The brass rod expands 0.145 m more than the invar rod when the temperature increases by 9.0 K.
The linear expansion coefficient of brass is α_brass = 19 × 10^(-6) K^(-1) and the linear expansion coefficient of invar is α_invar = 1.2 × 10^(-6) K^(-1).
The amount that a rod expands is proportional to its length and the change in temperature, so the expansion of the brass rod is given by ΔL_brass = α_brass x L x ΔT, where L = 755 mm = 0.755 m is the initial length of the rod and ΔT = 9.0 K is the change in temperature.
The expansion of the invar rod is given by ΔL_invar = α_invar x L x ΔT.
The difference in the expansion of the two rods is ΔL_brass - ΔL_invar = (α_brass - α_invar) x L x ΔT = (19 - 1.2) × 10^(-6) K^(-1) x 0.755 m x 9.0 K = 0.145 m.
So the brass rod expands 0.145 m more than the invar rod when the temperature increases by 9.0 K.
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fill in the blanks.
a.Pressure is the..............applied per unit area.
b.The pressure..................as the depth of liquid increases.
a long, straight uniformly charged wire has a net charge per unit length of 2.58 coulombs/meter. what is the magnitude of the electric force in newtons exerted by this wire on a proton that is located a perpendicular distance 6.09 meters away from the wire?
The magnitude of the electric force in newtons exerted by this wire on a proton is 5.99 x 10¹⁰ N.
What is the magnitude of the electric force?
The magnitude of the electric force in newtons exerted by this wire on a proton that is located a perpendicular distance 6.09 meters away from the wire is calculated as follows;
F = Eq
where;
E is the electric field strengthq is the chargeF = ( kq² ) / r
where;
k is coulombs' constantr is the position of the chargeF = ( 9 x 10⁹ x ( 2.58 x 6.09 )² ) / ( 6.09² )
F = 5.99 x 10¹⁰ N
Thus, the electric force exerted by the charge is a function of the charge magnitude and the distance of the charge.
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A bra rod i 2m long at a certain temperature. What i it length for temperature rie of 100k,if the expanivity of bra i 18×10-6k-1
The length of brass rod after expansion is 2.0036m.
How to calculate length?By definition, the length increase is:
Delta L = Alpha L_0 Delta TΔL=αL
naΔT
where alpha = 18 times 10^{-6}K^{-1}α=18×10−6
K-1
is expansion, L0 = 2 ml
na=2m is the initial length and Delta T = 100KΔT=100K is the temperature change. How to get:
Delta L = 18 times 10^{-6}cdot 2cdot 100 = 3.6 times 10^{-3} = 0.0036mΔL=18×10
−6
⋅2⋅100=3.6×10
−3
= 0.0036 meters
So the final length is:
L = L0 + delta L = 2 m + 0.0036 m = 2.0036 ml = l
0
na
+ΔL=2m+0.0036m=2.0036m
Linear expansion is the rate of increase in length of a solid sample per unit rise in temperature. If the length of the sample increases from l1 to l2 as the temperature increases by θ°, the expansion (α) is given by
l2 = l1(1 + αθ). This relationship assumes that α is independent of temperature.
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if you have a cart rolling down an inclined track and wish to calculate the acceleration of the cart, what value do you need to know about the track-cart system?
Acceleration on a ramp equals the ratio of the height to the length of the ramp, multiplied by gravitational acceleration.
What is track-cart system?
The Dynamics Cart and Track System provides students with the tools they need to explore kinematics, dynamics, momentum, and energy. This versatile system can also be easily adapted to study optics, color, and diffraction.A set of dynamic cart trolleys are used for investigation on momentum, velocity and acceleration. Each trolley consists of two rectangular wooden blocks, 300 mm long, moving on three low friction wheels (ball bearings in wheels). The trolley is fitted with spring loaded impulse rod.The Dynamics Cart and Track System provides students with the tools they need to explore kinematics, dynamics, momentum, and energy.Each cart is 310 x 310 x 90mm. Mass per cart is 600 grams. Cart colour is grey.To learn more about track-cart refers to:
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What is the gage pressure at the bottom of the tank filled with water to a depth of 5 ft when the tank accelerates upward at a rate of 3.0 ft/s2. p= __ psi
80.0 psi is the gage pressure at the bottom of the tank filled with water to a depth of 5 ft when the tank accelerates upward at a rate of 3.0 ft/s2.
To determine the gage pressure at the bottom of the tank, we need to calculate the pressure difference due to the acceleration of the tank and the pressure due to the weight of the water. The pressure due to the weight of the water can be calculated using the equation
=> p = ρgh,
here,
p is pressure,
ρ is density of water,
g is acceleration due to gravity,
and h is height of the water column.
The density of water = 62.4 lb/ft^3
Acceleration (gravity) is 32.2 ft/s^2.
Hence,
=> p = ρgh
= 62.4 lb/ft^3 x 32.2 ft/s^2 x 5 ft
= 10080 lb/ft^2
Next, we need to calculate the pressure difference due to the acceleration of the tank. The pressure difference due to acceleration can be calculated using the equation:-
=> Δp
= ρV^2/2g,
here,
V is velocity of the fluid,
g is acceleration due to gravity.
We can assume that the velocity of the fluid at the bottom of the tank is zero, and the acceleration of the tank is 3.0 ft/s^2.
Hence,
=> Δp = ρV^2/2g
= 62.4 lb/ft^3 x (3.0 ft/s^2)^2 / 2 x 32.2 ft/s^2
= 623.04 lb/ft^2
Finally, the gage pressure at the bottom of the tank can be calculated by adding the pressure due to the weight of the water and the pressure difference due to the acceleration of the tank. The gage pressure is given in pounds per square inch (psi), which can be converted from pounds per square foot by dividing by 144.
Hence,
=> p = (p + Δp) / 144
= (10080 + 623.04) lb/ft^2 / 144
= 80.0 psi
Therefore, the gage pressure at the bottom of the tank filled with water to a depth of 5 ft when the tank accelerates upward at a rate of 3.0 ft/s^2 is 80.0 psi.
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What is refraction? please answer it help me
Answer: Refraction is the bending of light (it also happens with sound, water and other waves) as it passes from one transparent substance into another.
Explanation:
9. A 45.0 kg ice skater stands at rest on the ice. A friend tosses the skater a 5.0 kg ball. The skater and the ball then move backwards across the ice with a speed of 0.5 m/s. What was the speed of the ball at the moment just before the skater caught it?
Answer:
The speed of the ball at the moment just before the skater caught it can be found using the conservation of momentum principle. According to the principle, the total momentum of the system before the collision (ball moving towards skater) is equal to the total momentum of the system after the collision (ball and skater moving backwards).
The momentum of the ball before the collision is m_ball * v_ball, where m_ball is the mass of the ball and v_ball is the speed of the ball. The momentum of the skater before the collision is 0, since she is at rest.
The momentum of the ball and skater after the collision is (m_ball + m_skater) * v_after, where v_after is the final speed of the ball and skater moving backwards.
So, we can set up the equation:
m_ball * v_ball = (m_ball + m_skater) * v_after
We know that the final speed of the ball and skater is 0.5 m/s and we know the masses of the ball and skater.
Solving for v_ball:
v_ball = (m_ball + m_skater) * v_after / m_ball
v_ball = (5.0 kg + 45.0 kg) * 0.5 m/s / 5.0 kg
v_ball = 9.0 m/s
Therefore, the speed of the ball at the moment just before the skater caught it was 9.0 m/s.
what step of the scientific method involves looking closely at the physical universe for the purpose of gathering knowledge? reading quiz h abeke 10th grade
The step of the scientific method that involves looking closely at the physical universe for the purpose of gathering knowledge is called observation.
Observation is an essential component of the scientific method and involves the collection of data through the use of the senses, instruments, or other methods. The goal of observation is to gather accurate and reliable information about the natural world, which can then be used to develop hypotheses, test theories, and ultimately deepen our understanding of the universe.
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as you increase the temperature of a gas in a sealed, rigid container, what happens to the density of the gas? would the results be the same if you did the same experi- ment in a container with a piston at constant pressure? explain.
When the temperature of a gas is raised in a tightly sealed, rigid container, the gas's density will not change. In contrast, when the piston is kept at the same temperature in a container, density decreases.
Charles Law: At constant pressure, the volume occupied by the fixed amount of gas is directly proportional to its absolute temperature.
A gas's mass per unit volume is its density. Volume is directly proportional to temperature, as stated by Charles's law. Volume increases as temperature rises. However, in a rigid container, the gas's mass is unaffected by changes in temperature and volume. As a result, even as the temperature rises, density does not change.
The pressure in a container with a piston stays the same. As a result, according to Charles' law, gas density decreases as temperature rises during heating.
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The picture shows two teenagers riding identical skateboards.
The skateboards are moving at the same speed and the teenagers have the same mass.Explain why the teenagers don’t have the same momentum
The teenagers do not have the same momentum because momentum is a vector quantity, meaning it has both a magnitude and a direction. While the skateboards are moving at the same speed, they could be moving in different directions,
which would result in different momentum values. Additionally, the teenagers themselves could be moving at different speeds in relation to the skateboards, which would also affect their momentum. Even though the teenagers have the same mass, their momentum will be different based on their velocity or direction of motion.
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2. A 1250 kg car is moving down the highway with a velocity of 32.0 m/s when it bumps into the car ahead of it which has a mass of 875 kg and a velocity of 25.0 m/s. After the collision, the two cars stick together. What will be the resulting velocity of the two cars together? How much energy will be lost in this collision?
Answer:
The resulting velocity of the two cars together can be calculated using the law of conservation of momentum, which states that the total momentum of the system before the collision is equal to the total momentum after the collision. The momentum of the first car before the collision is 1250 kg * 32 m/s = 40,000 kg m/s and the momentum of the second car before the collision is 875 kg * 25 m/s = 21,875 kg m/s. The total momentum before the collision is 61,875 kg m/s.
After the collision, the two cars stick together, so the final velocity of the two cars together is the same. Therefore, the momentum of the two cars together after the collision is (1250 kg + 875 kg) * v = 2125 kg * v = 61,875 kg m/s. Solving for v, the final velocity of the two cars together is v = 61,875 kg m/s / 2125 kg = 29.2 m/s.
The energy lost in the collision can be calculated using the equation E = 1/2 * m * v^2, where m is the mass of the system and v is the change in velocity. The mass of the system is 2125 kg and the change in velocity is 32 m/s - 29.2 m/s = 2.8 m/s. Therefore, the energy lost in the collision is E = 1/2 * 2125 kg * (2.8 m/s)^2 = 1/2 * 2125 kg * 7.84 m^2/s^2 = 6614.4 J (Joules).
Answer:
Energy lost in the collision = approximately 6.14 x 10^6 Joules.
Explanation:
The resulting velocity of the two cars together can be found using the principle of conservation of momentum. The total momentum before the collision is the momentum of the first car plus the momentum of the second car, and this total momentum will be equal to the total momentum after the collision.
Momentum = mass x velocity
Total momentum before collision = (1250 kg x 32.0 m/s) + (875 kg x 25.0 m/s) = 40,000 kg m/s
Total momentum after collision = (1250 kg + 875 kg) x velocity = 2125 kg x velocity = 40,000 kg m/s
Velocity = 40,000 kg m/s / 2125 kg = 18.84 m/s
To find the energy lost in the collision, we can use the equation for the change in kinetic energy (1/2 * m * (vf^2 - vi^2))
Change in kinetic energy = 1/2 * (1250 kg + 875 kg) * (18.84 m/s - (32.0 m/s + 25.0 m/s))^2 = 1/2 * 2125 kg * (-33.16 m/s)^2
= 1/2 * 2125 kg * 1103.69 m^2/s^2
Energy lost in the collision = approximately 6.14 x 10^6 Joules.
If the tank to hold this water is 1.500 meters tall, what is the average velocity of a liter of water when it flows out of a faucet 1.000 meters above the floor on the ground floor?
The average velocity of a liter of water when it flows out of a faucet 1.000 meters above the floor on the ground floor is 1.82 m/s.
What is the time of motion of the water?The time taken for the water to fall from the given height is calculated as follows;
t = √ ( 2h / g )
where;
h is the height of fall of the waterg is acceleration due to gravityt = √[ ( 2 x 1.5 ) / ( 9.8 ) ]
t = 0.55 second
The average velocity of a liter of water when it flows out of a faucet 1.000 meters above the floor on the ground floor;
v = d / t
v = ( 1 m ) / ( 0.55 s )
v = 1.82 m/s
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what is the resolving power of the medium power objective if the condensor numerical aperture is 1.25, the medium power objective numerical aperture is 0.75, and the wavelength of light used is 520 nm?
The resolving power of the medium power objective in this case is 346.67 nm.
The resolving power of a microscope objective is a measure of its ability to distinguish two closely spaced objects. It is determined by the wavelength of light used and the numerical aperture (NA) of the objective. The NA is a measure of the ability of the objective to gather light from a sample and focus it onto the image plane. The higher the NA, the greater the resolving power. In this case, the NA of the medium power objective is 0.75 and the wavelength of light used is 520 nm. Using these values, we can calculate the resolving power as:
Resolving power = λ / (2 × NA)
Resolving Power = 520 nm / (2 × 0.75)
Resolving power = 520 nm / 1.5
Resolving power = 346.67 nm
So the resolving power of the medium power objective in this case is 346.67 nm.
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your friend anna explains that she believes that everything in the universe is in a constant state of change, so nothing is the same from one moment to the next. which famous philosopher would anna most agree with?
Anna mostly agrees with Heraclitus
Heraclitus of Ephesus was a Greek philosopher who lived before Socrates. He was from the city of Ephesus, which was a part of the Persian Empire at the time.
The life of Heraclitus is largely unknown. He only produced one piece, of which only fragments have survived. Based on interpretations of the preserved fragments, it is now believed that the majority of the ancient stories about him are fabrications. Since antiquity, his paradoxical philosophy, love of wordplay, and appreciation for cryptic expressions have earned him the moniker "the obscure." He was regarded as a miser who suffered from depression. In contrast to the ancient philosopher Democritus, who was referred to as "the laughing philosopher," he became known as "the weeping philosopher" as a result.
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the following three hot samples have the same temperature. the same amount of heat is removed from each sample. which one experiences the smallest drop in temperature,and which one experiences the largest drop? sample a. 4.0 kg of water sample b. 2.0 kg of oil sample c. 4.0 kg of dirt
Sample A of 4.0 kg of water would experience the smallest drop in temperature since water has a higher specific heat capacity than oil and dirt.
This means that water requires much more energy to heat or cool by the same amount as oil or dirt. Therefore, when the same amount of heat is removed from each sample, the water sample experiences the smallest drop in temperature.
Sample C of 4.0 kg of dirt would experience the largest drop in temperature due to its low specific heat capacity, meaning that it takes less energy to heat or cool dirt than water or oil.
Therefore, when the same amount of heat is removed from each sample, the dirt sample would experience the largest drop in temperature.
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what are the electric potential and the magnitude of the electric field at the center of the square due to all four charges?
The electric potential at the center of the square due to all four charges is 0 volts.
The magnitude of the electric field at the center of the square due to all four charges is 2.83 E₀ N/C.
The complete question is in the attachment. The electric potential from a charge V = kQ/r
k = electrostatic constant = 9 × 10⁹ Nm²/C²q = charge (C)r = distance (m)V = the electric potential (V)The electric potential from four charges
V = V₁ + V₂ + V₃ + V₄
V₁ = V₂ = V₃ = V₄ = V₀The sign of charges is also a sign of electric potential.Q₁ = Q₂ = - QV = V₁ + V₂ + V₃ + V₄
V = - V₀ + (- V₀) + V₀ + V₀
V = 0 Volts
The magnitude of the electric field from a charge E = (k × Q) ÷ r²
E = The magnitude of electric fields (N/C)The direction of the electric field at a point from positive charges away from positive charges.The direction of the electric field at a point from negative charges to negative chargesAt P
Q₁ a negative charge.E₁₃ = E₁ + E₃ = E₀ + E₀ = 2E₀
E₂₄ = E₂ + E₄ = E₀ + E₀ = 2E₀
The angle between E₁₃ and E₂₄ = 90°
E² = E₁₃² + E₂₄² = (2E₀)² + (2E₀)² = 4E₀² + 4E₀² = 8E₀²
[tex]E \:=\: \sqrt{8E_0^2}[/tex]
E = 2√2 E₀
E = 2.83 E₀ N/C
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Find the magnitude of the total electric force exerted on the charge q1.
The magnitude of the total electric force acting on q₁ charge is 1.487 Newton.
What is electric force?
Electric force is the attracting or repulsive interaction between any two charged things. Similar to any force, Newton's laws of motion describe how it affects the target body and how it does so.
The magnitude of the total electric force acting on q₁ charge is = kq₁/d²√(q₂² +q₃²)
= {8.99 × 10⁹ × (2.1 × 10⁻⁶)² √(2.0² + 3.0²) } ÷ (0.31)² Newton
= 1.487 Newton.
Hence, the magnitude of the total electric force acting on q₁ charge is 1.487 Newton.
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hat is a property of electric potential energy? always a negative value inversely proportional to the distance between subject and source a vector quantity with direction determined by the electric flux independent of the subject's charge
The electric potential energy is inversely proportional to the distance between subject and source. Option a is the correct answer.
The electric potential energy of any given charge or system of charges is termed as the total work done by an external agent in bringing the charge or the system of charges from infinity to the present configuration without undergoing any acceleration.
Electrostatic potential energy is given by the formula, U = [1/(4πεo)] × [q1q2/d].
where, q1, q2 are the electric charges,
d is the distance between the charges.
As per the formula, the energy is inversely proportional to the distance between subject and source.
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--The complete question is, Which of these below is a property of electric potential energy of point charges?
a) inversely proportional to the distance between subject and source
b) independent of the subject's charge
c) a vector quantity with direction determined by the electric flux
d) always a negative value--
if the distance to a star was suddenly cut in half, how many times brighter would the star appear?
If the distance to a star was suddenly cut in half, the star would appear 4 times brighter.
We know the expression between the intensity of star and the distance as, I ∝ 1/r²
where,
r is the distance
I is the intensity of light
Here, it is given that the distance is cut down by half, so, r becomes r/2.
Placing it in the above relation, we have, I ∝ 1/(r/2)²
⇒ I ∝ 4/r²
So, the relation says, the intensity becomes 4 times when the distance is reduced to half.
Thus, the star appears to be four times brighter.
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a red blood cell contains 2.7 107 free electrons. what is the total charge of these electrons in the red blood cell?
The total charge of these electrons in the red blood cell - 4.3 × 10⁻¹² Coulombs. The result is obtained by multiplying the number of electrons by the charge or each electrons.
What is charge?Charge is a physical property of subatomic particles that causes objects experience a attractive force toward one another.
An electron has the charge of - 1.602 × 10⁻¹⁹ Coulombs. If there are n electron, the charge is
q = ne
Where
q = chargen = number of electrone = charge of an electronA red blood cell contains 2.7 × 10⁷ electrons.
Find the total charge!
The total charge of the electrons in the red blood cell is
q = ne
q = 2.7 × 10⁷ × (- 1.602 × 10⁻¹⁹)
q = - 4.3 × 10⁻¹² Coulombs
Hence, in the red blood cell, the total charge of the electrons is - 4.3 × 10⁻¹² Coulombs.
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Which equation can be used to calculate the time of impact when you have the impulse and force applied to an object?
Answer:
t=J/F
Explanation:
We know that impulse is given by J = Ft
where F is the force applied and t is the time of impact
Rearranging the equation, we get,
t = J/F
how much compression is exerted on the radius at the elbow joint when the biceps brachii, oriented at a 30° angle to the radius, exerts a tensile force of 200 n
The compression exerted on the radius at the elbow joint is approximately 70 N.
To calculate the compression exerted on the radius at the elbow joint, we must consider the vector components of the tensile force exerted by the biceps brachii.
The biceps brachii muscle is oriented at a 30° angle to the radius, which means that the force it exerts can be divided into two components: one perpendicular to the radius (the compression force), and one parallel to the radius (the tensile force).
Using trigonometry, we can calculate the perpendicular component of the force as follows:
compression force = 200 N * cos(30°) = 173 N
This means that the compression force is 173 N. However, it's important to note that this is an idealized calculation and does not take into account the effects of other muscles and tendons that may be present at the elbow joint, which can affect the actual compression force.
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a photographer in a helicopter ascending vertically at a constant rate of 1.2m/s accidentally drops a camera out the winder when the helicopter is 62m above the ground. how long will it take the camera to reach the ground
The time by the camera to reach the ground is 3.43 seconds, if it was initially coming down at the speed of 1.2 m/s.
Initial speed of the camera, u = 1.2 m/s
Acceleration due to gravity, g = 9.81 m/s²
Height of falling, h = 62 m
Let the time taken by the camera, = t
Now, by the second equation of motion
h = ut + 0.5gt²
62 = 1.2×t + 0.5×9.81×t²
4.905t² + 1.2t - 62 = 0
On solving we get, t = 3.435 sec and - 3.68
Ignoring the negative value, t = 3.435 seconds
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How long will it take for the plutonium to no longer exist?
Answer: Plutonium has a half life of 24,000 years meaning for plutonium to decay naturally, it would take 240,000 years.
Answer:
The time required for a radioactive substance to lose 50 percent of its radioactivity by decay is known as the half-life. Plutonium-238, plutonium-239, and plutonium-240 are isotopes of plutonium, and have half-lives of 87 years for plutonium-238, 24,065 years for plutonium-239, and 6,537 years for plutonium-240.
Explanation:
a spinning disk has a mass of 0.5 kg and a radius of 0.2 m. the disk is spinning at an angular velocity of 2 rad/s. what is the angular momentum of the disk? (i
Angular momentum in the absence of any external torque remains constant.
What is the angular momentum of the disk?
Suppose we have a disk of radius r and mass m travelling at velocity v. I want to calculate the instantaneous angular momentum with axis through the edge of the disc (on the circumference). Angular momentum =Iω. I=12mr2+mr2=32mr2 by the parallel axis theorem.The angular momentum of a particle rotating about an axis is defined as the moment of the linear momentum of the particle about that axis. It is measured as the product of linear momentum and the perpendicular distance of its line of action from the axis of rotation.Angular momentum is basically the product of the moment of inertia of an object and its angular velocity. Furthermore, both the quantities must be about the equal and the same axis i.e. the rotation line.
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what effect or effects would be most significant if the moon's orbital plane were exactly the same as the ecliptic plane? group of answer choices solar eclipses would be much more frequent. solar eclipses would last much longer. solar eclipses would be much rarer.
Solar eclipses would be much more frequent if the moon's orbital plane were the same as the ecliptic plane
What is ecliptic plane?
The ecliptic plane is defined as the imaginary plane containing the Earth's orbit around the sun. In the course of a year, the sun's apparent path through the sky lies in this plane.The ecliptic is so named because the ancients noted that eclipses only occur when the Moon is crossing it.Ecliptic, in astronomy, the great circle that is the apparent path of the Sun among the constellations in the course of a year; from another viewpoint, the projection on the celestial sphere of the orbit of Earth around the Sun. The constellations of the zodiac are arranged along the ecliptic.The Earth orbits the Sun on a particular angle and its orbit is elliptical in shape. The orbit is often shown as an ellipse made of dotted lines with the Sun at its center. If you made this ellipse a solid surface and extended it infinitively, then you would have the plane of the ecliptic.To learn more about ecliptic plane refers to:
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Ima Rilla Saari rushes to her car in order to hurry home and get dressed for work. Failing to realize the dangers of driving under slick and icy conditions, she collides her 964.0-kg Mazda Miata into the rear of a 3280.0-kg pick-up truck which was at rest at the light on Lake Avenue. Ima's pre-collision speed was 12.1 m/s. Determine the 3280.0-collision speed of the two entangled cars as they slide across the ice.
Answer:
The collision speed of the two cars is 8.8 m/s.
hree thin rods of length l are arranged in an inverted u. the two rods on the arms of the u each have mass m; the third rod has mass 3m. where is the center of mass of the assembly?
The y coordinate of the center of mass of the system is located at L/5. In this system, the two rods on the arms of u each have a mass of m; the third rod has a mass of 3m.
Substitute 0 for x₁, L/2 for x₂, and L for x₃ in the equation
Xcom = Mx₁+(3M)x₂+Mx₃/M+3M+M
Xcom = M(0)+(3M)(L/2)+M(L) / M+3M+M
= 5ML/2(5M)
= L/2
Therefore, the x coordinate of the center of mass of the system is located at L/2.
Similarly, substitute -L/2 for y₁, 0 for y₂, and -L/2 for y₃ in the equation,
Ycom = My₁+(3M)y₂+My₃ / M+3M+M,
Ycom = M(-L/2)+(3M)(0)+M(-L/2) / M+3M+M
= -ML/5ML
= -L/5
The negative sign highlights the fact that the point is in the downward direction relative to the origin. Therefore, the y coordinate of the center of mass of the system is located at L/5.
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The internal energy of an ideal gas is changed by adding heat Q to the system and also by doing work W on the gas. What is the change in internal energy of the gas?
A)Q - 4.186W
B)Q - W
C)Q + W
D)W - Q
E) 4.186Q - W
When an ideal gas's internal energy is altered by both doing work W on the gas and introducing heat Q to the system, the result is Q - W.
Given the heat added = Q
Since the work is done on the system = W
We know that the change in internal energy is represented s:
ΔU = Q - W
The function's initial and final states determine the change in internal energy (U), whereas Q and W also depend on the path taken. The internal energy increases when the temperature does, and vice versa. The system's internal energy grows by the amount, U = Q, when the amount of heat Q is introduced to it while the system remains motionless. In the case of an endothermic reaction, the system produces heat and q has a positive sign. The system loses energy whenever it performs any work, hence the sign of w is negative.
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what fraction of the incident intensity of a sound pulse will be reflected when sound travels from fat into lung? express your answer in percent.
The fraction of incident intensity of a sound pulse that will be reflected when sound travels from fat into lung is 58.24%
What is sound?An elastic material medium allows sound, a mechanical disturbance from an equilibrium state, to travel through it. It is also possible to define sound solely subjectively, as that which is perceived by the ear. However, this definition lacks clarity and is overly constrictive, as it is useful to discuss sounds that are produced by devices other than the human ear, such as dog whistles and sonar equipment, which cannot be heard by the human ear.
Starting with the characteristics of sound waves is important when studying sound. Transverse and longitudinal waves are the two basic types of waves, which are distinguished by the way in which the wave moves.
[tex]$$\rho=$ Density of material\\$\mathrm{c}=$ Acoustic velocity\\\\Impedance is given by$$Z=\rho c$$Acoustic impedance of lung$$Z_l=\rho_l c_l=0.18 \times 10^6 \mathrm{kgs} / \mathrm{m}^2$$Acoustic impedance of fat$$Z_f=\rho_f c_f=1.34 \times 10^6 \mathrm{kgs} / \mathrm{m}^2$$[/tex]
[tex]$$Reflection coefficient is given by$$\begin{aligned}& R=\left(\frac{Z_l-Z_f}{Z_l+Z_f}\right)^2 \\& \Rightarrow R=\left(\frac{0.18 \times 10^6-1.34 \times 10^6}{0.18 \times 10^6+1.34 \times 10^6}\right)^2 \\& \Rightarrow R=0.5824\end{aligned}$$[/tex]
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