Answers
One way to capture the domain of integration is with the set
[tex]D = \left\{(x,y) \mid 0 \le x \le 1 \text{ and } -x \le y \le 0\right\}[/tex]
Then we can write the double integral as the iterated integral
[tex]\displaystyle \iint_D \cos(y+x) \, dA = \int_0^1 \int_{-x}^0 \cos(y+x) \, dy \, dx[/tex]
Compute the integral with respect to [tex]y[/tex].
[tex]\displaystyle \int_{-x}^0 \cos(y+x) \, dy = \sin(y+x)\bigg|_{y=-x}^{y=0} = \sin(0+x) - \sin(-x+x) = \sin(x)[/tex]
Compute the remaining integral.
[tex]\displaystyle \int_0^1 \sin(x) \, dx = -\cos(x) \bigg|_{x=0}^{x=1} = -\cos(1) + \cos(0) = \boxed{1 - \cos(1)}[/tex]
We could also swap the order of integration variables by writing
[tex]D = \left\{(x,y) \mid -1 \le y \le 0 \text{ and } -y \le x \le 1\right\}[/tex]
and
[tex]\displaystyle \iint_D \cos(y+x) \, dA = \int_{-1}^0 \int_{-y}^1 \cos(y+x) \, dx\, dy[/tex]
and this would have led to the same result.
[tex]\displaystyle \int_{-y}^1 \cos(y+x) \, dx = \sin(y+x)\bigg|_{x=-y}^{x=1} = \sin(y+1) - \sin(y-y) = \sin(y+1)[/tex]
[tex]\displaystyle \int_{-1}^0 \sin(y+1) \, dy = -\cos(y+1)\bigg|_{y=-1}^{y=0} = -\cos(0+1) + \cos(-1+1) = 1 - \cos(1)[/tex]
Related Questions
please help me. PLEASE HELP ME.IM IN A HURRY PLEASE HELP ME QUESTION IS DOWN BELOW WORTH 15 POINTS each
Answers
a) [tex]\angle QST[/tex]
An inscribed angle has its vertex on the circumference of the circle.b) Arc QT
A minor arc is an arc that measures less than 180 degrees.c) Arc QRS
A semicircle is formed by the arc on either side of a diameter.d) 105 degrees
The measure of a central angle is the same as the measure of the arc it intercepts.e) 255 degrees
The circumference of a circle measures 360 degrees.The volume of a sphere is 4500π m3. What is the surface area of the sphere to the nearest square meter?
Answers
Answer:
2827 m²
Step-by-step explanation:
The equation for volume of a sphere is:
[tex]V=\frac{4}{3}\pi r^3[/tex]
Using this equation and the given volume of the sphere, we can find the radius of the sphere.
Finding the Radius[tex]V=\frac{4}{3}\pi r^3[/tex]
[tex]4500\pi = \frac{4}{3}\pi r^3[/tex]
Divide both sides by π
[tex]4500=\frac{4}{3}(r^3)[/tex]
Multiply both sides by 3
[tex]13500=4( r^3)[/tex]
Divide both sides by 4
[tex]3375=r^3[/tex]
Take the cube root of both sides
[tex]r=15[/tex]
Thus the radius of the sphere is 15m. We can use this information to find the surface area of the sphere.
Finding the Surface AreaThe equation for surface area of a sphere is [tex]4\pi r^2[/tex]. Substituting the value we found for the radius into the equation, we find:
[tex]SA=4\pi r^2\\SA=4\pi 15^2\\SA=4\pi 225\\SA=900\pi\\SA\approx2827$ m^2[/tex]
The surface area of the sphere, rounded to the nearest square meter, is 2827 m².
what is the answer to this?
Answers
Answer:
the coordinates of equations
1.4x+y=-7
for x =0
f(0,y)=4(0)+y=-7
y=-7
for y=0
f(x,0)=4x+0=-7
4x=-7
x=-7/4
2.x-y=2
for x=0
f(0,y)=0-y=2
-y=2
y=-2
for y=0
f(x,0)=x-0=2
x=2
graph all of the equations coordinates or you can look the image
so the answers are : {-3,-1}
CMIIW
The baseball coach is 70 inches tall. How tall is the child?
There is a picture that has the child's head slightly below the coach's shoulder.
Answers
The child is 59.4 inches tall, assuming the length from the coach's shoulder to his head cap is approximately 10 inches.
What is Heigth?Height refers to the vertical distance between the top and bottom of something.
Height measures the length of some objects or persons vertically to determine whether it is high or low, according to some ascertained criteria.
Data and Calculations:Baseball coach's height = 70 inches
Coach's shoulder to head = 10.6 inches
Height of the child standing slightly below the coach's shoulder = 59.4 inches (70 - 10.6)
Thus, the child standing slightly below the coach's shoulder is 59.4 inches tall.
Learn more about height measurements at https://brainly.com/question/73194
#SPJ1
Question Completion:Assume that the height of the coach from his shoulder to the head is 10.6 inches.
The mean of a normally distributed data set is 110, and the standard deviation is 15.
a) Use the Empirical Rule to find the probability that a randomly-selected data value is greater than 95.
b) Use the Empirical Rule to find the probability that a randomly-selected data value is greater than 125.
Answers
Step-by-step explanation:
68% of all values are within 1 SD (110 ± 15).
95% of all values are within 2SD (110 ± 2×15 = 30)
99.7% of all values are within 3 SD (110 ± 3×15 = 45)
a)
95 is 110 - 15, so exactly 1 SD apart from the mean value.
68% or 0.68 is the probability of all values between 95 and 125.
so, 34% or 0.34 is the probability of all values between 95 and 110. and 50% or 0.5 is the probability of all values larger than 110.
so, the probability of all values larger than 95 is
0.34 + 0.5 = 0.84
b)
125 is 110 + 15, so exactly 1 SD apart from the mean value.
so, as per a) 34% or 0.34 is the probability of all values between 110 and 125. and 50% or 0.5 is the probability of all values larger than 110.
so, the probability of all values larger than 125 is
0.5 - 0.34 = 0.16
Which function represents g(x), a reflection of f(x) = 1/2(3)^x across the y-axis?
Answers
The equation for the reflected function is:
g(x) = (1/2)*(3)^(-x)
How to get the reflected function?
Here we know that function g(x) is a reflection of f(x) across the y-axis.
Remember that the reflection is written as:
g(x) = f(-x)
Here we know that:
f(x) = (1/2)*(3)^x
Then, replacing that in the equation for g(x), we get:
g(x) = f(-x) = (1/2)*(3)^(-x)
g(x) = (1/2)*(3)^(-x)
If you want to learn more about reflections:
https://brainly.com/question/4289712
#SPJ1
2. What is the length of the hypotenuse k?
Answers
Answer:
k ≈ 50.77
Step-by-step explanation:
using the cosine ratio in the right triangle
cos19° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{48}{k}[/tex] ( multiply both sides by k )
k × cos19° = 48 ( divide both sides by cos19° )
k = [tex]\frac{48}{cos19}[/tex] ≈ 50.77 ( to 2 dec. places )
Hi :)
————————————————We'll use sohcahtoa to solve this problem
[tex]\Large\boxed{\begin{tabular}{c|1} \sf{Sohcahtoa} ~&~~~~~Formula~~~~~~~ \\ \cline{1-2} \ \sf{Soh} & Opp~\div \text{hyp}\\\sf{Cah} & Adj \div \text{hyp}\\\sf{Toa} & Opp \div \text{adj} \end{tabular}}[/tex]
Looking at our triangle, we can clearly see that we have :
adj. side = 48 (adjacent to the angle)hyp. k (the one we need)Set up the ratio
[tex]\longrightarrow\darkblue\sf{cos(19)=\dfrac{48}{k}}[/tex]
solve for k
[tex]\longrightarrow\darkblue\sf{k\cos(19)=48}[/tex] > multiply both sides by k to clear the fraction
[tex]\longrightarrow\darkblue\sf{k=\dfrac{48}{\cos(19)}}[/tex] > divide both sides by cos (19)
[tex]\star\longrightarrow\darkblue\sf{k\approx50.77}\star[/tex]
[tex]\tt{Learn~More ; Work\ Harder}[/tex]
:)
please help pls thanks
Answers
Reason:
The angles x and 71 are opposite the congruent sides. We call these the base angles. The base angles are congruent for any isosceles triangle. Therefore, x = 71.
It might help to rotate the triangle so that the angles x and 71 are flat along the ground (rather than tilted).
Select the correct answer. In the given diagram, . Prove: The transversal line intersects two parallel lines m and n with values of corresponding angles are congruent pairs of corresponding angles are (1, 5), (4, 8), (3, 7), and (2, 6) Statements Reasons 1. given 2. alternate exterior angle theorem 3. ? vertical angles theorem 4. transitive property of congruence Which statement is missing in the proof? A. B. C. D.
Answers
Based on the given diagram (see attachment), the statement which is missing in the proof is: D. m∠7 ≅ m∠5.
What are parallel lines?Parallel lines can be defined as two (2) lines that are always the same (equal) distance apart and never meet.
The condition for two parallel lines.In Geometry, two (2) lines are considered to be parallel if their slopes are the same (equal) and they've different y-intercepts. This ultimately implies that, two (2) lines are parallel under the following conditions:
m₁ = m₂
Note: m is the slope.
From the given diagram (see attachment), we can logically deduce that line m is parallel to line n (m || n) and a transversal line intersects both of them.
Based on these reasons, we can prove the following statements:
m || n (given)m∠1 ≅ m∠7 (alternate exterior angle theorem).m∠7 ≅ m∠5 (vertical angles theorem).m∠1 ≅ m∠7 (transitive property of congruence).In conclusion, we can logically deduce that the statement which is missing in the proof is m∠7 ≅ m∠5.
Read more on parallel lines here: brainly.com/question/25898901
#SPJ1
Answer:
here you go
Step-by-step explanation:
find the fourth roots of i
Answers
Answer:
1∠22.5°, 1∠112.5°, 1∠202.5°, 1∠292.5°
Step-by-step explanation:
A root of a complex number can be found using Euler's identity.
ApplicationFor some z = a·e^(ix), the n-th root is ...
z = (a^(1/n))·e^(i(x/n))
Here, we have z = i, so a = 1 and z = π/2 +2kπ.
Using r∠θ notation, this is ...
i = 1∠(90° +k·360°)
and
i^(1/4) = (1^(1/4))∠((90° +k·360°)/4)
i^(1/4) = 1∠(22.5° +k·90°)
For k = 0 to 3, we have ...
for k = 0, first root = 1∠22.5°
for k = 1, second root = 1∠112.5°
for k = 2, third root = 1∠202.5°
for k = 3, fourth root = 1∠292.5°
Solve the following system of equations. 4x + 3y = -5
- 3x + 7y=13
Answers
Answer: 13
Step-by-step explanation:
4x+3y=-5 solve x :
4x = -3y + -5 | -3y
1x = -0.75y + -1.25 | : 4
-3x + 7y = 13 solve x :
-3x + 7y = 13 | -7y
-3x = -7y = 13 | : (-3)
Equalization Method Solution: -0.75y+-1.25=2.333y+-4.333
-0, 75y - 1,25 = 2,333y - 4, 333 solve y:
-0, 75y - 1,25 = 2,333y -4, 333 | -2,333y
-3, 083y - 1,25 = -4,333 | + 1, 25
-3. 083y = -3,088 | : (-3, 083)
y = 1
Plug y = 1 into the equation 4x + 3y = -5 :
4x + 3 · 1 | Multiply 3 with 1
4x + 3 = -5 | -3
4x = -8 | : 4
x = -2
So the solution is:
y = 1, x = -2
ヘ( ^o^)ノ＼(^_^ )If you want to learn more about mathematics, I share this link to complement your learning:
https://brainly.com/question/20333461
30,098 in standard form full working pliz
Answers
Did not understand "full working pliz".
If the average score is 122 with a standard deviation of 35,
what percentage of students scored below 67? Answers are
rounded to the nearest whole percent.
O a.) 90%
O b.) 6%
O c.) 10%
O d.) 94%
Answers
Answer:
6%
Step-by-step explanation:
Got it right on the test.
-y(-6y-3) I need to combine like terms and simplify. I got 6y^2 + 3y by distributing. It's wrong and in the explanation it says use the distributive property to remove the parentheses and it gave -6y -3 -y as the first step answer. How the heck did they remove the parentheses or use the distributive property correctly?
Answers
if any number or variable is outside a parenthesis it will go to all the number rin the parenthesis.
in this case -y is outside the parenthesis so it will got to both the sides :
-y(-6y-3) = -6y x y - 3 x y
= -6y² -3y//
The vertices of a composite figure are given. Find the area of the figure.
G(-5, -1), H(-5, 1), I(2, 4), J(5, -1), K(1, -3)
Answers
Check the picture below.
so the composite is really a trapezoid and two triangles, let's get their area and sum them all up.
[tex]\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h~~=height\\ a,b=\stackrel{parallel~sides}{bases~\hfill }\\[-0.5em] \hrulefill\\ a = 2\\ b = 5\\ h = 7 \end{cases}\implies A=\cfrac{7(2+5)}{2} \\\\[-0.35em] ~\dotfill[/tex]
[tex]\stackrel{\textit{\LARGE Areas}}{\stackrel{yellow~trapezoid}{\cfrac{7(2+5)}{2}}~~ + ~~\stackrel{blue~triangle}{\cfrac{1}{2}(\stackrel{b}{3})(\stackrel{h}{5})}~~ + ~~\stackrel{orange~triangle}{\cfrac{1}{2}(\stackrel{b}{10})(\stackrel{h}{2})}} \\\\\\ 24.5~~ + ~~7.5~~ + ~~10\implies \text{\LARGE 42}[/tex]
(4x³-12x +11) + (2x - 2)
Answers
4x^3-10x+9
Explanation
4x^3-12x+11+2x-2
The tree diagram represents an
experiment consisting of two trials.
5
5
VV
P(A and D)= [?]
Answers
Based on the given parameters in the question, the value of the probability of A and D is 0.30
How to determine the probability?The given parameters from the tree diagram are:
Probability of event A: P(A) = 0.5Probability of event D: P(D) = 0.6The probability P(A and D) is calculated using the following probability formula
P(A and D) = P(A) × P(D)
Substitute the known values in the above equation
P(A and D) = 0.5 × 0.6
Evaluate the product of 0.5 and 0.6
P(A and D) = 0.30
Hence, the value of the probability of A and D is 0.30 based on the given parameters in the question
Read more about probability at:
brainly.com/question/795909
#SPJ1
Suppose you know that the distribution of sample proportions of fifth grade students in a large school district who read below grade level in samples of 100 students is normal with a mean of 0.30 and a standard deviation of 0.12. You select a sample of 100 fifth grade students from this district and find that the proportion who read below grade level in the sample is 0.54. This sample proportion lies 2.0 standard deviations above the mean of the sampling distribution. What is the probability that a second sample would be selected with a proportion greater than 0.54 ?
Answers
Based on the mean of the sample and the proportion who read below grade level, the probability that a second sample would have a proportion greater than 0.54 is 0.9772.
What is the probability of the second sample being greater than 0.54?The probability that the second sample would be selected with a proportion greater than 0.54 can be found as:
P (x > 0.54) = P ( z > (0.54 - 0.30) / 0.12))
Solving gives:
P (x > 0.54) = P (z > 2)
P (x > 0.54) = 0.9772
In conclusion, the probability that the second sample would be selected with a proportion greater than 0.54 is 0.9772.
Find out more on probability at https://brainly.com/question/25638875
#SPJ1
a dust mite is 400 pm long under a microscope, it looks 100,000 pm long. what magnification scale was used
Answers
Answer: 250:1
Step-by-step explanation:
Divide the measurement of appearance by the actual measurement.
[tex]100,000/400=250[/tex]
The magnification scale is 250:1. The scale is used by a 250X magnifying lense.
3. Joyce had a 10.00am appointment 60Km from her house. She averaged 80Km/h for the trip
but arrived 20 minutes late for the appointment. At what time did she leave her home that
morning?
A) 9.40
C) 9.15
B) 9.35
D) 9.20
E) None of these
Answers
Answer:
B) 9:35
Step-by-step explanation:
the travel time we get by dividing the distance by the speed
distance / distance/time = time
so,
60 / 80 = 6/8 = 3/4 = 0.75 hours or 45 minutes.
since she arrived 20 minutes late, that means at 10:20 am, she left home 45 - 20 = 25 minutes before 10:00am.
and that is 9:35 am.
3 1/3(2 1/5x-4 2/3) - 5 5/6=0, solve please
Answers
Based on the task content given; the solution to the equation for x 3 1/2(2 1/5x - 4 2/3) - 5 5/6 = 0 is 2 203/231
Simplification3 1/2(2 1/5x - 4 2/3) - 5 5/6 = 0
open parenthesis(3 1/2 × 2 1/5x) - (3 1/2 × 4 2/3) - 5 5/6 = 0
(7/2 × 11/5x) - (7/2 × 14/3) - 35/6 = 0
77/10x - 98/6 - 35/6 = 0
77/10x = 98/6 + 35/6
77/10x = 98+35 / 6
77/10x = 133/6
x = 133/6 ÷ 77/10
= 133/6 × 10/77
= 1330/462
x = 2 406/462
= 2 203/231
Learn more about simplification:
https://brainly.com/question/723406
#SPJ1
Find a potential function for the vector field
Answers
(a) We want to find a scalar function [tex]f(x,y,z)[/tex] such that [tex]\mathbf F = \nabla f[/tex]. This means
[tex]\dfrac{\partial f}{\partial x} = 2xy + 24[/tex]
[tex]\dfrac{\partial f}{\partial y} = x^2 + 16[/tex]
Looking at the first equation, integrating both sides with respect to [tex]x[/tex] gives
[tex]f(x,y) = x^2y + 24x + g(y)[/tex]
Differentiating both sides of this with respect to [tex]y[/tex] gives
[tex]\dfrac{\partial f}{\partial y} = x^2 + 16 = x^2 + \dfrac{dg}{dy} \implies \dfrac{dg}{dy} = 16 \implies g(y) = 16y + C[/tex]
Then the potential function is
[tex]f(x,y) = \boxed{x^2y + 24x + 16y + C}[/tex]
(b) By the FTCoLI, we have
[tex]\displaystyle \int_{(1,1)}^{(-1,2)} \mathbf F \cdot d\mathbf r = f(-1,2) - f(1,1) = 10-41 = \boxed{-31}[/tex]
[tex]\displaystyle \int_{(-1,2)}^{(0,4)} \mathbf F \cdot d\mathbf r = f(0,4) - f(-1,2) = 64 - 41 = \boxed{23}[/tex]
[tex]\displaystyle \int_{(0,4)}^{(2,3)} \mathbf F \cdot d\mathbf r = f(2,3) - f(0,4) = 108 - 64 = \boxed{44}[/tex]
In 2016, the CDC estimated the mean weight of U.S. women over the age of 20 years old was 168.5 pounds with a standard deviation of 68 pounds.
1. What is the expected mean for a sample of 150 women?
2. What is the standard deviation of the mean for a sample of 150 women?
3. What is the probability of 150 women having a sample mean below 160 pounds?
4. What is the probability of 150 women having a sample mean above 175 pounds?
5. What is the probability of 200 women having a sample mean below 160 pounds? Note the change in sample size.
6. What is the probability of 200 women having a sample mean above 175 pounds?
Answers
Step-by-step explanation:
1.
the expected sample mean is always the general mean : 168.5 pounds.
2.
the SD of a sample is the general SD / sqrt(sample size).
in our case
the sample SD = 68/sqrt(150) = 5.55217675...
3.
if we are looking for only the probability that any single woman is below 160 pounds, we would use the normal z calculation :
z = (x - mean)/SD = (160 - 168.5)/68 = -8.5/68
but we have here the question about the probability of the mean value of a whole sample of 150 women.
so, we need to adapt the z-calculation by the principle of 2) for the SD of a sample :
z = (x - mean)/(SD × sqrt(sample size)) =
= (160 - 168.5)/(68 × sqrt(150)) = -8.5/(68×sqrt(150)) =
= -0.010206207 ≈ -0.01
that gives us in the z-table the p-value 0.49601
this 0.49601 is the probability that a sample of 150 women has a mean value of below 160 pounds.
4.
similar to 3.
the z value we are looking for
z = (175 - 168.5)/(68 × sqrt(150)) = 6.5/(68 × sqrt(150)) =
= 0.007804747... ≈ 0.01
that gives us the p-value 0.50399.
that would be the probability of a sample mean of 175 or below.
to get above 175 we need to get the other side of the bell-curve :
1 - 0.50399 = 0.49601
so, this case has about the same probability as 3.
5.
as 3), just with the sqrt(200) instead of the sqrt(150).
z = -8.5/(68 × sqrt(200)) = -0.008838835... ≈ 0.01
so, the probability is still about the same as in 3) :
0.49601
6.
as 4) just with sqrt(200).
z = 6.5/(68 × sqrt(200)) = 0.006759109... ≈ 0.01
so, the probability is still about the same as for 4) :
0.49601
The answers are :
1) The expected mean for a sample of 150 women is 168.5 pounds.
2) The standard deviation (SD) of the mean for a sample of 150 women is 5.55.
3) The probability of 150 women having a sample mean below 160 pounds will be 0.49601.
4) The probability of 150 women having a sample mean above 175 pounds will be 0.49601.
5) The probability of 200 women having a sample mean below 160 pounds will be 0.49601.
6) The probability of 200 women having a sample mean above 175 pounds will be 0.49601.
What is probability ?
Probability is a measure of the likelihood of event to occur. The probability of all the events in a sample space adds up to 1.
1)
We know that the expected mean of a sample is always equal to general mean.
As per the question, mean weight is 168.5 pounds.
This implies :
The expected mean for a sample of 150 women is :
= 168.5 pounds
2)
The standard deviation (SD) of the mean for a sample of 150 women is :
= 68 / (√150)
= 5.55
3)
The probability of 150 women having a sample mean below 160 pounds will be represented by z and will be :
z = ( x - mean) / ( SD × (√sample size))
= (160 - 168.5) / (68 × √150)
= 0.01
If we use the z table then the probability will be :
= 0.49601
4)
Similarly as part 3 :
z = (175 - 168.5) / (68 × √150)
z = 0.01 (approximately)
The probability of 150 women having a sample mean below 175 pounds will be :
= 0.50399
And the probability of 150 women having a sample mean above 175 pounds will be :
= 1 - 0.50399
= 0.49601
5)
Here , we have to find probability of 200 women , so 150 in formula of z in 3rd part will be replaced by 200.
i.e.,
z = (160 - 168.5) / (68 × √200)
z = 0.01 ( approximately)
and probability will be :
= 0.49601
6)
Here , we have to find probability of 200 women , so 150 in formula of z in 4th part will be replaced by 200.
z = (175 - 168.5) / (68 × √200)
z = 0.01
And probability equal to :
= 0.49601
Therefore , the answers are :
1) The expected mean for a sample of 150 women is 168.5 pounds.
2) The standard deviation (SD) of the mean for a sample of 150 women is 5.55.
3) The probability of 150 women having a sample mean below 160 pounds will be 0.49601.
4) The probability of 150 women having a sample mean above 175 pounds will be 0.49601.
5) The probability of 200 women having a sample mean below 160 pounds will be 0.49601.
6) The probability of 200 women having a sample mean above 175 pounds will be 0.49601.
Learn more above probability here :
https://brainly.com/question/1846009
#SPJ2
The volume of a rectangular prism is given by the following function:
V(x) = 2x³ + x² - 16 - 15
The length of the rectangular prism is (x − 3) and the width is (2x + 5). What is the height?
Answers
[tex]v(x) = wlh \\ 2x {}^{3} + {x}^{2} - 16 x- 15 =(2x + 5)(x - 3)h \\ h = \frac{2x {}^{3} + x {}^{2} - 16x - 15 }{2x {}^{2} - x - 15 } \\ using \: long \: divison \\ h = x + 1[/tex]
Anna does sit-ups to get ready for her first triathlon. When she starts, she does a sit-up every 2 seconds. But, as she gets tired, each sit-up takes longer to do. Is the number of sit-ups Anna does proportional to the time she spends doing them?
Answers
Answer: No
Step-by-step explanation: proportional means corresponding in size or amount to something. However, the number of her sit-ups isn't consistent, so it isn't proportional to the time she spends doing them.
Two discs are randomly taken without replacement from a bag containing 3 red discs and 2 blue discs. What is the probability of taking 2 red discs ?
Answers
Answer:
3/10
Step-by-step explanation:
There are totally 5 disks. On the first pick, there are 3 red discs. So
P(red disc on first pick ) = 3/5
Assuming that a red disc has been picked the first time, there will be 2 red discs and 2 blue discs so
(P red disc on second pick given red disc on first pick) = 2/4
P(red disc on both picks) = 3/5 x 2/4 = 3/10
Identify the most reasonable unit to measure the time spent at school on an average school day. Seconds, minutes, or hours?
Answers
The most reasonable unit to measure the time spent at school on an average school day is in hours.
How to find the most reasonable unit for a measure?
In anything we are going to measure, we have to pay special attention to the unit. When doing this, we want to keep the absolute value of the measure, that is, the number small, hence the do this conversion of units may be used.
For example, it is easier and more practical to say one day instead of 87,840 seconds. The same logic is applied to this problem, in which the most reasonable unit to measure the time spent at school on an average school day is in hours, as it keeps the numerical measure smaller than it would be in minutes or seconds.
More can be learned about the most reasonable unit of a measure at https://brainly.com/question/21896360
#SPJ1
Answer For X (in degrees)
Answers
Answer:
I cant see your question can you show it properly??Consider the function f(x) = 3x + 1 and the graph of the function g(x) shown below.
A coordinate plane linear graph function shows a line intersecting Y-axis at minus 5 and X-axis at 1.5.
The graph g(x) is the graph of f(x) translated units , and g(x) =
Answers
g(x) is a translation of 6 units downwards.
How to identify the translation that generates g(x)?
Here we have the function:
y = f(x) = 3x + 1
Notice that the y-intercept of f(x) is:
f(0) = 3*0 + 1 = 1
The y-intercept of f(x) is y = 1.
Now, we know that the y-intercept of g(x) is -5. then:
g(x) = 3x - 5 = f(x) - 6
Meaning that g(x) is a translation of 6 units downwards.
If you want to learn more about translations:
https://brainly.com/question/24850937
#SPJ1
Answer:
translated 2
units up
g(x)= f(x-2)
Step-by-step explanation:
PLEASE HELP I will give 50 points! PLEASE ANSWER CORRECTLY
In a school, 10% of the students have green eyes. Find the experimental probability that in a group of 4 students, at least one of them has green eyes. The problem has been simulated by generating random numbers. The digits 0-9 were used. Let the number "9" represent the 10% of students with green eyes. A sample of 20 random numbers is shown. 7918 7910 2546 1390 6075 2386 0793 7359 3048 1230 2816 6147 5978 5621 9732 9436 3806 5971 6173 1430 Experimental Probability = [?]% =
Answers
Answer: 45%
Step-by-step explanation:
Given:
A sample of 20 random numbers.The number "9" represents the 10% of students having green eyes.Find:
The experimental probability that in a group of 4 students, at least one of them has green eyes.The number of groups which contains 9 is 9 and the total number of groups are 20.
So,
P = 9 / 20 = 0.45 = 45%
Therefore, the experimental probability is 45%
