Use the graph to determine which is greater, the heat of fusion or the heat of vaporization. Explain how you used the graph to determine that.
(The substance is water)

Answer:

Catenation refers to the ability of an atom to link to other atoms of the same kind to form a chain.

Explanation:

Catenation is the binding of an element to itself through covalent bonds to form chain or ring .Catenation can also be defined as the self-linking of atoms of an element to form chains and rings. This definition can be extended to include the formation of layers like two-dimensional catenation and space lattices like three-dimensional catenation. Thus, we can boldly say that, Catenation occurs when atoms of the same element covalently bond to one another to create a chain or ring.

Catenation occurs most readily in carbon, forming covalent bonds to and longer chains and structures with other carbon atoms. This is why the vast number of organic compounds are found in nature. Carbon is best known for its catenation properties, with the analysis of catenated carbon structures in organic chemistry.

Carbon is by no means the only element capable of forming such catenae, however, and several other main group elements are capable of forming a wide range of catenae, including silicon, sulfur, and boron. In group 14, the high bond energy of carbon makes it able to self-link almost indefinitely when compared with other members of the group which form only a few bonds to other atoms of the same element.

Answer:

- Increase pressure .

Explanation:

Hello,

In this case, during the dissolution process, the solute's molecules rearrange in order to get together with the solvent's molecules, in this case water.

Now, since we are talking about a solid whose particles are intimately held together, the only way to separate them is by increasing the temperature because the molecules start moving so they can join water's molecules, decreasing particle size since they will be more likely to separate to each other and increasing stirring since the applied energy will break the solid's intramolecular forces.

In such a way, since pressure significantly affects gases and slightly affects liquid, it is not able to modify a solid, just extreme pressures such as it needed to produce diamonds, is able to affect a solid. For that reason, increasing the pressure will not increase the solid's solubility.

Best regards.

Answer:

A) An element with the valence electron configuration 5s¹ would form a monatomic ion with a charge of +1. In order to form this ion, the element will lose electron(s) from/into the 5s subshell(s).

B) An element with the valence electron configuration 2s²2p⁴ would form a monatomic ion with a charge of +1. In order to form this ion, the element will lose electron(s) from/into the 2p (2pₓ specifically) subshell(s).

Explanation:

The secret to this task is to follow those rules for the stability of electronic structures of elements. The rules include

- Electrons are filled firstly into shells or subshells of lower energies first.

- While filling electronic structure or writing electronic structures for elements/ions, electrons are fed singly to the suborbital before pairing occurs, this is because the totally paired up electrons of a suborbital are more stable than the totally unpaired electrons of the same suborbital which is now in turn more stable than the combination of paired and unpaired electrons in the suborbitals.

A) For an element with its valence electron on 5s¹, this means that there is one valence electron on this atom's outermost shell and outermost suborbitals. So, to form a monoatomic ion, it would take between losing and gaining an electron. Gaining an electron leads to a 5s², which indicates empty 5p orbitals too and is therefore less stable than losing an electron which would lead to the loss of the shell 5 and focus on a completely filled 4-shell.

So, losing the electron from the 5s suborbital to become a monotonic ion makes it acquire a charge of +1.

B) Just like the explanation in (A), to form a monoatomic ion would require a loss or gain of an electron. With valence electrons 2s²2p⁴, gaining an electron would have led to a 2s²2p⁵ and a further breakdown as 2s²2pₓ²2pᵧ²2pz¹ which has unpaired and paired electrons in the 2p suborbital. This is evidently less stable than if an electron was lost, the valence electrons are 2s²2p³ and they are positioned in a totally unpaired fashion in the 2p suborbital as 2s²2pₓ¹2pᵧ¹2pz¹.

Hence, the more stable alternative is more likely to occur and the electron is lost from the 2pₓ suborbital to make the monoatomic ion of the element acquire a +1 charge status too because of lost electron too.

Hope this Helps!!!

The octet rule states that the atoms of the elements bond to each other in an attempt to complete their valence shell with eight electrons. In other words, the atoms will tend to give up or share electrons to complete eight electrons in the valence shell through an ionic, covalent or metallic bond.

In other words, the goal is to have the closest noble gas electron configuration, thus having the last complete electron shell and acquiring stability.

So, in this case, to comply with the octet rule:

A. An element with the valence electron configuration 5s¹ would form a monatomic ion with a charge of +1. In order to form this ion, the element will lose one electron from the 5s subshell.

For an element with its valence electron at 5s¹, this means that there is one valence electron in the outermost shell of this atom and in the outermost suborbitals. To form a monatomic ion, it would be necessary between losing or gaining an electron and that ion is stable. It takes less energy to lose the electron of the suborbital 5s and acquire a charge of of +1, than to acquire an electron, because it forms the 5s² suborbital, which indicates empty 5p orbitals too and is therefore less stable.

Also, in this way, the octet rule is fulfilled.

B. An element with the valence electron configuration 2s²2p⁴ would form a monatomic ion with a charge of -2. In order to form this ion, the element will gain two electron into the 2p subshell(s).

After gain two electron the atom has eight electrons in its valence shell, giving it the same electronic configuration as a noble gas (2s²2p⁶). In this way, the octet rule is fulfilled and the ion is stable.

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Answer:

If you have 67.31 g of CH₄, you have 4.21 moles

Explanation:

To know the amount of moles if you have 67.31 g of CH₄, you must know the molar mass, that is, the mass of one mole of a substance, which can be an element or a compound.

On the periodic table, the molar mass of the elements, also called the atomic mass or atomic weight, can be found at the bottom of the element. In this case:

To calculate the molar mass of a compound, the molar mass of the elements of the compound must be added multiplied by the times they appear. So in this case the molar mass of CH₄ is:  

CH₄= 12 g/mole + 4* 1 g/mole= 16 g/mole

Now you can apply the following rule of three: if 16 g are contained in 1 mole of CH4, 67.31 g in how many moles are present?

[tex]moles=\frac{67.31 g*1 mole}{16 g}[/tex]

moles= 4.21

If you have 67.31 g of CH₄, you have 4.21 moles

Answer:

q1..no.2 and 4 are aromatic

Answer:

46.07 g/mol is the molar mass of ethonal

Answer:

A: 94

B: 36

C: Kr

Explanation:

Got them right & hope it helps :)

Answer:

A:  94

B:  36

C:  Kr

Explanation:

edg2020

Answer:

[tex]M=1.1M[/tex]

Explanation:

Hello,

In this case, since we are mixing two NaOH solutions, the first step is to compute the total moles once the mixing is done, by using the volumes and concentrations of each solutions and subsequently adding them:

[tex]n_T=2.0L*0.60\frac{mol}{L}+495mL*\frac{1L}{1000mL}*3.0\frac{mol}{L}= 2.7molNaOH[/tex]

Next, we compute the total volume by adding the volume of each solution:

[tex]V_T=2.0L+495mL*\frac{1L}{1000mL}= 2.495L[/tex]

Finally, we compute the molarity of the resulting solution by the division between the total moles and the total volume:

[tex]M=\frac{2.7mol}{2.495L}\\ \\M=1.1M[/tex]

Best regards.

In this reaction, chlorine is losing electrons and being oxidized. Therefore, option A is correct.

The elementary electric charge of the electron is a negative one, making it a subatomic particle. Due to their lack of components or substructure, electrons, which are part of the lepton particle family's first generation, are typically regarded to be elementary particles.

Quarks make up protons and neutrons, but not electrons. We believe that quarks and electrons are fundamental particles that are not composed of lesser subatomic particles. Saying that everything is formed of particles is one thing.

An electron's energy is determined by where it is in relation to the atom's nucleus. The distance an electron in an atom has to travel from the nucleus depends on its energy level.

Thus, option A is correct.

To learn more about an electron, follow the link;

https://brainly.com/question/1255220

#SPJ6

Answer:

Explanation:

Option A - chlorine is losing electrons and being oxidized.

Answer: 351.19K

Explanation: This is a case were the combined gas equation can be applied.

Combined gas equation is given as; P1V1/T1  = P2V2/T2,

where P1 = Initial pressure = 2.50 atm

          P2=  Final pressure = 7.50 atm

          V1 = Initial volume = 3.50L

          V2 = Final Volume =  1.50L

          T1 =  Initial Temperature = 273.15K

          T2 =  Final Temperature =  ?

∴  2.50atm  x  3.50L  /  273.15K   =  7.50atm  x  1.50L /  T2

   Making T2 the subject of  Formular; we then have;

   T2 =  P2 V2 T1 / P1 V1   =  7.50atm  x  1.50L x 273.15K /  2.50atm  x  3.50L

        =   3072.94 / 8.75 = 351.19K

The change in temperature (T2) is 351.19K.

Answer:

Check the explanation

Explanation:

Sample volume V= 10 mL/min x 17 h x 60 min/h / 1000 mL/L = 10.2 L

The concentration is increased

             10200 mL (sample volum) / 10 mL (eluted sample) = 1020 times.

57x10-9 M / 1020 = 5.6x10-12 M    

1.5 M HNO3 will contain ≤ 2ppm x (1.5M/15.7M ) ≤ 0.190 ppm ≤ 190 ppb

Ignoring this is reagent impurity and calculating for sea water

≤ 190 ppb /1020 = 0.186 ppb = 0.186 x 10-9g/mL = 0.186 x 10-6g/L =

0.186 x 10-6g/L / 56 g/mol = 0.003 x10-6 M = 3 nM

Answer:

Explanation:

The boiling point of water is 100 °C or 212 °F at 1 atmosphere of pressure (sea level).

Answer:

The answer is 2

Explanation:

The equation that represent the conservation of charge is Option 2.

The following information should be considered:

Learn more; https://brainly.com/question/11833983?referrer=searchResults

Answer:

A. Buffer strips

Explanation:

The practice that could help reduce erosion of water banks is buffer strips.

Erosion is the action of surface processes that removes soil, rock or dissolved material from one location on the Earth's crust, and then transports it to another location where it is deposited.

One of the practices that could be used to reduce the effect of erosion is buffer strips.

What buffer strips do is slow and filter storm runoff while helping to hold soil in place.

Learn more on buffer strips here; https://brainly.com/question/26872640

Answer:

Liquid A.

Explanation:

Specific heat is defined as the amount of heat required per unit of mass to raise the temperature by one degree celsius.

When two liquids are heated, the liquid with larger specific heat is the one which is hotter. That is because is required more energy to decrease its temperature by 1°C.

Thus, in the problem, liquid A has the larger specific heat

Answer:

Kindly check the attachment for the diagram representing the cell and showing all necessary components including: anode, cathode, electron flow, cation flow and anion flow.

Explanation:

So, the reaction in the concentration cell is given below as;

Cu2+(1.00 M) → Cu2+(0.0100 M).--(1).

The anode = Cu2+(0.0100 M) because it has lesser Concentration, thus, lesser potential value.

Cathode = Cu2+(1.00 M) because it has higher Concentration, hence higher potential value.

It must be noted that in the digaram depicting the Reaction, the electrons moves from the anode part of the cell to the cathode part of the cell and this is done through an external circuit. The following are the things that happens at each electrode;

At the Anode: in here is where oxidation occurs and Cu^2+ is released into the solution.

At the cathode: in here is where the reduction occur and the Cu^2+ moves in the direction to where the Cu electrode is, thus, causing the deposition of Cu.

Answer:

82.9 mL  

Explanation:

1. Volume of silver

[tex]\begin{array}{rcl}\text{Density}&=& \dfrac{\text{Mass}}{\text{Volume}}\\\\\rho&=& \dfrac{m}{V}\\\\V &=& \dfrac{m}{\rho}\\\\& = & \dfrac{\text{50.0 g}}{\text{10.49 g$\cdot$mL}^{-1}}\\\\& = & \text{4.766 mL}\\\end{array}\\\text{The volume of the silver is $\large \boxed{\textbf{4.766 mL}}$}[/tex]

2. Volume of gold

[tex]\begin{array}{rcl}V& = & \dfrac{\text{50.0 g}}{\text{19.30 g$\cdot$mL}^{-1}}\\\\& = & \text{2.591 mL}\\\end{array}\\\text{The volume of the gold is $\large \boxed{\textbf{2.591 mL}}$}[/tex]

3. Total volume of silver and gold

V = 4.766 mL + 2.591 mL = 7.36 mL

4 New reading of water level

V = 75.5 mL + 7.36 mL = 82.9 mL

Answer:

In a chemical reaction, reactants contact each other, bonds between atoms in the reactants are broken, and atoms rearrange and form new bonds to make the products.

Explanation:

Answer:

$95

Explanation:

.75 x 120 = 90

90+5 = 95

Answer:

The similarities are the groups, triads law is a law where they are in groups or three, the octaves law is the 'best' law, is the one who every atom wants, they do everything to be in groups of eight.

Explanation:

Answer:

see explaination

Explanation:

Case 1) When we consider vapor pressure of H2O;

Let the pressure is 1 atm OR 760 torr.

As H2 is collected over water, we have to consider the vapor pressure of H2O as well.

Using data i.e. vapor pressure of H2O at 40° C = 55.365 torr

So, pressure of H2 = P = 760 - 55.365 = 704.635 torr = 704.635/760 = 0.9272 atm

Volume of H2 = 80 ml = 0.08 liter

Temperature (T) = 40 + 273 = 313 K

Gas constant (R) = 0.0821 L atm/mol K

Let n is moles of H2. Applying ideal gas equation;

PV = nRT

n = PV/RT = 0.9272 * 0.08 / 0.0821 * 313

n = 0.00289 moles

Mass of H2 = moles * molar mass = 0.00289 * 2.016 = 0.00582 grams

OR 5.8*10^-3 grams ...Answer

----> Case 2) When we don't consider vapor pressure;

Pressure of H2 = 1 atm, all other parameters will remain same as in case 1.

So, mass of H2 = 6.3*10^-3 grams

But Case 1) is correct approach as in question it is mentioned that H2 is collected over water.

Answer:

32.4 L

Explanation:

Note 1:

The Standard Temperature and Pressure (STP) is  defined by IUPAC as air at 0 gradius Celcius and 1 bar.

Note 2:

The Ideal Gas Law is used for solving this problem.

......

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

Answer:

The answer you are looking for is A

Answer:

Explanation:

Total mole of gases = 7.8 + 2.1 + .09 + .01 = 10

the partial pressures of the gases in a mixture

= mole fraction x Total pressure

mole fraction = mole of a gas in the mixture  / total mole

partial pressure of Ng = [tex]\frac{7.8}{10} \times 101.3 kPa[/tex]

= 79.014 kPa

partial pressure of O = [tex]\frac{2.1}{10} \times 101.3 kPa[/tex]

= 21.273 kPa .

partial pressure of  Ar = [tex]\frac{.09}{10} \times 101.3 kPa[/tex]

= .9117 kPa .

partial pressure of  Co = [tex]\frac{.01}{10} \times 101.3 kPa[/tex]

= .1013 k Pa .

Answer:

THE NEW VOLUME OF THE NITROGEN GAS AT 500 mmHg IS 20 L

Explanation:

We will solve the question by using the Boyle's law equation;

P1V1 = P2V2

Write out the values of the variables involved in the question

P1 = 1000 mmHg

V1 = 10 L

P2 = 500 mmHg

V2 = ?

Substitute the values into the equation, we have;

V2 = PIV1 / P2

V2 = 1000 * 10 / 500

V2 = 10000 /500

V2 = 20 L

The new volume of the nitrogen gas at a pressure of 500 mmHg is 20 L.

Answer:

True

Explanation:

Burning waste can lead to air pollution and release of greenhouse gases. Carbon dioxide is one of those gases.

Answer:

C

Explanation:

Answer:

I think its q

Explanation:

h is the Planck constant, c the speed of light