Answer: True
Explanation:
a shopper in a supermarket pushes a cart with a q/c force of 35.0 n directed at an angle of 25.08 below the horizontal. the force is just sufficient to bal- ance various friction forces, so the cart moves at con- stant speed. (a) find the work done by the shopper on the cart as she moves down a 50.0-m-long aisle. (b) the shopper goes down the next aisle, pushing hor- izontally a
The final answer is:
a) 1585 J
b) The applied force would be smaller and the work would again be zero
c) 0 N
Given,
Force = 35 N
Angle = 25.08 below horizontal
Distance = 50 m.
Work = ?
(a) The horizontal component of the applied force is 35 N x cos 25.08 = 31.70 N
To calculate the work done by the shopper,
Work = force x distance
= 31.7 N x 50 m
= 1,585 J
b) If the applied force were horizontal, all of it would counter friction, so only 31.7 N would be needed. The work done on the cart is zero because there is no change in mechanical energy.
c) The work done on the cart by the shopper will be zero because there is no change in mechanical energy.
Therefore, work done by the shopper is 1585 J if it moves the cart to 50 m and the work done by the shopper is zero when there is no mechanical energy applied.
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[THIS IS AN INCOMPLETE QUESTION.
THE COMPLETE QUESTION IS:
A shopper in a supermarket pushes a cart with a force of 35.0 N directed at an angle of 25.08 below the horizontal. The force is just sufficient to balance various friction forces, so the cart moves at constant speed. (a) Find the work done by the shopper on the cart as she moves down a 50.0-m-long aisle. (b) The shopper goes down the next aisle, pushing horizontally and maintaining the same speed as before. If the friction force doesn’t change, would the shopper’s applied force be larger, smaller, or the same? (c) What about the work done on the cart by the shopper?]
a spring has a length of 0.4 m when a 0.3 kg mass hangs from it, and a length of 0.8 m when a 2.1-kg mass hangs from it. (a) what is the unloaded length of the spring?
The spring is 1.4 in long when unloaded .To calculate the length of an extension spring, multiply the total number of coils by the length of the spring wire per coil.
The new spring's length can be determined in what way?To calculate the length of an extension spring, multiply the total number of coils by the length of the spring wire per coil. To obtain the overall length, multiply the active coil count by two. When using torsion springs, multiply the total number of coils by the length of the spring wire per coil.According to Hooke's Law, when a vertical spring is coupled to a mass, the gravitational force acting on the mass determines how long the spring will extend. Therefore, the elongation will increase as the mass increases. The vertical spring's length is directly inversely proportional to the gravitational force acting on the mass.Explanation:
In line with Hooke's law:
F \s= \sK \sx
x \s1 \s= \s 0.4
the strain on the first weight multiplied by two equals 0.3
On second weight K, m is the stretch.
0.1 + 1.3 = 1.4 .
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when raindrops form, the force of gravity pulls them toward the ground. which statement is correct about this chain of events?(1 point)
The correct statement about when raindrop form the force of gravity pull them towards the ground and causes the raindrops to accelerate.
In all the provided options, the most accurate answer will be the force of gravity causes the raindrops to accelerate.
When are in drop is form It is form of water and water contains mass, because of the presence of mass in the water of the raindrop the gravitational force of the earth works on the raindrop.
The force of gravity on the raindrop causes the it to accelerate.
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Complete question - When rain drops form, the force of gravity pulls them toward the ground. Which statement is correct about this chain of events?(1 point) The force of gravity causes the rain drops to form. There is a positive correlation between gravity and rain drop formation. There is a negative correlation between gravity and rain drop formation. The force of gravity causes the rain drops to accelerate.
FILL IN THE BLANK. immediately following the arrival of the stimulus at a skeletal muscle cell there is a short period called the __ period during which the events of excitation-contraction coupling occur.
Immediately following the arrival of the stimulus at a skeletal muscle cell, there is a short period called the latent period during which the events of excitation-contraction coupling occur.
This process is a connection between transduction in the sarcolemma and the initiation of muscle contraction. Sarcolemma is nothing but the cell membrane of skeletal muscle.
A single muscle twitch has a latent period, a contraction phase when tension increases and a relaxation phase when tension decreases.
The period of incubation, the interval preceding exposure to a pathogen toxin or radiation, and when effects occur. Muscle contracting, the time between a nerve stimulus and muscle contraction.
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a rock of mass m is dropped to the ground from a height h. a second rock, with mass 7m, is dropped from the same height. when the second rock strikes the ground, which of the following best describes its kinetic energy?
Two rocks, with mass m and 7m, are dropped from a height h. The kinetic energy of rock with mass 7m is 7 times that of the rock with mass m.
When an object is dropped from a certain height, it will experience a free fall motion. Its velocity just before the object hits the ground is:
v = √(2gh)
Hence, it the velocity doesn't depend on the mass of the object. Therefore, in the given case, the velocity of mass m and mass 7m will be the same.
The kinetic energy of an object with m is given by:
Ek = 1/2 . mv²
Since the velocities of the two rocks are the same, the kinetic energy is directly proportional to their masses.
Ek1 : Ek2 = m1 : m2
Ek1 : Ek2 = m : 7m
Ek2 = 7 Ek1
Thus, the kinetic energy of rock with mass 7m is 7 times that of the rock with mass m.
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a support crossbeam on a high speed train is made from a titanium rod that has a length of 1.25 m when measured by an observer on the train. the beam is positioned such that the observer on the train measures an angle of 27 degrees between the crossbeam and the floor of the train. (figure 1) at what speed u would the train have to be traveling in order for an observer standing outside the train to measure the angle as 83 degrees ? in the figure, s indicates the reference frame of the observer standing outside the train and s' indicates the reference frame of the observer on the train.
0.765 m/s is speed u would the train have to be traveling in order for an observer .
R=1.25
Sinθ=27
speed=sinθ/r
speed=sin27/1.25
speed=0.765 m/s
A scalar variable called speed can be used to express how much the location of an object shifts over time or how much it shifts per unit of time. It is often shortened to "s." The average speed of an object over a period of time is equal to the distance traveled by the object divided by the length of the period.
Time divided by distance is the speed-related metric. While the SI unit of speed is the meter per second (m/s), the most common unit in daily life is the kilometer per hour (kph).
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A bartender gives a full mug of beer an initial speed vfull, and the mug stops in front of a patron sitting at the end of the bar. This patron later asks for a mug only half full. The bartender stands at the same position as when she sent the full mug to the patron and gives the mug an initial speed vhalf.
The mug an initial speed vhalf is Vhalf = Vfull.
The friction force depends on the normal force, so the full mug has twice the friction force. If there's friction force, then Vhalf < Vfull since normal force is halved. The acceleration depends on the force divided by the inertia, so they have the same acceleration.
Initial Velocity describes how fast an object moves when gravity first exerts a force on it. To find the initial velocity first, multiply the acceleration by time. Then divide that number by 2 and write down the resulting quotient. Then divide the distance by the time and record this quotient as well. Finally, subtract the first quotient from her second quotient to get the initial velocity.
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just after vertical launch from earth surface, the space shuttle takes 8.0 ss to reach a speed of 160 km/hkm/h.
The required force F = 2504.04 N
acceleration is defined as the change in speed over time,
where v and u represent the final and starting velocities, respectively.
When v=160 km/h and u=0 are transformed to m/s,
acceleration equals apparent weight;
hence, if g=9.81 and m=84 kg
thus the answer can be calculated by :
a = (v - u) / t
on substituting the value we get
a = 160 / 8
this implies a = 20 [tex]m/s^2[/tex]
Thus the force = F = 84( 9.81 + 20 )
F = 2504.04 N
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igure 9-24 shows an overhead view of four particles of equal mass sliding over a frictionless surface at constant velocity. the directions of the velocities are indicated; their magnitudes are equal. consider pair- ing the particles. which pairs form a system with a center of mass that (a) is stationary, (b) is stationary and at the origin, and (c) passes through the origin
The pairs that form a system with a center of mass that
(a) is stationary are ac, bc and dc.
(b) is stationary and at the origin is bc
Coordinates of the four particles are:
a = ( - 4 m , 2 m )
b = ( 4 m , 2 m )
c = ( - 4 m , - 2 m )
d = ( 4 m , - 2 m )
The center of mass of two particles of equal masses lies exactly at the center of the tile joining them. If two particles are moving in the opposite direction with equal speeds, then their center of mass will be stationary.
Therefore, the pairs that form a system with a center of mass that
(a) is stationary are ac, bc and dc.
(b) is stationary and at the origin is bc
(c) passes through the origin are ad and bd
The given question is incomplete. The complete question is:
Figure 9-24 shown in the image attached shows an overhead view of four particles of equal mass sliding over a frictionless surface at constant velocity. The directions of the velocities are indicated; their magnitudes are equal. Consider pairing the particles. Which pairs form a system with a center of mass that (a) is stationary, (b) is stationary and at the origin, and (c) passes through the origin?
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A bullet of mass 0.016 kg traveling horizontally at a high speed of 210 m/s embeds itself in a block of mass 3 kg that is sitting at rest on a nearly frictionless surface.
What is the speed of the block after the bullet embeds itself in the block?
Calculate the total translational kinetic energy before and after the collision.
(A) After the collision, the block's final speed was 1.485 m/s.
(b) The total kinetic energy of the system after the collision is 3.33 J, while the kinetic energy before the collision is 627.2 J.
(c) The energy lost to frictional force during the impact accounts for the difference in the two kinetic energies.
How to calculate kinetic energy ?Final block velocityThe principle of linear momentum conservation is used to calculate the block's final speed following the collision.
v(m1 + m2) = m1u1 + m2u2.
0.016(280) + 3(0) = v(0.016 + 3)
4.48 = 3.016v
v = 4.48/3.016
v = 1.485 m/s
Kinetic energy overall both before and after a collisionFollowing are the calculations for the kinetic energy before to the impact;
K.E I = ¹/₂mv²
K.Ei = 0.5 x 0.016 x 280²
K.Ei = 627.2 J
The total kinetic energy of the system after the collision is calculated as follows;K.Ef equals 1/2(m1 + m2) v2.
K.Ef = ¹/₂(0.016 + 3) 1.485²
K.Ef = 3.33 J
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A rocket rises at 5 ft/s between 0 and 10 seconds. Afterwards it rises at 15 ft/s for another 15 seconds. Use one loop to calculate the rockets height at the end of the 25 seconds. Use h as the variable for height.
The height of the rocket, given that the rocket rises at 5 ft/s between 0 and 10 seconds and afterwards it rises at 15 ft/s for another 15 seconds is 275 ft
How do I determine the height of the rocket?First, we shall determine the height attained in the first 10 seconds. This can be obtained as follow:
Velocity = 5 ft/sTime = 10 secondsHeight in first 10 seconds =?Height = velocity × time
Height in first 10 seconds = 5 × 10
Height in first 10 seconds = 50 ft
Next, we shall determine the height in the next 15 seconds. This is shown below:
Velocity = 15 ft/sTime = 15 secondsHeight in next 15 seconds =?Height = velocity × time
Height in next 15 seconds = 15 × 15
Height in next 15 seconds = 225 ft
Finally, we shall determine the height of the rocket at the end of the 25 seconds. This is shown below:
Height in first 10 seconds = 50 ftHeight in the next 15 seconds = 225 ftHeight at the end =?Height at the end = 50 + 225
Height at the end = 275 ft
Thus, the height of the rocket is 275 ft
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what is the intensity of an electromagnetic wave with a peak electric field strength of 127 v/m? (answer must be in three digits)
The Intensity of the electromagnetic wave with a peak electric field strength of 127 V/m is 20.9W/m².
The relation between the intensity of an electromagnetic wave and the peak electric field strength is,
I = ecE²/2
Where,
e is the electric permittivity,
c is the speed of the electromagnetic wave,
E is the peak electric field.
The peak electric field is given to be 127 V/m, so, putting values,
I = 8.85 x 10⁻¹² x 3 x 10⁸ x 127 x 127/2
I = 20.9 W/m².
So, the intensity of the electromagnetic wave is 20.9 W/m².
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what is the term for the eye movements that occur as the observer shifts their gaze from one part of the visual scene to another?
The term for the eye movements that occur as the observer shifts their gaze from one part of the visual scene to another is known as Saccades.
What is Eye movement?Eye movement may be characterized as the voluntary and involuntary movements of the eyes that assist with obtaining, fixating on, and following visual stimuli.
The eyes are each connected to a system of six muscles. Light is sensed by the retina, which is a type of tissue that contains cells known as photoreceptors.
Therefore, saccades is the term for the eye movements that occur as the observer shifts their gaze from one part of the visual scene to another.
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in a game of tug of war the red team is pulling with a force 500 n to the left while the blue team is pulling with a force of 340 n to the right. what will be the net force of the flag in the middle?
The tug-of-war winner is the team who pulls the rope the hardest.
Reason being: The rope moves in the direction of greater force.
We are familiar with Newton's second law of motion, which describes circumstances in which all of the forces are not balanced. As a result, the acceleration is a function of our applied force. Inversely correlated with body mass is acceleration as well. The acceleration of the body produced is proportional to the net force we apply and in the direction of the force we apply, which is an alternative explanation for the second law. Consequently, the rope is pulled harder when playing tug of war. The acceleration of the rope increases as more force is applied. And the direction of the rope's movement is in the direction of a stronger force. Rope motion is in the direction of greater force.To know about Newton's second law of motion-
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a 275-kg glider is being pulled along by a 2,000-kg jet. the system accelerates to the right at 2.2 m/s2. how much thrust is provided by the jet's engines, in newtons?
The amount of thrust provided by the 2,000 kg jet's engine to 275-kg glider is 5,005N.
Thrust is defined as the reaction force described quantitatively by Newton's third law. When the system expels or accelerates mass in one direction, then it feels same acceleration in reverse direction.
We know very well that if a body is moving with some acceleration a and having some mass m then, change in momentum of that body is equal to force applied on the body by the ground surface.
In other words, F = ma
where m is mass and a is acceleration of the body
Total mass of the combined system =mass of glider + mass of jet's engines
=275kg +2000kg
=2275Kg
Acceleration given as 2.2m/sec².
So, on putting both of values.
=>F=2275×2.2
=>F=5,005 Kg-m/sec² or
=>F= 5,005N
Hence, amount of thrust provided is 5,005N.
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How fast would a light beam appear to einstein if he were traveling in the same direction at 90% of the speed of light?.
If Einstein were traveling in the same direction of a light beam at 90% of the speed of light, the light beam would be travelling at 10% of speed of light.
Speed of light, c = 3 * 10⁸ m / s
90 % of Speed of light = 3 * 10⁸ * 0.9
90 % of Speed of light = 2.7 * 10⁸ m / s
Relative speed = 3 * 10⁸ - 2.7 * 10⁸
Relative speed = 0.3 * 10⁸ m / s
Relative speed = 0.1 c = 10% of speed of light
Relative speed of one object with respect to another is the difference in speeds of both objects if they are travelling in same direction. Relative speed of one object with respect to another is the sum of speeds of both objects if they are travelling in opposite direction.
Therefore, if Einstein were traveling in the same direction of a light beam at 90% of the speed of light, the light beam would be travelling at 10% of speed of light.
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A particular interaction force does work Wint inside a system. The potential energy of the interaction is U. Which equation relates U and Wint?∆U=-Wint
The equation relates U and Wint is ΔU = -Wint.
Work is defined as the energy that is applied to or removed from an object by applying force along a displacement. In its simplest form, it equals the product of the force's magnitude and the distance traveled for a constant force directed in the same direction as the motion.
Potential energy is the power that an object can store due to its position in relation to other objects, internal stresses, electric charge, or other circumstances.
Consider the work of of interaction is W =mgh - equation -1
and the Potential energy = U.
Final Potential energy Uf =0 , And the Initial Potential Energy Ui =mgh
Now we will write the equation for a Change in Potential energy ΔU,
ΔU = Uf - Ui
= 0-m*g*h
ΔU = -m*g*h --Equation 2
Now compare the both equation
Wint = -ΔU
we can rewrite the above equation
ΔU = -W.
So our Answer is ΔU = -W.
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Given the formula, the Lewis Structure and the ball and stick model of each question below,
explain the simple molecule's:
Electronic Geometry
Molecular Geometry
Polarity
Intermolecular Forces
Compound Name
The Lewis hypothesis of chemical bonding aids in our understanding of how atoms are arranged and bound together to form molecules.
Each valence electron of an atom is represented by a dot in the Lewis structure, while a covalent link between two atoms is represented by a line. It also goes by the name "electron dots structure."The "balls" (spheres) in 3D models of the ball and stick symbolize various atoms. The atoms' connecting rods, or "sticks," stand in for the chemical bonds.The length (diameter) of spheres is far less than that of rods in the ball and stick model, allowing for a clearer view of the atoms and bonds. As a result, it is unable to show how much space the molecule actually takes up.
Since hard bonds and holes don't exhibit systems with irregular angles, the sticks can also be made flexible. This is particularly true of double and triple bonds, which are lengthier and more flexible than single bonds. They can facilitate geometric isomerism and restrict rotation(cis-trans).
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during the time that a comet passes through the inner solar system, the comet can appear quite bright because .
Because sunlight bounces off the comet's tail and coma, a comet can appear fairly bright as it passes through the inner solar system.
What is the significance of the Solar System?The biggest benefit is that it is a renewable, clean source of energy. Solar energy can also be scaled. This means that it can be utilized on an industrial scale or to power a single household. Home solar is a zero-emissions, sustainable energy source. Home solar, unlike fossil fuels such as coal and natural gas, does not emit hazardous pollutants or greenhouse gas emissions such as carbon dioxide into the air and water supplies. Solar photovoltaics for electricity, passive solar design for space heating and cooling, and solar water heating are the most often used solar technologies for homes and businesses.
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16.66 through 16.68 a thin plate of the shape indicated and of mass m is suspended from two springs as shown. if spring 2 breaks, determine the acceleration at that instant of (a) point a, (b) point b. 16.66 a square plate of side b 16.67 a thin hoop of diameter b 16.68 a rectangular plate of height b and width a
Take moment about G
EMG = T
T b/2 - I ∝
[tex]\frac{1}{2}mg (\frac{b}{2}) = \frac{mb^{2} }{T}[/tex]∝
∝ = [tex]\frac{39}{2b}[/tex]
Efy = 0
-w + T₁ = ma
-mg +1/2mg = -ma
a = [tex]\frac{9}{2}[/tex]
plane motion = Translation + Rotation
(a) [tex]a_{A} = a_{G} + a_{\frac{A}{G} } = a + \frac{b}{2}[/tex]∝
[tex]a_{A} =\frac{9}{2} (\frac{39}{2b}) = \frac{9}{4}[/tex]
[tex]a_{A} = \frac{9}{4}[/tex]↑
(b) aB = aG + aB/G = a +b/2∝ (↓)
= 9/2 +b/2 (39/2b)
aB = [tex]\frac{5}{4} 9[/tex]↓
A rectangular top can also complement the different shapes used in the table. Certain dishes are almost always well-suited to rectangular plates. In particular, it is the most common form of dinner plates and saucers. Square More common in Asian traditions such as sushi plates and bento boxes adds a modern style.
Squirrel Holds more groceries than round ones but takes up the same space in your cupboard. Mainly serves as a shield for insulated wires. It is also used to create a mounting base for mounting lamp holders or canopies.
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we have implemented volume encryption using a self-encrypting drive. which of the following attacks is the volume still vulnerable to? select all that apply.
Issue a new key at least every 2 years and use that key for all subsequent encryption tasks.
Disk encryption is a technology that protects data by way of converting it into unreadable code that can't be deciphered easily by unauthorized human beings. Disk encryption makes use of disk encryption software or hardware to encrypt each bit of records that is going on a disk or disk extent.
Full-disk encryption can ensure that no meaningful data may be extracted from a tool without the device password/encryption key, whichever is used to fasten the tool. hence, FDE can make sure the safety of device facts at relaxation.
There are major computer encryption types: full disk encryption and record-stage encryption. complete Disk Encryption or whole disk encryption protects the entire quantity and all documents on the force in opposition to unauthorized access.
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After the consumption of an alcoholic beverage, the concentration of alcohol in the bloodstream (blood alcohol concentration, or BAC) surges as the alcohol is absorbed, followed by a gradual decline as the alcohol is metabolized. The function C(t) = 1.3 te^(-2.1t)models the BAC, measured in mg/mL, in a test patient's bloodstream t hours after rapidly consuming 15 mL of alcohol. What is the maximum BAC during the first three hours? When does it occur?
The maximum blood alcohol concentration (BAC) during the first three hours is 0.177 mg/mL .
We are given that,
The function = C(t) = 1.3te^(-2.1t)
Concentration of alcohol in bloodstream = 15ml
The maximum is found where the derivative of C(t) is zero.
dC/dt = 1.3e^(-2.1t) -(1.3t)2.1e^(-2.1t) = 0
On Solving the above equation for getting the value of t,
t = 1/2.1
Therefore, the maximum C(t) is
C(1/2.1) = 1.3/2.1e^(-1) ≈ 0.177 mg/mL
The maximum average BAC during the first 6 hours would be about 0.177 mg/mL .
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Lego got bored of bows, so he went to buy a sling. We approximate it as a spring with constant
stiffness and a zero rest length. Lego can stretch the sling with force F = 31.4 N, and he wants it
to store as much energy as possible while it is stretched. There were two slings at the shop, with
stiffnesses k1 = 159 N/m and k2 = 265 N/m. What will be the difference between the potential
energies of those slings stretched with force F?
The difference between the potential energies of those slings stretched with force F is 1.25 J.
What is the extension of each spring?The extension produced in each spring by the applied force is calculated by applying Hooke's law as shown below;
F = kx
where;
F is the applied forcek is the spring constantx is the extension of the springThe extension of the first spring with stiffness of k1 = 159 N/m, is calculated as;
x₁ = F/k₁
x₁ = 31.4 N / 159 N/m
x₁ = 0.197 m
The energy stored in this first spring is calculated as;
E₁ = ¹/₂k₁x₁²
E₁ = ¹/₂(159)(0.197²)
E₁ = 3.1 J
The extension of the first spring with stiffness of k1 = 159 N/m, is calculated as;
x₂ = F/k₁
x₂ = 31.4 N / 265 N/m
x₂ = 0.118 m
The energy stored in the second spring is calculated as;
E₂ = ¹/₂k₂x₂²
E₂ = ¹/₂(265)(0.118²)
E₂ = 1.85 J
The difference in the two energies is calculated as follows;
ΔE = 3.1 J - 1.85 J
ΔE = 1.25 J
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what is the maximum speed, in meters per second, of electrons ejected from this metal by photons of light with wavelength 89 nm?
The maximum speed, in meters per second, of electrons ejected from this metal is 2.22 x 10⁶ m/s.
What is the maximum speed of the ejected electron?The maximum speed of the electron ejected is calculated by applying the following equation.
K.E(max) = hf
¹/₂mv² = hf
¹/₂mv² = hc/λ
mv² = 2hc/λ
v² = 2hc/λm
v = √(2hc/λm)
where;
h is Planck's constantc is the speed of lightλ is wavelengthm is mass of electronv = √( (2 x 6.626 x 10⁻³⁴ x 3 x 10⁸)/ (89 x 10⁻⁹ x 9.1 x 10⁻³¹) )
v = 2.22 x 10⁶ m/s
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a marble rolls off of a desk with a speed of 3 m/s. the top of the desk is 1.5 m above the floor. a. how long does it take for marble to hit the ground? b. how far away from the table is the marble when it hits the ground?
The height represented by s is equal to the height represented by theta which is 74. The value of t square is used to add half negative 9.81 to the power of 2. The h value is 42.51 in meters.
How do you calculate the speed & time of an object just before it hits the ground?Pick the duration of the fall of the item. We'll use a time of 8 seconds in this illustration. The formula v = v0 + gt = 0 + 9.80665 * 8 = 78.45 m/s may be used to get the final free fall speed (right before impact).As a result of gravity, there is a downward vertical acceleration of 9.8 m/s/s. A projectile's vertical velocity changes by 9.8 meters per second (m/s) each second, A projectile's vertical motion does not affect how it moves horizontally.Formula T tof=2(v 0 sin 0)g. A projectile's flight period begins at this point, whether it is being launched or colliding with a flat, horizontal surface.Given data :
Equation 1: y=y0+v0yt+1/2 at²
where y0=1.5m , y=0 meters (the floor), v0y=0, and a=-9.8 m/s2
. Plugging
these numbers in we get
The substitution of the horizontal component of this velocity was made. The 190 is equal to 74 cos 23 and we use the value of t to figure out the distance. equal to a square and a y t square.
The acceleration in the direction of the y is negative if we make the substitution. The height represented by s is equal to the height represented by theta which is 74. The value of t square is used to add half negative 9.81 to the power of 2. The h value is 42.51 in meters.
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If 250 mg of a radioactive element decays to 200 mg in 12 hours, find the half-life of the element. (Round your answer to the nearest
The half-life of the element, if 250 mg of a radioactive element decays to 200 mg in 12 hours is 37.5 hours
N ( t ) = No ( 1 / 2 [tex])^{t/h}[/tex]
N ( t ) = Quantity of substance remaining
No = Initial quantity
t = Time elapsed
h = Half life
t = 12 hrs
No = 250 mg
N ( 12 ) = 200 mg
N ( 12 ) = No ( 1 / 2 [tex])^{12/h}[/tex]
200 = 250 ( 0.5 [tex])^{12/h}[/tex]
( 0.5 [tex])^{12/h}[/tex] = 200 / 250
( 0.5 [tex])^{12/h}[/tex] = 0.8
taking log on both sides
log [ ( 0.5 [tex])^{12/h}[/tex] ] = log ( 0.8 )
12 / h log ( 0.5 ) = log ( 0.8 )
12 / h = log ( 0.8 ) / log ( 0.5 )
12 / h = - 0.0969 / - 0.301
12 / h = 0.32
h = 37.5 hours
Therefore, the half-life of the element, if 250 mg of a radioactive element decays to 200 mg in 12 hours is 37.5 hours
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uranus is much smaller and less massive than jupiter. uranus rotates on its side, giving it extreme seasons. this may have been caused by an impact. uranus has some large moons and rings. uranus's appearance is nearly featureless; very bland. uranus has no magnetic field. uranus's core is probably molten and very hot. uranus's blue color is due to being mostly made of methane, which absorbs long wavelengths.
The correct statements from the following list about how Uranus is different from Jupiter, and how its rings and moons formed and evolved includes the following:
Uranus is much smaller and less massive than Jupiter.Uranus's appearance is nearly featureless; very bland.Uranus has some large moons and rings.Uranus rotates on its side, giving it extreme seasons. This may have been caused by an impact.Describe Uranus?
Uranus is described as the seventh planet from the Sun. The name Uranus is a reference to the Greek god of the sky, Uranus, who, according to Greek mythology, was the great-grandfather of Ares, grandfather of Zeus and father of Cronus.
Some known facts about Uranus includes the following:
Uranus is the coldest planet in the Solar SystemUranus orbits the Sun on its sideA Season on Uranus lasts one long day which is equal to 42 yearsUranus is the second-least dense planet.Learn more about Uranus at: brainly.com/question/13770002
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What are the 5 stages of mitosis?.
Mitosis is divided into five distinct stages: prophase, prometaphase, metaphase, anaphase, and telophase. It is the process by which cells divide and replicate in order to produce two identical daughter cells.
The first stage of mitosis is prophase. During this stage, the chromosomes become visible and the nuclear envelope breaks down. The centrioles begin to move to opposite ends of the cell and the spindle fibers start to form. The chromosomes also condense and become shorter and thicker.
The second stage of mitosis is prometaphase. During this stage, the spindle fibers attach to the chromosomes and the chromosomes begin to move towards the center of the cell.
The third stage of mitosis is metaphase. During this stage, the chromosomes line up in the center of the cell in an orderly fashion, known as the metaphase plate.
The fourth stage of mitosis is anaphase. During this stage, the sister chromatids separate and move to opposite ends of the cell. The spindle fibers continue to move the chromosomes until they reach the opposite poles.
The fifth and final stage of mitosis is telophase. During this stage, the nuclear membrane reforms around the two sets of chromosomes that have moved to opposite ends of the cell. The chromosomes start to uncoil and new nucleoli are formed. The cell then divides in two and the two daughter cells move away from each other.
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true or false: a mass measurement includes the effect of earth's gravitational pull on the object being measured
A mass measurement includes the effect of earth's gravitational pull on the object being measured. : FALSE
What are the effects of gravitational pull ?The moon is maintained in its orbit around Earth by gravity, as are the planets in their orbits around the sun. Ocean tides are a result of the moon's gravitational effect on the oceans. The stuff that stars and planets are comprised of is pulled together by gravity to form them.
There are four consequences of gravitational pull:
1)The gas-holding force inside the sun.
2) It makes a ball that has been launched into the air land back down.
3) It makes a car coast downhill even when the gas pedal is not depressed.
4) It results in a glass you drop dropping to the ground.
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a chair lift loaded with two passengers weighs 500 lbs. determine the forces in the cable to the left and right of the lift.
The forces in the cable to the left and right of the lift are Tright = 939.7 lb and Tleft = 984.8 lb.
Equilibrium of the system
∑ Fx= 0 ⇒ Tleftcos20° = Tright cos 10°
Tleft = cos10°/cos20° × Tright
Tleft = 1.048 Tright
∑Fy = 0 ⇒ Tleftsin20 + Trightsin10 = W
(1.048 × sin 20° + sin 10°) Tright
0..532 Tright = 500lb
Tright = 939.7 lb
Tleft = 1.048 × 939.7
Tleft = 984.8 lb
The state of a system when neither its internal energy status nor the state of motion tends to change over time. If a simple mechanical body experiences neither linear acceleration nor rotational acceleration, it is said to be in equilibrium. If this state is not disturbed by an external force, it will persist unbrokenly. When all forces acting on a single particle are added together and equal to zero, equilibrium results.
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