Two charged objects are separated a distance d, the position vector of the object 1 with respect to the object 2 is P21 = d/2(√3i -j).
It is assumed in the problem that the origin is taken into account when determining the position of object 2. As a result, we may decompose the position vector of object 1 into its x and y components.
So, we can see from the diagram that the position vector's horizontal component is dcos30. This component is known as the x component because it lines up with the positive x axis. Hence, x=dcos30. Once more, dsin30 is the vertical component of the position vector. This component is known as the y component because it is congruent with the negative y axis. Hence, y=dsin30.
As a result, the position vector can be expressed as,
⇒P21=xi^+y(−j^)
The values P21=dcos30i+dsin30(j) are substituted
Now, the values of cos30 are 3-1/2 and sin30 are 12.
In order to substitute the values, we obtain P21=3-2di12dj.
Now, if we take the common, we get P21 = d/2(√3i -j).
This is the position vector of the object 1 with respect to the object 2.
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How much of the total energy in Problem 3 and 4 has been transformed to kinetic energy?
Answer:
Explanation:To find the change in kinetic energy, we subtract the initial energy from the final energy. This answer in positive because the car gains energy when it increases its velocity.
The energy of the flower pot is potential energy. The potential energy of the flower pot when it weighs 3 N in a height of 300 m is 900 J.
What is potential energy ?Potential energy of an object is the energy generated by virtue of its position whereas, kinetic energy is the energy generated by virtue of its motion.
Potential energy = mass x gravity x height
Given the weight of the flower pot is 3N. That is the force by gravity. Then displacement = 300 m.
Thus, P = 3 m × 300 m = 900 J.
If the flower pot is placed at a height of 10 m, the potential energy reduces as follows:
Potential energy = 3 x 10 m = 30 J.
Remaining energy is converted to the kinetic energy
ie. 900 J - 30 J = 870 J
Therefore, 870 J is transformed to kinetic energy.
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Your question is incomplete. But your complete question probably was:
A flower pot weighing 3 newtons is sitting on a windowsill 300 meters from the ground is the energy of the flower pot potential of kinetic? How many joules is this?
When the flower pot in problem 3 is only 10 meters from the ground, what is its potential energy?
How much of the total energy in problems 3 and 4 has been transformed to kinetic energy?
A ball strikes the floor for 0.0105 s and experiences a change in momentum of 1.52 kg·m/s. What is the force experienced by the ball?
A.) 1.60N
B.)144.76N
C.)23.82N
D.)0.016N
Pic is attached below
The force experienced by an object is 144.76 N.
O\ption B is correct.
What is force?A force is described as an influence that can change the motion of an object or that can cause an object with mass to change its velocity
The force can be calculated using the equation of force = change in momentum / time.
So, force = 1.52 kg·m/s / 0.0105 s = 145 N
Therefore, the answer is 144.76 N.
Some types of force available includes the following:
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Question 6 of 10
When making a winter coat, you should pick a fabric that has which
characteristic?
A. Heavyweight
OB. Warm
C. Resistant to wear
D. All of the above
Answer: Warm
Explanation:
4. A skier with a mass of 55 kg is skiing down a snowy slope that has an incline of 30°. Find the coefficient of kinetic friction for the skier if friction is known to be 25 N.
The coefficient of kinetic friction for the skier if the magnitude of frictional force is 25N will be 0.04638.
What is Kinetic friction?Kinetic friction can be defined as a force which acts between the moving surfaces. A object moving on the surface experiences a force in the opposite direction of the movement. The magnitude of the force will also depend on the coefficient of kinetic friction between the two objects.
F = μk Fn
where, F is the frictional force,
μk is the coefficient of kinetic friction,
Fn is the normal force
Fn = mass × acceleration due to gravity
Fn = 55 × 9.8
Fn = 539N
F = μk Fn
F = 25N,
25 = μk × 539
μk = 25/ 539
μk = 0.04638
Therefore, the coefficient of kinetic friction will be 0.04638.
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In the 2nd lab you were studying water squirting out from a hole in a cylinder filled with water into a tub. Just as a falling ball converts potential energy to kinetic energy, water pressure pushed water out of the hole by converting potential energy per unit volume (density x g x height) to kinetic energy per unit volume (density x velocity^2/2). Assume you have a 20 cm head of water above the hole and that the hole is 40 cm above ground.
What is the horizontal speed at which the water leaves the hole in units of ms^-1?
The horizontal speed at which the water leaves the hole is[tex]4.09 ms^-1.[/tex]
What is speed?Speed is the rate of change of the position of an object in a given direction. It is expressed as the distance traveled per unit of time, typically measured in meters per second (m/s). It is also commonly represented by the symbol ‘v’. Speed is a scalar quantity, meaning it has only magnitude, not direction.
The kinetic energy per unit volume at the point of the hole is equal to the density of the water multiplied by one-half the square of the velocity of the water leaving the hole.
Since these two values are constant across a horizontal streamline, we can set up the following equation:
[tex]ρgh = ρ(v^2/2)[/tex]
Solving for v, we get:
[tex]v = √(2gh)[/tex]
Plugging in the values for the height of the water above the hole (h = 0.4 m) and the acceleration due to gravity[tex](g = 9.81 ms^-2)[/tex], we get:
[tex]v = √(2*9.81*0.4) = 4.09 ms^-1[/tex]
Therefore, the horizontal speed at which the water leaves the hole is [tex]4.09 ms^-1.[/tex]
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You use a ruler marked with 1 mm increments to measure the lengths of the height h of a block and find h = 121 mm. According to the half least count rule, what is the uncertainty in your measurement of the height?
The uncertainty in height is, 0.5 mm.
The "half least count rule" states that the uncertainty in a measurement is equal to half of the smallest division on the measuring instrument. In this case, the ruler is marked in 1 mm increments, so the smallest division is 1 mm.
Using the half least count rule, the uncertainty in the measurement of the height is,
uncertainty = 1/2 * 1 mm = 0.5 mm
Therefore, the uncertainty in the measurement of the height is 0.5 mm. We can express the result as,
h = 121 ± 0.5 mm
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"If your primary goal is to build strength and increase muscle mass, you could____
increase the amount of aerobic activity
expand the number of anaerobic activities per week
complete workout sets of high repetitions and low weight (example: 3 sets of 20 repetitions with 5lb or less)
If one's primary goal is to build strength and increase muscle mass, completing workout sets of high repetitions and low weight is correct that is the last option, as the aerobic activity would not increase the muscle.
What is the importance of the muscle-building exercise?Anaerobic activities should be prioritized because they force the muscles to work at high intensity for short periods of time; this type of training is typically done with heavy weights for fewer repetitions and sets and builds the muscles.
Hence, if one's primary goal is to build strength and increase muscle mass, completing workout sets of high repetitions and low weight is correct that is the last option, as the aerobic activity would not increase the muscle.
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using only the electrical specifications, determine how deep the external underground secondary service conduits are installed.
However, typically, electrical codes require that buried secondary service conduits be installed at a minimum depth of 18 inches (45.7 cm) below the surface. In some cases, local codes may require a deeper depth, such as 24 inches (60.9 cm) or more, depending on factors such as soil type, climate, and intended use of the conduit.
It is also important to note that other factors, such as the type and size of conduit, the type of wiring used, and the intended electrical load, may also affect the required burial depth. Therefore, it is essential to consult with local building codes and a licensed electrician or electrical engineer to determine the appropriate depth for installing external underground secondary service conduits.
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You are fixing the roof of your house when a hammer breaks loose and slides down. The roof makes an angle of 45 ∘ with the horizontal, and the hammer is moving at 4.5 m/s when it reaches the edge. Assume that the hammer is moving from the top of the roof to its right edge.
1. What is the vertical component of the hammer's velocity just as it leaves the roof?
The hammer travels at 3.9 m/s in its horizontal direction. The roof is at an angle with the horizontal when the hammer is dropped from a height of v along it.
Describe a velocity example.The speed with which something travels in a specific direction is known as its velocity. As an illustration, think of the movement of a car driving north on either a highway or the speed at which a rocket takes off.
When does acceleration differ from velocity?The change in displacement is measured in terms of velocity. The speed of change in velocity is known as acceleration. Given that it has both a magnitude and a direction, mass and velocity quantity. Being merely the change in frequency, accelerating is also an vector quantity.
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A 4-kg fish swimming at a speed of 2 m/s swallows an absent-minded 1-kg fish at
rest. The speed of the larger fish after lunch is
6/5 m/s.
1 m/s.
5/6 m/s.
2/5 m/s.
8/5 m/s.
In first case speed of fish will be ⅚ m/s.
In the second case the speed of fish ⅙ m/s
Given data :-
Mass of bigger fish ( m₁ ) = 5 kg
Mass of small fish ( m₂ ) = 1 kg.
Speed of large fish ( v₁ ) = 1 m/s
Mass of bigger fish after eating smaller ones = 5 + 1 = 6 kg.
Case - 1
Momentum of bigger fish before eating the smaller fish = m₁* v₁ = 5 * 1 = 5 kg.m/s
Momentum of bigger fish after eating the larger fish = ( m₁ + m₂)*v
v = speed of bigger fish immediately after lunch.
Using the conservation of momentum.
m₁* v₁ = ( m₁ + m₂)*v
5 = 6 * v
v = m/s.
Case -2
Speed of small fish = 4 m/s
Momentum of bigger fish before lunch = 5 kg.m/s
Momentum of smaller fish before lunch = 4*1 = 4 kg.m/s
Net momentum before lunch = 5 - 4 = 1 kg.m/s
Momentum of bigger fish after eating the larger fish = 6 * V
Using the conservation of momentum.
1 = 6 * V
V = m/s.
What is conservation of momentum?
This indicates that a conserved quantity is represented by a variable in an equation that is constant over time. Its value is the same whether an event occurs before or after it.In physics, there are a lot of conserved quantities. For making forecasts in what would otherwise be exceedingly complex situations, they are frequently remarkably useful. There are three fundamental quantities in mechanics that are conserved. These include angular momentum, momentum, and energy. Most often, collisions between objects are described using the principle of conservation of momentum.To know more about conservation of momentum, click the link given below:
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Evan is a championship runner of the school's track team. During one of his trials, his speed was measured at 10.1 m/s. Find Evan's kinetic energy during that trial if his mass is 58.6 kg.
Evan's kinetic energy during the trial was [tex]295.99 kg m^2/s^2.[/tex]
What is energy?Energy is defined as the capacity for doing work. It is the ability to cause change or to make things happen. It exists in many forms and can be derived from various sources such as the sun, wind, water, and even nuclear power. Energy can be transformed from one form to another, such as when electricity is generated from the sun or when mechanical energy is converted into electrical energy. Energy can also be stored in batteries, stored in the form of potential or kinetic energy, or even converted into thermal energy.
Kinetic energy (KE) is the energy an object has due to its motion. It is calculated using the equation [tex]KE = 1/2 mv^2[/tex], where m is the mass of the object and v is its velocity.
In Evan's case, his mass is 58.6 kg and his velocity is 10.1 m/s. Therefore, his kinetic energy during the trial can be calculated as follows:
[tex]KE = 1/2 * 58.6 kg * (10.1 m/s)^2KE = 295.99 kg m^2/s^2[/tex]
Therefore, Evan's kinetic energy during the trial was [tex]295.99 kg m^2/s^2.[/tex]
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A 50-kg student pulls on a rope attached to a 2-kg box, which moves at constant speed along a smooth surface, as shown. Which of the following corresponds to a force pair? The friction between the box and the surface, and the horizontal component of the push on the box. The normal force on the box and the weight of the box. The push on the box by the student and the push on the student by the box. The vertical component of the push applied by the student and the weight of the box. The weight of the box and the weight of the student. There are no force pairs because the acceleration of the box is zero.
Correct option at constant speed is "The push on the box by the student and the push on the student by the box" due to Newton's Third Law.
This is because every force has an equal and opposite reaction force according to Newton's Third Law of Motion. In this case, the student is pulling the rope, which exerts a force on the box, and the box is exerting an equal and opposite force on the student through the rope.
The other options listed do not correspond to a force pair because they either involve a single force acting on an object or two forces that are not equal and opposite. The normal force on the box and the weight of the box, for example, are two forces acting on the same object but are not equal and opposite. Similarly, the weight of the box and the weight of the student are two different forces acting on different objects and are not equal and opposite.
It's important to note that even though the box is moving at a constant speed, there are still forces acting on it. In this case, the force of friction is balancing the force applied by the student, resulting in zero net force and constant velocity.
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IP An expectant father paces back and forth, producing the position-versus-time graph shown in the figure
Calculate the numerical value of the father's velocity for segment C
(part a)
Calculate the numerical value of the father's velocity for segment D.
(part b)
An expectant father paces back and forth. The value of C in units is 1 m/s; The value of D in units is -1.5 m/s.
What is velocity?The speed and direction of an object's motion are measured by its velocity. It is a vector quantity, which means that it has magnitude (or direction) and magnitude (or size). Meters per second (m/s) is a common unit of velocity. It is the rate at which an object moves in a specific direction. Typically, velocity is calculated by taking the time derivative of the position function.
Fathers Velocity for Segment C,
[tex]V_{c}[/tex] = (3- 2)/(3-2)
[tex]V_{c}[/tex] = 1 m/s
Fathers Velocity for Segment D,
[tex]V_{d}[/tex] = (0 - 3)/(5 - 3)
[tex]V_{d}[/tex] = -3/2
[tex]V_{d}[/tex] = - 1.5 m/s
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b) A ball is kicked by a footballer. The average force on the ball and the impact last for time interval 0.25 s. Calculate the cha momentum and also state the direction of change in more (Ans: 60 kg m/s) b)
60 kg m/s is the answer because you gave it and I thought you are telling ruth also you are a big questioner and also you should check with your doctor and go out and go touch the grass.
A planet of mass 6 × 10^24 kg is at location ‹ −3 × 10^11, 8 × 10^11, 0 › m. A star of mass 7 × 10^30 kg is at location ‹ 7 × 10^11, −5 × 10^11, 0 › m. What is the force exerted on the planet by the star? (It will probably be helpful to draw a diagram, including the relevant vectors.)
The force exerted on the planet by the star is 3.52 x 10²² N.
What is Newton's law of gravitation?Newton's law of gravitation is a fundamental law of physics that describes the force of gravitational attraction between two objects with mass. The law was first described by Sir Isaac Newton in 1687 and is one of the three laws that form the basis of classical mechanics.
To find the force exerted on the planet by the star, we can use Newton's law of gravitation, which states that the force between two objects with masses M1 and M2 and a distance r between their centers is given by:
F = G × M1 × M2 / r²
where G is the gravitational constant, which has a value of 6.67 x 10⁻¹¹ N*m²/kg².
We can first calculate the distance between the planet and the star by taking the difference between their positions:
r = √[(7 x 10¹¹ - (-3 x 10¹¹))² + (-5 x 10¹¹ - 8 x 10¹¹)² + 0²] = 1.38 x 10¹² m
Next, we can calculate the force exerted on the planet by the star:
F = G × M1 × M2 / r²
F = (6.67 x 10⁻¹¹ N*m²/kg²) × (6 x 10²⁴ kg) × (7 x 10³⁰kg) / (1.38 x 10¹² m²)
F = 3.52 x 10²²N.
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A hollow metal sphere has inner radius a and outer radius b. The hollow sphere has charge +2 Q. A point charge + Q sits at the center of the hollow sphere.
Determine the magnitude of the electric field in the region r≤a
The magnitude of the electric field in the region r≤a is zero.
What is Point Charge?
A point charge is a theoretical charge that is assumed to be located at a single point in space, with all of its electric charge concentrated at that point. It is an idealized model that is often used to simplify calculations in electromagnetism. A point charge can be either positive or negative and is characterized by its electric charge, which is a fundamental property of matter. The electric field created by a point charge decreases with distance from the charge, following an inverse square law. The concept of a point charge is often used in electrostatics, where the charge distribution of an object can be approximated as a collection of point charges.
Inside the hollow metal sphere (i.e., for r≤a), the electric field is zero because the excess charge +2Q on the sphere redistributes itself to cancel out the electric field due to the central charge +Q.
This can be shown using Gauss's Law. A spherical Gaussian surface of radius r≤a, centered at the center of the sphere and inside the metal shell, encloses only the point charge +Q. By symmetry, the electric field is radial and has the same magnitude at every point on the Gaussian surface. By Gauss's Law, the total electric flux through the surface is proportional to the charge enclosed by the surface. Since there is no charge inside the surface (because the excess charge on the metal sphere cancels out the charge inside it), the total electric flux through the surface is zero. Therefore, the electric field inside the hollow metal sphere is zero.
Thus, the magnitude of the electric field in the region r≤a is zero.
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3. What is the velocity of a 1.5 kg ball that has a momentum of 4.5 kg*m/s?
If a 1.5 kg ball has a momentum of 4.5 kg*m/s, the velocity of the ball is 3 m/s.
How to find the velocity of the ball?According to the question, the given quantity is,
Mass of the ball = 1.5 kg
The momentum of the ball = 4.5 kg. m/s
The momentum is defined as the product of the mass of the object and the velocity of the object, so p = mv.
p = momentum of an object
m = mass of an object
v = velocity of an object
According to question the given value outs in the formulae,
p= mv
4.50 = 1.50 × v
v = 4.50/ 1.50
v = 3 m/s.
Therefore, the velocity of the ball is 3 m/s.
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A 1500 kg car traveling east at 20 m/s collides with a moving 2500 kg truck moving 30 m/s west.. After they collide, the two interlock and move together. What was the final velocity of the truck? (Hint-momentum is a vector and direction matters, use + or - values as appropriate)* A. 11.25 m/s west B. 11.25 m/s east C. 32.6 m/s east D. 32.6 m/s west
The final velocity of the truck after the collision is -11.25 m/s.
A. 11.25 m/s west How to find the final velocity?In this collision, the total momentum of the system before the collision is equal to the total momentum of the system after the collision, since momentum is conserved. The total momentum of the system before the collision can be found by adding up the momenta of the car and truck.
The momentum of the car is given by:
= mass of car * velocity of car
= 1500 kg * 20 m/s = 30000 kg m/s (east)
The momentum of the truck is given by:
= mass of truck * velocity of truck
= 2500 kg * -30 m/s
= -75000 kg m/s (west)
The total momentum of the system before the collision is given by:
30000 kg m/s + (-75000 kg m/s) = -45000 kg m/s
The total mass of the system is given by:
total mass = mass of car + mass of truck = 1500 kg + 2500 kg = 4000 kg
The final velocity of the system is given by:
final velocity = -45000 kg m/s / 4000 kg = -11.25 m/s
Since the final velocity is negative, it means that the system is moving west, which is the direction of the truck's initial velocity.
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Find a function that models the simple harmonic motion having the given properties. Assume that the displacement is at its maximum at time t = 0.
amplitude 6.45 in., frequency 30 Hz
The function for the simple harmonic motion having the given properties. Assume that the displacement is at its maximum at time t = 0 is y = 6.45 cos(60π*t).
Moving an object back and forth along a line is known as simple harmonic motion.
See a pendulum, for instance. It follows the same path when we swing it back and forth. Oppositions are what these motions are. A simple harmonic motion example is the oscillations of a pendulum.
[tex]y=Acos(Bt)[/tex]
has amplitude |A| and period 2π/B, and reaches its maximum at t=0.
So we choose A = 6.45
Period = 1/frequency
Period = 2π/B = 1/30
2π/B = 1/30
B = 60π
y = A.cos(Bt)
y = 6.45 cos(60π*t)
Therefore, The function for the simple harmonic motion is y = 6.45 cos(60π*t).
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What is the smallest possible value of the principal quantum number n for an s electron?
Answer:
The smallest possible value of the principal quantum number (n) for an electron in an atom is n = 1. This is referred to as the first energy level or the "1s" orbital, and it corresponds to the lowest energy state of an electron in an atom.
Explanation:
In general, the value of n determines the size and energy of the electron orbital. The larger the value of n, the larger the size of the orbital and the higher the energy of the electron. The smallest possible value of n is therefore always 1, and it corresponds to the electron being in its lowest energy state.
An asteroid is travelling through the solar system at a constant velocity. Which of the following
choices correctly models the forces acting on the asteroid?
Answer:
The forces acting on an asteroid include gravity from the Sun and other celestial bodies, radiation pressure from the Sun, and the pressure from interplanetary gas and dust. The gravitational forces will act to pull the asteroid towards the Sun, while the radiation pressure and interplanetary gas and dust will act to push it away. The net force acting on the asteroid will determine its path and velocity through the solar system.
Explanation:
A laser beam of wavelength 700 nanometers, traveling at a speed of 3.0 x 108 m/s,
is shot from outer space toward earth. What is the frequency of the laser beam?
A. 3.0 x 10^8 Hz
B. 700 x 10^-9 Hz
C. 210 Hz
D. 4.3 x 10^14 Hz
E. 233 x 10^-17 Hz
Answer:
The correct option is D. 4.3×10¹⁴ Hz
Explanation:
It is because the frequency and the wavelength are inversely proportional to each other.
So, c=f × lambda
And, frequency = velocity/wavelength
The frequency of the laser beam is D. 4.3×10¹⁴ Hz
What is the difference between frequency and hertz (Hz)?One hertz (Hz) equals one cycle per second. A complete AC or voltage wave is called a cycle. The first half of the cycle is alternating. Period is the time it takes a waveform to complete a complete cycle. Frequency is essentially how often something repeats.
The rate at which the current changes direction in one second is called the frequency. Expressed in hertz (Hz), the international unit of measurement. One hertz equals one cycle per second.
It is because the frequency and the wavelength are inversely proportional to each other.
So, c=f × lambda
And, frequency = velocity/wavelength
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Complete Question is:
A laser beam of wavelength 700 nanometers, traveling at a speed of 3.0 x 108 m/s,
is shot from outer space toward earth. What is the frequency of the laser beam?
[tex]A. 3.0 x 10^8 HzB. 700 x 10^-9 HzC. 210 HzD. 4.3 x 10^14 HzE. 233 x 10^-17 Hz[/tex]
The words technology and ideology both contain the suffix -ology. Based on this information, what the does the suffix -ology MOST LIKELY mean?
The words technology and ideology both contain the suffix -ology. Based on this information,the suffix -ology means something added to the end of something else.
What is a suffix?
After a word's stem, an affix is called a suffix. Common examples are verb endings, which constitute the conjugation of verbs, case endings, which show the grammatical case of nouns, and adjectives. Inflectional and lexical suffixes are two types of suffixes that can carry grammatical information. a grammatical or inflectional suffix When a word is inflected in this way, its syntactic category and grammatical qualities are altered. Class-changing and class-maintaining derivational suffixes are the two types of derivational suffixes.Suffixes are known as affirmatives because they have the aabilitybility to change the form of words, especially in the study of Semitic languages.To know more about suffix, click the link given below:
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A certain asteroid is approximately 50 AU from the Sun. According to Kepler’s third law, what is the orbital period of this asteroid in terms of Earth years?
The orbital period of this asteroid is approximately 353.55 Earth years.
What is the orbital period of this asteroid?
Kepler's third law states that the square of the orbital period (in years) of a planet or asteroid is proportional to the cube of its semi-major axis (in AU).
Therefore, we can use the following formula to calculate the orbital period:
(T / 1 year)^2 = (a / 1 AU)^3
where;
T is the orbital period in years, and a is the semi-major axis in AU.Plugging in the values for the asteroid at 50 AU, we get:
(T / 1 year)^2 = (50 / 1 AU)^3
(T / 1 year)^2 = 125000
T / 1 year = √(125000)
T = 353.55 Earth years (rounded to two decimal places)
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A spaceship in outer space has a doughnut shape with 900-m
outer radius. The inhabitants stand with their heads toward the center and their feet on an outside rim.
A.) Over what time interval would the spaceship have to complete one rotation on its axis to make a bathroom scale have the same reading for the person in space as when on Earth’s surface?
The formula for centripetal acceleration within the spacecraft is: ac =The outside radius of a spacecraft's doughnut-shaped body is 440 metres. The people are standing with thier feet on an outer rim and their heads .
What materials make up the Earth's surface?Earth's crust is made of igneous, metamorphic, or sedimentary rocks, which range in composition from mud or clay to diamonds or coal. Igneous rocks, which are created as magma cools, are the most prevalent types of rocks in the crust. Igneous rocks like granite and basalt are abundant in the crust of the Earth.
What precisely is a radius?The distance between any two places on a circle's circumference is in fact its radius. R or r are frequently used to denote it. Almost all calculations involving circles take this quantity into account. The radius of a circle can be used to determine a circle's circumference and surface area.
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Distinguish selective attention and habituation?
A car driving at a constant speed of 20 m/s (meters per
second) turns right, down a street.
1. Is the car accelerating during the turn? Why or why not?
2. Would you feel any of the movement during this event?
Why or why not?
EXTRA HELP
What is changing as the car turns? What changes qualify as
an acceleration? How can you feel acceleration?
Answer:
it is accelerating because it is at constant speed.
A personal training log is a record of your physical activity. It should be created in a table (Microsoft Word) or spreadsheet (Excel) format. The log should contain enough information so that you know what dates you exercised on, what activity(s) you did, how long you spent exercising, and any weights used (if applicable). It should also contain a spot to note personal fitness improvements made with each exercise session.
The final requirement is to set a fitness goal for yourself. What do you want to accomplish by being physically active? Some examples include losing weight, gaining muscle strength, improving cardiovascular conditioning or getting ready for a competition. These are just examples though. Your goal can be anything you want to achieve in relation to your physical health. Write your goal above your log.
You will first submit this log blank for review by your teacher by uploading it as an attachment (do not use the answer box). At the end of the course in the lesson entitled "Racewalking", you will be submitting your completed log to determine how well you have done with achieving your fitness goals.
A scenario of how the log will be is given in the image attached.
What is the training log?In this scenario attached, the individual has set a goal of increasing their muscle strength and overall fitness. They have been keeping track of their exercises in a log, noting the date, activity, time, weights used, and improvement from the last session.
Therefore, As shown in the log, the individual has been progressively increasing the weights used in each exercise, which is a sign of improvement and progress towards their goal. By keeping this log, the individual can easily track their progress and make adjustments to their training routine as needed.
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A box with weight of 10000 pounds is held 25 miles above the Earth. What is the box's potential
energy in kip-feet? one kip = 1000 pounds (Remember that weight in pounds already accounts for
acceleration due to gravity.)
The potential energy of the box is 4180 kip-ft.
What is potential energy?Potential energy is described as the energy held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors.
The potential energy of an object can be calculated using the formula:
PE = mgh
In the scenario,
the mass of the box is m = 10000 pounds and
the height above the ground is h = 25 miles = 25 * 5280 feet = 132000 feet.
The acceleration due to gravity is g = 32.2 ft/s^2.
Substituting these values into the formula, wehave:
PE = mgh = 10000 * 32.2 * 132000 = 4.18 x 10^8 ft-lb
Converting this to kip-ft,
PE = 4.18 x 10^8 ft-lb / 1000 = 4180 kip-ft
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A heart pacemaker fires exactly 71
times a minute. Each time it fires, a 33.0 nF
capacitor is charged by a battery in series with a resistor to 0.732
of its full voltage. What is the value of the resistance
?
The value of the resistance is approximately 0.047 kΩ.
What is Resistance?
Resistance is a measure of how much a material or device opposes the flow of electric current through it. Resistance is typically denoted by the letter R and is measured in Ohms (Ω) in the International System of Units (SI).
We can use the formula for the charging of a capacitor through a resistor:
V = V_0 * (1 - e^(-t/RC))
where V_0 is the initial voltage, V is the final voltage, t is the time, R is the resistance, and C is the capacitance.
In this case, the capacitor is charged 71 times per minute, so the time between charges is:
t = 60 s / 71
= 0.845 s
The capacitor is charged to 0.732 of its full voltage, so the fraction remaining is:
1 - 0.732 = 0.268
0.268 = e^(-0.845/RC)
Solving for RC, we get:
RC = -0.845 / ln(0.268) ≈ 1.42 s
Since we know the capacitance C is 33.0 nF, we can solve for the resistance R:
RC = R * C
= 1.42 s * 33.0 nF
= 0.0468 ≈ 0.047 kΩ
Therefore, the value of the resistance is approximately 0.047 kΩ.
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