Given the following data:
Charge of B₁ = +17 µC to C = 17 × 10⁻⁶ C.Charge of B₂ = -5 µC to C = -5 × 10⁻⁶ C.Charge of B₃ = +26 µC to C = 26 × 10⁻⁶ C.Radius of B₁ to B₂ = 5 cm to m = 0.05 meter.Radius of B₂ to B₃ = 10 cm to m = 0.1 meter.How to determine the x and y components of the electric field?First of all, we would calculate the electric field due to B₁ to B₃ and the electric field due to B₂ to B₃ respectively.
The electric field due to B₁ to B₃ is given by:
E₁ = kq₁/r₁²
E₁ = (9 × 10⁹ × 17 × 10⁻⁶)/(0.05² + 0.1²)
E₁ = 153 × 10³/0.0125
Electric field, E₁ = 12.24 × 10⁶ N/C.
The electric field due to B₂ to B₃ is given by:
E₂ = kq₂/r₂²
E₂ = (9 × 10⁹ × 5 × 10⁻⁶)/(0.1²)
E₂ = 45 × 10³/0.01
Electric field, E₂ = 4.5 × 10⁶ N/C.
Also, the magnitude of the angle formed is given by tan trigonometry:
Tanθ = 5/10
Tanθ = 0.5
θ = tan⁻¹(0.5)
θ = 26.56°.
Next, we would calculate the x-component of the electric field at the observation location (Bee number 3) due to B₁:
E₁x = E₁cosθ - E₂
E₁x = 12.24 × 10⁶ × cos(26.56) - 4.5 × 10⁶
E₁x = 10.95 × 10⁶ - 4.5 × 10⁶
E₁x = 6.5 × 10⁶ N/C.
Similarly, we would calculate the y-component of the electric field at the observation location (Bee number 3) due to B₁:
E₁y = -E₁sinθ
E₁y = -12.24 × 10⁶ × sin(26.56)
E₁y = -12.24 × 10⁶ × 0.4471
E₁y = -5.5 × 10⁶ N/C.
Also, the magnitude of the electric field is given by:
Exy = √(E₁x² + E₁y²)
Exy = √(6.5 × 10⁶)² + (-5.5 × 10⁶)²)
Exy = √4.225 × 10¹³ + 3.025 × 10¹³)
Exy = √(7.25 × 10¹³)
Exy = 8.5 × 10⁶ N/C.
Part B.We would calculate the x-component of the electric field at the observation location (Bee number 3) due to B₂:
E₂x = -E₂sinθ
E₂x = -4.5 × 10⁶ × sin(90)
E₂x = -4.5 × 10⁶ N/C.
Similarly, we would calculate the y-component of the electric field at the observation location (Bee number 3) due to B₁:
E₂y = E₂cosθ
E₂y = -4.5 × 10⁶ × cos(90)
E₂y = 0 N/C.
How to calculate the net electric field at the observation location?The magnitude of the net electric field at B₃ is given by:
Eₙ = √(E₁x + E₂x)² + E₁y²)
Eₙ = √(6.5 × 10⁶ + (-4.5 × 10⁶))² + (-5.5 × 10⁶)²)
Eₙ = √(2.5 × 10⁶)² + (3.025 × 10¹³)
Eₙ = √(6.25 × 10¹²) + (3.025 × 10¹³)
Eₙ = √(3.65 × 10¹³)
Eₙ = 6.04 × 10⁶ N/C.
For the direction, we have:
Tanθ = x/y
Tanθ = 6.5/-5.5
Tanθ = -1.1818
θ = tan⁻¹(-1.1818)
θ = 49.76°.
Part C.The magnitude of the force on B₃ due to this net electric field is given by:
F = B₃ × Eₙ
F = 26 × 10⁻⁶ × 6.04 × 10⁶
F = 157.04 Newton.
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A worker uses a pulley system to raise a 225
N carton 16.5 m. A force of 129 N is exerted
and the rope is pulled 33.0 m. What is the IMA
of the system?
Answer:
1.74
Explanation:
"How do you calculate the mechanical advantage of a block and tackle pulley?
To calculate the mechanical advantage, we can either divide the weight of the object being lifted by the force required to lift it or we can divide the amount of rope we have to pull by the distance the object moves."
If we use the rope method the mech advantage is 33.0/16.5 = 2
now if we use the forces MA = 225/129 =1.74 <==== this is not equal to '2' as we first found due to energy being lost to friction/deformation of rope etc. SO I would say the true mechanical advantage = 1.74
Efficiency = 1.74/2 = 87%
At the top of a hill a roller coaster has gravitational potential energy due to its position. What happend to this potential energy as the roller coaster speeds up on the way down the hill?
As the roller coaster speeds up on the way down the hill, the potential energy of roller coaster will be converted to kinetic energy.
What is Conservation of Energy ?Conservation of energy state that energy is neither created nor destroy, they can only be transformed from one form to another. Energy of and object can transform from Potential energy to kinetic energy and vice versa
Given that at the top of a hill a roller coaster has gravitational potential energy due to its position. What will happen to this potential energy as the roller coaster speeds up on the way down the hill is that the potential energy to the roller coaster will start decreasing while the kinetic energy will start to increase.
The total energy of the roller coaster will be constant because of conservation of energy. As the roller coaster speeds up on the way down the hill, the potential energy will eventually reduce to zero where the total energy of the as the roller coaster will be equal to maximum kinetic energy.
Therefore, as the roller coaster speeds up on the way down the hill, the potential energy of roller coaster will be converted to kinetic energy.
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A child in a boat throws a 5.90-kg package out horizontally with a speed of 10.0 m/s. The mass of the child is 25.0 kg and the mass of the boat is 38.4 kg. (Figure 1)
Calculate the velocity of the boat immediately after, assuming it was initially at rest.
Express your answer to three significant figures and include the appropriate units. Enter positive value if the direction of the velocity is in the direction of the velocity of the box and negative value if the direction of the velocity is in the direction opposite to the velocity of the box.
-0.930 m/s is the velocity of the boat.
Given:Mass of child and boat , [tex]m_1[/tex] = (25.0 + 38.4 )kg
= 63.4 kg
Mass of the package, [tex]m_2[/tex] = 5.90 kg
Velocity of package thrown from boat , [tex]v_2[/tex] = 10.0m/s
[tex]v_1 =?[/tex]
Initial velocity v = 0 m/s
As the boat is at rest, [tex](m_1 + m_2) v=0[/tex]
According, to the law of conversation of momentum;
∴ Momentum before = Momentum after
[tex]( m_1 + m_2 ) v = m_1v_1 + m_2v_2\\0 = m_1v_1 + m_2v_2\\0 = 63.4 v_1 + 5.90*10.0\\63.4 v_1 = - 5.9\\v_1 = - 0.930 m/s[/tex]
Negative direction shows the velocity in the direction opposite to the motion of the package.
Therefore, -0.930 m/s is the velocity of the boat.
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Using the Left Hand Rule, if motion is down and the current is toward you, which way is the field?
In the left-hand rule, the field is represented by the forefinger and it is perpendicular to the motion.
Fleming’s Left-Hand Rule:A force perpendicular to the field's direction and the direction of the current flow is experienced by a current-carrying conductor when it is exposed to an external magnetic field. According to Fleming's Left Hand Rule, if the thumb, forefinger, and middle finger are arranged in a straight line on the left hand, the thumb will point in the direction of the force experienced by the conductor, and the forefinger will point in the direction of the magnetic field, and the middle finger will point in the direction of the electric current. This rule is employed to determine the magnetic force's direction within an electric motor.
Fleming’s Left-Hand Rule are essential rules applicable in magnetism and electromagnetism. They were created by John Ambrose Fleming in the late 19th century as an easy method of determining the direction of motion in an electric motor.
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A fighter plane is flying overhead at mach 1.20. What angle does the wave front of the shock wave produced make relative to the plane's direction of motion (in degrees)?
Answer: 56.44°
Explanation:
Given:
Let u represent the current speed of the plane, 1.2 MachConverting to SI Units (m/s):
= (1.2 mach)(340 ms^-1 / 1 Mach)
u = 408 m/s
Speed of sound in air, v = 340 m/sFind:
Angle the wave front of the shock wave relative to the plane's direction of motion, θWe have, sinθ = speed of sound / speed of object
sinθ = v / u
θ = sin^-1 (v / u)
= sin^-1 (340 / 408)
θ = 56.44°
The cricket ball has a mass of 0.16kg and it hits the bat with a speed of 25 m/s. After being in contact with the bat for 0.0013 s, the ball rebounds with a speed of 22 m/s in the direction exactly opposite to its original direction.
A) state the difference between speed and velocity
B) calculate.
I) the change in velocity of the cricket ball
Ii) the average acceleration of the ball whilst it is in contact with tge bat
Iii) the average force exerted on the ball by the bat
change in velocity is 3m/s,the force exterted by bat on ball is 4.8N and the acceleration is 30m/s².
Give some difference between velocity and speed.1) Speed is scalar quantity but velocity is vector quantity.
2) Speed is distance followed by an individual with respect to time and velocity is displacement with respect to time .
1) final velocity- intial velocity
25-22= 3m/s
2) The force is
F= ma
. 0.16×30= 4.8N
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16) Find the orbital speed of an ice cube in the rings of Saturn. The mass of Saturn is 5.68 x 10^26 kg, and use an orbital radius of 3.00 x 105 km. (G= 6.67 × 10-11 N·m2/kg2) A) 19.5 km/s B) 27.5 km/s *C) 11.2 km/s D) 20.5 km/. orbital speed?
The orbital speed of an ice cube in the rings of Saturn is 11.2 Km/s. The correct answer is option C
What does Orbital speed depend on ?The speed of an object travelling around a circle depends on two quantities namely;
Its angular velocity wIts distance from the center of the circle.Given that an ice cube in the rings of Saturn. The mass of Saturn is 5.68 x 10^26 kg, and use an orbital radius of 3.00 x 105 km. (G= 6.67 × 10-11 N·m2/kg2)
The given parameters are:
The mass of Saturn = 5.68 x 10^26 kgThe orbital radius = 3.00 x 105 kmG = 6.67 × 10-11 N·m2/kg2Let us first calculate the gravitational field strength on the Saturn.
g = GM/r²
Substitute all the necessary parameters and convert km to m
g = (6.67 × [tex]10^{-11}[/tex] × 5.68 × [tex]10^{26}[/tex]) ÷ (300000 × 1000)²
g = 3.79 × [tex]10^{16}[/tex] ÷ 9 × [tex]10^{16}[/tex]
g = 0.421 m/s²
The orbital speed will be
V² = gr
V² = 0.4211 × 300000 × 1000
V² = 126333333.3
V = √126333333.3
V = 11239.8 m/s
Convert it to Km/s by dividing the answer by 1000
V = 11239.8/1000
V = 11.2 Km/s
Therefore, the orbital speed of an ice cube in the rings of Saturn is 11.2 Km/s
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A child rolls a ball on a level floor 5.2 m to another child.
If the ball makes 15.0 revolutions, what is its diameter?
Express your answer to two significant figures and include the appropriate units.
Diameter of the ball = 11.03cm
The ball rolled by the child must cover a distance in a linear motion which will be then equal to the circumference of the ball after one complete revolution.
Linear distance = 5.2m
d = diameter of the ball =?
Total revolutions = 15
S = 2πr
S = πd
For 15 revolutions
S = 15πd
The Diameter of a ball is double the radius of the ball thus we use D instead of 2r in the formula
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why does a bus look red in the daylight?
Answer:
The red color in the sky at sunset (and sunrise) is due to an effect called Rayleigh scattering.
Explanation:
The CM of an empty 1300-kg car is 2.45 m behind the front of the car.
How far from the front of the car will the CM be when two people sit in the front seat 2.70 m from the front of the car, and three people sit in the back seat 3.65 m from the front? Assume that each person has a mass of 60.0 kg .
Express your answer to three significant figures and include the appropriate units.
The center of mass of the car with all people seated will be 3.20 m far from the front of the car.
Taking the front of the car as reference:
m₁x₁ + m₂x₂ + m₃x₃ = mx
where,
m₁ = mass of empty car = 1300 kg
x₁ = distance of center of mass of empty car from front = 2.45 m
m₂ = mass of 2 people sitting in front = 2 x 60 kg = 120 kg
x₂ = distance of center of mass of 2 people sitting in front from the front = 2.7 m
m₃ = mass of 3 people sitting in back seat = 3 x 60 kg = 180 kg
x₃ = distance of center of mass of 3 people sitting in the back seat from the front = 3.65 m
m = total mass of car with all people = 1300 kg + 120 kg + 180 kg = 1600kg
x = distance of center of mass of the car from the front when all are seated
Therefore,
(1300 kg)(2.45 m) + (120 kg)(2.7 m) + (180kg)(3.65 m) = (1300 kg)x
x = 4166 kg.m/1300 kg
x = 3.20 m
Therefore, the center of mass of the car with all people seated will be 3.20 m far from the front of the car.
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Two charged particles are a distance of 1.72 m from each other. One of the particles has a charge of 7.03 nC, and the other has a charge of 4.02 nC.
(A) What is the magnitude (in N) of the electric force that one particle exerts on the other?
______N
(B) Is the force attractive or repulsive?
The magnitude of the electric force that one particle exerts on the other is 8.59 x [tex]10^{-8}[/tex] N and the force is attractive.
How is Coulomb's Law Stated ?Coulomb law states that the attractive or repulsive force between two point charges is proportional to the product of the charges and inversely proportional to square of the distance between them. That is,
F = KQq / r²
Given that two charged particles are a distance of 1.72 m from each other. One of the particles has a charge of 7.03 nC, and the other has a charge of 4.02 nC.
Where
K = constant of proportionality = 9 x [tex]10^{9}[/tex] Nm²/c²Q = 7.03 x [tex]10^{-9}[/tex] Cq = 4.02 x [tex]10^{-9}[/tex] Cr = 1.72 m(A) The magnitude of the electric force that one particle exerts on the other will be
F = (9 x [tex]10^{9}[/tex] x 7.03 x [tex]10^{-9}[/tex] x 4.02 x [tex]10^{-9}[/tex]) / 1.72²
F = 2.54 x [tex]10^{-7}[/tex] / 2.96
F = 8.59 x [tex]10^{-8}[/tex] N
(B) Since our answer is positive, the force is therefore attractive.
Therefore, the magnitude of the electric force that one particle exerts on the other is 8.59 x [tex]10^{-8}[/tex] N and the force is attractive.
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A. The magnitude (in N) of the electric force that one particle exerts on the other is 8.60×10⁻⁸ N
B. The force is repulsive
A. How to determine the magnitude of the electric forceFrom the question given above, the following data were obtained:
Charge 1 (q₁) = 7.03 nC = 7.03×10¯⁹ CCharge 2 (q₂) = 4.02 nC = 4.02×10¯⁹ CElectric constant (K) = 9×10⁹ Nm²/C²Distance apart (r) = 1.72 mForce (F) =?The magnitude of the electric force can be obtained by using the Coulomb's law equation as shown below:
F = Kq₁q₂ / r²
F = (9×10⁹ × 7.03×10¯⁹ × 4.02×10¯⁹) / (1.72)²
F = 8.60×10⁻⁸ N
B. How to determine whether the force is attractive or repulsiveFrom the question given, we were told that:
Charge 1 (q₁) = 7.03 nC Charge 2 (q₂) = 4.02 nCSince both charge are positive, then the force attraction between them is repulsive as like charges repels and unlike charges attracts
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PLEASE read this carefully.
A solid, homogeneous sphere with a mass of m0, a radius of r0 and a density of ρ0 is placed in a container of water. Initially the sphere floats and the water level is marked on the side of the container. What happens to the water level, when the original sphere is replaced with a new sphere which has different physical parameters? Notation: r means the water level rises in the container, f means falls, s means stays the same. Combination answers like 'r or f or s' are possible answers in some of the cases.
The new sphere has a radius of r < r0 and a mass of m > m0.
The new sphere has a mass of m > m0 and a density of ρ < ρ0.
The new sphere has a density of ρ < ρ0 and a radius of r > r0.
For each of the given scenarios and based on the volume, mass, and density of the spheres, the water level is given as follows:
Scenario 1: The water level will rise; r
Scenario 2: The water level may rise or fall; r or f
Scenario 3: The water level will fall; f
What is the relationship between volume, density, and mass of the objects?The density, volume and mass of an object are related by the formula below:
Density = mass/volumeThe rise in the level of fluid when an object is placed in that fluid depends on the weight, volume and density of that object.
This is given by Archimedes' principle which states that the upthrust acting on a body immersed fully or partially in a fluid, is equal to the weight of the fluid displaced.
Based on the above, the water level in each of the scenarios is described thus:
Scenario 1: The new sphere has a radius of r < r0 and a mass of m > m0.
The new has a smaller volume and a greater mass and density. The water level will rise.
Scenario 2: The new sphere has a mass of m > m0 and a density of ρ < ρ0.
The new sphere has a greater volume and will float. Therefore, the water level may rise or fall.
Scenario 3: The new sphere has a density of ρ < ρ0 and a radius of r > r0.
The new sphere has a greater volume but less mass. Therefore, the water level will fall.
In conclusion, the rise or fall of the water level in the container depends on the volume, mass, and density of the spheres.
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The oxygen–hemoglobin dissociation curve depicts the relationship between the partial pressure of oxygen (pao2) and the:__________
The oxygen–hemoglobin dissociation curve depicts the relationship between the partial pressure of oxygen (pao2) and the arterial oxygen.
What does the oxygen–hemoglobin dissociation curve depicts?The oxygen-hemoglobin dissociation curve (OHDC) indicates the relationship between the oxygen saturation of hemoglobin and the partial pressure of arterial oxygen. This curve can change its position or shifted to another level depending on various factors.
So we can conclude that the oxygen–hemoglobin dissociation curve depicts the relationship between the partial pressure of oxygen (pao2) and the arterial oxygen.
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A centrifuge in a medical laboratory rotates at an angular speed of 3,400 rev/min. When switched off, it rotates through 52.0 revolutions before coming to rest.
Find the constant angular acceleration (in rad/s2) of the centrifuge.
______rad/s2
The constant angular acceleration (in rad/s2) of the centrifuge is 194.02 rad/s².
Constant angular acceleration
Apply the following kinematic equation;
ωf² = ωi² - 2αθ
where;
ωf is the final angular velocity when the centrifuge stops = 0ωi is the initial angular velocity θ is angular displacementα is angular accelerationωi = 3400 rev/min x 2π rad/rev x 1 min/60s = 356.05 rad/s
θ = 52 rev x 2π rad/rev = 326.7 rad
0 = ωi² - 2αθ
α = ωi²/2θ
α = ( 356.05²) / (2 x 326.7)
α = 194.02 rad/s²
Thus, the constant angular acceleration (in rad/s2) of the centrifuge is 194.02 rad/s².
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Human centrifuges are used to train military pilots and astronauts in preparation for high-g maneuvers. A trained, fit person wearing a g-suit can withstand accelerations up to about 9g (88.2 m/s2) without losing consciousness.
(a) If a human centrifuge has a radius of 4.00 m, what angular speed (in rad/s) results in a centripetal acceleration of 9g?
_______rad/s
(b) What linear speed (in m/s) would a person in the centrifuge have at this acceleration?
________m/s
(a) The angular speed of the human centrifuge is 4.7 rad/s.
(b) The linear speed (in m/s) a person in the centrifuge would have at this is 18.8 m/s.
Angular speed of the human centrifuge
a = ω²r
where;
a is centripetal acceleration = 9gr is radius of human centrifugeω = √(a/r)
ω = √(9g/r)
ω = √(9 x 9.8 / 4)
ω = 4.7 rad/s
Linear speed of the centrifugev = ωr
where;
v is linear speedv = (4.7 rad/s) x 4 m
v = 18.8 m/s
Thus, the angular speed of the human centrifuge is 4.7 rad/s. The linear speed (in m/s) a person in the centrifuge would have at this is 18.8 m/s.
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Piston 1 in the figure has a diameter of 1.87 cm.
Piston 2 has a diameter of 9.46 cm. In the absence of friction, determine the force F, necessary to support an object with a mass of 991 kg placed on piston 2. (Neglect the height difference between the bottom of the two pistons, and assume that the pistons are massless).
The force F, necessary to support an object with a mass of 991 kg placed on piston 2 is 373.8 N.
What is the force required to support the weight on piston 2?The force, F required to support the weight on piston 2 is calculated as follows:
F = F₂ * A₁/A₂f = 991 * 9.81 = 9721.71 N
A₂ = (9.46/2)² = 22.373
A₁ = (1.87/2)² = 0.874
F = 9721.71 * 0.874/22.373
F = 373.8 N
Inc conclusion, a smaller force is applied to lift the larger force at Piston 2.
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In the hydrogen atom, which electronic transition corresponds to the largest energy emission?
In hydrogen atom the electronic transition from n= ∞ to n=1 corresponds to largest energy emission.
What is electronic transition ?Electronic transition is the jump of an electron from one energy level to another energy level .
Which electronic transition in Hydrogen atom corresponds to highest energy emission?The fromula for energy emission isE = hc/λ
where E= emited energyh= plank constant =6.62*10^(-34)
c=speed of light
λ= wavelength of emited electron .
The electronic transition from infinity to ground state corresponds to lowest wavelength .Thus , we can conclude that the electronic transition from infinity to n=1 (ground state) corresponds to largest energy emission .
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How is faraday's law applicable in Electronic Drum
Faraday's law is applicable in the mechanism behind electric generators, credit cards, metal detectors, computer hard drives and electronic drum
What is Faraday's law?Faraday's law states that a changing magnetic field through an area or equivalently, a changing area with constant field will cause a voltage.
So therefore, Faraday's law is applicable in the mechanism behind electric generators, credit cards, metal detectors, computer hard drives and electronic drum
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what does personal mission statement?
Answer:
A personal mission statement defines who you are as a person (or as a team member where you work) and identifies your purpose, whether that's in the office or simply in life.
Explanation:
It explains how you aim to pursue that purpose, and why it matters so much to you.
What does the Q stand for in the enthalpy of fusion equation?
The Q in the enthalpy of fusion equation stands for heat energy absorbed or released.
What is enthalpy?In thermodynamics, enthalpy is a measure of the heat content of a chemical or physical system.
The enthalpy of fusion is the amount of heat energy required to convert a unit mass of a solid at its melting point into a liquid without an increase in temperature.
Its units are usually Joules per gram (J/g) or calories per gram (cal/g).
The enthalpy of fusion equation is given as follows:
Q = m·ΔHf
Where;
Q = heat energym = massΔHf = heat of fusionTherefore, the Q in the enthalpy of fusion equation stands for heat energy absorbed or released.
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In the Roman soldier model for refraction, what happens to the distance between the rows of each soldier once they enter the stream?
A. Not enough info
B. They are closer together
C. They stay the same distance
D. They are further apart
They pick up speed and move away from the usual.
Using meter sticks, a group of pupils makes a straight line (shoulder to shoulder) and connects to their closest neighbor. Two media are separated in the room by a strip of masking tape. Students can be seen moving normally in one of the media (on one side of the tape). The kids in the other medium (or on the opposite side of the tape) move very slowly and in baby stages. The class moves in the union in a straight line in the direction of the diagonal piece of masking tape. As they get close to the masking tape, the pupils stay in line. Each pupil immediately changes the speed of her or his walk as she or he reaches the tape.
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PLEASE HELP 20!!+BRAINLIEST
It is critical for scientists to be able to describe components of a system quantitatively. Explain why it is important to be able to describe a system quantitatively, using an example from your investigation about habitable worlds
It is important to be able to describe a system quantitatively because there exist many variables that show a continuous range of variation.
What is quantitative research?Quantitative research is any type of investigation based on scientific variables that express their values as a continuous range of variation.
For example, there are genetic traits such as height and weight that show quantitative variation, thereby they need to be expressed as ranges.
In conclusion, it is important to be able to describe a system quantitatively because there exist many variables that show a continuous range of variation.
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a)Calculate the angular velocity of the Earth in its orbit around the Sun.
Express your answer using three significant figures.
b) Calculate the angular velocity of the Earth about its axis.
Express your answer using three significant figures.
The earth's orbital angular velocity around the Sun is 0.986° per day, and its axial angular velocity is 15.041° per hour.
Calculation:
The speeds, not the velocities, are what we require in this case, therefore that is how I will approach it.
Regular speed is calculated by dividing the distance traveled by the travel time.
So, speed = [tex]\frac{distance -travelled}{time}[/tex]
The angular velocity is essentially the same.
Hence, it's divided by the amount of time it took to turn the angle.
(a) Calculation of Earth's orbit around the Sun :
The Earth orbits the Sun in a circle that is 2 radians in diameter (360 degrees). It also takes a year, as we are aware (approx 365 days)
360°/365.25636 days = 0.986°/day ≈ 1° per day
(b) Next, we have to calculate Earth's angular velocity on its axis:
determining the Earth's angular velocity as it fulfills a complete revolution on its axis (a solar day)-
This one requires more precision because a day does not always have 24 hours. Depending on how we define a day,If the day is defined as the time between the Sun's highest and lowest points in the sky, a year's worth of data equals an average of 24 hours.If we define a day as the duration of time it requires for a planet to get to the same location in the sky the following night, then it is 23 hours 56 minutes 4.09 seconds.According to this, the angular speed of rotation = 360°/ 23h 56min 4.09s = 15.041° / hour.
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A 0.550 kg air-track glider is attached to each end of the track by two coil springs. It takes a horizontal force of 0.500 N to displace the glider to a new equilibrium position, x= 0.070 m.
1. Find the effective spring constant of the system.
2. The glider is now released from rest at x= 0.070 m. Find the maximum x-acceleration of the glider.
3. Find the x-coordinate of the glider at time t= 0.650T, where T is the period of the oscillation.
4. Find the kinetic energy of the glider at x=0.00 m.
(1) The effective spring constant of the system is 7.14 N/m.
(2) The maximum x-acceleration of the glider is 0.9 m/s².
(3) The x-coordinate of the glider at time t= 0.650T is 0.28 m.
(4) The kinetic energy of the glider at x=0.00 m is zero.
The effective spring constant of the system
The effective spring constant of the system is calculated as follows;
F = kx
where;
k is spring constantk = F/x
k = 0.5/0.07
k = 7.14 N/m
Maximum acceleration of the glidera = ω²x
where;
ω is angular speedω = √k/m
ω = √(7.14/0.55)
ω = 3.6 rad/s
a = (3.6)² x 0.07
a = 0.9 m/s²
Period of the oscillationT = 2πx/v
T = 2πx/(ωx)
T = 2π/ω
T = 2π/(3.6)
T = 1.75 seconds
t = 0.65T
t = 0.65 x 1.75
t = 1.14 seconds
x = vt
x = (ωx)t
x = (3.6 x 0.07) x 1.14
x = 0.28 m
kinetic energy of the gliderAt position x = 0, the glider is at rest, the velocity is zero and the kinetic energy will be zero.
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Is India a rich country?
Explanation:
India. Total wealth: $8.9 trillion | Wealth per capita: $6,440 | India, which is the fifth-largest economy in the world, is home to 3,57,000 HNWIs and 128 billionaires.
Answer:
50505050128128128128
Explanation:
What is a small portable device that counts every step taken throughout the day?
A.stethoscope
B.pedometer
C.otoscope
D.thermometer
Answer: B
Explanation: i learned it last year
Pedometer is a small portable device that counts every step taken throughout the day. The correct option is (B).
A pedometer is a small portable device that counts the number of steps taken by an individual throughout the day. It is typically worn on the waist or carried in a pocket and uses a mechanism to detect body motion and count each step.
Pedometers are commonly used for tracking physical activity and encouraging individuals to achieve daily step goals as part of their fitness routines.
Therefore, Pedometer is a small portable device that counts every step taken throughout the day. Choose the option (B).
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An old grindstone, used for sharpening tools, is a solid cylindrical wheel that can rotate about its central axle with negligible friction. The radius of the wheel is 0.330 m. A constant tangential force of 200 N applied to its edge causes the wheel to have an angular acceleration of 0.844 rad/s2.
What is the moment of inertia of the wheel (in kg · m2)?
________kg · m2
What is the mass (in kg) of the wheel?
_______kg
The wheel starts from rest and the tangential force remains constant over a time period of 4.00 s. What is the angular speed (in rad/s) of the wheel at the end of this time period?
_______rad/s
(a) The moment of inertia of the wheel is 78.2 kgm².
(b) The mass (in kg) of the wheel is 1,436.2 kg.
(c) The angular speed (in rad/s) of the wheel at the end of this time period is 3.376 rad/s.
Moment of inertia of the wheel
Apply principle of conservation of angular momentum;
Fr = Iα
where;
F is applied forcer is radius of the cylinderα is angular accelerationI is moment of inertiaI = Fr/α
I = (200 x 0.33) / (0.844)
I = 78.2 kgm²
Mass of the wheelI = ¹/₂MR²
where;
M is mass of the solid cylinderR is radius of the solid cylinderI is moment of inertia of the solid cylinder2I = MR²
M = 2I/R²
M = (2 x 78.2) / (0.33²)
M = 1,436.2 kg
Angular speed of the wheel after 4 secondsω = αt
ω = 0.844 x 4
ω = 3.376 rad/s
Thus, the moment of inertia of the wheel is 78.2 kgm².
The mass (in kg) of the wheel is 1,436.2 kg.
The angular speed (in rad/s) of the wheel at the end of this time period is 3.376 rad/s.
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A steel piano wire, of length 1.150 m and mass 4.80 g is stretched under a tension of 580.0 N. What is the speed of transverse waves on the wire?
The speed of transverse waves on the wire is 1.555.
Given: Length= 1.150 m
Mass= 4.80 g
Speed =mass/length
U=M/L formula
U=1.150 *10^(-3)/4.80
v=√t/u
v=√580*4.80/1.150*10^(-3)=1.555
1.555
The derivative of the displacement with respect to time gives the transverse velocity in the y direction, as velocity is the rate of change of position: Where k = 2/ is referred to as the wave number and = 2f as before, v(x,t) = y(x,t)/t = -A cos (k x - t + ).The linear density and tension v=FT can be used to determine the wave's speed. v = F T μ . According to the equation v=FT, v = F T, the tension would need to be increased by a factor of 20 if the linear density were to be doubled by almost as much.
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Which of the following phrases describes power?
A. How much energy is lost in friction
B. How much energy is lost in heat
OC. The rate energy is consumed
OD. The rate an object is moving
The rate energy is consumed this statement describes power.
Hence, Option C is correct answer.
How can we understand that this statement can describe power?Power is related to energy by that it is the rate at which energy is transferred.
What is Power ?It is a measure of the rate at which work is done.
According to the definition of power, Power is the amount of energy transferred or converted or consumed per unit time.
SI unit of power is watt.
By definition, 1 watt is equal to one joule of work done per second. So if P represents power in watts, E is the change in energy (number of joules) and t is the time taken in seconds then:
P=[tex]\frac{E}{t}[/tex]= [tex]\frac{1 Joule}{1 Second}[/tex]= 1 Watt.
Thus from the above conclusion we can say that, The rate energy is consumed describes power.
Hence, Option C is correct answer
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the highest theoretical efficiency of a certain engine is 30% if the engine uses the atmosphere which has a temperature of 300k as its cold reservoir what is temperature of its hot reservoir
The temperature of its hot reservoir would be = 210k
Calculation of reservoir temperatureThe highest theoretical engine efficiency (η)= 30% =0.3
The temperature of the engine cold reservoir (T1)= 300k
Therefore the temperature of the engine hot reservoir (T2) = ?
Using this formula:
η=1- T2/T1
Make T2 the subject formula:
T2= T1 (1 - η)
T2 = 300 ( 1-0.3)
T2 = 300 × 0.7
T2 = 210k
Therefore, the temperature of its hot reservoir would be = 210K.
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