The force would be F0=9×F1
Solution
The equation describing the attractive force between two masses (m) separated by a distance (r) is known as Sir Isaac Newton's universal law of gravitation (F=Gmm/r²)
By putting the values given in the question -
F0= Gm1m2÷r²
F1=Gm1m2÷(3r)²
By dividing F0 and F1 we get -
F0=9×F1
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According to the nebular theory of solar system formation, which law best explains why the solar nebula spun faster as it shrank in size?.
The law of conservation of angular momentum.
What is angular momentum?
Angular momentum is the rotational analog of linear momentum in physics. It is a conserved quantity, meaning the total angular momentum of a closed system remains constant. Both the direction and magnitude of angular momentum are conserved.
What is the law of conservation of angular momentum?
The law of conservation of angular momentum asserts that a system's total angular momentum is conserved when there is no external torque present. In other words, the magnitude and direction of the total angular momentum of an isolated system remain constant.
According to the Nebular Theory, the solar system originated as a massive, slowly rotating cloud of gas measuring around one light-year in diameter. As the cloud cooled, its own gravity caused it to collapse. It distorted into a revolving pancake shape due to the conservation of angular momentum, which required it to spin faster as it shrank.
Hence, the law of conservation of angular momentum best explains why the solar nebula spun faster as it shrank in size.
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I need to know what the answer is to this
I agree with Katelyn's statement
Explanation:Netwon's first law of motion states that an object will remain at rest or in uniform motion except acted upon by an external (unbalanced) force.
When balanced forces are acting on an object in motion, the object maintains its speed and direction.
This means that balanced forces do not change the speed and direction of an object in motion. We can say that the object is in equilibrium. It either remains at rest or in uniform motion.
Therefore, I agree with Katelyn's statement
AP Physics -An object is thrown downward with an initial speed of 20. m/s on Earth. What is the:
a) acceleration of the object
b) displacement after 4 seconds.
c) time required to reach a speed of 50. m/s.
d) time required to fall 300. M (Hint: factor the quadratic).
e) speed after falling 100. m.
Answer:
Explanation:
Given:
V₀ = 20 m/s
t = 4 s
V = 50 m/s
H₁ = 300 m
H₂ = 100 m
______________
a) Acceleration of the object:
g = 9.8 m/s²
b) Displacement after 4 seconds.
H = V₀*t₁ + g*t²/2 = 20*4 + 9.8*4² / 2 ≈ 160 m
c) Time required to reach a speed of 50 m/s.
t = (V - V₀) / g = (50 - 20) / 9.8 ≈ 3 s
d) Time required to fall 300 m.
H₁ = V₀*t + g*t²/2
300 = 20*t + 9.8*t² / 2
4.9*t² + 20*t - 300 = 0
t ≈ 6 s
e) Speed after falling 100 m.
Н₂ = (V₂² - V₀²) / (2*g)
V₂² = V₀² + 2*g*H
V₂ = √ (V₀² + 2*g*H) = √ (20² + 2*9.8*100) ≈ 49 m/s
4. A team of physicists is testing how long it takes for a charged particle to travel through a magnetic field. They measure the time as 4.050*10^-6 seconds. How many significant figures does this
measurement have?
05
2
Significant figures 4.050*10^-6 seconds has is four as exponential digits in scientific notation are not significant.
Five rules for significant figures are
All the non-zero numbers are significant.Zeros between two non-zero digits are also significant. Leading zeros are not said significant.Trailing zeros to the right of the decimal are taken as significant. Trailing zeros in a whole number with the decimal are taken significant.All the digits known with certainty or those indicated by the markings on the measuring device and the first estimated, digit that is one digit past the smallest marking on the measuring device is called the significant figures of a measured quantity.
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The diagram below shows a wind turbine.
At a particular wind speed, a volume of 2.3 × 10ª m³
of air passes the blades each second.
The density of air is 1.2 kg/m³.
Calculate the mass of air passing the blades per
second.
The mass of air passing the blades per second is 2.76 × [tex]10^{4}[/tex] kg
What is wind energy formula?A kind of solar energy is wind energy. The technique through which wind is utilized to generate power is known as wind energy. The kinetic energy in the wind is converted to mechanical power by wind turbines.
A renewable energy source that harnesses the power of the wind is wind energy. The wind energy formula is given by,
P = 1/2 ρAV³, where P = Power
Given that,
density of air (ρ) = 1.2kg/m³
volume (v) = 2.3×[tex]10^{4}[/tex] m³
Now calculate mass of the air -
mass = density × volume
= 1.2 × (2.3 × [tex]10^{4}[/tex])
= 2.76 × [tex]10^{4}[/tex] kg
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osteoporosis is a condition that makes bones more
A car of mass 1,000 kg begins stationary on a road at the top of a mountain, at a height h = 3,000 m. The car then rolls freely down a winding road, travelling a total distance of 5 km, to reach the height h = 2,000 m. Assume g = 9.8 ms-2:
give answer in 3 significant figures, with units.
The amount of energy lost by the car when it descended from a height of 3000 m to 2000 m is 980×10⁴ J
How do I determine the energy lost?We'll begin by obtaining the energy at the top of the mountain (height = 3000 m). This is shown below:
Mass (m) = 1000 KgAcceleration due to gravity (g) = 9.8 m/s²Height (h) = 3000 mEnergy (E) =?E = mgh
E = 1000 × 9.8 × 3000
E = 29400000 J
Next, we shall obtain the energy at height = 2000 m
Mass (m) = 1000 KgAcceleration due to gravity (g) = 9.8 m/s²Height (h) = 2000 mEnergy (E) =?E = mgh
E = 1000 × 9.8 × 2000
E = 19600000 J
Finally, we shall obtain the the energy lost by the car. Details below:
Energy (at height 3000 m) = 29400000 JEnergy (at height 2000 m) = 19600000 JEnergy lost =?Energy lost = Energy (at height 3000 m) - (at height 2000 m)
Energy lost = 29400000 - 19600000
Energy lost = 980×10⁴ J
Thus, we can conclude that the energy lost is 980×10⁴ J
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Complete question:
A car of mass 1,000 kg begins stationary on a road at the top of a mountain, at a height h = 3,000 m. The car then rolls freely down a winding road, travelling a total distance of 5 km, to reach the height h = 2,000 m. Assume g = 9.8 ms-2:
How much energy did the car lose on descent? Give you answer to 3 significant figures, with units.
Energy lost =?
A 2 kg basketball is thrown towards a stationary 1.35 kg kickball with a velocity of 2.37 m/s. After impact the kickball moves forward at a rate of 1.5 m/s. What is the velocity of the basketball after the collision?
Given,
Mass of basketball is 2 kg.
Mass of kickball is 1.32 kg
The initial velocity of the basket ball is 2.37m/s.
The final velocity of the kickball is 1.5 m/s
By conservation of momentum,
[tex]\begin{gathered} 2\times2.37=1.32\times1.5+2v \\ \Rightarrow v=\frac{1.38m}{s} \end{gathered}[/tex]The velocity of the basketball is 1.38 m/s
At which point is the water table closest to the surface? Explain.
I need to get it done right now
The point is the water table closest to the surface in valleys.
In areas of topographic relief, the water table generally follows the surface but tends to approach it in valleys and intersect the surface with streams and lakes. Closest to the surface is the vented zone where the interstices between the soil are filled with both air and water. Below this layer is a saturation zone where the gaps are filled with water.
The water table is the subsurface boundary between the soil surface and the area where groundwater saturates the space between sediment and rock fissures. At this boundary, water pressure equals atmospheric pressure. The top surface of the groundwater is the groundwater table. Beneath this surface, all pore spaces and cracks in sediments and rocks are completely filled and saturated with water. Groundwater occurs in these saturated layers known as saturation zones or water vapor zones.
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help please i need help
An object accelerates from rest to a speed of 24 m/s over a distance of 56 m. What
acceleration did it experience?
Answer:
5.14 m/s^2
Explanation:
v * t = distance AVERAGE velocity = (24-0) / 2 = 12 m/s
distance / v = time
56 m / 12 m/s = 4.67 s
vf = at
24 = a ( 4.67) a = 5.14 m/s^2
If X = 5 and Y = 3, what does Z equal?
Answer:
What is the figure? please provide
Which of the following statements about the nucleus of a typical atom (such as a carbon atom in your little finger) is FALSE:
A. the nucleus has an overall positive charge
B. the nucleus takes up a very small amount of space compared to the entire atom
C. the nucleus contains both protons and neutrons
D. the nucleus repels the electrons which move around it
E. the nucleus contains most of the mass of the atom
Answer:
D - False
Explanation:
D the protons and electrons are ATTRACTED to each other
The statement which is false about the nucleus of an atom is that the nucleus repels the electrons which move around it. Hence, option D is correct.
What is an atom?The atom is the smallest particle of matter that may be divided without releasing electrically charged. Additionally, it is the smallest piece of matter with the characteristics of a chemical substance. The atomic is the basic unit of chemistry as a result. The majority of an atom remains in space. A cluster of negative electrons surrounds a positive charge nucleus made up of nucleons, which make up the rest of the structure.
The electrons, the lightest alpha particles in nature, are larger and less dense than the nucleus, which is both small and dense. Electrons are drawn to positive charges by their electric forces, which also bind electrons to a nucleus in an atom.
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How do the Earth's physical factors influence population density? When population growth increases in an area, what is happening to the
birth rate and age structure of that population?
Any region's population density is determined by the physical characteristics of Earth.
Earth:
The only astronomical object known to harbour life is Earth, which is third from the Sun. Despite the vast amounts of water in the Solar System, only Earth has liquid surface water. Around 71% of the surface of the Earth is covered by the seas, dwarfing its lakes, rivers, and polar ice. The remaining 29% of the Earth's surface is made up of land, which includes continents and islands. The interplay between the numerous slowly moving tectonic plates that make up the Earth's surface layer produces mountain ranges, volcanoes, and earthquakes. The planet's liquid outer core generates the magnetic field that creates the magnetosphere and diverts dangerous solar winds.
The population density is greatly influenced by the physical characteristics of the Earth. It is evident that locations with ideal living circumstances have higher population densities. The population density is influenced by the temperature and climate.
An territory's birth rate will rise and its mortality rate will fall as population growth grows in that location. The population consequently starts to increase.
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A coin is dropped from a height of 80 m. How fast will it fall, just before it hits the ground? [Take g = 10 m/s2 , Hint: For a falling body, the total PE at the greatest height will be equal to the K.E., just before it touches the ground]
The speed of the coin just before it hits the ground dropped from a height of 80 m will be 40 m / s
The total PE at the greatest height = The K.E just before it touches the ground
PE = m g h
KE = 1 / 2 * mv²
PE = Potential energy
KE = Kinetic energy
m = Mass
g = Acceleration due to gravity
h = Height
v = Final velocity
h = 80 m
g = 10 m / s²
PE = KE
m g h = 1 / 2 * mv²
m * 10 * 80 = 1 / 2 * m * v²
v² = 800 * 2
v = √ 1600
v = 40 m / s
Potential energy is the energy at rest and kinetic energy is the energy in motion. Potential energy is maximum at rest and when the object starts to move, it potential energy drops and it kinetic energy rises.
Therefore, the speed of the coin just before it hits the ground is 40 m / s
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a car accelerates from rest to 30m/s while traveling a distance of 20m what was its acceleration
Answer:
22.5 m/s²
Explanation:
The final velocity, initial velocity, distance traveled and acceleration are related by the equation
v² = u² - 2ad [1]
where
v = final velocity
u = initial velocity
a = acceleration
d = displacement
We can manipulate the above equation [1] to solve for a in terms of the other parameters
a = (v² - u²)/2d
Given v = 30 m/s, u = 0 m/s, d = 20 m.
a = (30² - 0²)/(2 x 20)
a = 900/40
a = 22.5 m/s²
A ball, thrown upward, initially loses speed due to downward free-fall__________. At the top of it’s trajectory, it momentarily stops, then increases its speed as it descends. Throughout, its acceleration is ___________.
A ball, thrown upward, initially loses speed due to downward free-fall. At the top of it’s trajectory, it momentarily stops, then increases its speed as it descends. Throughout, its acceleration is (g)= 9.8 m/s²
What is acceleration?A particular object has changed its velocity in a particular time. That ratio called the acceleration of the object. Example: A car starts its journey from rest and ends at 25 m/s velocity in 5 second interval. So the acceleration is = 25/5 = 5m/s²
How can we calculate the acceleration of the ball?According to the definition of the acceleration due to gravity, Whenever a particle or a object throw upwards some amount of force attract that object at the center of the earth that is called the gravity. For this gravity that produce a acceleration due to gravity. The value of acceleration due to gravity is 9.8 m/s².
According to the question a ball is thrown upwards, initially loses speed due to downward free-fall. This case happens for the gravity.
At the top of it’s trajectory, it momentarily stops, then increases its speed as it descends. This also happens for the gravity cause the ball always attract the ball at the center of the earth.
For this attraction the acceleration due to gravity generated. So its acceleration throughout the case is same as the acceleration due to gravity, that means = 9.8 m/s².
According to the conversation, we can conclude that, Throughout, its acceleration is (g)= 9.8 m/s²
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)since individual stars can live from millions to billions of years, how can observations taken at the current time tells us about stellar evolution?
A nebula is a cloud of gas and dust that gives rise to stars. The lone star can shine on its own for a very long time. They are not everlasting, despite the fact that they shine for a very long period. These observations allow us to examine the inside of stars of various ages, each of which has a unique interior temperature and set of circumstances.
How do stars develop?In frigid clouds of gas and dust, stars form. Because dust is particularly opaque to optical and ultraviolet light, neither wavelength will get through the star-forming zone. Although less opaque than dust, gas remains opaque nonetheless. (b) Infrared, microwave, and radio wavelengths all easily penetrate dust. Additionally, dust scatters IR wavelengths to UV-optical light, which makes newborn stars and other dusty objects even luminous in the IR. Atomic and molecular gas that is cool (T 50 k) and dense is visible in the IR and also emits line radiation in the submm and radio.
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An Atwood machine consists of 40-kg object A and 43-kg object B. Suppose
object A is released from rest. Determine the magnitude of the acceleration for
both objects. Assume the rope and pulley are massless.
Help
The magnitude of the acceleration for both objects is 0.36 m/s².
Acceleration is the name we supply to any system wherein the velocity modifications. for the reason, that velocity is a velocity and a path, there are only methods in order to accelerate: trade your velocity or exchange your path or exchange each.
Acceleration is the fee of alternating of the velocity of an object with recognition to time. Accelerations are vector quantities. The orientation of an object's acceleration is given by means of the orientation of the internet pressure acting on that object.
Uniform acceleration, non-uniform acceleration, and average acceleration are the three varieties of multiplied motions. The term uniform acceleration refers to a motion in which an object travels in an immediate line with an increase in velocity at the same intervals of time.
calculation:-
mass 1 = 43 kg
F₁ = 430 N
mass 2= 40 kg
F₂ = 400 N
Tension = (F₁m₂ + F₂m₁)/ m₁ + m₂
= (430 × 40 + 400 × 43) / 83
=34400 /83
= 414.46 N
a = (F₁ - F₂)/ toatl mass
= 430 N - 400N / 83
= 0.36 m/s²
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HELP! PLEASE Show ALL the work, Thank you!
Jacque's velocity during the race segment is 3 meter/sec.
The direction of a body or object's movement is defined by its velocity. In its basic form, speed is a scalar quantity. In fact, velocity is a vector quantity. It has magnitude and direction both.
We are given that,
The time taken by Jacque = Δt = t₂ - t₁ = 7.0min - 3.5min = 3.5 min
The distance covered in race = Δx = x ₂- x₁ = 1260m - 630m = 630m
To get the velocity of the racer we can calculate by the equation,
V = Δx/ Δt
Here, Δx is the change in distance and Δt is the change in time of the racer. So putting the value in above equation for getting racer velocity,
V = 630m/3.5min
V = 180 m/min
V = 3 m/sec
Therefore , Jacque's velocity during the race would be 3 m/s.
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If a 60 kg student is standing on the edge of a cliff. Find the student's
gravitational potential energy if the cliff is 40 m high.
Formula with variables (letters):
Formula with numbers:-
Answer with units:
Answer: PE = 23535.96 J
Explanation: Screenshot is formula
A boy walks 1/4th of his journey at 2 m/s and run the rest at 3 m/s - what is his average speed?
Answer:
See below
Explanation:
1/4 d / 2 = time for 2 m/s
3/4d / 3 = time for 3 m/s
total distance / total time = average speed :
d / [ 1/4 d / 2 m/s + 3/4 d/ 3 m/s ] <=====simplify ( 'd' goes away)
1 / [ 1/4 / 2 + 3/4 / 3 ] = 2 2/3 m/s
if you transmitted radio signals to the moon when it is 385,000 km from earth and waited to receive the echo, how long would you wait (in s)?
If you transmitted radio signals to the moon when it is 385,000 km from the earth and waited to receive the echo, then you have to wait 2.57 seconds.
What is Velocity?The total displacement covered by any object per unit of time is known as velocity.
As given in the problem if you transmitted radio signals to the moon when it is 385,000 km from the earth and waited to receive the echo,
The speed of light = 3 × 10⁸ m /s
The distance traveled by the radio waves = 2 × 385,000 × 1000
= 770000000 meters
The time of the echo = 770000000 / 3 × 10⁸
= 2.57 seconds
Thus, you have to wait 2.57 seconds to receive the echo.
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A car with a mass of 1,500 kg is driving at 20 m/s. What is the kinetic energy of the car?
O 15,000 J
O 300,000 J
O 30,000 J
O 150,000 J
The kinetic energy of the car is 300,000J
What is Kinetic energy?Kinetic energy is the energy of motion.
The formula for kinetic energy is given as [tex]K.E = \frac{1}{2} mv^{2}[/tex]
where m = mass of object , v = speed of object.
An object having some speed and mass will have kinetic energy while an object at rest will not have any kinetic energy since the speed of object at rest is zero.
Since at rest speed is zero, an object has kinetic energy only when it is in motion.
From the question,
m = 1,500kg
v = 20m/s
K.E = (1/2) x 1,500 x 20 x 20
K. E = 300,000J
The car now possess a kinetic energy of 300,000J
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what is the moment of inertia of the object starting from rest if it has a final velocity of 5.8 m/s? express the moment of inertia as a multiple of mr2 , where m is the mass of the object and r is its radius.
The moment of inertia of the object as a multiple of MR² is 0.126 MR².
According to the law of conservation of energy he is always conserved at each and every point so going by this,
At the top will be equal to the energy at the bottom.
Because at the top there will be no kinetic energy and add the bottom there will be no potential energy the bottom there will be only kinetic energy and rolling energy.
So we can write,
Mgh = 1/2IW² +1/2MV²
Where,
M is the mass of the body,
G is acceleration due to gravity,
H is the height,
I is the moment of inertia,
W is angular velocity,
V is the linear velocity.
The height of the object is given to be 2.11 m. Final velocity is given to be 5.8m/s.
Now, putting all the values,
M(2.11)(9.8) = 1/2(IV²/R²) + 1/2MV²
I = 0.126MR²
Hence the moment of inertia of the object is 0.126MR².
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Complete question- an object rolls without slipping down a 2.1 m high incline.
What is the moment of inertia of the object starting from rest if it has a final velocity of 5.8m/s stress the moment of inertia as a multiple of MR² object and R is its radius.
Choose the statements that accurately describe the feeding relationships in this food web. Check all that apply.
The otter is a secondary consumer.
The frog is a secondary consumer.
The algae are producers.
The flies are primary consumers.
The snails are primary consumers.
The heron is a secondary consumer.
The algae are producers. The otter is a secondary consumer, frog is a secondary consumer. The flies are primary consumers, snails are primary consumers and heron is a secondary consumer. All statements are correct.
What is a food web?A food web is basically a graphical representation of animals eating each other in an ecological community that is formed by the natural interconnection of food chains.
Sea otters are secondary consumers that hunt sea urchins in the kelp forest. A secondary consumer is the great blue heron. It can be eaten by the food web's tertiary consumer.
Snails are herbivores, which means they only eat plants, and thus fit into the food web as primary consumers.
Herbivores are always the primary consumers, and omnivores can be the primary consumers when eating plants. Rabbits, bears, giraffes, flies, humans, horses, and cows are examples of primary consumers.
Thus, all the given statements are correct.
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a stores sign has a mass of 20kg and is 3.0 m long. it is unfirm. what is the magnitude of the force that the boly exerts on the sign
The boly pulls on the sign with a force of 60N, according to the magnitude formula f=MxA.
How would you define magnitude?Magnitude means essentially "distance or amount" in the perspective of physics. In terms of motion, it shows the relative or absolute size, direction, or movement of an object. It is employed to describe something's size or scope. Magnitude in physics generally refers to a quantity or quantity.
What are magnitude and intensity?The magnitude scale, which measures an earthquake's size, is unchanged by distance from the event. Nevertheless, strength reflects the level of rocking brought on by an earthquakes at a specific location and diminishes with distances from the epicentre.
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what is the average velocity of a race car that traveled 88km in 20 min
Answer:
73.3333meters per second
Explanation:
average velocity= distance ÷ time
=(88×1000)/(20×60)
=73.3333m/s
What is the wavelength in micrometers of light with a frequency of 3. 2 × 10^12 hz?.
94 mn the wavelength in micrometers of light with a frequency of 3. 2 × 10^12 hz.
What is wavelength?
The wavelength of a periodic wave is the distance over which the wave's shape repeats in physics. It is the distance between two successive corresponding locations of the same phase on the wave, such as two neighbouring crests, troughs, or zero crossings, and it is a feature of both travelling and standing waves, as well as other spatial wave patterns. The spatial frequency is the inverse of the wavelength. The Greek letter lambda (λ) is widely used to represent wavelength.
Because all electromagnetic waves travel at the speed of light, c = v (lambda) where v is frequency and lambda is wavelength and c is the speed of light.
v=c/λ
By putting the values -
3.2 × 10^12 = 3.00*10^8 / λ
λ= 3.0010^8 / 3.2 × 10^12
= 9.375m 1 / 10^
= 94 mn
Therefore the answer to this question is 94 mn.
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A golf ball rolls off a horizontal shelf with a velocity of 0.25 m/s. If it takes the ball 1.7 seconds to hit the ground, how high was the table? Choose the closest answer.
Answer:
Explanation:
Given:
V₀ = 0.25 m/s
t = 1.7 s
g = 9.8 m/s²
_____________
H - ?
H = V₀*t + g*t²/2
H = 0.25*1.7 + 9.8·1,7² / 2 = 14.6 m
