Answer:
Density Definition: Density is the measurement of how tightly a material is packed together. It is defined as the mass per unit volume. Density Symbol: D or ρ Density Formula: ρ = m/V, where ρ is the density, m is the mass of the object and V is the volume of the object.
A bicyclist accelerates from her initial velocity at a rate
of 0.50 meters per second squared for 4.0 seconds.
During this time, she covers a distance of 44 meters.
What is the bicyclist's initial velocity?
Answer:
We can use the equation:
distance = initial velocity * time + (1/2) * acceleration * time^2
We know that the distance is 44 meters, the acceleration is 0.50 meters per second squared and the time is 4.0 seconds.
By substituting these values into the equation:
44 = initial velocity * 4.0 + (1/2) * 0.50 * 4.0^2
Solving for initial velocity, we get:
initial velocity = (44 - 2) / 4 = 42 / 4 = 10.5 meters per second.
So, the bicyclist's initial velocity is 10.5 meters per second.
Object A, which has been charged to +4.0 nC is at the origin. Object B, which has been charged to −8.0 nC, is at (x,y)=(0.0 cm, 2.0 cm).
What is the electric force on B due to A in component form?
What is the electric force on A due to B in component form?
The electric force on B due to A in component form is -7.2 x 10^-4N and the electric force on A due to B in component form is +7.2 x 10^-4N.
Given the charge on object A (q1) at origin = +4.0 nC
The charge on object B at (x,y) is (q2) = −8.0 nC
The position of object B = (0.0 cm, 2.0 cm).
Soo, the distance from origin to object B is (r) = 2cm = 0.02m on y-axis.
From Coulombs law, we know that Fc = kq1q2/r^2 where k is electrostatic constant = 9 x 10^9Nm^2/C^2
The electric force on B due to A in component form is Fq1q2
Then, Fq1q2 = 9 x 10^9 x (+4 x 10^-9)(-8 x 10^-9)/0.02 x 0.02
Fq1q2 = -7.2 x 10^-4N
The electric force on A due to B in component form is Fq2q1
Then, Fq2q1 = 9 x 10^9 x(-8 x 10^-9) (+4 x 10^-9)/0.02 x 0.02
Fq2q1 = 7.2 x 10^-4N
Here, the electric force on B due to A and on A due to B is same in magnitude but the direction of force changes.
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find the volume of the parallelepiped (box) determined by u, v, and w.
The volume of the parallelepiped determined by u, v, and w is| w · ( u × v)|.
In geometry, a parallelepiped is a three-dimensional figure made up of six parallelograms. Similar to a parallelogram, just like a cube is a square. The volume of the parallelepiped enclosed by a, b, and c is: Volume = area of the base and height = |a×b∥c||cosφ|=|(a×b)·c| The formula comes from the properties of the cross product. The area of the base of the parallelogram is |a×b| and the vector a×b is perpendicular to the base. The height of the cube is |c||cosφ|. Therefore, the volume of the parallelepiped determined by u, v, and w is| w · ( u × v)|.
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How much force is required to stop a 0.25 Kg ball moving at 5 m/s during a time of 0.01
seconds?
The force required to stop a 0.25 Kg ball moving at 5 m/s during a time of 0.01 seconds is 2.5 Newtons.
How much force is required to stop a 0.25 Kg ball moving at 5 m/s during a time of 0.01 seconds?This can be calculated using the equation F = m*a, where m is the mass of the object (0.25 Kg) and a is the acceleration (5 m/s/0.01 seconds).Thus, F = 0.25 * 5 = 2.5 N.The force required to stop a 0.25 Kg ball moving at 5 m/s during a time of 0.01 seconds is 12.5 N. This is a type of impulse force, which is a force that acts over a period of time rather than a single instantaneous force. Impulse forces are typically used to change momentum. In this case, the impulse force is being used to reduce the momentum of the ball from 5 kgm/s to 0 kgm/s in the space of 0.01 seconds.This is achieved by applying a force of 12.5 N over the 0.01 second period. This is known as an impulse force because it is applied over a period of time, rather than in a single instantaneous action. This type of force is often used in physics problems to determine the momentum of a moving object, as it allows for the calculation of the force needed to stop the object in a certain amount of time.To learn more about impulse force refer to:
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a merry-go-round is initially at rest. it accelerates constantly until its final angular speed is 10 rad/s and it completes 3 rotations in the process. what angular acceleration does the carousel have during this time?
The angular acceleration of the merry-go-round starting from rest to a velocity of 10 rad/s and completing 3 rotations is 2.67 rad/s².
Angular Acceleration is defined as the rate of change of angular velocity per unit time. It is usually expressed in radians per second square. The angular acceleration is also called rotational acceleration. The angular acceleration is expressed as, α= ΔωΔt, where Δω is the change in angular velocity and Δt is the change in time. The merry-go-round is initially at rest. So, the initial angular velocity is 0. The number of rotations completed in this process is 3 rotations. The final angular velocity is 10 rad/s. The angular displacement is( 3×2π) rad. So angular acceleration is given by the equation, a=w²/2×d=10×10/2×3×2π= 2.67 rad/s².
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tiger woods hit a golf ball at a velocity of 80 m/s. the head of his club was in contact with the 50 g ball for 0.40 ms. what is the average force acting on the golf ball during impact?
The average force acting on the golf ball during impact is 200,000 Newtons.
The average force acting on the golf ball during impact can be calculated using Newton's second law of motion. The equation is F = ma, where F is the force, m is the mass of the object, and a is the acceleration. Since the mass of the golf ball is 50g (0.05 kg), and the acceleration is determined by the velocity of the ball and the time it is in contact with the club (80 m/s divided by 0.0004 s), the average force acting on the golf ball during impact is 200,000 Newtons.
F = ma
m = 50g or 0.05kg
a = v/t
a = 80/0.0004 ( as velocity "v" = 80 m/s and time "t" = 0.40ms which is equal to 0.0004 s ).
Put the values of "a" and "m" in equation F = ma
therefore, F = 0.05 ( 80/0.0004 )
F = 200,000 N
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what is replicability in tok
Replicability in the context of the theory of knowledge (ToK) refers to the ability of a knowledge claim or scientific experiment to be repeated and produce consistent results.
In ToK, replicability is seen as an important criterion for evaluating the reliability and validity of knowledge claims. When a scientific experiment is replicated and produces consistent results, it increases the confidence that the original experiment was correctly designed and executed, and that the results accurately reflect the underlying phenomena being studied. Conversely, if a scientific experiment cannot be replicated, it calls into question the validity of the original experiment and the knowledge claims that were based on its results.
In addition to its importance in the evaluation of scientific knowledge, replicability is also a key aspect of the process of scientific inquiry. By attempting to replicate previous experiments, scientists can build on existing knowledge and add to the body of scientific evidence in support of a particular hypothesis or theory.
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What is the total mechanical energy of a mass of 2 kg oscillating on a spring given that the maximum velocity of the mass is 5 m/s and the spring constant is 50 N/m?
Answer:
The total mechanical energy of a mass oscillating on a spring is given by the sum of its kinetic energy and potential energy. The kinetic energy of the mass is given by (1/2) * m * v^2 and the potential energy is given by (1/2) * k * x^2 where m is the mass, v is the velocity, x is the displacement and k is the spring constant.
Given that the mass is 2 kg and the maximum velocity is 5 m/s, the kinetic energy is (1/2) * 2 * (5)^2 = 25 J.
Given that the spring constant is 50 N/m, the potential energy at maximum displacement is (1/2) * 50 * x^2 but we don't know the displacement x, so we can't calculate the potential energy. But the total mechanical energy is the sum of kinetic energy and potential energy, so we don't need to know the potential energy, we can calculate the total mechanical energy as 25 J
So the total mechanical energy is 25 J.
april has 3 hours to spend training for an upcoming race. she completes her training by running full speed the distance of the race and walking back the same distance to cool down. if she runs at a speed of 10mph and walks back at a speed of 2mph , how long should she plan to spend walking back?
April should plan to spend walking back after 3 hours training for an upcoming race and runs at a speed of 10mph and walks back at a speed of 2mph = 30 minutes.
How to determine the time to spend walking back?First, determine the distance,
d = speed x time
The distance = 10
The speed = 2 mph
The time = (3 - x hours)
Let's say 'x' represents the amount of time spent running in hours, and 3-x represents the amount of time spent walking in hours.
Hence,
10x = 2(3 - x)
10x = 6 - 2x
12x = 6
x = [tex]\frac{1}{2}[/tex] hour
= 30 minutes
So, April should she plan to spend walking back in 30 minutes.
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what element seems poorly placed in group ia (1), the alkali metals?
The element which seems poorly placed in group ia (1), the alkali metals is hydrogen.
Methane is the most prevalent chemical element and is thought to make about 75% of the universe's mass. Numerous hydrogen atoms can be found in water, plants, animals, and, of course, people here on earth. The lightest element is hydrogen. Under normal circumstances, hydrogen is a gas made up of diatomic molecules with the formula H2. It is non-toxic, tasteless, colourless, odourless, and extremely flammable.
Alkali metals are extremely reactive, hence they are almost never encountered in nature in their elemental state instead appearing as ionic compounds (except for hydrogen).
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help me please pleass please i beg
There are three states of matter.
What are the states of matter?There are three states of matter and these are the solid, the liquid and the gas. We have to note that the way that the states of matter are found would depend on the arrangement and the movement of the particles that are in each of the states of matter as we know it.
In this case we know that the liquid and the gases are compressible but the solid is nnot compressible. The sold has a fixed shape but the liquid and the gas does not. The liquid and the solid have a definite volume but the gas does not.
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According to the first law of thermodynamics, the sum of the heat gained by a system and the work done on that same system is equivalent to which of the following? (2 points) a. entropy change c. temperature change b. internal energy change d. specific heat
According to the first law of thermodynamics, the sum of the heat gained by a system and the work done on that same system is equivalent to internal energy change.
The first law of thermodynamics is based on the principle of the conservation of energy. The principle of conservation of energy states that energy cannot be created or destroyed. It can, however, be transferred from one location to another and converted to and from other forms of energy.
The first law of thermodynamics states that the total internal change of a system is the sum of the algebraic sum of the heat gained by a system and the work done on that system.
Hence, the internal energy change is the correct option.
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Suppose you conduct one experiment and find that the E = mc3, rather than the historically accepted formula, E = mc2. What should you do next?
a. Test a new variable
b. Share your findings
c. Apply your results to a new experiment
d. Repeat the exact same procedure
Suppose you conduct one experiment and find that the E = mc3, rather than the historically accepted formula, E = mc2. Then you have to repeat the exact same procedure
E = mc2. The most well-known equation in the world, but what does it actually mean? "Mass times the square of the speed of light equals energy." The equation's most fundamental claim is that energy and mass (matter) are interchangeable; they are just different manifestations of the same thing.
The answer to the question "Why does E=mc2?" is thus straightforward and elegant: "Because everything is always traveling through spacetime." By seeing the situation correctly, we can understand that the rest energy that we weren't expecting is simply a result of the time component of that motion.
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conclusions: why did you not take a volume reading for the butane gas at 0 °c?
The volume reading is not taken because butane's boiling point is close to 0 C.
These instances of how temperature can change a confined gas's volume while maintaining a constant pressure are typical: The volume rises with rising temperature and falls with falling temperature. Pressure and volume are inversely related for an ideal gas with a fixed mass maintained at a fixed temperature. Boyle's law, another gas law, states that there is an inverse relationship between a gas's pressure and volume. When the temperature is held constant, pressure decreases as volume increases and vice versa. Plots of gas volume vs temperature extrapolate to zero volume at absolute zero (0 K), which is 273.15°C, the lowest temperature imaginable. The volume of a gas is thought to be directly proportional to its absolute temperature according to Charles' law.
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A 40.0 kg projectile leaves a 2200 kg launcher with a speed of 800 m/s. What is
the recoil velocity of the launcher?
A 40.0 kg projectile leaves a 2200 kg launcher with a speed of 800 m/s. 10m/s is the recoil velocity of the launcher.
How does one calculate recoil velocity?
The recoil velocity of the launcher can be calculated using the law of conservation of momentum. According to this law, the momentum of the projectile leaving the launcher must be equal to the momentum of the recoiling launcher. Therefore, the momentum of the projectile is equal to the momentum of the launcher.
The momentum of the projectile is equal to the product of its mass and velocity:
Momentum of the projectile = 40.0 kg x 800 m/s = 32,000 kg m/s
The momentum of the launcher is also equal to the product of its mass and velocity:
Momentum of the launcher = 2200 kg x V (velocity of the launcher)
Therefore, the recoil velocity of the launcher can be calculated by solving for V:
32,000 kg m/s = 2200 kg x V
V = 32,000 kg m/s/2200 kg
V = 14.545 m/s
Therefore, the recoil velocity of the launcher is 14.545 m/s.
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Two objects with different masses and different velocities have the same momentum. What must be true of the velocity of the more massive object?
Answer: i think the answer is b
Explanation:
Answer:
The more massive object has a slower velocity than the lesser massive object.
Explanation:
Let M1 be the mass of the more massive object. M2 be the mass of less massive object. V1 be the mass of more massive object. V2 be the mass of less massive object. It is told that their momenta are the same. So M1V1= M2V2 or M1/M2= V2/V1.Also M1 is greater than M2.
From the equation we got M1/M2= V2/V1.
This means V2/V1 is greater than 1.
Which means V2 is greater than V1.
The object with more mass has lesser velocity than object with less mass.
Thus the answer to your problem is, The more massive object has a slower velocity than the lesser massive object.
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PART A
First, record some data for this comparison below.
Record your measured values of displacement and velocity for times t = 8.0 seconds and t = 10.0 in the columns below.
Next, use the measured displacment and velocity values at t = 7.0 seconds and t= 9.0 seconds to interpolate the values of displacement and velocity at t = 8.0 seconds.
Use the followinf formula to interpolate and extrapolate. Remember, x and y here represent values om the x and y axes of the graph. The x values will really be time and the y values will either be displacement (x) or velocity (vx).
(formula included in picture)
The displacement at 8.0 seconds is 19.08 m.
The velocity at 8.0 seconds is -0.06 m/s.
What is the displacement and velocity of the particle?
The displacement and velocity of the particle is calculated by applying interpolation and extrapolation.
8.0 s --------> 19.08 m
10.0 s --------> 16.81
8.0 s --------> x
(8 - 10 ) / ( 10 - 8 ) = ( 19.08 - 16.81 ) / ( 16.81 - x )
(-2 ) / ( 2 ) = ( 2.27 ) / ( 16.81 - x )
-1 (16.81 - x ) = 2.27
16.81 - x = -2.27
x = 16.81 + 2.27
x = 19.08 m
The velocity at 8.0 seconds is calculated as follows;
8.0 s ---------------> -0.06 m/s
10.0 s ---------------> -2.39 m/s
8.0 s ----------------> x
( 10 - 8 ) / ( 10 - 8 ) = ( -2.39 - - 0.06 ) / ( -2.39 - x )
1 = ( -2.33 ) / ( -2.39 - x )
-2.39 - x = -2.33
x = 2.33 - 2.39
x = -0.06 m/s
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two football players with mass of 75 kg and 100 kg run towards each other with a combined speed of 6 m per second and 8 m per second respectively. if they grab each other as they collide the combines speed of the two players just after the collision would be
When two objects collide and stick together, their combined speed after the collision can be calculated using the conservation of momentum principle. The principle states that the total momentum of an isolated system remains constant if no external forces act on it.
In this case, the initial momentum of the two players before the collision can be calculated as follows:
75 kg * 6 m/s + 100 kg * (-8 m/s) = 450 kg m/s
After the collision, the players stick together, and their combined speed can be calculated as follows:
Final momentum = (75 kg + 100 kg) * v
450 kg m/s = 175 kg * v
v = 450 kg m/s / 175 kg = 2.57 m/s
So, the combined speed of the two players just after the collision would be 2.57 m/s.
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I used up all my tries for part a and I'm honestly stuck. I know it has something to do with the conservation of energy but I can't figure it out :(
a. Find d, the initial displacement of the spring-block system (in cm).
b. Find the speed of the block when it reaches the equilibrium position. (in m/s)
c. How fast is the block moving when it reaches a position 4.00 cm to the left of its equilibrium position?
d. Assuming friction not negligible, find the coefficient of kinetic friction between the block and the surface if the block-spring system compresses 0.300 cm from the equilibrium position before stopping and moving back to the right?
Using the equation of motion:
1/2mv^2 = 1/2kx^2
where
m is the mass of the block,
v is the velocity
x is the displacement from the equilibrium position
we can find the initial displacement, d.
b. To find the speed of the block when it reaches the equilibrium position, we can use the conservation of mechanical energy.The total mechanical energy of the system is the sum of the kinetic energy and potential energy.
Initial Potential energy = 1/2kd^2
Final kinetic energy = 1/2mv^2
so,
v=sqrt(2*(1/2kd^2))/m
c. The speed of the block when it reaches a position 4.00 cm to the left of its equilibrium position will be the same as when it reaches the equilibrium position. Because the speed will be at its maximum at the equilibrium position.d. To find the coefficient of kinetic friction between the block and the surface, we can use the work-energy theorem, which states that the work done on an object is equal to the change in kinetic energy of the object.Work done = change in kinetic energy
The work done by friction is equal to the force of friction multiplied by the distance over which the force acts.
Friction force = friction coefficient * normal force
Friction force = friction coefficient * m * g
work done = friction force * distance
By putting the value of friction force and work done we can find the coefficient of kinetic friction.
Hooke's Law
Hooke's Law states that the force (F) required to extend or compress a spring by some distance x is proportional to that distance. Mathematically, it is represented as F = kx, where k is the spring constant and is unique to the spring. This relationship is only valid for small displacements, and assumes that the spring is not stretched beyond its elastic limit.
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light traveling in air enters a material at an angle of 30 degrees with respect to the normal. the refracted beam in the material makes an angle of 15 degrees with respect to the normal. calculate the index of refraction of the material.
The index of refraction of the material is 1.93
To calculate the index of refraction (n) of the material, we can use the formula:
n = sin(angle of incidence) / sin(angle of refraction)
In this case, the angle of incidence is 30° and the angle of refraction is 15°. Therefore:
n = sin(30°) / sin(15°)
n = 1.93
So the index of refraction of the material is 1.93.
It's worth noting that in general, when the angle of incidence is smaller, the angle of refraction will be smaller as well, so the refracted beam will be closer to the normal. And the index of refraction is inversely proportional to the sine of the angle of incidence and refraction.
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A certain spring elongates 9 mm when it is suspended vertically anda block of mass M is hung on it. The natural frequency ofthis mass-spring system is?
A certain spring elongates 9 mm when it is suspended vertically and a block of mass M is hung on it. The natural frequency of the mass-spring system obtained is [tex]5.25\ Hz[/tex].
Given:
Elongation of the spring is given by [tex](x) = 9\ mm = 9 \times 10^{-3}\ m[/tex]
Acceleration due to gravity [tex](g) = 9.8 m/s^2[/tex]
Find the natural frequency (f) of the mass-spring system the steps are given below.
The spring constant (k) is given by:
[tex]k = (M \times g) / x\\k = (M \times 9.8) / (9 \times 10^{-3}) \\k= 1088.89 \times M\ N/m[/tex]
The natural frequency formula is given by:
[tex]f = (1 / 2\pi) \times \sqrt\(k / M)[/tex]
Substitute the value of k as follows:
[tex]f = (1 / 2\pi) \times \sqrt\(1088.89 * M / M\)\\f = (1 / 2\pi) \times \sqrt\(1088.89\)[/tex]
Calculate the square root and the value of frequency is obtained:
[tex]f = (1 / 2\pi) \times 32.995 \\f = 5.25\ Hz[/tex]
Hence, the natural frequency of the mass-spring system is obtained approximately [tex]5.25\ Hz[/tex].
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a drone has a frequency of 2.11 ghz (gigahertz). what wavelength is associated with this frequency?
The wavelength of the drone which is associated with the frequency of 2.11 Ghz is 0.111 m.
λ = c / f = ( 3 x 10^8 ) / ( 2.71 x 10^8 ) = 0.111 m.
where lambda is the wavelength, c is the speed of light and f is the frequency.
What is wavelength?
The distance between repeating components of a wave, like electromagnetic waves, is known as its wavelength (e.g. light, radio waves). The Greek letter lambda is frequently used to symbolize it, and it is typically expressed in meters.
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Drew currently walks two miles every day after school but wants to take his workout to the next level. Which of these changes would you suggest he make to his routine to increase his stamina?
Answer:
Explanation:
Drew could run instead of walk after school.
I need help please mark you answers with the question Ex: Question: 1 The answer is __
thank you
The velocity of an object includes direction of the motion of an object whereas speed does not include direction. Thus, the correct options for 1, 2, 3, 4, and 5 are B, B, A, A, and B, respectively.
What is Velocity?Velocity can be defined as the directional speed of an object in the motion as an indication of the rate of change in the position of an object as observed from a particular frame of reference by the observer and as measured by a particular standard of time.
The velocity is different from that of speed as it is a vector quantity, the velocity of an object includes direction of the motion of an object whereas speed does not include direction.
Track runners cover same distance however, the winner in the race is the one who covers the particular distance in less time than other competitors.
The slowest runner in the graph is the one represented with blue color. This is because, this runner took maximum time to cover the distance.
The distance covered by the train is 300 miles in time period of 6 hours. Therefore, the speed of the train will be the distance covered by the train divided by the total time taken.
Speed of the train = 300 miles/ 6 hours
Speed of the train = 50 miles per hour.
The example of velocity is the one with the unit of length per time. From the given options, 80 miler per hour is an example of velocity as miles is the unit of length and hour is the unit of time.
Therefore, the correct options for 1, 2, 3, 4, and 5 are B, B, A, A, and B, respectively.
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A horizontal force of 3 N is exerted on an object while a vertical force of 4 n is exerted at the same time. calculate the resultant force on the object.
Answer:
resultant force = 5N
Explanation:
Answer:
5N
Explanation:
Horizontal Force = 3N
Vertical Force = 4N
Resulting force (magnitude) = √(4² + 3²)
= 5 N
the lower heating value of methane is 50,016 kj/kg. determine the heating value per mass of mixture
The heating value per mass of mixture of methane is found to be 2760 kj/kg-mix.
If the latent heat of vaporisation of water in the reaction products is not recovered, the lower heating value of a fuel is defined as the amount of heat released by combusting a particular quantity (at first at 25°C) and returning the temperature of the combustion products to 150°C. Taking into consideration the latent heat of vaporisation of water in the combustion products, the greater heating value of a fuel is defined as the amount of heat released by a particular quantity (originally at 25°C) once it has been burned and the products have returned to that temperature.
Given,
Lower heating value of methane is 50.016 kj/kg at 298 K.
So, To determine the heating value per mass of mixture,
Let us assume that mixture behaves as an ideal gas and P = 1 atm.
Stoichiometric relation: CH4 + aO2 + 3.76aN2 → CO2 + 2H2O + 3.67aN2
For P = 1 a = x + y/4 where x = 1 and y = 4
a = 2.
Now, then
A/F = 4.67a MWair/MWfuel = 4.67(2) 28.85/16.043 = 17.12 kg-air/kg-fuel
LHV[kj/kg-mix] = LHV[kj/kg-fuel] (1/1 + A/F )(kg-fuel/kg-mix)
LHV[kj/kg-mix] = (50016 kj/kg-f)( 1/1 + 17.12 kg-fuel/kg-mix)
LHV = 2760 kj/kg-mix.
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we now know that the total rest energy of the particle equals the sum of the rest energy of all constituents minus the total binding energy?
Yes, that is correct. In particle physics, the total rest energy of a particle is equal to the sum of the rest energies of all its constituent particles minus the total binding energy.
The rest energy of a particle is the energy it has when it is at rest, and it is equal to the mass of the particle multiplied by the speed of light squared(E = mc²). On the other hand, the binding energy is the energy required to separate a particle into its constituent particles, and it is a measure of the stability of the particle.
Therefore, the total rest energy of a particle is equal to the sum of the rest energies of all its constituent particles minus the binding energy, which represents the energy that holds the particles together.
--The given question is incomplete, the complete question is:
"Is it correct that the total rest energy of the particle equals the sum of the rest energy of all constituents minus the total binding energy?"--
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a study hall is 5.4 m long and 5.7 m wide and 10. m high. if the air conditioner provides 434.7 cu ft. of air/min, how long (in minutes) will it take for the air into the room to be completely replaced once? 1 m
For the air in the room to be completely replaced once, it will take 24.85 minutes if the air conditioner provides 434.7 cu ft. of air/min.
The volume of the study hall can be calculated as
5.4 m × 5.7 m × 10 m = 308.18 cubic meters.
Converting the airflow rate of the air conditioner from cubic feet to cubic meters, we get 434.7 cu ft/min = 12.3824 m³/min.
Therefore, it would take 308.18 / 12.3824 = 24.85 minutes for the air in the room to be completely replaced once.
It's important to note that this calculation assumes ideal conditions with no air leakages, no air being added to the room, and a constant air flow rate. In reality, the actual time it takes for the air in the room to be completely replaced will depend on various factors such as air leaks, people entering and leaving the room, and variations in the airflow rate of the air conditioner.
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Write two ways of reducing friction
Answer:
Explanation:
The two ways of reducing friction are by:
1) applying lubricants (like oil or grease)
2) by converting static or sliding friction into rolling friction with the help of wheels or ball bearings.
a landscape engineer has 200 feet of border to enclose a rectangular pond. what dimensions will result in the largest pond?
The required dimensions which will result in the largest pond are calculated to be l = 50 feet, b = 50 feet.
The perimeter of the rectangular pond is given as 200 feet.
Mathematically, we know perimeter = 2( l + b)
So, 2( l + b) = 200
( l + b) = 100
Breadth = 100 - length
The area of rectangle = l b
A = l (100 - l) = -l² + 100 l
The function has a maximum and the parabola opens down if the x² coefficient is negative.
A = -x² + 100 x
We have a < 0, so f(x) has a maximum,
we know that, f(-b/2a) = maximum
l = -b/2a = -100/2(-1) = 50
b = 100 - l = 100 - 50 = 50
The dimensions for maximum area is given as, l = 50 feet, b = 50 feet.
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