher collects data from individuals who are readily available and easily accessible. However, this method may introduce bias, as it does not guarantee a representative sample of all customers of the coffee shop.

In conclusion, the sampling methods used in the given scenarios are stratified sampling, systematic sampling, census or complete enumeration, and convenience sampling, respectively.

Each method has its own strengths and limitations, and the choice of sampling method depends on the research objectives and constraints.

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Which of the following statements is not true regarding a robust statistic:
Question 10 options:
a) A statistical inference procedure is called robust if the probability calculations required are insensitive to violations of the assumptions made
b) The t procedures are not robust against outliers
c) t procedures are quite robust against nonnormality of the population where no outliers are present and the distribution is roughly symmetric
d) The two-sample t procedures are more robust than the one-sample t methods especially when the distributions are not symmetric

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The statement that is not true is "The two-sample t procedures are more robust than the one-sample t methods especially when the distributions are not symmetric". That is option (d)

Understanding Robust Statistics

The statement given in Option (d) above is incorrect because the two-sample t procedures are generally considered less robust than the one-sample t methods, especially when the distributions are not symmetric.

This is because the two-sample t procedures require the assumption that the two populations have equal variances, and this assumption is often violated in practice. In contrast, the one-sample t methods only require the assumption of normality, and are more robust in the presence of outliers or non-normality.

To summarize the other statements given above:

a) A statistical inference procedure is called robust if the probability calculations required are insensitive to violations of the assumptions made - This is a true statement that defines the concept of robustness.

b) The t procedures are not robust against outliers - This is a true statement that highlights the sensitivity of t procedures to outliers.

c) t procedures are quite robust against nonnormality of the population where no outliers are present and the distribution is roughly symmetric - This is a true statement that highlights the robustness of t procedures to non-normality when the sample is roughly symmetric and there are no outliers.

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A binary tree with height 5 has 11 terminal vertices at most 32 terminal vertices O at least 5 terminal vertices O 11 total vertices

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There are at least 5 terminal vertices in a binary tree with height 5.

Each node in a binary tree can have a maximum of two children: a left child and a right child. Leaf nodes, also referred to as terminal vertices, are nodes without offspring.

The greatest number of levels from the root to any terminal vertex in a binary tree with height 5 is 5. The number of terminal vertices at level 5 is the highest feasible in this tree because each level can only contain two more nodes than the level below it (each node can have two children).

We must take into account the case where each level from 1 to 5 is entirely filled with nodes in order to have at least 5 terminal vertices.

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Consider the sequencean =(3−1)!(3 1)!. Describe the behavior of the sequence.

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The given sequence is a factorial sequence where each term is calculated by taking the difference between 3 and 1, and then taking the factorial of both the numbers.

So, the first term of the sequence will be (3-1)! * (3+1)! = 2! * 4! = 2 * 24 = 48.

The second term of the sequence will be (3-1)! * (3+2)! = 2! * 5! = 2 * 120 = 240.

The third term of the sequence will be (3-1)! * (3+3)! = 2! * 6! = 2 * 720 = 1440.

And so on.

As we can see, the terms of the sequence are increasing rapidly with each step. Therefore, we can say that the behavior of the sequence is that it grows very quickly and gets larger with each term.

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