use the substitution method to find the value of y in the given system of equations y=2x+5 x+y=4

Answer:

52 miles per hour

Step-by-step explanation:

I think you're missing some info, so this is all I can help with right now

Answer:

I am in 5 classso i did not known answer

Answer:

Yes by AAA

Step-by-step explanation:

Angle A is the same for both triangles. Angle D is congruent to Angle A since BC and DE are parallel lines and same with angle E. So by AAA the triangles are similar

Answer:

a.) 5¹⁰

b.) 6¹⁷

Step-by-step explanation:

a.) 5⁸ × 25

Write 25 in the exponential form with the base of 5.

To calculate product use exponent rule

b.) 6¹⁵ × 36

Similarly, 6¹⁵ × 36

Write 25 in the exponential form with the base of 6.

To calculate product use exponent rule.

Answer:

[tex] \displaystyle {5}^{10} [/tex]

[tex] \displaystyle {6}^{17} [/tex]

Step-by-step explanation:

we want to rewrite the following expression as an exponent

[tex] \displaystyle {5}^{8} \times {25}[/tex]

remember that 25 is the square of 5 therefore

[tex] \displaystyle {5}^{8} \times {5}^{2} [/tex]

recall that,

[tex] \displaystyle {x}^{m} \times {x}^{n} = {x}^{m + n} [/tex]

with that law we obtain:

[tex] \displaystyle {5}^{8 + 2} [/tex]

simplify addition:

[tex] \displaystyle {5}^{10} [/tex]

likewise Question-1 36 is the square of 6 Thus,

[tex] \displaystyle {6}^{15} \times {6}^{2} [/tex]

similarly apply law of exponent:

[tex] \displaystyle {6}^{15 + 2} [/tex]

simplify addition:

[tex] \displaystyle {6}^{17} [/tex]

hence,

we have written the expression as an exponent

Answer:

3m-8n

Step-by-step explanation:

Set up an equation:

(5m-3n)-(2m+5n) = ?

Solve:

   5m-3n

-  2m+5n

   3m-8n

Hope this helps!

Answer:

50 km/hr

Step-by-step explanation:

speed = x + 75

distance = 250km

time = 2

250 = (x + 75) * 2

125 = x + 75

x = 50

Answer:

B=-5

Step-by-step explanation:

Slope=rise/run

The line passes in

P1(-1,3)

and

P2(0,-2)

So slope=(3-(-2))/(-1-0)=5/-1=-5

Answer:

x = 70     y = 140

Step-by-step explanation:

Apologies if I get any names of vocabulary terms wrong, I never pay much attention to the names.

The central angle measure of an arc is the same as the arc's measure. In this case, y is the central angle and 140 is the arc's measure, so y = 140.

The inscribed angle measure of an arc is 1/2 the arc's measure. An inscribed angle lies on the circle. So 140/2 = 70 = x.

Step-by-step explanation:

a) k = 1

b) geometric progression formula:

Tn = ar^(n-1)

first term, a = 3/2

Answer:

The bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.

Step-by-step explanation:

We are given that

Mean, [tex]\mu=8.04 g[/tex]

Standard deviation, [tex]\sigma=0.08g[/tex]

We have to find the two weights that separate the top 3% and the bottom 3%.

Let x be the weight of  machine components

[tex]P(X<x_1)=0.03, P(X>x_2)=0.03[/tex]

[tex]P(X<x_1)=P(Z<\frac{x_1-8.04}{0.08})[/tex]

=0.03

From z- table we get

[tex]P(Z<-1.88)=0.03, P(Z>1.88)=0.03[/tex]

Therefore, we get

[tex]\frac{x_1-8.04}{0.08}=-1.88[/tex]

[tex]x_1-8.04=-1.88\times 0.08[/tex]

[tex]x_1=-1.88\times 0.08+8.04[/tex]

[tex]x_1=7.8896[/tex]

[tex]\frac{x_2-8.04}{0.08}=1.88[/tex]

[tex]x_2=1.88\times 0.08+8.04[/tex]

[tex]x_2=8.1904[/tex]

Hence, the bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.

ST = ST (Common)

RT = TQ (Given)

∠ RTS = ∠ SQT (Both 90°)

So, ∆ RTS ≅ ∆ QTS (By SAS congruency rule)

So, RS = QS (By C.P.C.T.)

=> 2x + 8 = 8x - 4

=> 8 + 4 = 8x - 2x

=> 12 = 6x

=> 12/6 = x

=> 2 = x

SR = 2x + 8 (Given)

=> SR = 2(2) + 8 (Putting the value of x)

=> SR = 4 + 8

=> SR = 12

Answer:

Step-by-step explanation:

Hi there!  

»»————-　★　————-««

I believe your answer is:  

520 students.

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

60% of the 1300 students passed. This means that 40% of the students failed.

⸻⸻⸻⸻

[tex]1300 * 0.4= 520[/tex]

⸻⸻⸻⸻

520 students failed school.

⸻⸻⸻⸻

[tex]\boxed{\text{Another way to find this...}}\\\\\text{Take 60}\% \text{ of 1300:}\\\\1300 * 0.6 = 780\\\\\text{780 students passed school.}\\\\\text{Subtract 780 from 1300:}\\\\1300 - 780 = \boxed{520}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

8

Step-by-step explanation:

[tex] \frac{23}{2} = 11.5[/tex]

[tex]92 \div 11.5 = 8[/tex]

Your answer is 2.98004491789381.

Answer:

D

Step-by-step explanation:

First find h(3)

2(3)-2= 4

then find g(4)

4³-5= 59

Answer:

Step-by-step explanation:

radius of base=8/2=4 ft

l²=4²+9²=16+81=97

l=√97 ft

Step-by-step explanation:

Hello,

Let's say a the  first term and r the ratio  of the G.P.

[tex]u_1=a=81\\u_2=a*r\\u_3=a*r^2\\u_4=a*r^3\\\\\dfrac{u_4}{u_1} =\dfrac{a*r^3}{a} =r^3=\dfrac{24}{81} =\dfrac{8}{27} \\\\r=\sqrt[3]{\dfrac{8}{27} } \\\\\boxed{r=\dfrac{2}{3}}\\[/tex]

Answer:

[tex]{\dag{\underline{{\sf{\red{t {}^{2} = \: \dfrac{4.05}{5} \: = 0.81 \: , \: \: t = 0.9s}}}}}}[/tex]

Given:

The matrix is:

[tex]A=\begin{bmatrix}\cos x&-\sin x\\\sin x&\cos x\end{bmatrix}[/tex]

To show:

[tex](A^{-1})^{-1}=A[/tex]

Solution:

If a matrix is:

[tex]M=\begin{bmatrix}a&b\\c&d\end{bmatrix}[/tex]

Then,

[tex]M^{-1}=\dfrac{1}{ad-bc}\begin{bmatrix}d&-b\\-c&a\end{bmatrix}[/tex]

We have,

[tex]A=\begin{bmatrix}\cos x&-\sin x\\\sin x&\cos x\end{bmatrix}[/tex]

Using the above formula, we get

[tex]A^{-1}=\dfrac{1}{(\cos x)(\cos x)-(-\sin x)(\sin x)}\begin{bmatrix}\cos x&\sin x\\-\sin x&\cos x\end{bmatrix}[/tex]

[tex]A^{-1}=\dfrac{1}{\cos^2x+\sin^2x}\begin{bmatrix}\cos x&\sin x\\-\sin x&\cos x\end{bmatrix}[/tex]

[tex]A^{-1}=\dfrac{1}{1}\begin{bmatrix}\cos x&\sin x\\-\sin x&\cos x\end{bmatrix}[/tex]

[tex]A^{-1}=\begin{bmatrix}\cos x&\sin x\\-\sin x&\cos x\end{bmatrix}[/tex]

Now, the inverse of [tex]A^{-1}[/tex] is:

[tex](A^{-1})^{-1}=\dfrac{1}{(\cos x)(\cos x)-(\sin x)(-\sin x)}\begin{bmatrix}\cos x&-\sin x\\\sin x&\cos x\end{bmatrix}[/tex]

[tex](A^{-1})^{-1}=\dfrac{1}{\cos^2x+\sin^2x}\begin{bmatrix}\cos x&-\sin x\\\sin x&\cos x\end{bmatrix}[/tex]

[tex](A^{-1})^{-1}=\dfrac{1}{1}A[/tex]

[tex](A^{-1})^{-1}=A[/tex]

Hence proved.

Answer: 70

Step-by-step explanation:

We are required to calculate the total distance Cecilia travelled in 5 days

The total distance Cecilia travelled for 5 days is 99 kilometers

Day 1 = 27 kilometers

Day 2 to day 5 = 2/3 of 27

= 2/3 × 27

= 2 × 9

= 18 kilometers each day

Total distance = day 1 + day 2 + day 3 + day 4 + day 5

= (27 + 18 + 18 + 18 + 18) kilometers

= 99 kilometers

Therefore, the total distance Cecilia travelled for 5 days = 99 kilometers

Read more:

https://brainly.com/question/17207658

Answer:

4

Step-by-step explanation:

[tex] \frac{p - 1}{p} = 4[/tex]

Solve for p.

The numerator. difference has to be 4 times the answer of the denomiator.

So we can say

[tex]p - 1 = 4p[/tex]

Solve for p

[tex] - 1 = 3p[/tex]

[tex]p = - \frac{1}{3} [/tex]

Now plug this in for the other formula.

[tex]( \frac{ - \frac{1}{3} +1}{ \frac{1}{3} } ) {}^{2} = 2 {}^{2} = 4[/tex]

So

============================================================

Explanation:

I'm assuming that segments AD and CD are tangents to the circle.

We'll need to add a point E at the center of the circle. Inscribed angle ABC subtends the minor arc AC, and this minor arc has the central angle AEC.

By the inscribed angle theorem, inscribed angle ABC = 50 doubles to 2*50 = 100 which is the measure of arc AC and also central angle AEC.

----------------------------

Focus on quadrilateral DAEC. In other words, ignore point B and any segments connected to this point.

Since AD and CD are tangents, this makes the radii EA and EC to be perpendicular to the tangent segments. So angles A and C are 90 degrees each for quadrilateral DAEC.

We just found angle AEC = 100 at the conclusion of the last section. So this is angle E of quadrilateral DAEC.

---------------------------

Here's what we have so far for quadrilateral DAEC

Now we'll use the idea that all four angles of any quadrilateral always add to 360 degrees

A+E+C+D = 360

90+100+90+D = 360

D+280 = 360

D = 360-280

D = 80

Or a shortcut you can take is to realize that angles E and D are supplementary

E+D = 180

100+D = 180

D = 180-100

D = 80

This only works if AD and CD are tangents.

Side note: you can use the hypotenuse leg (HL) theorem to prove that triangle EAD is congruent to triangle ECD; consequently it means that AD = CD.

Answer:

your y-intercept is 5 and your slope is 1 hope this helps with translating into the form you want

Step-by-step explanation:

Step-by-step explanation:

C

im not sure of my answer. hope to help

Answer:

3

Step-by-step explanation:

Answer:

C) 3 times the sq root of 3

Step-by-step explanation:

In a right angle triangle, the COS is definned as the ajacent side over the hypotenuse. So

COS 60 = JK/JL

COS 60 = JK/(6*sq root 3)

.5 = JK/(6*3**1/2)

JK = .5 *(6*3**1/2)

JK = 3*3**1/2

Answer:

Missing angle A = 56.1° (approximately)

Step-by-step explanation:

<A = arcsin(a×sin(C)/c)

= arcsin(5×sin 95/6)

= 56.1154084° ≈ 56.1°

Answered by GAUTHMATH

Answer

Step-by-step explanation:

y = -2x + 0

Therefore; y = -2x

Answer:

Step-by-step explanation:

m∠2 =  [tex]\frac{1}{2}[/tex](55+41)

m∠2 =   [tex]\frac{1}{2}[/tex](96)

m∠2 =48°

m∠1 = 180-48 = 132°