The force between the two charges will be 25k N m.
This can be determined by using Coulomb's Law, which is a formula relating the forces between two charges (q 1 and q 2 ) at a distance r apart. The formula states that their force is equal to kq1q2/r2, where k is a constant (9 × 109 N m2/C2). If we plug in the values of 100 newtons for each charge and 4 meters for their distance, we get:
F = 100k/(4 × 109) = 25k N m
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place the flat sides of the polarizers together and observe the room lights through both polarizers at the same time. rotate one of the polarizers until the intensity is minimum. is any light transmitted through both polarizers when the intensity is minimum? if some light is transmitted, does it have any color? if so, what is the color, and what do you conclude about how the polarizers behave as a function of wavelength (color)?
I = I° cos²∅
When ∅ is 0° then intensity is maximum
When ∅ is 90° then intensity is minimum.
When two polarizer are combined in such a way that their crystallographic axes are parallel, the resulting intensity is at its highest, and you can see the light's original color as it passed through intensity the first polarizer. In this scenario, if the polarizer is colored and we are looking at the object through the polariser, the color that corresponds to the superposed wave that was created by the object's radiated wave (object's color) and the polariser's color will be the color of the object. On a beach, this is what happens when you wear polarized intensity sunglasses on a sunny day: the color of the objects appears differently than when you are wearing sunglasses.
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in which direction should he proceed in order to decrease the temperature most rapidly? how do you know? b. if the ship travels at e 8 meters per second, how fast will the temperature decrease if he proceeds in that direction?
a) in the z direction he should proceed in order to decrease the temperature most rapidly
b) The temperature decrease in the rate of −2√14e2 if he proceeds in that direction.
Taking the gradient of TT yields ∇T(x,y,z)=⟨−2xe(−x2−2y2−3z2),−4ye(−x2−2y2−3z2),−6ze(−x2−2y2−3z2)⟩, where we get the direction of maximum increase of any point (x,y,z). As we're at (1,1,1) so the appropriate vector in order for the maximum decrease is
−∇T(1,1,1)=⟨2e6,4e6,6e6⟩≈⟨0.0049575,0.00991501,0.0148725⟩
we normalize the upper result giving us :
⃗ =−∇T(1,1,1)∥−∇T(1,1,1)∥=⟨−1/√14,−√2/7, −3/√14⟩, here we are getting the direction of and along with an angle
Now, if r(t) is a parametrized path, then d/dtT(r(t))= change in T(r(t)).r ′(t)), in order for heading to the direction of maximum decrease, so UV =∥u∥ ∥v∥cosθ in here θ=0. So, the rate of decrease is ∥∇T(1,1,1)∥e8=2/√14e2 or -2/√14e2
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The temperature of the ship's hull when he is at location (x,y,z) will be given by T(x,y,z)=e−x2−2y2−3z2, where x,y, and z is measured in meters. He is currently at (1,1,1).
(A) In what direction should he proceed in order to decrease the temperature most rapidly?
(B) If the ship travels at e8 meters per second, how fast will the temperature decrease if he proceeds in that direction?
the 20-g centrifuge at nasa's ames research center in mountain view, california, is a horizontal, cylindrical tube 58.0 ft long and is represented in the figure below. assume an astronaut in training sits in a seat at one end, facing the axis of rotation 29.0 ft away. determine the rotation rate, in revolutions per second, required to give the astronaut a centripetal acceleration of 10.6g.
In rotations per second, the rotation rate is The angular speed in revolutions per second can then be converted to radians per second by dividing that time by 10.
Explain about the centripetal acceleration?Centripetal acceleration is a characteristic of an object's motion along a circular path. Centripetal acceleration applies to any object moving in a circle with an acceleration vector pointing in the direction of the circle's center.
An object must continuously change directions in order to maintain circular motion. Changes in direction result in changes in velocity because velocity is a vector. Centripetal acceleration is the term for the change in velocity caused by circular motion.
A net force that keeps an object moving in a circular motion is known as a centripetal force. Examples of centripetal force include the rotation of the top and the moon's orbit around the earth.
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suppose the skateboarder starts with 0 kinetic energy at the point -5 and starts to roll. describe the motion she will go through assuming that whatever resistive forces are acting can be neglected. describe one full cycle of the motion.
The kinetic energy will start dropping that is slows down , she keeps slowing down while the kinetic energy keeps decreasing with potential energy rising.
What is kinetic energy and what is the motion of the skateboarder starting with 0 kinetic energy ?Kinetic energy is the motion of the molecules of the container due the rise in temperature.Potential energy is the form of energy that an object gains as it is lifted and is stored and conserved.When she is proceeding to speed up potential energy drops and kinetic energy increases.Skateboarder keeps on speeding till +3 units till the potential energy drops.Then the potential energy starts to drop while the kinetic energy keeps on increasing.Skateboarder keeps slowing down till potential energy rises and kinetic energy drops to zero.To know more about kinetic energy visit:
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a skateboard with a negative acceleration, which of the following statements is always true
The initial velocity of the skateboard will be greater than its final velocity.
The correct option is C.
What is acceleration ?Acceleration is the rate at which the speed and direction of velocity vary over time. A point or object going straight ahead gets accelerated when it accelerates or decelerates. Even if the speed decreases, movement on a circle accelerates because the direction is always shifting.
Is speed acceleration?We refer to a change in an object's speed or direction as acceleration. The rate at which speed varies is known as acceleration. Keep in mind that velocity has two parts: speed and direction.
Can acceleration have a negative ?Our theory says that an object accelerates in the reverse direction from the velocity when it slows down. As a result, the object is moving backwards.
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The complete question is-
For a skateboard with a negative acceleration, which of the following statements is always true?
A. The skateboard is losing speed
B. The final velocity of the scooter will be negative
C. The initial velocity of the skateboard will be greater than its final velocity
D. The skateboard will have a negative displacement
what additional information is most important for them to add to the graph to best explain the work they've done?
Text is helpful for guiding the viewer and assisting with understanding. The graph's text provides extra details. In graphs, there are two different sorts of text: text that appears around the data regions.
In mathematics, a graph is a visual representation of any data that has been organized. The graph depicts the link between the various variables. The set of items that are somehow related to one another is represented by the graph in a graph theory.
A report can include numerous data regions. Data regions expand to hold the information from the report dataset to which they are associated. For instance, a matrix that shows annual sales for each product has a row group based on the names of the products and a column group based on the years.
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water flows from the pipe shown in the figure with a speed of 8.0 m/s what is the water pressure as it exits into the air? what is the height h of the standing column of water?
The atmosphere supports a column of mercury with a height of 760 mm. Supports a 32 m high water column. And, of course, that's why we fill the barometer with mercury instead of water or alcohol.
The vapor pressure of mercury is also minimal. Therefore, the pressure at the exit point is equal to atmospheric pressure. This pressure is therefore equal to 10 to the power of 5 times 1.1. The base area of this water cube is 12" x 12" = 144 square inches. So, the pressure at the bottom of the water cube is 62.4 pounds / 144 square inches = 0.433 pounds per square inch (psi). The RCC column minimum size is 9" x 9" and incorporates four 12mm bars steel stiffeners and cleats of 8mm steel rings spaced 150mm center to center.
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What is work and give an example?
In 1924, edwin hubble proved that the andromeda galaxy lay far beyond the bounds of the milky way, thereby putting to rest the idea that it might have been a cloud within our own galaxy. What key observation enabled him to prove this?.
Key observation that enabled Edwin Hubble to prove that the Andromeda galaxy laid far beyond the bounds of the Milky Way, thereby putting to rest the idea that it might have been a cloud within our own galaxy, was individual Cepheid variable stars.
The Discovery of the Andromeda GalaxyThe Andromeda galaxy was always thought to be a nebula within our own galaxy, the Milky Way. A Persian astronomer, Abd al-Rahman al-Sufi, was the first to formally describe the Andromeda as a nebulous smear (small cloud).
It wasn't until Edwin Hubble's discovery in 1925, when he identified extragalactic Cepheid variable stars for the first time on astronomical photos of Andromeda in 1925, that the Andromeda galaxy was eventually concluded to be an independent galaxy.
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After energy conversions, you end up with the same total amount of energy as the original amount energy. Which law explains this rule?.
The law that explains after energy conversions, the total amount of energy has the same amount as the original amount of energy is the Law of conservation of energy.
The state law of conservation of energy is that energy cannot be created, the energy cannot be destroyed, and the energy can be converted from one form of energy to another form of energy. Examples like mechanical energy. Mechanical energy is the sum of potential energy and kinetic energy.
Potential energy is the kind of energy stored by an object because of its position.Kinetic energy is the kind of energy that is possessed by an object in motion.If an apple fell from a branch of a tree
The potential energy on the branch is the maximum potential energy.When it fell, the potential energy reduces and changes into kinetic energy.When the apple almost reaches the ground, the potential energy gets smaller and the kinetic energy gets bigger.Before it hit the ground the potential energy is the minimum potential energy, but the kinetic energy reaches the maximum kinetic energy. At every point in its movement, the mechanical energy is always the same amount of energy.Learn more about Law of conservation of energy here: https://brainly.com/question/24772394
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a constant force is applied to an object, causing the object to accelerate at 10 m/s2 . what will the acceleration be if the force is halved and the object's mass is doubled? express your answer using two significant figures.
The acceleration is if the force is halved and the item's mass is doubled is 2.5 m/s².
Force is a push or pulls upon an item due to the item's interaction with a few different item. strain is a energy that could change the motion of an item. A force can purpose an object with mass to exchange its velocity, i.e., to boost up. stress also may be defined intuitively as a push or a pull. A force has each significance and route, making it a vector amount.
In the first case,
Let the mass of the object is = m
acceleration = 10 m/s²
The constant force F = ma
F = 10m ---------(1)
New case 2,
force F' = F/2
mass M' = 2m
a = F'/M'
= F/2 × 2m
a = F/4m
F = 4ma ----------(2)
dividing equations 1 and 2
⇒ [tex]\frac{F = 4ma}{F = 10m}[/tex]
a = 10/4
a = 2.5 m/s²
The phrase 'force' has a unique which means. At this degree, it's far truely appropriate to describe a pressure as a push or a pull. A force isn't always something that an item consists of or 'has in it. A pressure is exerted on one object thru another. The idea of a force is not confined to living matters or non-dwelling matters.
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a 0.20-kg ball on a stick is whirled on a vertical circle at a constant speed. when the ball is at the three o'clock position, the stick tension is 16 n. find the tensions in the stick when the ball is at the twelve o'clock and at the six o'clock positio
The tension when the stick is at six o clock will be 17.96 N and when the stick will be on 12 o clock the tension will be 14.04 N.
What is tension and how the tensions are calculated out to be so ?Tension is actually the force acting and that both have same unit Newton whose formula is T =mg + ma.Here the question is saying that0.20 kg ball in a stick is whirled on a circle at a constant speed.When the stick would be at 6 position , T6 = mg+T3 = 0.2 x 9.8 +16 = 17.96 N.When the stick would be at 12 position, T12 = T3-mg = 16- o.2x9.8 = 14.04N.Hence when a 0.20 kg ball on a stick whirling on a verticle circle at constant speed , the tension at six and twelve will be 17.96 N and 14.04N respectively.To know more about speed visit:
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At what time after the discharge begins is the charge on the capacitor reduced to half its initial value?.
The time it takes for the energy stored in the capacitor to be reduced to half its initial value is 0.00693 seconds.
What is meant by capacitor?A capacitor is a device that stores electrical energy in an electric field by accumulating electric charges on two insulated surfaces. It is a two-terminal passive electronic component. Capacitance is the effect of a capacitor.
The time it takes for the energy stored in the capacitor to be reduced to half its initial value is calculated as follows.
Q=Q₀[tex]e^{-t/RC}[/tex]
the time constant, RC = 10 ms = 0.01 s
Q₀ is the initial charged stored
Q is the final charge of the capacitor
Q₀/2=Q₀[tex]e^{-t/RC}[/tex]
Q₀/2Q₀=[tex]e^{-t/RC}[/tex]
1/2=[tex]e^{-t/RC}[/tex]
㏑(1/2)=-t/RC
㏑(1/2)=-t/0.01
-0.693=-t/0.01
t=o.00693 s
Thus, the time at which the energy stored in the capacitor will reduce to half of its initial value is 0.00693 s.
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The complete question is:
"The capacitor in an RC circuit is discharged with a time constant of 10.0ms. At what time after the discharge begins is the charge on the capacitor reduced to half its initial value."
a hoop with a radius r and a mas m has a momentum of inertia i. what would be the moment of inertia of a second hoop with the same radius but twice the mass?
The momentum of inertia of second hoop will be twice of first hoop
The moment of inertia of a hoop will be = m[tex]r^{2}[/tex]
first hoop:
radius = r1
mass = m1
inertia = I1 = m1[tex]r1^{2}[/tex]
second hoop
radius = r2 = r1
mass = m2 = 2m1
inertia = I2 = m2 * [tex]r2^{2}[/tex]
= 2m1 [tex]r1^{2}[/tex] = 2 I1
The momentum of inertia of second hoop will be twice of first hoop
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A candle 3.0 cm high is placed 30 cm from a converging mirror with a focal length of 20 cm.
I hate to leave you without an answer, but there isn't enough information to be able to answer your problem.
you hang 200 grams on the 10-cm mark and 400 grams on the 80-cm mark. if the meter stick has a mass of 100-g where should you clamp the meter stick so that it is in balance?
the meter stick so that it is in balance is 56 cm
Taking the equilibrium of Torque about C
200g (40 + x) + 100g x = 400g (30 - x)
200 (40 + x) + (100) x = (400) (30 - x)
x = 5.71
so location = 50 + 5.71 = 55.71 cm = 56 cm
chemical equilibrium is the state during a reversible chemical process where there is no net change in the amounts of reactants and products. When a chemical reaction is reversible, the products react with the original reactants as soon as they are created. There is no net change in the quantity of the constituent substances when the two opposing processes are in equilibrium because they are occurring at identical rates or velocities. The reaction may now be regarded as being finished, meaning that the maximal amount of reactants to products has been converted under the given reaction conditions.
It is possible to quantify the equilibrium-related conditions. For instance, in the reversible reaction A B + C,
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Determine the direction of the magnetic field of the current-carrying wire in the vicinity of the loop.
To determine the direction of the magnetic field of the current-carrying wire in the vicinity of the loop, you can use the right-hand rule.
How do you use this right-hand rule?If you're confused of what the direction of the magnetic field around a current-carrying wire is supposed to be, you can use the right-hand rule to conveniently figure out the direction. To use this right-hand rule, first curl your right-hand fingers and then point your right thumb in the direction of the current in the wire. Your right-hand fingers will be curled in the same direction as the direction of the magnetic field around the current-carrying wire.
There is another type of the right-hand rule. This type of right-hand rule is used to identify the direction of axes or parameters that point in three dimensions.
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a heavy brass ball is used to make a pendulum with a period of 5.5 s. part a how long is the cable that connects the pendulum ball to the ceiling? how long is the cable that connects the pendulum ball to the ceiling? 4.7 m 6.2 m 7.5 m 8.7 m request answer provide feedback
The length of the cable that connects the pendulum ball to the ceiling with a period of 5.5 s is 7.5 m
T = 2 π √ ( L / g )
T = Time period
L = Length of the pendulum
g = Acceleration due to gravity
T = 5.5 s
g = 9.8 m / s²
5.5 = 2 * 3.14 √ ( L / 9.8 )
√ L = 0.88 * √ 9.8
L = 0.77 * 9.8
L = 7.5 m
A simple pendulum consists of a mass suspended in air by a massless and unstretchable string that is fixed to a rigid support on the other end. The time taken to complete on oscillation is the time period of a simple pendulum.
Therefore, the length of the cable is 7.5 m
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a car enters the freeway with a speed of 5.9 m/s and accelerates uniformly for 3.3 km in 2.9 min. how fast is the car moving after this time?
The car will move fast with the velocity of 32.03 m/s
What is acceleration?Acceleration: the rate at which the speed and direction of a moving object vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting. Both effects contribute to the acceleration for all other motions.Acceleration is a vector quantity, since it has both a magnitude and a direction. A vector quantity is also velocity. The velocity vector change during a time interval divided by the time interval is the definition of acceleration. The limit of the ratio of the change in velocity during a given time interval to the time interval as the time interval approaches zero determines the instantaneous acceleration (at a specific time and location) For instance, acceleration will be stated in meters per second per second if velocity is expressed in meters per second.Calculation
Initial velocity(u) = 5.9 m/s
Distance traveled = 3.3 km = 3300 m
Time = 2.9 min = 2.9×60 = 174 seconds
Formula,
[tex]s=\frac{1}{2} (u+v)t[/tex]
[tex]3300=\frac{1}{2} (5.9+v)*174[/tex]
[tex]v= (\frac{6600}{174} -5.9)m/s[/tex]
v = 37.93–5.9 = 32.03 m/s
Hence, the car will move fast with velocity = 32.03 m/s
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erry-go-round accelerates from rest to in 34 s. assuming the merry-go-round is a uniform disk of radius 7.0 m and mass 31,000 kg, calculate the net torque required to accelerate it.
1.514 x 10⁴ N-m is the torque required to accelerate it.
Torque is the force that acts on the body causing it to turn about an axis.
It's given by
τ = I α ------- equation 1
Here I = moment of inertia of the disk
α = angular acceleration of the disk
For disk, moment of inertia = ½ m r²
I = 1/2 x (31 x 10³ kg) x (7)²
= 1/2 x (1514 x 10³)
α = ω₂₋ω₁ / t
here ω = angular velocity of the rotating merry-go-round
Substituting the values
α = ( 0.68rad/s - 0rad/s ) / 34s => 0.02 rad/s²
Putting the values of I and α in equation 1
τ = 1/2 x (1514 x 10³) x 0.02
=> 1.514 x 10⁴ N-m
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for a charged particle, a constant magnetic field can be used to change for a charged particle, a constant magnetic field can be used to change only the direction of the particle's velocity. only the magnitude of the particle's velocity. both the magnitude and direction of the particle's velocity. none of the above.
For a charged particle, a constant magnetic field can be used to change for a charged particle, only the direction of the particle's velocity .
magnetic force = q(VxB)
which is perpendicular to V and B
so it can't change magnitude only can change direction.
What is magnetic field?A magnetic field is a vector field near a magnet, an electric current, or an alternating electric field where the observed magnetic forces exist. A magnetic field consists of moving electric charges and the internal magnetic moments of elementary particles associated with a fundamental quantum property called spin. The magnetic field and the electric field are both related and are components of the electromagnetic force, which is one of the four forces of nature.
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A source vibrating at constant frequency generates a sinusoidal wave on a string under constant tension. If the power delivered to the string is quadrupled, by what factor does the amplitude change?.
As the tension of the spring is held constant as well as the frequency of the resulted sinusoidal wave, if the power delivered to the string is quadrupled, the amplitude will increase by factor 2.
If the frequency is held constant, the energy delivered to a wave is directly proportional to the square of its amplitude, or:
E ∝ A²
Where:
E = energy
A = amplitude
Power is energy per unit time, therefore power is also directly proportional to the square of amplitude.
P₂ : P₁ = A₂² : A₁²
From the problem, we know that P₂ = 4P₁
Hence,
4P₁ : P₁ = A₂² : A₁²
A₂² = 4 A₁²
A₂ = 2 A₁
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Suppose a spacecraft is orbiting 3.91* 10^5 meters above the surface of Mars. Calculate the magnitude of Mars' gravitational field and the approximate acceleration due to gravity experienced by the spacecraft (the mass of Mars is 6.39* 10^23 kg and its radius is 3.40* 10^6 m). [gravity, gravitational fields, gravitational acceleration]
The magnitude of Mars' gravitational field is 3.66 N/kg.
The approximate acceleration due to gravity experienced by the spacecraft is 3.66 m/s².
What is the gravitational fields?
The gravitational fields of the Mars is calculated by applying the following equation;
E = F/m = GM/r²
where;
G is universal gravitation constantM is the mass of Marsr is the radius of Mars F is gravitational forceE = (6.626 x 10⁻¹¹ x 6.39 x 10²³) / (3.4 x 10⁶)²
E = 3.66 N/kg
The approximate acceleration due to gravity experienced by the spacecraft is calculated as follows;
F = mg = GmM/r²
g = GM/r²
where;
G is universal gravitation constantM is the mass of Marsr is the radius of Mars F is gravitational forceg is acceleration due to gravityg = (6.626 x 10⁻¹¹ x 6.39 x 10²³) / (3.4 x 10⁶)²
g = 3.66 m/s²
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Draw your model to show what happens during the time when a balloon is being rubbed on a girl’s hair.
The electrons are transferred from hair to balloon when a balloon is being rubbed on a girl’s hair and attains a negative charge.
What happens when a balloon is rubbed with hair?Rubbing the balloon against the hair leads to the transfer of electrons from the hair to the balloon because electrons are negatively charged, the balloon attains a negative charge, while on the other hand, the hair with the loss of negative charges gets a net positive charge. Static electricity occurs due to an imbalance between negative charges and positive charges in a body. These charges can build up on the surface of a body until they find a path to be released or discharged. Static electricity is produced when positive and negative charges are not in a balanced situation. Protons and neutrons don't move around but electrons jump from one place to another place. When an object has more electrons than protons, it has a negative charge.
So we can conclude that when a balloon is being rubbed on a girl’s hair, the electrons are transferred from hair to balloon.
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a rocket with a mass of 4kg accelerates up from the ground at a rate of 20ft m/s^2, what is the drag force acting on the rocket if the thrust of the rockets is 150n
The drag force acting on the rocket is 80N.
Give an explanation of drag force?The divergence in velocity between the fluid and the item, also known as drag, exerts a force on it. Between the liquid and the solid object, there should be motion. Drag is absent in the absence of motion.
The air molecules are more compressed (pushed together) on the surfaces that are facing the front while being more dispersed (spread out) on the surfaces facing the back. Turbulent flow, which occurs when air layers split from the surface and start to swirl, is what causes this.
The drag force acting on the rocket F = ma
Given,
m = 4kg, a = 20ftm/s²
Substituting m and a values in the above formula,
The drag force acting on the rocket F = 4×20
The drag force acting on the rocket F = 80N.
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a he-ne laser emits wavelength of 633 nm. its beam diameter is 1 mm. find the minimum angular spread due to diffraction.
The minimum angular spread due to diffraction is 633×10⁻⁹m.
What is diffraction-induced spread?The spread of the spot (obtained on the opposite wall of the camera) is thought to equal the total of its geometrical spread and the spread caused by diffraction when the hole is lit by a parallel beam of light with wavelength lambda.
When waves flow through an aperture or around objects, they spread out, which is referred to as diffraction. It happens when the wavelength of the incident wave and the size of the aperture or obstruction are on the same order of magnitude. The majority of the wave is blocked at extremely small aperture diameters.
Minimum angular spread due to diffraction (θ) = λ/b
Given.
Wavelength = 633nm = 633×10⁻⁹m
Beam diameter is 1mm.
Minimum angular spread due to diffraction (θ) = 633×10⁻⁹m/1
Minimum angular spread due to diffraction (θ) = 633×10⁻⁹m.
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A 5 kg ball is thrown into the air. It is going 6
m/s when
thrown. How much potential energy will it have
at the top?
The potential energy will be 180J
By going through the formula of potential energy that is U=mgh
where, U= Potential energy
m= mass
g= gravitational feild
h= height
Now as per the question,
Initial velocity, u = 6 m/s
Final velocity, v = 0 m/s
Acceleration due to gravity, g = -5 m/s²
(The negative sign implies that the object is moving downwards)
To find the value of Height, we need to use the relation,
v^2 - u^2 = 2gh
0 - 36 = -10h
h = 36/10 m
Height = 18/5 m
therefore, Potential Energy(U) = mgh
= 10 × 5 × 18/5 J
= 180 J
Therefore, the ball will have a potential energy of 180 J when it is at its highest point.
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If you have a Corvette with a mass of 1,054 kg and a velocity of 48m/s, find the kinetic energy in J.
Kinetic energy of Corvette with a mass of 1,054 kg and a velocity of 48m/s is 12,14,208 J
What is kinetic energy?Kinetic energy is a type of power that an item or particle possesses as a result of motion. An object accelerates and acquires kinetic energy when it undertakes work—the transfer of energy—by being subjected to a net force. Kinetic energy is one of the properties of a moving object or particle, which depends on both mass and speed. The type of motion can be any combination of vibration, rotation on an axis, and translation (or transit along a path from one spot to another).
A body's translational kinetic energy is equal to 1/2mv2, or one-half of the product of its mass, m, and square of its velocity, v.
Here,
m = 1,054 kg
v = 48 m/s
KE = ?
KE = 1/2 mv²
KE = [tex]\frac{1}{2}[/tex] × 1054 × 48²
KE = 0.5 × 1054 × 2304
KE = 12,14,208 J
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AP physics 1: Extra points!!
1. There are three forces.
2. Yes, the forces on the beam are balanced.
3. The magnitude of the net force on them is zero.
4. The tension in Cable 1 is 8,596.49 N
5. The tension in Cable 2 is 8,596.49 N
The forces acting on the beam are two tension forces due to the cable and one gravitational pull due to its weight. Thus, there are three forces acting on the beam.
The force on the beam is perfectly balanced as the cable is uniformly attached to it. The beam is moving with constant velocity, thus the acceleration is zero, and hence, the net force acting on it is also zero.
The tension, T, in both cables is equal as they are inclined at the same angle.
Now, we resolve them into rectangular components and write
Tsin35 +Tsin35 = mg = 1000*9.8 = 9800
2Tsin35 = 9800
Tsin35 = 4900
T*0.57 = 4900
T = 8,596.49 N
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in a high wind situation, the flames of a wildfire will bend away from the direction of the wind and the flame height will be different from the flame length. which is used to describe the fireline intensity?
Flame length is used to describe the fireline intensity.
What is fireline intensity?
The sum of the heat released during a given period of time for each unit length of the fire's edge and the rate at which the fire spreads per unit of ground area is called the heat availability of combustion per unit of ground. Btu/sec/ft of fire front is the fundamental unit of measurement.
The rate of energy or heat emission per unit time per unit length of the fire front is called the fireline intensity (kW/m). From a mathematical perspective, it is equal to the product of the fuel's low heat of combustion (kJ/kg), the amount of fuel used in the flame front (kg/m2), and the linear rate of fire
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