Elements in a period on the periodic table have different properties that repeat across the next period.
Why do properties change across a period?
In a period, on moving from left to right across a period,number of valence electrons in the valence shell goes on increasing as electrons are added to the same shell.
Across a period as no new valence shell is added the elements in a period, have different valence electrons and hence different properties.
Elements belonging to the same group have same number of valence electrons because in a group in every successive element a new shell is added,valence electrons present in which remain the same and hence their properties are similar.
As the elements are arranged in a way such that their properties are repeated at regular intervals,elements in a period have different properties which repeat across the next period.
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A gaseous mixture containing 32.00 g n2 and 16.00 g ne is placed into an 4.00 l vessel at 0.00 °C. What is the pressure of the mixture?
The pressure of the mixture can be found out adding the Partial Pressure of the gas.
Partial pressure of gas is the pressure if it alone occupied the entire volume of original mixture.
Moles = given mass / molar mass
Given,
Mass of Nitrogen = 32g
Molar Mass of Nitrogen = 28g
Mass of Neon = 16g
Molar Mass of Neon = 20g
Volume of gas = 4L
Temperature of vessel = 0°C = 273K
Partial Pressure of nitrogen = P₁
Partial Pressure of neon = P₂
Moles of nitrogen, n₁= 32/28 = 1.14
Moles of neon, n₂= 16/20 = 0.8
Using Ideal gas equation for Nitrogen,
∴ P₁V = n₁RT
⇒ P₁ (1) = 1.14 × 0.082 × 273
⇒ P₁ = 25.52atm
Using Ideal gas equation for Neon,
∴ P₂V = n₂RT
⇒ P₂ (1) = 0.8 × 0.082 × 273
⇒ P₂ = 17.9 atm
Total pressure of the mixture can be found out by adding the partial pressures of both the gases.
Total pressure P = P₁ + P₂
P = 25.52 + 17.9 atm
P = 43.42 atm
Hence, total pressure of the mixture is 43.42atm
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A voltaic cell has a zinc anode and a copper cathode. They are connected by a wire but no salt bridge. What can you predict will happen? A. Without a salt bridge to slow it down the reaction will occur faster than normal. B. The electrons will flow to the zinc anode where a negative charge will build up and eventually halt the reaction. C. None of these D. The electrons will flow to the copper cathode where a negative charge will build up and eventually halt the reaction.
The prediction is that B. The electrons will flow to the zinc anode where a negative charge will build up and eventually halt the reaction.
What is zinc?This is known as a chemical element, of the periodic table, that is essential to life and is one of the most widely used metals. Zinc is of considerable commercial importance.
Without the salt bridge, positive and negative charges will build up around the electrodes causing the reaction to stop.
Hence, we know that the purpose of the salt bridge is to keep the solutions electrically neutral and allow the free flow of ions from one cell to another.
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If the rock had originally 2400 atoms of u 235 and now has 440 left, how many atoms of pb 207 are there in the rock now?
436 atoms of Pb 207 are left in the rock.
Radioactive decay:Alpha and beta decays are the mechanism through which uranium transforms into the lead. While 235U and its daughter nuclides only experience seven alpha and four beta decays, 238U and its daughter nuclides suffer eight alpha and six beta decays overall.
When there are too few neutrons in relation to protons, alpha decay occurs. There is the discharge of an alpha particle, which consists of two protons and two neutrons.
When there are more neutrons than protons, beta decay can happen. A high-speed electron is ejected from a proton that transforms spontaneously from a neutron.
Since gamma radiation is emitted as a wave rather than a particle, the atomic structure of an atom remains unaltered. Atomic fission is the primary cause of neutron emission. At one time, many neutrons can be released.
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Calculate the standard potential, ∘, for this reaction from its δ∘ value. x(s) y2 (aq)⟶x2 (aq) y(s)δ∘=−61. 0 kj
The equilibrium potential and the standard free energy change can give the standard potential of the electrodes. The standard cell potential is 0.32 V.
What is standard free energy change?A reaction's standard free energy change (∆Gº') is the energy produced when the reactants undergo changes to form the product. It is given as,
ΔG° = -nFE° cell
Given,
Standard free energy change (ΔG°) = − 61. 0 kJ
Number of moles of electrons (n) = 2
Faraday's constant (F) = 96500 C
The standard cell potential (E° cell) is calculated as:
E° cell = ΔG° ÷ -nF
E° cell = − 61000 ÷ -(2 × 96500)
E° cell = 61000 ÷ 193000
= 0.32 V
Therefore, 0.32 V is the standard cell potential of the cell.
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The molar solubility of cui is 2. 26 × 10-6 m in pure water. Calculate the ksp for cui.
Ksp(the solubility product constant) = [Cu⁺] [I⁻]
So, the Ksp for Cui would be:
Ksp = (2.26 × 10⁻⁶) (2.26 × 10⁻⁶) = 5.11 x 10⁻¹²
Formula used:
K = [tex]K_{sp} = [A^+]^a [B^-]^b[/tex], where
Ksp = solubility product constant
A⁺ = cation in an aquious solution
B⁻ = anion in an aqueous solution
a, b = relative concentrations of a and b
DefinitionThe equilibrium constant for a solid material dissolving in an aqueous solution is the SOLUBILITY PRODUCT CONSTANT, Ksp. It stands for the degree of solute dissolution in solution. A substance's Ksp value increases with how soluble it is.
Take into account the general dissolving response (in aqueous solutions) below:
aA(s)⇔cC(aq)+dD(aq)
The molarities or concentrations of the products (cC and dD) must be multiplied in order to find the Ksp. Any product that has a coefficient in front of it must be raised to the power of that coefficient (and also multiply the concentration by that coefficient).
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A gas effuses 4.0 times faster than oxygen (o2). what is the molecular mass of the gas? 1.0 g/mol 1.0 g/mol 2.0 g/mol 2.0 g/mol 4.0 g/mol 4.0 g/mol 7.67 g/mol
Answer:
32(molecular mass has no unit )
Explanation:
(16)(o2)
16×2
=32
What was the average molarity of the sodium hydroxide solution obtained from your two fine titrations?
Divide the number of moles of NaOH by the number of liters of NaOH solution needed to reach the titration's endpoint to determine the molarity of the NaOH solution.
"The process of calculating the quantity of a material A by adding measured increments of substance B, the titrant, with which it reacts until exact chemical equivalency is obtained (the equivalence point)" is the definition of titration.
Titration is a method of chemical analysis where the amount of a sample's ingredient is determined by adding an exact known amount of a different substance to the measured sample in which the desired constituent interacts in a specific, known proportion.
The equivalence point, or the point at which chemically equivalent amounts of the reactants have been combined, is to be detected by the titration. The stoichiometry of the reaction determines how many reactants have been combined at the equivalence point.
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Suppose that 25. 0 ml of 0. 10 m ch3cooh(aq) ( ka =1. 8 x 10-5) is titrated with 0. 10 m naoh(aq). (a)what is the initial ph of the 0. 10 m ch3cooh (aq) solution?
The initial ph of the 0. 10M ch3cooh (aq) solution is -0.64.
The salt sodium acetate is present at the equivalency point. It is a salt of a strong base and a weak acid. The expression "its pH" provides the information.
pH = 7 + 0.5p + 0.5logC
where C is the salt concentration. Monobasic acid is Acetic acid here.
25 ml of 0.10 M NaOH solution are needed for the titration of 25 ml of 0.10 M acetic acid.
Total volume = 25 + 25 = 50ml
The salt concentration = C = 0.10× = 0.05
The pH for weak acid is given by,
pH = [tex]\frac{1}{2}[/tex] (p[tex]K_{a}[/tex] + logC)
pH = [tex]\frac{1}{2}[/tex] (1.8× + log0.05)
pH = [tex]\frac{1}{2}[/tex] [1.8× + (-1.30)]
pH = [tex]\frac{1}{2}[/tex] (1.8× -1.30)
pH = -0.64
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The pH of an aqueous solution is determined to be 3. What is the hydronium ion concentration of the
solution?
A. [H3O+] = 1 x 10-³ M
B. [H3O+] = 3 x 10-³ M
[H3O+] = 1 x 10-11 M
D. [H3O+] = 3 x 10-11 M
Considering the definition of pH, the hydronium ion concentration [H₃O⁺] of the solution is 1×10⁻³ M.
Definition of pHpH is the Hydrogen Potential. It is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.
Mathematically, pH is calculated as the negative base 10 logarithm of the activity of hydrogen ions:
pH= - log [H⁺]= -log [H₃O⁺]
The numerical scale that measures the pH of substances includes the numbers from 0 to 14. The pH value 7 corresponds to neutral substances. Acidic substances are those with a pH lower than 7, while basic substances have a pH higher than 7.
Hydronium ion concentrationIn this case, being pH= 3, you can replace this value in the definition of pH:
3= -log [H₃O⁺]
Solving:
[H₃O⁺]= 10⁻³ M
[H₃O⁺]= 1×10⁻³ M
Finally, the hydronium ion concentration [H₃O⁺] of the solution is 1×10⁻³ M.
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Compute the theoretical density of zns given that the zn-s distance and bond angle are 0. 234 nm and 109. 5o, respectively? The atomic weights of zinc and sulfur are 65. 41 g/mol and 32. 06 g/mol.
Density of ZnS given that the zn-s distance and bond angle are 0. 234 nm and 109. 5o, respectively if the atomic weights of zinc and sulfur are 65. 41 g/mol and 32. 06 g/mol. is 4.1109 g/cm³
For density In the crystal structure, we determine the angle's value for one set of ZnS bonds. θ θ + ∅ + 90° = 180° θ = 90° - ∅ θ = 90° - (109.5° / 2) After determining that = 35.25°, we derive the value of x from the geometry: distance angle d = 0.234 x = dsin = 0.234 sin35.25°) = 0.135 nm = 0.135 107 cm; following this, we get the length of the unit cell: a = 4x a = 4(0.135) a = 0.54 nm = 0.54 107 cm; and The formula for n' is (number of corner atoms in unit ell contribution of each corner atom in unit cell) + (number of face center atoms in unit cell contribution of each face center atom in unit cell). n' = 8 × 1/8) + (6 × 1/2) = 1 + 3 = 4
Density = P = [4( 65.41 + 32.06)] / [ ( 0.54 × 10⁻⁷ )³ × (6.023 × 10²³)] = 389.88 / 94.84 = 4.1109 g/cm³
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The ionic compound iron(ii) sulfate is used in iron-containing supplements. What does the (ii) in the name of this compound specifically indicate?
The iron ion's charge is +2 in iron (II) sulfate, which is denoted by the symbol (II).
Information about iron (II) sulfate:
A group of salts having the formula FeSO4xH2O is referred to as iron(II) sulfate or ferrous sulfate. Although there are multiple known values for x, the heptahydrate form of these chemicals is the most frequent. The hydrated form has both commercial and medicinal uses, including the treatment of iron deficiency.The identical aqua combination [Fe(H2O)6]2+, which has octahedral molar mass and is paramagnetic, is produced when all iron(II) sulfates are dissolved in water. Historically, copper(II) sulfate was referred to as blues copperas, and iron(II) and zinc sulfate were referred to, correspondingly, as greenish and white copperas.Learn more about iron here:
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Who invented the clay triangle?
A chemistry laboratory device is a clay triangle to support the crucible when heated to high temperatures. It consists of a three-sided triangle frame made of clay or ceramic material.
The heat can pass through the open sides and is evenly distributed throughout the crucible. Although the soil triangle is a common and commonly used piece of laboratory equipment, it is difficult to ascertain who actually invented it.
The design of the clay triangle probably changed over time as a result of diverse contributions from scientists and chemists working on building laboratory equipment. The soil triangle may not have had a clear beginning, as is the case with many scientific instruments, but it is considered an evolution in laboratory technology overall.
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A 0.200 M solution of a weak acid, HA, is 9.4% ionized. Using this information, calculate Ka for HA.
Select one:
a.
9.4 × 10−3
b.
1.8 × 10−3
c.
1.9 × 10−2
d.
3.8 × 10−3
[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]
Let's solve ~
Initial concentration of weak acid HA = 0.200 M
and dissociation constant ([tex]{ \alpha} [/tex]) is :
[tex]\qquad \sf \dashrightarrow \: \alpha = \frac{dissociation \: \: percentage}{100} [/tex]
[tex]\qquad \sf \dashrightarrow \: \alpha = \frac{9.4}{100} = 0.094[/tex]
Now, at initial stage :
[tex] \textsf{ Conc of HA = 0.200 M} [/tex][tex] \textsf{Conc of H+ = 0 M} [/tex][tex] \textsf{Conc of A - = 0 M} [/tex]At equilibrium :
[tex] \textsf{Conc of HA = 0.200 - 0.094(0.200) = 0.200(1 - 0.094) = 0.200(0.906) = 0.1812 M} [/tex][tex] \textsf{Conc of H+ = 0.094(0.200) = 0.0188 M} [/tex][tex] \textsf{Conc of A - = 0.094(0.200) = 0.0188 M} [/tex]Now, we know :
[tex]\qquad \sf \dashrightarrow \: { K_a = \dfrac{[H+] [A-]}{[HA]}} [/tex]
( big brackets represents concentration )
[tex]\qquad \sf \dashrightarrow \: { K_a = \dfrac{0.0188×0.0188}{0.1812}} [/tex]
[tex]\qquad \sf \dashrightarrow \: { K_a = \dfrac{0.00035344}{0.1812}} [/tex]
[tex]\qquad \sf \dashrightarrow \: { K_a \approx 0.00195 } [/tex]
[tex]\qquad \sf \dashrightarrow \: {K_a \approx 1.9 × {10}^{-3} } [/tex]
According to the problem, we have a 0.200 M solution of a weak acid HA that is 9.4% ionized. To find the Ka (acid dissociation constant) for HA, we can use the percent ionization formula:
[tex]\sf \% \: ionization = \dfrac{[H+]}{[HA]initial \times 100}[/tex]From this formula, we know that [H+] (the concentration of hydrogen ions) is equal to 9.4% of [HA]initial, and [HA]initial is equal to the initial concentration of the weak acid, which is 0.200 M. Solving for [H+], we get:
[tex]\sf [H+] = 0.094 \times 0.200 \: M = 0.0188\: M[/tex]Now we can use the equation for Ka:
[tex]\sf Ka = \dfrac{[H+][A-]}{[HA]}[/tex]We don't know the concentration of the conjugate base (A-) at this point, but we can assume that it is equal to [H+] because the weak acid is only slightly ionized. Therefore, we can substitute [A-] = [H+] = 0.0188 M into the equation and solve for Ka:
[tex]\sf Ka = \dfrac{(0.0188)^2}{(0.200 - 0.0188)} = \bold{1.8 \times 10^{-3}}[/tex]
So the answer is [tex]\bold{ B.\: 1.8 \times 10^{-3}}[/tex].
I hope this helps!
A combustion reaction will always be associated with a change in entropy that will be:_________
A combustion reaction will always be associated with a change in entropy that will be positive.
What is entropy ?The entropy of a system is the measurement of the disorder of the system which happens in the thermodynamic reaction.
During association the value of entropy will be positive and during dissociation the value will be negative.
During association the number of molecule increases due to which the entropy of the combustion increases and the value will be positive .
Therefore , combustion reaction will always be associated with a change in entropy that will be positive.
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A 1. 3×10−6mol sample of sr(oh)2 is dissolved in water to make up 25. 0 ml of solution. what is the ph of the solution at 25. 0∘c?
The pH of the solution at 25 degree celsius of 1.3 × 10⁻⁶ moles of a sample of Sr(OH)₂ is 10.02.
How do we calculate pH?The pH of any solution gives an idea about the acidic and basic nature of the solution and the equation of pH will be represented as:
pH + pOH = 14
Given that,
Moles of Sr(OH)₂ = 1.3 × 10⁻⁶ mol
Volume of solution = 25mL = 0.025L
The concentration of Sr(OH)₂ in terms of molarity = 1.3×10⁻⁶/0.025
= 5.2×10¯⁵M
Dissociation of Sr(OH)₂ takes place as:
Sr(OH)₂ → Sr²⁺ + 2OH⁻
From the stoichiometry of the reaction 1 mole of Sr(OH)₂ produces 2 moles of OH⁻.
Given that the base is a strong base and that it entirely dissociates into its ions, the hydroxide ion concentration is 5.2×10¯⁵×2 = 1.04×10¯⁴ M.
pOH = -log[OH⁻]
pOH = -log(1.04×10¯⁴)
pOH = 3.98
Now we put this value on the first equation we get,
pH = 14 - 3.98 = 10.02
Therefore, the value of pOH is 10.02.
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Determine the age of a rock (in years) containing 0. 068 g of uranium-238 (t1/2 = 4. 5×109 yr) and 0. 025 g of lead-206. (assume that all the lead-206 came from 238u decay. )
The age of rock that is containing 0.628 g Uranium-238 is 2032631864.35 years.
What is half-life?Half-life can be given as the time required by the object to reduced to half of its initial concentration. The concentration remained can be given as:
Final concentration = Initial concentration * 1/2 ^ (t/t1/2)
The initial concentration of rock has been the remaining uranium-238 and lead-206 cumulative concentration. Thus, the initial concentration is given as:
Initial concentration = Uranium-238 + Lead-206
Initial concentration = 0.068 g + 0.025 g
Initial concentration = 0.093g
The final concentration of Uranium-238 remained = 0.68 g
The half life given = 4.5 × 10⁹ years
The age (t) of the rock can be given as:
[tex]0.068=0.093\left(\frac{1}{2}\right)^{\frac{t}{4.5\times \:10^9}}\\\\\frac{t\times \:10^{-9}}{4.5}\ln \left(\frac{1}{2}\right)=\ln \left(\frac{68}{93}\right)\\\\t=2032631864.35961[/tex]
Thus, the age of rock that has remaining 0.068 g Uranium-238 is 2032631864.35 years.
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Calculate the number of molecules in 1500 mL of a gas measured under a pressure of 800.0
torr at 19.0°C
Answer:
3.97 x 10²² molecules
Explanation:
To find the moles, you need to use the Ideal Gas Law:
PV = nRT
In this equation,
-----> P = pressure (atm)
-----> V = volume (L)
-----> n = moles
-----> R = Ideal Gas constant (0.08206 atm*L/mol*K)
-----> T = temperature (K)
Before you can plug the values into the equation, you need to (1) convert the pressure from torr to atm (by dividing by 760), then (2) convert the volume from mL to L (by dividing by 1000), and then (3) convert the temperature from Celsius to Kelvin (by adding 273).
P = 800.0 torr / 760 = 1.05 atm R = 0.08206 atm*L/mol*K
V = 1500 mL / 1000 = 1.5 L T = 19.0 °C + 273 = 292 K
n = ? moles
PV = nRT
(1.05 atm)(1.5 L) = n(0.08206 atm*L/mol*K)(292 K)
1.579 = n(23.96)
0.0659 = moles
Now, you need to convert moles to molecules using Avogadro's Number.
Avogadro's Number:
6.022 x 10²³ molecules = 1 mole
0.0659 moles 6.022 x 10²³ molecules
------------------------ x ------------------------------------- = 3.97 x 10²² molecules
1 mole
The molar absorption coefficient of a substance dissolved in benzene is measured to be 712 L mol-1 cm-1 at 403 nm. Calculate what fraction of the incident light intensity of that wavelength passes through 2.67 mm of a solution of concentration 3.17 mmol/L.
According to Beer-Lambert's law, the solution allows for the passage of 3/4 of the incoming light intensity at that wavelength.
Calculation:
According to Beer-Lambert's law,
A = ∈ * C * l
A = log(I₀/I)
T = I₀/I
log (I₀/I) = ∈ * C * l
Here,
A= absorbance of the solution
l= path length= 2.67 mm = 0.267 cm (∵ 1mm = 0.1 cm)
T= transmittance
C= concentration of the given solution = 3.17mmol/L = 3.17* 10⁻³ mol/L
I= transmitted light
I₀= incident light
∈= molar absorption coefficient = 712 L mol⁻¹cm⁻¹
A = ∈ * C * l= 712 * 3.17 * 0.267 *10⁻³ = 602.63* 10⁻³ =0.602
T = [tex]10^{-A}[/tex] = [tex]10^{-0.602}[/tex] = 0.25
so, the percentage of transmittance = 0.25 * 100 = 25 %
Therefore, the intensity reduction will be equal to the original radiation intensity less the transmittance.
Give the initial intensity = 100
So, the reduction = 100 - 25 = 75.
Hence the fraction of incident light intencity= 75/100 = 3/4
Therefore the answer is 3/4.
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In a chemical equation, the number of atoms of a particular element that are present in a substance is indicated by a:________.
Answer:
subscript
Explanation:
H₂ O means there are two hydrogen atoms and one oxygen atom
the ' ₂ ' is a subscript
What is the kb of the base po−34 given that a 0. 48m solution of the base has a ph of 12. 70? the equation described by the kb value is:___________
The equation described by the kb value is 5.21 x [tex]10^-^3[/tex].
The potential of Hydrogen is what pH is formally known as. The negative logarithm of the concentration of H+ ions is known as pH. Thus, the definition of pH as the amount of hydrogen is provided. The hydrogen ion concentration in a solution is described by the pH scale, which also serves as a gauge for the solution's acidity or basicity.
Assuming PO₄³⁻ (the phosphate anion).
PO₄³- + H₂O ==> HPO₄²⁻ + OH⁻
Kb = [HPO₄²⁻][OH⁻] / [PO₄³⁻]
We can find the [OH⁻] from the pH of 12.70.
pH + pOH = 14
14.0 - 12.7 = 1.3 = pOH
[OH] = 1x[tex]10^-^1^.^3[/tex]
[OH-] = 5.0x[tex]10^-^2[/tex] M
[HPO₄²⁻] = 5.0x[tex]10^-^2[/tex] M
Kb = (5.0x[tex]10^-^2[/tex])2 / 0.48
= 2.5x[tex]10^-^3[/tex] / 0.48
Kb = 5.21 x [tex]10^-^3[/tex]
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If 30. 0 ml of 0. 150 m CaCl2 is added to 15. 0 ml of 0. 100 m AgNo3, what is the mass in grams of AgCl precipitate?
The mass of AgCl precipitated is 0.215g.
What do you mean by precipitation?Precipitate is to form an insoluble compound either by reacting two salts or by changing the temperature to affect the solubility of the compound.
To calculate mass of AgCl precipitate -
The first step is to make a balanced chemical equation.
2AgNO3 + CaCl2 ---> 2AgCl + Ca(NO3)2
Molecular Weights:
CaCl2 = 110.98 g/mol
AgNO3 =170.01g/mol
AgCl= 143.45 g/mol
Volume:
CaCl2: 30.0mL=0.03L
AgNO3: 15.0mL=0.015 L
mole CaCl2 = 30/1000 x 0.2 =0.006
mole AgNO3 =15/1000 x 0.1 = 0.0015
CaCl2 is in excess so 0.0015 mole AgCl will form
0.0015 x 143.5 = 0.215g
The 0.215 mass in grams of AgCl will precipitate.
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Structures of compounds people use every day are shown. From which group of unsaturated hydrocarbons is each derived? 2 carbons are double bonded together, with H bonded to the left, and C H 2 bonded below left, above right, and below right. In a segment of an ongoing chain, 3 iterations of this structure are bonded together by single bonds from the bottom right C H 2 of one structure to the bottom left C H 2 of the next.
The group of unsaturated hydrocarbons which 2 carbons are double bonded together, with H bonded to the left, and C H 2 bonded below left, above right, and below right is derived from Alkenes
What are organic compounds?Organic compounds are compounds which contains carbon and hydrogen
Some few classes or organic compounds or hydrocarbons are as follows:
AlkanesAlkenesAlkynesAlkanolsAlkanoic acidKetonesEstersSo therefore, the group of unsaturated hydrocarbons which 2 carbons are double bonded together, with H bonded to the left, and C H 2 bonded below left, above right, and below right is derived from Alkenes
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Answer:
The answer is A.) Alkene
All the answers in that section are:
Alkene
Aromatic Hydrocarbon
Alkene
Alkyne
Explanation:
Here's the picture as proof. Hope it helps!
The reaction of hydrogen bromide(g) with chlorine(g) to form hydrogen chloride(g) and bromine(g) proceeds as follows:
2HBr(g) + Cl2(g) -->2HCl(g) + Br2(g)
When 23.5 g HBr(g) reacts with sufficient Cl2(g), 11.8 kJ is evolved.
Calculate the value of △,H for the chemical equation given.
The smallest particle of an element that retains all of the properties of that element is called a(n) ______.
Answer:
Atom
Explanation:
That describes an ATOM
Which metal can be used as a sacrificial electrode to prevent the rusting of an iron pipe? auau cucu mnmn agag
Mn metal can be used as a sacrificial electrode to prevent the rusting of an iron pipe. So, the correct option is (c) Mn.
Commonly, sacrificial electrodes are employed to stop another metal from corroding or oxidising. A metal that is more reactive than the metal being shielded must serve as the sacrificial electrode. Magnesium, aluminium, and zinc are the three metals most frequently used in sacrificial anodes.
Manganese-Magnesium (Mn-Mg) electrode is more suited for on-shore pipelines where the electrolyte (soil or water) resistivity is higher since it has the highest negative electropotential of the three. In order to replenish any electrons that could have been lost during the oxidation of the shielded metal, the highly active metal offers its electrons.
Therefore, Mn metal can be used as a sacrificial electrode to prevent the rusting of an iron pipe. So, the correct option is (c) Mn.
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Which main intermolecular force must be overcome to convert liquid nh3 to nh3 vapor?
Intermolecular hydrogen force must be overcome to convert liquid NH3 to NH3 vapour.
Sublimation is the phase transition of a substance directly from the solid to the gaseous phase without passing through the liquid phase.
There are the 3 forces that exist between the 2 molecules of NH3
1. Dispersion force: these forces exist between any 2 molecules regardless of anything else.
2. Hydrogen bonding: H is directly bonded to the extremely electronegative atom N, O and F, hence is nearly stripped off electron due to the large electronegativity difference. Hydrogen being small atom further reduces in size even allowing it to approach other molecules very closely. Here, N, O, and F gathers more partial negative charge.
Due to the closure approach between the molecule and strong partial charge, hydrogen bonding is generally more important than dipole bond.
3. dipole dipole interaction: NH3 is a polar molecule with a permanent separation of charge. Each molecules behaves like a tiny magnet and has positive and negative poles so 2 NH3 molecules attract each other. Dipole dipole interactions are stronger than dispersion force in the small molecules.
Thus we concluded that the hydrogen bond should overcome to convert NH3 to vapours.
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What would the corresponding
concentration values of H₂O be
for pH values: 1, 3, 5, 7, 9, 11?
Answer:
7,9,11
Explanation:
this is because water includes 0H, which would mean that it is more than 6
What is the best method to convert styrene, c6h5ch=ch2, to 2-phenylethanol with minimal side product formation?
Styrene is an organic chemical used to make rubber, latex, resins, etc. It can be best converted using the anti-Markovnikov rule by (1) BH₃ - THF and (2) H₂O₂, NaOH. Thus, option B is correct.
What is anti- Markovnikov rule?The anti-Markovnikov rule defines the attachment of the substituent group to the least substituted carbon than the more substituted groups. This is due to the induction and hyperconjugation effect.
To convert styrene, the alcohol group from sodium hydroxide must be added to the least substituted carbon of the compound using other reagents like BH₃ - THF and hydrogen peroxide.
Therefore, option B. (1) BH₃ - THF and (2) H₂O₂, NaOH can be used to convert styrene.
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Your question is incomplete, but most probably your full question was, What is the best method to convert styrene, C₆H₅CH=CH₂, to 2-phenyl ethanol with minimal side product formation?
H₂O, H₂SO₄(1) BH₃ - THF and (2) H₂O₂, NaOH(1) HBr (2) KOH, H₂O(1)HBr, peroxides (2) NaOH, H₂OThe density of aluminum is 2.7 g/cm³. What is the density of aluminum in decagrams/m³?
Answer:
Density = 0.27 decagrams/cm³
Explanation:
From conversion tables, we know that;
1 g/cm³ = 0.1 decagrams/cm³
We are given;
Density of aluminium = 2.7 g/cm³
Thus;
Density = 2.7 * 0.1
Density = 0.27 decagrams/cm³
Answer:
270000 decagrams/m³
Explanation:
1.
Density=mass/Volume
=2.7g/1cm3
=(2.7/1000)/(1/1000000)
=2.7x1000
Density=2700kg/ m3
= 270000 decagrams/m³
2.
1000g=1kg
1g=1/1000kg
1cm3= ? m3
100cm=1m
1cm=1/100 m
1cm3=1/1000000 m3
A chemical by itself is harmless in the human body. However, in the
presence of lead, the chemical becomes toxic. This is the result of
Answer:
synergy
Explanation:
when two substances combine effects to be greater than just their sum of their individual effects
