Answer:
c. 5.5 years, 0.51 years
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
Mean of 5.5 years and a standard deviation of 2.1 years.
This means that, for the population, [tex]\mu = 5.5, \sigma = 2.1[/tex]
Random samples of size 17.
This means that [tex]n = 17[/tex]
Use the Central Limit Theorem to find the mean and standard error of the mean of the indicated sampling distribution.
The mean is the same as the mean for the population, that is, 5.5 years.
The standard deviation is:
[tex]s = \frac{\sigma}{\sqrt{n}} = \frac{2.1}{\sqrt{17}} = 0.51[/tex]
This means that the correct answer is given by option c.
The mean of a data set is observed to be very different from its median, representing a strong skewness. However, the 1.5 IQR rule reveals that there are no outliers. Which of the following is correct, if the sample size is 100?
a. A normal quantile plot of the data follows a diagonal line, and the t-procedure is appropriate to use.
b. A normal quantile plot of the data does not follow a diagonal line, and the t- procedure is not appropriate to use.
c. A normal quantile plot of the data follows a diagonal line, and the t-procedure is not appropriate to use.
d. A normal quantile plot of the data does not follow a diagonal line, and the t- procedure is appropriate to use.
Answer:
a. A normal quantile plot of the data follows a diagonal line, and the t-procedure is appropriate to use.
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
In this question:
Sample size of 100 > 30, which means that we use the Central Limit Theorem, and thus, the sampling distribution is approximately normal, following a diagonal line, and since the standard deviation of the population is not know, we use the t-procedure. Thus, the correct answer is given by option a.
12.03 MC)
rectangle ABCD was reflected over the y-axis, reflected over the x-axis, and rotated 180°, where would point A' lie?
Hint: Place your coordinates in the blank with no parentheses and a space after the comma in the form: x, y]
9514 1404 393
Answer:
(1, -1)
Step-by-step explanation:
The three transformations are ...
(x, y) ⇒ (-x, y) . . . . . reflection over the y-axis
(x, y) ⇒ (x, -y) . . . . . reflection over the x-axis
(x, y) ⇒ (-x, -y) . . . . . rotation 180°
Then the composition of the three transformations is ...
(x, y) ⇒ (x, y) . . . . . . back to the original position
A(1, -1) ⇒ A'(1, -1)
Answer:
(1, -1)Step-by-step explanation:
hope it helps muchHELP ASAP?
the two answers not showing on screen are
C:y<6x-3
D:y<6-3
Answer:
A is that answer
A) y<2x-3
: Find absolute minimum and maximum values of (, ) = 2
2 +
4 + 4
On the close triangular region R bounded by the lines = −2, = 0, = 2
URGENT PLS HELP
Given f(y)=2y^2 - 4y, and h(x)= x^2 - 1, determine f(h(x))
Answer:
f(h(x)) = 2•(x²-1)² -4•(x²-1)
Choose which triangle goes into the right category.
Answer:
obtuse cant be a right angle
Step-by-step explanation:
in order to be obtuse you have to be more than 90 dagrees
Find the slope of the line that passes through the two points. -3,6 & -7,3
HELP!!!!
convert 65 kg into gram .
Answer:
65000
Step-by-step explanation:
65x 1000
1000 because 1kg= 1000
How many additional teachers will have to be hired to reduce the ratio to 1:20
Answer:
30 additional teachers will have to be hired to reduce the ratio to 1:20.
Step-by-step explanation:
Given that Jefferson School has 1800 students, and the teacher-pupil ratio is 1:30, to determine how many additional teachers will have to be hired to reduce the ratio to 1:20, the following calculation must be performed:
30 = 1800
1 = X
1800/30 = X
60 = X
20 = 1800
1 = X
1800/20 = X
90 = X
90 - 60 = 30
Therefore, 30 additional teachers will have to be hired to reduce the ratio to 1:20.
Newborn babies: A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights of 732 babies born in New York. The mean weight was 3311 grams with a standard deviation of 860 grams. Assume that birth weight data are approximately bell-shaped. Part 1 of 3 (a) Estimate the number of newborns whose weight was less than 4171 grams. Approximately of the 732 newborns weighed less than 4171 grams. Part 2 of 3 (b) Estimate the number of newborns whose weight was greater than 1591 grams. Approximately of the 732 newborns weighed more than 1591 grams. Part 3 of 3 (c) Estimate the number of newborns whose weight was between 3311 and 5031 grams. Approximately of the 732 newborns weighed between 3311 and 5031 grams.
Answer:
a) 615
b) 715
c) 344
Step-by-step explanation:
According to the Question,
Given that, A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights of 732 babies born in New York. The mean weight was 3311 grams with a standard deviation of 860 gramsSince the distribution is approximately bell-shaped, we can use the normal distribution and calculate the Z scores for each scenario.Z = (x - mean)/standard deviation
Now,
For x = 4171, Z = (4171 - 3311)/860 = 1
P(Z < 1) using Z table for areas for the standard normal distribution, you will get 0.8413.Next, multiply that by the sample size of 732.
Therefore 732(0.8413) = 615.8316, so approximately 615 will weigh less than 4171For part b, use the same method except x is now 1591.
Z = (1581 - 3311)/860 = -2
P(Z > -2) , using the Z table is 1 - 0.0228 = 0.9772 . Now 732(0.9772) = 715.3104, so approximately 715 will weigh more than 1591.For part c, we now need to get two Z scores, one for 3311 and another for 5031.
Z1 = (3311 - 3311)/860 = 0
Z2 = (5031 - 3311)/860= 2
P(0 ≤ Z ≤ 2) = 0.9772 - 0.5000 = 0.4772
approximately 47% fall between 0 and 1 standard deviation, so take 0.47 times 732 ⇒ 732×0.47 = 344.
Geometry please someone help i cant fail this class
Given: f(x) = x- 7 and h(x) = 2x + 3
Write the rule for f(h(xc)).
Answer:
[tex]f(h(xc)) = 2xc-4[/tex]
Step-by-step explanation:
Given
[tex]f(x) = x - 7[/tex]
[tex]h(x) = 2x + 3[/tex]
Required
[tex]f(h(xc))[/tex]
First, calculate h(xc)
If [tex]h(x) = 2x + 3[/tex]
Then
[tex]h(xc) = 2xc + 3[/tex]
Solving further:
[tex]f(x) = x - 7[/tex]
Substitute h(xc) for x
[tex]f(h(xc)) = h(xc) - 7[/tex]
Substitute [tex]h(xc) = 2xc + 3[/tex]
[tex]f(h(xc)) = 2xc + 3 - 7[/tex]
[tex]f(h(xc)) = 2xc-4[/tex]
Robert paid $4.5 for 3 apples. Find the cost per apple.
Answer:
$1.50
Step-by-step explanation:
so its
4.5 ÷ 3
which
1.5
There are 100 sheets of paper on table. It takes 10 seconds to count 10 sheets. How many seconds will you need to count 80 sheets?
Answer:
80 seconds
Step-by-step explanation:
10/10 = 1
now it takes 1 seconds to count 1 sheet
80 x 1 = 80 seconds to count 80 sheets
Step-by-step explanation:
10sheets=10seconds
1sheet=1sheet÷10sheets x 10seconds
=1second
80sheets=80sheets÷1sheet x 1second
80seconds
hope this is helpful
The area of a rectangle is 110 square units. Its length measures 11 units. Find the
length of its diagonal. Round to the nearest tenth of a unit.
Answer:
A
=
w
l
d
=
w
2
+
l
2
Solving for
d
d
=
l
2
+
(
A
l
)
2
=
11
2
+
(
110
11
)
2
≈
14.86607
The length of the diagonal of the rectangle is 14.9 units.
What is a diagonal?A diagonal is the longest line that divides a plane shape into two halves.
To calculate the diagonal of the rectangle, we use Pythagoras theorem.
Formula:
A = lw.............. Equation 1Where:
A = Area of the rectanglel = Length of the rectanglew = width of the rectangle.make w the subject of the equation
w = A/l.............. Equation 2From the question,
Given:
A = 110 square unitsl = 11 unitsSubstitute these values into equation 2
w = 110/11w = 10 units.Finally, to calculate the diagonal of the rectangle, we use the formula below
d² = l²+w²............. Equation 3Given:
w = 10 unitsl = 11 units.Substitute these values into equation 3
d² = 10²+11²d² = 100+121d² = 221d = √221d = 14.9 units.Hence, the length of the diagonal of the rectangle is 14.9 units.
Learn more about diagonal here: https://brainly.com/question/654982
#SPJ2
Which of the following equations describes this graph?
A. y=(x-1)^2-
B. y=(x-3)^2+2
C. y=(x+1)^2-2
D. y=(x-2)^2+3
Answer:
The choose (A)
y=(x-1)²-2
Respond to each of the four questions.
Describe the steps to graphing a linear equation. Be sure to provide an example to illustrate your description.
Describe the steps to graphing a quadratic equation. Be sure to provide an example to illustrate your description.
Describe how to solve a linear equation. Be sure to provide an example to illustrate your description.
Describe how to solve a quadratic equation. Be sure to provide an example to illustrate your description.
Answer:hello
Step-by-step explanation:
1+1
O EXPONENTAL AND LOGARITHMIC FUNCTIONS
Finding the initial or final amount in a word problem on...
An initial amount of money is placed in an account at an interest rate of 2% per year, compounded continuously. After two years, there is $1269.79 in the
account. Find the initial amount placed in the account. Round your answer to the nearest cent.
Answer:
$ 1220.00
Step-by-step explanation:
1269.79 = A [tex]e^{.02 * 2}[/tex]
1269.79 /A = [tex]e^{.04}[/tex]
ln(1269.79 /A) = .04 ln(e)
ln(1269.79 /A) = .04
1269.79 /A = [tex]e^{.04}[/tex]
1269.79 /A = 1.0408
A = 1269.79 / 1.0408
$ 1220.00
A robot that makes _/6 of a boat per day will make 5 boats in 6 days
if a x + B Y is equal to a square minus b square and b x + A Y is equal to zero find the value of x + Y
9514 1404 393
Answer:
a-b
Step-by-step explanation:
Add the two equations together:
(ax +by) +(bx +ay) = (a² -b²) +(0)
x(a +b) +y(a +b) = (a +b)(a -b)
x + y = a - b . . . . . divide by (a+b), assuming a+b ≠ 0
g At a certain gas station, 30% of all customers use the restroom. What is the probability that, out of the next 10 customers, (a) exactly 4 will use the restroom
Answer:
[tex]P(x=4) = 0.200[/tex]
Step-by-step explanation:
Given
[tex]n=10[/tex] --- selected customers
[tex]x = 4[/tex] --- those that are expected to use the restroom
[tex]p =30\% = 0.30[/tex] --- proportion that uses the restroom
Required
[tex]P(x = 4)[/tex]
The question illustrates binomial probability and the formula is:
[tex]P(x) = ^nC_x * p^x * (1 - p)^{n - x}[/tex]
So, we have:
[tex]P(x=4) = ^{10}C_4 * (0.30)^4 * (1 - 0.30)^{10 - 4}[/tex]
[tex]P(x=4) = ^{10}C_4 * (0.30)^4 * (0.70)^6[/tex]
[tex]P(x=4) = 210* (0.30)^4 * (0.70)^6[/tex]
[tex]P(x=4) = 0.200[/tex]
How many vertices (corners) does a cube have?
How many faces does a rectangular prism have?
How many edges does a rectangular prism have?
How many edges does a square-based pyramid have?
How many vertices (corners) does a square-based pyramid have?
How many faces does a triangular prism have?
How many vertices (corners) does a triangular prism have?
kb 2021
Answer:
The answer is below
Step-by-step explanation:
a) A cube is a three dimensional solid with 6 square faces.
A cube has 8 vertices
b) A rectangular prism is a three dimensional solid with two parallel rectangular bases.
A rectangular prism has 6 faces.
c) A rectangular prism is a three dimensional solid with two parallel rectangular bases.
A rectangular prism has 12 edges.
d) A square-based pyramid is a pyramid with a square base.
A square-based pyramid has 8 edges
e) A triangular prism is a three dimensional solid with two parallel triangular bases.
A triangular prism has 5 faces.
f) A triangular prism is a three dimensional solid with two parallel triangular bases.
A triangular prism has 6 vertices.
The total number of labor hours for a construction project by week x is given by: Week 1 4 7 10 13 16 19 Total hours 25 158 1254 5633 9280 10,010 10,100 Look at its scatter plot, an appropriate model for this data is:
Answer:
Logistic model
Step-by-step explanation:
A scatter plot is a mathematical representation or diagram which is used to shoe the relation between two given variables. It uses the Cartesian coordinates which is used to display the values for a typically two variables for the given set of data.
In the context, a scatter plot is made between two variables. The two variables are the total number of hours and the number of weeks.
From the graph shown, we can say that model is a logistic model as the shape of the graph is S shaped.
Therefore, the appropriate model for the data given is logistic model.
help on part 3? not sure what i’m supposed to do
The x-intercepts are the points on the plot of a function f(x) where the graph crosses the x-axis. In other words, they're the values of x that make f(x) = 0.
In this case, the x-intercepts are the two roots of the parabola,
(x - 4) (x - 5) = 0 … … … (this is what the hint is referring to)
==> x - 4 = 0 or x - 5 = 0
==> x = 4 or x = 5
The intercepts themselves are points (x, f(x)), so you can report them as (4, 0) and (5, 0).
please help please help
Answer:
1. number line or 3
2. D
3. E and K
4. B
5. A
Brainliest please~
if cars A and B are traveling at the speed of 55km/hr and 75km/hr respectively. What is their average speed?
Answer:
65 km/hr
Step-by-step explanation:
The average of numbers can be calculated by adding them up and dividing that by how many numbers there are.
Here, we have two numbers. Therefore, we first add them (55+75 = 130) and then divide by 2 because there are 2 numbers, so 130/2 = 65
the angle of elevation of the top of the mast from a point 53m to its base on level ground is 61°. find the height of the mast to the nearest meter
the answer Is 95.61465. If you approximate you get 10.
3x7 I need help with this i do not know the answer pls help.
Answer:
21
Step-by-step explanation:
7+7+7=21
Verify the sine law by taking particular triangle in four quadrant.
Answer:
answer is in the picture above
Please help me with solving these. I’d really appreciate your help. Thank you very much.
Answer:
Problem 17)
[tex]\displaystyle y=-\frac{5}{2}x+\frac{7}{2}[/tex]
Problem 18)
[tex]\displaystyle y=\frac{3}{2}x-\frac{3}{2}+\frac{\pi}{4}[/tex]
Step-by-step explanation:
Problem 17)
We have the curve represented by the equation:
[tex]\displaystyle 4x^2+2xy+y^2=7[/tex]
And we want to find the equation of the tangent line to the point (1, 1).
First, let's find the derivative dy/dx. Take the derivative of both sides with respect to x:
[tex]\displaystyle \frac{d}{dx}\left[4x^2+2xy+y^2\right]=\frac{d}{dx}[7][/tex]
Simplify. Recall that the derivative of a constant is zero.
[tex]\displaystyle \frac{d}{dx}[4x^2]+\frac{d}{dx}[2xy]+\frac{d}{dx}[y^2]=0[/tex]
Differentiate. We can differentiate the first term normally. The second term will require the product rule. Hence:
[tex]\displaystyle 8x+\left(2y+2x\frac{dy}{dx}\right)+2y\frac{dy}{dx}=0[/tex]
Rewrite:
[tex]\displaystyle \frac{dy}{dx}\left(2x+2y\right)=-8x-2y[/tex]
Therefore:
[tex]\displaystyle \frac{dy}{dx}=\frac{-8x-2y}{2x+2y}=-\frac{4x+y}{x+y}[/tex]
So, the slope of the tangent line at the point (1, 1) is:
[tex]\displaystyle \frac{dy}{dx}\Big|_{(1, 1)}=-\frac{4(1)+(1)}{(1)+(1)}=-\frac{5}{2}[/tex]
And since we know that it passes through the point (1, 1), by the point-slope form:
[tex]\displaystyle y-1=-\frac{5}{2}(x-1)[/tex]
If desired, we can simplify this into slope-intercept form. Therefore, our equation is:
[tex]\displaystyle y=-\frac{5}{2}x+\frac{7}{2}[/tex]
Problem 18)
We have the equation:
[tex]\displaystyle y=\tan^{-1}\left(x^3\right)[/tex]
And we want to find the equation of the tangent line to the graph at the point (1, π/4).
Take the derivative of both sides with respect to x:
[tex]\displaystyle \frac{dy}{dx}=\frac{d}{dx}\left[\tan^{-1}(x^3)][/tex]
We can use the chain rule:
[tex]\displaystyle \frac{d}{dx}[u(v(x))]=u'(v(x))\cdot v(x)[/tex]
Let u(x) = tan⁻¹(x) and let v(x) = x³. Thus:
(Recall that d/dx [arctan(x)] = 1 / (1 + x²).)
[tex]\displaystyle \frac{d}{dx}\left[\tan^{-1}(x^3)\right]=\frac{1}{1+v^2(x)}\cdot 3x^2[/tex]
Substitute and simplify. Hence:
[tex]\displaystyle \frac{d}{dx}\left[\tan^{-1}(x^3)\right]=\frac{1}{1+v^2(x)}\cdot 3x^2=\frac{3x^2}{1+x^6}[/tex]
Then the slope of the tangent line at the point (1, π/4) is:
[tex]\displaystyle \frac{dy}{dx}\Big|_{x=1}=\frac{3(1)^2}{1+(1)^6}=\frac{3}{2}[/tex]
Then by the point-slope form:
[tex]\displaystyle y-\frac{\pi}{4}=\frac{3}{2}(x-1)[/tex]
Or in slope-intercept form:
[tex]\displaystyle y=\frac{3}{2}x-\frac{3}{2}+\frac{\pi}{4}[/tex]
