To figure out the answer, the given parameters have to be converted to meters.
The conversion from centimeters to meters is given to be:
[tex]100\text{ cm}\to1\text{ m}[/tex]Therefore, the parameters are converted by dividing by 100 as shown below:
[tex]\begin{gathered} length=20\text{ cm}\div100=0.2\text{ m} \\ width=17\text{ cm}\div100=0.17\text{ m} \end{gathered}[/tex]Hence, the area of a rectangle formula can be applied:
[tex]area=length\times width[/tex]Substituting known values, the area is calculated as shown below:
[tex]\begin{gathered} area=0.2\times0.17 \\ area=0.034 \end{gathered}[/tex]The area is 0.034 m².
Jackie's class took a field trip to the art museum. They left school at 11:00 A.M. It took them30 minutes to drive to the museum. They stayed at the museum for 3 hours. What time wasit when Jackie's class left the museum?
Given
Jackie's class took a field trip to the art museum.
They left school at 11:00 A.M.
It took them 30 minutes to drive to the museum.
They stayed at the museum for 3 hours.
To find:
What time was it when Jackie's class left the museum?
Explanation:
It is given that,
Jackie's class took a field trip to the art museum.
They left school at 11:00 A.M.
It took them 30 minutes to drive to the museum.
They stayed at the museum for 3 hours.
That implies,
Since,
Jackie's class left the school at 11:00 A.M and drove for 30 minutes.
Then,
The time at which they reach the museum is,
[tex]\begin{gathered} Time\text{ }taken\text{ }to\text{ }reach\text{ }the\text{ }museum=30\text{ }mins \\ \therefore Jackie^{\prime}s\text{ }class\text{ }reach\text{ }the\text{ }museum\text{ }at\text{ }(11.00+0.30)=11.30\text{ }A.M \end{gathered}[/tex]Also,
Since,
They stayed at the museum for 3 hours.
Then,
[tex]\begin{gathered} Jackie^{\prime}s\text{ }class\text{ }left\text{ }the\text{ }museum\text{ }at\text{ }(11.30+3.00)=14.30\text{ }hours \\ That\text{ }is, \\ They\text{ }left\text{ }the\text{ }museum\text{ }at\text{ }(12.00+2.30)\text{ }hours=2.30\text{ }P.M \end{gathered}[/tex]Hence, they left the museum at 2.30 P.M.
What is the complementary number of 54
For this type of problems we recall the definition of the complementary number of another number:
Let's say we have a number x, then the complementary number of x is a number for which the following happens:
[tex]x+mplementaryofx=10^n[/tex]Where n is the minimum number such that
[tex]10^n\ge x[/tex]For example: the complementary number of 5 is 5, the complementary number of 100 is 0, the complementary number of 350 is 650.
Answer: the complementary number of 54 is 100-54= 46.
Evaluate the expression when a = 5 and b = 49.
b-6a
Answer:
19
Step-by-step explanation:
Evaluating means substituting letters in an equation for values given :
b-6a
b = 49
a = 5
(49) -6(5)
= 49-30
= 19
Hope this helped and have a good day
PLS HELP ME IN TEN MINS FOR 10 POINTS THANKS U which group of numbers to replace the ? In a tree diagram? [ A] -7/8, -2.5, -4 [B] 7/8 ,2.5 ,4 [C] -7, 8 ,-4 [D] NOT heren
According to the given image, the tree diagram begins with Real Numbers.
The second level is formed by subsets of Real Numbers which are Rational Numbers and Irrational Numbers.
The third level is formed by subsets of rational numbers which are Non-Integer Rational Numbers and Integer Rational Numbers.
This means the missing part must be filled with Integer Rational Numbers.
Therefore, the right answer is -7, 8, -4, because these numbers are rational integers.10 ( -7/8) = ( -7/8 ) 10
Solve both sides of the equation to determine if true.
10(-7/8) = (-7/8)10
-70/8 = -70/8
This equation is true.
Answer:
[tex]10\left(\frac{-7}{8}\right)=\left(\frac{-7}{8}\right)\cdot \:10\quad :\quad \mathrm{True}[/tex]
Step-by-step explanation:
STEPS
[tex]10\left(\frac{-7}{8}\right)=\left(\frac{-7}{8}\right)\cdot \:10[/tex]
Frist u simplify [tex]10\left(\frac{-7}{8}\right)[/tex]
[tex]=10\cdot \frac{-7}{8}\\\\[/tex]
[tex]=-\frac{7\cdot \:10}{8}[/tex]
[tex]=-\frac{70}{8}[/tex]
[tex]=-\frac{35}{4}[/tex]
[tex]-\frac{35}{4}=-\frac{35}{4}[/tex]
THIs means both sides are true
hope this helps
~~Wdfads~~
What is the weight of a 35.01-carat diamond in grams and ounces? Use 1 carat = 0.2 gram, 1 carat = 3.086 grains, and 1 ounce = 437.5 grains.
The weight of a 35.01-carat diamond is
(Round to two decimal places as needed.)
The weight of a 35.01-carat diamond is oz.
The weight of a 35.01-carat diamond in grams and ounces
7.002gram0.247 ouncesHow to determine the weight of a 35.01-carat diamond in grams and ouncesInformation given in the question include
1 carat = 0.2 gram,
1 carat = 3.086 grains,
1 ounce = 437.5 grains.
The conversion of the weight units using the given variables can bbe done as follows
1 carat = 0.2 gram
35.01-carat diamond = ?
cross multiplying gives
1 * ? = 35.01 * 0.2
? = 7.002gram
1 carat = 3.086 grains
35.01-carat diamond = ?
cross multiplying gives
1 * ? = 35.01 * 3.086
? = 108.041 grains
That is 35.01-carat diamond = 108.041 grains
1 ounce = 437.5 grains
? = 108.041 grains
cross multiplying gives
437.5 * ? = 108.041 * 1
? = 108.041 /437.5
? = 0.247 ounces
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Solve for the remaining angles and side of the triangle described below. Round to the nearest thousandth:C = 60°, b = 3,a = 4AnswerHow to enter your answer (opens in new window) 2 Points
Explanation
Let's first make a sketch of the triangle:
We can find the measure of c with the law of cosines:
[tex]c=\sqrt{a^2+b^2-2ab\cdot cos(C)}[/tex][tex]c=\sqrt{9+16-24\cdot\frac{1}{2}}[/tex][tex]c=\sqrt{13}[/tex]For B and A we can use the sine law:
[tex]\frac{sin(B)}{3}=\frac{sin(60)}{\sqrt{13}}[/tex][tex]B=73.898°[/tex]And
[tex]\frac{sin(A)}{4}=\frac{sin(60)}{\sqrt{13}}[/tex][tex]A=46.102°[/tex]Answer
[tex]c=\sqrt{13}[/tex][tex]B=73.898°[/tex][tex]A=46.102°[/tex]A die was rolled 60 times. It landed on one—11 times, two—9 times, four—12 times, five—12 times, and six—8 times. What is the empirical probability of rolling an even number?
Step-by-step explanation:
Empirical Probability is the experimental probability.
The probability formula is
the number of times an event occured/total times all events happen.
We know we rolled the dice 60 times so that will be in the numerator.
We roll 2, 9 times
We roll 4, 12 times
We roll 6, 8 times so
we roll even numbers a total of 29 times, so our experimentally Probability is
[tex] \frac{29}{50} = 0.58[/tex]
I'm trying to translate the phrase into an algebraic expression the quotient of -11 and the cube of B
hello
to solve this problem, we just have to take the fraction between the numbers that responded they use the produt to the total numbers that carried out the survey.
the numbers that responded yes = 120
total number that carried out the survey = 132
[tex]x=\frac{120}{132}=\frac{60}{66}=\frac{30}{33}=\frac{10}{11}[/tex]the fraction in the lowest terms of the women surveyed that use the product is 10/11
A bag of fertilizer covers 2500 square feet of lawn. Find how many bags of a rectangular lawn 170 feet by 110 feet
you can find how many bags you need dividing the square feet of the place by the square feet the fertilizer cover, so:
170*110=18700 square feet (area of the place)
18700/2500=7.48
so you will need 8 bags of fertilizer to cover it
Violet read 1250 words in 5 minutes. About how long will it take her, in minutes, to read 10000 word essay?
Answer:
40 minutes
Explanation:
The ratio of the number of words to the number of minutes is constant. Then, If violet read 1250 words in 5 minutes, we can write the following equation:
[tex]\frac{1250\text{ words}}{5\text{ minutes}}=\frac{10000\text{ words}}{x\text{ minutes}}[/tex]Where x is the number of minutes that she needs to read a 10000-word essay.
So, solving for x, we get:
[tex]\begin{gathered} \frac{1250}{5}=\frac{10000}{x} \\ 1250x=5(10000) \\ 1250x=50000 \\ \frac{1250x}{1250}=\frac{50000}{1250} \\ x=40\text{ minutes} \end{gathered}[/tex]Then, she will take 40 minutes to read the essay.
402,394,386 find the 33rd term
The sequence are 402, 394, 386. The 33 rd term can be found below
What place value first determines which of the numbers 279.1642 or 279.1651 is the
larger number
279.1651 is larger
======================================================
Explanation:
Both values have "279.16" at the start
The difference starts to happen in the digit just after the 6, which is the thousandths digit
The first value 279.1642 has '4' in the thousandths digitThe second value 279.1651 has '5' in the thousandths digitThis makes 279.1651 to be the slightly larger value.
Let U = {1, 2, 3, 4, 5, 6, 7}, A = {2, 4, 6}, B = {1, 2, 3, 5, 7}, and C = {1, 3, 6, 7}.Find (A U B)’Question 44 options:a) { }b) {1, 2, 3, 4, 5, 6, 7}c) {2, 4, 6}d) {2}
Given:
U = {1, 2, 3, 4, 5, 6, 7}
A = {2, 4, 6}
B = {1, 2, 3, 5, 7}
C = {1, 3, 6, 7}
To find:
(A U B)’
First, we will find (A U B):
A = {2, 4, 6}
B = {1, 2, 3, 5, 7}
[tex]\begin{gathered} (A\text{ U}B):all\text{ the numbers in A and B without repetition} \\ \left(AUB\right)=\text{ \textbraceleft}{2,4,6,1,2,3,5,7}\rbrace \\ (AUB)={\text{ \textbraceleft}1,2,2,3,4,5,6,7\rbrace} \\ without\text{ repeating the numbers:} \\ (A\text{ U B\rparen= \textbraceleft1, 2, 3, 4, 5, 6, 7\textbraceright} \end{gathered}[/tex][tex]\begin{gathered} (A\text{ U}B)^{\prime}\text{ : this entails the numbers that are in U }but\text{ not in \lparen A U}B) \\ U\text{ = \textbraceleft1, 2, 3, 4, 5, 6, 7\textbraceright} \\ (AUB)=\left\{1,2,3,4,5,6,7\right\} \\ The\text{ numbers in both sets are the same} \\ \\ Hence,\text{ the complement of \lparen AUB\rparen will be a null set} \\ (AUB)^{\prime}\text{ = \textbraceleft \textbraceright \lparen option A\rparen} \end{gathered}[/tex]Solve the following system of equations. -3x-7y=-3-2x+5y=-2
1) Let's solve that system by elimination. We'll eliminate the x terms firstly:
Since the LMC, between 3 and 2 is 6 let's multiply the first and the second equation to get 6x
-3x-7y=-3 x -2
-2x+5y=-2 x 3
6x +14y= 6
-6x+15y=-6
-------------------------
0 + 29y = 0
y= 0
2) Now let's plug into one of those equations, usually the simpler one, that value for y. To find out the x.
-2x +5y=-2
-2x +5(0) =-2
-2x= -2
2x=2 Divide both sides by 2
x=1
3) So the solution for this system is (1,0).
create a data set with a minimum of 5 data points each where the mean = 25, median =25 and mode =25
A data set with a minimum of 5 data points each where the mean = 25, median =25 and mode =25 is 23, 24, 25, 26, 27.
Data set
A data set is a collection of numbers or values that relate to a particular subject.
For example, the test scores of each student in a particular class is a data set. The number of fish eaten by each dolphin at an aquarium is a data set.
Given that the mean = 25, median =25 and mode =25
Mean = The mean of a dataset is the sum of all values divided by the total number of values. It's the most commonly used measure of central tendency and is often referred to as the “average.”
Median = The median is the middle number in a sorted, ascending or descending list of numbers and can be more descriptive of that data set than the average.
Mode = When it's unique, the mode is the value that appears the most often in a data set and it can be used as a measure of central tendency, like the median and mean. But sometimes, there is no mode or there is more than one mode. There is no mode when all observed values appear the same number of times in a data set.
Therefore the data set will be
23, 24, 25, 26, 27
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If the log is 11 ft long, and one piece is x feet long, how long is the length of the other piece?
Total length of the log = 11 ft
Length of one piece = x
Length of the other piece = 11-x
What is Q1 in the given box-and-whisker plot?A box-and-whisker plot. The number line goes from 0 to 20. The whiskers range from 2 to 19 and the box ranges from 6.5 to 18. A line divides the box at 17.a.2c.17b.6.5d.18
we have that
Min=2
Max=19
Median=17
Answer:
b. 6.5
Step-by-step explanation:
edge 2023 I did it myself trust me
2.) What does the graph below represent? What are key points andcharacteristics? Provide as many details as possible.
The graph shows the evolution of the profits, in a scale of dollars, in time, in the scale of months.
The profit grows from month 0 to 1, decrease from month 1 to 2, and then increases from there (with stagnation in months 4, 5 and 6).
We have no information from month 7 or bigger.
The range of the profit up to month 6 is between $2,000 and $6,000, but the arrow indicate it will grow over $6,000 the following months.
Given any triangle ABC with corresponding side lengths A, B, and C, the law of cosine states:
The Law of Cosines is used to find the remaining parts of an oblique triangle when either the lengths of two sides and the measure of the included angle are known or the lengths of the three sides are known.
Consider the following oblique triangle:
Applying this oblique triangle, we can state the law of cosines to find side b:
[tex]b^2=a^2+c^2\text{ - 2ac }\cos(B)[/tex]We can conclude that the correct answer is:
Answer:[tex]b^2=a^2+c^2\text{ - 2ac }\cos(B)[/tex]A collection of stamps consists of 3c stamps 5c stamps and 7c stamps. There are 6 more 3c stamps than 5c stamps and two more 7c stamps than 3c stamps. The total value of the stamps is $1.94. How many 3c stamps are in the collection?
The number of 3¢ stamps that are in the collection is: 22.
What is an expression?An expression can be defined as a mathematical equation which is used to show the relationship existing between two or more variables and numerical quantities.
In this exercise, you're required to determine the number of 3 cents (3¢) . Therefore, we would translate the word problem into an algebraic expression and then evaluate it as follows:
Note: 100 cents (¢) is equal to 1 dollar ($).
A collection of stamps consists of 3¢ stamps, 5¢ stamps and 7¢ stamps; 3¢ + 5¢ + 7¢ = 194
6 more 3¢ stamps than 5¢ stamps; 3¢ = 5¢ + 6 ⇒ 5¢ = 3¢ - 6
Two more 7¢ stamps than 3¢ stamps; 7¢ = 3¢ + 2
Combining the above equations, we have:
3¢ + 3¢ - 6 + 3¢ + 2 = 194
9¢ = 198
¢ = 198/9
¢ = 22.
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Complete Question:
A collection of stamps consists of 3¢ stamps 5¢ stamps and 7¢ stamps. There are 6 more 3¢ stamps than 5¢ stamps and two more 7¢ stamps than 3¢ stamps. The total value of the stamps is $1.94. How many 3¢ stamps are in the collection?
John is asked to roll a fair number cube, numbered from one to six,and toss a balanced quarter simultaneously. What is the probabilitythat he will roll a 2 and the quarter will come up tails?Leave your answer in fraction form
Solution
John is asked to roll a fair number cube, numbered from one to six, and toss a balanced quarter simultaneously
Total possible outcome when a number cube is rolled is 6, i.e numbers from 1 to 6
Total possible outcome when a balanced quarter is 2 i.e a head or a tail
The formula to find probability, P, is
[tex]P=\frac{\text{Required Outcome}}{Total\text{ possible outcome}}[/tex]The probability that a he will roll a 2, P(2) is
[tex]P(2)=\frac{1}{6}[/tex]The probability that the quarter comes up with a tail, P(T) is
[tex]P(T)=\frac{1}{2}[/tex]The probability that he will roll a 2 and the quarter will come up tails is
[tex]P=P(2)\times P(T)=\frac{1}{6}\times\frac{1}{2}=\frac{1}{12}[/tex]Hence, the answer is 1/12
5 = 60(0.93)^x
Initial value:
Growth or Decay:
Growth/Decay Rate:
Initial value is 60 and growth factor is -0.93 in this instance.
How are growth and decay determined?The formulas f(x) = a(1 + r)t and f(x) = a(1 - r)t provide the necessary computations for the exponential growth and decay. Here, t is the length of time or the time factor, an is the initial quantity, r is the growth or decay constant.
The formula is 5 = 60(0.93)^x.
The beginning value and growth/decay factor should be determined.
Solution:
Y = a(1+r)^x is the formula for the exponential growth/decay model in general (i)
where an is the starting value, r>0 indicates growth factor, r0 indicates decay factor, and x indicates time.
As a result, 5 = 60(0.93)^x.
It can be expressed mathematically as 5 = 60(1 + (-0.93))x (ii)
We obtain a = 60 and r = -0.93 when comparing I with (ii).
Initial value is 60 and growth factor is -0.93 in this instance.
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Write each rate as a fraction in lowest terms 5 feet in 35 seconds
The rate 5/35 feet per seconds as a fraction in lowest terms would be 1/7
In this question we need to write each rate as a fraction in lowest terms 5 feet in 35 seconds.
The rate would be feet per seconds.
i.e., 5/ 35
To convert this rate in simplest terms, we need to reduce all common factors.
5 = 5 × 1
and 35 = 5 × 7
So, the rate would be,
5/35 = (5 × 1)/(5 × 7)
5 is the common factor for both the numbers 5 and 35.
5/35 = 1/7 ..........(cancel the common factor)
Therefore, the rate 5/35 feet per seconds as a fraction in lowest terms would be 1/7
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The following are distances (in miles) traveled to the work place by 6 employees of a certain brokerage firm. Find the standard deviation of this sample distances. ROund your answer to two decimal places
Step 1
Arrange the data from smallest to biggest
[tex]2,5,14,34,37,40[/tex]Step 2
The formula for standard deviation for sample is given as;
[tex]\begin{gathered} \sigma=\sqrt{\frac{\sum(x-\mu)^2}{n-1}} \\ \mu=mean \\ n=number\text{ of data} \end{gathered}[/tex]Find the mean
[tex]mean=\frac{132}{6}=22[/tex]Hence the standard deviation will be;
[tex]\begin{gathered} \sigma=\sqrt{\frac{1446}{6-1}=}17.005881 \\ \sigma\approx17.01\text{ to 2 decimal places} \end{gathered}[/tex]Answer; The standard deviation for the sample to two decimal places is;
[tex]17.01[/tex]make up a story for the graph below. describe all 5 events A-E of your story. note whether you mention whether your events are decreasing increasing or constant distance
Explanation:
We need to describe a story such that for event A, C, and E the distance is increasing, for event B the distance is constant, for event D, the distance is decreasing. So, the story is:
Answer:
On a specific day, you decided to travel to another city with your friends but you are the only one with a car, so you need to pick up each of your friends, so the y-axis represents the distance from your home.
So, event A is when you go to pick up your first friend that lives 2 hours away. This friend wasn't ready so you wait for an hour (event B). Then you go to the house of your second friend (event C) and at that moment you realize that you forget a third friend that lives closer to your house, so you have to come back to his house (event D). Finally, they start to travel to the city (event E).
An unfair coin has a probability 0.4 of landing heads. The coin is tossed two times. What is the probability that it lands heads at least once?
O 0.6
O 0.84
O 0.64
O 0.5
A store manager order 28 crates of mangoes there were thirty-six mangoes and each crate when the mangoes were delivered he sold the right mangoes and repack the rest equally into 73 boxes they were 12 mangoes in each box how many right angles are sold show your work and explain your reasoning
A windmill converts the mechanical energy of wind into _________ energy produced by a generator.
Answer:
electrical
Step-by-step explanation:
You want the kind of energy produced by a windmill's generator.
WindmillA typical windmill has airfoils in the wind stream that are connected to a shaft that rotates when the wind moves them. The rotation of the shaft turns the rotor in a generator, which causes wire to move through a magnetic field, producing a current in the wire. That current represents electrical energy produced by the generator.
What is exponential equation that has a y-intercept of 5 and a multiplier of 1.7
The exponential equation having y- intercept of 5 and a multiplier of 1.7 is
[tex]y=5(1.7^x\text{)}[/tex]Hence
, wwhen x = 0
[tex]\begin{gathered} y=5(1.7^0) \\ y\text{ = 5} \end{gathered}[/tex]Therefore the correct answer is
[tex]y=5(1.7^x)[/tex]