Three different resistors, R1, R2, and R3 are connected in parallel to a battery. Suppose R1 has 2 V across it, R2 = 4 ohms, and R3 dissipates 6 W. What is the current in R3?
A) 0.5 A
B) 2 A
C) 3 A
D) 12 A

To find the current in R3, we need to use the formula for power in a resistor: P = I^2 * R, where P is power, I is current, and R is resistance. We can rearrange this formula to solve for I: I = sqrt(P/R).

We know that R1 has 2 V across it, but we don't know its resistance. However, we can use Ohm's Law (V = IR) to find it: R1 = 2V / I. Since R2 is given as 4 ohms, we don't need to do any calculations for it.

To find the total resistance of the circuit, we use the formula for resistors in parallel: 1/Rtotal = 1/R1 + 1/R2 + 1/R3. Plugging in the values we know, we get: 1/Rtotal = 1/(2V/I) + 1/4 + 1/R3. Simplifying this equation requires some algebra, but we can eventually solve for Rtotal.

Once we have Rtotal, we can use Ohm's Law again to find the total current in the circuit: I = Vtotal / Rtotal, where Vtotal is the voltage of the battery.

Finally, we can use the fact that R3 dissipates 6 W to find the current in R3: 6 = I^2 * R3, which we can rearrange to I = sqrt(6/R3).

Putting it all together, we get:

- R1 = 2V / I
- R2 = 4 ohms
- 1/Rtotal = 1/(2V/I) + 1/4 + 1/R3
- I = Vtotal / Rtotal
- I = sqrt(6/R3)

Unfortunately, we don't know the voltage of the battery or the value of Rtotal, so we can't solve for I. Therefore, the answer is "cannot be determined from the given information."

TO KNOW MORE ABOUT Three different resistors CLICK THIS LINK -

brainly.com/question/14987770

#SPJ11

73) If the temperature of a gas is increased from 20°C to 100°C, by what factor does the rms speed of an ideal molecule change?
A) 1.1
B) 1.3
C) 2.2
D) 1.6