Use a table of values to graph the function ƒ(x) = |x + 2| – 1. Select the correct graph below.

Triangle MNL and triangle QNL are congruent to each other based on by either ASA or AAS.

A triangle is a polygon with three sides and three angles. Types of triangles are isosceles, equilateral, scalene and right angle triangle. Two triangles are said to be congruent if they have the same shape and their corresponding sides are congruent to each other.

From triangle MNL and triangle QNL, in triangle MNL:

∠M + ∠N + ∠L = 180° (sum of angles in a triangle)

90 + 58 + ∠L = 180

∠L = 32°

Hence Triangle MNL and triangle QNL are congruent to each other based on by either ASA or AAS.

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The slopes of the two diagonals of the rhombus are: A. b - f/a - e and -a + e/b - f.

To find the slope, the formula used is: change in y/change in x.

If two lines are perpendicular to each other, their slope values will be negative reciprocals.

In a rhombus, the two diagonals in the rhombus bisects each other at angle 90 degrees. This means that the two diagonals of a rhombus are perpendicular to each other. Therefore, the slope of the diagonals of any rhombus would be negative reciprocals.

The slope of the diagonals of the rhombus given would therefore be negative reciprocals to each other.

Given two endpoints of one of the diagonals as:

(a, b) = (x1, y1)

(e, f) = (x2, y2)

Slope (m) = change in y / change in x = b - f/a - e

The negative reciprocal of b - f/a - e is -a + e/b - f.

Therefore, the slopes of the two diagonals are: A. b - f/a - e and -a + e/b - f.

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Answer:

ummm the answer is very simple

The answer is 0/6

Step-by-step explanation:

[tex] \frac{1}{2 \times 3} - \frac{1}{6} [/tex]

[tex] \frac{1}{6} - \frac{1}{6} [/tex]

[tex]1 - 1 = \frac{0}{6} [/tex]

[tex]\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}[/tex]

◉ [tex]\large\bm{ -4}[/tex]

[tex]\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}[/tex]

Before performing any calculation it's good to recall a few properties of integrals:

[tex]\small\longrightarrow \sf{\int_{a}^b(nf(x) + m)dx = n \int^b _{a}f(x)dx + \int_{a}^bmdx}[/tex]

[tex]\small\sf{\longrightarrow If \: a \angle c \angle b \Longrightarrow \int^{b} _a f(x)dx= \int^c _a f(x)dx+ \int^{b} _c f(x)dx }[/tex]

So we apply the first property in the first expression given by the question:

[tex]\small \sf{\longrightarrow\int ^3_{-2} [2f(x) +2]dx= 2 \int ^3 _{-2} f(x) dx+ \int f^3 _{2} 2dx=18}[/tex]

And we solve the second integral:

[tex]\small\sf{\longrightarrow2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} f(x)dx = 2 \int ^3_{-2} f(x)dx + 2 \cdot(3 - ( - 2)) }[/tex]

[tex]\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} 2dx = 2 \int ^3_{-2} f(x)dx + 2 \cdot5 = 2 \int^3_{-2} f(x)dx10 = }[/tex]

Then we take the last equation and we subtract 10 from both sides:

[tex]\sf{{\longrightarrow 2 \int ^3_{-2} f(x)dx} + 10 - 10 = 18 - 10}[/tex]

[tex]\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx = 8}[/tex]

And we divide both sides by 2:

[tex]\small\longrightarrow \sf{\dfrac{2 { \int}^{3} _{2} }{2} = \dfrac{8}{2} }[/tex]

[tex]\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx=4}[/tex]

Then we apply the second property to this integral:

[tex]\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} f(x)dx = 4}[/tex]

Then we use the other equality in the question and we get:

[tex]\small\sf{\longrightarrow 2 \int ^3_{-2} f(x)dx = 2 \int ^3_{-2} f(x)dx = 8 + 2 \int ^3_{-2} f(x)dx = 4}[/tex]

[tex]\small\longrightarrow \sf{2 \int ^3_{-2} f(x)dx =4}[/tex]

We substract 8 from both sides:

[tex]\small\longrightarrow \sf{2 \int ^3_{-2} f(x)dx -8=4}[/tex]

• [tex]\small\longrightarrow \sf{2 \int ^3_{-2} f(x)dx =-4}[/tex]

Answer:

Step-by-step explanation:

a. This information is given to you.

b. We want to find

[tex]\mathrm{Pr}\{X > 8.9\}[/tex]

so we first transform [tex]X[/tex] to the standard normal random variable [tex]Z[/tex] with mean 0 and s.d. 1 using

[tex]X = \mu + \sigma Z[/tex]

where [tex]\mu,\sigma[/tex] are the mean/s.d. of [tex]X[/tex]. Now,

[tex]\mathrm{Pr}\left\{\dfrac{X - 10.5}2 > \dfrac{8.9 - 10.5}2\right\} = \mathrm{Pr}\{Z > -0.8\} \\\\~~~~~~~~= 1 - \mathrm{Pr}\{Z\le-0.8\} \\\\ ~~~~~~~~ = 1 - \Phi(-0.8) \approx \boxed{0.7881}[/tex]

where [tex]\Phi(z)[/tex] is the CDF for [tex]Z[/tex].

c. The 76th percentile is the value of [tex]X=x_{76}[/tex] such that

[tex]\mathrm{Pr}\{X \le x_{76}\} = 0.76[/tex]

Transform [tex]X[/tex] to [tex]Z[/tex] and apply the inverse CDF of [tex]Z[/tex].

[tex]\mathrm{Pr}\left\{Z \le \dfrac{x_{76} - 10.5}2\right\} = 0.76[/tex]

[tex]\dfrac{x_{76} - 10.5}2 = \Phi^{-1}(0.76)[/tex]

[tex]\dfrac{x_{76} - 10.5}2 \approx 0.7063[/tex]

[tex]x_{76} - 10.5 \approx 1.4126[/tex]

[tex]x_{76} \approx \boxed{11.9126}[/tex]

Give f(x) a dotted boundary and shade it above.

Give g(x) a solid boundary and shade it above.

The solution set is the region that is in the shaded region of both graphs.

Answer:

Joey needs 9 boxes.

Step-by-step explanation:

You will use the fact that a dozen is 12 cookies. You're trying to find how many dozen are in 100.

Something like:

12b = 100

or if you're studying inequalities:

12b >= 100

Divide by 12 to solve. See image. Interpret the results. See image.

Answer: [tex]x=-5[/tex]

Step-by-step explanation:

[tex]x+5=0 \implies x=-5[/tex]

Answer: 22.5 inches

Step-by-step explanation:

[tex]p=s+s+s+s+s[/tex]

[tex]5(4.5 in)=p[/tex]

∴ 22.5 inches = perimeter of the pentagon

Answer:

B

Step-by-step explanation:

a dream like imageeeeee

Answer:

Your answer is - 28

Step-by-step explanation:

Given,

          a = 2

          b = - 3

          c = - 1

          d = 4

Now,

       - 2 ( b²  -  5 c )

= - 2 ( -3²  -  5 ( - 1 ) )

= - 2 ( 9 + 5 )

= - 2 × 14

= - 28   ans….

Hope its helpful :-)

If so, please mark me as brainlist :-)

[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]

To prove two lines parallel, we need to check if the two angles involving the lines acts as some angle pair with defininte property.

In the given figure,

( by Alternate Exterior angle pair )

Hence, the two lines are parallel.

[tex] \qquad \large \sf {Conclusion} : [/tex]

Answer: 3 loops

Step-by-step explanation: The loop is 1.2 miles, and the total walk is 3.6 miles. You want to find out how many laps are in the 3.6 miles. This can be found using division. 3.6/1.2= the number of 1.2 mile laps inside the 3.6 mile walk, which is 3 laps. hope this helped!

Answer:

5%.

Step-by-step explanation:

That is

(24/480 * 100    

 Now 480 / 24 = 20 so we have

(1/20) * 100

= 100/20

= 5%.

Answer:

24 is 5% of 480

Step-by-step explanation:

24 / 480 = 0.05

Percent is "for each 100"

Then:

0.05 * 100 = 5%

Answer:

[tex]2 {x}^{2} + 7xy - 15 {y}^{2} [/tex]

Step-by-step explanation:

We can use the rainbow expansion method to find the expression.

[tex](2x - 3y)(x + 5y) \\ = 2 {x}^{2} + 10xy - 3xy - 15 {y}^{2} \\ = 2 {x}^{2} + 7xy - 15 {y}^{2} [/tex]

Answer:

$824.56

Step-by-step explanation:

Use the compound interest formula which is A = P(1+r/n)^nt

1st using the given information we are going to find out values:
P is our initial amount of $500
r is the annual rate of interest (expressed as a decimal) 8% becomes 0.08.
n is how many times interest is compounded per year, in this case since its not stated we are going to assume its annually, so n is 1
t is how long the money is deposited (in years) so t is 6.5
A is our final amount

2nd plug in our values into the equation

Plugging all these values we get A = 500 (1 +0.08/1)^(0.08)(6.5)

A = $824.56

The equation for the horizontal asymptote will be y = -2.

Since the degree of the numerator and denominator of f(x) is the same both being 1, therefore horizontal asymptote exists and is given by:

y = Leading coefficient of numerator of f(x) / Leading coefficient of denominator of f(x)

= y = -2/1

= y = -2

The vertical asymptote will be f(x) = -2x / (x + 3). To find the vertical asymptote we will equate the denominator of f(x) = 0

= x + 3 = 0

= x = -3

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Answer:

9:8:2

Step-by-step explanation:

3/4 : 2/3 : 1/6 Multiply by 12.
9 : 8 : 2

Step-by-step explanation:

1 kilogram (kg) = 1000 grams (g)

as "kilo" means 1000.

b = a × c / 1000

it is simple : we have "c" square meters. as we need to apply "a" grams per square meter, we need to multiply both numbers to know how many grams we need for that many square meters. hence a × c.

and to get kg, we need to divide this number of grams by 1000.

that's it.

Answer: $51156

Step-by-step explanation:

a = b x p%

how much will the price increase

a = 49,000 x 4.4%

= 49,000 x 0.044

= $2156

price of next model

49,000 + 2156 = $51156

The answer is |-4 - 1|.

If you solve this absolute value, the answer would be 5 and if you look at the number line, the distance between the two dots is 5 units.

|-4 - 1| --> |-5| --> 5

in an absolute value, there are no negative numbers so the -5 becomes 5.

Answer:

Step-by-step explanation:

2^0 is less than or equal to 1!, because 1<= 1

if 2^n <= (n+1)!, we wish to show that 2^(n+1) <= (n+2)!, since

(n+2)! = (n+1)! * (n+2), and (n+1)!>= 2^n, then we want to prove that n+2<=2, which is always true for n>=0

Answer:

y=(−2)x−-6

Step-by-step explanation:

Use the slope −2 and the point (−5,4) to find the y-intercept.

y=mx+b

⇒4=(−2×−5)+b

⇒−4=10+b

⇒b=−6

Write the equation in slope intercept form as:

y=mx+b

⇒y=(−2)x−-6

Answer:

Yes

Step-by-step explanation:

The sum of the lengths of any two sides of a triangle must be greater than the length of the third side or largest side. So, 7+6 = 13 which is greater than 9

Answer:

Yes, triangle with sides 6, 7 ,9 can be formed.

Step-by-step explanation:

The sum of any two sides of the triangle should be greater than the third side. If so, triangle can be formed.

6 + 7 = 13  >  9

7+ 9 = 16    > 6

6 +9 = 15   > 7

[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]

The contrapositive of the statement is False.

Because we already know, Cube is a 3 - dimensional shape with 6 faces, all its sides are equal and all faces are congruent.

But the contrapositive of the statement is not true, because not only cube has six faces.

There are other 3 - D shapes that have 6 faces.

[tex] \qquad \large \sf {Conclusion} : [/tex]

The contrapositive of the statement is false.

Answer:

55

Step-by-step explanation:

[tex]\sqrt{3018+\sqrt{36+\sqrt{169} } }[/tex]

= [tex]\sqrt{3018+\sqrt{36+13} }[/tex]

= [tex]\sqrt{3018+\sqrt{49} }[/tex]

= [tex]\sqrt{3018+7}[/tex]

= [tex]\sqrt{3025}[/tex]

= 55

The addition of the polynomials x⁴ - 3x + 1, 4x² - 2x + 8, x³ - 9 in descending powers of x is x⁴ + x³ + 4x² - 5x.

Adding the polynomial

(x⁴ - 3x + 1) + (4x² - 2x + 8) + (x³ - 9)

= x⁴ - 3x + 1 + 4x² - 2x + 8 + x³ - 9

= x⁴ + x³ + 4x² - 3x - 2x + 1 + 8 - 9

= x⁴ + x³ + 4x² - 5x

Therefore, the addition of the polynomials x⁴ - 3x + 1, 4x² - 2x + 8, x³ - 9 in descending powers of x is x⁴ + x³ + 4x² - 5x.

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