Using plane K, name a point that is not on the line.

From the information given, F(x) = 9.3319419 or approximately 9. This is  problem relating to math functions

Recall that we are given x to be = 16.1

Hence,

[tex]f\left(x\right)=\ 2x^{\frac{1}{4}}\ +\ 3x^{\frac{1}{2}}[/tex] =

2 (16.1) ⁰°²⁵ + 3 (16.1)⁰°⁵

= 32.2⁰°²⁵ + 48.3⁰°⁵

= 2.3821218 +6.9498201

f(x) = 9.3319419

f(x) approximately 9

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Answer:

.8849   or   88.49% have score ess than 123

Step-by-step explanation:

Answer:

88.49 %  have less than 123   (or .8849)

Step-by-step explanation:

123 is    18/15 = 1.2   S.D. ABOVE the mean    z-score +1.2

   from z- score table    +1.2    this is .8849   or 88.49 %

The adjusting entry to registering the Rent revenue shall be as pursues:

Unearned Rent Revenue Debit $6,000

Rent Revenue         Credit      $6,000

(being the adjustment made for Rent Revenue earned)

Adjusting entry to record the Rent Revenue are as follows:

It exists shown that on November 1, the company rented space to another tenant. A check in the amount of $9,000, symbolizing three months' rent in advance, stood obtained from the tenant on that date. The payment stood registered with a credit to the unearned rent revenue account.

Now on December 31, we must organize the adjusting access to record the Rent Revenue for the period (Nov. 1 to Dec. 31) which exists for two months. The Rent Revenue for two months shall be

9000 [tex]*[/tex] 2/3 = $6,000

Therefore the adjusting entry to registering the Rent revenue shall be as pursues:

Unearned Rent Revenue Debit $6,000

Rent Revenue         Credit      $6,000

(being the adjustment made for Rent Revenue earned)

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The complete question is:

On November 1, the company rented space to another tenant. A check for $9,000, representing three months' rent in advance, was received from the tenant on that date. The payment was recorded with a credit to the unearned rent revenue account. Complete the necessary adjusting entry for December 31 by selecting the account names and dollar amounts from the drop-down menus.

Using the monthly payment formula, we have that:

It is given by:

[tex]A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}[/tex]

In which:

The down payment is 20% of $175,000, hence:

D = 0.2 x 175,000 = $35,000.

Hence the parameters are:

P = 175,000 - 35,000 = 140,000, r/12 = 0.055/12 = 0.004583, n = 30 x 12 = 360.

Then the monthly payment is found as follows:

[tex]A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}[/tex]

[tex]A = 140,000\frac{0.004583(1.004583)^{360}}{(1.004583)^{360} - 1}[/tex]

A = $795.87.

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Answer:i am not sure

Step-by-step explanation:

This question is very hard to answer

Answer: I think your brain needs cheese but..............................................

Step-by-step explanation:

Don't know

Answer:

23370 students live with in 500 miles of the university.

Step-by-step explanation:

large university students =24000

selected students = 750

surveyed students =120 lives far away from university.

students live with in 500mile=?

750-120=630

24000-630=23370

Answer:

See image

Step-by-step explanation:

It cant be wrong

Answer:

  34

Step-by-step explanation:

You want the value of |m² +n²| for m = -5 and n = 3.

Put the values where the variables are in the expression and do the arithmetic.

  |m² +n²| = |(-5)² +3²| = |25 +9| = |34| = 34

The value of the expression is 34.

__

Additional comment

Here, the absolute value bars don't do anything, because the value between them is positive. If it were negative, they would remove the minus sign.

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Answer:

in case you don't understand feel free to ask bye.

The standard form of the equation whose graph is the line through (1, -2) and (-5, 6) is 3y = -4x -2.

According to the question,

The standard form of the equation whose graph is the line through (1, -2) and (-5, 6). Now first to find slope of the equation using below formula,

Slope of the equation (m)= (change in y axis) / (change in x axis)

= (6- (-2))/(-5 - 1)

= 8/-6

=-(4/3)

Slope of the equation (m) = -4/3. whose graph is the line through (1, -2) and (-5, 6).Formula to find Standard form of the equation is y = mx + c.

-2 = -(4/3) 1 + c

c = -2 +(4/3)

c = -2/3

The standard form of the equation whose graph is the line through (1, -2) and (-5, 6) is 3y = -4x -2. y = -(4/3)x -(2/3).

⇒  3y = -4x -2.

Hence, the standard form of the equation whose graph is the line through (1, -2) and (-5, 6) is 3y = -4x -2.

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Because the parabola intercepts the x-axis only once, we conclude that the discriminant is 0.

For a quadratic equation:

y = a*x^2 + b*x + c

The discriminant is:

D = b^2 - 4ac

In the graph we can see that the parabola intercepts the x-axis in its vertex, then the parabola has only one real zero, then we conclude that the discriminant is equal to zero.

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Answer:

Step-by-step explanation:

f(x)=ax³

ax³+2=b(x+1)³

ax³+2=b(x³+3x²+3x+1)

(a-b)x³-3bx²-3bx-b=0

The equivalent expression of  2x√44x - 2√11x  is 2x√11x

An equivalent expression can be find when simplified or factorised.

An expression is a combination of numbers, variables, functions (such as addition, subtraction, multiplication or division etc.)

In other words, an expression or algebraic expression is any mathematical statement which consists of numbers, variables and an arithmetic operation between them.

The expression equivalent to 2x√44x - 2√11x is as follows:

2x√44x - 2√11x

factorise

2x√44x - 2√11x = 2(x√44x - √11x³)

Hence,

2(x√44x - √11x) = 2(x√4 × 11x  - √11x³)

2(x√4 × 11x  - √11x) =  2(2x√11x  - x√11x)

Therefore,

2(2x√11x  - x√11x) = 4x√11x - 2x√11x

4x√11x - 2x√11x = 2x√11x

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Answer:

Solution Given:

To find the simplest form we need to open bracket

-2x²(3x²-2x-6)

-2x²*3x²-2x²*(-2x) -2x²*(-6)\

[tex]-6x^{4}+4x^{3}+12x^2[/tex] is  a required answer.

Using the normal distribution, there is a 0.1587 = 15.87% probability that’s a car picked at random is traveling at more than 100 km/hr.

The z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The mean and the standard deviation are given, respectively, by:

[tex]\mu = 90, \sigma = 10[/tex]

The probability that’s a car picked at random is traveling at more than 100 km/hr is one subtracted by the p-value of Z when X = 100, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{100 - 90}{10}[/tex]

Z = 1

Z = 1 has a p-value of 0.8413.

1 - 0.8413 = 0.1587.

0.1587 = 15.87% probability that’s a car picked at random is traveling at more than 100 km/hr.

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0.03607

Absolute value is the distance of a number from zero. Since distance is always positive, the absolute value is the same number but positive.

Please note, for this problem I have rounded to 5 decimal points because the answer is irrational.

Subtracting

There are 2 different ways to approach this problem. You can either estimate the square root of 5 or plug this question straight into a calculator.

First, we can estimate [tex]\sqrt{5}[/tex] and round to 5 decimal places.

Then, take this value and subtract.

Absolute Value

Now that we have solved the subtraction problem we have to find the absolute value. As stated above, the easiest way to find absolute value is to simply make the number positive. Since the answer is already positive, this is the final answer.

Step-by-step explanation:

pls make did make sense, darling!!

Answer:

100°

Step-by-step explanation:

basically, in this situation, whatever number or angle you're given, and the number diagonally across from it are supposed to add up to 180°.

(i think its called a cyclic quadrilateral, so do with that what you will.)

The two triangles exist congruent if they contain two congruent corresponding sides and their contained angles exist congruent.

Let [tex]$&\overline{A B} \cong \overline{D E} \\[/tex] and [tex]$&\overline{A C} \cong \overline{D F}[/tex]

Angle between [tex]$\overline{A B}$[/tex] and [tex]$\overline{A C}$[/tex] exists [tex]$\angle A$[/tex].

Angle between [tex]$\overline{D E}$[/tex] and [tex]$\overline{D F}$[/tex] exists [tex]$\angle D$[/tex].

Therefore, [tex]$\triangle A B C \cong \triangle D E F$[/tex] by SAS, if [tex]$\angle A \cong \angle D$$[/tex].

Given:

[tex]$&\overline{A B} \cong \overline{D E} \\[/tex] and

[tex]$&\overline{A C} \cong \overline{D F}[/tex]

According to the SAS congruence property, two triangles exist congruent if they contain two congruent corresponding sides and their contained angles exist congruent.

Let [tex]$&\overline{A B} \cong \overline{D E} \\[/tex] and [tex]$&\overline{A C} \cong \overline{D F}[/tex]

Angle between [tex]$\overline{A B}$[/tex] and [tex]$\overline{A C}$[/tex] exists [tex]$\angle A$[/tex].

Angle between [tex]$\overline{D E}$[/tex] and [tex]$\overline{D F}$[/tex] exists [tex]$\angle D$[/tex].

Therefore, [tex]$\triangle A B C \cong \triangle D E F$[/tex] by SAS, if [tex]$\angle A \cong \angle D$$[/tex].

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The proportion of the population exists less than 30 then

(x< 30) = 0.986.

To estimate the z-score using the formula, z = (x - µ)/σ

Where, x be the randomly chosen values = 30

µ be the mean = 31

σ be the standard deviation = 10

Proportion of the population that exists less than 18 = P(x < 30)

Plug in the values into z = (x - µ)/σ, to get z-score.

Substitute the values in the above equation, we get

z = (30 - 31)/10

z = -1/10 = -0.1

Therefore, the value of z = - 0.1.

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[tex]x ^{3} + 5x {}^{2} - 8 r - 20 = 0 \\ x { }^{3} + 5x {}^{2} - 8r - 20(x {}^{3} + 5x {}^{2} ) = 0 - (x {}^{3} + 5x {}^{2} ) \\ - 8r - 20 = - (x {}^{3} + 5x {}^{2} ) \\ \\ - 8r - 20 + 20 = - (x {}^{3 } + 5x {}^{2} ) + 20 \\ \\ - 8r = x {}^{3} - 5x {}^{2} + 20 \\ \\ [/tex]

hope it is helpful

Answer:

hey can you show me the pic because the question doesn't make any sense

Given the above information, it is correct to say Yes, since a sample mean number of eggs of 15.1 eggs or less only occurred twice in simulated values, there is evidence that the true mean number of eggs is less than 16. (Option A)

Recall that the mean (statistically speaking) is a measure of central tendency of a probability distribution along median and mode.

You could also state that it is an expected value. Given that samples of actual value taken from the

Hence, since from 100 samples taken, the number of eggs of 15.1 or less occurred, then the true mean or actual mean is less than 16.

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Answer:

line NM

Step-by-step explanation:

Since planes extend infinitely in all directions, planes intersect at a line, not at a line segment.

The types of study that we have hereare the

2. The question here would be

3. The answer that would be answered here would be

4. The question would be

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The cosine equation of the attached graph is; y = 5 cos [( π/40)(x - (π/2))] + 3

The given parameters are:

Diameter = 10 m

Thus;

Radius; r = 5 m

Time; t = 80 s

Height above the ground, h = 2 m

The above means that:

Amplitude; A = 5 m

Period, T = 80 s

Minimum = 2 m

The cosine function is represented as:

y = a cos [k(x - d)] + c.

where;

A is amplitude

B is cycles from 0 to 2π

period = 2π/k

d is horizontal shift

c is vertical shift (displacement)

Thus;

2π/k = 80

k = 2π/80 = π/40

Where

c = Amplitude - Minimum

c = 5 - 2

c = 3

Shift to the left by π/2 gives;

d = π/2

Thus, the equation of the cosine graph is;

y = 5 cos [( π/40)(x - (π/2))] + 3

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Answer:

arithmetic sequence formula: first term + (n - 1)common difference

9 + (n - 1)-2

9 + -2n + 2

= -2n + 11

Answer: its the 3rd one if im wrong im sorry

:3

Answer:

y = 33

Step-by-step explanation:

Angle y and 33 are alternate interior angles since the figure is a parallelogram and alternate interior angles are equal

y = 33

Answer:

y = 33°

Step-by-step explanation:

The diagonal of the parallelogram (a transversal) intersects two opposite and parallel sides of the parallelogram  

Then

The angles of measures y° and 33° are Alternate interior angles

Then

they are congruent.

In other words , y = 33°