Tin is an example of an element that has a great number of naturally occurring isotopes. How many neutrons are in tin-120?

The crystallization step of recrystallization removes soluble impurities from a solid mixture. When a solid is dissolved in a solvent and then allowed to cool, the solubility of the solid in the solvent decreases and the solid crystallizes out of the solution.

Soluble impurities, which are typically more soluble in the solvent than the desired compound, will remain in solution or be incorporated into the crystal lattice of the impure crystals. As a result, the crystals that form during the crystallization step will have a higher purity than the initial solid mixture. Further purification can be achieved through multiple rounds of recrystallization using different solvents or by additional purification methods such as chromatography.

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Answer:The mass of a single water molecule can be calculated using its molecular formula, H2O. The molecular weight of water is 18.015 g/mol.If we have 3.01 x 10^24 water molecules, the total mass can be calculated as follows:Mass = Number of water molecules * Molecular weight of waterMass = 3.01 x 10^24 * 18.015 g/molMass = 5.45 x 10^25 gSo, the mass of 3.01 x 10^24 water molecules is approximately 5.45 x 10^25 grams.

Metallic bonding is a common characteristic of a material that may conduct electricity when it is solid. The movement of electrical power or charge is known as electricity.

Metallic bonding is the kind of bonding that results in a material with the capacity to conduct electricity when it is solid. The valence electrons of metal atoms become delocalized and free to roam about the crystal lattice during metallic bonding, forming a "sea" of electrons. As they are able to transfer electricity through solid materials, these delocalized electrons are what give solid materials their electrical conductivity. Copper, aluminium, and gold are a few examples of metals that display metallic bonding and electrical conductivity in the solid form. A fundamental component of the natural world, electricity is also one of the most extensively utilised energy sources.

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The water droplet on wax paper is round and flat on a glass surface, this is because of the hydrophobic and hydrophilic properties of water.

The water drop on wax paper is very round in comparison to the one on a glass which is flatter, this indicates the property of cohesion of water molecules, this is due to gravity.

On the other hand, when the water droplet is on wax paper it is way rounder in shape and attracted to the wax paper called as adhesion.

Hydrophobic literally means "fear of water."

In chemistry, it could be said it's the physical property of molecules that are repelled from a mass of water. This is the case with wax paper where its can't get absorbed or fail to mix and rather tend to repel.

Hydrophile is basically opposite of hydrophobic which is the molecules attracted to water. A hydrophile is a molecule or other molecular entity that is attracted to water molecules and tends to be dissolved by water.

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We require the number of moles of solute and the volume of the solution in liters to determine the molarity of a solution. Initially, we must calculate the amount of moles of NaCl in 5.85 g. NaCl .

has a molar mass of 58.44 g/mol: NaCl moles = mass of NaCl / molar mass of NaCl moles = 5.85 g / 58.44 g/mol NaCl moles = 0.1 mol The volume of the solution must then be converted from milliliters to liters: 500 mL / 1000 mL/L solution volume 0.5 L solution volume We can compute the molarity of the solution now that we know the number of moles of NaCl and the volume of the solution in liters: molarity = solute moles / volume of solutio molarity = 0.1 mol / 0.5 L molarity = 0.2 mol/L Therefore, the molarity of the solution is 0.2 mol/L, which corresponds to option C.

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The mineral Calcite has a pale yellow color with a dull luster. It has no visible cleavage.

It appears to have a conchoidal fracture, where the pieces break apart with curved edges.Calcite is a very common mineral composed of calcium carbonate (CaCO3). It is the primary mineral in many metamorphic and sedimentary rocks, and is a major component of limestone and marble. Calcite has a hardness of 3 on the Mohs scale, which makes it suitable for use in jewelry and ornaments. Calcite occurs in a variety of colors, including white, yellow, orange, pink, blue, and green. It is also the main component of many chalk deposits. Calcite is used in many industrial processes and products, including as a filler in cement, as a neutralizing agent in soil, and as a flux in steelmaking. It is also used as a source of calcium in animal feed and as a food additive.

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complete question:Observe the minerals Calcite. Describe the mineral's colour, luster (shiny or dull) and the way they break apart (cleavage or fracture) in the student guide

Number of protons number of electrons neutral atom cation anion neutral atom cation anion neutral atom cation anion number of proton is 7 So, atomic number is 7 atomic number is 7 for N charge.

Number of proton is 7 So, atomic number is 7 atomic number is 7 for N charge = number of proton - number of electron  = 7 - 10  = -3 So, this is anion A .

Protons are the positively charged particles that are inside the nucleus of an atom. The protons are pushed apart by the electromagnetic force but pulled together by the strong force, which is stronger over short distances .

Cations are positively-charged ions (atoms or groups of atoms that have more protons than electrons due to having lost one or more electrons). Anions are negatively-charged ions (meaning they have more electrons than protons due to having gained one or more electrons).

The number of neutrons is equal to the difference between the mass number of the atom (M) and the atomic number (Z).

Electron, proton, neutron are subatomic particles which build the atom. The atom consists of a central nucleus containing neutron and proton. Electrons revolve around the nucleus. Electrons are negatively charged, proton is positively charged and neutron is neutral.

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Answer:

[tex]\huge\boxed{\sf P = 800.8\ Ns}[/tex]

Explanation:

Speed = v = 10.4 m/s

Mass = m = 77 kg

Momentum = P = ?

P = mv

Put the given data in the above formula.

P = (77)(10.4)

[tex]\rule[225]{225}{2}[/tex]

you need to measure out 17.0 grams of NaOH to prepare a 1.7 M solution of 250.0 mL.

To calculate the amount of NaOH needed to prepare a 1.7 M solution of 250.0 mL, we can use the formula:

moles of solute = concentration (in M) x volume (in L)

First, we need to convert the volume from milliliters to liters:

250.0 mL = 250.0 / 1000 = 0.25 L

Now, we can plug in the values:

moles of NaOH = 1.7 M x 0.25 L

moles of NaOH = 0.425 mol

Finally, we can calculate the mass of NaOH required using its molar mass:

mass of NaOH = moles of NaOH x molar mass of NaOH

The molar mass of NaOH is 40.00 g/mol (sodium: 22.99 g/mol, oxygen: 15.99 g/mol, hydrogen: 1.01 g/mol).

mass of NaOH = 0.425 mol x 40.00 g/mol

mass of NaOH = 17.0 g

Therefore, To calculate the amount of NaOH needed to prepare a 1.7 M solution of 250.0 mL, we can use the formula:

moles of solute = concentration (in M) x volume (in L)

First, we need to convert the volume from milliliters to liters:

250.0 mL = 250.0 / 1000 = 0.25 L

Now, we can plug in the values:

moles of NaOH = 1.7 M x 0.25 L

moles of NaOH = 0.425 mol

Finally, we can calculate the mass of NaOH required using its molar mass:

mass of NaOH = moles of NaOH x molar mass of NaOH

The molar mass of NaOH is 40.00 g/mol (sodium: 22.99 g/mol, oxygen: 15.99 g/mol, hydrogen: 1.01 g/mol).

mass of NaOH = 0.425 mol x 40.00 g/mol

mass of NaOH = 17.0 g

Therefore, you need to measure out 17.0 grams of NaOH to prepare a 1.7 M solution of 250.0 mL.

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Out of the given pairs of atoms, sodium and iodine are most likely to form an ionic bond with each other.

Ionic bonds occur between atoms with significantly different electronegativities, where one atom donates an electron(s) to another atom, resulting in the formation of a positively charged cation and a negatively charged anion that are then held together by electrostatic forces.

Sodium (Na) has one valence electron and a relatively low electronegativity, while iodine (I) has seven valence electrons and a relatively high electronegativity. Therefore, when sodium and iodine come into contact, sodium is likely to donate its valence electron to iodine to form the ionic compound sodium iodide (NaI).

Sodium and potassium have similar electronegativity values and are both alkali metals, making them less likely to form ionic bonds with each other since their properties are similar.

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The partial pressure of Cl2 is calculated by taking the chemical equation that is mentioned below. In an equilibrium mixture at 500 K, the partial pressure of PCl5 is 0.860 atm and that of PCl3 is 0.350 atm.

The partial pressure of Cl2 at equilibrium is. Q. 'a' mol of PCl5 undergoes thermal dissociation as-

PCl5⇌PCl3+Cl2;

the mole fraction PCl3 at equilibrium is 0.25 and the total pressure is 2 atm. The partial pressure can be calculated as follows: P(gas 1) = x(gas 1) * P(Total); where x(gas 1) = no of moles(gas 1)/ no of moles(total). As you can see the above formulae does not require the individual volumes of the gases or the total volume.

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In a 60g sample of tetraethyl-lead, a gasoline is addictive, is found to contain 38.43g lead, 17.83g carbon and 3.74g hydrogen, its empirical formula is PbC₆H₂₀.

The term Empirical formula is defined as the chemical formula of a compound that gives the ratios of the elements present in the compound but not the actual numbers or arrangement of atoms.

The percentage mass of Pb = 38.43/60 × 100

= 64.05 %

The percentage mass of C = 17.83/60 × 100

= 29.71%

The percentage mass of H = 3.74/60 × 100

= 6.23%

Now,

Pb → 64.05/207

= 0.3094

C ⇾ 29.71/12

= 2.475

H ⇾ 6.23/1

= 6.23

Therefore, the ratio is as follows:

Pb : C : H = 1 : 8 : 20

Thus, empirical formula is PbC₆H₂₀.

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The concentration of the acid is  0.016 M

A neutralization reaction is a chemical reaction in which an acid and a base react to form a salt and water. The reaction occurs when the hydrogen ions (H+) from the acid react with the hydroxide ions (OH-) from the base to form water (H2O). The salt that forms depends on the specific acid and base that are reacted.

Using;

CAVA/CBVB = NA/NB

CA = concentration of acid

CB = concentration of base

VA = volume of acid

VB = Volume of base

Then;

CAVANB = CBVBNA

CA =  CBVBNA/VANB

CA = 0.0193 M  *  25.6 mL * 1/15 mL  * 2

CA = 0.016 M

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The molar ratio of Mg reacted to H2 produced is 1:1. This means that for every mole of Mg that reacts, one mole of H2 is produced. The stoichiometric ratio between the Mg ribbon reactant and the hydrogen gas product is also 1:1.

This ratio is determined by the balanced chemical equation for the reaction between Mg and HCl, which is Mg + 2HCl → MgCl2 + H2. The coefficients in this equation represent the number of moles of each reactant and product that are involved in the reaction. The coefficient for Mg is 1, indicating that one mole of Mg reacts with two moles of HCl to produce one mole of H2 and one mole of MgCl2.

The stoichiometric ratio is important because it allows us to determine the number of reactants or products needed in a reaction. For example, if we know the amount of Mg we have, we can use the stoichiometric ratio to calculate the amount of H2 that will be produced. Similarly, if we know the amount of H2 we need, we can use the stoichiometric ratio to determine how much Mg we need to react with HCl to produce the required amount of H2.

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Between 0 and 1500, the average reaction rate is 0.000112 M/s, or 7.14*[tex]10^{-5}[/tex]Instantaneous rate is thus 7.25*[tex]10^{-5}[/tex] M/s..

Resistance or antagonism to a force, action, or movement is a reactionary act, process, or occurrence. especially: a reaction to a particular treatment, circumstance, or stimulus; leaning toward a past and typically antiquated political or social system or policy. She was shocked by the information.

The paper ought to include a synopsis of the source material, but the major emphasis should be on your opinions and justifications regarding the topics included in the actual text. This necessitates your consideration of the provided work, followed by a targeted, well-thought-out response supported by outside sources, when appropriate.

Part A:

At t = 0 s , [A] = 0.184 M

At t = 1500 s , [A] = 0.016 M

Average rate = \Delta[A] / \Deltat

= (0.016 - 0.184) / (1500 - 0)

= - 0.168 / 1500

= - 0.000112 M/s

Hence average rate = 1.12*[tex]10^{-4}[/tex] M/s

Part B:

At t = 500 s , [A] = 0.069 M

At t = 1200 s , [A] = 0.019 M

Average rate = (0.019 - 0.069) / (1200 - 500)

= - 0.05 / 700

= - 7.14*[tex]10^{-5}[/tex] M/s

Hence average rate = 7.14*[tex]10^{-5}[/tex] M/s

Part C:

0.20 0.18 0.16 0.14 0.12 Z 0.10 0.08 0.06 0.04 0.02 0 200 400 600 800 1000 1200 1400 1600 Time (s)

Now, we have:

At t = 600s ; [A] = 0.043 M

At t = 1000s ; [A] = 0.014 M

Instantaneous rate = slope of tangent at t = 800s

= d[A] / dt

= (0.014 - 0.043) / (1000 - 600)

= - 0.029 / 400

= - 0.0000725 M/s

Hence instantaneous rate =  7.25*[tex]10^{-5}[/tex] M/s

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A 0.0907 g sample of a weak acid requires 15.0 ml of 0.1008 m sodium hydroxide to be neutralized by titration. the molar mass of the monoprotic weak acid is 60.13 g/mol.

We can use the balanced chemical equation of the neutralization reaction to calculate the number of moles of the weak acid that reacted with the sodium hydroxide:

Weak acid + NaOH → NaA + H2O

where NaA is the sodium salt of the weak acid.

The number of moles of sodium hydroxide used can be calculated from its concentration and the volume used in the titration:

n(NaOH) = C(NaOH) x V(NaOH)

n(NaOH) = 0.1008 mol/L x 0.0150 L

n(NaOH) = 0.00151 mol

Since 1 mole of weak acid reacts with 1 mole of sodium hydroxide, the number of moles of the weak acid is also 0.00151 mol.

The molar mass of the weak acid can be calculated using its mass and the number of moles:

Molar mass = mass / moles

Molar mass = 0.0907 g / 0.00151 mol

Molar mass = 60.13 g/mol

Therefore, the molar mass of the monoprotic weak acid is 60.13 g/mol.

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By titration, it is found that the 11.9 ml of the 0.101 M NaOH(aq) is needed to neutralize the 25.0 ml of HCl(aq).The concentration of the HCl solution is 0.048 M.

The reaction is as follows :

NaOH + HCl ---->  NaCl  +  H₂O

The concentration of the NaOH = 0.101 M

The volume of the NaOH = 11.9 mL = 0.0119 L

The moles of the NaOH = molarity ×volume

                                        = 0.101 × 0.0119

                                        = 0.0012 mol

The Volume of the HCl = 25 mL = 0.025 L

The moles of the HCl = 0.0012 mol

The concentration of the HCl = moles / volumes in L

                                                 = 0.0012 / 0.025

                                                 = 0.048 M

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It is typical to measure liquid volume using both a graduated cylinder and a buret. As the name implies, a graded cylinder is a cylindrical glass or plastic tube that is sealed at one end and has a calibrated scale inscribed on the outside.

A measuring cylinder, often referred to as a graded cylinder, a measuring cylinder, or a mixing cylinder, is a piece of lab apparatus used to gauge the quantity of fluids, chemicals, or solutions used during a typical lab session. Graduated cylinders are more precise and accurate than traditional laboratory flasks and beakers. The scale on a 50-mL buret is in increments of 0.1 mL. A buret's liquid level is measured and recorded to the nearest 0.01 mL in order to prevent any inaccuracies. The volume of the liquid can be calculated using a measuring flask, pipette, and measuring cylinder.

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Avogadro's number can be multiplied by the number of moles to determine the number of atoms in 4.48 L of He gas at STP is  1.20 x 10²³ atoms.

Option D is correct.

                       N = N × n

                = 6.02 x 10²³ × 0.200 mol

                            = 1.20 x 10²³ atoms.

Therefore, the answer is 1.20 x 10²³ atoms.

In physics and chemistry, Avogadro's number is a fundamental constant that indicates the number of atoms, ions, or molecules in one mole of a substance. It is exactly 6.02214076 x 10²³ particles per mole, as defined.

Standard Temperature and Pressure is spelled STP. For the purpose of measuring the physical properties of gases, STP is utilized as a reference condition. It has a temperature of 0° Celsius and a pressure of one atmosphere.

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Human activities have disrupted the natural balance in the carbon cycle and are the main reason for the current imbalance.

The equation provided represents the balance in the atmospheric carbon levels. The atmospheric carbon is equal to the sum of all carbon output, such as emissions from fossil fuel burning and deforestation, minus the sum of all carbon inputs, such as photosynthesis and carbon absorption by oceans.

However, due to human activities like burning of fossil fuels, deforestation, and land use changes, the balance in the carbon cycle has been disrupted. The amount of carbon output has increased significantly, leading to a rise in atmospheric carbon levels. Meanwhile, the inputs, such as photosynthesis and carbon absorption by oceans, have not increased proportionately.

As a result, the equation is no longer balanced and there is now more atmospheric carbon than can be absorbed through natural processes. This has led to an increase in greenhouse gases and global warming, causing a range of environmental and health problems.

Therefore, human activities have disrupted the natural balance in the carbon cycle and are the main reason for the current imbalance.

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The electron gain enthalpy of Na+ is 5.65 eV.

The amount of energy released when an electron is added to a single gaseous atom is known as the electron gain enthalpy. Energy can either be released or absorbed when an electron is added.

The electron gain enthalpy of Na+ can be calculated using the formula below:

Electron gain enthalpy of Na+ = Ionization enthalpy of Na - Electron affinity of Na

The ionization enthalpy of Na is 5.1 eV.

The electron affinity of Na is -0.55 eV.

Therefore, the electron gain enthalpy of Na+ can be calculated as:

Electron gain enthalpy of Na+ = Ionization enthalpy of Na - Electron affinity of Na

Electron gain enthalpy of Na+ = 5.1 eV - (-0.55 eV)

Electron gain enthalpy of Na+ = 5.65 eV

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The correct answer is the correct formula for Magnesium Chloride is MgCl2

An inorganic compound with the chemical formula MgCl2 is magnesium chloride. It generates MgCl2nH2O hydrates, where n can range in value from 1 to 12. These salts are white or colorless solids that are very soluble in water. These chemicals can be found in nature in both their compounds and solutions, and they have a wide range of practical uses. Anhydrous magnesium chloride serves as the primary precursor for the widely produced magnesium metal. Magnesium chloride that has been hydrated is the form that is most readily available. Magnesium chloride may be extracted using brine or saltwater. The Great Salt Lake in North America provides the bulk of the brine used to make it. It is utilized in the Jordan Valley and is from the Dead Sea. The mineral bischofite (MgCl26H2O) is extracted by solution mining from ancient seabeds like the Zechstein seabed in northwest Europe. Some deposits are a result of the high magnesium chloride content of the primordial ocean. Saltwater evaporation causes a little quantity of magnesium chloride to be created.

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20 billion tons of carbon (as carbon dioxide) are released into the air each year. So option c. is the correct answer.

Each year, human actions release more carbon dioxide into the atmosphere than natural cycles can deduct, resulting in the quantity of carbon dioxide in the atmosphere inflating. The global average carbon dioxide forms a new record high in 2021: 414.72 parts per million. Carbon dioxide concentrations are rising primarily because of the fossil fuel that people are burning for energy.

Fossil fuels like coal and oil contain carbon that plants removed out of the atmosphere through photosynthesis over multiple millions of years; we are reciprocating that carbon to the atmosphere in merely a few hundred.

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As electron orbital transition a produces light with a wavelength of 690 nm, the wavelength of the light produced by transition b is 1380 nm.

The energy of a photon is inversely proportional to its wavelength, so we can use the fact that transition b involves half the energy of transition a to determine the wavelength of the light it produces.

The energy of transition b is half that of transition a, so the wavelength of the light produced by transition b will be twice that of transition a. Therefore, the wavelength of the light produced by transition b is:

Wavelength b = 2 x Wavelength a

Wavelength b = 2 x 690 nm

Wavelength b = 1380 nm

So, the wavelength of the light produced by transition b is 1380 nm.

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D. The lines connect points of equal air pressure.

Histidine is an important amino acid with an aromatic side chain that contains two nitrogens. The nitrogen in position 1 is more likely to get protonated in acid.

Under acidic circumstances, histidine's imidazole side chain can behave as a weak base and take up a proton (H+). The pKa values of the two nitrogens in the imidazole ring differ, determining which nitrogen is more likely to be protonated.

The nitrogen that is more likely to be protonated in acid is the more basic nitrogen, which is the nitrogen that is less able to share its electron pair due to its ring location. In the case of histidine, the nitrogen situated at position 1 of the imidazole ring is more basic and hence more likely to be protonated in acid.

This is because nitrogen in position 1 has a lower pKa value (about 6) than nitrogen in position 3. (around 9). This indicates that the nitrogen in position 1 is more likely to take up a proton and get protonated in acidic circumstances, whereas the nitrogen in position 3 is less likely to do so.

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A. The rate of the reaction with respect to each of the reactants and products is given by:
Rate = -1/2 Δ[N2O]/Δt = 1/2 Δ[N2]/Δt = Δ[O2]/Δt

Note that the negative sign in the rate of change of N2O is due to the fact that the concentration of N2O is decreasing with time, while the positive signs for the other two rates indicate that the concentrations of N2 and O2 are increasing with time.
B. The average rate of the reaction over the first 15.0 s can be calculated by dividing the change in the concentration of O2 by the time interval:
Average rate of reaction = Δ[O2]/Δt = (0.015 mol)/(15.0 s) = 0.001 mol/s
Note that the reaction is given in terms of moles of O2 produced, so we can directly use the change in the concentration of O2 to calculate the rate.
C. The rate of change in the concentration of N2O over the first 15.0 s can be predicted using the rate expression:
Rate = -1/2 Δ[N2O]/Δt
We can rearrange this equation to solve for the rate of change in the concentration of N2O:
Δ[N2O]/Δt = -2 × Rate
Substituting the average rate of reaction calculated in part B, we get:
Δ[N2O]/Δt = -2 × 0.001 mol/s = -0.002 mol/s
This indicates that the concentration of N2O is decreasing at a rate of 0.002 mol/s over the first 15.0 s of the reaction.


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The Ka for the weak acid is 9.14 x 10^(-6).

A weak acid is an acid that only partially dissociates in water, and its strength is described by its acid dissociation constant (Ka).

To determine the Ka for the weak acid, we can use the relationship between the Ka and the pH of the solution:

Ka = 10^(-pH) * [HA]/[A-]

where [HA] is the concentration of the undissociated weak acid and [A-] is the concentration of the conjugate base.

From the given information, we know that the pH of the solution is 2.535. This means that:

[H+] = 10^(-pH) = 10^(-2.535) = 3.62 x 10^(-3) M

Since the acid is weak, we can assume that the concentration of the undissociated weak acid ([HA]) is approximately equal to the initial concentration of the acid (0.150 M).

Next, we can use the equation for the dissociation of the weak acid:

HA + H2O ⇌ H3O+ + A-

to write an expression for the equilibrium constant (Ka):

Ka = [H3O+][A-]/[HA]

We can use the fact that the solution is electrically neutral to write:

[H3O+] = [A-] + [OH-]

where [OH-] is the concentration of hydroxide ions.

Since the acid is weak, we can assume that the concentration of hydroxide ions is much smaller than the concentration of hydronium ions, so we can approximate:

[H3O+] ≈ [A-]

Substituting these expressions into the equation for Ka, we get:

Ka = [H3O+]^2 / [HA]

Plugging in the values we have calculated, we get:

Ka = (3.62 x 10^(-3))^2 / 0.150

Ka = 9.14 x 10^(-6)

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After 2.4 hours, only 15.8% of the initial concentration of N2O5 will remain when  first-order reaction 2N2O5 -> 2N2O4 + O2 at a particular temperature. The half-life of N2O5 is 0. 90 hours.

The first-order reaction 2N2O5 -> 2N2O4 + O2 has a rate constant k that can be determined using the half-life of N2O5. The half-life of a first-order reaction is given by the equation:

t1/2 = ln(2) / k

where t1/2 is the half-life and ln is the natural logarithm.

Substituting the given half-life of 0.90 hours into this equation, we can solve for the rate constant k:

0.90 = ln(2) / k

k = ln(2) / 0.90

k = 0.77 / hour

Now we can use the integrated rate law for a first-order reaction to determine the fraction of the initial concentration of N2O5 that will remain after 2.4 hours:

ln([N2O5]t/[N2O5]0) = -kt

where [N2O5]t is the concentration of N2O5 at time t, [N2O5]0 is the initial concentration of N2O5, and k is the rate constant.

We want to find [N2O5]t/[N2O5]0 when t = 2.4 hours. We know that t1/2 = 0.90 hours, so after one half-life (0.90 hours), the concentration of N2O5 will be reduced to half its initial value. After two half-lives (1.80 hours), the concentration will be reduced to one quarter of its initial value, and so on. We can use this information to determine that 2.4 hours is equal to 2.67 half-lives:

2.4 hours / 0.90 hours per half-life = 2.67 half-lives

Substituting this value into the integrated rate law, we get:

ln([N2O5]t/[N2O5]0) = -kt

ln([N2O5]t/[N2O5]0) = -(0.77 / hour) x (2.4 hours)

ln([N2O5]t/[N2O5]0) = -1.85

Taking the antilogarithm of both sides, we get:

[N2O5]t/[N2O5]0 = e^-1.85

[N2O5]t/[N2O5]0 = 0.158

Therefore, after 2.4 hours, only 15.8% of the initial concentration of N2O5 will remain.

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Answer:

Explanation:

The acceleration can be calculated using the following formula:

acceleration = (final velocity - initial velocity) / time

In this case:

acceleration = (3 m/s - 15 m/s) / 2 seconds = -6 m/s^2

So the horse slows down with an acceleration of -6 meters per second squared. Note that the negative sign indicates that the direction of the acceleration is opposite to the direction of motion.