Use: 10 m/s, sin 37-0.6, cos 37°-0.8 A horizontal Force F-6 N is acting on a block of mass M=2.0 kg, pulling it up on a frictionless Inclined surface at an angle = 37° from the horizontal. What is the normal force acting on the block?

I can provide you with an analysis of the potential impact of water recreation on marine diversity.

Water recreation activities, such as swimming, snorkeling, scuba diving, and boating, can have both positive and negative impacts on marine diversity.

Positive impacts:

Negative impacts:

Answer:

The Correct answer is D

molecules of liquid are stationary

In the Roman soldier model for refraction, the first soldier who hits the muddy stream would slow down and turn slightly. Option B is correct.

The Roman soldier model is a simplified model used to explain the behavior of light when it passes from one medium to another. In this model, a group of Roman soldiers is marching across a field towards a muddy stream. The soldiers represent light rays, and the muddy stream represents the boundary between two media with different refractive indices.

When the first soldier hits the muddy stream, they slow down because the speed of light decreases when it passes from a medium with a lower refractive index to a medium with a higher refractive index. Additionally, the soldier turns slightly because the direction of the light ray changes as it passes through the boundary between the two media. This change in direction is called refraction, and it occurs because the speed of light changes when it passes through a medium with a different refractive index.

The amount of refraction that occurs depends on the angle at which the light ray hits the boundary between the two media and the difference in refractive indices between the two media. The Roman soldier model is a useful tool for understanding the basics of refraction, but it has limitations and cannot fully explain all aspects of the phenomenon. Option B is correct.

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If Superman remains 283 metres away from Lois Lane, she must fall 120 metres before he can kinetic  grab her. A bad guy throws a rock right at Lois from a height of 4 metres.

a list of horizontality definitions. the property of being horizontally parallel. "Houses with a pronounced horizontality" as a form of: position, spatial interaction. the spatial characteristic of the location or orientation of something.

Store-bought Fine sand plus polydimethylsiloxane are combined to create kinetic sand. It is a peculiar chemical in that stress causes its viscosity to rise. It can be sliced and formed into interesting shapes. It's hardly the least expensive item to purchase, either.

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The position of the center of mass of the system is 13.0 cm from the left edge of square A.

The center of mass can be calculated by multiplying the masses you're trying to find the center of mass between by their positions. Then you add them all up and divide the total by the sum of the individual masses.

We use the formula for the center of mass of a system of particles,

[tex]x_c_m = (m_Ax_A + m_Bx_B + m_C*x_C) / (m_A + m_B + m_C)[/tex]

[tex]m_A[/tex] = mass of square A

[tex]m_B[/tex] = mass of square B

[tex]m_C[/tex] = mass of square C

[tex]x_A[/tex] = distance of the center of mass of square A

[tex]x_B[/tex] = distance of the center of mass of square B

[tex]x_C[/tex] = distance of the center of mass of square C

Substitute values,

[tex]x_c_m = (100.0 cm^2 * 5.0 cm + 400.0 cm^2 * 10.0 cm + 900.0 cm^2 * 15.0 cm) / (100.0 cm^2 + 400.0 cm^2 + 900.0 cm^2)[/tex]

[tex]x_c_m = 13.0 cm[/tex]

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The initial horizontal velocity of the stone is 29 m/s.

The initial vertical velocity of the stone is 0 m/s.

The time of motion of the stone is calculated as follows;

h = V₀yt + ¹/₂gt²

where;

Since the stone is projected horizontally, the initial vertical velocity = 0

h = ¹/₂gt²

t = √(2h/g)

t = √(2 x 31/9.8)

t = 2.52 s

The initial horizontal velocity of the stone is calculated as follows;

d = V₀ₓt

V₀ₓ = d/t

V₀ₓ = 73 m / 2.52 s

V₀ₓ = 29 m/s

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Answer:

Time to get to top = 5 m/s / 10 m/s^2 = .5 sec

H at top = v0 t - 1/2 g t^2 =  5 * .5 - 1/2 * 10 * .5^2 = 1.25 m

Time to fall 1.25 + 20 = 21.25 m

S = 1/2 g t^2     since it starts out ar zero speed

t = (2 * 21.25 / 10)^1/2 = 2.06 sec

Total time = .5 + 2.06 = 2.56 sec

Calculations using equations of motion reveal that the total time for the ball to hit the ground, when thrown upward from a 20m high cliff with an initial speed of 5m/s and subjected to a gravitational pull of 10m/s², is about 3 seconds.

The time it takes for the ball to hit the ground is calculated using the equation of motion, t = sqrt((2h)/g), where 'h' is the height of the cliff and 'g' is the acceleration due to gravity. Since the ball is thrown upwards first, we also need to consider the time it takes for the ball to reach its maximum height and start falling down. This can be calculated using the equation t = v/g, where 'v' is the initial speed of the ball.

So, the total time would be the time it takes for the ball to reach the maximum height and fall down back to the ground, which is calculated using the following equation: t_total = t_up + t_down. Given that 'h' is 20m, 'v' is 5m/s, and 'g' is 10m/s², the total time it would take for the ball to hit the ground at the base of the cliff comes out to be approximately 3 seconds.

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Explanation:

Yes, they can....and so can fish.    When a tornado passes ofver water , it forms what is called a 'water spout'  which sucks up water ...and frogs and fish....and drops them elsewhere.

Answer:

Let M be the mass  of water present:

ΔQ = M (T2 - T1) Sw + M Ss      using specific heat of water and latent heat of vaporization

ΔQ = 20 g * 74 deg C * 1 cal / (g & deg C) + 20 g * 540 cal / g)

ΔQ = 12,300 cal

The expression is: m*x''(t) + mk*x'(t) + f(t) = 0.This expression represents a second order differential equation describing the motion of a particle under the influence of a force, f(t).

Motion is the action or process of moving or being moved from one place to another. It is a fundamental property of all matter, as all physical objects possess the ability to move. Motion occurs when a force is applied to an object and causes it to change shape, direction, speed, or orientation. Motion can be described in terms of displacement, velocity, acceleration, momentum, and force. It involves an interaction between an object and its environment, and is often characterized by a change in energy. Motion can be studied through the fields of mechanics, kinematics, and dynamics.

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If the thrust was cut in half, the new acceleration of the spare shuttle would be half of its original acceleration.

Assuming that the mass of the space shuttle remains constant, the new acceleration of the space shuttle would be half of its original acceleration.

The formula for acceleration is:

a = F/m

where,

a = acceleration

F = force applied

m = mass of the object

If the force is cut in half, the new acceleration can be calculated as follows:

a' = (F/2)/m

where,

a' = new acceleration

Simplifying this equation, we get:

a' = F/2m

Since we know that a = F/m, we can substitute this expression into the equation above to obtain:

a' = a/2

So, the new acceleration of the space shuttle would be half of its original acceleration.

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No, it is not in equilibrium at this point. This is because, at the highest point in its path, the object is still in motion and is still subject to the forces of gravity and air resistance.

Resistance is the opposition to something or the refusal to accept or comply with it. It is a measure of the opposition to the flow of electric current, or other forms of energy. Resistance is measured in ohms, which is the amount of energy required to move one ampere of current through one ohm of resistance.

No, it is not in equilibrium at this point. This is because, at the highest point in its path, the object is still in motion and is still subject to the forces of gravity and air resistance which are acting to move it back down.

Yes, the speed of an object can change if the net work done on it is zero. This is because an object can gain or lose energy through non-conservative forces, such as friction, even if no net work is done on the object.

Yes, a car can move around a circular racetrack so that the car has a tangential acceleration but no centripetal acceleration. This is because the car can be travelling at a constant speed in a curved path, which will produce a tangential acceleration, but no centripetal acceleration.

No, a large amount of pressure is not always caused by a large force. Pressure is defined as force per unit area, so a large amount of pressure can be caused by a small force if it is acting over a large area. Similarly, a small force can cause a large amount of pressure if it is acting over a small area.

If the length of the pendulum is doubled, the period of the pendulum will also double. This is because the period of a pendulum is directly proportional to its length, so if the length is doubled the period will also double.

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Complete question:

An object thrown into the air stops at the highest point in its path. Is it in equilibrium at this point? Explain. 9. Can the speed of an object change if the net work done on it is zero? 10. Can a car move around a circular racetrack so that the car has a tangential acceleration but no centripetal acceleration? 11. Is a large amount of pressure always caused by a large force? Explain your answer. 12. The period of a simple pendulum, defined as the time necessary for one complete oscillation is measured in time units and is given by the equation L T = 2π ag where L is the length of the pendulum and a, is the acceleration due to gravity, which has​ a value of 9.8 m/s². How does the period of the pendulum change if the length of the pendulum is doubled?

The work done is 259.8 J

The net work done is 140.625 J

Fx = F * cos(θ)

Fx = 60 N * cos(30°)

Fx ≈ 51.96 N

Fy = F * sin(θ)

Fy = 60 N * sin(30°)

Fy = 30 N

W = Fx * d

where d is the distance (5 m) the block moves.

work done = 51.96 N * 5 m

work done ≈ 259.8 J

Force norm = 10 kg * 9.81 m/s² - 30 N

Force  norm ≈ 68.1 N

Force  friction = 0.35 * 68.1 N

Force  friction ≈ 23.835 N

Workdone friction = 23.835 N * 5 m

Workdone friction ≈ 119.175 J

Workdone net = W_Force - W_friction

Workdone net = 259.8 J - 119.175 J

Workdone net ≈ 140.625 J

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The pressure of a gas at the triple point of water is 1.50 atm, which means it is at the temperature and pressure where water can exist as a solid, liquid, and gas simultaneously.

To find the pressure of the gas at the temperature at which CO2 solidifies, we need to know the triple point of CO2. The triple point of CO2 is -56.6°C and 5.1 atm.

If the volume of the gas remains unchanged, then its pressure will change with a change in temperature. Using the ideal gas law, PV = nRT, we can find the new pressure of the gas:

P1V1 = P2V2

At the triple point of water:

P1 = 1.50 atm

V1 = V (unchanged)

T1 = 0.01°C (triple point of water)

At the triple point of CO2:

P2 = 5.1 atm

V2 = V1 (unchanged)

T2 = -56.6°C

Using the ideal gas law and solving for P2:

P2 = P1(T2/T1)

P2 = 1.5 x (-56.6+273.15) / (0.01+273.15)

P2 = 0.818 atm

Therefore, the pressure of the gas at the temperature at which CO2 solidifies is 0.818 atm.

The shorter the distance between the balls, the greater the electric force between them.

option C

The electric force between charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

F = kq²/r²

where;

Therefore, if the charges on the pith balls are fixed, the closer they are, the stronger the electric force between them will be. So option C is the correct answer.

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The force produces a torque on an object,  need to look for a force that is applied in a direction that is not parallel to the axis of rotation, has a nonzero magnitude, and is applied at a distance from the axis of rotation.

Torque is a measure of a force's ability to rotate an object around an axis or pivot point. It is the product of the force and the perpendicular distance from the force's line of action to the axis of rotation. In other words, torque depends on both the magnitude and direction of the force and the lever arm, which is the distance between the axis of rotation and the point where the force is applied.

To identify the force that produces torque on an object, you need to consider the following factors:

Direction: The force must be applied in a direction that is not parallel to the axis of rotation. If the force is applied along the axis of rotation, it will not produce any torque.

Magnitude: The force must have a nonzero magnitude. A force that is too weak will not produce enough torque to rotate the object.

Lever arm: The force must be applied at a distance from the axis of rotation. The greater the distance, the greater the torque.

Once you have identified the force that meets these criteria, you can calculate the torque it produces using the formula:

Torque = Force x Lever arm x sin(θ)

where theta is the angle between the force vector and the lever arm vector.

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Answer: The magnetic field has a magnitude of approximately 1.96 * 10^-4 T and points in the positive x direction. The magnetic field vector is B = (1.96 * 10^-4, 0, 0) T.

Explanation:

To find the direction and magnitude of the magnetic field, we'll use the formula for the magnetic force acting on a moving charged particle:

F = q * (v x B)

where F is the magnetic force, q is the charge of the particle, v is its velocity, and B is the magnetic field. The cross product (v x B) implies that the force is perpendicular to both the velocity of the particle and the magnetic field.

Since the electron experiences zero magnetic force when it moves in the positive x direction, we can conclude that the magnetic field is either parallel or antiparallel to the x-axis.

Now let's analyze the situation when the electron moves in the positive y direction and experiences a force in the negative z direction. The electron charge is negative, with q = -1.6 * 10^-19 C. The velocity vector is v = (0, 4.2 * 10^5, 0) m/s, and the force vector is F = (0, 0, -2.0 * 10^-13) N.

Using the formula for magnetic force, we have:

F = q * (v x B)

Now, we need to find the cross product (v x B):

v x B = (0, 4.2 * 10^5, 0) x (Bx, 0, 0)

Since the cross product is orthogonal to both vectors, and we know that the force is in the negative z direction, we can conclude that the magnetic field must be in the positive x direction (parallel to the x-axis). So, the magnetic field vector is B = (Bx, 0, 0).

Now we can rewrite the force equation:

(0, 0, -2.0 * 10^-13) = -1.6 * 10^-19 * (0, 0, 4.2 * 10^5 * Bx)

To solve for Bx, we can focus on the z component of the force equation:

-2.0 * 10^-13 = -1.6 * 10^-19 * (4.2 * 10^5 * Bx)

Dividing both sides by (-1.6 * 10^-19 * 4.2 * 10^5):

Bx = (2.0 * 10^-13) / (-1.6 * 10^-19 * 4.2 * 10^5)

Bx ≈ 1.96 * 10^-4 T

Thus, the magnetic field has a magnitude of approximately 1.96 * 10^-4 T and points in the positive x direction. The magnetic field vector is B = (1.96 * 10^-4, 0, 0) T.

The following is a force that is at work between two objects(A). gravity

is correct option.

Gravity is the force of attraction that exists between any two objects in the universe. It is a fundamental force that affects all objects with mass and is responsible for phenomena like the motion of planets around the sun, the tides in oceans, and the weight of objects on Earth's surface.

Force is a physical quantity that describes the interaction between two or more objects, causing a change in motion or deformation of the objects. It is represented by the symbol F and is measured in units of Newtons (N) in the International System of Units (SI).

There are several types of forces, including gravitational, electromagnetic, nuclear, and frictional forces. Gravitational force is the force of attraction that exists between any two objects with mass, while electromagnetic force is the force of attraction or repulsion between electrically charged particles. Nuclear forces are the forces that hold the atomic nucleus together, and frictional forces are the forces that resist the relative motion of objects in contact.

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Answer:

A.

Position-time graph:

The position-time graph for the ball punted vertically will be a parabolic curve, with the vertex at the highest point of the ball's trajectory. Since the initial position is zero, the curve will go through the origin.

Velocity-time graph:

The velocity-time graph will be a straight line that starts at the initial velocity and decreases linearly until it reaches zero at the highest point of the ball's trajectory. After that, the velocity increases linearly in the negative direction until the ball hits the ground.

Acceleration-time graph:

The acceleration-time graph will be a constant negative value, representing the acceleration due to gravity.

Motion map:

A motion map is a diagram that shows the position of an object at several specific times during its motion. For the ball punted vertically, the motion map would look like this:

|O|------|-------|------|-------|------|H|

O represents the initial position, and H represents the highest point of the ball's trajectory. The "|" symbols represent the position of the ball at regular intervals of time.

B.

To find the initial velocity of the ball, we can use the hang time and the acceleration due to gravity.

Hang time = 3.8 seconds

Acceleration due to gravity = -9.8 m/s^2

At the highest point of the ball's trajectory, the velocity is zero. Therefore, we can use the following kinematic equation to find the initial velocity:

hang time = (final velocity - initial velocity) / acceleration

Solving for initial velocity:

initial velocity = final velocity - (hang time x acceleration)

final velocity = 0 m/s

hang time = 3.8 s

acceleration = -9.8 m/s^2

initial velocity = 0 - (3.8 x -9.8)

initial velocity = 37.64 m/s

Therefore, the initial velocity of the ball was 37.64 m/s.

Answer:

intensity of this field around the conductor is proportional to the distance from it with the strongest point being next to the conductor and progressively getting weaker further away from the conductor

If one of the forces acts in the negative y-direction with a magnitude of 410 N. Then, the magnitude of the second force (F₂) is 410 N.

We can use Newton's second law of motion, which states that the net force acting on an object is equal to the object's mass times its acceleration:

ΣF = m × a

where ΣF is the net force, m is the mass, and a is the acceleration.

In this problem, we know the mass (m = 32 kg) and acceleration (a = 44 m/s²) of the object, and we also know that one force (F₁) acts in the negative y-direction with a magnitude of 410 N. Let's call the second force F₂, which acts in the positive x-direction.

To find the magnitude of F₂, we need to use vector addition to find the net force in the x-direction;

ΣFx = F₂

And in the y-direction;

ΣFy = -F₁

Since the acceleration is only in the x-direction, the net force in the y-direction must be zero. Therefore, we have;

ΣFy = 0 = F₂sin(θ) - F₁

where θ is the angle between F₂ and the x-axis, which is 90 degrees since F₂ acts in the x-direction.

Solving for F₂, we get;

F₂ = F₁ / sin(θ) = 410 N / sin(90°)

= 410 N

Therefore, the magnitude of the second force (F₂) is 410 N.

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Sound waves are longitudinal waves.

Since, the particles of the medium through which the sound is transmitted vibrate parallel to the direction that the sound wave moves, they are longitudinal waves.

A sound wave is a pressure wave; as a result of the vibrations of the sound source, zones of high pressure (compressions) and low pressure (rarefactions) are created. These rarefactions and compressions are caused by the sound.

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Answer:

The Correct answer is D

molecules of liquid are stationary

The statement true about sound waves is " Sound moves faster in the ocean than in the air."  The correct option is C.

Sound waves travel much faster in water (such as the ocean) compared to air. The speed of sound in air is around 343 meters per second at room temperature, while in water, it is about 1,500 meters per second. The denser medium of water allows sound waves to propagate more quickly.

A. Sound would move faster in a pool of water than in a pool of Jello: This statement is not true. Sound actually moves faster in water compared to Jello. The speed of sound depends on the medium it travels through, and in general, sound travels faster in denser materials. Water is denser than Jello, so sound waves would move faster in water.

B. Sound would move faster in a pool of rubber than in a pool of diamonds: This statement is not true. Sound waves do not travel faster in rubber compared to diamonds. In fact, the speed of sound in a material depends on its elasticity and density. Diamonds are much denser and have a higher elasticity compared to rubber, so sound waves would move faster in diamonds than in rubber.

D. Sound moves faster in a lake than in the ocean: This statement is not true. Sound waves do not travel faster in a lake compared to the ocean. The speed of sound in water depends on several factors, including temperature, salinity, and pressure. In general, the speed of sound is higher in the ocean compared to lakes due to the higher salinity and pressure in the ocean.

Therefore, C. Sound moves faster in the ocean than in the air: This statement is true.

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The index of refraction for the plastic is determined as 1.5.

The index of refraction for the plastic is calculated using Snell's law.

sinθ₁/sinθ₂ = n₂/n₁

Where;

sin(31°)/sin(27°) = n₂/1.33

n₂ = 1.33 x sin(31°)/sin(27°)

n₂  = 1.5

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The sensitivity of the moving coil galvanometer is 0.1 A/°. This means that for every 1° of deflection, the galvanometer requires a current of 0.1 A.

A galvanometer is an instrument used to detect and measure small amounts of electrical current. It works on the principle of electromagnetic induction and consists of a coil of wire that can rotate in a magnetic field. When an electric current flows through the coil, it experiences a torque that causes it to rotate.

The sensitivity of a moving coil galvanometer is defined as the current required to produce a full-scale deflection (FSD) of the pointer. In this case, the FSD of the galvanometer is 3A, and it corresponds to a deflection of 30°. Therefore, the sensitivity of the instrument can be calculated as follows:

Sensitivity = FSD/Deflection Angle

Sensitivity = 3A/30°

Sensitivity = 0.1 A/°

Hence, The moving coil galvanometer has a 0.1 A/° sensitivity. This means that the galvanometer needs a current of 0.1 A for every 1° of deflection.

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An ice cube of mass 0.008 kg at 0°C was placed in water at 15°C in an insulated plastic beaker. The mass of water in the beaker was 0.120 kg. After the ice cube had melted, the water was stirred, and its temperature was found to have fallen to 9°C. The specific heat capacity of water is 4200 J/kg °C.

a) The energy transferred from the water can be calculated using the equation

Q = m_water * c_water * ΔT

Where Q is the energy transferred, m_water is the mass of water, c_water is the specific heat capacity of water, and ΔT is the change in temperature of the water.

First, we need to find the initial temperature difference between the water and the ice

ΔT_1 = 15°C - 0°C = 15°C

Next, we can use the heat lost by the water to melt the ice

Q_1 = m_ice * L_fusion

Where Q_1 is the energy transferred during melting, m_ice is the mass of the ice, and L_fusion is the specific latent heat of fusion of water.

Finally, we need to find the energy transferred from the water to cool down from 15°C to 9°C

ΔT_2 = 15°C - 9°C = 6°C

Q_2 = m_water * c_water * ΔT_2

Now, we can find the total energy transferred from the water

Q = Q_1 + Q_2

Q = m_ice * L_fusion + m_water * c_water * ΔT_2

Q = 0.008 kg * L_fusion + 0.120 kg * 4200 J/kg°C * 6°C

Q = L_fusion + 3024 J

b) The energy gained by the melted ice can be calculated using the equation

Q = m_ice * c_water * ΔT

Where Q is the energy gained, m_ice is the mass of the melted ice, c_water is the specific heat capacity of water, and ΔT is the change in temperature of the melted ice.

The mass of the melted ice is equal to the mass of the original ice cube

m_melted_ice = m_ice = 0.008 kg

The change in temperature of the melted ice is

ΔT = 9°C - 0°C = 9°C

Now, we can find the energy gained by the melted ice

Q = m_melted_ice * c_water * ΔT

Q = 0.008 kg * 4200 J/kg°C * 9°C

Q = 302.4 J

Therefore, the melted ice gained 302.4 J of energy.

c) We can use the equation from part (a) to solve for the specific latent heat of fusion of water

L_fusion = Q - m_water * c_water * ΔT_2

L_fusion = 3024 J - 0.120 kg * 4200 J/kg°C * 6°C

L_fusion = 3024 J - 3024 J

L_fusion = 0 J/kg

Hence, the specific latent heat of fusion of water is known to be approximately 334 kJ/kg.

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