two oppositely-charged plates are set up in the lab, where the positive plate is placed north of the other plate. in which direction would the electric field lines between the plates be pointing of a diagram was drawn?

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Answer 1

Answer:

Explanation:


Related Questions

1. A student measures the mass of a solution before and after a chemical reaction takes place. In both cases the student measures the mass to be 50.25 g on an electronic balance with an uncertainty of 0.05 g. The student realizes that the ranges of uncertainty for each measurement overlap exactly. Which claim can the student make?(a) The mass definitely stayed the same because the ranges of uncertainty overlap exactly.(b) We can't know for sure whether or not the mass changed, but it seems reasonable to claim that the mass did not change, given that the ranges of uncertainity overlap.(c) The mass definitely stayed the same because the measurement of 50.25 g was obtained each time.2. In the previous question you learned that a measurement system can be accurate but not precise, precise but not accurate, neither, or both. If an equipment contains a systematic error, then increasing the sample size will in general:(a) improve both accuracy and precision.(b) have no effect on either accuracy and precision.(c) improve accuracy but will not increase precision.(d) increase precision but will not improve accuracy.3. The cloth tape measure that you use to measure the length of an object had been stretched out from years of use. As a result, all of your length measurements were too small. How could you compensate for the incorrect results of using the stretched out tape measure?(a) There is no way to compensate for the incorrect result.(b) This is due to systematic error. Assuming that a new tape is more accurate, compare the stretched tape to a new tape to see how much the measurements are off. This difference will tell you how much to correct each original length measurement causing the systematic error to be minimized.(c) This is due to random error. Take more measurements until you get enough data to average and reduce the error.(d) This stretch is due to random error, so it can be ignored.

Answers

a) The claim student can make is - We can't know for sure whether or not the mass changed, but it seems reasonable to claim that the mass did not change, given that the ranges of uncertainity overlap.

b)  increasing the sample size will in general - increase precision but will not improve accuracy.

c) incorrect results of using the stretched out tape measure- This is due to systematic error. Assuming that a new tape is more accurate, compare the stretched tape to a new tape to see how much the measurements are off. This difference will tell you how much to correct each original length measurement causing the systematic error to be minimized.

a) Since the pupil used the same electronic balance with an query of0.05 g to weigh the mass of the result ahead and later, we can say that the millions are the same within the query of the balance.

b) Precision is the degree to which unborn measures yield the same results. delicacy, on the other hand, is a measure of how nearly the results agree with a true value. By adding the sample size the standard error is dropped meaning that unborn measures will probably fall near to the average. However, also taking further measures won't address this error and ameliorate delicacy as each dimension will be" off" by the same quantum from the true value, If methodical error is present. rather the methodical error needs to be removed, if possible, and this will ameliorate delicacy.

c) The stretching of the tape recording measure introduces a methodical error which could be corrected by comparing the tape recording with a different tape recording( essence or new). Once the pupil knows how important each dimension is out, the pupil can acclimate the original measures consequently. Performing further measures simply reduces the arbitrary error caused by the person reading the scale and won't affect the delicacy of the dimension.

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what sort of human activity do you think is contributing to increase carbon dioxide

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The human activities that are contributing to increase carbon dioxide are said to be releasing chemicals into the atmosphere, deforestation, construction, burning fossil fuels, etc.

Burning the fossil fuels is done to produce coal, generation of electricity, in factory usage which results in the release of huge amounts of CO₂.

Smoke from the vehicles contribute to the increased CO₂ levels.

Deforestation is done to acquire land for agriculture and construction purposes. Urbanisation leads to increase in CO₂ levels with the increased construction.

Construction of high rise buildings leads to the usage of a lot of cement. Thus increasing CO₂ levels into the atmosphere.

Increased CO₂ levels in the atmosphere leads to the climate change by increasing the temperature of the earth.

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WHY is the answer B? Please give scientifically sound explanation. Will give brainliest.

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The ball would stationary at the maximum height and accelerated greatly as it falls until it comes to rest on the ground. Option B

What is the velocity time graph for an object thrown up?

The slope of the velocity-time graph represents the acceleration of the object. At the highest point of the object's trajectory, the acceleration is zero, as it is temporarily at rest. As the object starts to fall, its acceleration becomes negative, indicating that it is accelerating downwards due to the force of gravity.

The velocity-time graph is a useful tool for analyzing the motion of an object and understanding its velocity and acceleration at different points in time.

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what is the acceleration two point on a velocity time graph which has coordinate (10sec,15ms)and (20sec,35ms)​

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The acceleration between two point on a velocity time graph which has coordinate (10sec,15ms)and (20sec,35ms)​ is 2.5m/s².

What is Acceleration?

This is referred to as the rate at which velocity changes with time, in terms of both speed and direction.

Acceleration = change in velocity/change in time

                          = 35m/s - 15m/s  / 20s - 10s

                            = 25m/s / 10s = 2.5m/s²

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If a force of unknown magnitude acts on a 10 kg box resting on a frictionless horizontal surface and changes its speed to 40 m/s in 5 s, then the acceleration of the box will be

Answers

Answer:

The box has a magnitude of 80 N

Explanation:

The acceleration of the box can be calculated as follows:

a = (v_f - v_i) / t

where

v_f = 40 m/s (final velocity)

v_i = 0 m/s (initial velocity)

t = 5 s (time)

a = (40 - 0) / 5

a = 8 m/s^2

So, the acceleration of the box is 8 m/s^2. This acceleration can be caused by the force acting on the box, which can be found using the equation:

F = m * a

where

m = 10 kg (mass of the box)

F = 10 * 8

F = 80 N (Newton)

So, the force acting on the box has a magnitude of 80 N.

The density equation is
ρ = m/v
The density of water is 1gram per 1milliliter of water. Written as 1g/1ml.
Use the density of water and the density equation to calculate the mass of 334 ml of water.
A 334 grams of water
B 334 grams/ml of water
C .003 grams/ml of water
D .003 grams of water

Answers

Answer:

We can use the density equation to find the mass of 334 ml of water.

Explanation:

Given that the density of water is 1 g/ml, we can substitute the values into the density equation:

ρ = m/v

ρ = 1 g/ml

v = 334 ml

So, m = ρ x v

m = 1 g/ml x 334 ml

m = 334 g

Therefore, the mass of 334 ml of water is 334 g, which is answer option A: 334 grams of water.

2. a student blows across the top of an empty bottle causing it to resonate at its fundamental frequency. the bottle has a height of .4m. the speed of sound is 340 m/s. what is the fundamental frequency? (4 pts)

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The fundamental frequency of the resonating air column in the bottle is 212.5 Hz. When a tube or bottle with one closed end is excited, it can resonate at certain frequencies, with the lowest frequency being the fundamental frequency.

The fundamental frequency of a resonating air column in a tube with one closed end, like the bottle in this case, is given by:

f = v/4L

where f is the fundamental frequency, v is the speed of sound, and L is the length of the air column.

In this case, the length of the air column is equal to the height of the bottle, which is 0.4 meters. The speed of sound is 340 m/s. Substituting these values into the formula, we get:

f = (340 m/s)/(4 x 0.4 m) = 212.5 Hz

Therefore, the fundamental frequency of the resonating air column in the bottle is 212.5 Hz.

When a tube or bottle with one closed end is excited, it can resonate at certain frequencies, with the lowest frequency being the fundamental frequency. The length of the air column inside the tube determines the fundamental frequency of the resonating air column. The resonant frequencies of the tube are determined by the speed of sound in air, the length of the air column, and the properties of the tube, such as its shape and the position of the closed end.

The fundamental frequency of a resonating air column in a tube with one closed end can be determined using the formula:

f = v/4L

where f is the frequency, v is the speed of sound, and L is the length of the air column. This formula assumes that the air column is a simple tube with one closed end, and that the air inside the tube is at rest before the sound wave is introduced.

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which particles constantly move around the center of an atom

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Answer:

electron is the correct answer

Explanation:

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a bolt is dropped from a bridge under construction, falling 90 m to the valley below the bridge. (a) in how much time does it pass through the last 20% of its fall? what is its speed (b) when it begins that last 20% of its fall and (c) when it reaches the valley beneath the bridge?

Answers

a) The bolt 1.38 seconds to fall through the last 20% of its fall.

b) The bolt begins the last 20% of its fall 3.06 seconds after it is dropped.

c) The speed of the bolt just before it hits the ground is 42.43 m/s.

(a) The time it takes for the bolt to fall through the last 20% of its fall can be calculated using the kinematic equation:

[tex]y = vi*t + (1/2)at^2[/tex]

where y is the distance fallen, vi is the initial velocity (which is 0), a is the acceleration due to gravity ([tex]-9.8 m/s^2[/tex]), and t is the time taken.

Let's call the total distance fallen by the bolt "d". Then, the distance fallen in the last 20% of the fall is 0.2d, and the distance fallen before that is [tex]0.8d[/tex]. So we can write:

[tex]0.2d = (1/2)at^2[/tex]

Solving for t, we get:

[tex]t = sqrt((0.2d)/(0.5*a))[/tex]

Plugging in the values, we get:

[tex]t = sqrt((0.290)/(0.5(-9.8))) = 1.38 seconds[/tex]

To find the speed of the bolt at the end of this 20% fall, we can use the kinematic equation:

[tex]v = vi + a*t[/tex]

where v is the final velocity, vi is the initial velocity (which is 0), a is the acceleration due to gravity ([tex]-9.8 m/s^2[/tex]), and t is the time taken.

Plugging in the values, we get:

[tex]v = 0 + (-9.8)*1.38 = -13.524 m/s[/tex]

The negative sign indicates that the velocity is downward.

(b) The time at which the bolt begins the last 20% of its fall can be found by multiplying the total time taken to fall by 0.8 (since the first 80% of the fall takes 80% of the total time):

[tex]t_start = 0.8sqrt((2d)/g) = 0.8sqrt((2*90)/9.8) = 3.06 seconds[/tex]

(c) The speed of the bolt just before it hits the ground can be found using the kinematic equation:

[tex]v^2 = vi^2 + 2ay[/tex]

where v is the final velocity, vi is the initial velocity (which is 0), a is the acceleration due to gravity [tex](-9.8 m/s^2)[/tex], and y is the distance fallen.

Plugging in the values, we get:

[tex]v = sqrt(0 + 2*(-9.8)*90) = 42.43 m/s[/tex]

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I need help in this please

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The net electric force on charge +q is along direction C.

option C.

What is the electric force between two charges?

The electric force between two charges is determined applying Coulomb's law of electrostatic force.

Mathematically, the formula for this law is given as;

F = kq₁q₂/r²

where;

k is the Coulomb's constantq₁ is the magnitude of charge 1q₂ is the magnitude of charge 2r is the distance between the charges

The strength of the electric force increases with decrease in the distance between the two charged particles.

The distance between the charge at the center and

point C = 1.5 dpoint B = 2dpoint D = point A = √[ (1.5d)² + (2d)² ] = 2.5d

The electric force is strongest towards point C, so the direction of the force will be towards point C.

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a 2 coulomb charge is moved from a to b in the presence of an electric field created by other charges. the potential energy when the charge is at point b is 30 j higher then the potential energy when the charge was at a. the voltage (created by the other charges) at point a was 10 volts. what is the voltage at point b?

Answers

When the charge is at point b, the potential energy is 30 j, and the voltage produced at point b by the other charges is 25 volts.

We can use the formula for potential energy in an electric field to relate the change in potential energy to the difference in voltage between the two points:

ΔU = qΔV

here,

ΔU is change in potential energy,

q is charge, and

ΔV is difference in voltage.

We are given that

q = 2 C, and

That the change in potential energy

= ΔU = 30 J.

Therefore, we can solve for the difference in voltage between points a and b:

ΔV = ΔU / q

ΔV = 30 J / 2

ΔV = 15 V

This means that the voltage at point b is

10 V + 15 V = 25 V,

because the potential energy when the charge is at point b is 30 J higher than at point a.

Therefore, the voltage created by the other charges at point b is 25 volts.

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A boy of 50 kg climbs a wall 2m high. Calculate the change in potential energy of the boy

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Answer:

If this is the question : boy weighing 50kg climbs up a vertical height of 100m. Calculate the amount of work done by him. How much potential energy does he gain (g=9.8m/s2)

So the answer will be:

mass of boy = m = 50 kg   
height = h = 100m  

 since boy does not move anything with his force, work done by him is zero    work done on the boy = gain in potential energy   
 P.E=mgh    P.E=50×9.8×100   P.E=49KJ  so, potential energy gained by boy is 49 KJ 

Explanation:

a player catches a ball. consider the action force to be the impact of the ball against the player's glove. the reaction to this force is the friction of the ground against the player's shoes. player's grip on the glove. force the glove exerts on the ball. muscular effort in the player's arms. none of these

Answers

The reaction to this force is force the glove exerts on the ball.

When a player catches the ball, what kind of force is this?

Frictional force allows the ball to stay in the hand while muscular force is employed to stop the motion of the ball during catching.

First, second, and third laws of motion of Newton :According to the first law, until a force acts on an item, it will not alter its motion. According to the second law, an object's force is determined by multiplying its mass by its acceleration. According to the third law, when two objects interact, they exert equal-sized and opposite-direction pressures upon one another.

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suppose a 59.5 kg gymnast climbs a rope. (a) what is the tension (in n) in the rope if he climbs at a constant speed?

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The required tension in the rope if he climbs at constant speed is said to be 583.7 N.

The mass of the gymnast is given as 59.5 kg.

It is said that he climbs a rope at constant speed. This speed is to be calculated.

An object is said to be moving at a constant pace when it covers the same distance in the same amount of time. When moving at a constant pace, an object covers a fixed distance in a fixed amount of time.

The action-reaction pair of forces operating at either end of the aforementioned elements can also be thought of as tension. A string, rope, chain, or other similar object, or both ends of a rod, truss member, or other equivalent three-dimensional object, transmits tension when they pull in the same direction.

Drawing a free-body diagram has allowed us to:

T - m g = 0

T = m g = 59.5(9.81) = 583.7 N

Thus, the tension in the rope if he climbs at constant speed is said to be 583.7 N.

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a long jumper's take-off velocity is 14.6 m/s at an angle of 18o from the horizontal. her center of mass is 1 m above the ground at take-off and is 0.2 m above the ground at landing. neglect air resistance, find what is her take-off horizontal velocity (in m/s).

Answers

Take-off horizontal velocity = 14.6 m/s * cos(18°) = 12.5m/s

What is Horizontal Velocity?

Horizontal velocity is the speed of an object in a straight line, measured in a specific direction. It is a vector quantity, meaning it has both magnitude and direction. Horizontal velocity is usually measured in meters per second (m/s). It is distinct from vertical velocity, which measures how fast an object is moving up or down. Horizontal velocity is generally used to describe the motion of an object along the x-axis of a coordinate system. It is calculated by dividing the distance traveled in the x-direction by the time it took to travel that distance.

The take-off horizontal velocity can be calculated using the equations of projectile motion. The equation for horizontal velocity is Vx = Vcos(angle). In this case, V = 14.6 m/s and angle = 18o.

Therefore, the take-off horizontal velocity is Vx = 14.6 cos(18degrees) = 12.5 m/s.

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Sarah rides her horse with a constant speed of 8 km/h. How far can she travel in 1 1/2 hours?

Answers

Answer:

12 Kilometers

Explanation:

To find the distance Sarah travels in a given time, we can use the formula:

distance = speed * time

In this case, the speed of the horse is 8 km/h and the time Sarah travels is 1 1/2 hours.

distance = 8 km/h * 1 1/2 hours = 12 km

So, Sarah can travel 12 kilometers in 1 1/2 hours.

an organ pipe is 95 cm long and open on both ends. what frequency note does the pipe produce? take the speed of sound to be 343 m/s

Answers

The organ pipe produces a note with a frequency of approximately 181 Hz.

f = (nv)/(2L)

where:

f = frequency

n = the harmonic number (the first harmonic is 1, the second is 2, etc.)

v = the speed of sound (343 m/s)

L = the length of the pipe (95 cm = 0.95 m)

Since the pipe is open on both ends, it can produce all the odd harmonics (1st, 3rd, 5th, etc.). We'll find the frequency of the first harmonic (n=1):

f = (1343)/(20.95)

f = 181.05 Hz

Frequency is a term used in physics to describe the number of waves, vibrations, or cycles that occur in a given amount of time. It is measured in Hertz (Hz), which represents the number of cycles per second. For example, if a wave oscillates up and down 50 times in one second, its frequency is 50 Hz.

Frequency is a fundamental concept in many areas of physics, including sound, light, and radio waves. It is an important factor in determining the pitch of a sound, as well as the color of light.

In addition, frequency is closely related to the wavelength of a wave, which is the distance between two consecutive points of a wave with the same phase. The relationship between frequency and wavelength is given by the equation c = fλ, where c is the speed of light or sound, f is the frequency, and λ is the wavelength.

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A student conducts an investigation on a bar magnet with unlabeled poles. To determine which side of the magnet is north (N) or south (S), what steps can the student take?

A. The student can cut the bar magnet in half and observe the direction of the magnetic field on each individual piece.

B. The student can place the bar magnet near a nonmetal surface and observe the direction of the magnetic field on the surface.

C. The student can place the bar magnet near a metallic surface and observe the direction of the magnetic field on the surface.

D. The student can place the bar magnet near the known pole of a second magnet and observe the interaction between the poles.

Answers

Answer: D. The student can place the bar magnet near the known pole of a second magnet and observe the interaction between the poles.

Explanation: Magnets having the property that they attract the different poles and repel the same poles.

The better Investigation should be going to be conducted by the student is that by taking the known pole magnet and make the interaction with the unlabeled magnet.

step 1: choose the known magnet pole first (say S-pole).

step 2: make interaction of this pole with the any of two poles of unlabeled magnet.

step 3: if both magnets are attracting to each other, the pole will be North pole (N-pole), and if repelling to each other, the pole will be South pole(S-pole)

Now if we got the first Pole, the second will be obvious.

(since , magnets have two poles. N-pole and S-pole)

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today the sun appears to be located in the middle of the constellation virgo. therefore, tomorrow the sun will be in the constellation today the sun appears to be located in the middle of the constellation virgo. therefore, tomorrow the sun will be in the constellation sagittarius. libra. leo. virgo.

Answers

If today the sun appears to be located in the middle of the constellation Virgo. therefore, tomorrow the sun will be in the constellation Virgo. Hence, option D is correct.

What is a constellation?

An arrangement of stars is a constellation. Others have observed patterns in the stars that are used to classify the groups. A lion's form, for instance, appears to be traced by the stars of the constellation Leo.

The western zodiac consists of the 12 constellations Aries, Taurus, Gemini, Cancer, Leo, Virgo, Libra, Scorpio, Sagittarius, Capricorn, Aquarius, and Pisces is one constellation tradition.

Thus, if today the sun appears to be located in the middle of the constellation Virgo. Then, tomorrow the sun will be in the constellation Virgo. Hence, option D is correct.

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after the switch is closed, which plate of the capacitor eventually becomes positively charged? after the switch is closed, which plate of the capacitor eventually becomes positively charged? the top plate only the bottom plate only both plates neither plate because electrons are negatively charged

Answers

After the switch is closed, the top plate  of the capacitor eventually becomes positively charged

When the switch is closed, what happens to the capacitor's charge?

It initially acts like a short-circuit because when the switch is first closed, the voltage across the capacitor, which we were assured was entirely discharged, is zero volts. The capacitor will eventually operate as an open circuit because the voltage of the capacitor will eventually equal the voltage of the battery.

An electrolytic capacitor with polarity will be labelled with the word "polarity" on it. A minus sign or a color stripe that runs the length of the capacitor is commonly used to indicate the capacitor's negative. The positive lead of the capacitor is longer than the negative lead.

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A. An adaptive filter What type of digital signal processing filter is used to generate an SSB signal? A. An adaptive filter B. A notch filter C. A Hilbert-transform filter D. An elliptical filter

Answers

A Hilbert-transform filter is used to generate an SSB signal.

A Single Sideband (SSB) signal is generated by filtering one sideband of a modulated signal and suppressing the other sideband and the carrier signal. The most common way of generating an SSB signal is by using a Hilbert-transform filter.

This filter is used to shift the phase of the modulated signal by 90 degrees, effectively converting the upper sideband to the lower sideband, or vice versa. By filtering out one of the sidebands, the SSB signal can be generated. Therefore, option C is the correct answer.

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--The complete question is, What type of digital signal processing filter is used to generate an SSB signal?

A. An adaptive filter

B. A notch filter

C. A Hilbert-transform filter

D. An elliptical filter--

what parts are in a tv

Answers

The exterior or housing, the audio reception and speaker system, the picture tube, and a complicated mass of electronics including cable.

What are the principal sets of parts in TV?

Antennae input and output devices, a built-in antenna in most sets, a remote control receiver, and computer chips, make up the four main sets of parts that make up a television.

Typically, in addition to coaxial cable, HDMI, and other audio-video connectors, smart TVs also enable Ethernet, WiFi, USB, Bluetooth, and flash memory cards from digital cameras.

Therefore, the TV consists of exterior, audio reception, speaker system, and picture tube.

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Use the tools to measure and calculate the vertical momentum of the two-puck system before the collision. Show your process

Answers

To measure and calculate the vertical momentum of the two-puck system before the collision.

Set up the experiment: Place two pucks of known masses on a frictionless air hockey table, with one puck placed directly above the other. Ensure that the pucks are in contact with each other before the experiment begins.Measure the mass of the pucks: Use a scale to measure the masses of the two pucks. Let's assume the mass of the top puck is 0.1 kg and the mass of the bottom puck is 0.2 kg.Measure the initial velocity of the system: Use a motion sensor or a timer to measure the initial velocity of the system just before the collision. Let's assume the initial velocity of the system is 2 m/s.Calculate the initial momentum of the system: The momentum of the system before the collision can be calculated using the formula:

Initial momentum = (mass of top puck + mass of bottom puck) x initial velocity

Substituting the values we have:

Initial momentum = (0.1 kg + 0.2 kg) x 2 m/s

Initial momentum = 0.3 kg x 2 m/s

Initial momentum = 0.6 kg m/s

Therefore, the vertical momentum of the two-puck system before the collision is 0.6 kg m/s.

Define collision.

When two or more objects come into contact with one another and exchange energy, momentum, or other physical properties, the occurrence is called a collision. Depending on the nature of the items involved and how they interact with each other during the impact, a collision in physics can be either elastic or inelastic.

The complete kinetic energy of the colliding objects is preserved in an elastic collision, which means that none of the kinetic energy is converted into other kinds of energy like heat or sound. The items in this kind of collision bounce off one another with the same velocity and direction as before the collision.

On the other hand, in an inelastic collision, some or all of the kinetic energy of the colliding objects is transformed into other types of energy, such heat, sound, or object deformation. In this kind of collision, the items may cling together after impact or bounce off one another in a different direction or at a different speed than previously.

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(b) A dark nebula is a type of nebula that does not emit light.
A dark nebula looks dark because it blocks the light from stars that are behind it.
Suggest why dark nebulae are thought not to contain stellar nurseries.
*******

Answers

Dark nebulae are thought not to contain stellar nurseries because they are primarily composed of gas and dust, which are the building blocks of stars, but they are too cold and dense to collapse and form stars.

What is nebula?

A nebula is a distinctively luminous region of the interstellar medium, which may be made up of cosmic dust, neutral, neutrally ionized, or molecular hydrogen.

Because dark nebulae are predominantly made of gas and dust, the raw materials for stars, but are too cold and dense to collapse into stars, it is believed that they do not contain stellar nurseries.

In other words, the gas and dust in a black nebula are not in an ideal environment to start the star-forming process.

The quantity of light that is accessible for star formation may be diminished by the dust particles in dark nebulae that can absorb and scatter light.

Thus, despite the fact that black nebulae may contain a lot of gas and dust, they are not suitable for the formation of new stars, and are unlikely to contain stellar nurseries.

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how is rayleigh scattering and frequency related? double

Answers

Rayleigh scattering and frequency are related because the amount of scattering is inversely proportional to the fourth power of the frequency of the light. This means that as the frequency of the light increases, the amount of scattering decreases. This relationship is described by the Rayleigh scattering equation:


Is = I0 (1 + cos2θ) / (2r2) (λ0/λ)4


Where Is is the intensity of the scattered light, I0 is the intensity of the incident light, θ is the scattering angle, r is the distance from the scattering particle, λ0 is the wavelength of the incident light, and λ is the wavelength of the scattered light. This equation shows that the intensity of the scattered light is inversely proportional to the fourth power of the wavelength of the incident light, which is directly related to the frequency of the light.


Therefore, Rayleigh scattering and frequency are related in that the amount of scattering decreases as the frequency of the light increases.

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3. A shelf hangs from the ceiling by two identical wires fixed to each end of the shelf.
The wires both make an angle of 25 degrees to the horizontal. The tension in each
wire is 80 N. What is the mass of the shelf? (Use g = 10 m/s^2 for this problem)
A 3.4 kg
B 6.8 kg
C 7.3 kg
D 14.4 kg

Answers

Answer:

C. 7.3 kg

Explanation:

The weight of the shelf can be calculated using the equation:

W = mg

where m is the mass of the shelf and g is the acceleration due to gravity (10 m/s^2).

Since the tension in each wire is equal and equal to 80 N, the total tension in the two wires is 80 N + 80 N = 160 N.

The horizontal component of the tension in each wire can be calculated using the equation:

T_horizontal = T * cos(25)

where T is the tension in each wire and 25 is the angle between the wire and the horizontal.

The horizontal component of the tension in each wire is equal to the weight of the shelf, so we can set the two equal:

T_horizontal = W

80 * cos(25) = W

W = 80 * cos(25) = 74.17 N

Finally, we can calculate the mass of the shelf using the equation for weight:

m = W / g

m = 74.17 / 10

m = 7.417 kg

Therefore, the mass of the shelf is approximately 7.417 kg, which is closest to option C, 7.3 kg.

g in light of this result that you derive, if you read publications in field a and field b, which field's publications have higher chance to be true? field a. field b.

Answers

Field B may have a higher chance of having low statistical power and thus a higher rate of false positives.

The result suggests that scientific fields with low statistical power have a higher chance to have a high rate of false positives, indicating that their findings are less likely to be true.

On the other hand, Field A, which has a thorough background knowledge, a small community of researchers, and good ways of testing hypotheses, may have a higher likelihood of having a higher statistical power, resulting in a lower rate of false positives and more reliable publications. However, this is not to say that all publications in Field A are true, as individual studies can still have their limitations and potential biases. It is always important to critically evaluate the evidence and findings presented in scientific publications.

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questions: 1. if you want to measure voltage across on a resistor connected to a 5v dc power supply, which two jacks of the dmm should be used? where do you set the function/range knob? which voltage range should be selected? 2. if the current flowing in a circuit is about 60ma. where should the function/range knob be set at in order to measure the current? which two jacks of the dmm will be used? what range should be used?

Answers

The voltage range should be selected to be at least 5V or greater to ensure accurate measurement and with the DMM placed in series with the circuit.

To measure the voltage across a resistor connected to a 5V DC power supply, you should use the red and black jacks of the DMM, where the red jack is connected to the positive side of the resistor and the blackjack is connected to the negative side. The function/range knob should be set to measure DC voltage (V~), and the voltage range should be selected to be at least 5V or greater to ensure accurate measurement.

If the current flowing in a circuit is about 60mA, the function/range knob should be set to measure DC current (A) and the range should be selected to be at least 200mA or greater to ensure accurate measurement. The two jacks of the DMM used, in this case, will be the red and black jacks, where the red jack is connected to the positive side of the circuit and the blackjack is connected to the negative side, with the DMM placed in series with the circuit.

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Which of these would cause the most physical weathering?
A. sand being blown across a field.
B. The roots of a large tree.
C. A deep fast-moving river.
D. A shallow slow-moving river.

Answers

The most affecting physical weathering is by the roots of large trees. They are strong enough to erode rocks. Hence, option B is correct.

What is physical weathering ?

Rocks, minerals, and soils disintegrate through a process known as physical weathering, sometimes known as mechanical weathering. Abrasion is the main physical weathering process.

Temperature, pressure, frost, root movement, and burrowing animals can all cause physical deterioration. For instance, physical weathering will expose more surface area through the use of cracks, speeding up the pace of deterioration.

Across the world, gorges, ravines, and valleys are formed by processes of water, ice, and wind that are loaded with silt. Here, strong roots embedded into the soil are enough to cause physical weathering.

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show answer no attempt 50% part (b) how much energy is lost to friction if the motorcycle only gains an altitude of 21 m before coming to rest?

Answers

From the information provided, the energy lost to friction if the motorcycle only gains an altitude of 21 m before coming to rest is approximately 65,954.64 J.

To calculate the energy lost to friction, we need to first determine the initial total mechanical energy of the motorcycle and the final total mechanical energy of the motorcycle after it has climbed to a height of 21 meters and come to rest. The difference between the initial and final energies will give us the energy lost to friction.

The initial total mechanical energy of the motorcycle is given by:

Ei = (1/2)mv² + mgh + 2(1/2)Iw²

where m is the mass of the motorcycle, v is its initial speed, h is the height it climbs, g is the acceleration due to gravity, I is the moment of inertia of the wheels, and w is their initial angular velocity.

We need to calculate the moment of inertia of each wheel:

I = (1/2)mr²

where m is the mass of the wheel and r is its radius. Substituting the given values, we get:

I = (1/2)(12 kg)(0.33 m)² = 0.6534 kg m²

The initial angular velocity of each wheel is not given, so we can assume that it is initially at rest (i.e., w = 0).

Substituting the given values into the equation for E, we get:

Ei = (1/2)(180 kg)(25 m/s)² + (180 kg)(9.81 m/s²)(36 m) + 2(1/2)(0.6534 kg m²)(0)²

= 101,812.44 J

The final total mechanical energy of the motorcycle is given by:

Ef = mgh

where m, g, and h are as before, and the speed and rotational energy of the wheels are both zero.

Substituting the given values, we get:

Ef = (180 kg)(9.81 m/s²)(21 m) = 35,857.8 J

The energy lost to friction is the difference between the initial and final energies:

Energy lost = Ei - Ef = 101,812.44 J - 35,857.8 J = 65,954.64 J

Question - Suppose a 180 kg motorcycle is heading toward a hill at aspeed of 25 m/s. The two wheels weigh 12 kg each and are each annular rings with an inner radius of 0.280 m and an outer radius of 0.330 m. Randomized Variables m 180 kg ˇ-25 m/s h 36 m. how much energy is lost to friction if the motorcycle only gains an altitude of 21 m before coming to rest?

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