Use the counting principle to determine the number of elements in the sample space. Two digits are selected with replacement from the digits 1,2,3, and 4

Answer: its the 3rd one if im wrong im sorry

:3

Given the above information, it is correct to say Yes, since a sample mean number of eggs of 15.1 eggs or less only occurred twice in simulated values, there is evidence that the true mean number of eggs is less than 16. (Option A)

Recall that the mean (statistically speaking) is a measure of central tendency of a probability distribution along median and mode.

You could also state that it is an expected value. Given that samples of actual value taken from the

Hence, since from 100 samples taken, the number of eggs of 15.1 or less occurred, then the true mean or actual mean is less than 16.

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Answer:

.8849   or   88.49% have score ess than 123

Step-by-step explanation:

Answer:

88.49 %  have less than 123   (or .8849)

Step-by-step explanation:

123 is    18/15 = 1.2   S.D. ABOVE the mean    z-score +1.2

   from z- score table    +1.2    this is .8849   or 88.49 %

The answer choice which correctly draws a comparison between the end behaviours of the functions is; Choice C; They have the same end behavior as x approaches -∞ and same end behavior as x approaches ∞.

As given in the task content; the graph of the exponential function passes through (-4, 9), (0, 1), (1, 0), and (5, -2).

It therefore follows that as; x reduces (approaches -∞), the y value increases.

And, as x -increases (approaches +∞), the y-value decreases.

For the table, the values can be written as coordinates as follows; (-1,2), (0,4), (1,6), (2, 0), (3,-2).

Consequently, as x reduces (approaches -∞), the y- values decrease.

And, as x increases (approaches +∞), the y-values decrease.

Ultimately, the two functions in discuss can be concluded to have; Choice C.

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Using simple interest, it is found that:

Simple interest is used when there is a single compounding per time period.

The amount of money after t units of time in is modeled by:

[tex]A(t) = A(0)(1 + rt)[/tex]

In which:

For this problem, the parameters are given as follows:

A(0) = 875, r = 0.0004273, t = 32.

Hence the amount paid is given by:

A(32) = 875 x (1 + 0.0004273 x 32) = $887.

The amount of interest is given by:

I = 887 - 875 = $12.

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Answer:

5. P = 23 m

   A =  15 [tex]m^{2}[/tex]

6. P = 24.4 in

   A = 15.3 [tex]in^{2}[/tex]

Step-by-step explanation:

Area formula of a triangle is A = 1/2 bh

Area formula of a parallelogram is A = bh

5. The height of a triangle is perpendicular to the base.

    A = 1/2 * 10 * 3

    A = 15 [tex]m^{2}[/tex]

6. The height of the parallelogram is also perpendicular to the base.

    A = 9 * 1.7

    A = 15.3 [tex]in^{2}[/tex]

Perimeter means you add all the side lengths.

5. The side lengths are 5m, 8m, and 10m. Adding those together, you get 23m.

6. A parallelogram has congruent opposite sides. That means your side lengths are 9 in, 3.2 in, 9 in and 3.2 in. Adding those together, you get 24.4 in.

The proportion of the population exists less than 30 then

(x< 30) = 0.986.

To estimate the z-score using the formula, z = (x - µ)/σ

Where, x be the randomly chosen values = 30

µ be the mean = 31

σ be the standard deviation = 10

Proportion of the population that exists less than 18 = P(x < 30)

Plug in the values into z = (x - µ)/σ, to get z-score.

Substitute the values in the above equation, we get

z = (30 - 31)/10

z = -1/10 = -0.1

Therefore, the value of z = - 0.1.

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Answer:

C

Step-by-step explanation:

Option b accurately reflects this scenario, as it states that most of the students' test scores are around the mean, which aligns with the idea of a small standard deviation.

The correct option is:

b. Most of students' test scores are around the mean.

A large range indicates that there is a significant difference between the highest and lowest scores in the set.

On the other hand, a small standard deviation indicates that the data points (test scores) are clustered closely around the mean.

When the range is large but the standard deviation is small, it means that most of the students' test scores are relatively close to the mean, and there are no extreme values that are significantly far from the mean. In other words, the majority of students performed similarly on the test, with only a few outliers having scores much higher or much lower than the mean.

Option b accurately reflects this scenario, as it states that most of the students' test scores are around the mean, which aligns with the idea of a small standard deviation.

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0.03607

Absolute value is the distance of a number from zero. Since distance is always positive, the absolute value is the same number but positive.

Please note, for this problem I have rounded to 5 decimal points because the answer is irrational.

Subtracting

There are 2 different ways to approach this problem. You can either estimate the square root of 5 or plug this question straight into a calculator.

First, we can estimate [tex]\sqrt{5}[/tex] and round to 5 decimal places.

Then, take this value and subtract.

Absolute Value

Now that we have solved the subtraction problem we have to find the absolute value. As stated above, the easiest way to find absolute value is to simply make the number positive. Since the answer is already positive, this is the final answer.

Answer:

23370 students live with in 500 miles of the university.

Step-by-step explanation:

large university students =24000

selected students = 750

surveyed students =120 lives far away from university.

students live with in 500mile=?

750-120=630

24000-630=23370

Answer:

The original number is 72.

Step-by-step explanation:

Let the number by

[A][B]

The reverse number is

[B][A]

Original number:

A = B + 5

[A][B] - 2[B][A] = [A][B]/4

10A + B - 20B - 2A = (10A + B)/4

8A - 19B = (10A + B)/4

32A - 76B = 10A + B

22A - 77B = 0

22(B + 5) - 77B = 0

22B + 110 - 77B = 0

-55B = -110

B = 2

A = B + 5 = 2 + 5 = 7

The original number is 72.

The reverse is 27.

Let's check.

"the tens digit of a 2 digit number is 5 greater than the units digit"

7 is 5 greater than 2,so 72 looks good so far.

"if you subtract twice the reverse number the result is one fourth the original"

The reverse number is 27. Twice 27 is 2 × 27 = 54.

Subtract 54 from 72: 72 - 54 = 18

18 is 1/4 of 72. It works.

Answer: the original number is 72

The equivalent expression of  2x√44x - 2√11x  is 2x√11x

An equivalent expression can be find when simplified or factorised.

An expression is a combination of numbers, variables, functions (such as addition, subtraction, multiplication or division etc.)

In other words, an expression or algebraic expression is any mathematical statement which consists of numbers, variables and an arithmetic operation between them.

The expression equivalent to 2x√44x - 2√11x is as follows:

2x√44x - 2√11x

factorise

2x√44x - 2√11x = 2(x√44x - √11x³)

Hence,

2(x√44x - √11x) = 2(x√4 × 11x  - √11x³)

2(x√4 × 11x  - √11x) =  2(2x√11x  - x√11x)

Therefore,

2(2x√11x  - x√11x) = 4x√11x - 2x√11x

4x√11x - 2x√11x = 2x√11x

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Answer:

See image

Step-by-step explanation:

It cant be wrong

Answer:

Solution Given:

To find the simplest form we need to open bracket

-2x²(3x²-2x-6)

-2x²*3x²-2x²*(-2x) -2x²*(-6)\

[tex]-6x^{4}+4x^{3}+12x^2[/tex] is  a required answer.

Answer:i am not sure

Step-by-step explanation:

This question is very hard to answer

Answer: I think your brain needs cheese but..............................................

Step-by-step explanation:

Don't know

Answer:

Step-by-step explanation:

f(x)=ax³

ax³+2=b(x+1)³

ax³+2=b(x³+3x²+3x+1)

(a-b)x³-3bx²-3bx-b=0

Using the monthly payment formula, we have that:

It is given by:

[tex]A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}[/tex]

In which:

The down payment is 20% of $175,000, hence:

D = 0.2 x 175,000 = $35,000.

Hence the parameters are:

P = 175,000 - 35,000 = 140,000, r/12 = 0.055/12 = 0.004583, n = 30 x 12 = 360.

Then the monthly payment is found as follows:

[tex]A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}[/tex]

[tex]A = 140,000\frac{0.004583(1.004583)^{360}}{(1.004583)^{360} - 1}[/tex]

A = $795.87.

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From the information given, F(x) = 9.3319419 or approximately 9. This is  problem relating to math functions

Recall that we are given x to be = 16.1

Hence,

[tex]f\left(x\right)=\ 2x^{\frac{1}{4}}\ +\ 3x^{\frac{1}{2}}[/tex] =

2 (16.1) ⁰°²⁵ + 3 (16.1)⁰°⁵

= 32.2⁰°²⁵ + 48.3⁰°⁵

= 2.3821218 +6.9498201

f(x) = 9.3319419

f(x) approximately 9

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Answer:

line NM

Step-by-step explanation:

Since planes extend infinitely in all directions, planes intersect at a line, not at a line segment.

Answer:

arithmetic sequence formula: first term + (n - 1)common difference

9 + (n - 1)-2

9 + -2n + 2

= -2n + 11

The cosine equation of the attached graph is; y = 5 cos [( π/40)(x - (π/2))] + 3

The given parameters are:

Diameter = 10 m

Thus;

Radius; r = 5 m

Time; t = 80 s

Height above the ground, h = 2 m

The above means that:

Amplitude; A = 5 m

Period, T = 80 s

Minimum = 2 m

The cosine function is represented as:

y = a cos [k(x - d)] + c.

where;

A is amplitude

B is cycles from 0 to 2π

period = 2π/k

d is horizontal shift

c is vertical shift (displacement)

Thus;

2π/k = 80

k = 2π/80 = π/40

Where

c = Amplitude - Minimum

c = 5 - 2

c = 3

Shift to the left by π/2 gives;

d = π/2

Thus, the equation of the cosine graph is;

y = 5 cos [( π/40)(x - (π/2))] + 3

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Answer:

y= -1

Step-by-step explanation:

(2) (0) − y = 1

0 + − y = 1

(−y) + (0) = 1

−y = 1

Step 2: Divide both sides by -1

Y = −1

Using the normal distribution, there is a 0.1587 = 15.87% probability that’s a car picked at random is traveling at more than 100 km/hr.

The z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The mean and the standard deviation are given, respectively, by:

[tex]\mu = 90, \sigma = 10[/tex]

The probability that’s a car picked at random is traveling at more than 100 km/hr is one subtracted by the p-value of Z when X = 100, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{100 - 90}{10}[/tex]

Z = 1

Z = 1 has a p-value of 0.8413.

1 - 0.8413 = 0.1587.

0.1587 = 15.87% probability that’s a car picked at random is traveling at more than 100 km/hr.

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The two triangles exist congruent if they contain two congruent corresponding sides and their contained angles exist congruent.

Let [tex]$&\overline{A B} \cong \overline{D E} \\[/tex] and [tex]$&\overline{A C} \cong \overline{D F}[/tex]

Angle between [tex]$\overline{A B}$[/tex] and [tex]$\overline{A C}$[/tex] exists [tex]$\angle A$[/tex].

Angle between [tex]$\overline{D E}$[/tex] and [tex]$\overline{D F}$[/tex] exists [tex]$\angle D$[/tex].

Therefore, [tex]$\triangle A B C \cong \triangle D E F$[/tex] by SAS, if [tex]$\angle A \cong \angle D$$[/tex].

Given:

[tex]$&\overline{A B} \cong \overline{D E} \\[/tex] and

[tex]$&\overline{A C} \cong \overline{D F}[/tex]

According to the SAS congruence property, two triangles exist congruent if they contain two congruent corresponding sides and their contained angles exist congruent.

Let [tex]$&\overline{A B} \cong \overline{D E} \\[/tex] and [tex]$&\overline{A C} \cong \overline{D F}[/tex]

Angle between [tex]$\overline{A B}$[/tex] and [tex]$\overline{A C}$[/tex] exists [tex]$\angle A$[/tex].

Angle between [tex]$\overline{D E}$[/tex] and [tex]$\overline{D F}$[/tex] exists [tex]$\angle D$[/tex].

Therefore, [tex]$\triangle A B C \cong \triangle D E F$[/tex] by SAS, if [tex]$\angle A \cong \angle D$$[/tex].

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Answer:

C...........................

Answer:

11% more people voted for Candidate B than Candidate A

Step-by-step explanation:

15+6=21

9+23=32

32-21=11

Answer:

78000

Step-by-step explanation:

5000/1 times 52/10 times 3)1