What are some important attitudes to keep in mind when working with parents and families with special needs?

Answer:

do no answer pls tell sorry

Answer:

270 m

Explanation:

Given:

v₀ = 63 m/s

a = 2.8 m/s²

t = 4.0 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (63 m/s) (4.0 s) + ½ (2.8 m/s²) (4.0 s)²

Δx = 274.4 m

Rounded to two significant figures, the displacement is 270 meters.

A plane traveling at 63 meters/seconds down a runway begins accelerating uniformly at 2.8 meters/seconds, then the total distance traveled by plane would be 274.4 meters.

The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object.

As given in the problem a plane traveling at 63 meters/seconds down a runway begins accelerating uniformly at 2.8 meters/seconds, then we have to find the total distance traveled in 4.0 seconds,

By using the second equation of the motion,

S = ut + 1/2 at²

  =63×4 +0.5×2.8×4²

  =274.4 meters

Thus, the total distance traveled by plane would be 274.4 meters.

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Answer:

F=200N d=20m t=30s

W=F*d

W=200*20

W=4000J

P=W/t

P=4000/30

P=400/3

P=133.333333334 W

Answer:

2.35 m/s²

Explanation:

Given that

Mass of the smaller crate, m₁ = 21 kg

Mass of the larger crate, m₂ = 90 kg

Tensión of the rope, T = 261 N

We know that the sum of all forces for the two objects with a force of friction F and a tension T are:

(i) m₁a₁ = F

(ii) m₂a₂ = T - F, where m and a are the masses and accelerations respectively.

1) no sliding can also mean that:

a₁ = a₂ = a

This makes us merge the two equations written above together as:

m₂a = T - m₁a

If we then solve for a, we would have something like this

a = T / (m₁+m₂)

a = 261 / (21 + 90)

a = 261 / 111

a = 2.35 m/s²

Therefore, the needed acceleration of the small crate is 2.35 m/s²

Answer:

C. The horizontal momentum and the vertical momentum are both conserved.

Explanation:

Answer:

The horizontal momentum and the vertical momentum are both conserved.

Explanation:

Just took it

Answer:

A plain mirrior is a mirrior with flat reflective surface.

hope it is helpful for you.

Answer:

Wheres the table?

Explanation:

The expression for the initial velocity at point A is:

0 = (velocity at point A - 0) / time

Simplifying the equation, we find:

Velocity at point A = 0

The initial velocity at point A is zero, indicating that the object starts from rest before sliding on the horizontal plane AB.

To write an expression for the initial velocity at point A, we need to analyze the forces acting on the object and apply the principles of motion.

Given:

Mass of the object, m

Radius of the semi circle, R

Coefficient of kinetic friction, μ[tex]_k[/tex] = 0.5

Force applied at point C, F = 3mg

The object is initially at rest.

Let's break down the motion into two parts: the motion on the horizontal plane AB and the motion along the semi circle BCD.

1. Motion on the horizontal plane AB:

The only force acting on the object on the horizontal plane is the force of kinetic friction. The frictional force can be calculated using:

Frictional force, f = μ[tex]_k[/tex]* Normal force

The normal force is equal to the weight of the object, which is mg.

Normal force, N = mg

Frictional force, f = μ[tex]_k[/tex] * mg

The frictional force acts in the opposite direction to the motion, so its magnitude is negative. Thus, the net force on the object on the horizontal plane is:

Net force = -f = -μ[tex]_k[/tex]* mg

Using Newton's second law, we can relate the net force to the acceleration:

Net force = mass * acceleration

-μ[tex]_k[/tex] * mg = m * acceleration

The acceleration can be expressed as the rate of change of velocity:

Acceleration = (final velocity - initial velocity) / time

Since the object is initially at rest, the initial velocity is zero.

For more such information on: velocity

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Answer:

The acceleration of the object occurred at 2.95 s

Explanation:

Given;

initial angular velocity of the object, ω = 0

angular acceleration, α = 2.3 rad/s²

angular displacement of the object, θ = 10 radians

The time of the motion is given by the following kinematic equation;

θ = ω + ¹/₂αt²

θ = 0 + ¹/₂αt²

θ = ¹/₂αt²

[tex]t^2 = \frac{2 \theta}{\alpha}\\\\t = \sqrt{\frac{2 \theta}{\alpha}}\\\\t = \sqrt{\frac{2 *10}{2.3}}\\\\t = 2.95 \ s[/tex]

Therefore, the acceleration of the object occurred at 2.95 s

Answer:

Before beginning its descent, the object gets 143.5 meters high

Explanation:

Projectile Motion

It's known as the type of motion that experiences an object that is projected near the Earth's surface and moves along a curved path exclusively under the action of gravity.

Being vo the initial speed of the object, θ the initial launch angle, and [tex]g=9.8m/s^2[/tex] the acceleration of gravity, then the maximum height reached by the object is:

[tex]\displaystyle y_m=\frac{v_o^2\sin^2\theta}{2g}[/tex]

The object is shot at vo=75 m/s at an angle of θ=45°. The maximum height is calculated below:

[tex]\displaystyle y_m=\frac{75^2\sin^2 45^\circ}{2\cdot 9.8}[/tex]

[tex]\displaystyle y_m=\frac{5625\cdot 0.707^2}{19.6}[/tex]

[tex]y_m=143.5\ m[/tex]

Before beginning its descent, the object gets 143.5 meters high

Answer:

Air masses are created by patterns of heating and cooling of the Earth's surface.

Answer:

Study

Explanation:

From the given analogy, we understand that.

Teachers educates

If this is true,

The students are expected to learn from what the teacher teaches.

This can also be said that, the students studies what the teachers teach

Hence, to complete the analogy.

We have;

(1) Students, Study.

We can also make use of

(2) Students, learn.

(1) & (2) answer the question completely.

Answer:

STUDENT:STUDY OR LEARN

Explanation:

Answer:

oxygen

Explanation:

as it is in the air it can't be depleted or used up

Answer:

Deplete definition is - to empty of a principal substance. How to use deplete in a ... to reduce in amount by using up The soil was depleted of minerals. deplete.

Explanation:

Answer:

The initial velocity of this shark is [tex]8.0\; \rm m \cdot s^{-1}[/tex]. (Assuming that the unit of the acceleration in this question is [tex]\rm m\cdot s^{-2}[/tex].)

Explanation:

Let [tex]a[/tex] denote the acceleration of this shark.

Let [tex]v_0[/tex] denote the initial velocity of this shark.

Assume that the acceleration [tex]a[/tex] of this shark is constant (as it is in this question.) Over a period of time [tex]t[/tex], the shark would have travelled a distance of:

[tex]\displaystyle x = \frac{1}{2}\, a\, t^2 + v_0\, t[/tex].

This question states that:

This question is asking for [tex]v_0[/tex], the initial velocity of this shark at the beginning of this [tex]0.8[/tex]-second period. Substitute the three known values into the equation:

[tex]\displaystyle 11.52 = \frac{1}{2}\times 16\times (0.8)^2 + 0.8\, v_0[/tex].

Solve for [tex]v_0[/tex]:

[tex]v_0 = \displaystyle \frac{11.52 - (1/2) \times 16 \times (0.8)^2}{0.8} = 8.0\; \rm m \cdot s^{-1}[/tex].

Answer:

Current in the circuit= 2 A

Explanation:

Current in a Series Connection

When two or more resistors are connected in series, all of them have the same current, and the sum of their individual voltages is the total voltage applied to the circuit.

We know a voltmeter connected to R2=3Ω measures 6V. Applying Ohm's law:

[tex]V=R.I[/tex]

We can calculate the current through R2:

[tex]\displaystyle I=\frac{6}{3}=2\ A[/tex]

Since the current in R2 is the same in the rest of the resistors, the current of R1 and R3 is also 2 A.

Answer:

Explanation:

Physical quantities in mathematics are divided into two:

1) Scalar quantity: This are quantities that gas only magnitude but doesn't specify direction. They only talk about the position of an object in space. For example, Distance, position, speed at all scaler quantities because they didn't specify direction. Distance only talk about how far a body has traveled while speed talks about how far a body has traveled in a specified period of time.

Scalar quantities are:

- Position: coordinate of point on a plane.

- Speed: Speed is the distance covered in a specified time.

- Distance: is how far a body has travelled.

2) Vector quantity: This is a quantity that has both MAGNITUDE and DIRECTION. They specify both position of an object as well as the direction of travel. Example of vector quantities are:

- Velocity: This is the change in displacement of a body with respect to time. Since displacement specifies direction, hence velocity is classified as a vector quantity.

- Displacement: This is the distance traveled by a body in a specified direction.

- Average velocity: distance travelled in a specified time.

Answer:

Higher Pitched! (b)

Explanation:

The Doppler effect makes it seem high pitched, as the sound waves are mushed together at a higher frequency, while moving away, the sound waves spread out like a lower frequency wave!

Answer:

a) 1.725*10^5 N

b) 3.83*10^3 N

c) i) 173.24 kN

c) ii) 4.57 kN

Explanation:

See the attachment for calculations

(a) The ball has a final velocity vector

[tex]\mathbf v_f=v_{x,f}\,\mathbf i+v_{y,f}\,\mathbf j[/tex]

with horizontal and vertical components, respectively,

[tex]v_{x,f}=\left(20.5\dfrac{\rm m}{\rm s}\right)\cos(-38^\circ)\approx16.2\dfrac{\rm m}{\rm s}[/tex]

[tex]v_{y,f}=\left(20.5\dfrac{\rm m}{\rm s}\right)\sin(-38^\circ)\approx-12.6\dfrac{\rm m}{\rm s}[/tex]

The horizontal component of the ball's velocity is constant throughout its trajectory, so [tex]v_{x,i}=v_{x,f}[/tex], and the horizontal distance x that it covers after time t is

[tex]x=v_{x,i}t=v_{x,f}t[/tex]

It lands 103 m away from where it's hit, so we can determine the time it it spends in the air:

[tex]103\,\mathrm m=\left(16.2\dfrac{\rm m}{\rm s}\right)t\implies t\approx6.38\,\mathrm s[/tex]

The vertical component of the ball's velocity at time t is

[tex]v_{y,f}=v_{y,i}-gt[/tex]

where g = 9.80 m/s² is the magnitude of the acceleration due to gravity. Solve for the vertical component of the initial velocity:

[tex]-12.6\dfrac{\rm m}{\rm s}=v_{y,i}-\left(9.80\dfrac{\rm m}{\mathrm s^2}\right)(6.38\,\mathrm s)\implies v_{y,i}\approx49.9\dfrac{\rm m}{\rm s}[/tex]

So, the initial velocity vector is

[tex]\mathbf v_i=v_{x,i}\,\mathbf i+v_{y,i}\,\mathbf j=\left(16.2\dfrac{\rm m}{\rm s}\right)\,\mathbf i+\left(49.9\dfrac{\rm m}{\rm s}\right)\,\mathbf j[/tex]

which carries an initial speed of

[tex]\|\mathbf v_i\|=\sqrt{{v_{x,i}}^2+{v_{y,i}}^2}\approx\boxed{52.4\dfrac{\rm m}{\rm s}}[/tex]

and direction θ such that

[tex]\tan\theta=\dfrac{v_{y,i}}{v_{x,i}}\implies\theta\approx\boxed{72.0^\circ}[/tex]

(b) I assume you're supposed to find the height of the ball when it lands in the seats. The ball's height y at time t is

[tex]y=v_{y,i}t-\dfrac12gt^2[/tex]

so that when it lands in the seats at t ≈ 6.38 s, it has a height of

[tex]y=\left(49.9\dfrac{\rm m}{\rm s}\right)(6.38\,\mathrm s)-\dfrac12\left(9.80\dfrac{\rm m}{\mathrm s^2}\right)(6.38\,\mathrm s)^2\approx\boxed{119\,\mathrm m}[/tex]

Answer:

velocity= 68.58m/s

Explanation:

formula: v = initial velocity + (acceleration)(time)

plug in your values: v= 18m/s + (1.8 m/s2)(28.1s)

solve the parenthesis first: v = 18 m/s + 58.58m/s

add: v = 68.58 m/s

Answer:

a

  The  value at an inside point is Zero  

b

The electric field is [tex]E = 2.7*10^{6} \ N/C[/tex]

Explanation:

From the question we are told that

The magnitude of the charge is [tex]q = 3.0 \mu C = 3.0 *10^{-6} \ C[/tex]

The radius of the spherical ball is [tex]r = 5.0 \ mm = 0.005 \ m[/tex]

Generally according to law postulated by Gauss the magnitude of charge enclosed inside a conducting material is zero which implies that the electric field inside the spherical ball is zero

Generally the electric field out side the spherical ball is mathematically represented as

[tex]E = \frac{kq}{ a^2}[/tex]

Here a is the position outside the spherical ball that is been considered and the value is [tex]a = 10 \ cm = \frac{10}{100} = 0.1 \ m[/tex]

and k is the coulombs constant with value

[tex]k = 9*10^{9}\ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.[/tex]

=> [tex]E = \frac{ 3 *10^{-6} * 9*10^9 }{ (0.1)^2}[/tex]

=> [tex]E = 2.7*10^{6} \ N/C[/tex]

Answer:

A social movement dedicated to sustaining Earth's systems that support life​

Explanation:

That would be environmentalism.

Hope that helped:)

Answer:

I would say a but it could be b too. It’s definetly not the last two.

I say a because no reason to go up the hill and that’s not gonna give her speed going down so. Good luck!

Explanation:

Answer:

B

Explanation:

When air is heated, it expands and rises.

Answer:

B

Explanation:

hot air is less dense than cold air, meaning its particles are farther apart. this causes it to expand and rise, since it is less dense. if you know about convection currents, you'll know that hot air rises and cold air falls.

Answer:

The horizontal distance traveled by the rock from the wall after 2 seconds is 6m.

Explanation:

Given;

initial speed of the rock, u = 3 m/s

height of the wall, h = 25 m

time of travel, t = 2 seconds

The horizontal distance is determined as follows;

X = ut + ¹/₂gt²

where;

g is acceleration due to gravity, horizontal distance is not affected by gravity, g = 0

X = ut

X = 3 x 2

X = 6 m

Therefore, the horizontal distance traveled by the rock from the wall after 2 seconds is 6m.