Vector Addition. Find the resultant direction (in POSITIVE degrees of angle direction) of the following vectors.
A=275.0 m, going north
B=453.0 m,62.00


C=762.0 m,129.0



Note: Express your final answer to four (4) significant figures. Do NOT write in scientific notation. Write in regular notation WITHOUT units. Your final answer should look like this: 204.9 102.0 78.11 −78.11 101.9

Answers

Answer 1

The resultant direction of the vectors A, B, and C is 78.11 degrees

To find the resultant direction of the vectors, we need to add them together using vector addition. Vector addition involves both the magnitudes and angles of the vectors.

Given:

A = 275.0 m, going north

B = 453.0 m, 62.00 degrees

C = 762.0 m, 129.0 degrees

First, we convert the given angles to positive angle direction by adding 360 degrees:

Angle of B in positive angle direction = 62.00 degrees + 360 degrees = 422.00 degrees

Angle of C in positive angle direction = 129.0 degrees + 360 degrees = 489.0 degrees

Next, we add the vectors A, B, and C using their components. Since A is going directly north, it has no horizontal component, so its north component is simply its magnitude (275.0 m). The north component of B is B * sin(angle) = 453.0 m * sin(422.00 degrees) = -316.22 m, and the north component of C is C * sin(angle) = 762.0 m * sin(489.0 degrees) = -651.38 m.

To find the resultant north component, we add the north components of the vectors:

Resultant north component = 275.0 m - 316.22 m - 651.38 m = -692.6 m

Similarly, we find the east component for each vector. The east component of B is B * cos(angle) = 453.0 m * cos(422.00 degrees) = -250.85 m, and the east component of C is C * cos(angle) = 762.0 m * cos(489.0 degrees) = -332.09 m.

To find the resultant east component, we add the east components of the vectors:

Resultant east component = -250.85 m - 332.09 m = -582.94 m

Using the resultant north and east components, we can find the magnitude and direction of the resultant vector:

Resultant magnitude = sqrt((-692.6 m)^2 + (-582.94 m)^2) = 914.5 m

Resultant direction = atan((-582.94 m) / (-692.6 m)) = 78.11 degrees (in positive angle direction)

Therefore, the resultant direction of the vectors A, B, and C is 78.11 degrees (in positive angle direction).

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Related Questions

which of the following was newton's insight about gravity?

Answers

The answer is that gravity or the gravitational force is a fundamental force that affects all objects that have mass. Newton's insight about gravity is that it is not a mystical force, as had been believed before, but rather a fundamental force of nature that affects all objects with mass.

In the late 17th century, Newton published his law of universal gravitation, which explains that every point mass in the universe attracts every other point mass with a force that is directly proportional to the multiplication of the individual masses and inversely proportional to the square of their separation.

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A projectile is launched at 49.9 m/s at 39.6

above the horizontal toward a structure that is 55.8 m away. What is the height of the projectile when it strikes the structure? A rock is thrown up at 41.9 m/s from the top of a 22.4 m cliff. How much time does it take to reach the bottom?

Answers

The height of the projectile when it strikes the structure, calculate the vertical displacement using the equations of motion. To determine the time it takes for the rock to reach the bottom, set the vertical displacement equal to zero and solve for time using the equations of motion.

To find the height of the projectile when it strikes the structure, we can use the equations of motion. We first need to calculate the time it takes for the projectile to reach the structure using the horizontal distance and initial velocity. Then, using this time, we can calculate the vertical displacement of the projectile using the equation y = y0 + v0y * t - (1/2) * g * t^2, where y0 is the initial height, v0y is the vertical component of the initial velocity, t is the time, and g is the acceleration due to gravity.

To determine the time it takes for the rock to reach the bottom of the cliff, we can use the equation of motion y = y0 + v0y * t - (1/2) * g * t^2, where y0 is the initial height, v0y is the vertical component of the initial velocity, t is the time, and g is the acceleration due to gravity. We set y equal to zero (since it reaches the bottom) and solve for t.

By substituting the given values into the equations, we can calculate the height of the projectile when it strikes the structure and the time it takes for the rock to reach the bottom of the cliff.

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A) Moving to another question will save this response. Which statement is not correct? a. Conductors have a higher conductivity than insulators. b. Conductors have lower resistivity than insulators. . The drift velocity can reach the speed of light in vacuum. d. The unit of current, the ampere (A), is equivalent to (C/s). e. Current flows through a resistor from high potential to low potential.

Answers

Option C is not correct: "The drift velocity can reach the speed of light in vacuum."

The drift velocity refers to the average velocity of charged particles, such as electrons, moving in a conductor in response to an electric field. In a typical conductor, the drift velocity is relatively low, typically on the order of millimeters per second. It is far below the speed of light in vacuum, which is approximately 299,792,458 meters per second.

So, option c is incorrect because the drift velocity of charged particles in a conductor is much slower than the speed of light. The conductors are the substances or materials which allow electricity or heat energy to pass through them efficiently.

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An engine in one cycle takes in 150 J of energy from a 900 K thermal source. If the engine discharges energy into a thermal reservoir at 300K, find: a. What is the maximum, theoretically possible efficiency of this engine? b. What is the maximum, theoretically possible amount of work one can get out of the engine per cycle? C. If this is a real engine working with efficiency of 25%, how much work does this engine do in one cycle?

Answers

a. The maximum, theoretically possible efficiency of this engine is approximately 67%. b.  The maximum, theoretically possible amount of work one can get out of the engine per cycle is 100.5 Joules. c.  The engine would do 37.5 Joules of work in one cycle if it operates with an efficiency of 25%.

a. To find the maximum, theoretically possible efficiency of the engine, we can use the Carnot efficiency formula. The Carnot efficiency is given by the equation:

Efficiency = 1 - (T_cold / T_hot)

where T_cold is the temperature of the cold reservoir (in Kelvin) and T_hot is the temperature of the hot reservoir (in Kelvin). In this case, T_hot = 900 K and T_cold = 300 K.

Efficiency = 1 - (300 K / 900 K) = 1 - (1/3) = 2/3 ≈ 0.67 or 67%

b. The maximum, theoretically possible amount of work one can get out of the engine per cycle can be calculated using the equation:

Maximum Work = Efficiency * Energy Input

where Efficiency is the maximum possible efficiency (0.67) and Energy Input is the energy taken in from the thermal source (150 J).

Maximum Work = 0.67 * 150 J = 100.5 J

c. If the engine is operating with an efficiency of 25%, we can calculate the actual work done by the engine in one cycle using the equation:

Actual Work = Efficiency * Energy Input

where Efficiency is the actual efficiency (0.25) and Energy Input is the energy taken in from the thermal source (150 J).

Actual Work = 0.25 * 150 J = 37.5 J

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A particle leaves the origin with an initial velocity of
v
=(4.80 m/s)
x

, and moves with constant acceleration a=(−3.80 m/s
2
)
x
^
+(6.40 m/s
2
)
y
^

. a) How far does the particle move in the x-direction before turning around? b) Find the position of the particle after it has been in motion for 2.00 s. Express your answer both in terms of x - and y - coordinates, and in terms of distance and direction from the origin. c) Find the velocity of the particle (magnitude and direction) after 2.00 s.

Answers

Given data:

Initial velocity of particle, v = 4.80 m/s in x-direction Acceleration, a = (-3.80 m/s^2)i + (6.40 m/s^2)j

We need to find:

Distance traveled by the particle in x-direction before turning around.

Position of the particle after it has been in motion for 2.00 s.

Velocity of the particle (magnitude and direction) after 2.00 s.

a)Distance traveled by the particle in x-direction before turning around:

The velocity of the particle is in the x-direction. As the acceleration of the particle is in the negative x-direction, it will slow down until its velocity is zero, at which point it will turn around.

So, we can find the time taken by the particle to come to rest as follows:

Using third equation of motion:

v = u + at0 = 4.80 - 3.80t,

t = 4.80/3.80 = 1.26 s

Thus, it takes the particle 1.26 seconds to come to rest.

Distance traveled by the particle before turning around:

Using second equation of motion:

s = ut + 1/2at^2

s = 4.80(1.26) + 1/2(-3.80)(1.26)^

2 = 2.41 m (distance traveled in x-direction before turning around)

The particle moves 2.41 m in the x-direction before turning around.

b) Position of the particle after it has been in motion for 2.00 s:

Using first equation of motion:

s = ut + 1/2at^2

Initial position of the particle was the origin.

So, the final position vector r can be found as:

r = ut + 1/2at^2

[tex]r = 4.80(2.00) + 1/2(-3.80)(2.00)^2 i + 1/2(6.40)(2.00)^2 j[/tex]

r = 2.40i + 12.8j

We can express this answer in terms of distance and direction from the origin using:

r = √(2.40^2 + 12.8^2)

= 12.9 mθ

= tan^-1(12.8/2.40) = 79.7 degrees

So, the particle is 12.9 m from the origin at an angle of 79.7 degrees with the positive x-axis.

c) Velocity of the particle (magnitude and direction) after 2.00 s:

Using first equation of motion: v = u + at

Final velocity of the particle can be found as:

v = 4.80 - 3.80(2.00) i + 6.40(2.00)

j = -3.4i + 13.0j

We can express this answer in terms of magnitude and direction as:

|v| = √((-3.4)^2 + 13.0^2)

= 13.5 m/s

θ = tan^-1(13.0/-3.4)

= -73.2 degrees

So, the velocity of the particle after 2.00 seconds is 13.5 m/s at an angle of -73.2 degrees with the positive x-axis.

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Four forces act on a 700×375 mm plate, a) find the resultant of these forces and their direction with respect to point E. b) Locate the resultant force with respect to line CE.

Answers

To find the resultant of the forces and their direction with respect to point E, we perform vector addition of the forces. To locate the resultant force with respect to line CE, we determine the perpendicular distance between the resultant force and line CE, which gives us the moment arm or lever arm of the force about line CE.

To determine the resultant of the four forces acting on the plate, we need to consider both the magnitudes and directions of the forces.

(a) To find the resultant force with respect to point E, we can use vector addition. Let's denote the forces as F1, F2, F3, and F4. We'll represent them as vectors with their respective magnitudes and directions.

After obtaining the vectors for each force, we can add them together using vector addition. The resultant force is the vector sum of all the individual forces. The direction of the resultant force can be determined by finding the angle it makes with respect to a reference line or axis.

(b) To locate the resultant force with respect to line CE, we need to find the perpendicular distance between line CE and the line of action of the resultant force. This distance represents the moment arm or lever arm of the force about line CE.

By determining the perpendicular distance, we can express the resultant force as a single force acting at a specific distance from line CE. This helps us understand the rotational effect of the resultant force about line CE.

In summary, to find the resultant of the forces and their direction with respect to point E, we perform vector addition of the forces. To locate the resultant force with respect to line CE, we determine the perpendicular distance between the resultant force and line CE, which gives us the moment arm or lever arm of the force about line CE.

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Come up with your own question that contains at least 5 different forces (e.g. gravity, normal, tension, friction, etc.) acting on the object. And then draw the corresponding FBD.

Answers

A person of mass 60 kg is riding a bicycle with a speed of 10 m/s. The bicycle hits a flat road from a hill, with a downward slope of 30 degrees. The bicycle tires have a coefficient of kinetic friction of 0.3. Draw the corresponding free body diagram for the person on the bicycle and find the net force acting on them.

Answer: The free body diagram for the person on the bicycle is given below:

The forces acting on the person on the bicycle are: The force of gravity, which is acting downward and can be calculated as:

Fg = mg

= (60 kg) (9.8 m/s²)

= 588 N

The force of friction, which is acting upward and can be calculated as:

Ff

= μkFn

= (0.3) (588 N)

= 176.4 N

The force of air resistance, which is acting opposite to the direction of motion and can be ignored in this case since its magnitude is relatively small. The net force acting on the person on the bicycle can be calculated as:

F net = ma

= m (g sinθ - μk cosθ)

= (60 kg) (9.8 m/s² sin30° - 0.3 cos30°)

= 294 N

Therefore, the net force acting on the person on the bicycle is 294 N.

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In the example, suppose we want the drum to rotate at a speed of 2 revolutions per second and still be able to remove the floor safely by: (a) changing the radius but keeping μ the same and (b) changing u but keeping the radius the same. What are the values of the radius and u in the two cases?

Answers

If we want the radius of the drum to be 1 meter, then the coefficient of friction must be μ = 1. If we want the radius of the drum to be 2 meters, then the coefficient of friction must be μ = 0.5. The angular velocity of the drum is 2 revolutions per second, which is 2 * 2π rad/s = 4π rad/s.

(a) Changing the radius but keeping μ the same

The angular velocity of the drum is 2 revolutions per second, which is 2 * 2π rad/s = 4π rad/s. The coefficient of friction between the drum and the floor is μ. The radius of the drum is r.

The force required to remove the floor is equal to the product of the coefficient of friction, the normal force, and the radius of the drum.

So, the force is:

force = μ * normal force * radius

The normal force is equal to the weight of the drum. The weight of the drum is equal to the mass of the drum multiplied by the acceleration due to gravity.

So, the normal force is:

normal force = mass of drum * acceleration due to gravity

The acceleration due to gravity is 9.8 m/s^2.

The force required to remove the floor must be greater than or equal to the weight of the drum.

So, we have the following inequality:

μ * normal force * radius >= mass of drum * acceleration due to gravity

We want the drum to rotate at a speed of 2 revolutions per second, so the angular velocity of the drum is 4π rad/s. The coefficient of friction between the drum and the floor is μ. The radius of the drum is r.

The normal force is equal to the weight of the drum. The weight of the drum is equal to the mass of the drum multiplied by the acceleration due to gravity.

So, we have the following equation:

μ * mass of drum * acceleration due to gravity * r >= mass of drum * acceleration due to gravity

We can cancel the mass of the drum and the acceleration due to gravity from both sides of the equation, and we are left with:

μ * r >= 1

So, the radius of the drum must be greater than or equal to 1 / μ.

If we want the radius of the drum to be 1 meter, then the coefficient of friction must be μ = 1.

If we want the radius of the drum to be 2 meters, then the coefficient of friction must be μ = 0.5.

(b) Changing u but keeping the radius the same

The angular velocity of the drum is 2 revolutions per second, which is 2 * 2π rad/s = 4π rad/s. The radius of the drum is r = 1 meter.

The force required to remove the floor is equal to the product of the coefficient of friction, the normal force, and the radius of the drum.

So, the force is:

force = μ * normal force * radius = μ * mass of drum * acceleration due to gravity

The normal force is equal to the weight of the drum. The weight of the drum is equal to the mass of the drum multiplied by the acceleration due to gravity.

So, the force is:

force = μ * mass of drum * acceleration due to gravity = μ * m * g

The acceleration due to gravity is 9.8 m/s^2.

The force required to remove the floor must be greater than or equal to the weight of the drum.

So, we have the following inequality:

μ * m * g >= m * g

We can cancel the mass of the drum and the acceleration due to gravity from both sides of the equation, and we are left with:

μ >= 1

So, the coefficient of friction must be greater than or equal to 1.

If we want the coefficient of friction to be 1, then the force required to remove the floor is equal to the weight of the drum.

If we want the coefficient of friction to be 2, then the force required to remove the floor is twice the weight of the drum.

Therefore, the answers are:

(a) r = 1 m, μ = 1

(b) r = 1 m, μ >= 1

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A container holds a liquid at 66°C bulk temperature, and convects heat to a wall with an external wall temperature of 25°Clf the surface heat transfer coefficient is 5 W/m²K Calculate the heat transfer per m² and state the principles and theories used to produce this calculation.

Answers

The heat transfer per m² is 205 Watts using the principles of convective heat transfer and the given parameters.

Convective heat transfer occurs when a fluid, in this case, the liquid in the container, transfers heat to a solid surface, the wall. The rate of heat transfer is influenced by the temperature difference between the fluid and the wall, as well as the surface heat transfer coefficient.

In this case, the bulk temperature of the liquid is given as 66°C, while the external wall temperature is 25°C. To calculate the temperature difference, we subtract the wall temperature from the bulk temperature: 66°C - 25°C = 41°C.

The surface heat transfer coefficient is provided as 5 W/m²K, which represents the rate at which heat is transferred between the fluid and the wall per unit area and per degree of temperature difference.

To calculate the heat transfer per m², we multiply the temperature difference (41°C) by the surface heat transfer coefficient (5 W/m²K):

Heat transfer per m² = 41°C × 5 W/m²K = 205 W/m²

Therefore, the heat transfer per m² in this scenario is 205 Watts per square meter.

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Air is contained in a vertical piston-cylinder assembly fitted with an electrical resistor. The atmosphere exerts a pressure of 1.2 bar on the top of the piston, which has a mass of 50 kg and a face area of 0.09 m2. Electric current passes through the resistor, and the volume of the air slowly increases by .048 m3 while its pressure remains constant. The mass of the air is 0.29 kg, and its specific internal energy increases by 47 kJ/kg. The air and piston are at rest initially and finally. The piston-cylinder material is a ceramic composite and thus a good insulator. Friction between the piston and cylinder wall can be ignored, and the local acceleration of gravity is g = 9.81 m/s2. Determine the heat transfer from the resistor to the air, in kJ, for a system consisting of (a) the air alone, (b) the air and the piston?

Answers

(a) The heat transfer from the resistor to the air alone is 14.16 kJ.

(b) The heat transfer from the resistor to the air and the piston is 14.16 kJ.

(a) For the air alone, the heat transfer is given by Q = m * Δu. Substituting the given values, we have Q = 0.29 kg * 47 kJ/kg = 13.63 kJ. However, it's important to note that this value only represents the change in internal energy of the air.

(b) For the air and the piston, the heat transfer is also given by Q = m * Δu. Since the piston is in contact with the air, any heat transferred to the air will also be transferred to the piston. Therefore, the heat transfer is the same as in part (a), which is 13.63 kJ.

In both cases, the heat transfer from the resistor to the air and the piston is 13.63 kJ.

When the volume of the air increases while its pressure remains constant, it indicates an isobaric process. To determine the heat transfer, we can use the equation Q = m * Δu, where Q is the heat transfer, m is the mass of the air, and Δu is the change in specific internal energy.

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Correctly label the following parts of a motor unit. neuromuscular junction spinal cord skeletal muscle fibers neuromuscular junction skeletal muscle fibers spinal cord

Answers

The correct labeling for the parts of a motor unit is neuromuscular junction, spinal cord, and skeletal muscle fibers.

A motor unit refers to a group of muscle fibers or cells that are controlled by a single motor neuron. Motor units are essential for the functionality of the neuromuscular system as they permit the muscle to produce force and movement. A motor unit is composed of three main parts: neuromuscular junction, spinal cord, and skeletal muscle fibers.

Neuromuscular junction refers to the site where a motor neuron meets and connects with the muscle fiber. This junction is critical for the transfer of impulses and activation of muscle fibers. Spinal cord plays a significant role in the functionality of motor units. It contains motor neurons that control the movement of the skeletal muscle fibers.

The spinal cord receives signals from the brain, which it then translates into a motor response to control the contraction of the muscle fibers. Skeletal muscle fibers refer to the individual muscle fibers that make up a muscle. They are attached to the bones of the skeleton and play an essential role in locomotion and body movements.

Skeletal muscle fibers are activated by the motor neuron, which initiates the release of calcium ions to stimulate the contraction of the muscle fibers.

In conclusion, the correct labeling for the parts of a motor unit is neuromuscular junction, spinal cord, and skeletal muscle fibers.

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Final answer:

The neuromuscular junction is where neurons connect to muscle fibers to transmit muscle contraction signals. Skeletal muscle fibers are the cells within a muscle that contract in response to these signals. These contraction signals originate from motor neurons located in the spinal cord.

Explanation:

The neuromuscular junction serves as the connection point between neurons and skeletal muscle fibers that allows signals to pass and trigger contractions. An axon terminal of a motor neuron connects with a muscle fiber at the neuromuscular junction and it uses acetylcholine to propagate signals. Skeletal muscle fibers are individual cells within a skeletal muscle and respond to these signals by contracting, facilitated by the neuromuscular junction. The spinal cord is involved as it houses motor neurons originating from the brainstem and these neurons are responsible for transmitting the signals that cause a skeletal muscle to contract via the neuromuscular junctions.

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The radius of curvature of a spherical concave mirror is 15 cm. Describe the image formed when a 20 mm tall object is positioned a) 5 cm from the mirror, b) 20 cm from the mirror. For each case give the image distance, the image height, the type of image (real or virtual), and the orientation of the image (upright or inverted). Express your answer with the appropriate units.

Answers

(a) When the object is placed 5 cm from the concave mirror, the object distance (u) is -5 cm (-0.05 m). Using the mirror formula 1/f = 1/v + 1/u, where f is the focal length of the mirror, we can calculate the image distance (v). With a focal length of 15 cm (0.15 m), the equation becomes 1/0.15 = 1/v + 1/-0.05. Solving this equation, we find 1/v = 6.67 - (-20), resulting in 1/v = 26.67.

Thus, v is approximately 0.0375 m (3.75 cm). The magnification (m) is given by -v/u, which is -3.75/(-0.05) = 150 mm (15 cm). The image is real and inverted.

(b) When the object is placed 20 cm from the concave mirror, the object distance (u) is -20 cm (-0.2 m). Applying the mirror formula, 1/f = 1/v + 1/u, with a focal length (f) of 15 cm (0.15 m), we obtain 1/0.15 = 1/v + 1/-0.2. Solving this equation, we find 1/v = 6.67 - (-5), resulting in 1/v = 11.67. Hence, v is approximately 0.0856 m (8.56 cm). The magnification (m) is -v/u, which is -8.56/-0.2 = 0.856 m (85.6 cm). The image is real and inverted.

In summary, when the object is placed 5 cm from the concave mirror, the image is real, inverted, located at approximately 3.75 cm from the mirror, and has a magnification of 15 cm. When the object is placed 20 cm from the mirror, the image is also real, inverted, located at around 8.56 cm from the mirror, and has a magnification of 85.6 cm.

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If the inside arrow is 9 m and the outside arrow is 25 m,and the center has no negative or positive charges and the shell has a uniform charge of 5C. What is the potential difference if a charge goes from 10 m to 16 m?

Answers

The potential difference when a charge goes from 10m to 16m is approximately -1.6875 x [tex]10^9[/tex] V. The negative sign indicates a decrease in potential as the charge moves farther away from the uniformly charged shell.

To calculate the potential difference between two points, we can use the formula:

V = k * (Q / r)

V is the potential difference

k is the electrostatic constant (k = 9 x [tex]10^9 N m^2/C^2[/tex])

Q is the charge

r is the distance

In this case, the charge (Q) is 5C and the distances (r) are 10m and 16m.

First, let's calculate the potential at the initial point (10m):

V_initial = k * (Q / r_initial)

V_initial = (9 x [tex]10^9 N m^2/C^2[/tex]) * (5C / 10m)

V_initial = 4.5 x [tex]10^9[/tex] V

Next, let's calculate the potential at the final point (16m):

V_final = k * (Q / r_final)

V_final = (9 x [tex]10^9 N m^2/C^2)[/tex] * (5C / 16m)

V_final = 2.8125 x[tex]10^9[/tex] V

Finally, we can calculate the potential difference (ΔV) between the two points:

ΔV = V_final - V_initial

ΔV = 2.8125 x [tex]10^9[/tex] V - 4.5 x[tex]10^9[/tex] V

ΔV = -1.6875 x [tex]10^9[/tex] V

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What is the apparent weight of 125 cm3 of steel submerged in
water? ANS: 8.4 N

Answers

When an object is submerged in water, the apparent weight is less than its actual weight due to the buoyant force. To determine the apparent weight of 125 cm³ of steel submerged in water, we will need to use the formula for buoyant force.

Buoyant force = Weight of water displaced by the object

We know the volume of the steel is 125 cm³. Since 1 cm³ of water has a mass of 1 gram and the density of steel is 7.8 g/cm³, we can calculate the mass of the steel:

mass of steel = volume of steel × density of steel= 125 cm³ × 7.8 g/cm³= 975 g

To determine the weight of water displaced by the steel, we need to know the volume of water displaced.

This is equal to the volume of the steel:

volume of water displaced = volume of steel = 125 cm³

The weight of water displaced is equal to the weight of this volume of water, which we can calculate using the density of water and the volume of water displaced:

weight of water displaced = volume of water displaced × density of water= 125 cm³ × 1 g/cm³= 125 g

Now we can calculate the buoyant force acting on the steel:

Buoyant force = Weight of water displaced by the object= 125 g × 9.81 m/s²= 1.23 N

The apparent weight of the steel submerged in water is equal to the actual weight minus the buoyant force:

Apparent weight = Actual weight - Buoyant force

Actual weight = mass of steel × gravitational acceleration= 975 g × 9.81 m/s²= 9.57 N

Apparent weight = 9.57 N - 1.23 N = 8.34 N

Therefore, the apparent weight of 125 cm³ of steel submerged in water is 8.34 N (to two decimal places).

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A spring (with k=18 N/m ) has a 2.2 kg object suspended. Assume that this object is pulled 0.35 m downward from its equilibrium position and allowed to oscillate. What is the maximum kinetic energy of the object? 2.0 J 1.1J 0.25J 4.0J 0.50 J

Answers

Maximum kinetic energy = maximum potential energy

Therefore, the maximum kinetic energy of the object is 0.905 J.

A spring with spring constant k = 18 N/m has a 2.2 kg object suspended.

If this object is pulled 0.35 m downward from its equilibrium position and allowed to oscillate,

Solution:

Maximum potential energy = 1/2 kA²

... equation 1

Where k = 18 N/m and

A = 0.35 m.

Maximum potential energy =[tex]1/2 × 18 N/m × (0.35 m)² = 0.905 J[/tex]

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Lifting a 74-kg barbell and weights from rest up to a speed of 1.0 m/s in 0.50 s, resisted by the combined weight of the barbell and weights, requires what applied force in N to two significant digits?

Answers

According to the question statement, we are given;

Mass of the barbell and weight, m = 74 kg

Speed of the barbell and weight, v = 1.0 m/s

Time taken to lift the barbell and weight, t = 0.50 s

The force required to lift the barbell and weight is given by,

F = m(v - u)/twhere u = 0 (initial velocity of the barbell and weight is at rest)

Substituting the given values in the above equation, we get;

F = (74 kg)(1.0 m/s - 0 m/s)/(0.50 s) = 148 N (upward force to two significant digits)

Therefore, the applied force required to lift the barbell and weights from rest up to a speed of 1.0 m/s in 0.50 s, resisted by the combined weight of the barbell and weights is 148 N to two significant digits.

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A centrifuge in a medical laboratory rotates at an angular speed of 3 600 rev/min. When switched off, it rotates 50.0 times before coming to rest. Find the constant angular acceleration of the centrifuge.

A.

2.26 x 102 rad/s2

B.

4.52 x 102 rad/s2

C.

1.26 x 102 rad/s2

D.

-2.26 x 102 rad/s2

Answers

The constant angular acceleration of the centrifuge is approximately -2.26 x 10^2 rad/s^2, as it rotates 50 times before coming to rest at an initial angular velocity of 376.99 rad/s. This corresponds to option (D) in the answer choices.

To find the constant angular acceleration of the centrifuge, we can use the equation:

ω_f = ω_i + αt,

where ω_f is the final angular velocity, ω_i is the initial angular velocity, α is the angular acceleration, and t is the time.

Given that the centrifuge rotates 50.0 times before coming to rest, we can calculate the time it takes for the centrifuge to stop using the formula:

t = (number of rotations) / (angular speed) = 50.0 rev / (3600 rev/min).

Converting the angular speed to rad/s, we have:

ω_i = (3600 rev/min) * (2π rad/rev) * (1 min/60 s) = 376.99 rad/s

Substituting the values into the first equation, we can solve for α:

0 = 376.99 rad/s + α * [(50.0 rev) / (3600 rev/min)]

Simplifying the equation, we find:

α = -376.99 rad/s / [(50.0 rev) / (3600 rev/min)] = -2.26 x 10^2 rad/s^2.

Therefore, the constant angular acceleration of the centrifuge is approximately -2.26 x 10^2 rad/s^2, corresponding to option (D).

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Which of the following is NOT another name for the Big and Little Dippers?
A. Cart B. Drinking gourd. C. Many little eyes. D. Plow.

Answers

"Many little eyes," is not another name for the Big and Little Dippers.

Hence, the correct option is C.

The Big Dipper and Little Dipper are two well-known asterisms (a pattern of stars) in the northern sky. They are also referred to by other names in different cultures and regions. The options A, B, and D are alternative names for the Big and Little Dippers:

A. Cart: This is another name for the Big Dipper.

B. Drinking gourd: This is another name for the Big Dipper, particularly associated with African American folklore and the Underground Railroad.

D. Plow: This is another name for the Big Dipper, commonly used in agricultural and farming communities.

Therefore, "Many little eyes," is not another name for the Big and Little Dippers.

Hence, the correct option is C.

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determine a location in our solar system you would like to visit (other than the Earth) and... Design a way to survive there. What would the difficulties include, what problems would you face, and how would you overcome them. What would you need to bring with you, and what would you find there that you could use.

Answers

Surviving on Enceladus would require protective suits, advanced heating systems, sustainable food/water/oxygen sources, efficient recycling methods, and utilization of local materials for construction and energy generation to overcome challenges such as low gravity, lack of atmosphere, extreme cold temperatures, and limited resources.

Enceladus, one of Saturn's moons, presents an intriguing destination for exploration due to its subsurface ocean and potential for harboring life. Surviving on Enceladus would require addressing several challenges. Firstly, the moon's low gravity and lack of atmosphere would necessitate protective suits to counter the absence of atmospheric pressure and shield against radiation.

The extreme cold temperatures on Enceladus, reaching as low as -330 degrees Fahrenheit (-201 degrees Celsius), would require advanced heating systems and insulated habitats to maintain a habitable environment. Additionally, ensuring a sustainable source of food, water, and oxygen would be crucial, possibly achieved through hydroponics systems and advanced life support technologies.

Explorers would also need to address the limited availability of resources by developing efficient recycling methods and utilizing local materials for construction and energy generation. Despite these challenges, the potential for scientific discoveries and the search for extraterrestrial life would make the journey to Enceladus worthwhile.

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You will make your own map of the Solar System "to scale". On a sheet of paper you will make a map, labeling the streets. Choose a corner to be the location of the Sun. (x=0) Walk in one direction, counting your steps (1 meter =3 steps), and mark the location of the planets of the Solar System and Pluto on your map. You will take a picture of your map and upload it as a pdf. Afterward answer the questions below, as if you are going on a trip to Mars with your family. PACKING FOR MARS: You and your family are a flight crew, planning to spend several years together on a trip to Mars. What problems do you anticipate? These are very nice people, but will their taste in food and music drive you crazy? As you take our solar system walk, make a list of a few of the most important things you need to pack to keep your trip to Mars safe, friendly, and sane!

Answers

As a flight crew planning to spend several years together on a trip to Mars, there are a few problems that we can anticipate.

One of the problems is that there is a possibility that our taste in food and music can be different and this might lead to conflicts. This means that everyone will have to be flexible and open to compromise to keep the environment friendly and sane.As we take our solar system walk, a few of the most important things that we need to pack to keep our trip to Mars safe, friendly, and sane are listed below:Food and Water: We will need a lot of food and water to sustain us throughout the journey. We will have to ensure that the food is well-packaged, nutritious, and can last for the duration of the trip.

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speed of sound is 340 m/s where a tuning fork produces the second resonance position above an air column that is 49.8 cm in length. What is the frequency of the tuning fork?

Answers

The frequency of the tuning fork is approximately 342.17 Hz. We can use the formula for the speed of sound in a pipe with one closed end: v = (2 * L * f) / n.

To determine the frequency of the tuning fork, we can use the formula for the speed of sound in a pipe with one closed end:

v = (2 * L * f) / n

where v is the speed of sound, L is the length of the air column, f is the frequency of the tuning fork, and n is the harmonic number.

In this case, the second resonance position above the air column corresponds to n = 1 (first harmonic) because one end of the air column is closed.

Given that the speed of sound is 340 m/s and the length of the air column is 49.8 cm (or 0.498 m), we can rearrange the formula to solve for the frequency:

f = (v * n) / (2 * L)

Substituting the values, we have:

f = (340 m/s * 1) / (2 * 0.498 m)

f ≈ 342.17 Hz

Therefore, the frequency of the tuning fork is approximately 342.17 Hz.

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A coffee-maker ( 13Ω) and a toaster (11Ω) are connected in parallel to the same 120−V outlet in a kitchen. How much total power is supplied to the two appliances when both are turned on? Number Units

Answers

Given that a coffee-maker ( 13Ω) and a toaster (11Ω) are connected in parallel to the same 120-V outlet in a kitchen.

We need to calculate the total power supplied to the two appliances when both are turned on.

Let's calculate the total resistance (RT) of the circuit using the formula for resistors in parallel:

1/RT = 1/R1 + 1/R2

Where R1 = 13Ω and

R2 = 11Ω1/RT = 1/13Ω + 1/11Ω= (11+13) / (13*11)= 24/143ΩRT = 5.96Ω

Total power (P) can be calculated using the formula:

P = V² / RP = (120 V)² / 5.96ΩP = 2880 / 5.96W = 482.55 W

the total power supplied to the two appliances when both are turned on is 482.55 W.

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A machine is used to form bubbles from pure water by
mechanically foaming it. The surface tension of water is 0:070 N
m-1. What is the gauge pressure inside bubbles of radius 10 m?

Answers

The gauge pressure inside the bubble is 14,000 N/m² or 14,000 Pa. We can use Laplace's law for pressure inside a curved liquid interface: ΔP = 2σ/R.

To find the gauge pressure inside bubbles, we can use the Laplace's law for pressure inside a curved liquid interface:

ΔP = 2σ/R

where ΔP is the pressure difference across the curved interface, σ is the surface tension of water, and R is the radius of the bubble.

Given:

Surface tension of water (σ) = 0.070 N/m

Radius of the bubble (R) = 10 μm = 10 × 10^(-6) m

Substituting the values into the equation, we have:

ΔP = 2σ/R

= 2 * 0.070 / (10 × 10^(-6))

= 14,000 N/m²

The gauge pressure is the difference between the absolute pressure inside the bubble and the atmospheric pressure. Since the problem only asks for the gauge pressure, we assume the atmospheric pressure to be zero.

Therefore, the gauge pressure inside the bubble is 14,000 N/m² or 14,000 Pa.

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hung without causing the rod to slip at point A .

Answers

One end of a uniform 4.00−m−long rod of weight Fg is supported by a cable at an angle of θ=37° with it is held by friction. The rod will start to slip at point A before any additional object can be hung.

To determine the minimum distance x from point A at which an additional object can be hung without causing the rod to slip at point A, we need to consider the equilibrium conditions for the rod.

Given:

Length of the rod, L = 4.00 m

Angle of the cable with the rod, θ = 37°

Coefficient of static friction, μs = 0.500

We'll start by analyzing the forces acting on the rod:

Weight of the rod (mg):

The weight of the rod acts vertically downward at its center of mass. Its magnitude can be calculated as Fg = mg, where m is the mass of the rod and g is the acceleration due to gravity.

Tension in the cable (T):

The cable supports one end of the rod at an angle of θ = 37°. The tension in the cable acts upward and at an angle θ with respect to the horizontal.

Frictional force (f):

The rod is held by friction against the wall at point A. The frictional force opposes the tendency of the rod to slip. The maximum static frictional force is given by fs = μsN, where N is the normal force exerted by the wall on the rod.

To prevent slipping at point A, the sum of the forces acting on the rod in the horizontal direction must be zero, and the sum of the forces acting on the rod in the vertical direction must also be zero.

Horizontal forces:

T*cos(θ) - f = 0

Vertical forces:

T*sin(θ) + N - Fg = 0

Now let's calculate the values of the forces:

Fg = mg (mass times acceleration due to gravity)

N = Fg (since the rod is in equilibrium vertically)

fs = μsN (maximum static frictional force)

Substituting the values into the equations:

Tcos(θ) - fs = 0

Tsin(θ) + Fg - Fg = 0

Simplifying the equations:

Tcos(θ) - fs = 0

Tsin(θ) = 0

From the second equation, we can see that T*sin(θ) = 0, which means sin(θ) = 0. This is not possible for θ = 37°, so we can conclude that there is no vertical force balancing the weight of the rod.

Therefore, the rod will start to slip at point A before any additional object can be hung.

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Complete question:

One end of a uniform 4.00−m−long rod of weight Fg is supported by a cable at an angle of θ=37°  with it is held by friction as shown in Figure P12.23. The coefficient of static friction between the wall and the rod is μs =0.500. Determine the minimum distance x from point A at which an additional object, also with the same weight Fg, can be hung without causing the rod to slip at point A.

Calculate the wavelength and frequency of the photon emitted if an electron in a one-dimensional box of length 1.00 nm (1.00 x 10-ºm) makes a transition from n=3 to n=2 and the energy difference is entirely converted into the energy of the photon.

Answers

Given the length of the one-dimensional box, L, as 1.00 nm (1.00 × 10⁻⁹ m), the energy of an electron in the box can be calculated using the formula En = n²h²/8mL², where n is the quantum number, h is Planck's constant, m is the mass of an electron, and L is the length of the box.

To find the energy difference between two levels, n₁ and n₂, we use the formula ΔE = E(n₂) - E(n₁), where E represents the energy.

Using the values n₁ = 3 and n₂ = 2, and substituting the given constants, we find ΔE = 3.07 × 10⁻¹⁹ Joules.

The frequency of the photon emitted is calculated using the formula ν = ΔE / h, where ν represents frequency and h is Planck's constant. Substituting the calculated value of ΔE, we find ν = 4.63 × 10¹⁴ Hz.

To determine the wavelength of the emitted photon, we use the equation λ = c / ν, where λ represents the wavelength and c is the speed of light. Substituting the given values, we find λ = 6.47 × 10⁻⁷ m or 647 nm.

Therefore, the wavelength of the emitted photon is 6.47 × 10⁻⁷ m or 647 nm, and the frequency is 4.63 × 10¹⁴ Hz or 463 THz.

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Two speakers are located on the x-axis, one at the origin and one at d = 0.584. A microphone located at coordinate x (which unknown but is larger than d) will detect destructive interference when the speakers are emitting what frequency between 500 Hz and 1000 Hz? The speed of sound is 340 m/s.

Answers

Two speakers are located on the x-axis, one at the origin and one at d = 0.584. No frequency between 500 Hz and 1000 Hz that would result in destructive interference at the given microphone location.

To determine the frequency that would result in destructive interference at a given microphone location, we need to consider the path length difference between the two speakers.

Destructive interference occurs when the path length difference between the two speakers is equal to an odd multiple of half the wavelength. Mathematically, this can be expressed as:

Δx = n × λ ÷ 2

Where:

Δx = Path length difference between the two speakers

n = Integer (odd number for destructive interference)

λ = Wavelength of the sound wave

The wavelength of a sound wave can be related to its frequency (f) and the speed of sound (v) using the formula:

λ = v ÷ f

Given the speed of sound (v) as 340 m/s, we can rearrange the equation to solve for the wavelength:

λ = v ÷ f

Now, we can substitute this expression for wavelength in the path length difference equation:

Δx = n × (v ÷ f) ÷ 2

Since we are interested in the frequency that results in destructive interference at a given microphone location (x), we can write the path length difference equation in terms of the microphone location:

Δx = (x - 0) - (x - 0.584) = 0.584

Now, we can substitute this value of path length difference into the equation:

0.584 = n × (v ÷ f) ÷ 2

Rearranging the equation to solve for the frequency:

f = n × (v ÷ (2 × Δx))

We know that the frequency should be between 500 Hz and 1000 Hz. Let's calculate the frequencies for n = 1, 3, 5, 7, etc., and check if they fall within this range.

For n = 1:

f = 1  (340 m/s ÷(2 × 0.584 m)) ≈ 291.78 Hz

For n = 3:

f = 3 (340 m/s ÷ (2 × 0.584 m)) ≈ 875.34 Hz

For n = 5:

f = 5 (340 m/s ÷ (2 × 0.584 m)) ≈ 1458.9 Hz

None of these frequencies fall within the range of 500 Hz to 1000 Hz.

We can conclude that there is no frequency between 500 Hz and 1000 Hz that would result in destructive interference at the given microphone location.

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In a medium traveling a sinusoidal wave with the equation: y1(x, t) = 4.6 sin(0.5πx - 400πt) mm.
a. Determine, the wavelength, frequency , amplitude and speed of propagation of the wave.
b. If at the same place, at the same time and in the same direction, the second wave also propagates with the equation:
y2(x, t) = 4.60 sin(0.5πx - 400πt + 0.80π ) mm
Determine the wave equation for the superposition of the two waves.

Answers

For the given wave equation y1(x, t), we determined the wavelength (λ = 4 mm), frequency (f = -200 Hz), amplitude (A = 4.6 mm), and speed of propagation (v = -800 mm/s). For the superposition of the two waves, we derived the wave equation y(x, t) = 4.6 [sin(0.5πx - 400πt) + sin(0.5πx - 400πt + 0.8π)] mm.

a. In the wave equation y1(x, t) = 4.6 sin(0.5πx - 400πt) mm:

The coefficient in front of x, 0.5π, corresponds to the angular wave number (k) of the wave. Since k = 2π/λ (where λ is the wavelength), we can solve for λ: λ = 2π/(0.5π) = 4 mm.

The coefficient in front of t, -400π, corresponds to the angular frequency (ω) of the wave. Since ω = 2πf (where f is the frequency), we can solve for f: f = (-400π)/(2π) = -200 Hz. Note that the negative sign indicates the wave is propagating in the negative direction of the x-axis.

The amplitude of the wave is given as 4.6 mm.

The speed of propagation (v) of the wave can be calculated using the relationship v = λf. Substituting the values, we get v = (4 mm)(-200 Hz) = -800 mm/s. Again, the negative sign indicates the wave is propagating in the negative direction of the x-axis.

b. The wave equation for the superposition of the two waves y1(x, t) and y2(x, t) can be obtained by adding the individual equations together:

y(x, t) = y1(x, t) + y2(x, t) = 4.6 sin(0.5πx - 400πt) + 4.6 sin(0.5πx - 400πt + 0.8π) mm.

Simplifying the equation, we have:

y(x, t) = 4.6 [sin(0.5πx - 400πt) + sin(0.5πx - 400πt + 0.8π)] mm.

In summary, for the given wave equation y1(x, t), we determined the wavelength (λ = 4 mm), frequency (f = -200 Hz), amplitude (A = 4.6 mm), and speed of propagation (v = -800 mm/s). For the superposition of the two waves, we derived the wave equation y(x, t) = 4.6 [sin(0.5πx - 400πt) + sin(0.5πx - 400πt + 0.8π)] mm. The superposition represents the combined effect of both waves at the same place, time, and direction.

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what are speed and velocity and how do they compare

Answers

Speed and velocity are both physical quantities that describe the motion of an object, but they have distinct meanings. Speed refers to how fast an object is moving, while velocity refers to the speed of an object in a specific direction. While speed is a scalar quantity, velocity is a vector quantity.

Speed is defined as the rate at which an object covers a distance. It is a scalar quantity, meaning it only has magnitude and no specific direction. Speed is calculated by dividing the distance traveled by the time taken. For example, if a car travels 100 kilometers in 2 hours, the speed would be 50 kilometers per hour.

On the other hand, velocity includes both speed and direction. It is a vector quantity, meaning it has both magnitude and direction. Velocity describes the rate at which an object changes its position in a specific direction. For instance, if a car travels 100 kilometers in 2 hours towards the east, the velocity would be 50 kilometers per hour to the east.

In summary, speed refers to how fast an object is moving without considering its direction, while velocity takes into account both the speed and the direction of motion. Speed is a scalar quantity, while velocity is a vector quantity.

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Problem 2 Region of Magnetic Field B -d=0.012 m A mass spectrometer is constructed as shown. It is used for determining the mass of singly ionized positively charged ions (missing 1 electron). There is a uniform magnetic field B = 0.20 tesla is perpendicular to the page within the shaded region (inside the whole box). A potential difference of V = 1500 V is applied across the parallel plates L and K, which are separated by a distance d = 0.012 meter and which act as a velocity selector (see problem 19.6 in book). (Positive z out of page) M (a) (3 points) In which direction, relative to the coordinate system shown, should the magnetic field point in order for positive ions to move along the path shown by the dashed line in the diagram? Explain. (b) (3 points) Should plate K have a positive or negative polarity, relative to plate L? Explain. (c) (6 points) Calculate the magnitude of the electric filed between the plates. (d) (7 points) Calculate the speed of a particle that can pass between the parallel plates without being deflected. (e) (6 points) Calculate the mass of the singly charged ion that travels in a semicircle of radius R = 0.50 meter. L K V= 1,500 V

Answers

(a) The magnetic field should point into the page (negative z-direction) in order for positive ions to move along the path shown by the dashed line. This is because the ions are positively charged and experience a force perpendicular to both their velocity and the magnetic field direction, following the right-hand rule.

(b) Plate K should have a positive polarity relative to plate L. This creates an electric field that opposes the magnetic force on the positive ions, allowing them to pass through the plates without being deflected.

(c) The magnitude of the electric field between the plates can be calculated using the formula E = V/d, where E is the electric field, V is the potential difference, and d is the distance between the plates.

(d) The speed of a particle that can pass between the parallel plates without being deflected can be calculated by equating the electric force to the magnetic force and solving for the speed. The electric force is given by F = qE, where q is the charge of the particle, and the magnetic force is given by F = qvB, where v is the speed of the particle and B is the magnetic field strength.

(e) The mass of the singly charged ion that travels in a semicircle of radius R can be calculated using the formula mv²/R = qvB, where m is the mass of the ion and q is its charge.

In order for positive ions to move along the path shown by the dashed line, the magnetic field should point into the page (negative z-direction). This is because positive ions are moving in a direction perpendicular to the magnetic field. According to the right-hand rule, the force experienced by a positively charged particle moving perpendicular to a magnetic field is directed inward.

Plate K should have a positive polarity relative to plate L. By applying a potential difference across the plates, an electric field is created. This electric field opposes the magnetic force on the positive ions. The electric force acts in the opposite direction to the magnetic force, allowing the ions to pass through the plates without being deflected.

The magnitude of the electric field between the plates can be calculated using the formula E = V/d, where E is the electric field, V is the potential difference (given as 1500 V), and d is the distance between the plates (given as 0.012 meters). By substituting the values into the formula, the magnitude of the electric field can be determined.

To calculate the speed of a particle that can pass between the parallel plates without being deflected, the electric force and the magnetic force must be equal. The electric force is given by F = qE, where q is the charge of the particle (singly ionized) and E is the electric field between the plates. The magnetic force is given by F = qvB, where v is the speed of the particle and B is the magnetic field strength. By equating these forces and solving for the speed, the answer can be obtained.

The mass of the singly charged ion that travels in a semicircle of radius R can be determined by using the formula mv²/R = qvB. Here, m represents the mass of the ion, v is its speed, q is the charge (singly ionized), R is the radius of the semicircle (given as 0.50 meters), and B is the magnetic field strength (given as 0.20 tesla). By rearranging the formula and substituting the known values, the mass of the ion can be calculated.

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Two capacitors connected in paraliel produce an Part A equivalont capacitance of 38.0μF but when connected in senes the equivalent capacitance is What is the individual capacitance of each capactar? only 7.0μF Express your answers using two signlficant figures. Enter your answers nunerically separated by a comma.

Answers

The equivalent capacitance of two capacitors connected in series is 3.5 µF.

Capacitance of two capacitors connected in parallel, CP = 38.0 µF;

Capacitance of each capacitor, C = 7.0 µF;

Let the equivalent capacitance of two capacitors connected in series be CS.

For two capacitors connected in parallel, the equivalent capacitance is given by CP = C1 + C2

where C1 and C2 are the capacitances of the two capacitors.

For two capacitors connected in series, the equivalent capacitance is given by the expression:

1 / CS = 1 / C1 + 1 / C2

On substituting the given values,

CP = C1 + C2

38.0 = C + C

C = 7.0 µF

The expression for equivalent capacitance when two capacitors are connected in series is:

1 / CS = 1 / C1 + 1 / C21 / CS

=> 1 / 7.0 + 1 / 7.0

= 2 / 7.0

CS= 7.0 / 2 µF

= 3.5 µF

Therefore, the equivalent capacitance of two capacitors connected in series is 3.5 µF.

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Do not indent Date Account Titles and Explanation Debit Credit 2019 Salaries and Wages Expense Salaries and Wages Payable (To accrue the expense and liability for vacations) Salaries and Wages Expense Salaries and Wages Payable (To accrue the expense and liability for sick pay) No Entry No Entry (To record payment for compensated time when used by employees) 2020 Salaries and Wages Expense Salaries and Wages Payable (To accrue the expense and liability for vacations) Salaries and Wages Expense Salaries and Wages Payable (To accrue the expense and liability for sick pay) Salaries and Wages Expense Salaries and Wages Payable Cash (To record vacation time paid) Salaries and Wages Expense Salaries and Wages Payable Cash (To record sick leave paid) Why does the Supply Management system of agricultural goods continue to exist in Canada? Describe how the system operates and explain its advantages and disadvantages, identifying particular groups in Canadian society who gain or lose by Supply Management. Is there any prospect of the system changing? If so, who would gain and who would lose? What were two actions of God as a result of Solomon's sin? confusion rebuke famine discipline disease Suppose Olivia and Randall are neighbors in a small town that only allows fireworks one day a year. As a result, Olivia and Randall are both deciding on how many fireworks to purchase. They live far enough away from other citizens that they will only see one another fireworks. If they don't purchase fireworks, they can purchase hamburgers. Their utility functions are identical and is given by Ui(H,FO,FR)=2/3ln(Hi)+1/3ln(FO+FR). They are both given 200 to spend on hamburgers and fireworks. The price of hamburgers is 1 and the price of fireworks is 2 . 1) What is the budget constraint? 2) If left to the private provision, what will be the optimal allocation of hamburgers and fireworks for Olivia and Randall? 3) What would be the socially optimal allocation of hamburgers and fireworks? in act v of romeo and juliet what does romeo buy from the apothecarytruefalse Briefly describe the Understand-Solve-Explain approach to problem solving, giving examples of things that should be considered in each step.What is the "Understand" step of this part of the problem solving approach? Use the table on Black holes we used in class and: 1AU=93,000,000 miles; mass of Sun =2x 1030 kg, mass of Earth =61024 kg, mass of Moon =7.31022 kg, moon radius =1080 miles, Earth radius =4000 miles; answer the following: How many times larger in radius is Earth than a stellar black hole? 1) Explain what is meant by the term "Team Manager" 2) Explain exactly how a Team Manager is different from a "Produce or Perish" manager 3) Give three examples of behaviour which illustrates the difference between the two styles of management Martin is the new director for marketing at Panther Shoes, a manufacturer of athletic apparel. He suggested a relationship marketing campaign and has conducted a market research to gain more insights of the company's customers. From the research, the data shows that Panther Shoes' customers are mainly single females between 22 and 35 years old with higher than average income. They enjoy outdoor activities but prefer to live in the urban area closer to different parks and recreation facilities. Most of them are career motivated and will buy at least 3 pairs of running shoes annually. With high disposable income, they enjoy products with higher quality, going to the gym at least twice a week, and are willing to pay more for sustainable products that will protect the environment. Question: Based on this case, please describe THREE Panther Shoes' current target segments using THREE different segmentation bases, i.e, one segmentation base for each target segment. In your answers, you will NAME the segmentation base used and PROVIDE the supporting information from the case. Elliot Rosewater constructs a portfolio comprised of the following: - Long 3 shares of RWF stock, with a current price of 72.00 - Short 2 call options on RWF, with a strike price of 72.00 and three months to expiration. The price of each call option is 6.00- Long 2 put options on RWF, with a strike price of 72.00 and three months to expiration. The price of each put option is 5.013 - Short a zero-coupon bond, which matures in three months with a face amount of 144. The current risk-free rate is 5.52%. a. Determine the cost (as of today) of Elliot's portfolio.b. Determine the price of RWT stock at the end of three months if the portfolio breaks even at that time. c. Determine the minimum profit of the portfolio at the end of three months. d. Determine the stock price at the end of three moths such that the profit of the portfolio is 27.00. Control charts have many applications in operations. Define and provide an example of at least 3 applications where control charts would be beneficial to an operations manager? you need extensive knowledge of networks to set up a home network.t/f Microsoft stock is currently trading at $305.00 per share. Assume that the dividend yield is 0 and the annual risk-free rate is 2%. You calculate the standard deviation of stock returns to be 35% (0.35). What is the hedge-ratio (the option \Delta) of a 6-month Microsoft call option with a strike price of $310? Doubling the thickness of shielding on a spacecraft will reduce the impacts on your spacecraft from energetic charged particles by a factor of two. True False Two flat, partially transmitting mirrors are separated in air by 1 mm. A material of refractive index n=1.5 is inserted between the mirrors. (a) What is the optical path length before and after inserting the high index material between the two mirrors? (b) A laser beam travels along an axis perpendicular to the mirror faces and it enters through one mirror into the space between mirrors. The laser has a wavelength of 500 nm. How many whole wavelengths fit in exactly between the two mirrors in each case.