Answer:
[tex]90^{\circ}[/tex]. In other words, these two angles are both right angles, and this parallelogram would be a rectangle.
Step-by-step explanation:
Two angles that congruent have the same size.
At the same time, those two adjacent angles of this parallelogram would be a pair of consecutive interior angles. Because the two sides of a parallelogram are parallel to one another, the sum of these two consecutive interior angles would be [tex]180^{\circ}[/tex]- they are supplementary to one another.
Let the two angles be [tex]\angle1[/tex] and [tex]\angle 2[/tex].
[tex]\angle 1 = \angle 2[/tex] because the two angles are congruent.
[tex]\angle 1 + \angle 2 = 180^{\circ}[/tex] because these two angles are adjacent angles of a parallelogram.
Hence, [tex]\displaystyle \angle 1 = \angle 2 = \frac{1}{2} \times 180{^\circ} = 90^{\circ}[/tex].
algebra 2 help pls answer
Answer:
The volume of this rectangular prism equals [tex]V = 20x^{4} + 20x^{3} + 40x^{2}[/tex]
Step-by-step explanation:
In order to solve this question, we have to use the formula provided in the question to find out the volume of the rectangular prism. The formula goes as follows...
V = l × w × h (where "l" is the length, "w" is the width, and "h" is height.
From the question, we know that...
l = 4x
w = 5x
h = [tex]x^{2} + x + 2[/tex]
Now we just have to substitute all of these values into the equation and we get that...
V = l × w × h
V = 4x × 5x × [tex](x^{2} + x +2)[/tex]
[tex]V = (20x^{2})(x^{2} + x + 2)\\V = 20x^{4} + 20x^{3} + 40x^{2}[/tex]
Therefore, The volume of this rectangular prism equals [tex]V = 20x^{4} + 20x^{3} + 40x^{2}[/tex]
Find the area of the triangle with vertices A(-3,2), B(1,-2), and c(1,3)
Answer:
[tex]A(-3,2)\: B(-1,-2)\: C(1,3)[/tex]
[tex]A=1/2[x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)][/tex]
[tex]=1/2[-3(-2-3)(+1(3-2)+1(2-(-2))][/tex]
[tex]=1/2(15+1+4)[/tex]
[tex]=1/2(20)[/tex]
[tex]=10[/tex]
[tex]ANSWER: 10 ~units^{2}[/tex]
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The area of triangle with vertices A(-3,2), B(1,-2), and c(1,3) is 12 units^2.
What is area of triangle?The area of a triangle is defined as the total space occupied by the three sides of a triangle in a 2-dimensional plane. The basic formula for the area of a triangle is equal to half the product of its base and height, i.e., A = 1/2 × b × h.
The green line represents the height of the triangle = 4 units
The red line represents the base of the triangle = 6 units
Area of the triangle = 1/2 x 6 x 4 = 12 units^2
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Using the number line below, draw a box and whisker plot for the following data: 12,18,18,20,22,22,25,26,30,30,32,32,35,35,38,49,42
Answer:
Step-by-step explanation:
Population size: 17
Median: 30
Minimum: 12
Maximum: 49
First quartile: 21
Third quartile: 35
Interquartile Range: 14
Outliers: none
Solve 4x + 11 = k for x.
O A. x= -11
O B. x=-11
O C. x = 4k - 44
D. x= k-7
Answer:
4x + 11 = k
<=> 4x = k - 11
<=>
[tex]x = \frac{k - 11}{4} [/tex]
Evaluate the function. f(x)=3x^2 −4x Find f(−1)
Answer:
7
Step-by-step explanation:
evaluate the function means substitute x=-1 and calculate
f(x) = 3x²-4x
f(-1) =f(x=-1) = 3(-1)²-4(-1) =3+4 =7, because (-1)²=1 and -4(-1) =4
4 Two number cubes are rolled. The faces have the numbers 1-6 on them. The number that shows on top is recorded. What is the probability that
the same number shows on both number cubes?
OF
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What is a set ? Give an example of a set .
Answer: 24
Step-by-step explanation:
Please help me here. I've tried this one over and over and I'm unable to get the answer that was given. How do I find the area of this triangle?
Answer:
jjdjdjdj and technology and technology and technology and technology and technology
Calculate cos (theta) to two decimal places. PLS HELP ASAP
Answer:
B. -0.07
Step-by-step explanation:
Apply the Law of signs find θ.
Cos θ = (a² + b² - c²)/2ab
Where,
a = 7
b = 8
c = 11
Plug in the values
Cos θ = (7² + 8² - 11²)/2*7*8
Cos θ = (49 + 64 - 121)/112
Cos θ = -8/112
Cos θ = -0.0714285714
Cos θ = -0.07 (to 2 decimal places)
The local library lends an average of 68.24 books to readers each day. What is the average number of books lent to readers in a week?
Answer:
Step-by-step explanation:
Set this up as a proportion and solve. The ratios are books:day, so keep in mind that a week is 7 days because your values have to be the same
[tex]\frac{books}{day}:\frac{68.24}{1}=\frac{x}{7}[/tex] and cross multiply to solve for x, the number of books lent out in a week:
x = 68.24(7) so
x = 477.68 books in a week
What are the coordinates of points E, F, and GS
A. E (2, 3), F (8,5), G (5,8)
B. E (3, 2), F (8,3), G (5,6)
C. E (3, 2), F (8,4), G (5,7)
D. E (3, 3), F (9, 4), G (6,7)
Answer:
its a i think
Step-by-step explanation:
Length of a rope is 5 metre. What does it mean?
Step-by-step explanation:
Length of a rope is 5 meter. it means the rope is 5 meter long..
hope it helps.stay safe healthy and happy...
6. Write an equation of a line that is Parallel to the line: y = 3x -3
Answer:
3x - y -6 = 0
Step-by-step explanation:
We need to find the Equation of the line parallel to the given equation of line . The given equation of the line is ,
[tex]\rm\implies y = 3x - 3 [/tex]
Slope Intercept Form :-
[tex]\rm\implies y = mx + c [/tex]
where ,
m is slopec is y intercept .Therefore , the Slope of the line is 3 . Let the parallel line passes through ( 3,3) . We know that the parallel lines have same slope . Therefore the slope of the parallel line will also be 3 .
Using point slope form :-
[tex]\rm\implies y - y_1 = m ( x - x_1) \\\\\rm\implies y - 3 = 3( x - 3 ) \\\\\rm\implies y -3 = 3x -9 \\\\\rm\implies 3x -y -9+3=0\\\\\rm\implies \boxed{\rm\red{ 3x -y -6=0}}[/tex]
La potencia que se obtiene de elevar a un mismo exponente un numero racional y su opuesto es la misma verdadero o falso?
Answer:
Falso.
Step-by-step explanation:
Sea [tex]d = \frac{a}{b}[/tex] un número racional, donde [tex]a, b \in \mathbb{R}[/tex] y [tex]b \neq 0[/tex], su opuesto es un número real [tex]c = -\left(\frac{a}{b} \right)[/tex]. En el caso de elevarse a un exponente dado, hay que comprobar cinco casos:
(a) El exponente es cero.
(b) El exponente es un negativo impar.
(c) El exponente es un negativo par.
(d) El exponente es un positivo impar.
(e) El exponente es un positivo par.
(a) El exponente es cero:
Toda potencia elevada a la cero es igual a uno. En consecuencia, [tex]c = d = 1[/tex]. La proposición es verdadera.
(b) El exponente es un negativo impar:
Considérese las siguientes expresiones:
[tex]d' = d^{-n}[/tex] y [tex]c' = c^{-n}[/tex]
Al aplicar las definiciones anteriores y las operaciones del Álgebra de los números reales tenemos el siguiente desarrollo:
[tex]d' = \left(\frac{a}{b} \right)^{-n}[/tex] y [tex]c' = \left[-\left(\frac{a}{b} \right)\right]^{-n}[/tex]
[tex]d' = \left(\frac{a}{b} \right)^{(-1)\cdot n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{(-1)\cdot n}[/tex]
[tex]d' = \left[\left(\frac{a}{b} \right)^{-1}\right]^{n}[/tex]y [tex]c' = \left[(-1)^{-1}\cdot \left(\frac{a}{b} \right)^{-1}\right]^{n}[/tex]
[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c = (-1)^{n}\cdot \left(\frac{b}{a} \right)^{n}[/tex]
[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{b}{a} \right)\right]^{n}[/tex]
[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left[-\left(\frac{b}{a} \right)\right]^{n}[/tex]
Si [tex]n[/tex] es impar, entonces:
[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = - \left(\frac{b}{a} \right)^{n}[/tex]
Puesto que [tex]d' \neq c'[/tex], la proposición es falsa.
(c) El exponente es un negativo par.
Si [tex]n[/tex] es par, entonces:
[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left(\frac{b}{a} \right)^{n}[/tex]
Puesto que [tex]d' = c'[/tex], la proposición es verdadera.
(d) El exponente es un positivo impar.
Considérese las siguientes expresiones:
[tex]d' = d^{n}[/tex] y [tex]c' = c^{n}[/tex]
[tex]d' = \left(\frac{a}{b}\right)^{n}[/tex] y [tex]c' = \left[-\left(\frac{a}{b} \right)\right]^{n}[/tex]
[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{n}[/tex]
[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = (-1)^{n}\cdot \left(\frac{a}{b} \right)^{n}[/tex]
Si [tex]n[/tex] es impar, entonces:
[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = - \left(\frac{a}{b} \right)^{n}[/tex]
(e) El exponente es un positivo par.
Considérese las siguientes expresiones:
[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = \left(\frac{a}{b} \right)^{n}[/tex]
Si [tex]n[/tex] es par, entonces [tex]d' = c'[/tex] y la proposición es verdadera.
Por tanto, se concluye que es falso que toda potencia que se obtiene de elevar a un mismo exponente un número racional y su opuesto es la misma.
what is the x-intercept of the line shown below enter your answer as a coordinate pair
Answer: (-2, 0)
Step-by-step explanation: The x-intercept is the point where a line crosses or intersects the x-axis. In this case, the point is intersecting the x-axis 2 units to the left of the origin or at the point (-2, 0).
Battle is making fruit baskets, which include apples and bananas to send to some of her real estate clients. She wants each basket to have at least 12 pieces of fruit but the fruit should weigh no more than 80 ounces total. On average each apple weighs 5 ounces and each banana weighs 7 ounces.
Answer:
there are 2 apples in the basket
there are 10 banana in the basket
Step-by-step explanation:
According to the Question,
We have, Battle is making fruit baskets, which include apples and bananas to send to some of her real estate clients. She wants each basket to have at least 12 pieces of fruit.let x for apple And y for banana So, x+y=12---Equation 1
And, the fruit should weigh no more than 80 ounces total. On average each apple weighs 5 ounces and each banana weighs 7 ounces.Thus, 5x+7y=80 ----Equation 2
Now, (Equation 1) × 5 Subtract with (Equation 2) We get,
2y = 20 ⇒ y=10 (there are 10 banana in basket)
Put value of y=10 in Equation 2 we get5x+70=80 ⇔ x=2(there are 2 apples in basket)
You're working as a floor rep in the local home improvement store. The store wants to increase its inventory. Last year, 40 lawn mowers cost $4,776. At the same cost, how much will 120 lawn mowers cost this year?
Given ACM, angle C=90º. AP=9, PM=12. Find AC, CM, AM.
Answer:
AM = 25, AC = 15, CM = 20
Step-by-step explanation:
The given parameters are;
In ΔACM, ∠C = 90°, [tex]\overline{CP}[/tex] ⊥ [tex]\overline{AM}[/tex], AP = 9, and PM = 16
[tex]\overline{AC}[/tex]² + [tex]\overline{CM}[/tex]² = [tex]\overline{AM}[/tex]²
[tex]\overline{AM}[/tex] = [tex]\overline{AP}[/tex] + PM = 9 + 16 = 25
[tex]\overline{AM}[/tex] = 25
[tex]\overline{AC}[/tex]² = [tex]\overline{AP}[/tex]² + [tex]\overline{CP}[/tex]² = 9² + [tex]\overline{CP}[/tex]²
∴ [tex]\overline{AC}[/tex]² = 9² + [tex]\overline{CP}[/tex]²
Similarly we get;
[tex]\overline{CM}[/tex]² = 16² + [tex]\overline{CP}[/tex]²
Therefore, we get;
[tex]\overline{AC}[/tex]² + [tex]\overline{CM}[/tex]² = 9² + [tex]\overline{CP}[/tex]² + 16² + [tex]\overline{CP}[/tex]² = [tex]\overline{AM}[/tex]² = 25²
2·[tex]\overline{CP}[/tex]² = 25² - (9² + 16²) = 288
[tex]\overline{CP}[/tex]² = 288/2 = 144
[tex]\overline{CP}[/tex] = √144 = 12
From [tex]\overline{AC}[/tex]² = 9² + [tex]\overline{CP}[/tex]², we get
[tex]\overline{AC}[/tex] = √(9² + 12²) = 15
[tex]\overline{AC}[/tex] = 15
From, [tex]\overline{CM}[/tex]² = 16² + [tex]\overline{CP}[/tex]², we get;
[tex]\overline{CM}[/tex] = √(16² + 12²) = 20
[tex]\overline{CM}[/tex] = 20.
Write 8 as the ratio of two integer
Answer:
Step-by-step explanation: 7 1 16 37
8/1 8 divided by 1
16/2 16 divided by 2
24/3 24 divided by 3 I could go on, but won't
how do you find the arc length of a semi-circle?
the arc length is calculated by the formula [tex]\displaystyle\bf C=\frac{2\pi r}{360} \cdot\alpha[/tex] then [tex]\displaystyle\bf C=\frac{2\cdot 8 \pi }{360} \cdot180=8\pi=3,14\cdot8=25.12[/tex] or it can be calculated using the circumference of the circle since we have a semicircle the circumference 2πr must be divided by 2 С=2πr:2=πr =8π=25,12
The answers to this question make no sense please help
Answer:
Step-by-step explanation:
each die has numbers 1-6 thus there are 36 (6*6) possible outcomes
a) 18 of the 36 are even = 1/2 = .5 = 50%
b) (1,2) and (2,1) are the only 3's 2/36 = 1/18 = .055
c) there are 10 combos that are LESS THAN 6 (2,3,4,5)
10/36 = .277 = 27.7%
2 3 4 5 6 7
3 4 5 6 7 8
4 5 6 7 8 9
5 6 7 8 9 10
6 7 8 9 10 11
7 8 9 10 11 12
∣1/12 − 5/6∣ − (2/5 + 1/10)
I WILL GIVE BRAINLYST
Answer:
forst mark me as a brainleast
The temperature of a chemical solution is originally 21^\circ\text{C}21 ∘ C21, degrees, start text, C, end text. A chemist heats the solution at a constant rate, and the temperature of the solution is 75^\circ\text{C}75 ∘ C75, degrees, start text, C, end text after 121212 minutes of heating. The temperature, TTT, of the solution in ^\circ\text{C} ∘ Cdegrees, start text, C, end text is a function of xxx, the heating time in minutes. Write the function's formula. T=
Answer:
T(x) = 21 + 4.5x
Step-by-step explanation:
Given :
Original temperature = 21°C
Final temperature = 75°C
Time, x = 12 minutes
The temperature, T as a function of x, heating time in minutes :
We need to obtain the constant heating rate per minute :
Final temperature = initial temperature + (constant rate change,△t * time)
75 = 21 + 12△t
75 - 21 = 12 △t
54 = 12 △t
△t = 54 / 12
△t = 4.5°C
Hence, temperature change is 4.5°C per minute.
Hence,
T(x) = 21 + 4.5x
Answer:
T= 21+4.5x
Step-by-step explanation:
I got it right on Khan Academy
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A boat has a ladder that's ten feet long, and hangs off the side of the boat,
with its last two feet submerged in water. If the ocean tide rises five feet,
how much of the ladder will be underwater?
Answer:
2ft
Step-by-step explanation:
The tide doesn't effect the part of ladder that is underwater that is always 2ft
How much of the ladder that will be underwater is 7 ft.
Since the ladder is 10 ft long and its last two feet are submerged under water, this implies that 2 ft of the ladder are submerged under water.
When the tide rises by five feet, the part of the ladder that would be under water is 2 ft + 5ft = 7ft.
So, how much of the ladder that will be underwater is 7 ft.
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Through any two points there is exactly one _____
space.
plane.
line.
point.
Answer:
C. Line
Is the correct answer
8. Write the equation for a line that has a slope of 5 and a y-intercept of
negative 12.
Answer:
[tex]y=5x-12[/tex]
Step-by-step explanation:
This is in slope-intercept form, [tex]y=mx+b[/tex] where [tex]m[/tex] stands for the slope and [tex]b[/tex] stands for the y-intercept.
Hope this is helpful.
Step-by-step explanation:
equation of the line is given by the equation
y=mx+c
in this question you are given the slope (m) as 5 and the y intercept (c) as -12
therefore the equation will be
y=5x+(-12)
y=5x-12
Write the product as a single power. 6^(5) * 6^(2) * 6^(5)
Answer:
6^12
Step-by-step explanation:
add up all the exponents
[tex]\displaystyle\bf \boxed{a^m\cdot a^n=a^{m+n}}\\\\6^5\cdot 6^2\cdot6^5=6^{5+2+5}=\boxed{6^{12} }[/tex]
Carla packed this box with one centimeter cubes what is the volume of the box plus is it cubic centimeters or just centimeters or is it square centimeters pls help you'll get brainlist
Cubic centimetres since they are cubes. Did you add any picture of the question? There seems to be none.
instructions: state what additional information is required in order to know that the triangle in the image below are congruent for the reason given.
Given: SAS
Answer:
please I don't know can u please help me out
Answer:
The answer to your question where SAS is given
∠T ≈∠ W
2√4^3
find the rationalizing factor
Hello!
2√4³ =
2 × √4 ³ =
2 × 2³ =
2 × 8 = 16
Good luck! :)