verify that rolle's theorem can be applied to the function f(x)=x3−10x2 31x−30 on the interval [2,5]. then find all values of c in the interval such that f′(c)=0. enter the exact answers in increasing order

Answers

Answer 1

The function f(x) = x³ - 10x² + 31x - 30, satisfied all the three conditions of rolle's theorem on interval [2,5], that is verified it. The values of c in the interval are [tex]\frac{ 10 + \sqrt{7}}{3}[/tex] and [tex]\frac{ 10 + \sqrt{7}}{3}[/tex].

Rolle's theorem are important for the theorem to be true, three main conditions for it are following:

f(x) is continuous on the closed interval [a,b]; f(x) is differentiable on the open interval (a,b); f(a) = f(b).

We have a function, f(x) = x³ - 10x² + 31x - 30 --(1) on interval [2,5]. We have to verify the rolle's theorem for f(x). First differentiating f(x) in equation (1),

f'(x) = 3x² - 20x + 31

Now, f'(x) is exist for every value of x in interval [2,5]. Hence, f(x) is differential function. As we know every differential function is continuous function. This implies f(x) is continuous function in

interval [2,5]. Now, value of function f(x) at x = 2 and 5

=> f( 2) = 2³ - 10×2² + 31×2 -30

= 8 - 40 + 62 - 30 = 0

f( 5) = 5³ - 10× 5² + 31× 5 - 30

= 125 - 250 + 155 - 30 = 0

So, f( 2) = f(5) = 0, thus, all three conditions of rolle's theorem are satisfied. So, rolle's theorem is verified for function f(x) = x³ - 10x² - 31x - 30. To determine the value of c , put f'(c) = 0

=> 3c² - 20c + 31 = 0, which is an quadratic equation. Solve it using quadratic formula, [tex]c = \frac{- (-20) ± \sqrt{20² - 4×3×31}}{2×3}[/tex]

[tex]=\frac{ 20 ± \sqrt{28}}{6}[/tex]

= [tex] \frac{ 10 ± \sqrt{7}}{3}[/tex]. Hence, required values of c are [tex] \frac{ 10 ± \sqrt{7}}{3}[/tex].

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Related Questions

1. What is the annual rate of tropical forest loss, as a percentage of total forest area, in each of the five countries?

2. What is the annual rate of tropical deforestation collectively in all of the countries represented in the table?

3. According to the table, and assuming the rates of deforestation remain constant, which country's tropical forest will be totally destroyed first?

4. Assuming the rate of deforestation in country C remains constant, how many years will it take for all of its tropical forests to be destroyed?

The table needed to find the answer is below

Answers

Country C's tropical forest will be totally destroyed first because it has the highest annual rate of deforestation as a percentage of its total forest area.

The annual rate of tropical forest loss, as a percentage of total forest area, in each of the five countries is:

Country A: (50,000 / 1,800,000) x 100% = 2.78%

Country B: (3,000 / 55,000) x 100% = 5.45%

Country C: (6,000 / 22,000) x 100% = 27.27%

Country D: (12,000 / 530,000) x 100% = 2.26%

Country E: (700 / 80,000) x 100% = 0.88%

The annual rate of tropical deforestation collectively in all of the countries represented in the table is:

Total deforestation per year = 50,000 + 3,000 + 6,000 + 12,000 + 700 = 71,700 square kilometers

According to the table, and assuming the rates of deforestation remain constant

Country C's tropical forest will be totally destroyed first because it has the highest annual rate of deforestation as a percentage of its total forest area.

Assuming the rate of deforestation in Country C remains constant, it will take (22,000 / 6,000) = 3.67 years or approximately 4 years for all of its tropical forests to be destroyed.

Hence, Country C's tropical forest will be totally destroyed first because it has the highest annual rate of deforestation as a percentage of its total forest area.

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determine the arc length of x = 0.5y^2 for 0 <= x <= ½ without a calculator

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The arc length of x = 0.5y² for 0 ≤ x ≤ ½ is 1.14779.

Arc length is the distance between two points along a section of a curve.

To determine the arc length of x = 0.5y² for [tex]0 \leq  x \leq  \frac{1}{2}[/tex] without a calculator, we need to use the formula for arc length:
[tex]L = \int_{a}^{b}\sqrt{[1 + (dy/dx)^2]} dx[/tex]

In this case, we need to express y in terms of x, so we can find dy/dx:
x = 0.5y²
y = ±√(2x)

Since we are only interested in the curve for [tex]0 \leq  x \leq  \frac{1}{2}[/tex], we can take the positive root:
y = √(2x)

Next, we need to find dy/dx:
dy/dx = [tex]\frac{d}{d x}(\sqrt{2 x})[/tex]
dy/dx = [tex]\frac{1}{\sqrt{2x}}[/tex]

Now, we can plug this into the formula for arc length:
[tex]L = \int_{0}^{1/2}\sqrt{[1 + (dy/dx)^2]} dx[/tex]
[tex]L = \int_{0}^{1/2} \sqrt{[1 + (1/2x)]} dx[/tex]
[tex]L = \int_{0}^{1/2} \sqrt{\frac{2x+1}{2x} } dx[/tex]

Integrating and substituting the limits, we get:

L= 1.14779.

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please help me outtttt

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Answer:

Step-by-step explanation:

Determine whether the geometric series is convergent or divergent. 9 + 8 + 64/9 +512/ 81 + .... convergent /divergent If it is convergent, find its sum. (If the quantity diverges, enter DIVERGES.)

Answers

The sum of the convergent geometric series is approximately 81.82.

This is a geometric series with first term a = 9 and common ratio r = 8/9. To determine if it converges or diverges, we need to check if |r| < 1:

|r| = |8/9| < 1

Since |r| < 1, the series converges. To find its sum, we use the formula:

S = a/(1 - r)

S = 9/(1 - 8/9)

S = 9/(1/9)

S = 81

Therefore, the series is convergent and its sum is 81.
To determine whether the geometric series is convergent or divergent, we first need to identify the common ratio (r). Let's look at the given terms:

9, 8, 64/9, 512/81, ...

We can see that each term is obtained by multiplying the previous term by a certain number (r). Let's find r:

8 / 9 = r
r ≈ 0.89

Now, for a geometric series to be convergent, the absolute value of r must be less than 1, i.e., |r| < 1. In this case:

|0.89| < 1

Since the condition is satisfied, the series is convergent. To find the sum of the convergent series, we can use the formula for the sum of an infinite geometric series:

S = a / (1 - r)

where S is the sum, a is the first term (9), and r is the common ratio (0.89). Plugging in the values, we get:

S = 9 / (1 - 0.89)
S = 9 / 0.11
S ≈ 81.82

So, the sum of the convergent geometric series is approximately 81.82.

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A newspaper article claimed that 3 out of 5 households in the area had internet connections. If they surveyed 300 households, how many did not have internet hookups?

Answers

For a probability of 3 out of 5 households had internet connections in a area. The number of households had not internet connections in a area is equals to the 120.

We have a newspaper article claimed that 3 out of 5 households in the area had internet connections.

Total number of households = 300

Let E be an Event such that the household has an interent connection.

Probability of success that is housholds with internet connection, P(E) = 3/5

We have to determine the number of households have not internet connection. We know that probability is defined as ratio of favourable outcomes to the total possible outcomes. Mathematically, P = number of favourable ways/ total possible ways

Here, total possible outcomes = 300

Using probability formula, 3/5 = n(E)/300

where n(E) -> number of household with internet connection

=> n( E) = 900/5 = 180

Now, the number of households with no interent connection = 300 - 180

= 120

Hence, required value is 120.

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find the standard deviation for the sampling distribution of the sample proportion with (i) n=100, (ii) n=500(i) standard deviation =(ii) standard deviation =(round to four decimal places as needed)

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The standard deviation for the sampling distribution of the sample proportion with n=100 is 0.05, and with n=500 is approximately 0.0224

The standard deviation for the sampling distribution of the sample proportion can be calculated using the formula:
standard deviation = √(p(1-p)/n)
where p is the true population proportion and n is the sample size.
(i) n=100, we don't know the true population proportion, so we will assume a conservative estimate of p=0.5  

Substituting in these values, we get:
standard deviation = √(0.5(1-0.5)/100) = 0.05
Therefore, the standard deviation for the sampling distribution of the sample proportion with n=100 is 0.05.


(ii) n=500, we again assume a conservative estimate of p=0.5 and plug in the values:
standard deviation = √(0.5(1-0.5)/500) = 0.0224
Therefore, the standard deviation for the sampling distribution of the sample proportion with n=500 is 0.0224.

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use the parametric equations of an ellipse, x = a cos(), y = b sin(), 0 ≤ ≤ 2, to find the area that it encloses.

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To find the area enclosed by an ellipse using its parametric equations, we can use the formula:

Area = 4ab ∫0^(π/2) cos(t) sin(t) dt

where a and b are the lengths of the semi-major and semi-minor axes of the ellipse, respectively.

To simplify the integrand, we can use the identity:

cos(t) sin(t) = (1/2) sin(2t)

Substituting this into the integral, we get:

Area = 2ab ∫0^(π/2) sin(2t) dt

Using the substitution u = 2t, du = 2dt, the integral becomes:

Area = (ab/2) ∫0^π sin(u) du

Using the fact that the integral of sin(u) from 0 to π is 2, we get:

Area = ab

Therefore, the area enclosed by an ellipse with parametric equations x = a cos(t), y = b sin(t), 0 ≤ t ≤ 2π, is given by the equation ab.

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how many pairs of whole numbers have a geometric mean of 6?

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There are 5 pairs of whole numbers with a geometric mean of 6.

What is geometric mean?

The geometric mean is a type of average used to calculate the central tendency of a set of numbers, where the values are multiplied together and then the nth root of the product is taken, where n is the total number of values in the set.

Let's consider two whole numbers, a and b, with a geometric mean of 6. The geometric mean is defined as the square root of the product of the numbers, so we have:

√(ab) = 6

Squaring both sides of the equation, we get:

ab = 36

We want to find all pairs of whole numbers (a, b) that satisfy this equation. Since 36 has prime factorization 2² * 3², the only possible pairs of whole numbers are:

a = 1, b = 36

a = 2, b = 18

a = 3, b = 12

a = 4, b = 9

a = 6, b = 6

Therefore, there are 5 pairs of whole numbers with a geometric mean of 6.

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what techniques overcome resistance and help build credibility? check all that apply. including performance tests, polls, or awards sending unwanted merchandise using a celebrity name without authorization listing names of satisfied users what is illegal to include in a sales letter? check all that apply. free sample trials unauthorized use of a celebrity name misleading statements satisfied customer names

Answers

1) Including testimonials , Sending free trial samples techniques overcome resistance and help build credibility .Option (b,c)

2) A postscript should the final paragraph of your sales message include option (A)

1) The best way to overcome resistance is through persistence, patience, and understanding. Show empathy, communicate clearly and establish trust. Provide clear incentives and benefits to encourage change, and offer support throughout the process. Use positive reinforcement, celebrate small wins, and emerge as a positive role model.

2) A postscript is a brief additional note at the end of a letter or document. It is used to convey important information that was not included in the main body of the text. Sometimes, a postscript can be used to add a personal touch or to emphasize a point.

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Full Question: 1) What techniques overcome resistance and help build credibility? Check all that apply.

A. Sending unwanted merchandise

B. Including testimonials

C. Sending free trial samples

D. Using misleading statements

2) What should the final paragraph of your sales message include? Check all that apply.

A. A postscript

B. A puffery claim

C. A misleading statement

D. A punch line

True or False? Sequential interdependence exists when the output of operation A is the input of operation B, and the output of operation B is the input back again to operation A.

Answers

Sequential interdependence exists when the output of one operation becomes the input of the next operation, but it doesn't necessarily have to loop back to the original operation. The statement is false.

Sequential interdependence exists when the output of operation A is the input of operation B, but the output of operation B is not the input back again to operation A. In other words, the output of operation B depends on the output of operation A, but the output of operation A does not depend on the output of operation B.

The scenario described in the statement is an example of circular interdependence or a feedback loop, where the output of each operation depends on the output of the other.

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list the first five terms of the sequence. an = (−1)n − 1 3n a1 = a2 = a3 = a4 = a5 =

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The first five terms of the sequence are: -3, 6, -9, 12, and -15.

Repetition is permitted and order is important in the sequence, which is a predetermined group of objects. Formally, a sequence is a function that connects the elements at each point to natural numbers. It has members, which are known as elements or words, just like a set. The length of the sequence is determined by the number of items. In contrast to a set, the same items might appear more than once in a sequence at various points, and the order does important.

The idea of a sequence can be expanded to include an indexed order that is based on an index set that may or may not correspond to a distinct collection of components. Now, let's look at the definition, notation, and examples of sequences.

Given the formula an = (−1)^n - 1 * 3n, let's find the first five terms of the sequence:

a1 = (−1)^1 - 1 * 3(1) = -1 * 3 = -3
a2 = (−1)^2 - 1 * 3(2) = 1 * 6 = 6
a3 = (−1)^3 - 1 * 3(3) = -1 * 9 = -9
a4 = (−1)^4 - 1 * 3(4) = 1 * 12 = 12
a5 = (−1)^5 - 1 * 3(5) = -1 * 15 = -15

The first five terms of the sequence are: -3, 6, -9, 12, and -15.

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I just need this to be solved for my homework I don’t understand any of it.

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Both functions f(x) = (1/3^x) and g(x) = 3^x are exponential functions, but they differ in their behavior as x increases or decreases.

How to explain the function

The function f(x) approaches zero as x approaches infinity, while g(x) grows without bound as x increases. Another difference is that f(x) is a decreasing function while g(x) is an increasing function.

The correct key characteristic for the function f(x) = 5(3)^x with the domain of all real numbers is that it has a horizontal asymptote at y = 0. As x approaches negative infinity, the function approaches 0. The y-intercept of this function is 5, not 1.

The base or decay factor of the exponential decay function describing the construction equipment's value is 0.75, or 75%. This means that the equipment loses 25% of its value each year.

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choose the statement that best explains the use of the sample standard deviation in tests of the mean where the population standard deviation is not known.

Answers

The correct answer is option A. The sample standard deviation can be used as an estimate of the population standard deviation is the statement that explains the use of the sample standard deviation in tests of the mean when the population standard deviation is not known.

By taking the square root of the variance, the sample standard deviation—a measurement of the data's propagation derived. A sample, which is a smaller portion of the population, is used to calculate it.

The sample standard deviation can be used as an estimate of the population standard deviation because the population standard deviation is typically unknown.

Following that, confidence intervals and other tests of the mean can be computed using this.

The sample standard deviation is another tool used to assess the data's variability because it shows how dispersed the data exists.

Complete Question:

Choose the statement that best explains the use of the sample standard deviation in tests of the mean when the population standard deviation is not known:

A. The sample standard deviation can be used as an estimate of the population standard deviation.

B. The sample standard deviation can be used to measure the spread of the data.

C. The sample standard deviation can be used to calculate the confidence interval.

D. The sample standard deviation can be used to measure the variability of the data.

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What is the surface area of the prism? 10 in. 6 in 16 in. 10 in. 7 in.​

Answers

The surface area of the prism is 460 square inches.

What is the surface area?

The surface area of a prism is the sum of the areas of all its faces. The formula for finding the surface area of a prism depends on the shape of its bases. For example, the surface area of a rectangular prism can be found using the formula:

Surface Area = 2lw + 2lh + 2wh

where l, w, and h are the length, width, and height of the rectangular prism, respectively.

To find the surface area of the prism, we need to calculate the area of each of its faces and then add them up.

The prism has two rectangular faces, two square faces, and two parallelogram faces. The rectangular faces have dimensions of 10 in by 6 in, so their combined area is:

2 * (10 in * 6 in) = 120 in²

The square faces have dimensions of 10 in by 10 in, so their combined area is:

2 * (10 in * 10 in) = 200 in²

The parallelogram faces have base 10 in and height 7 in. To find the area of each parallelogram face, we multiply the base by the height:

2 * (10 in * 7 in) = 140 in²

Adding up the areas of all the faces, we get:

120 in² + 200 in² + 140 in² = 460 in²

Therefore, the surface area of the prism is 460 square inches.

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If f(x) = 0.5x2 - 2 and g(x) = 8x3 + 2, find the value of the following function.
(f · g)(x) = __x5 -__ x3 + __x2 - __

Answers

The function (f · g)(x) is equal to: 4x^5 - 16x^3 + x^2 - 4

How to find the value of the function stated

To find the product of two functions f(x) and g(x), we need to multiply them term by term, i.e.,

(f · g)(x) = f(x) * g(x)

Let's start by multiplying the two functions:

f(x) * g(x) = (0.5x^2 - 2) * (8x^3 + 2)

Expanding the brackets, we get:

f(x) * g(x) = 4x^5 + x^2 - 16x^3 - 4

So the value of the function (f · g)(x) is:

(f · g)(x) = 4x^5 - 16x^3 + x^2 - 4

Therefore, the function (f · g)(x) is equal to:

4x^5 - 16x^3 + x^2 - 4

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separable programming is applicable when there are increasing or decreasing marginal returns. (True or False)

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True, separable programming is applicable when there are increasing or decreasing marginal returns. This is because separable programming can handle cases with non-linear relationships, such as those involving increasing or addition decreasing marginal returns.

True. Separable programming is applicable when there are increasing or decreasing marginal returns, which refers to the change in the additional output that results from increasing the input by one unit. If the marginal returns are increasing, the additional output increases at a faster rate with each addition input. If the marginal returns are decreasing, the additional output increases slower with each additional input. Separable programming allows for optimizing the inputs and outputs separately, taking into account these marginal returns.

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Find an autonomous differential equation with all of the following properties:
equilibrium solutions at y=0 and y=5,
y′>0 for 0 y′<0 for −[infinity] dydt=

Answers

An autonomous differential equation with all of the following properties is dy/dx = -y(y - 5).

Autonomous differential equation is a type of ordinary differential equation that does not depend on an independent variable.

It is an equation of the form dy/dx = f(y), where the right side of the equation does not depend on the independent variable x.

The differential equation should be:

dy/dx = f(x, y)

The differential equation is zero at equilibrium points, i.e., dy/dx = 0 at y = 0 and y = 5.

The differential equation is therefore

dy/dx = y(y - 5)

Given that y' > 0 for 0 < y < 5.

Replace y = 2 in dy/dx = y(y - 5) and then check the dy/dx sign.

dy/dx = (2)(2 - 5)

dy/dx = 2(-3)

dy/dx = -6 < 0    not satisfied the condition

Consequently, add -1 to the function f(x, y).

As a result, the necessary function is dy/dx = -y(y - 5).

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The complete question is:

Find an autonomous differential equation with all of the following properties:

equilibrium solutions at y = 0 and y = 5,

y' > 0 for 0 < y < 3 and

y' < 0 for -∞ < y < 0 and 5 < y < ∞

dy/dx =

Vector V1 is 6.0 units long and points along the negative x axis. Vector V2 is 9.0 units long and points at 55° to the positive x axis. Determine the angle of the sum V1+V2

Answers

To find the angle of the sum V1+V2, we first need to find the sum of the two vectors.

Vector V1 points along the negative x-axis, so it can be represented as     V1 = -6i (where i is the unit vector in the x-direction).
Vector V2 points at 55° to the positive x-axis, so it can be represented as  V2 = 9cos(55°)i + 9sin(55°)j (where j is the unit vector in the y-direction).

Adding these two vectors gives us:
V1 + V2 = -6i + 9cos(55°)i + 9sin(55°)j
= (9cos(55°) - 6)i + 9sin(55°)j

Now we can find the angle of this vector by using the arctangent function:

angle = arctan(9sin(55°)/(9cos(55°) - 6))
Plugging in the values, we get:
angle = arctan(1.12)
angle ≈ 48.2°

Therefore, the angle of the sum V1+V2 is approximately 48.2°.

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A sphere has a diameter of 9 millimeters.
9mm
What is its volume, to the nearest cubic millimeter?

Answers

- Answer: the volume of the sphere to the nearest cubic millimeter is approximately 381.7 cubic millimeters.


To calculate the volume of a sphere, we use the formula:

V = (4/3) * π * r^3

where V is the volume, π is a mathematical constant approximately equal to 3.14159, and r is the radius of the sphere.

Since we are given the diameter of the sphere, which is 9 millimeters, we can calculate the radius by dividing it by 2:

r = d/2 = 9mm/2 = 4.5mm

Now we can substitute this value into the formula:

V = (4/3) * π * (4.5mm)^3
V ≈ 381.7 cubic millimeters

at 9:30 am, andrew left exeter for portsmouth, cycling at 12 mph. at 10:00 am, stacy left portsmouth for exeter, cycling at 16 mph. the distance from exeter to portsmouth is 20 miles. find the time when they met.

Answers

According to the distance, Andrew and Stacy will meet 0.5 hours after Stacy starts her journey from Portsmouth, which would be at 10:30 am.

To solve this problem, we will use the concept of distance, speed, and time. The distance between Exeter and Portsmouth is given as 20 miles. Andrew starts his journey at 9:30 am and cycles at a speed of 12 mph. Stacy starts her journey at 10:00 am from Portsmouth and cycles at a speed of 16 mph.

Let's consider the distance traveled by Andrew and Stacy before they meet. Suppose they meet after a time of "t" hours, and let's assume that Andrew has traveled "d1" miles from Exeter towards Portsmouth, and Stacy has traveled "d2" miles from Portsmouth towards Exeter.

Since Andrew starts half an hour earlier than Stacy, he would have traveled for "t + 0.5" hours before they meet. Hence, the distance traveled by Andrew would be:

d1 = speed x time = 12 x (t + 0.5) miles

Similarly, Stacy would have traveled for "t" hours before they meet. Hence, the distance traveled by Stacy would be:

d2 = speed x time = 16 x t miles

Now, we know that the total distance between Exeter and Portsmouth is 20 miles. Therefore, the sum of the distances traveled by Andrew and Stacy should be equal to 20 miles when they meet.

d1 + d2 = 12(t + 0.5) + 16t = 20

Simplifying the equation, we get:

28t + 6 = 20

28t = 14

t = 0.5

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plssssss helppppppppppp

Answers

Answer:

1: biggest one and 2. the smallest one 3. biggest one

4. medium one 5.all students

Step-by-step explanation:

I am not sure

In a class of 30 students, 12 of them have a cat,
14 of them have a dog and 8 of them have neither.
Find the probability that a student chosen at random
has a cat and a dog.
You may wish to complete the Venn diagram to help you.
E
Cat
Dog

Answers

Answer:

Step-by-step explanation:

Let A and B be two events in a sample space for which Pr(A) - 0.9923, Pr(B) = 0.0355700000000001 and Pr(AB) 0.02787. a. What is Pr(AUB)? b. What is Pr(AIB)? c. What is Pr(BIA)? d. What is Prt 2 )? e. What is Pr(A)? f. What is Pr(BP)? g. What is Pr((AUB)')?

Answers

For two events A and B in a sample space (a) Pr(AUB) = 1.0000000000001. (b) Pr(AIB) = 0.7840058543652 (c) Pr(BIA) =0.0280920459043 (d) Pr(A') = 1 - Pr(A) = 0.00769999999999996. (e) Pr(A) = 0.9923. (f) Pr(B') = 0.96443. (g) Pr((AUB)') = -1.11022302462516 x 10^-16.

Let A and B be two events in a sample space for which Pr(A) - 0.9923, Pr(B) = 0.0355700000000001 and Pr(AB) 0.02787 then :

a. To find Pr(AUB), we use the formula: Pr(AUB) = Pr(A) + Pr(B) - Pr(AB)
Plugging in the given values, we get: Pr(AUB) = 0.9923 + 0.0355700000000001 - 0.02787 = 1.0000000000001

b. To find Pr(AIB), we use the formula: Pr(AIB) = Pr(AB)/Pr(B)
Plugging in the given values, we get: Pr(AIB) = 0.02787/0.0355700000000001 = 0.7840058543652

c. To find Pr(BIA), we use the formula: Pr(BIA) = Pr(AB)/Pr(A)
Plugging in the given values, we get: Pr(BIA) = 0.02787/0.9923 = 0.0280920459043

d. Pr(A') = 1 - Pr(A) = 0.00769999999999996.

e. Pr(A) is given as 0.9923.

f. Pr(B') = 1 - Pr(B) = 0.96443.


g. To find Pr((AUB)'), we use the formula: Pr((AUB)') = 1 - Pr(AUB)
Plugging in the value we found in part (a), we get: g. Pr((AUB)') = 1 - Pr(AUB) = -1.11022302462516 x 10^-16.
Note that this result is not a valid probability since probabilities must be between 0 and 1.

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let a 5 {a, b}, b 5 {1, 2}, and c 5 {2, 3}. find each of the following sets.

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To find the Cartesian products of three sets: A = {a, b}, B = {1, 2}, and C = {2, 3}, you need to form all possible ordered pairs from the given sets.

1. A x B: This is the set of all ordered pairs with the first element from set A and the second element from set B.
A x B = {(a, 1), (a, 2), (b, 1), (b, 2)}

2. A x C: This is the set of all ordered pairs with the first element from set A and the second element from set C.
A x C = {(a, 2), (a, 3), (b, 2), (b, 3)}

3. B x C: This is the set of all ordered pairs with the first element from set B and the second element from set C.
B x C = {(1, 2), (1, 3), (2, 2), (2, 3)}

These are the Cartesian products of the sets A, B, and C.

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a researcher has gathered the number of soft drinks teenagers drink on a daily basis by taking a random sample of 1500 teenagers from around the world. we find that our data shows that the mean is larger than the median. what does this tell us about the shape of the distribution?

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The fact that the mean is larger than the median in a sample of 1500 teenagers suggests that the distribution of soft drink consumption is skewed to the right.

Assuming the mean is bigger than the middle in a dataset, it by and large proposes that the dispersion of the information is slanted to one side, with a more extended tail on the right half of the circulation. For this situation, the information on the quantity of sodas young people drink consistently may have a few outrageous qualities on the better quality, making the mean be pulled towards the right half of the dispersion. Nonetheless, it is vital to take note of that this end depends with the understanding that the example is illustrative of the whole populace of teens all over the planet, and that the example was gathered and examined appropriately.

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the chi-square values (for interval estimation) for a sample size of n=10 at 95% confidence: a. 2.700 and 19.023 b. 3.325 and 16.919 c. 4.168 and 14.684 d. 3.247 and 20.483 e. none of the above answers is correct

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The chi-square values for a sample size of n=10 at 95% confidence are 2.700 and 19.023, which corresponds to option (a).

1. Identify the degrees of freedom: Since the sample size is n=10, the degrees of freedom (df) will be n-1 = 9.
2. Look for the chi-square values corresponding to 95% confidence level: For a 95% confidence interval, we will look for the values corresponding to 2.5% (0.025) in the lower tail and 97.5% (0.975) in the upper tail of the chi-square distribution table.
3. Locate the values in the table: Using the table, find the chi-square values for df=9 and the specified tail probabilities.

Based on the chi-square distribution table, the values corresponding to df=9 at 95% confidence are:
a. 2.700 (for 0.025 tail probability) and 19.023 (for 0.975 tail probability).

So, the chi-square values for a sample size of n=10 at 95% confidence are 2.700 and 19.023, which corresponds to option (a).

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Help ASAP! Timed! State the domain and range of the graph in interval notation.

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Answer:

Step-by-step explanation:

find the distance traveled by a particle with position (x, y) as t varies in the given time interval. x = 3 sin2(t), y = 3 cos2(t), 0 ≤ t ≤ 5

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To find the distance traveled by a particle with position (x, y) as t varies in the given time interval, we need to calculate the length of the path traced by the particle. We can evaluate this integral using a substitution method or a numerical approach to find the exact distance traveled by the particle in the given time interval.

The position functions are x = 3sin^2(t) and y = 3cos^2(t) in the interval 0 ≤ t ≤ 5.

Find the derivatives of the position functions with respect to t.
dx/dt = d(3sin^2(t))/dt = 6sin(t)cos(t)
dy/dt = d(3cos^2(t))/dt = -6sin(t)cos(t)

Calculate the magnitude of the velocity vector.
|v| = sqrt((dx/dt)^2 + (dy/dt)^2) = sqrt((6sin(t)cos(t))^2 + (-6sin(t)cos(t))^2)

Simplify the expression.
|v| = sqrt(36sin^2(t)cos^2(t) + 36sin^2(t)cos^2(t)) = sqrt(72sin^2(t)cos^2(t))

Integrate |v| over the interval [0, 5] to find the distance traveled.
Distance traveled = ∫|v| dt from 0 to 5 = ∫(sqrt(72sin^2(t)cos^2(t))) dt from 0 to 5

Now, you can evaluate this integral using a substitution method or a numerical approach to find the exact distance traveled by the particle in the given time interval.

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Sammy wrote the following proof. What did he do wrong?

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While solving the proof, Sammy made a mistake as option b), he assumed secθ = 1/sinθ but secθ = 1/cosθ

Here we see that in the first line, Sammy writes

cos²θ . tan²θ = cos²θ(sec²θ -1)

This is definitely correct as 1 + tan²θ = sec²θ

Now, in the next line, he expanded the expression by solving the brackets to get

cos²θ . tan²θ = cos²θ . sec²θ - cos²θ

Now, he changes the sec²θ expression. We know that,

secθ = 1/cosθ

Hence, sec²θ = 1/cos²θ

But, Sammy wrote, 1/sin²θ, hence he was wrong here.

Therefore, the correct proof will be

cos²θ . tan²θ = cos²θ/cos²θ - cos²θ

or, cos²θ . tan²θ = 1 - cos²θ

= sin²θ

Hence Sammy assumed secθ = 1/sinθ but secθ = 1/cosθ and made a mistake

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the null hypothesis is stated in terms of the population, even though the data come from a sample. (True or False)

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True. The null hypothesis (denoted as H0) is a statement about a population parameter, typically a population mean or proportion, and it is formulated based on the assumption that there is no effect, relationship, or difference in the population.

However, in statistical hypothesis testing, data is often collected from a sample, not the entire population, due to practical limitations.

The sample data is then used to assess the evidence against the null hypothesis.

The null hypothesis is always stated in terms of the population, even though the data being analyzed comes from a sample.

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