This individual observed that an object painted on a revolving disc appeared to be stationary when illuminated by intense electric light. He also noticed that flying insects seemed to be fixed in mid-air by the same means. Who was it

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Answer 1

This individual observed that an object painted on a revolving disc appeared to be stationary when illuminated by intense electric light. He also noticed that flying insects seemed to be fixed in mid-air by the same means. It was William Roentgen

In 1895, a German physicist William Roentgen who discovered X-rays, noticed this phenomenon while experimenting with cathode rays and a vacuum tube. He noticed that a painted object on a spinning disc appeared stationary when illuminated by an intense electric light. He also observed that flying insects appeared to be suspended in mid-air when exposed to the same illumination.

These observations led him to discover X-rays, which he named due to their unknown nature at the time. Roentgen's discovery revolutionized the field of medicine and had a significant impact on scientific research. In 1901, he was awarded the Nobel Prize in Physics for his groundbreaking discovery. So, it was William Roentgen the  individual observed that an object painted on a revolving disc appeared to be stationary when illuminated by intense electric light.

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Related Questions

A wire loop moves at constant velocity without rotation through a constant magnetic field. The induced current in the loop will be

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A constant velocity motion of a wire loop through a constant magnetic field does not induce any current.

According to Faraday's law of electromagnetic induction, a changing magnetic field induces an electric field, which in turn can cause a current to flow in a closed loop of wire. However, when a wire loop moves at a constant velocity without rotation through a constant magnetic field, there is no change in the magnetic field with respect to the loop, and therefore no induced electric field or current. This is because the magnetic field is uniform and does not vary in time, so there is no change to induce a current.

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A conducting metal banana-shaped object is placed in an external, non-uniform electric field. What can you say about the geometry of the resulting electric field lines just outside the outer surface of the conducting object

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The electric field lines just outside the outer surface of the conducting banana-shaped object will be perpendicular to the surface at every point.

When a conducting object, like the banana-shaped one, is placed in a non-uniform electric field, charges on its surface redistribute themselves until they reach electrostatic equilibrium. In this state, the electric field inside the conductor is zero, and the electric field lines just outside the conductor's surface must be perpendicular to the surface. This is because any tangential component of the electric field on the conductor's surface would cause charges to move, violating electrostatic equilibrium. Thus, the geometry of the resulting electric field lines just outside the outer surface of the conducting object will be perpendicular to the surface at every point.

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In 0.450 s, a 11.9-kg block is pulled through a distance of 4.33 m on a frictionless horizontal surface, starting from rest. The block has a constant acceleration and is pulled by means of a horizontal spring that is attached to the block. The spring constant of the spring is 407 N/m. By how much does the spring stretch

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In 0.450 s, a 11.9-kg block is pulled through a distance of 4.33 m on a frictionless horizontal surface, starting from rest. The block has a constant acceleration and is pulled by a horizontal spring. Then, the spring stretches by 0.479 m.

We can use the work-energy principle to solve this problem. The work done by the spring force is equal to the change in the kinetic energy of the block;

W = ΔK

where W is work done by the spring force, and ΔK is change in kinetic energy.

The work done by the spring force can be calculated as the integral of the spring force over the distance the block moves;

W = ∫ F dx

where F is the spring force and x is the distance the block moves.

The spring force is given by Hooke's law;

F = -kx

where k is the spring constant and x is the displacement of the spring from its equilibrium position.

Substituting the expression for the spring force into the expression for the work done by the spring force, we get;

W = -∫ kx dx

W = - (1/2) kx²

where we have used the fact that the displacement x is equal to the distance the block moves.

Substituting the values given in the problem, we get;

W = (1/2) m[[tex]V_{f}[/tex]² - (1/2) m[tex]V_{i}[/tex]²

where [[tex]V_{f}[/tex] is final velocity of the block, and [tex]V_{i}[/tex] is its initial velocity (zero).

Solving for x, we get;

x = √[[tex]V_{f}[/tex]² - [tex]V_{i}[/tex]²)/(2k)]

where k is the spring constant.

Substituting the given values, we get;

x = √[(2 × 11.9 kg × 4.33 m) / (2 × 407 N/m)]

= 0.479 m

Therefore, the spring stretches by 0.479 m.

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An 80 kg man jumps onto a stationary 3 kg skateboard with frictionless wheels with a horizontal velocity of 7 m/s. What is his velocity as the skateboard starts moving

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The velocity of the man and the skateboard after the jump is  6.92 m/s

When the 80 kg man jumps onto the stationary 3 kg skateboard with frictionless wheels, the two objects will form a system. According to the Law of Conservation of Momentum, the total momentum of the system will remain constant as long as no external forces are acting on it.

Initially, the total momentum of the system is given by:

P1 = (80 kg)(7 m/s) + (3 kg)(0 m/s) = 560 kg m/s

Here, the man has a horizontal velocity of 7 m/s, while the skateboard is stationary.

As the man jumps onto the skateboard, the momentum of the system is conserved, and the skateboard and the man move together. Assuming that there is no external force acting on the system, the total momentum of the system remains constant.

The final momentum of the system, P2, is given by:

P2 = (80 kg + 3 kg) v

Here, v is the velocity of the man and the skateboard after the jump.

According to the Law of Conservation of Momentum, P1 = P2. Therefore:

560 kg m/s = (80 kg + 3 kg) v

Solving for v, we get:

v = 6.92 m/s

This means that the man and the skateboard move together with a velocity of 6.92 m/s after the jump.

In conclusion, when the 80 kg man jumps onto the stationary 3 kg skateboard with frictionless wheels, the two objects form a system. The momentum of the system is conserved, and the man and the skateboard move together with a velocity of 6.92 m/s after the jump.

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the current in a stream is 3 km/h. A boat travels 18 km upstream and 18 km downstream in a total time of 8 hours. What is the boat's speed in still water.

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The boat can travel at a speed of 4.5 km/h in still water.

To solve this problem, we need to use the formula:
distance = speed x time

Let's let the boat's speed in still water be represented by "x". We can also use the given current speed of 3 km/h to help us calculate the boat's speed when traveling upstream and downstream.

When traveling upstream (against the current), the boat's effective speed is reduced by the current speed, so the boat's speed is:
x - 3 km/h

When traveling downstream (with the current), the boat's effective speed is increased by the current speed, so the boat's speed is:
x + 3 km/h

Now, we can set up the equation using the formula:
18 / (x - 3) + 18 / (x + 3) = 8

This equation represents the total time it takes for the boat to travel 18 km upstream and 18 km downstream. We can simplify it by finding a common denominator and then combining like terms:

18(x + 3) + 18(x - 3) = 8(x² - 9)
36x = 8x² - 216
8x² - 36x - 216 = 0

We can solve for "x" using the quadratic formula:
x = (-b ± sqrt(b² - 4ac)) / 2a

Where a = 8, b = -36, and c = -216. Plugging these values in, we get:

x = (36 ± sqrt(36² - 4(8)(-216))) / 16
x = (36 ± 60) / 16
x = 4.5 or x = -3

Since the boat's speed cannot be negative, we can disregard the negative solution. Therefore, the boat's speed in still water is:
x = 4.5 km/h

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Estimate the radiation pressure due to a bulb that emits 25 W of EM radiation at a distance of 4.0 cm from the center of the bulb. Assume that light is completely absorbed.

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The estimated radiation pressure due to a bulb that emits 25 W of EM radiation at a distance of 4.0 cm from the center of the bulb is approximately 1.68 × [tex]10^-8[/tex]N.

The radiation pressure is given by the formula:

P = (2I/c)A

where P is the radiation pressure, I is the intensity of the radiation, c is the speed of light, and A is the area over which the radiation is incident.

First, we need to calculate the intensity of the radiation emitted by the bulb. We know that the bulb emits 25 W of EM radiation, so the power per unit area (the intensity) is:

I = P/A = 25 W / (4π(0.04 m)²) = 49.9 W/m²

Next, we need to calculate the area over which the radiation is incident. Assuming the bulb emits radiation uniformly in all directions, the area is the surface area of a sphere with a radius of 4.0 cm:

A = 4π(0.04 m)² = 0.0201 m²

Now we can plug in these values into the formula for radiation pressure:

P = (2I/c)A = (2 × 49.9 W/m² / 299792458 m/s) × 0.0201 m² ≈ 1.68 × [tex]10^-8[/tex]N

Therefore, the estimated radiation pressure due to a bulb that emits 25 W of EM radiation at a distance of 4.0 cm from the center of the bulb is approximately 1.68 × [tex]10^-8[/tex]N.

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if you expend a 10 j of work to push a 1-C charge against an electric field what is its change in velocity

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The charge could have a final velocity of either 4.47 m/s or -4.47 m/s, depending on the direction of the electric field and the direction of the force exerted on the charge.

ΔK = (1/2)mv²f - (1/2)mv²i

Substituting these values into the equation, we get:

(1/2)mv²f - (1/2)mv²i = W

(1/2)(1 kg)(v²f - 0) = 10 J

Simplifying the equation, we get:

v²f = 20 m²/s²

Taking the square root of both sides, we get:

vf = ±4.47 m/s

Velocity is a vector quantity that describes the rate at which an object changes its position in a particular direction. It is defined as the rate of change of displacement with respect to time. Velocity is expressed in units of meters per second (m/s) or any other unit of distance divided by time. The direction of the velocity vector is the same as the direction of motion of the object.

The difference between velocity and speed is that velocity takes into account the direction of motion, whereas speed only refers to the magnitude of the motion. An object can have different velocities at different times. If the velocity of an object changes, then it is said to be accelerating. The acceleration of an object is the rate of change of velocity with respect to time.

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Suppose that the speedometer of a truck is set to read the linear speed of the truck, but uses a device that actually measures the angular speed of the tires. If larger diameter tires are mounted on the truck, how will that affect the speedometer reading as compared to the true linear speed of the truck

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When larger diameter tires are mounted on the truck, the speedometer reading will be lower than the true linear speed of the truck.



When a truck has larger diameter tires, the relationship between the angular speed (measured by the device) and the linear speed (read by the speedometer) will be affected.

Here's a step-by-step explanation of the process:

1. The device measures the angular speed of the tires (how fast the tires are rotating).
2. The speedometer converts this angular speed into a linear speed, which is the actual speed of the truck on the road.
3. When larger diameter tires are mounted on the truck, the distance covered in one complete rotation of the tire increases because the circumference of the tire is larger.
4. With larger tires, the same angular speed will result in a higher linear speed because the truck is covering more distance per rotation.
5. However, the speedometer is still calibrated for the original, smaller tires and will not account for the increased distance covered by the larger tires.

In conclusion, when larger diameter tires are mounted on the truck, the speedometer reading will be lower than the true linear speed of the truck. This is because the speedometer is still calibrated for the smaller tires and does not take into account the increased distance covered by the larger tires at the same angular speed.

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when a conductor cuts magnetic lines of force a voltage is induced into the conductor this principle is called

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when a conductor cuts magnetic lines of force a voltage is induced into the conductor this principle is called Faraday's law of electromagnetic induction.

Faraday's law, named after the British physicist Michael Faraday, describes the relationship between a changing magnetic field and an induced electromotive force (EMF) in a conductor. According to the law, when a conductor is placed in a varying magnetic field, a voltage is induced across the ends of the conductor, creating an electric current.

Faraday's law is a fundamental principle of electromagnetism and is used to explain a wide range of phenomena, including the operation of electric generators, transformers, and motors. It also plays a crucial role in the understanding of electromagnetic induction, which is the process by which a changing magnetic field can create an electric field, and vice versa.

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An electric field of 1.22 kV/m and a magnetic field of 0.497 T act on a moving electron to produce no net force. If the fields are perpendicular to each other, what is the electron's speed

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The electron's speed is 2450 m/s.

The force on an electron in an electric field E and a magnetic field B is given by the Lorentz force:

F = q(E + v x B)

where q is the charge of the electron, v is its velocity, and x denotes the vector cross product.

Since the electron experiences no net force, we have F = 0. This implies that

v x B = -E

Taking the magnitude of both sides and using the fact that the cross product of two vectors is perpendicular to both, we get

|v| |B| = |E|

Solving for |v|, we find

|v| = |E|/|B| = (1.22 kV/m)/(0.497 T) = 2450 m/s

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The frequency of a particular electromagnetic wave is 5.00 x 1014 Hz. What is the energy of an individual photon in that wave

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The energy of an individual photon in the given electromagnetic wave is approximately 3.31 x 10⁻¹⁹ joules (J).

The energy of a photon can be calculated using the formula:

E = hf

where E is the energy of the photon, h is Planck's constant, and f is the frequency of the electromagnetic wave.

Plugging in the given values, we get:

E = (6.626 x 10⁻³⁴ J s) x (5.00 x 10¹⁴ Hz)

= 3.31 x 10⁻¹⁹ J

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A baseball of mass 146 g is thrown with a velocity of < 23, 23, -14 > m/s. What is the kinetic energy of the baseball

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The kinetic energy of the baseball is approximately 162.18 J (joules).

To calculate the kinetic energy of the baseball, we use the formula:

Kinetic Energy (KE) = 0.5 * mass * velocity²

First, we need to convert the mass of the baseball from grams to kilograms:

146 g = 0.146 kg

Next, we need to calculate the magnitude of the velocity vector:

|velocity| = √(23² + 23² + (-14)²) = √(529 + 529 + 196) = √1254 ≈ 35.41 m/s

Now, we can calculate the kinetic energy:

KE = 0.5 * 0.146 kg * (35.41 m/s)² ≈ 162.18 J

The kinetic energy of an object is the energy it possesses due to its motion. It depends on both the mass and the velocity of the object. In this case, we have a baseball with a mass of 146 g and a given velocity vector. To find the kinetic energy, we first converted the mass to kilograms, then calculated the magnitude of the velocity vector, and finally used the kinetic energy formula to find the answer. The kinetic energy of the baseball is approximately 162.18 J.

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A car traveling along the highway brakes to a stop over a certain distance. More braking force is required if the car has more momentum. less stopping distance. more mass. all of the above none of the above

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The correct answer is A. more momentum. This is because momentum is the product of an object's mass and velocity, and a car with more momentum will require more force to slow down or stop.

While a shorter stopping distance (option B) would require more force, it is not the determining factor in this scenario. Similarly, a car with more mass (option C) will have more momentum and require more force to stop. Therefore, option D, all of the above, is not correct.

The propensity of a body to continue its inertial motion is known as momentum. It is the vector sum of the products of its masses and velocities, or the product of its mass and velocity.

Momentum has both a magnitude and a direction because it is a vector quantity.

The SI unit for momentum is kgm/s or N/s since it is the result of mass and velocity.

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The Earth rotates on its axis once every 24 hours. Due to this motion, roughly how many full hours would you expect to pass between two subsequent high tides at any given location on the Earth

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The rotation of the Earth on its axis causes a periodic change in the position of the Moon and the Sun relative to any given location on the Earth's surface.

Earth is typically viewed as a massive, rotating, and gravitationally-bound celestial body that orbits around the sun. It has a radius of approximately 6,371 kilometers and a mass of approximately 5.97 x 10^24 kilograms. Earth's rotation on its axis produces day and night cycles, and its orbital motion around the sun produces the yearly cycle of seasons.

Earth's gravity plays a crucial role in many physical phenomena, such as tides, atmospheric pressure, and the motion of objects on its surface. Additionally, Earth's magnetic field helps to protect the planet from the charged particles of the solar wind. In terms of energy, Earth receives radiation from the sun and emits radiation in the form of heat.

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On a planet, an astronaut determines the acceleration of gravity by means of a pendulum. She observes that the 1-m-long pendulum has a period of 1.5 s. The acceleration of gravity, in meters per second squared, on the planet is

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On a planet, an astronaut determines the acceleration of gravity using a 1-meter long pendulum with a period of 1.5 seconds: the acceleration of gravity on the planet is approximately 17.56 meters per second squared.

To find the acceleration of gravity in meters per second squared, we can use the formula for the period of a simple pendulum:

T = 2π√(L/g),

where T is the period, L is the length of the pendulum, and g is the acceleration of gravity. Given the period T=1.5 seconds and the length L=1 meter, we can rearrange the formula to solve for g:

g = (4π²L)/T².

Substituting the given values:

g = (4π²(1))/(1.5²)


g ≈ 17.56 meters per second squared.

Therefore, the acceleration of gravity on the planet is approximately 17.56 meters per second squared.

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Find the acceleration of a hamster when it increases its velocity from rest to 5.0 m/s in 1.6 s . Express your answer to two significant figures and include the appropriate units. a

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The acceleration of the hamster can be found using the equation:
a = (vf - vi)/t
where vf is the final velocity (5.0 m/s), vi is the initial velocity (0 m/s since the hamster starts from rest), and t is the time taken to reach the final velocity (1.6 s).a = (5.0 m/s - 0 m/s)/1.6 s
a = 3.13 m/s^2
Therefore, the acceleration of the hamster when it increases its velocity from rest to 5.0 m/s in 1.6 s is 3.13 m/s^2 (to two significant figures).


To find the acceleration of the hamster, we can use the formula:
a = (v_f - v_i) / t
where a is the acceleration, v_f is the final velocity (5.0 m/s), v_i is the initial velocity (0 m/s, as the hamster starts from rest), and t is the time (1.6 s). Plugging in the values, we get:
a = (5.0 m/s - 0 m/s) / 1.6 s
a = 5.0 m/s / 1.6 s
a ≈ 3.1 m/s²

So, the acceleration of the hamster is approximately 3.1 m/s² (to two significant figures), with the appropriate unit being meters per second squared.

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If a typical house requires 400 W of electric power on average, how much deuterium fuel would have to be used in a year to supply these electrical needs

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the typical house requires 400 W of electric power on average, this means that it consumes 400 watt-hours (Wh) of energy Therefore, approximately 42.048 kg of deuterium fuel.

In most cases, electricity for household use is generated by power plants that use a variety of fuels, including coal, natural gas, nuclear fuel, and renewable sources such as wind and solar. The amount of fuel needed to generate a given amount of electricity depends on the efficiency of the power plant and the type of fuel used.

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The equivalent resistance of resistors combined in parallel is the _____ of the individual resistances.

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The equivalent resistance of resistors combined in parallel is the inverse of the sum of the reciprocals of the individual resistances.

This means that as the number of resistors in parallel increases, the equivalent resistance decreases. In parallel, each resistor has the same voltage across it, but the current is divided among the resistors based on their individual values.

Resistors are electronic components that are used to control the flow of electric current in a circuit. They come in different values and are used to limit or adjust the flow of current. By using resistors, we can protect components in a circuit from excessive current or voltage, and also adjust the output of a circuit to our desired value.
 The equivalent resistance of resistors combined in parallel is the reciprocal of the sum of the reciprocals of the individual resistances. To calculate this, you can follow these steps:

1. Find the reciprocal of each individual resistance (1/resistance).
2. Add the reciprocals obtained in step 1.
3. Take the reciprocal of the sum obtained in step 2.

This will give you the equivalent resistance of the resistors combined in parallel. Remember that combining resistors in parallel usually results in a lower overall resistance compared to the individual resistances.

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The flutes on a twist drill serve which one of the following functions: (a) adds rigidity to the drill, (b) improves hole size accuracy, (c) lubricates the cutting edges, (d) provides passageways for extraction of chips, or (e) strengthens the drill

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The flutes on a twist drill serve multiple functions, including (b) improving hole size accuracy by helping to maintain a consistent diameter throughout the drilling process, (d) providing passageways for extraction of chips to prevent clogging and overheating, and (c) to some extent, lubricating the cutting edges to reduce friction and heat buildup.

However, they do not add rigidity or strengthen the drill.


The flutes on a twist drill serve the function of (d) providing passageways for extraction of chips. This improves the drilling process by efficiently removing debris and allowing for smooth drilling operation.

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The resistivity of pure copper is 17 nano-Ohm-meters. How much more resistive than copper is the wire used in this experiment (1.126*10^-6 Ohm-meters)

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The wire used in the experiment is approximately 15000 times more resistive than pure copper.

Resistivity is a measure of how much a material opposes the flow of electrical current. The lower the resistivity, the better the material is at conducting electricity. Pure copper has a very low resistivity of 17 nano-Ohm-meters, which is why it is commonly used in electrical wiring.

In comparison, the wire used in the experiment has a resistivity of 1.126*10^-6 Ohm-meters, which is significantly higher than pure copper. To calculate how much more resistive the wire is than copper, we can divide the resistivity of the wire by the resistivity of copper:

(1.126*10^-6 Ohm-meters) / (17 nano-Ohm-meters) = 66,235

This means that the wire used in the experiment is approximately 66,235 times more resistive than pure copper.

Thus, the wire used in the experiment is significantly more resistive than pure copper, with a resistivity that is approximately 15000 times higher. This could impact the performance and efficiency of any electrical devices that use this wire.

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Question 1 of 10
Which of the following describes a command economy?
A. Individuals own businesses, and they compete with one another
for profits.
B. The government and the people own everything together.
C. Individuals own some businesses, and the government also owns
some businesses.
D. The government owns and runs all the businesses.

Answers

A command economy is one in which the government owns and runs all the businesses. Option D.

What is a command economy?

In a command economy, the government makes all the economic decisions, such as what goods to produce, how much to produce, and at what prices.

The government also owns and controls all the resources and means of production, including factories, land, and natural resources.

This is in contrast to a market economy, where individuals and businesses own and operate the means of production and make economic decisions based on market forces and supply and demand.

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PLFA circuit conductors shall be separated by at least _____ inches from conductors of any electric light, power, Class 1, non-power-limited fire alarm, or medium-power-network-powered broadband communications circuits.

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PLFA circuit conductors shall be separated by at least 2 inches from conductors of any electric light, power, Class 1, non-power-limited fire alarm, or medium-power-network-powered broadband communications circuits.

This requirement is part of the National Electric Code (NEC), which specifies minimum standards for electrical wiring and equipment. The purpose of this separation is to prevent interference between different types of circuits, which can cause malfunctions or safety hazards. The 2-inch separation is intended to provide enough distance to prevent arcing or other electrical discharge between conductors. Other NEC requirements may also apply, depending on the specific installation and local building codes. Compliance with these standards is important for ensuring safe and reliable electrical systems.

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An object starting from rest moves on a circular path with a radius 40 cm and a constant tangential acceleration of 10 cm/s2. How much time is needed after the motion begins for the centripetal acceleration of the object to be equal to the tangential acceleration

Answers

It takes 2 seconds for the centripetal acceleration of the object to be equal to the tangential acceleration.

We know that the tangential acceleration (a_t) of an object moving in a circular path is given by:

a_t = r α

where r is the radius of the circular path and α is the angular acceleration.

The centripetal acceleration (a_c) of the object is given by:

a_c = rω²

where ω is the angular velocity of the object.

At the instant when the centripetal acceleration becomes equal to the tangential acceleration, we have:

a_c = a_t

rω² = r α

ω² = α

ω = sqrt(α)

We can use this relationship to find the time (t) required for the centripetal acceleration to become equal to the tangential acceleration. We can start by finding the angular acceleration:

α = a_t / r = 10 cm/s² / 40 cm = 0.25 rad/s²

Then, we can find the angular velocity at the instant when the centripetal acceleration becomes equal to the tangential acceleration:

ω = sqrt(α) = sqrt(0.25 rad/s²) = 0.5 rad/s

Finally, we can find the time required for the centripetal acceleration to become equal to the tangential acceleration:

t = ω / α = (0.5 rad/s) / (0.25 rad/s²) = 2 s

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The resistance of a very fine aluminum wire with a 19 μm × 19 μm square cross section is 1200 Ω . A 1200 Ω resistor is made by wrapping this wire in a spiral around a 2.3-mm-diameter glass core.

How many turns of wire are needed?

Answers

The first step to solving this problem is to find the length of the wire needed to make a 1200 Ω resistor. We can use the formula for the resistance of a wire, which is:

R = ρ * L / A

where R is the resistance, ρ is the resistivity of the material (which is 2.65 × 10^-8 Ω*m for aluminum), L is the length of the wire, and A is the cross-sectional area of the wire.

We know the resistance (1200 Ω) and the cross-sectional area (19 μm x 19 μm = 361 μm^2 = 3.61 × 10^-10 m^2), so we can rearrange the formula to solve for the length of the wire:

L = R * A / ρ

L = 1200 Ω * 3.61 × 10^-10 m^2 / (2.65 × 10^-8 Ω*m)

L = 1.63 m

Now we need to find the number of turns of wire needed to wrap around the 2.3-mm-diameter glass core. We can use the formula for the length of a wire wrapped in a spiral:

Lspiral = π * (d + D) * n / 2

where Lspiral is the length of the wire in the spiral, d is the diameter of the wire, D is the diameter of the core, and n is the number of turns.

We know the length of the wire (1.63 m), the diameter of the core (2.3 mm = 0.0023 m), and the diameter of the wire (19 μm = 0.000019 m), so we can rearrange the formula to solve for the number of turns:

n = 2 * Lspiral / π * (d + D)

n = 2 * 1.63 m / π * (0.000019 m + 0.0023 m)

n = 3034 turns

Therefore, we need 3034 turns of the fine aluminum wire to make a 1200 Ω resistor by wrapping the wire in a spiral around a 2.3-mm-diameter glass core.

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If two stars have the exact same spectral class then they must ______. If a newly discovered stellar object is cooler than an M star, then it is probably _____.

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If two stars have the exact same spectral class, then they must have similar temperatures, masses, and sizes. The spectral class of a star is determined by its surface temperature, which affects the colors and intensities of the electromagnetic radiation emitted by the star. This information is typically used to classify stars into seven different spectral types: O, B, A, F, G, K, and M, with O being the hottest and M being the coolest.

If a newly discovered stellar object is cooler than an M star, then it is probably a brown dwarf, a type of sub-stellar object that is too small to sustain nuclear fusion in its core. Brown dwarfs are often referred to as "failed stars" since they are too small to become full-fledged stars but too large to be classified as planets. Brown dwarfs emit very little visible light and instead radiate in the infrared part of the spectrum. They can be difficult to detect due to their low luminosity and can be identified using specialized instruments that are sensitive to infrared radiation.

In summary, the spectral class of a star provides information about its temperature, size, and mass, and stars with the same spectral class will have similar properties. A newly discovered stellar object that is cooler than an M star is likely a brown dwarf, a sub-stellar object that emits primarily in the infrared part of the spectrum.

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The index of refraction of a type of glass is 1.50, and the index of refraction of water is 1.33. If light enters water from this glass, the angle of refraction (transmission) will be Group of answer choices greater than the angle of incidence. equal to the angle of incidence. less than the angle of incidence.

Answers

The angle of refraction is less than the angle of incidence.

When light travels from one medium to another, it changes its direction of propagation. This phenomenon is called refraction, and the angle of refraction is determined by the indices of refraction of the two media and the angle of incidence. The law of refraction states that the ratio of the sine of the angle of incidence to the sine of the angle of refraction is equal to the ratio of the indices of refraction of the two media.

In this case, the index of refraction of glass is greater than the index of refraction of water, which means that light will bend away from the normal as it enters the water from the glass. This implies that the angle of refraction will be less than the angle of incidence.

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A car has two horns, one emitting a frequency of 200 Hz. if the observed beat frequency is 6 Hz, what are the possible frequencies for the second horn

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The possible frequencies for the second horn are 206 Hz and 194 Hz.

To determine the possible frequencies for the second horn, we can use the concept of beat frequency.

The beat frequency is the difference between the frequencies of two sound waves. In this case, the observed beat frequency is 6 Hz.

Let's assume the frequency of the second horn is f2. The beat frequency is given by:

Beat frequency = |f1 - f2|

where f1 is the frequency of the first horn.

Given that the frequency of the first horn (f1) is 200 Hz and the observed beat frequency is 6 Hz, we can rearrange the equation to find the possible frequencies for the second horn (f2):

f2 = f1 ± beat frequency

Substituting the given values:

f2 = 200 Hz ± 6 Hz

Thus, the possible frequencies for the second horn are:

f2 = 200 Hz + 6 Hz = 206 Hz

f2 = 200 Hz - 6 Hz = 194 Hz

Therefore, the possible frequencies for the second horn are 206 Hz and 194 Hz.

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3. If you double the pressure on the surface of a can of water, the buoyant force on a stone placed in that water will (0.5p) A) increase, but not double. B) double. C) decrease, but not by one-half. D) not change.

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The correct answer is D) not change if you double pressure on surface of can on water where buoyant force will be applied.

The buoyant force on a stone submerged in water depends on the volume of the displaced water and the density of the water, according to Archimedes' principle. The equation for buoyant force (F_b) is:

[tex]F_b = ρ * V * g[/tex]
where ρ is the density of the fluid, V is the volume of the displaced fluid, and g is the acceleration due to gravity.

Doubling the pressure on the surface of the can of water does not change the volume of water displaced by the stone or the density of the water. Therefore, the buoyant force on the stone remains the same, even if the pressure on the surface of the water is doubled.

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A hypothetical heat pump, working in a Carnot heat pump cycle, provides heat to a house at a rate of 14 kW, to maintain its temperature constant at 25 oC, while the outdoor temperature is 7 oC. Find the power required to operate this heat pump and the amount of heat taken from the outdoors.

Answers

To find the power required to operate the hypothetical heat pump, we can use the equation:
Power = Qh / efficiency
Where Qh is the heat provided to the house and efficiency is the Carnot efficiency, which is given by:
efficiency = 1 - (Tc / Th)
Where Tc is the temperature of the cold reservoir (in this case, the outdoors) and Th is the temperature of the hot reservoir (in this case, the house).

We know that Qh = 14 kW and Th = 25 oC, which is 298 K. To find Tc, we can use the fact that the heat pump is maintaining the house temperature constant at 25 oC. This means that the heat taken from the outdoors must be equal to the heat provided to the house, so:
Qc = Qh = 14 kW
Now we can use the equation for efficiency:
efficiency = 1 - (Tc / Th)
Solving for Tc, we get:
Tc = Th - (Th x efficiency)
Tc = 298 K - (298 K x (1 - Qc / Qh))
Tc = 298 K - (298 K x (1 - 1))
Tc = 7 oC

So the temperature of the outdoors is 7 oC, which is the same as the given temperature. Now we can calculate the efficiency:
efficiency = 1 - (Tc / Th)
efficiency = 1 - (280 K / 298 K)
efficiency = 0.0597
Finally, we can calculate the power required to operate the heat pump:
Power = Qh / efficiency
Power = 14 kW / 0.0597
Power = 235 kW
Therefore, the power required to operate the heat pump is 235 kW, and the amount of heat taken from the outdoors is also 14 kW, since this is the heat provided to the house.

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A 1 kg ball is pushed against a spring until the spring compresses by 1 cm. Then the ball is released and is launched with an initial speed of 10 m/s. What is the spring constant

Answers

The spring constant is 500 N/m.

To find the spring constant, we can use the equation for elastic potential energy, which is:
E = (1/2)kx²

where E is the elastic potential energy, k is the spring constant, and x is the displacement (compression) of the spring. We can also use the equation for kinetic energy, which is:
K = (1/2)mv²

where K is the kinetic energy, m is the mass, and v is the initial velocity. When the ball is released, the elastic potential energy is converted into kinetic energy, so we can equate these two expressions:
(1/2)kx² = (1/2)mv²

Now, we can plug in the given values: m = 1 kg, x = 0.01 m (1 cm converted to meters), and v = 10 m/s:
(1/2)k(0.01)² = (1/2)(1)(10)²

Solve for k:
k(0.0001) = 50
k = 500 N/m

So, the spring constant is 500 N/m.

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