The Solution:
Given:
Let the unknown number be y.
Three times the sum of a number and 9 equals 8.
Putting the above statement in equation form, we get:
[tex]3(y+9)=8[/tex]Therefore, the correct answer is:
[tex]3(y+9)=8[/tex][tex]3(y+9)=8[/tex]You need to ride an average of at least 35 miles per day for five consecutive days toqualify for a cross-country biking expedition. The distances (in miles) of your rides in thefirst four days are 45, 33, 27, and 26. What distances on the fifth day will allow you toqualify for the competition?
We are to maintain a constant mean distance of ( d-avg ) to qualify for the cross-country biking expedition.
The qualification for the expedition is to rirde an average distance of:
[tex]d_{avg}\text{ }\ge\text{ 35 miles each for 5 consecutive day }[/tex]We are already on target for 4 days. For which we covered a distance ( d ) for each day:
[tex]\begin{gathered} \text{\textcolor{#FF7968}{Day 1:}}\text{ 45 miles} \\ \text{\textcolor{#FF7968}{Day 2:}}\text{ 33 miles} \\ \text{\textcolor{#FF7968}{Day 3:}}\text{ 27 miles} \\ \text{\textcolor{#FF7968}{Day 4: }}\text{26 miles} \end{gathered}[/tex]We are to project how much distance we must cover atleast on the fifth day ( Day 5 ) so that we can qualify for the expedition. The only condition for qualifying is given in terms of mean distance traveled over 5 days.
The mean value of the distance travelled over ( N ) days is expressed mathematically as follows:
[tex]d_{avg}\text{ =}\sum ^N_{i\mathop=1}\frac{d_i}{N}[/tex]Where,
[tex]\begin{gathered} d_i\colon Dis\tan ce\text{ travelled on ith day} \\ N\colon\text{ The total number of days in consideration} \end{gathered}[/tex]We have the data available for the distance travelled for each day ( di ) and the total number of days in consideration ( N = 5 days ). We will go ahead and used the standard mean formula:
[tex]d_{avg}\text{ = }\frac{d_1+d_2+d_3+d_4+d_5}{5}[/tex]Then we will apply the qualifying condtion to cover atleast 35 miles for each day for the course of 5 days.
[tex]\frac{45+33+27+26+d_5}{5}\ge\text{ 35}[/tex]Then we will solve the above inequality for Day 5 - (d5) as follows:
[tex]\begin{gathered} d_5+131\ge\text{ 35}\cdot5 \\ d_5\ge\text{ 175 - 131} \\ \textcolor{#FF7968}{d_5\ge}\text{\textcolor{#FF7968}{ 44 miles}} \end{gathered}[/tex]The result of the above manipulation shows that we must cover a distance of 44 miles on the 5th day so we can qualify for the expedition! So the range of distances that we should cover atleast to qualify is:
[tex]\textcolor{#FF7968}{d_5\ge}\text{\textcolor{#FF7968}{ 44 miles}}[/tex]All covered distances greater than or equal to 44 miles will get us qualified for the competition!
Han spent a total of $221.76, before tax, on bags of chips for the basketball team, and each bag cost $3.52. What is the total number of bags of chips that Han bought?
Given:
a.) Han spent a total of $221.76, before tax, on bags of chips for the basketball team.
b.) Each bag cost $3.52.
Let's determine the number of bags of chips bought.
[tex]\text{ No. of bags of chips bought = }\frac{\text{ Total cost}}{\text{ Price of each bag}}[/tex][tex]\text{ = }\frac{\text{ 221.76}}{\text{ 3.52}}[/tex][tex]\text{ = 63}[/tex]Therefore, Han bought 63 bags of chips for the basketball team.
The answer is 63.
Spongebob was trying to fill up Gary's bath with water. He noticed the tub filled up 1 gallon per minute.AContinuousBDiscrete
given data:
Spongebob was trying to fill up Gary's bath with water. He noticed the tub filled up 1 gallon per minute.
to find what kind of data this is.
it is discrete because it is measurable. that is countiuse while countable.
Thus the answer is discrete.
I just need to know the answer to question 11
Answer:
A number line a closed circle on 8, shading to the left, and a closed circle on 11, shading to the right.
Explanation:
Given the compound inequalities:
[tex]x-1\le7\text{ or }2x\ge22[/tex]First, solve both inequalities:
[tex]\begin{gathered} x-1\le7\implies x\le7+1\implies x\le8 \\ 2x\ge22\implies x\ge\frac{22}{2}\implies x\ge11 \end{gathered}[/tex]Thus, the number line should be the one that represents the solution:
[tex]x\le8\text{ or }x\ge11[/tex]• For x≤8, there is a ,closed circle on 8, and ,shading to the left.
,• For x≥11, there is a ,closed circle on 11, and ,shading to the right.
Therefore, the correct description will be:
A number line a closed circle on 8, shading to the left, and a closed circle on 11, shading to the right.
The last option is correct.
Classify the polynomial as constant, linear, quadratic, cubic, or quartic, anddetermine the leading term, the leading coefficient, and the degree of thepolynomial.g(x) = - 2x^4 - 6
Given:
[tex]g(x)=-2x^4-6[/tex]To classify: The polynomial name, degree, leading term, and leading coefficient
Explanation:
Since the degree of the polynomial is the highest or the greatest power of a variable in a polynomial equation.
Here, 4 is the greatest power of a variable x.
So, the degree of the polynomial is 4.
As we know,
The leading term is the term containing the highest power of the variable.
So, the leading term is,
[tex]-2x^4[/tex]Since the coefficient of the term of the highest degree in a given polynomial is -2.
So, the leading coefficient is -2.
Since the degree of the polynomial is 4.
So, the given polynomial is a quartic polynomial.
Final answer: Option C. Quartic polynomial.
y varies directly as x. y =84 when x=6. Find y when x=12y= ?
If y varies directly as x, we have that
[tex]y\propto x[/tex]Then
[tex]y=kx(where\text{ k is a constant\rparen}[/tex][tex]\begin{gathered} When\text{ y=84 , x= 6} \\ y=kx \\ 84=6k \\ k=\frac{84}{6}=14 \end{gathered}[/tex]The relationship between x and y is given as
[tex]\begin{gathered} y=kx \\ y=14x \end{gathered}[/tex]Therefore when x= 12, y=?
[tex]\begin{gathered} y=14x \\ y=14\times12=168 \end{gathered}[/tex]Hence, the value of y when x = 12 is 168
Final answer: y = 168
Graph the line. I am only able to use 2 points on this graph.
In order to graph line first we need to calculate the equation of the line
[tex]y-y_1=m(x-x_1)[/tex]where m is the slope and (x1,y1) is a line where the line passing throught
in our case
m=3/4
(x1,y1)=(-4,5)
[tex]y-5=\frac{3}{4}(x+4)[/tex]Then we isolate the y
[tex]y=\frac{3}{4}x+3+5[/tex][tex]y=\frac{3}{4}x+8[/tex]We can calculate another point to obtain the graph in this case the y-intercept (0,8)
The points are
(-4,5) and (0,8)
the graph is
consider the relationship between f(x)=2^x and g(x)=log2 x.g is a reflection of f over the line y=x.True or False
the function
[tex]\log _2x[/tex]is the inverse function of
[tex]2^x^{}[/tex]On the graph, the inverse of a function is the reflection of the original function over the line y = x. Then, the statement is true
Use the drawing tool(s) to form the correct answer on the provided graph.
Graph the solution to this system of inequalities in the coordinate plane.
3y>2x + 122x + y ≤ -5Having trouble rewriting in form. Graphing once in form okay.
Explanation
We are given the following system of inequalities:
[tex]\begin{gathered} 3y>2x+12 \\ 2x+y\leqslant-5 \end{gathered}[/tex]We are required to graph the given system of inequalities.
This is achieved thus:
- First, we determine two coordinates from the given inequalities:
[tex]\begin{gathered} 3y>2x+12 \\ \text{ Suppose }3y=2x+12 \\ \text{ Let x = 0} \\ 3y=12 \\ y=4 \\ Coordinate:(0,4) \\ \\ \text{Suppose }3y=2x+12 \\ \text{ Let y = 0} \\ 0=2x+12 \\ 2x=-12 \\ x=-6 \\ Coordinate:(-6,0) \end{gathered}[/tex]- Now, we plot the points on a graph. Since the inequality is "strictly greater than", the line drawn will be broken. The graph is shown below:
- Using the second inequality, we have:
[tex]\begin{gathered} 2x+y\leqslant-5 \\ \text{ Suppose }2x+y=-5 \\ \text{ Let y = 0} \\ 2x=-5 \\ x=-2.5 \\ Coordinate:(-2.5,0) \\ \\ \text{Suppose }2x+y=-5 \\ \text{ Let x = 0} \\ y=-5 \\ Coordinate:(0,-5) \end{gathered}[/tex]The graph becomes:
Combining both graphs, we have the solution to be:
The solution is the intersection of both graphs as indicated above.
Write the STANDARD FORM of the equation through the point (4,-4) witha slope of -2.
The general equation of line with the slope "m" and passing points (a,b) is :
y - b = m (x -a)
In the given question:
Slope m = -2, passing points (a,b) = (4,-4)
Substitute the value of a = 4, b = -4 in the general equation of line
[tex]\begin{gathered} y-b=m(x-a) \\ y-(-4)=(-2)(x-4) \\ y+4=-2(x-4) \\ y+4=-2x+8 \\ y+2x=8-4 \\ 2x+y=4 \end{gathered}[/tex]The equation with the slope -2 and passing points (4,-4) is 2x + y = 4
Answer : 2x + y = 4
i need help with question 2
To find the vertex (h,k), we have to find h using the following formula
[tex]h=-\frac{b}{2a}[/tex]Where a = 1 and b = -10.
[tex]h=-\frac{-10}{2\cdot1}=5[/tex]Then, we find k by evaluating the function when x = 5.
[tex]y=5^2-10\cdot5+9=25-50+9=-16[/tex]Hence, the vertex is (5,-16).The axis of symmetry is given by the h coordinate of the vertex.
Hence, the axis of symmetry is x = 5.The y-intercept is found when x = 0.
[tex]y=0^2-10\cdot0+9=9[/tex]The y-intercept is (0,9).The x-intercepts are found when y = 0.
[tex]x^2-10x+9=0[/tex]To solve this expression, we have to look for two numbers which product is 9, and which addition is 10. Those numbers are 9 and 1.
[tex](x-9)(x-1)=0[/tex]Then, we use the zero product property to express both solutions
[tex]\begin{gathered} x-9=0\rightarrow x=9 \\ x-1=0\rightarrow x=1 \end{gathered}[/tex]Hence, the x-intercepts are (9,0) and (1,0).The minimum value is defined by the k coordinate of the vertex.
Therefore, the minimum value of the function is -16.The domain of the function would be all real numbers because quadratic functions don't have any domain restrictions.
[tex]D=(-\infty,\infty)[/tex]The range of the function is determined by the vertex, given that the parabola opens upwards, then the range is
[tex]R\colon\lbrack-16,\infty\rbrack[/tex]Use elimination to solve eachsystem of equations3x - y = -56x - 2y = 8
Solution
We are given the pair of simultaneous equation
[tex]\begin{gathered} 3x-y=-5\ldots\ldots\ldots\ldots\ldots(1) \\ 6x-2y=8\ldots\ldots\ldots\ldots\ldots\ldots(2) \end{gathered}[/tex]we solve using elimination method
equation (1) x 2
[tex]\begin{gathered} 6x-2y=-10\ldots\ldots\ldots\ldots\ldots(1) \\ 6x-2y=8\ldots\ldots\ldots\ldots\ldots\ldots(2) \end{gathered}[/tex]Equation (2) - equation (1)
We have
[tex]\begin{gathered} (6x-6x)+(-2y+2y)=8-(-10) \\ 0=18 \end{gathered}[/tex]Which is impossible because 0 (zero) can never be equal to 18
Therefore, the simultaneous is not consistent or it degenerate and thus, there is no solution
how to answer this system of equations using cramer's rule
Given:
Given the system of equations:
[tex]\begin{gathered} c+w+p=456 \\ c-p=80 \\ p=2w-2 \end{gathered}[/tex]Required: Solution of the system using Cramer's rule
Explanation:
The system of equations can be rewritten as
[tex]\begin{gathered} c+p+w=456 \\ c-p+0w=80 \\ 0c+p-2w=-2 \end{gathered}[/tex]Write down the augmented matrix.
[tex]\begin{bmatrix}{1} & {1} & {1} & {456} \\ {1} & {-1} & {0} & {80} \\ {0} & {1} & {-2} & {-2} \\ {} & {} & {} & {}\end{bmatrix}[/tex]Calculate the main determinant.
[tex]\begin{gathered} D=\det\begin{bmatrix}{1} & {1} & {1} \\ {1} & {-1} & {0} \\ {0} & {1} & {-2}\end{bmatrix} \\ =1\left(2-0\right)-1\left(-2-1\right) \\ =2+3 \\ =5 \end{gathered}[/tex]Substitute the c-column with RHS and find the determinant.
[tex]\begin{gathered} D_c=\det\begin{bmatrix}{456} & {1} & {1} \\ {80} & {-1} & {0} \\ {-2} & {1} & {-2}\end{bmatrix} \\ =456\left(2-0\right)-80\left(-2-1\right)-2\left(0+1\right) \\ =912+240-2=1150 \end{gathered}[/tex]Substitute the p-column with RHS and find the determinant.
[tex]\begin{gathered} D_p=\det\begin{bmatrix}{1} & {456} & {1} \\ {1} & {80} & {0} \\ {0} & {-2} & {-2}\end{bmatrix} \\ =1(-160-0)-1(-912+2) \\ =-160+910 \\ =750 \end{gathered}[/tex]Substitute the w-column with RHS and find the determinant.
[tex]undefined[/tex]write a part to part and a part to whole ratio for each problem situation of the 31 students surveyed 19 prefer white bread and the remaining students prefer wheat bread
Total number of students = 31
19 prefer white bread
31 - 19 prefer wheat bread ==> 31- 19 = 12 prefer wheat bread
Relations:
Part to part:
Relation between the number of students that prefer wheat bread to the number of students that prefer white bread:
Ratio: 12/19
Part to part:
Relation between the number of students that prefer white bread to the number of students that prefer white bread:
Ratio: 19/12
Part to whole:
Relation between the number of students that prefer wheat bread to the total number of students:
Ratio: 12/31
Part to whole:
Relation between the number of students that prefer white bread to the total number of students:
Ratio: 19/31
The rectangular rug has side lengths of 3 and 4 ft. What is the length of the diagonal? Draw a picture of the problem and solve. Round to the nearest tenth
ANSWER
The length of the diagonal is 5 ft
EXPLANATION
The diagram of the rug with the diagonal is:
The diagonal and the sides form a right triangle, so we can use the Pythagorean theorem to find x, the length of the diagonal:
[tex]\begin{gathered} x^2=3^2+4^2 \\ x=\sqrt[]{9+16} \\ x=\sqrt[]{25} \\ x=5 \end{gathered}[/tex]In a isosceles triangle one angle is 57° greater than each of the other two equal angles. find a measure of all three angles
An Isosceles triangle has two sides and two angles to be congruent or equal.
Let the two congruent angles be x° degrees, then the third side which is 57° greater than the congruent angles would measure (x+57°).
SKETCH
The sum of angles in a triangle is 180°. Hence,
[tex]\begin{gathered} x+x+(x+57)=180^0 \\ 3x+57=180^0 \\ 3x=180-57 \\ 3x=123 \\ x=\frac{123}{3} \\ x=41^0 \\ \therefore(x+57)=41^0+57^0=98^0 \end{gathered}[/tex]Therefore, the measure of all three angles are: 41,⁰ 41⁰, and 98⁰
An employee makes $10.51 per hour but is getting a 3% increase. What is his new wage per hour to the nearest cent?
First, we find 3% of $10.51.
[tex]0.03\cdot10.51=0.32[/tex]Then, we add this increase to $10.51.
[tex]10.51+0.32=10.83[/tex]Hence, the new wage per hour is $10.83.simplify: 9x^4-27x^6/3x^3
simplify: 9x^4-27x^6/3x^3
we have the expression
[tex]\begin{gathered} 9x^4-\frac{27x^6}{3x^3} \\ \\ 9x^4-9x^{(6-3)} \\ 9x^4-9x^3 \end{gathered}[/tex]we have the expression
[tex]\begin{gathered} \frac{9x^4-27x^6}{3x^3} \\ \frac{9x^4}{3x^3}-\frac{27x^6}{3x^3} \\ 3x-9x^3 \end{gathered}[/tex]this is the answer
Find the solution for the given the system of equations:Y= (1/2)x - 1/2 and y=2^(x+3)
Answer:
This system has no solution.
Step-by-step explanation:
The solution of this system is the ordered pair that is the solution to both equations, we can solve this using the graphical method, which consists of graphing both equations in the same coordinate system.
The solution to the system will be at the point where the two functions intersect.
Since the functions do not intersect, this system has no solution.
On Monday, Freda spent $20 to buy 3 burgers and 4 orders of fries for her friends to share for lunch. Let r represent the cost of a burger and y represent the cost of an order of fries. What linear equation would model this?
Let:
r = Cost of a burger
y = Cost of an order of fries
Freda spent $20 to buy 3 burgers and 4 orders of fries for her friends to share for lunch, therefore:
[tex]3r+4y=20[/tex]Lola has 8 bear figurines. These bear figurines make up 40% of her collection of animal figurines. Find the total number
Hence, the total number of bear figurines are 20
Use a properly of equality to solve this equation: 4.5x = 18
To solve the equation you can use the property of the multiplicative inverse, like this
[tex]\begin{gathered} 4.5x=18 \\ \frac{1}{4.5}\cdot4.5x=18\cdot\frac{1}{4.5} \end{gathered}[/tex]Dividing by 4.5 into both sides of the equation is the same as multiplying by the multiplicative inverse of 4.5 on both sides of the equation
[tex]x=\frac{18}{4.5}[/tex]Therefore,
[tex]x=4[/tex]Which function is undefined for x = 0?O y=³√x-2Oy=√x-2O y=³√x+2Oy=√x+2
The above function is defined for (x=0)
From the question, we have
Function 1 - y = ∛x-2
Function 2 - y = √x-2
Function 3 - y = ∛x+2
Function 4 - y = √x+2
substituting (x = 0) to determine which function is undefined for (x = 0).
Function 1 - y = ∛x-2
substituting (x = 0), we get
y=∛-2
The above function is defined for (x=0).
Function 2 - y = √x-2
substituting (x = 0), we get
y = √-2
The above function is defined for (x=0).
Function 3 - y = ∛x+2
substituting (x = 0), we get
y = ∛2
The above function is defined for (x=0).
Function 4 - y = √x+2
substituting (x = 0), we get
y = √2
The above function is defined for (x=0).
Hence, it can be concluded that the above function is defined for (x=0)
Subtraction:
Subtraction represents the operation of removing objects from a collection. The minus sign signifies subtraction −. For example, there are nine oranges arranged as a stack (as shown in the above figure), out of which four oranges are transferred to a basket, then there will be 9 – 4 oranges left in the stack, i.e. five oranges. Therefore, the difference between 9 and 4 is 5, i.e., 9 − 4 = 5. Subtraction is not only applied to natural numbers but also can be incorporated for different types of numbers.
The letter "-" stands for subtraction. Minuend, subtrahend, and difference are the three numerical components that make up the subtraction operation. A minuend is the first number in a subtraction process and is the number from which we subtract another integer in a subtraction phrase.
To learn more about subtraction visit: https://brainly.com/question/2346316
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Brenda received a gift card for an internet cafe. The cost,y, of renting a computer and using it for x hours at the cafe is shown in the graph below. Which equation represents the same relationship as the graph?
In order to find the equation of the graph, we need to get two points on the graph.
Two points on the graph are points (2, 24) and (4, 33)
The next step is to find the slope of the graph, using the two points above
[tex]\begin{gathered} \text{ slope, m = }\frac{y_2-y_1}{x_2-x_1} \\ \text{ (x}_1,y_1)=(2,24)_{} \\ (x_2,y_{2_{}})=(4,\text{ 33)} \\ m=\frac{33-24}{4-2} \\ m=\frac{9}{2} \\ m=4.5 \end{gathered}[/tex]Then, using slope and one point formula, find the equation of the line
[tex]\begin{gathered} \text{ y-y}_1=m(x-x_1) \\ m=\text{ 4.5, (x}_1,y_1)=(2,24) \\ y-24=4.5(x-2) \\ y-24=4.5x-9 \\ y=4.5x-9+24 \\ y=4.5x+15 \end{gathered}[/tex]The correct answer is y= 4.5x + 15
Consider the following function. Complete parts (a) through (e) below.f(x)=x²-2x-8The vertex is.(Type an ordered pair.)c. Find the x-intercepts. The x-intercept(s) is/are(Type an integer or a fraction. Use a comma to separate answers as needed.)d. Find the y-intercept. The y-intercept is(Type an integer or a fraction.)e. Use the results from parts (a)-(d) to araph the quadratic function.
Given the function:
[tex]f(x)=x^2-2x-8[/tex]It is a quadratic function where:
a=1
b= -2
c= -8
The x-coordinate of the vertex is given by:
[tex]x=-\frac{b}{2a}[/tex]Substitute a and b:
[tex]x=-\frac{-2}{2(1)}=\frac{2}{2}=1[/tex]Substituting in the original equation to obtain the y-coordinate, we obtain:
[tex]y=(1)^2-2(1)-8=1-2-8=-9[/tex]So, the vertex is (0, -9)
c. For the intercept at x we make y = 0:
[tex]0=x^2-2x-8[/tex]And solve for x by factorization:
[tex]\begin{gathered} (x-4)(x+2)=0 \\ Separate\text{ the solutions} \\ x-4=0 \\ x-4+4=0+4 \\ x=4 \\ and \\ x+2=0 \\ x+2-2=0-2 \\ x=-2 \end{gathered}[/tex]So, the x-intercepts are:
(-2, 0) and (4,0)
Answer: (-2,0), (4,0)
d. For the intercept at y we make x = 0:
[tex]y=(0)^2-2(0)-8=-8[/tex]So the y-intercept is (0, -8)
Answer: (0, -8)
e. Graphing the function:
Find the volume of this cone.Use 3 for TT.V = Tigh3Hint: The radius (1) is1/2 of the diameter.6 ft6 ft-3V ~ [?]ft
ANSWER
[tex]54ft^3[/tex]EXPLANATION
The volume of a cone is given by:
[tex]V=\frac{\pi r^2h}{3}[/tex]where r = radius
h = height
The height of the given cone is 6 ft and its diameter is 6 ft. The radius of a cone is half its diameter, hence its radius is:
[tex]\begin{gathered} r=\frac{6}{2} \\ r=3ft \end{gathered}[/tex]Hence, the volume of the cone is:
[tex]\begin{gathered} V=\frac{3\cdot3^2\cdot6}{3} \\ V=54ft^3 \end{gathered}[/tex]That is the answer.
Pls help now You play a game that requires rolling a 6 sided die then randomly choosing a colored card from a deck containing 5 red cards,4blue cards, and 8 yellow cards find the probability that you will roll 3 on the die and choose a yellow card
Find the probability that you will get a 3 on a roll of a die. Since there is only one 3 in a die and there are 6 sides in a die, divide 1 by 6.
[tex]P(3)=\frac{1}{3}[/tex]Find the probability that you will get a yellow card. Divide the number of yellow cards by the total number of cards.
[tex]\begin{gathered} P(y)=\frac{8}{5+4+8} \\ =\frac{8}{17} \end{gathered}[/tex]Since the two events are independent, multiply the obtained probabilities.
[tex]undefined[/tex]The recommended daily allowance of niacin for adults is 20 mg. One serving of a certain breakfast cereal provides 8 mg of niacin, What percent of the recommendeddaily allowance of niacin does one serving of this cereal provide?
Given:
Total allowance = 20mg.
Used = 8 mg
Percentage of daily allowance is:
[tex]\begin{gathered} =\frac{8}{20}\times100 \\ =\frac{8}{2}\times10 \\ =8\times5 \\ =40 \end{gathered}[/tex]So 40% daily allowance .
Use the Pythagorean Theorem to find the length of the unknown side in the righttriangle shown below. (Round your answer to the nearest tenth.)817
pythagorean theorm is a^2 + b^2 = c^2
side lengths 8 and 17
8 is a base and 17 is the hypotenuse, the other side is 15
8 15 17 is one of the first 10 Pythagorean triples
8^2 + 15^2 = 17^2
64 + 225 = 289
289 = 289
What is the greatest common factor of the polynomial: 35y + 5y + 157 "
The greatest common factor of the expression is:
[tex]5y^3[/tex]This comes from the fact that 5 is the greatest common factor of the constants, whereas y^3 is the greatest common factor of the variable.
