To establish the identity[tex]∑r=0n(r+1)(r+2))(nr)(−1)r+2=n+21,[/tex] we can use the expansion of (1+x)n. First, let's expand (1+x)n using the binomial theorem. The binomial theorem states that (a + b)n = Σk=0n(nk)akbn−k.
In this case, we have (1+x)n, so we can rewrite it as (1+x)n = Σk=0n(nk)1n−kxk. Now, let's consider the terms in the expansion. We have[tex](r+1)(r+2))(nr)(−1)r+2.[/tex]
We can rewrite (r+1)(r+2) as r(r+1) + 2(r+1). This gives us (r(r+1) + 2(r+1))(nr)(−1)r+2. Now, we can substitute this into our expansion of (1+x).
[tex]n: Σr=0n(r+1)(r+2))(nr)(−1)r+2 = Σr=0n[(r(r+1) + 2(r+1))(nr)(−1)r+2](nk)1n−kxk[/tex]
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By explaining the expansion of (1+x)n we can get the answer is ∑r=0n(r+1)(r+2))(nr)(−1)r+2 = n+21.
To establish the identity ∑r=0n(r+1)(r+2))(nr)(−1)r+2=n+21 using the expansion of (1+x)^n, we can follow these steps:
1. Expand (1+x)^n using the binomial theorem:
(1+x)^n = nC0 + nC1x + nC2x^2 + ... + nCrx^r + ... + nCnx^n
2. Notice that the coefficient of x^r in the expansion is nCr, which represents the number of ways to choose r items from a set of n items.
3. We need to find the sum of (r+1)(r+2)nCr(-1)^(r+2) from r=0 to n.
4. Multiply (r+1)(r+2) with nCr and (-1)^(r+2):
(r+1)(r+2)nCr(-1)^(r+2) = (r+1)(r+2)nCr(-1)^r(-1)^2 = -(r+1)(r+2)nCr(-1)^r
5. Rearrange the terms to simplify:
-(r+1)(r+2)nCr(-1)^r = -(r^2+3r+2)nCr(-1)^r = (-1)^r(r^2+3r+2)nCr
6. Now, substitute this expression back into the sum:
∑r=0n(-1)^r(r^2+3r+2)nCr
7. Simplify the expression further:
∑r=0n(-1)^r(r^2+3r+2)nCr = ∑r=0n(r^2+3r+2)nCr(-1)^r
8. Observe that (r^2+3r+2) is the expansion of (r+1)(r+2).
9. Substitute (r+1)(r+2) into the sum:
∑r=0n(r+1)(r+2)nCr(-1)^r = ∑r=0n(r+1)(r+2)nCr(-1)^r
10. Finally, simplify the expression to obtain the desired identity:
∑r=0n(r+1)(r+2)nCr(-1)^r = n+2C2 = (n+2)!/(2!(n-2)!)
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This is a two-part question. The symmetric matrix A=
⎝
⎛
1084
108
852
168
788
180
852
180
−1150
⎠
⎞
has three distinct eigenvalues. (a) Two of the three eigenvalues are 1444 and -1444. Suppose that the third eigenvalue is k. Enter the value of k in the box below. (b) You are given that the symmetric matrix A has throe linearly independent elgenvectors
⎝
⎛
17
6
6
⎠
⎞
.
⎝
⎛
−6
−1
18
⎠
⎞
and
⎝
⎛
6
−18
1
⎠
⎞
with corresponding eigenvalues 1444,−1444 and k. Find an orthogonal matrix Q such that D=Q
T
AQ is a diagonal matrix, where D=
⎝
⎛
1444
0
0
0
−1444
0
0
0
h
⎠
⎞
Enter the matrix Q in the box below.
The matrix Q is: Q = [ [17/19, 6/19, 6/19], [-6/19, -1/19, 18/19], [6/19, -18/19, 1/19] ]
To find the value of the third eigenvalue, we can use the fact that the sum of the eigenvalues of a matrix is equal to the trace of the matrix. In this case, the trace of matrix A is 1084 - 1150 = -66.
Since we already know that two eigenvalues are 1444 and -1444, we can calculate the third eigenvalue as follows:
Third eigenvalue + 1444 + (-1444) = -66
Third eigenvalue = -66 - 1444 + 1444
Third eigenvalue = -66
So the value of the third eigenvalue (k) is -66.
To find the matrix Q, we can use the given eigenvectors. Since eigenvectors are orthogonal, we can create a matrix Q by arranging the eigenvectors as columns and normalizing them.
Normalize each eigenvector by dividing it by its length:
v1 = [17, 6, 6]
v2 = [-6, -1, 18]
v3 = [6, -18, 1]
Normalize v1:
v1_normalized = v1 / ||v1||
v1_normalized = [17/19, 6/19, 6/19]
Normalize v2:
v2_normalized = v2 / ||v2||
v2_normalized = [-6/19, -1/19, 18/19]
Normalize v3:
v3_normalized = v3 / ||v3||
v3_normalized = [6/19, -18/19, 1/19]
Now, matrix Q is formed by arranging the normalized eigenvectors as columns:
Q = [v1_normalized, v2_normalized, v3_normalized]
Substituting the values:
Q = [ [17/19, 6/19, 6/19], [-6/19, -1/19, 18/19], [6/19, -18/19, 1/19] ]
So, the matrix Q is:
Q = [ [17/19, 6/19, 6/19], [-6/19, -1/19, 18/19], [6/19, -18/19, 1/19] ]
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Suppose m is the midpoint of segment fg. use the given information to find the missing measure or value. fm= 8a+1, fg=42, a=?
The missing value of "a" is 2.5.
To find the value of "a", we can use the fact that "m" is the midpoint of segment "fg".
Given that "fm" = 8a + 1 and "fg" = 42, we can set up the equation:
fm = fg / 2
Substituting the given values, we get:
8a + 1 = 42 / 2
Simplifying the right side of the equation, we have:
8a + 1 = 21
To isolate "a", we can subtract 1 from both sides:
8a = 21 - 1
8a = 20
Now, we can solve for "a" by dividing both sides by 8:
a = 20 / 8
a = 2.5
Therefore, the missing value of "a" is 2.5.
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Calculate the directional derivative of f(x,y)=x3y2 in the direction of v=−2i j at the point p=(−1,−2). remember to normalize the direction vector
The directional derivative of [tex]\(f(x, y) = x^3y^2\)[/tex] in the direction of [tex]\(\mathbf{v} = -2\mathbf{i} + \mathbf{j}\) at the point \(P(-1, -2)\) is \(-4\sqrt{5}\)[/tex].
To calculate the directional derivative of the function [tex]\(f(x, y) = x^3y^2\)[/tex] in the direction of [tex]\(\mathbf{v} = -2\mathbf{i} + \mathbf{j}\) at the point \(P(-1, -2)\)[/tex], we need to find the unit vector in the direction of [tex]\(\mathbf{v}\)[/tex] and then the dot product of the gradient of [tex]\(f\)[/tex] with this unit direction vector.
Step 1: Normalize the direction vector [tex]\(\mathbf{v}\)[/tex] to find the unit vector [tex]\(\mathbf{u}\)[/tex]:
The unit vector [tex]\(\mathbf{u}\)[/tex] in the direction of [tex]\(\mathbf{v}\)[/tex] is obtained by dividing [tex]\(\mathbf{v}\)[/tex] by its magnitude:
[tex]\[\mathbf{u}[/tex] = [tex]\frac{\mathbf{v}}{\|\mathbf{v}\|}\][/tex]
The magnitude of [tex]\(\mathbf{v}\)[/tex] is given by:
[tex]\[\|\mathbf{v}\| = \sqrt{(-2)^2 + 1^2} = \sqrt{5}\][/tex]
So, the unit vector [tex]\(\mathbf{u}\)[/tex] is:
[tex]\[\mathbf{u} = \frac{-2\mathbf{i} + \mathbf{j}}{\sqrt{5}}\][/tex]
Step 2: Find the gradient of [tex]\(f(x, y)\)[/tex]:
The gradient of [tex]\(f(x, y)\)[/tex] is a vector whose components are the partial derivatives of [tex]\(f\)[/tex] with respect to x and y:
[tex]\[\nabla f = \left(\frac{\partial f}{\partial x}, \frac{\partial f}{\partial y}\right)\][/tex]
For [tex]\(f(x, y) = x^3y^2\)[/tex], we have:
[tex]\[\frac{\partial f}{\partial x} = 3x^2y^2 \quad \text{and} \quad \frac{\partial f}{\partial y} = 2x^3y\][/tex]
So, the gradient of \(f\) is:
[tex]\[\nabla f = (3x^2y^2, 2x^3y)\][/tex]
Step 3: Calculate the directional derivative:
The directional derivative of \(f\) in the direction of [tex]\(\mathbf{v}\)[/tex] at point \(P(-1, -2)\) is given by the dot product of the gradient of \(f\) with the unit direction vector [tex]\(\mathbf{u}\)[/tex]:
[tex]\[D_{\mathbf{u}}f(-1, -2) = \nabla f \cdot \mathbf{u} = (3x^2y^2, 2x^3y) \cdot \frac{-2\mathbf{i} + \mathbf{j}}{\sqrt{5}}\][/tex]
Now, plug in the coordinates of point \(P(-1, -2)\) into the expression:
[tex]\[D_{\mathbf{u}}f(-1, -2) = (3(-1)^2(-2)^2, 2(-1)^3(-2)) \cdot \frac{-2\mathbf{i} + \mathbf{j}}{\sqrt{5}}\][/tex]
Simplify:
[tex]\[D_{\mathbf{u}}f(-1, -2) = (12, 4) \cdot \frac{-2\mathbf{i} + \mathbf{j}}{\sqrt{5}}\][/tex]
Finally, compute the dot product:
[tex]\[D_{\mathbf{u}}f(-1, -2) = (12 \cdot (-2) + 4 \cdot 1) / \sqrt{5} = (-20) / \sqrt{5} = -4\sqrt{5}\][/tex]
The directional derivative of [tex]\(f(x, y) = x^3y^2\)[/tex] in the direction of [tex]\(\mathbf{v} = -2\mathbf{i} + \mathbf{j}\)[/tex] at the point P(-1, -2)is [tex]\(-4\sqrt{5}\)[/tex].
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For constant coefficient, second order, linear, homogeneous differential equations, we have 6 basic types of solutions: - y=erl with r>0 - y=erl with r<0 - y=tert with r>0 - y=tert with r<0 - y=eαtcos(βt) with α>0 - y=eαtcos(βt) with α<0 (These last two could be sine functions instead.) (a) (6 points) Draw a sketch of each type of solution. Desmos or any graphing calculator can help you here. You can turn in hand drawn sketches or copies images from desmos or another graphing utility. (b) (2 points) For the oscillating solutions, what is the effect of increasing β on your plot? Sketch e−t/2cos(5t) and e−t/2cos(10t) from t=0 to t=50, and comment on the difference
(a) Unfortunately, as a text-based bot, I am unable to draw sketches or include images. However, I can describe the sketches for each type of solution.
1. y = e^rt with r > 0: This solution represents exponential growth. The graph starts at the origin and steadily increases as t increases.
2. y = e^rt with r < 0: This solution represents exponential decay. The graph starts at a positive value and steadily decreases as t increases.
3. y = te^rt with r > 0: This solution represents exponential growth with a linear term. The graph starts at the origin and increases more rapidly than the first type of solution.
(b) Increasing β in the oscillating solutions has the effect of increasing the frequency of the oscillations. In other words, the graph will have more oscillations within a given time period. For example, when comparing the graphs of e^(-t/2)cos(5t) and e^(-t/2)cos(10t) from t = 0 to t = 50, the graph of e^(-t/2)cos(10t) will have twice as many oscillations as the graph of e^(-t/2)cos(5t) within the same time interval.
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The six basic types of solutions for constant coefficient, second-order, linear, homogeneous differential equations have distinct characteristics. Sketching them using a graphing calculator helps visualize their behavior, and increasing β in oscillating solutions leads to higher frequency oscillations.
For constant coefficient, second-order, linear, homogeneous differential equations, we have six basic types of solutions:
1. y = e^rt with r > 0
2. y = e^rt with r < 0
3. y = te^rt with r > 0
4. y = te^rt with r < 0
5. y = e^αtcos(βt) with α > 0
6. y = e^αtcos(βt) with α < 0 (or sine functions)
(a) To sketch each type of solution, you can use Desmos or any graphing calculator. Let's take the first type, y = e^rt with r > 0, as an example. When r is positive, the solution represents exponential growth. The graph will start at (0,1) and rise as t increases.
(b) For the oscillating solutions, increasing β affects the frequency of the oscillations. Let's compare the graphs of e^(-t/2)cos(5t) and e^(-t/2)cos(10t) from t = 0 to t = 50. As β increases from 5 to 10, the oscillations become more frequent. The peaks and troughs occur more rapidly in the second graph compared to the first.
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jacob is a teacher. he made 757575 cookies to give to his students on the first day of school. he gave 222 cookies to each student who showed up for class.
According to the question he gave 222 cookies to each student who showed up for class. Jacob gave cookies to approximately 3415 students on the first day of school.
To solve the problem, we can divide the total number of cookies Jacob made (757575) by the number of cookies given to each student (222).
Number of students = Total number of cookies / Cookies given to each student
Number of students = 757575 / 222
Number of students ≈ 3415
Therefore, Jacob gave cookies to approximately 3415 students on the first day of school.
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Determine the missing items, identifying each item by the appropriate letter. Round your percentages to one decimal place.
The question refers to missing items that need to be determined, identified by appropriate letters, and percentages rounded to one decimal place.
To provide a specific answer to the question, it's necessary to know the context and the specific missing items being referred to. Without that information, it is not possible to identify the missing items and calculate their percentages.
Therefore, without the missing items and their corresponding context, it is not feasible to determine the appropriate letters or calculate the percentages.
It's important to have clear and specific information to address the missing items accurately. By providing the missing items and their context, it would be possible to identify the appropriate letters and calculate the corresponding percentages based on the given data or information.
In summary, the question asks for missing items and their corresponding percentages, but without specific information, it is not possible to determine the appropriate letters or calculate the percentages.
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What would be the opportunity cost of spending $90,000 on advertising but only producing 12,000 units? Potential sales (before advertising) of 12,000 units, Price of $16, Fixed costs of $48,000, Variable costs $8, Advertising $90,000 Assume advertising multiplier is (30,000+ advertising)/30,000
$76,800
$576,000
$192,000
−$191,936
$768,000
The opportunity cost of spending $90,000 on advertising but only producing 12,000 units can be calculated by comparing the benefits of the advertising investment to the potential alternative uses of that money.
First, let's calculate the total cost of producing 12,000 units. Fixed costs amount to $48,000, and variable costs are $8 per unit, resulting in a total cost of $48,000 + ($8 × 12,000) = $144,000.
Next, we need to calculate the potential sales revenue without advertising. With a price of $16 per unit, the potential sales revenue would be $16 × 12,000 = $192,000.
Now, let's calculate the potential sales revenue after advertising. The advertising multiplier is given as (30,000 + advertising) / 30,000. In this case, the multiplier would be (30,000 + 90,000) / 30,000 = 4.
Therefore, the potential sales revenue after advertising would be $192,000 × 4 = $768,000.
The opportunity cost is the difference between the potential sales revenue after advertising ($768,000) and the potential sales revenue without advertising ($192,000), which is $768,000 - $192,000 = $576,000.
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what is the smallest head size before a soldier needs to get a custom-made helmet?round your answer to 2 decimal places
Answer:
The army's helmet supplier regularly stocks helmets that fit male soldiers with head circumferences between 20 and 26 inches. Anyone with a head circumference outside that interval requires a customized helmet order.Step-by-step explanation:
IF IT HELPED UH PLEASE MARK MEH A BRAINLIEST ♡♡let a=2-3j and c=-9-2j
c) polar representation of a
d) polar representation of c
e) a+c*
f) a* (complex conjugate)
g) |a|
h) angle(a)
i) angle(c)
The angle of c, denoted as angle(c), is the angle formed between the positive real axis and the line connecting the origin to c. To find the angle, we can use the arctan function: angle(c) = arctan(-2/(-9)).
c) The polar representation of a is r_a * e^(i * theta_a), where r_a is the modulus (magnitude) of a and theta_a is the argument (angle) of a.
d) The polar representation of c is r_c * e^(i * theta_c), where r_c is the modulus (magnitude) of c and theta_c is the argument (angle) of c.
e) To find the sum of a and the complex conjugate of c (c*), we add the real parts and imaginary parts separately. The sum is (a + c*) = (2 - 3j) + (-9 + 2j) = (-7 - j).
f) The complex conjugate of a (a*) is obtained by changing the sign of the imaginary part. So, a* = 2 + 3j.
g) The modulus (magnitude) of a, denoted as |a|, is the distance of a from the origin in the complex plane. |a| = sqrt((2^2) + (-3^2)) = sqrt(4 + 9) = sqrt(13).
h) The angle of a, denoted as angle(a), is the angle formed between the positive real axis and the line connecting the origin to a. To find the angle, we can use the arctan function: angle(a) = arctan(-3/2).
i) The angle of c, denoted as angle(c), is the angle formed between the positive real axis and the line connecting the origin to c. To find the angle, we can use the arctan function: angle(c) = arctan(-2/(-9)).
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If CR3 (only) fails, is b an unbiased estimator of B,? Choose the best answer.
A• Yes, since the population regression errors still have a normal distribution.
B No, since we needed to assume CR3 to prove that b, is an unbiased estimator of Bi.
C• Yes, since we did not need to assume CR3 to prove that b is an unbiased estimator of Bi. •
D.No, since our sample is no longer representative of the population if the population
regression errors are correlated with each other.
D. No, since our sample is no longer representative of the population if the population regression errors are correlated with each other.
The assumption of classical regression model assumption CR3 (Conditional Homoscedasticity) states that the population regression errors are not correlated with each other. When this assumption fails, it implies that there is a systematic relationship or pattern in the errors that is not accounted for in the model. In such cases, the sample may not be representative of the population, and the estimator b may no longer provide an unbiased estimate of the true parameter B.
When CR3 fails, it suggests that there is a problem with the assumption of independent and identically distributed errors, which is necessary for the unbiasedness of the estimator. If the errors are correlated, it means that the regression model does not capture all the relevant factors or there is some omitted variable bias. In this situation, the estimator b may be biased and not provide an accurate estimate of the true parameter B.
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7
14
21
28
Table 2
10
20
30
40
Which statements about the ratios are true? Check all that apply.
O The ratio 3:5 is less than the ratio 7:10.
The ratio 3:5 is greater than the ratio 7:10.
O The ratio 14:20 is less than the ratio 9:15.
The ratio 14:20 is greater than the ratio 9:15.
The ratios in Table 1 are less than the ratios in Table 2.
The ratios in Table 1 are greater than the ratios in Table 2.
The true statements about the given ratios are:
A: The ratio 3:5 is less than the ratio 7:10.
D: The ratio 14:20 is greater than the ratio 9:15.
E: The ratios in Table 1 are less than the ratios in Table 2.
How to Interpret the ratio?Let us analyze each of the given options:
A: The ratio 3:5 is less than the ratio 7:10.
Now, converting both to decimals gives us:
3:5 = 0.6
7:10 = 0.7
Thus, the statement is true.
B) The ratio 3:5 is greater than the ratio 7:10:
From A above, this statement is false.
C) The ratio 14:20 is less than the ratio 9:15:
Now, converting both to decimals gives us:
14:20 = 0.7
9:15 = 0.6
Thus, the statement is False
D) The ratio 14:20 is greater than the ratio 9:15.
From C above, we can say that this statement is true
E) The ratios in Table 1 are less than the ratios in Table 2.
This statement is true because as seen in the given vallues of both tables, their ratios are lesser in table 1.
F) This statement is false.
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If $10000 is invested in an account with a 3% nominal interest rate, compounded monthly. (a) Find the exact amount in the account after 5 years and after 10 years. (b) Find the approximate amount (rounded to the nearest penny) in the account after 5 years and after 10 years. (c) Write, but do not solve an equation that would determine how long it would take for the account to be worth $20000. (d) Write, but do not solve an equation that would determine how long it would take for the account to be worth $40000.
(a) - The Exact Amount in the Account After Five (5) Years is
10000(1 + 0.03/12)^12 * 5 and After Ten (10) Years is 10000(1 + 0.03/12)^12 * 10
(b) - The Approximate Amount in the Account After Five (5) Years is $11618.37 and After Ten (10) Years is $1348.29
(c) - The Equation to determine how long it would take for the account to be worth $20000 is: 20000 = 10000(1 + 0.03/12)^12t
(d) - The Equation to Determine How long it would take for the Account to be worth $40000 is 40000 = 10000( 1 + 0.03/12)^12t
Step-by-step explanation:
MAKE A PLAN:
Use the FORMULA for COMPOUND INTEREST:
A = P(1 + r/n)^nt
Where "A" is:
Where, A = FINAL AMOUNT
Where, P = PRINCIPAL
Where, r = NOMINAL INTEREST RATE
Where, n = NUMBER of TIMES INTEREST COMPOUNDED PER YEAR
Where, t = NUMBER of YEARS
SOLVE THE PROBLEM:(a) - EXACT AMOUNT after FIVE (5) Years, and TEN (10) YEARS:
(1) - AFTER FIVE (5) YEARS:A = 10000(1 + 0.03/12)^12 * 5
(2) - AFTER TEN (10) YEARS:A = 10000(1 + 0.03/12)^12 * 10
(b) - APPROXIMATE AMOUNT AFTER FIVE (5) YEARS, and TEN (10) YEARS:(1) - After Five (5) Years: ≈A ≈ 11618.37
(2) - After Ten (10) Years:A ≈ 13486.29
(c) - Equation for the Account to be worth 20000:20000 = 10000(1 + 0.03/12)^12t
(d) - Equation for the Account to be worth 40000:40000 = 10000(1 + 0.03)^12t
Draw the conclusion:(d) - The Equation to Determine How long it would take for the Account to be worth $40000 is 40000 = 10000( 1 + 0.03/12)^12t
I hope this helps you!
Suppose you borrowed $16,000 at a rate of 9.0% and must repay it in 4 equal installments at the end of each of the next 4 years. How large would your payments be? Show your calculation 2. Suppose you borrowed $11,000 at a rate of 11.2% and must repay it in 5 equal installments at the end of each of the next 5 years. How much interest would you have to pay in the first year? Show your calculation
1. Using the formula of present value, the amount of the payment is $5000.
2. The interest to be paid in the first year is $1232
How large would the payments be?1. To calculate the size of the payments for the loan of $16,000 at a rate of 9.0% to be repaid in 4 equal installments, we can use the formula for the equal periodic payment amount on an installment loan. The formula is given by:
Payment = Loan Amount / Present Value Factor
Where the Present Value Factor can be calculated using the formula:
Present Value Factor = (1 - (1 + interest rate)^(-number of periods)) / interest rate
Let's calculate the size of the payments:
Interest Rate = 9.0% = 0.09
Number of Periods = 4
Present Value Factor = (1 - (1 + 0.09)⁻⁴) / 0.09
Present Value Factor = 3.2
Payment = $16,000 / 3.2 = $5000
The payment is $5000
Therefore, the size of the payments would be approximately $4,935.77.
2. Let's find the interest of the first payment;
The interest component of the first payment can be calculated as:
Interest = Loan Amount * Interest Rate
Let's calculate the interest payment:
Loan Amount = $11,000
Interest Rate = 11.2% = 0.112
Interest = $11,000 * 0.112
Interest = $1,232
Therefore, the interest to be paid in the first year would be $1,232.
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!50 POINTS! (4 SIMPLE GEOMETRY QUESTIONS)
QUESTIONS BELOW
|
|
\/
Answer:
1 ) 7 < x < 11
2) 1 < x < 5
3) 1 < x < 11
4) 5 < x < 13
Step-by-step explanation:
Triangle inequality theorem : the sum of any two sides is always greater than the third side
Let the unknown side be x nad let the known sides by a and b
We will have three inequalities:
(i) a + b > x
(ii) a + x > b
⇒ x > b - a
This will be negative if b < a
(iii) b + x > a
⇒ x > a - b
This will be negative if a < b
From (ii) and (iii)
if a < b, (b-a) will be positive and x > (b - a)
otherwise x > (a - b)
By combining, we can say that x > |a - b|
So our inequalities will be:
(a + b)> x and x > |a - b|
⇒|a - b| < x < (a + b)
This is the required range
1) a = 9, b = 2
|a - b| < x < (a + b)
⇒ |9 - 2| < x < (9 + 2)
⇒ |7| < x < 11
⇒ 7 < x < 11
2) a = 2, b = 3
|a - b| < x < (a + b)
⇒ |2 - 3| < x < (2 + 3)
⇒ |-1| < x < 5
⇒ 1 < x < 5
3) a = 5, b = 6
|a - b| < x < (a + b)
⇒ |5 - 6| < x < (5 + 6)
⇒ |-1| < x < 11
⇒ 1 < x < 11
4) a = 4, b = 9
|a - b| < x < (a + b)
⇒ |4 - 9| < x < (4 + 9)
⇒ |-5| < x < 13
⇒ 5 < x < 13
47. Find the value of x in the picture below, given minor arc AB = 60° and minor arc DC = 150°.
A 75
B. 135
C. 115
D. 105
E. 110
The measure of the indicated angle, x is 105 degrees
Finding the measure of the indicated angle, x.from the question, we have the following parameters that can be used in our computation:
The circle
The indicated angle is x and it can be calculated using
x = 1/2 * (150 + 60)
When evaluated, we have
x = 105
Hence, the indicated angle is 105 degrees
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you toss a biased coin, where the probability of heads is 70%. your first toss is tails. what is the expected number of flips until you flip the same number of heads and tails
The expected number of flips until you flip the same number of heads and tails is approximately 2.586 flips.
To determine the expected number of flips until you flip the same number of heads and tails, we can analyze the possible outcomes and their probabilities. Let's denote H as heads and T as tails.
In this scenario, we have a biased coin with a 70% probability of landing on heads (H) and a 30% probability of landing on tails (T). Since the first toss is tails, we need to calculate the expected number of flips until we get an equal number of heads and tails.
Let's consider the possible sequences of flips that can lead to an equal number of heads and tails:
HT: This sequence occurs with a probability of 0.3 * 0.7 = 0.21.
HTH: This sequence occurs with a probability of 0.3 * 0.7 * 0.3 = 0.063.
HTHT: This sequence occurs with a probability of 0.3 * 0.7 * 0.3 * 0.7 = 0.0441.
HTHTH: This sequence occurs with a probability of 0.3 * 0.7 * 0.3 * 0.7 * 0.3 = 0.01323.
HTHTHT: This sequence occurs with a probability of 0.3 * 0.7 * 0.3 * 0.7 * 0.3 * 0.7 = 0.009261.
We can observe that each sequence has an equal number of heads and tails, so we need to calculate the expected value by multiplying each sequence's length by its respective probability and summing them up:
Expected value = (2 * 0.21) + (3 * 0.063) + (4 * 0.0441) + (5 * 0.01323) + (6 * 0.009261) = 2.1 + 0.189 + 0.1764 + 0.06615 + 0.055566 = 2.586116.
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We refer to an open connected set D⊂C as a domain of the complex plane, and if F(z) is an analytic function on D we call the set F(D)={F(z):z∈D} the analytic transformation of D by F. (E.g.: if the open unit disk centered at 1 is given as U
1
={z∈C:∣z−1∣<1}, and F(z)=z+i,H(z)=iz, then the analytic transformations F(U
1
) and H(U
1
) are a shift by i of U
1
, and a counterclockwise rotation by 90 degrees - or π/2 radian - around the origin of U
1
, respectively.) a) Consider U
0
={z∈C:∣z∣<1}, and f
1
(z)=
1−z
z+1
. Show that f
1
(z) is a 1-1 (and analytic) function on U
0
, and argue that f
1
, also referred to as a Möbius transformation, transforms U
0
to the right half plane, i.e. f
1
(U
0
)={z∈C:Rez>0}. b) Write the function f(z)=e
−iln{[i(
1−z
z+1
)]
2
1
}
as a composite of 6 analytic functions f(z)=f
6
∘f
5
∘f
4
∘f
3
∘f
2
∘f
1
(z) and show that f transforms U
0
into an annulus f(U
0
). [Hint: Determine in order f
1
(U
0
),f
2
∘f
1
(U
0
),…,f
6
∘f
5
∘f
4
∘f
3
∘f
2
∘f
1
(U
0
).]
The specific expressions for f₂, f₃, f₄, f₅, and f₆ are not provided in the given information. To obtain the final expression for f(z) and determine the transformation of U₀ into an annulus f(U₀), the specific functions f₂, f₃, f₄, f₅, and f₆ need to be known.
a) To show that f₁(z) is a one-to-one (injective) and analytic function on U₀, we can demonstrate that it has a non-zero derivative throughout U₀. The function f₁(z) can be rewritten as:
f₁(z) = (1 - z) / (z + 1)
To find its derivative, we apply the quotient rule:
f₁'(z) = [(1 + z) - (1 - z)] / (z + 1)²
= (2z) / (z + 1)²
The derivative f₁'(z) is non-zero for all z in U₀, indicating that f₁(z) is analytic on U₀.
To prove that f₁(z) is one-to-one, we need to show that if f₁(z₁) = f₁(z₂), then z₁ = z₂. Let's assume f₁(z₁) = f₁(z₂) and proceed with the algebraic manipulation:
(1 - z₁) / (z₁ + 1) = (1 - z₂) / (z₂ + 1)
Cross-multiplying, we have:
(1 - z₁)(z₂ + 1) = (1 - z₂)(z₁ + 1)
Expanding and rearranging, we get:
z₁ - z₂ + z₁z₂ + 1 - z₁ = z₂ - z₁ + z₁z₂ + 1 - z₂
Simplifying, we obtain:
z₁ = z₂
This shows that if f₁(z₁) = f₁(z₂), then z₁ = z₂, proving the one-to-one property of f₁(z).
Now, let's consider the transformation f₁(U₀) and show that it maps U₀ to the right half-plane, i.e., f₁(U₀) = {z ∈ C: Re(z) > 0}.
To determine f₁(U₀), we substitute z = x + yi, where x and y are real numbers, into f₁(z) and analyze the resulting expression:
f₁(z) = (1 - (x + yi)) / ((x + yi) + 1)
= (1 - x - yi) / (x + yi + 1)
= [(1 - x - yi) / (x + 1 + yi)] * [(x + 1 - yi) / (x + 1 - yi)]
= [(1 - x - yi)(x + 1 - yi)] / [(x + 1)² + y²]
Expanding the numerator, we have:
[(1 - x - yi)(x + 1 - yi)] = (1 - x - yi)(x + 1) + (1 - x - yi)(-yi)
= (1 - x)(x + 1) + (1 - x)(-yi) + (-y)(x + 1) + (-y)(-yi)
= (1 - x²) - (xi) - (x + 1)y - y²
= 1 - x² - y² - xi - xy - y
Simplifying the denominator, we get:
[(x + 1)² + y²] = x² + 2x + 1 + y²
Now, the expression for f₁(z) becomes:
f₁(z) = [1 - x² - y² - xi - xy - y] / [x² + 2x + 1 + y²]
To determine the real part of f₁(z), we focus on the terms without the imaginary unit "i":
Re[f₁(z)] = [1 - x² - y² - y] / [x² + 2x + 1 + y²]
To show that Re[f₁(z)] > 0, we observe that the numerator is always positive (1 - x² - y² - y > 0) for z in U₀ because x² + y² < 1. The denominator is also positive (x² + 2x + 1 + y² > 0) for z in U₀. Therefore, Re[f₁(z)] > 0 for all z in U₀, implying that f₁(z) maps U₀ to the right half-plane.
b) Given the function f(z) = e^(-i ln{[(i(1 - z)/(z + 1))^2] / 1}), we can express it as a composition of six analytic functions:
f(z) = f₆∘f₅∘f₄∘f₃∘f₂∘f₁(z)
To determine f₁(U₀), f₂∘f₁(U₀), f₃∘f₂∘f₁(U₀), and so on, we can calculate the successive compositions as follows:
f₁(U₀) = {z ∈ C: Re(f₁(z)) > 0}
f₂∘f₁(U₀) = {z ∈ C: Re(f₂(f₁(z))) > 0}
f₃∘f₂∘f₁(U₀) = {z ∈ C: Re(f₃(f₂(f₁(z)))) > 0}
f₆∘f₅∘f₄∘f₃∘f₂∘f₁(U₀) = f(U₀)
Each successive composition can be determined by applying the respective function to the result of the previous composition.
Note: The specific expressions for f₂, f₃, f₄, f₅, and f₆ are not provided in the given information. To obtain the final expression for f(z) and determine the transformation of U₀ into an annulus f(U₀), the specific functions f₂, f₃, f₄, f₅, and f₆ need to be known.
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A firm producing paper clips has a short run cost function: C(y)=y
3
−15y
2
+300y+1000 Calculate the following: C
v
(y)=TVC
−
y
3
−15y
2
+300y F=TC−TVC=1,000 AC(y)=
y
TL
=
y
1
−15y
2
+300y+1000−15+1000 AVC(y)=
y
TVC
−y
2
−15y+300 AFC(y)=
y
TFC
=
y
1000
MC(y)=
dy
dTC
=y
2
−30y+300 a. At which quantity is the average variable cost minimized? b. at which quantity is the average total cost minimized?
The quantity at which the average variable cost (AVC) and average total cost (ATC) are minimized cannot be determined easily from the given information. Further analysis using numerical methods is necessary to find the specific quantities at which these costs are minimized.
a. To find the quantity at which the average variable cost (AVC) is minimized, we need to take the derivative of AVC(y) with respect to y and set it equal to zero.
AVC(y) = (y^3 - 15y^2 + 300y) / y
Taking the derivative of AVC(y) with respect to y, we get:
dAVC(y) / dy = (3y^2 - 30y + 300 - (y^3 - 15y^2 + 300y)) / y^2
= (3y^2 - 30y + 300 - y^3 + 15y^2 - 300y) / y^2
= (-y^3 + 18y^2 - 330y + 300) / y^2
Setting this equal to zero and solving for y:
-y^3 + 18y^2 - 330y + 300 = 0
Unfortunately, this equation does not have a simple solution. We would need to use numerical methods to find the value of y at which AVC is minimized.
b. To find the quantity at which the average total cost (ATC) is minimized, we need to take the derivative of ATC(y) with respect to y and set it equal to zero.
ATC(y) = (y^3 - 15y^2 + 300y + 1000) / y
Taking the derivative of ATC(y) with respect to y, we get:
dATC(y) / dy = (3y^2 - 30y + 300 - (y^3 - 15y^2 + 300y + 1000)) / y^2
= (3y^2 - 30y + 300 - y^3 + 15y^2 - 300y - 1000) / y^2
= (-y^3 + 18y^2 - 330y - 700) / y^2
Setting this equal to zero and solving for y:
-y^3 + 18y^2 - 330y - 700 = 0
Again, this equation does not have a simple solution and numerical methods would be needed to find the value of y at which ATC is minimized.
Conclusion: The quantity at which the average variable cost (AVC) and average total cost (ATC) are minimized cannot be determined easily from the given information. Further analysis using numerical methods is necessary to find the specific quantities at which these costs are minimized.
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Evaluate \( \int\left(10 \sin x+3 x^{3}\right) d x \). If necessary, use \( c \) as a constant.
The integral of (10 sin(x) + 3x^3) with respect to x is -10 cos(x) + (3/4)x^4 + c.
To evaluate the integral ∫(10 sin(x) + 3x^3) dx, we use the rules of integration. The integral of sin(x) is -cos(x), and the integral of x^n is (1/(n+1))x^(n+1), where n is a constant.
1. For the term 10 sin(x), we integrate term by term. The integral of 10 sin(x) is -10 cos(x). This term gives us the antiderivative of the sine function.
2. For the term 3x^3, we apply the power rule of integration. The power rule states that the integral of x^n dx is (1/(n+1))x^(n+1). In this case, n = 3, so the integral of 3x^3 is (3/4)x^4.
3. Combining the integrals of the two terms, we have -10 cos(x) + (3/4)x^4. These are the antiderivatives of the given terms.
4. Since integration involves finding antiderivatives, we introduce a constant of integration, represented by 'c'. The constant 'c' accounts for the possibility of additional solutions.
Therefore, the final result of the integral is -10 cos(x) + (3/4)x^4 + c, where 'c' represents the constant of integration.
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(4) consider three sheep M1,M2,M3 playing leapfrog. We (4). will place the sheep in a flan and characterize them by their coordinates M1=(x10,y10),M2=(x20,y20),M3=(x30,y30) the rules of the game are as follows: - M1 jump over M2 and the new fosition of the first sheep is the mirrol image of M1 by the center symmetry M2. - M M2 jumps above M3 and the new position of the second sheep is the symmetric of M2 by the centas symmetry M3 - M3 Jumps Above M1 and the new position of the second sheep is the symmetry of M by the symmetry of center M1 (Attention M1 has ofready fumped, the symmetry is therefore made with to its mew Position!). We continue the process by following the previous rustes, we denate by (x1m,y1n),(x2n,y2m) and (x3m,y3n) the coordinates of the shcep M1,M2 and M3 after m iterations. Let xm and ym be the vectors defined by xn=⎝⎛x1mx2mx3m⎠⎞ym=⎝⎛y1my2my3m⎠⎞ 1. Give a link between xn+1 and xn for all n∈N. Same question for ym+1 and ym. 2. Deduce a link between xn and x0. Same question for yn and y0 3. Determine an explicit formula for x1n,x2n and x3n and function of x10,x20 and x30 4. Under what condition(s) on the imitial fositions of M1,M2 and M3 con the sheep fump to infinity in a bounded space of the plane?
The link between xn+1 and xn for all n ∈ N is xn+1 = 2xn - xn-1. The link between yn+1 and yn is yn+1 = 2yn - yn-1. The link between xn and x0 is xn = 2x0 - xn-1. The link between yn and y0 is yn = 2yn - yn-1.
The explicit formula for x1n, x2n, and x3n is as follows:
x1n = 2x10 - x1(n-1)
x2n = 2x20 - x2(n-1)
x3n = 2x30 - x3(n-1)
The sheep can jump to infinity in a bounded space of the plane if and only if the initial positions of M1, M2, and M3 form an equilateral triangle.
The link between xn+1 and xn can be found by considering the symmetry of the leapfrog game. When M1 jumps over M2, the new position of M1 is the mirror image of its previous position with respect to M2. This means that the x-coordinate of M1 will be the same as the x-coordinate of M2, but the y-coordinate will be the negative of the y-coordinate of M2.
The link between yn+1 and yn can be found by considering the symmetry of the leapfrog game. When M2 jumps over M3, the new position of M2 is the mirror image of its previous position with respect to M3. This means that the y-coordinate of M2 will be the same as the y-coordinate of M3, but the x-coordinate will be the negative of the x-coordinate of M3.
The explicit formula for x1n, x2n, and x3n can be found by using the recursive formulas for xn+1 and xn.
The condition for the sheep to jump to infinity in a bounded space of the plane can be found by considering the distance between the sheep. If the initial positions of M1, M2, and M3 form an equilateral triangle, then the distance between the sheep will remain constant. This means that the sheep will continue to jump forever, and they will never reach the boundary of the space.
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- 8 upon 5-[-2 whole 1 upon 4] - 1 upon 2
The simplified expression is -7/20. To simplify the expression -8 upon 5-[-2 whole 1 upon 4] - 1 upon 2.
We need to follow the order of operations (PEMDAS/BODMAS) and simplify each part of the expression step-by-step.
Simplify the inside of the square brackets:
-2 whole 1 upon 4 = -2 + 1/4.
Since -2 is the whole number, we can rewrite it as -2/1. Adding -2/1 and 1/4, we get
-8/4 + 1/4 = -7/4.
Rewrite the expression without the square brackets:
-8 upon 5 - (-7/4) - 1 upon 2.
Simplify the expression inside the parentheses:
-(-7/4) = 7/4.
Rewrite the expression without the parentheses:
-8 upon 5 + 7/4 - 1 upon 2.
Find a common denominator for the fractions:
The common denominator for 5 and 4 is 20.
Rewrite the fractions with the common denominator:
-8/5 + 7/4 - 1/2 = -32/20 + 35/20 - 10/20.
Combine the fractions:
-32/20 + 35/20 - 10/20 = (-32 + 35 - 10)/20 = -7/20.
Therefore, the simplified expression is -7/20.
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Let A=R−{1}, and let f:A→A. Show that f is bijective when defined as f(x)= (x+1)/(x−1) 8. Let A=P(R). Define f:R→A by the formula f(x)={y∈R∣y2
To show that the function f(x) = (x+1)/(x-1) is bijective when defined on A = R - {1}, we need to demonstrate that it is both injective and surjective.
To prove that f(x) is injective, we need to show that if f(a) = f(b), then a = b for any a, b ∈ A.Let's assume f(a) = f(b). Then, we have (a+1)/(a-1) = (b+1)/(b-1). Now, we can cross-multiply to get (a+1)(b-1) = (b+1)(a-1). Expanding both sides, we get ab - a + b - 1 = ba - b + a - 1. Simplifying, we have ab - a + b - 1 = ab - a + b - 1.
Since both sides of the equation are equal, we can conclude that a = b. Therefore, the function f(x) is injective.To prove that f(x) is surjective, we need to show that for every y ∈ A, there exists an x ∈ A such that f(x) = y.
Let y ∈ A. We want to find an x such that f(x) = y.
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Emily purchased a bond valued at $10,000 for highway construction for $5,860. If the bond pays 6.7% annual interest compounded monthly, how long must she hold it until it reaches its full face value? She must hold onto the bond for years (Round to two decimal places as needed.)
To determine how long Emily must hold the bond until it reaches its full face value, we can use the compound interest formula:
A = P(1 + r/n)^(nt)
Where:
A = final amount (face value of the bond)
P = principal amount (purchase price of the bond)
r = annual interest rate (6.7% or 0.067)
n = number of times interest is compounded per year (monthly compounding, so n = 12)
t = time in years
Given that the face value (A) is $10,000 and the purchase price (P) is $5,860, we can substitute these values into the formula:
$10,000 = $5,860(1 + 0.067/12)^(12t)
Next, we can isolate the exponent:
(1 + 0.067/12)^(12t) = $10,000/$5,860
Simplifying the right side of the equation:
(1 + 0.067/12)^(12t) = 1.706
Now, take the natural logarithm of both sides to solve for t:
ln[(1 + 0.067/12)^(12t)] = ln(1.706)
Using the logarithmic property, we can bring down the exponent:
12t * ln(1 + 0.067/12) = ln(1.706)
Divide both sides by 12 * ln(1 + 0.067/12):
t = ln(1.706)/(12 * ln(1 + 0.067/12))
Using a calculator, we find:
t ≈ 12.89 years
Therefore, Emily must hold the bond for approximately 12.89 years until it reaches its full face value.
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Use undetermined coefficients method to find the general solution of the non-homogeneous ODE y
′′
−6y
′
+5y=(5x
2
+3x−16)−9e
2x
+29sin(2x)
To find the general solution of the non-homogeneous ordinary differential equation (ODE) using the undetermined coefficients method, we follow these steps:
Step 1: Solve the associated homogeneous equation:
y'' - 6y' + 5y = 0
The characteristic equation is:
r^2 - 6r + 5 = 0
Factoring the quadratic equation, we get:
(r - 1)(r - 5) = 0
So the homogeneous solution is:
y_h = C1e^x + C2e^5x, where C1 and C2 are constants.
Step 2: Find the particular solution:
We assume the particular solution has the form:
y_p = Ax^2 + Bx + C - De^(2x) + Fsin(2x) + Gcos(2x)
Here, A, B, C, D, F, and G are coefficients that need to be determined.
Step 3: Substitute the particular solution into the non-homogeneous equation:
(y_p)'' - 6(y_p)' + 5y_p = (5x^2 + 3x - 16) - 9e^(2x) + 29sin(2x)
Differentiating and substituting, we get:
2A - 6(2Ax + B) + 5(Ax^2 + Bx + C - De^(2x) + Fsin(2x) + Gcos(2x)) = 5x^2 + 3x - 16 - 9e^(2x) + 29sin(2x)
Step 4: Collect the terms and equate coefficients of like terms:
For the terms with the same powers of x, we get the following equations:
-3A + 5C = -16 (coefficients of x^0)
-6A + 5B = 3 (coefficients of x^1)
2A - 6B + 5A = 5 (coefficients of x^2)
-6A + 5D = -9 (coefficients of e^(2x))
0 = 29 (coefficients of sin(2x))
0 = 0 (coefficients of cos(2x))
Solving these equations, we find the values of A, B, C, D, F, and G.
Step 5: Substitute the values of the coefficients into the particular solution:
y_p = 2x^2 - x - 8 + 3e^(2x) + 29sin(2x)
Step 6: The general solution is the sum of the homogeneous and particular solutions:
y = y_h + y_p = C1e^x + C2e^5x + 2x^2 - x - 8 + 3e^(2x) + 29sin(2x)
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we roll two six-sided dice, one with sides 1, 2, 2, 3, 3, 4 and the other with sides 1, 3, 4, 5, 6, 8. what is the pmf of the sum?
The pmf of the sum when rolling these two dice is as follows:
Sum | Probability
-----|------------
2 | 1/36
3 | 1/18
4 | 1/36
5 | 1/18
6 | 1/18
7 | 1/18
8 | 1/18
9 | 1/18
10 | 1/18
11 | 1/18
12 | 1/36
The pmf (probability mass function) of the sum when rolling two six-sided dice can be calculated by determining the probability of each possible sum.
To find the pmf, we need to consider all the possible outcomes when rolling the two dice. We will calculate the probability for each sum and then normalize the probabilities to add up to 1.
Let's list all the possible sums and their corresponding probabilities:
- The sum can be 2 when both dice show a 1. The probability of this is (1/6) * (1/6) = 1/36.
- The sum can be 3 when one die shows a 1 and the other die shows a 2. There are two possible combinations: (1, 2) and (2, 1). The probability of each combination is (1/6) * (1/6) = 1/36. So, the total probability for a sum of 3 is 2 * (1/36) = 1/18.
- The sum can be 4 when one die shows a 2 and the other die shows a 2. The probability of this is (1/6) * (1/6) = 1/36.
- The sum can be 5 when one die shows a 2 and the other die shows a 3. There are two possible combinations: (2, 3) and (3, 2). The probability of each combination is (1/6) * (1/6) = 1/36. So, the total probability for a sum of 5 is 2 * (1/36) = 1/18.
- The sum can be 6 when one die shows a 2 and the other die shows a 4. There are two possible combinations: (2, 4) and (4, 2). The probability of each combination is (1/6) * (1/6) = 1/36. So, the total probability for a sum of 6 is 2 * (1/36) = 1/18.
- The sum can be 7 when one die shows a 3 and the other die shows a 4. There are two possible combinations: (3, 4) and (4, 3). The probability of each combination is (1/6) * (1/6) = 1/36. So, the total probability for a sum of 7 is 2 * (1/36) = 1/18.
- The sum can be 8 when one die shows a 3 and the other die shows a 5. There are two possible combinations: (3, 5) and (5, 3). The probability of each combination is (1/6) * (1/6) = 1/36. So, the total probability for a sum of 8 is 2 * (1/36) = 1/18.
- The sum can be 9 when one die shows a 3 and the other die shows an 8. There are two possible combinations: (3, 8) and (8, 3). The probability of each combination is (1/6) * (1/6) = 1/36. So, the total probability for a sum of 9 is 2 * (1/36) = 1/18.
- The sum can be 10 when one die shows a 4 and the other die shows a 5. There are two possible combinations: (4, 5) and (5, 4). The probability of each combination is (1/6) * (1/6) = 1/36. So, the total probability for a sum of 10 is 2 * (1/36) = 1/18.
- The sum can be 11 when one die shows a 4 and the other die shows an 8. There are two possible combinations: (4, 8) and (8, 4). The probability of each combination is (1/6) * (1/6) = 1/36. So, the total probability for a sum of 11 is 2 * (1/36) = 1/18.
- The sum can be 12 when one die shows a 8 and the other die shows an 8. The probability of this is (1/6) * (1/6) = 1/36.
Now, let's add up all the probabilities:
(1/36) + (1/18) + (1/36) + (1/18) + (1/18) + (1/18) + (1/18) + (1/18) + (1/18) + (1/18) + (1/36) = 1/2
Therefore, the pmf of the sum when rolling these two dice is as follows:
Sum | Probability
-----|------------
2 | 1/36
3 | 1/18
4 | 1/36
5 | 1/18
6 | 1/18
7 | 1/18
8 | 1/18
9 | 1/18
10 | 1/18
11 | 1/18
12 | 1/36
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Given the function g(x)=2x and the domain {0, 2, 4), what is the range? {0, 1, 2} {2, 4, 8) {1, 2, 3) {0, 4, 8}
According to the question we get the following outputs For x = 0, g(0) = 0 , For x = 2, g(2) = 4 , For x = 4, g(4) = 8. the range of the function g(x) = 2x, with the given domain {0, 2, 4}, is {0, 4, 8}.
The range of the function g(x) = 2x, with the given domain {0, 2, 4}, can be determined by evaluating the function for each value in the domain.
For x = 0: g(0) = 2(0) = 0
For x = 2: g(2) = 2(2) = 4
For x = 4: g(4) = 2(4) = 8
Therefore, the range of the function is {0, 4, 8}.
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Which image below shows the graph of a function
Answer:
Step-by-step explanation:
You need to do a vertical line test. If you draw a vertical line(line going up and down) at all points you can never hit that vertical line more than once for it to be a function.
A. Not a function. Hits at twice at the whole loop
B. Not a function. The 3 dots hit the vertical line at same tiem.
C. Not a function. When x=2 there are 2 dots
D. Yes Function. Passes vertical line test.
Solve the following recurrence in closed form. Show all your work. T(n) = 2T(n − 1) − T(n − 2) + 2 for n ≥ 2 and T(0) = 1, T(1) = 3.
(b) Consider g(n) = n^3 . Is T(n) = O(g(n))? Justify your answer.
Since T(n) does not have a closed form solution, we cannot determine whether T(n) = O(g(n)) without further information or analysis. Therefore, we cannot provide a conclusion about T(n) = O(g(n)) in this case.
To solve the given recurrence relation T(n) = 2T(n - 1) - T(n - 2) + 2, we will first find the characteristic equation.
Assuming T(n) = xⁿ, substituting it into the recurrence relation gives:
x^n = 2xⁿ⁻¹ - xⁿ⁻² + 2.
Dividing through by xⁿ⁻², we get:
x² = 2x - 1 + 2/xⁿ⁻².
Rearranging terms, we have:
x² - 2x + 1 = 2/xⁿ⁻².
Multiplying through by xⁿ⁻², we obtain:
x^(n) - 2xⁿ⁻¹ + xⁿ⁻² = 2.
The characteristic equation is now:
x² - 2x + 1 = 0.
Factoring the equation, we find that:
(x - 1)² = 0.
This means that x = 1 is a repeated root of the characteristic equation.
To find the general solution, we use the form T(n) = (An + B)(1)ⁿ.
Substituting T(0) = 1 and T(1) = 3, we get:
T(0) = (A(0) + B)(1)⁰ = 1, which implies A + B = 1,
T(1) = (A(1) + B)(1)¹ = 3, which implies A + B = 3.
From these equations, we can solve for A and B as follows:
A + B = 1,
A + B = 3.
Subtracting the second equation from the first, we have:
0 = 2.
This implies that the system of equations has no solution. Hence, the recurrence relation T(n) = 2T(n - 1) - T(n - 2) + 2 does not have a closed form solution.
Regarding the second part of your question, T(n) = O(g(n)) if there exist constants c and n0 such that T(n) ≤ c * g(n) for all n ≥ n0.
Let's consider g(n) = n³. We need to determine whether there exist constants c and n0 such that T(n) ≤ c * n³ for all n ≥ n0.
Since T(n) does not have a closed form solution, we cannot determine whether T(n) = O(g(n)) without further information or analysis. Therefore, we cannot provide a conclusion about T(n) = O(g(n)) in this case.
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all students press space to open convenience sampling press space to open snowball sampling press space to open college students press space to open psychology students press space to open simple random sampling
Convenience sampling and snowball sampling are non-probability sampling methods, while simple random sampling is a probability-based method used in research.
Convenience sampling involves selecting participants based on their availability or proximity, leading to a biased sample that may not be representative of the population.
Snowball sampling relies on participants referring others with similar characteristics, potentially leading to a chain of referrals.
College students and psychology students represent specific subgroups within the larger student population and may be targeted for research purposes.
In contrast, simple random sampling involves randomly selecting participants from the entire population, ensuring that each member has an equal chance of being included.
This method provides a more unbiased representation of the population, making it useful for generalization and statistical analysis.
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ulie went to visit her aunt and uncle for the weekend. she took the following clothes: two pairs of slacks – one brown, one black; three sweaters – one tan, one red and one white; two shirts – one white and one gray. what is the probability that julie will wear brown slacks and a white shirt? 23 16 112 14
The probability that Julie will wear brown slacks and a white shirt is 0.25.
To calculate the probability of Julie wearing brown slacks and a white shirt, we need to determine the total number of outfit combinations and the number of desired outcomes.
Julie has 2 options for slacks (brown or black) and 2 options for shirts (white or gray). Therefore, the total number of outfit combinations is 2 (slacks) multiplied by 2 (shirts) which equals 4.
Out of the 4 outfit combinations, Julie desires to wear brown slacks and a white shirt, which is only 1 combination.
To calculate the probability, we divide the number of desired outcomes by the total number of outfit combinations: 1 (desired outcome) divided by 4 (total combinations) equals 1/4.
In fraction form, the probability is 1/4. However, to convert it to decimal form, we divide 1 by 4, resulting in 0.25.
Therefore, the probability that Julie will wear brown slacks and a white shirt is 0.25.
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