Triangle A is rotated 90° about the origin. Which triangle shows the image?

Triangle A Is Rotated 90 About The Origin. Which Triangle Shows The Image?

Answers

Answer 1

Rotation 90° about the origin.

First, choose a point from triangle A.

For example: (-2,2)

For any point (x,y) rotated 90° =(-y,x)

So:

(-2,2) becames = (-2,-2)

Triangle D


Related Questions

Can You Teach Me How To Multiple Fractions ?

Answers

Let's suppose we are given two fractions:

[tex]\frac{a}{b},\frac{c}{d}[/tex]

In order to multiply them we simply multiply the numerators and denominators, like this:

[tex]\frac{a}{b}\times\frac{c}{d}=\frac{a\times c}{b\times d}[/tex]

For example, let's say we are given the following fractions:

[tex]\frac{1}{2},\frac{3}{5}[/tex]

We can multiply them following the previous rule:

[tex]\frac{1}{2}\times\frac{3}{5}=\frac{1\times3}{2\times5}=\frac{3}{10}[/tex]

how do I solve (4w+3x+5)-(4w-3x+2)

Answers

Answer:

6x + 3

Explanation:

To solve the initial expression, we need to write it without the parenthesis as:

( 4w + 3x + 5 ) - ( 4w - 3x + 2)

4w + 3x + 5 - 4w + 3x - 2

Then, we need to identify the like terms as:

4w and -4w are like terms

3x and 3x are like terms

5 and -2 are like terms

Now, we can organize the terms as:

4w - 4w + 3x + 3x + 5 - 2

Adding like terms, we get:

(4w - 4w) + (3x + 3x) + (5 - 2)

0 + 6x + 3

6x + 3

Therefore, the answer is 6x + 3

Use Part Il of the Fundamental Theorem of Calculus to evaluate the definite integral

Answers

Answer:

[tex]4\ln (2)+\frac{49}{3}\approx19.1059[/tex]

Given:

[tex]\int ^{-1}_{-2}\frac{7x^5-4x^2}{x^3}dx[/tex]

Simplify:

[tex]\int \frac{7x^3-4}{x}dx[/tex]

Expand:

[tex]\int (7x^2-\frac{4}{x})dx[/tex]

Apply linearity:

[tex]7\int x^2dx-4\int \frac{1}{x}dx[/tex]

Apply power rule and the standard integral ln(x)

[tex]7(\frac{x^3}{3})-4\ln (x)[/tex]

Now, applying the Fundamental Theorem of Calculus Part 2

[tex]\int ^{-1}_{-2}\frac{7x^5-4x^2}{x^3}dx=(7(\frac{(-1)^3}{3})-4\ln (-1))-(7(\frac{(-2)^3}{3})-4\ln (-2))[/tex][tex]=4\ln (2)+\frac{49}{3}[/tex]

Or approximately

[tex]\approx19.1059[/tex]

im confused on premtier

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we have to calculate the perimeter of the semicircle which radius is 16 mm

[tex]P_{sc}=\frac{2\pi\cdot r}{2}=\pi\cdot r=16\pi\approx50.26\operatorname{mm}[/tex]

Now we have to add the outter sides of the triangle

[tex]P=20+20+50.26=90.26\operatorname{mm}[/tex]

What is the seventy-seven is forty-six more than r

Answers

Answer: 77 = 46 + r, r = 31

Step-by-step explanation:

      We will write an equation to represent this situation. Then, we will solve for r by isolating the variable.

  Seventy-seven is forty-six more than r.

77 is forty-six more than r.

77 = forty-six more than r.

77 = 46 more than r.

  77 = 46 + r

  77 = 46 + r

(77) - 46 = (46 + r) - 46

31 = r

  r = 31

i need help, im confused

Answers

Answer:

2

Step-by-step explanation:

use prowers and multiplication to write the equation whose value is 10 to the 11th power

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if we have

(10^9)(10^2)

adds the exponents

10^(9+2)

10^11

If you have

10^18/ 10^7

subtract the exponents

10^(18-7)

10^11

If you have

(10^6)^2/10

First multiply the exponents

10^(6*2)/10

10^12/10

subtract exponents

10^(12-1)

10^11

Please help this is due tomorrow!!

Answers

The expression 2x⁷· y⁴ would be equivalent to the given polynomial expression.

What is a polynomial?

A polynomial is defined as a mathematical expression that has a minimum of two terms containing variables or numbers. A polynomial can have more than one term.

The given polynomial expression below is:

⇒ 10x⁵y⁷/5x⁵y · 3x⁴y⁸/3x⁻³y¹⁰

Apply the division operation in the constant terms

⇒ 2x⁵y⁷/x⁵y · x⁴y⁸/x⁻³y¹⁰

Apply the arithmetic operation in the Exponents of the same base variables

⇒ 2y⁶ · x⁷y⁻²

⇒ 2y⁶⁻² · x⁷

⇒ 2y⁴ · x⁷

⇒ 2x⁷· y⁴

Therefore, the expression 2x⁷· y⁴ would be equivalent to the given polynomial expression.

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I'm graphing and I need to find out how mutch it costs for 4.5 inches of the construction. and the construction is $25.50 per inch

Answers

You have to determine the cost for 4.5 inches of the construction using the graph.

The height is on the y-axis, and the cost is on the x-axis.

First, locate 4.5 in the y-axis, which is the value in the midpoint between 4 and 5.

Draw a horizontal line until you intersect with the line, then draw a vertical line from the function until the x-axis:

The line crosses the x-axis at the midpoint between values 102 and 127.5 to determine the value at this point you have to average both costs:

[tex]\frac{127.5+102}{2}=\frac{229.5}{2}=114.75[/tex]

The cost of 4.5 inches of construction is $114.5

Please look at the image below. By the way this is my homework.Use the definition of congruence to decide whether the two figures are congruent. Explain your answer. Give coordinate notation for the transformations you use.

Answers

Congruent Shapes

Two congruent shapes have the same size and shape, which means all of their side lengths are equal and all of their internal angles are congruent (have the same measure),

All of the rigid transformations map the original figure to a congruent figure. One of the transformations is the reflection.

The image shows two shapes SRQP and EDCB. They seem to have the same shape and size, but it must be proven by finding the appropriate transformation used.

Comparing the corresponding vertices we can find that out. For example, the coordinates of S are (-6,4) and the coordinates of E are (4,4). The x-coordinate of the midpoint between them is

xm = (-6+4)/2 = -1

Now analyze the points P(-8,2) and B(6,2). The x-coordinate of the midpoint is:

xm = (-8+6)/2 = -1

For the points R(-4,-6) and D(2,-6):

xm = (-4+2)/2 = -1

For the points Q(-9,-4) and D(8,-4):

xm = (-9+8)/2 = -0.5

Since this last pair of corresponding points don't have the same axis of symmetry as the others, the shapes don't have the same size and angles, thus they are not congruent

For both shapes to be congruent, the coordinates of Q should have been (-10,-4)

The cost C (in dollars) of producing x units of a product is given by the following. C= 2.6. Square root of x + 600

Answers

The marginal cost in dollars of producing x units is given by the next equation:

[tex]C=2.6\sqrt[]{x}+600[/tex]

a)

To find the marginal cost (in dollars per unit) when x= 9.

Then, we need to replace x=9 on the derivation of the cost equation:

So:

[tex]\frac{d}{dx}C=\frac{1.3}{\sqrt[]{x}}[/tex]

Where:

[tex]\frac{d}{dx}2.6\sqrt[]{x}=2.6\frac{d}{dx}\sqrt[]{x}=2.6\frac{d}{dx}^{}x^{\frac{1}{2}}=2.6\cdot\frac{1}{2}x^{\frac{1}{2}-1}=1.3\cdot x^{-\frac{1}{2}}=\frac{1.3}{\sqrt[]{3}}[/tex]

and, the derivate of a constant is equal to zero.

[tex]\frac{d}{dx}600=0[/tex]

Replacing x= 9

[tex]\frac{d}{dx}C=\frac{1.3}{\sqrt[]{9}}[/tex]

Hence, the marginal cost is equal to:

[tex]\frac{d}{dx}C=0.43[/tex]

b) Now, when the production increases 9 to 10. It's the same as the cost of producing one more machine beyond 9.

Then, it would be x=10 on the cost equation:

[tex]C=2.6\sqrt[]{x}+600[/tex][tex]C=2.6\sqrt[]{10}+600[/tex][tex]C=608.22[/tex]

and x= 9

[tex]C=2.6\sqrt[]{9}+600[/tex][tex]C=2.6(3)+600[/tex][tex]C=607.8[/tex]

Then, we calculate C(10) - C(9) =

[tex]608.22-607.8[/tex][tex]=0.43[/tex]

C)

Both results are equal.

Hence, the marginal cost when x=9 is equal to the additional cost when the production increases from 9 to 10.

use accounting principles to find the number of outcomes: How many ways can Mark create a 4-digitcode for his garage door opener?

Answers

To creat a 4 - digit code, we need to consider that for each digit we have 10 options:

0, 1, 2, 3, 4, 5, 6, 7, 8, 9 -----> 10 options for each digit.

Next, we multiply the number of options we have for each digit. In this case, since we need the code to have 4 digits:

[tex]10\times10\times10\times10[/tex]

We multiply 4 times 10.

And the result is:

[tex]10\times10\times10\times10=10,000[/tex]

He has 10,000 ways to create a 4-digit code.

Swine Flu is attacking Springfield. The function below determines how many people have swine where t=time in days and S=the number of people in thousands.

Answers

[tex]s(t)=9t-4[/tex]

A.find s(4)

[tex]\begin{gathered} s(4)=9(4)-4 \\ s(4)=36-4 \\ s(4)=32 \end{gathered}[/tex]

B. means that in 4 days there will be 32000 infected people

C. find t to S(t)=23

[tex]\begin{gathered} 23=9t-4 \\ 9t=23+4 \\ t=\frac{27}{9} \\ t=3 \end{gathered}[/tex]

D. means there will be 23,000 infected people after 3 days

E. Graph

to draw the line we need two points which we already have but we will add another to make a table of 3 values the new value is t=1

[tex]\begin{gathered} s(1)=9(1)-4 \\ s(1)=5 \end{gathered}[/tex]

table

graph

George filled up his car with gas before embarking on a road trip across the country. The capacity of George's gas tank is 12 gallons and her car uses 2 gallons of gas for every hour driven. Make a table of values and then write an equation for G, in terms of t, representing the number of gallons of gas remaining in George's gas tank after t hours of driving.

Answers

Given that the capacity of George's gas tank is 12 gallons and her car uses 2 gallons of gas for every hour driven.

[tex]\begin{gathered} G_{\circ}=12 \\ m=-2 \end{gathered}[/tex]

slope m is negative since the gas is reducing every hour.

Writing the equation for G, in terms of t, representing the number of gallons of gas remaining in George's gas tank after t hours of driving.​

[tex]\begin{gathered} G=G_{\circ}+mt \\ G=12+(-2)t \\ G=12-2t \end{gathered}[/tex]

The equation for G is;

[tex]G=12-2t[/tex]

Calculating the number of gallons remaining in the tank after 0,1,2 and 3 hours, we have;

[tex]\begin{gathered} G=12-2t \\ at\text{ t=0}; \\ G_0=12-2(0)=12 \\ at\text{ t=1}; \\ G_1=12-2(1)=10 \\ at\text{ t=2}; \\ G_{2_{}}=12-2(2)=12-4=8 \\ at\text{ t=3;} \\ G_3=12-2(3)=12-6=6 \end{gathered}[/tex]

Completing the table, we have;

justify proposes each step

Answers

the answer is associative property of multiplicaction

because

A*(B*C)=(A*B)*C

How does basic algebra come to play in everyday life? Explain (or give examples) in at least two sentences

Answers

Explanation

1) Algebra can be used while cooking to estimate the amount of ingredients by solving some easy algebraic expressions of the head.

e.g 2 tea spoons of pepper out of a 1kg pack might be the right amount to spice a soup.

2) For example, a plumber may do some quick calculations to determine the number of pipes required for a house

e.g 5 pipes in the bathroom, two pipes in the toilet, three in the kitchen gives 10 pipes altogether.

Find the slope of the line that passes through (8, 7) and (6, 2).

Answers

[tex]m = \frac{y2 - y1}{x2 - x1} \\ m = \frac{2 - 7}{6 - 8} \\ m = \frac{ - 5}{ - 2} \\ m = \frac{5}{2} [/tex]

ATTACHED IS THE SOLUTION WITH THE FORMULA TO CALCULATE THE SLOPE BETWEEN POINTS.

need help with excerise step by step been 20 year's

Answers

Given:

Standard deviation

[tex]\sigma=5.18[/tex]

Mean

[tex]\mu=129[/tex]

Required:

Find the longest braking distance one of these cars could have and still in the bottom.

Explanation:

The z-score formula is given as:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

Substitute the given values and find the value of z.

[tex]z=\frac{x-129}{5.18}[/tex]

This is the first percentile which is X when Z has a p-value of 0.01, so z = -2.327.

[tex]\begin{gathered} -2.327=\frac{x-129}{5.18} \\ x-129=-2.327(5.18) \\ x-129=-12.054 \\ x=129+12.054 \\ x=116.946\text{ ft} \end{gathered}[/tex]

Final answer:

The longest braking distance one of these cars could have and still in the bottom 1% is 116.946 ft.

7, -28, 112, -448, ..... as a formula

Answers

n = number

We can see that the value of each number is multiplied by 4 at each point in time

And the initial value is 7

[tex]a_n=7(4)^{n-1}[/tex]

18. Yvonne paid $18.72 for 8 gallons of gas. How much would she have spent on gas if she had only needed 5 gallons of gas?

Answers

As given by the question

There are given that $18.72 for 8 gallons of gas.

Now,

Since, $18.72 for 8 gallons of gas;

Then,

First calculate the price of one-gallon gas

So,

[tex]\frac{18.72}{8}=2.34[/tex]

The price og one g

x=-3
f(x)= -2
f’(x)=2
g(x)=3
g’(x)=-1

h(x) = g(x)/2f(x)
Find h'(-3)

Answers

Answer: [tex]-1[/tex]

Step-by-step explanation:

Using the quotient rule,

[tex]h'(x)=\frac{2f(x)g'(x)-2g(x)f'(x)}{(2f(x))^2}\\\\h'(3)=\frac{2f(3)g'(3)-2g(3)f'(3)}{(2f(3))^2}\\\\=\frac{2(-2)(-1)-2(3)(2)}{2(-2)^2}\\\\=-1[/tex]

This is a non graded practice that I am doing. I don’t under these questions 5-11

Answers

7. The intersection of two intersecting lines is a point.

In the given image, we see that lines NQ and ML intersect at point P.

Therefore, the intersection of NQ and ML is P.

The price of Stock A at 9 A.M. was ​$12.42. Since​ then, the price has been increasing at the rate of ​$0.12 each hour. At noon the price of Stock B was ​$12.92. It begins to decrease at the rate of ​$0.09 each hour. If the two rates​ continue, in how many hours will the prices of the two stocks be the​ same?

Answers

The hours when the prices of the two stocks be the same is 2.38 hours.

How to illustrate the information?

From the information, the price of Stock A at 9 A.M. was $12.42 and the price has been increasing at the rate of $0.12 each hour. This will be the expressed as 12.42 + 0.12h.

At noon the price of Stock B was $12.92. It begins to decrease at the rate of $0.09 each hour. This will be:

= 12.92 - 0.09h

where h = number of hours

Equate both equations. This will be:

12.42 + 0.12h = 12.92 - 0.09h

Collect like terms

12.92 - 12.42 = 0.12h + 0.09h

0.21h = 0.50

h = 0.50 / 0.21

h = 2.38 hours.

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The points (-6, -10) and (23, 6) form a line segment.
Write down the midpoint of the line segment.

Answers

A line segment has the endpoints at (-6, -10) and (23, 6) then the midpoints of the line segment will be (17, -2).

What is meant by line segment?

An area or portion of a line with two endpoints is called a line segment. A line segment, in contrast to a line, has a known length. A line segment's length can be estimated by utilizing either metric measurements like millimeters or centimeters, or conventional measurements like feet or inches.

A line segment has the endpoints at (-6, -10) and (23, 6).

Mid point of the line segment is given by [tex]$\left(\frac{x_1+x_2}{2}\right),\left(\frac{y_1+y_2}{2}\right)$[/tex]

The midpoints of the line segment will be

=  [tex]$\frac{23+-6}{2}[/tex], [tex]$\frac{-10+6}{2}}[/tex]

= 17, -2

Therefore midpoints of the line segment will be (17, -2).

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What is 9207 /10 equivalent to?

Answers

Answer:

9207/10 is equivalent to 920.7

I am trying to solve this equation using Synthetic Division. I got the answer wrong, I would like to see where I made a mistake.

Answers

Answer:

The result for the division is:

[tex]2x^2+43x+865+\frac{17309}{x-20}[/tex]

Explanation:

Step 1: Write the coefficients of the numerator on the right-hand side, and the opposite of the constant term in the denominator on the left-hand side.

20..............2 || 3 || 5 || 9

..................2

Step 2: Multiply 20 by 2 and add the result to 3

20..............2.......................|| 3 || 5 || 9

..................2*20 = 40

....................2 || 3 + 40 = 43

Step 3: Multiply 43 by 20, and add the result to 5

20..............2 || 3 .........................|| 5 || 9

...................... 40.......20*43 = 860

....................2||43 .......5+860=865

Step 4: Multiply 865 by 20, and add the result to 9

20..............2 || 3 || 5 ..........................|| 9

...................... 40 ||860......20*865=17300

....................2||43||865...9 + 17300=17309

The coefficients are 2, 43, 865, 17309

The quotient is:

[tex]2x^2+43x+865[/tex]

and the remainder is 17309

So, we can write:

[tex]2x^2+43x+865+\frac{17309}{x-20}[/tex]

Find the indicated quantity, given u = (4, -9), v = (-4, -7).Step 4 of 4: Find (u • v)4v.

Answers

Answer:

[tex]\begin{equation*} \langle-1316,-2303\operatorname{\rangle} \end{equation*}[/tex]

Explanation:

Given the vectors:

[tex]\begin{gathered} u=\langle4,-9\rangle \\ v=\langle-4,-7\rangle \end{gathered}[/tex]

The dot product of u and v is calculated below:

[tex]\begin{gathered} u\cdot v=4\times-4+-9\times-7 \\ =-16+63 \\ =47 \end{gathered}[/tex]

Therefore:

[tex]\begin{gathered} (u\cdot v)4v=47\times4\langle-4,-7\rangle \\ =329\langle-4,-7\rangle \\ =\langle-4\times329,-7\times329\rangle \\ =\langle-1316,-2303\operatorname{\rangle} \end{gathered}[/tex]

The indicated quantity is:

[tex]\begin{equation*} \langle-1316,-2303\operatorname{\rangle} \end{equation*}[/tex]

Graph the line y = 5x – 1, then name the slope and y-intercept by looking at the graph.

Answers

Answer:

m = 5

y-intercept = (0, -1)

Step-by-step explanation:

y = mx + b

y = 5x - 1

m = 5

y-intercept = b = (0, -1)

Point 1: (0, -1)

Point 2: (1, 4)

Point 3: (-1, -6)

I hope this helps!

Animal is a bird Can fly Tiger Penguin ✓ ✓ Robin ✓ Snail Sparrow ✓ ✓ Pelican ✓ ✓ ✓ Bat Let event A = The animal is a bird. Let event B = The animal can fly. Which outcomes are in A and 8? O A. (robin, sparrow.pelican) B. (penguin, robin, sparrow, pelican) c. robin, sparrow, pelican, bat) D. (penguin, robin, sparrow. pelican, bat)

Answers

Outcome that are in A and B simply means both outcome must be achieved.

Therefore,

[tex]\begin{gathered} \text{Animal can fly and Animal is bird both exist in } \\ A\text{. }\mleft\lbrace\text{Robbin, sparrow, pelican}\mright\rbrace \end{gathered}[/tex]

For the point P(24,14) and Q(31,17), find the distance d(P,Q) and the coordinates of the midpoint M of the segment PQ.

Answers

STEP 1

Identify what is given and establish what is required.

We are given the coordinates of two points P and Q on the cartesian and are asked to find their midpoint M assuming a straight line is drawn from P and Q

Midpoint between two points is given as:

[tex]\begin{gathered} M=\frac{x_1+x_2}{2},\text{ }\frac{y_1+y_2_{}}{2} \\ \text{Where} \\ x_1,y_{1\text{ }}are\text{ the coordinates of point 1} \\ x_2,y_{2\text{ }}are\text{ the coordinates of point }2 \end{gathered}[/tex]

STEP 2

Employ formula while putting the appropriate variables.

We select point P as our point 1 as in the formulae and

We select point Q as our point 2 as in the formulae

This gives us:

[tex]\begin{gathered} M=\frac{24+31}{2},\frac{14+17}{2} \\ M=\frac{55}{2},\frac{31}{2} \\ M=27.5,15.5 \end{gathered}[/tex]

Therefore, our midpoint M is(27.5, 15.5)

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