Two blocks, M1 and M2, are connected by a massless string that passes over a massless pulley as shown in the figure. M2, which has a mass of 19.0 kg,
rests on a long ramp of angle =25.0∘.
Ignore friction, and let up the ramp define the positive direction.

If the actual mass of M1 is 5.00 kg and the system is allowed to move, what is the acceleration of the two blocks?

What distance does block M2 move in 2.00 s?

"Compression of rock is nothing but squeezing the rock together and shearing is pushing the rock in opposing directions."

It squeezes the boulder as a whole and should cause the pulls to shear. This is because compression causes the weight necessary for rocks to be squeezed. Additionally, the rock's draws shouldn't be spaced apart. It shouldn't be going in opposing ways either.

When rocks are compressed together, they fold, fracture, or even shatter. Compression stress is the most prevalent stress at convergent plate boundaries. There is stress when rocks are being torn apart. Under stress, rocks either lengthen or fragment.

Due to the compression pushing the hanging wall up in relation to the footwall, if the fault arises in a scenario of compression, it will be a reverse fault.

Compressional stresses cause a rock to shorten. A rock elongates or pulls apart as a result of tensional pressures. Shear forces cause rocks to slide past one another.

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Answer:

The henry (symbolized H) is the International System of Units (SI) derived unit of electrical inductance. Reduced to base SI units, one henry is the equivalent of one kilogram meter squared per second squared per ampere squared (kg m2 s-2 A-2).

The electrons in copper (Cu) are loosely bound to the nucleus is the most accurate answer

explain about the copper ?

Copper is a chemical element with the symbol Cu and atomic number 29. It is a soft, malleable, and ductile metal with high thermal and electrical conductivity. Copper has been used by humans for thousands of years for various purposes including coinage, electrical wiring, plumbing, and industrial machinery. It is commonly found in nature as copper oxide or copper sulfide, and it can be extracted through mining and refining processes. Copper is also an essential nutrient for all living organisms and plays important roles in biological processes such as the formation of red blood cells and the maintenance of the nervous and immune systems.

The electrons in copper (Cu) are loosely bound to the nucleus is the most accurate answer. This is because in metals like copper, the outermost electrons of atoms are not tightly bound to their respective nuclei, and can therefore move easily through the material, allowing for efficient conduction of electricity. On the other hand, in non-metal substances like carbon fiber, the electrons are more tightly bound to their respective nuclei, making it less efficient in conducting electricity.

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Answer:

(Question) Why is copper wire a better conductor of electricity than carbon fiber?

(Answer) The electrons in copper (Cu) are loosely bound to the nucleus

(Question) Which of the following best describes a direct current?

(Answer) An electrical current that flows in one direction

(Question) Which of the following substances would allow an electric current to flow through it easily?

(Answer) aluminum (Al)

(Question) Which of the following statements about electrical charges is true?

(Answer) Opposite charges attract one another

(Question) Which of the following statements best describes the relationship between atoms and conductivity?

(Answer) Atoms with a nearly empty valence shell make good conductors

Explanation:

i just finished the quick check

The magnitude of the velocity of the horse will be 8.89 m/s.

Given, the mass of the horse is 900 kg and the momentum of the horse is 8000 Kgm/s.

To calculate, the velocity of the horse from the given values.

Momentum of any body is defined as the product of the mass of the body and the velocity of that body.                                         Momentum(p) = Mass(m) × Velocity(v)

Keeping the provided values in the formula, momentum = mass × velocity to calculate the velocity of the horse

8000 Kgm/s =  900Kg × velocity

velocity = 8000/900 m/s = 8.89 m/s

So, the velocity of the horse is 8.89 m/s.

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Field representation of a positive or  of a positive or negative charge cannot be a representation for the gravitational field around one mass. It height from the ground must be determined.

The gravitational force is a kind of force by which an object attracts other objects into its center of a mass. Earth attracts every objects in its surface in to the ground and that is why we are all standing on the ground.

Gravitational force between two objects depends on their mass and distance between them. The field representation of the charge does not represent a gravitational field but it can show an electric field between them.

The height of the mass from the surface have to be determined to represent the gravitational field. The gravitational field is not at all depending on the charge of the object.

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The answer is option C. A baseball is heading upward after being thrown at an angle.

Kinetic energy is a type of energy associated with motion. It is defined as the energy an object possesses due to its motion, and is dependent on both the object's mass and its velocity. The formula for kinetic energy is KE = 1/2 mv^2, where m is the mass of the object and v is its velocity.

Kinetic energy can be transferred between objects, and is often involved in collisions and other interactions. For example, when a moving object collides with another object, some of its kinetic energy may be transferred to the second object. Kinetic energy is an important concept in physics and is used in many real-world applications, such as in the design of vehicles, machines, and athletic equipment.

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The cylinder rolls on the plane without slipping, and the string is parallel to the plane. Assume the cylinder has a radius of R and an inertia moment about its center of mass of I.

Tension in the string (T), the gravitational force on mass m (mg), and the frictional force on the cylinder from the plane are the forces acting on the system (f).

The tension in the string (T) is balanced by the gravitational force on mass m because the string is parallel to the plane (mg). As a result, we can write:

T = mg

To find the acceleration of mass m, we can use Newton's second law for the vertical motion of mass m:

mg - T = ma

Substituting T with mg, we get:

a = g - g(M/m)

where M/m is the ratio of the masses of the cylinder and the mass, respectively.

To find the condition on the ratio M/m for which the cylinder accelerates down the plane, we need to apply Newton's second law for the rotational motion of the cylinder. The torque acting on the cylinder is due to the frictional force f, which is given by:

f = μN

where μ is the coefficient of static friction, and N is the normal force on the cylinder from the plane. Since the cylinder rolls without slipping, the frictional force f is equal to the force due to the tension in the string, which is mg.

Therefore, we can write:

mg = f = μN

The normal force N is equal to the weight of the cylinder, which is Mg. Therefore, we can write:

mg = μMg

Simplifying, we get:

μ = m/M

For the cylinder to accelerate down the plane, the frictional force must be less than or equal to the maximum static frictional force, which is given by:

f_max = μ_s N

where μ_s is the coefficient of static friction. Therefore, we need to have:

f <= f_max

Substituting f and f_max, we get:

mg <= μ_s Mg

Substituting μ = m/M, we get:

mg <= μ_s Mg

Simplifying, we get:

m/M <= μ_s

Therefore, the condition on the ratio M/m for which the cylinder accelerates down the plane is:

M/m > μ_s

where μ_s is the coefficient of static friction between the cylinder and the plane.

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Taking into account the definition of density, the mass of 500.0 mL of propylene glycol, which has a density of 1.036 g/mL, is 518 g.

Density is the amount of matter in a given space and is defined as the amount of mass of a substance per unit volume.

In other words, density is defined as the amount of mass in a certain volume of a substance.

The expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

density= mass÷ volume

In this case, you know that:

Replacing in the definition of density:

1.036 g/mL= mass÷ 500 mL

Solving:

mass= 1.036 g/mL×500 mL

mass= 518 g

Finally, the mass is 518 g.

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Gulls are often observed dropping clams . When it hits the rocks, the shell is traveling at approximately 22.3 m/s.

The following equation for motion with constant acceleration caused by gravity can be used to determine the shell's velocity when it hits the rocks:

where v = v₀ + a × t

v is the shell's final velocity when it hits the rocks; v₀ is its initial velocity, which is 0 m/s since it was dropped from rest; a is the acceleration caused by gravity (9.8 m/s²); and t is the time it takes for the shell to fall to the rocks. We can use the vertical displacement equation to determine the time t.

y = v₀ × t + (1/2) × a × t²

17 m = 0 m/s × t + (1/2) × 9.8 m/s² × t²

17 m = 4.9 m/s² × t²

t = √(17 m / 4.9 m/s²)

t = 2.28 s

Now that we have the time t, we can substitute it back into the equation for velocity:

v = v₀ + a × t

v = 0 m/s + 9.8 m/s² × 2.28 s

v = 22.3 m/s

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a. The total energy is 10.75 J

b. The elastic potential energy at t= 1.25 s is 2.69 J

Energy is the ability to do work.

Elastic potential energy is energy stored in a spring.

The total energy of the system is the maximum elastic potential energy of the system. It is given by E' = 1/2kx'² where

Given that

Substituting the values of the variables into the equation, we have that

E = 1/2kx'²

= 1/2 × 21.5 N/m × (1.0 m)²

= 1/2 × 21.5 N/m × 1.0 m²

= 10.75 Nm

= 10.75 J

The total energy is 10.75 J

The potential energy stored in the system is given by

E = 1/2kx² where

At t = 1.25 s from the graph, x = -0.5 m

Since k = 21.5 N/m, substituting the values of the variables into the equation, we have

E = 1/2kx²

E = 1/2 × 21.5 N/m × (-0.5 m)²

E = 1/2 × 21.5 N/m × 0.25 m²

E = 10.75 N/m × 0.25 m²

E = 2.6875 Nm

E = 2.6875 J

E ≅ 2.69 J

The potential energy is 2.69 J

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The water gauge pressure at location P is;

P p = 104525 Pa

We have been provided;

L = 4 cm = 0.04 m needle length

Water's viscosity; = 1 10(-3) Pa

r = 1 mm = 0.001 m Radius

v = 10 m/s is the speed.

The flow rate via a cylindrical pipe may be calculated using Poiseuille's equation for viscous liquid flow.

Q = (ΔP•πr⁴)/(8ηL)

Flow rate is now also written as;

Q = πr²v

Thus;

πr²v = (ΔP•πr⁴)/(8ηL)

This boils down to;

v = (ΔP•r²)/(8ηL)

Inserting the necessary values;

10 = (ΔP × 0.001²)/(8 × 10^(-3) × 0.04)

ΔP = (10 × 8 × 10^(-3) × 0.04)/(0.001²)

ΔP = 3200 Pa

This implies that;

P atm - P p = P

Where;

P p is the water gauge pressure at point P.

P atm is atmospheric pressure, which equals 101325 Pa.

Thus;

P p - 101325 = 3200

P p = 101325 + 3200

P p = 104525 Pa

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Answer:

The Force of Friction:

Friction is a self-adjusting force. The block in the question is moving with constant velocity under the force of 5 N. This implies that the force of kinetic friction acting on the block is also 5 N, acting opposite to the applied force and net force on the block is

When acceleration is equal to zero average velocity and the instantaneous velocity vectors are identical.

Types of velocity

Velocity is defined as the rate of displacement of an object with respect to time. It is measured in meter/ seconds and is a vector quantity.

Acceleration is defined as the rate at which velocity changes with time.

There are two types of velocity which includes:

Average velocity: This is the average rate of change of position of particles with respect to time over an interval.

Instantaneous velocity: This is defined as the specific rate of change of position with respect to time at a particular point.

The situation that will make the average velocity and the instantaneous velocity vectors to be equal or identical is when acceleration is equal to zero.

The Little Albert experiment is controversial and ethically questionable by today's standards, as it involved intentionally inducing fear in a child and potentially causing lasting psychological harm

The experiment you are describing is known as the "Little Albert" experiment and was conducted by John B. Watson and his graduate student Rosalie Rayner in 1920. The purpose of the experiment was to demonstrate the principles of classical conditioning, which is a type of learning where an individual learns to associate a neutral stimulus with a meaningful stimulus and responds accordingly.

In the case of Little Albert, the white rat was initially a neutral stimulus that did not elicit any fear or emotional response from him. However, when Watson and Rayner paired the presentation of the rat with a loud, startling noise (the unconditioned stimulus), Little Albert began to associate the two stimuli and developed a fear response (the conditioned response) to the rat alone (the conditioned stimulus).

Watson and Rayner then went on to demonstrate that Little Albert's fear response had generalized to other similar stimuli, such as other furry animals and even a Santa Claus mask. This demonstrated the idea of stimulus generalization, where a conditioned response can be elicited by stimuli that are similar to the original conditioned stimulus.

The true identity of Little Albert was never definitively established, and it is not known what became of him after the experiment.

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The statement that is true about momentum is as follows: Momentum is a vector (option D).

Momentum is the tendency of a body to maintain its inertial motion. It is the product of its mass and velocity, or the vector sum of the products of its masses and velocities.

Momentum is a vector quantity i.e. it has both magnitude and direction.

Since momentum is a product of mass and velocity, it's S.I unit is kgm/s or N/s.

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Momentum is that momentum is a vector quantity. Therefore, the answer is option D.Momentum is a property of objects that are moving, that is, an object's tendency to stay in motion. Momentum is a measure of an object's motion or its inertia in motion.

An object's momentum is calculated as the product of its mass and its velocity, with the direction of momentum being the same as the direction of velocity.Vector and scalar quantitiesMomentum is a vector quantity because it has both magnitude and direction. A scalar quantity, on the other hand, is a quantity that has only magnitude and no direction.

For example, speed is a scalar quantity because it is defined as distance divided by time and has only magnitude (no direction).In physics, there are two types of quantities: vector quantities and scalar quantities. A vector quantity is a quantity that has both magnitude and direction, whereas a scalar quantity is a quantity that has only magnitude.

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Answer:

Explanation:

p=227/3=75.66Pascal

[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Pressure is defined as : Force per unit Area

[tex]\qquad \sf  \dashrightarrow \: p = \dfrac{force}{area} [/tex]

[tex]\qquad \sf  \dashrightarrow \: p = \dfrac{227}{3} [/tex]

[tex]\qquad \sf  \dashrightarrow \: p \approx75.67 \: \: pascals[/tex]

[ note : to get pressure in pascals, force and area should be in S.I unit, it's given in S.I unit in given question, but if not you can make conversion first and then solve ]

Tension is a force along the length of a medium, especially a force carried by a flexible medium, such as a rope or cable.

The tension in the cord is approximately 10624 N.

To solve this problem, we can use the principles of Newton's laws and apply them to each of the objects involved. We will also use the fact that the tension in the cord is the same on both sides of the pulley (neglecting any friction or mass in the pulley).

First, we can consider the forces acting on the block (m1). The only forces acting on the block are its weight (mg) and the tension in the cord (T), which is directed upward. We can resolve these forces into components parallel and perpendicular to the inclined plane:

The weight of the block has a component parallel to the inclined plane given by [tex]mg*sin(θ)[/tex].

The tension in the cord has a component parallel to the inclined plane given by [tex]T*sin(θ)[/tex].

Using Newton's second law, we can write:

[tex]m1 * a = T * sin(θ) - m1 * g * sin(θ)[/tex]

where a is the acceleration of the block down the inclined plane.

Next, we can consider the forces acting on the sphere ([tex]m2[/tex]). Since the sphere is hanging from the cord, the only force acting on it is its weight ([tex]mg[/tex]), which is directed downward. Using Newton's second law, we can write:

[tex]m2 * a = m2 * g - T[/tex]

where a is the acceleration of the sphere downward.

Since the cord is assumed to be massless and the pulley is assumed to be frictionless, the tension in the cord is the same on both sides of the pulley. Therefore, we can set the two expressions for T equal to each other:

[tex]T * sin(θ) - m1 * g * sin(θ) = m2 * g - T[/tex]

Solving for T, we get:

T = [tex](m2 + m1) * g / (sin(θ) + 1)[/tex]

Substituting the given values, we get:

T = [tex](540 kg + 2.00 kg) * 9.81 m/s^2 / (sin(49.0°) + 1)[/tex]

T = 10624 N (to three significant figures)

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Two charged objects are separated a distance d,  the position vector of the object 1 with respect to the object 2 is P21 = d/2(√3i -j).

It is assumed in the problem that the origin is taken into account when determining the position of object 2. As a result, we may decompose the position vector of object 1 into its x and y components.

So, we can see from the diagram that the position vector's horizontal component is dcos30. This component is known as the x component because it lines up with the positive x axis. Hence, x=dcos30. Once more, dsin30 is the vertical component of the position vector. This component is known as the y component because it is congruent with the negative y axis. Hence, y=dsin30.

As a result, the position vector can be expressed as,

⇒P21=xi^+y(−j^)

The values P21=dcos30i+dsin30(j) are substituted

Now, the values of cos30 are 3-1/2 and sin30 are 12.

In order to substitute the values, we obtain P21=3-2di12dj.

Now, if we take the common, we get P21 = d/2(√3i -j).

This is the position vector of the object 1 with respect to the object 2.

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After a workplace incident requiring first aid, is it beneficial to review the first aid response because:

1) The WHS Act and Regulations make it a legal duty.

2) That the initial responder/s were properly trained for the occurrence.

3) Verify the efficacy of the workplace's first aid strategy and risk management procedure.

A review of first aid occurrences may be required by the workplace health and safety (WHS) act and regulations to confirm that correct procedures and protocols were followed and to identify any areas for improvement.

Confirming that the first aider/s had the requisite training for the event is critical to ensuring that the appropriate steps were taken during the incident and that the first aider/s were equipped with the knowledge and abilities to respond correctly.

After an event, review the first aid response to confirm the success of the workplace's first aid strategy and risk management approach. This can aid in identifying areas for development and preparing the workplace for similar situations in the future. The study may involve assessing the availability and accessibility of first aid equipment and supplies, as well as first aid personnel response time.

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The ball needs to go at least  speed is 13 m/s per second to be able to clear the ceiling.

angle should you toss the ball 46.26°.

From the query, we learn that

We are 6.0 metres away from one home wall.

who is 6.0 metres from the wall across from you.

Both the throw and the catch take place one metre above the ground.

Assume that you and your companion are both 6.0 metres from the edge of the roof.

The Newtons equation for the distance is typically expressed numerically as

[tex]s=v*t+\frac{a}{2}*t^{2}\\5=0*t+4.9*t^{2}\\t=1.04[/tex]

Therefore

[tex]2*t = 2.0s[/tex]

Where

[tex]18=V_{x} *2.0\\V_{x} =8.9[/tex]

And

[tex]5=V_{y} *1.04-4.9*1.04^{2}\\V_{y} =9.8[/tex]

Therefore

[tex]V=\sqrt{V_{y}^{2}+V_{x} ^{2} } \\V=\sqrt{(9.8)^{2}+(8.9)^{2}} \\\V=13m/s[/tex]

In order to determine the angle at which you should toss the ball, you must first calculate the distance between you and your friend. This is done by using the Pythagorean Theorem to calculate the hypotenuse of the right triangle formed by the two walls and the distance between you and your friend:

[tex]C = \sqrt (6.0m)^2 + (6.0m)^2 \\ = 8.485m[/tex]

Now you can calculate the angle using trigonometry. Since the triangle is a right triangle, you can use the inverse tangent function to calculate the angle:

tan⁻¹[tex](\frac{6.0m}{8.485m})[/tex] = 46.26°

Therefore, you should toss the ball at an angle of 46.26°.

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If m1 > m2, then the sign of the velocity of m2, v2, will be positive after the collision.

Why is the velocity positive?

This is because in a one-dimensional collision, the momentum of the system is conserved. Before the collision, only m1 has momentum, so the total momentum is mv0. After the collision, the two masses stick together, so the total momentum is (m1 + m2) * v, where v is the velocity of the combined masses.

Conservation of momentum gives:

mv0 = (m1 + m2) * v

Solving for v gives:

v = mv0 / (m1 + m2)

Since m1 > m2, the denominator is larger than the numerator, so v is smaller than v0. Therefore, after the collision, both masses will be moving in the positive x direction, and m2 will have a positive velocity, v2, while m1 will have a smaller positive velocity, v1. The actual values of v1 and v2 depend on the specific details of the collision (e.g., whether it is elastic or inelastic).

So the velocity of m2, v2, will be positive after the collision.

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Answer: B

Explanation: The best answer is B. A baseball thrown by a professional pitcher. Momentum is the product of an object's mass and its velocity. Since the baseball has the greatest velocity of all the objects listed, it has the greatest momentum.

The average speed of the school bus while the bus is slowing down is 5m/s.

Initial velocity, u = 15 m/s.

Distance traveled, d = 55 m.

Time is taken, t = 11 s.

Final velocity, v = 0 m/s.

We know, average velocity is given by :

[tex]v_a_v_g= \frac{distance}{time} = \frac{55}{11} = 5m/s[/tex]

Therefore, the average velocity is 5 m/s.

The pace is measured as the ratio of distance to the time wherein the distance is turned into a blanket. the pace is a scalar quantity because it has the most effective course and no importance. For the size of the pace in vehicles, speedometers are used. pace also can be calculated with the assistance of a graph. the space-time graph allows know-how of the rate of an object.

In regular use and in kinematics, the rate of an object is the value of the change of its position over the years or the importance of the alternate of its function per unit of time; its miles as a result a scalar amount. the spot pace is the limit of the common pace because the period of the time c program language period approaches 0. pace isn't always similar to velocity.

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Answer:

It's False

Explanation:

I know :)

True. "A strength training program is built on a series of exercises that targets specific muscle groups. "

Strength is the ability of a muscle or group of muscles to exert force against a resistance. It is often measured by the maximum amount of weight or resistance that a person can lift or move in a single repetition, commonly referred to as their "one-rep max." Strength can be developed through resistance training, which involves working against progressively heavier loads or resistance over time, causing the muscle fibers to adapt and become stronger. Building strength can have a variety of benefits, including improved athletic performance, increased bone density, and better overall physical health and well-being.

By targeting specific muscle groups with exercises, strength training programs can help individuals build muscle mass, increase bone density, improve balance and coordination, and enhance overall physical performance. Additionally, strength training has been shown to have many health benefits, such as reducing the risk of chronic diseases, improving mental health, and enhancing overall quality of life.

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Two blocks are attached to either end of a light rope that passes over a light, the change in gravitational PE is 11.76, -15.68j,  0.2T, -0.2T and speed is 0.7483 m/s.

partA] change in gravitational PE :

U6 = m1gh = 6*9.8*0.2 = 11.76 J

 U8 = -m2gh = -8*9.8*0.2 = -15.68 J

ANSWER = 11.76, -15.68

partB] W6 = T*0.2 = 0.2T

W8 = T*-0.2 = -0.2T

  answer = 0.2T, -0.2T

partC] WT = 0.2T-0.2T = 0

    deltaUg = 11.76-15.68 = -3.92 J

   increase in KE = 3.92J

   speed v = sqrt(2KE/(m1+m2))= sqrt(2*3.92/14) = 0.7483 m/s

  answer = 0,-3.92, 0.7483

The pace is measured as the ratio of distance to the time wherein the distance is turned into a blanket. the pace is a scalar quantity because it has the most effective course and no importance. For the size of the pace in vehicles, speedometers are used. pace also can be calculated with the assistance of a graph. the space-time graph allows know-how of the rate of an object.

In regular use and in kinematics, the rate of an object is the value of the change of its position over the years or the importance of the alternate of its function per unit of time; its miles as a result a scalar amount. the spot pace is the limit of the common pace because the period of the time c program language period approaches 0. pace isn't always similar to velocity.

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Answer: Vitamins

Explanation:

Answer:

the driver does 29,400 J of work in pushing the car to the gas station.

Explanation:

To find the amount of work done by the driver, we need to know the force applied by the driver and the distance the car is moved.

The force applied by the driver is given as 140 N, and the distance the car is moved is given as 210 m.

Work done can be calculated using the formula:

W = F * d * cos(θ)

where W is the work done, F is the force applied, d is the distance moved, and θ is the angle between the force and the displacement. Since the force and displacement are in the same direction, θ = 0, and the cosine of 0 is 1.

So,

W = F * d * cos(θ) = 140 N * 210 m * 1 = 29,400 J

Answer:

Explanation: POTENTIAL ENERGY is stored energy, energy ready to go. A race car at the starting line of a race, a bicycle on top of a hill, and students waiting to go home from school are all examples of potential energy.

A moving bicycle has mechanical energy. When you apply the brakes, the bicycle's mechanical energy is not destroyed. The mechanical energy is transformed into thermal energy. Friction between the brake pad of a car and the moving wheel transforms mechanical energy into thermal energy (heat).

During braking, 60% of the kinetic energy of the bicycle and rider is converted to thermal energy in the brake blocks.

The rms voltage measured across the secondary coil is 565.68 V.

The root mean square (RMS) value of an alternating current (AC) or voltage is the equivalent steady direct current (DC) value that produces the same heating effect or power dissipation in a resistor. In other words, it is the DC voltage or current that would produce the same amount of heat as the AC voltage or current over a given time period.

The rms voltage (V_rms) across the secondary coil can be calculated using the formula:

V_rms,secondary = (N_secondary/N_primary) * V_rms,primary

where N_secondary is the number of turns in the secondary coil, N_primary is the number of turns in the primary coil, and V_rms,primary is the rms voltage across the primary coil.

The rms voltage across the primary coil can be found from the given voltage function:

V_rms,primary = (1/√2) * V_peak,primary

where V_peak,primary = 200 V is the peak voltage across the primary coil.

Substituting the values, we get:

V_rms,primary = (1/√2) * 200 V = 141.42 V

Now, using the formula above, we can calculate the rms voltage across the secondary coil:

V_rms,secondary = (700/175) * 141.42 V = 565.68 V

Therefore, the rms voltage measured across the secondary coil is 565.68 V.

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The radius of the oil droplet in this experiment is approximately 1.11 x 10^-7 meters.

The Millikan oil-drop experiment was designed to determine the fundamental unit of electrical charge, the charge on a single electron, by observing the behavior of charged oil droplets suspended in an electric field. To calculate the radius of an oil droplet given the electric field strength and the charge on one electron, we can use the following formula:

q = mg / E

where q is the charge on the droplet, m is the mass of the droplet, g is the acceleration due to gravity, and E is the electric field strength.

Assuming that the droplet has only one excess electron and that its weight is balanced by the electric force of the field on that electron, we can write:

q = e

where e is the charge on one electron.

Equating these two expressions for q, we can solve for the mass of the droplet:

mg / E = e

m = eE/g

Next, we can use the density of the oil droplet to calculate its volume and then its radius:

[tex]V = (4/3)πr^3 = m/ρ[/tex]

[tex]r = [(3m/4πρ)]^(1/3)[/tex]

where ρ is the density of the oil.

Substituting in the given values, we get:

[tex]m = eE/g = (1.60 x 10^-19 C)(6.45 x 10^4 N/C)/(9.81 m/s^2) = 1.04 x 10^-14 kg[/tex]

ρ = 0.90 g/cm^3 = 900 kg/m^3

[tex]r = [(3m/4πρ)]^(1/3) = [(3(1.04 x 10^-14)/(4π)(900))]^(1/3) = 1.11 x 10^-7 m[/tex]

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