What are the 7 stages of mitosis in order?.

According to the definition given, non-ionizing means using microwaves on a substance without causing charged ions to form by removing electrons from atoms.

The six primary forms of energy are chemical, electromechanical, photonic, muscular, geothermal, and nuclear fuel. Other research may focus on other forms including electrochemical, psychological, electromagnetic, and others.

Energy is a crucial part of our everyday life despite being just a basic human need. The buildings that people have constructed are heated and cooled by energy. Energy is needed to do things like lift your finger, get out of bed, or even merely go along the main corridor.

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Two key problems for controlled fusion on Earth are high temperature and containment.

Nuclear fusion can be defined as a type of nuclear reaction which involves combining two smaller (light) nuclei of atoms and forms a single heavier nucleus which is accompanied with the release of energy.

Controlled fusion can be defined as a thermonuclear process that involves the fusion of smaller/light atomic nuclei into a single heavier nucleus, generally at high temperatures and under controlled conditions.

Therefore, high temperatures/heating and containment are the two fundamental problems that are associated with controlled fusion on planet Earth.

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The ventilation load in buildings refers to the principal energy used to handle the external fresh air to maintain the internal thermal comfort.

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The sum of the moment of inertia of two perpendicular axes passing through the same point in the object's plane determines the moment of inertia about an axis perpendicular to the plane.

The sum of the moment of inertia of a plane lamina about two axes that are perpendicular to one another and both lie in the same plane (i.e., the z-axis) is equal to the moment of inertia of the plane lamina about the z-axis.

The vector r is always defined to run from the axis of rotation to the location where the force F is applied. It must also be perpendicular to the axis of rotation.

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At the summit, the ring pushes the rider with a force of 801N.

Centripetal force and force equilibrium are ideas needed to address the challenges.

Calculate the rider's velocity by first multiplying the period by the round-up wheel's complete circumference. The centripetal force acting on the rider may then be calculated using the velocity. The normal force may then be calculated using the force equilibrium.

The radius of a circle is,           r=[tex]\frac{d}{2}[/tex]

Here,

d is the diameter of the circle

The circumference of a circle is,  C= 2πr

The speed is the total distance covered in a given time. The speed is,

v=[tex]\frac{x}{t}[/tex]

here,

x is the distance covered and t is the time taken

The centripetal force acting on a body moving in a circular path is,

[tex]F_{c}[/tex]=[tex]\frac{mv^{2} }{r}[/tex]

Here,

m is the mass of the body.

The weight of a body is, W=mg

g is the acceleration due to gravity.

step: 1

Part A

The radius of the wheel is, r=[tex]\frac{d}{2}[/tex]

Here, d is the diameter of the wheel

d=16.0m

r=16/2

r=8m

The circumference of the wheel is, c=2*(3.14rad)*(8m)

                                                           c= 50.3m

The speed of rider is,   v=[tex]\frac{C}{T}[/tex]

                                      v=50.3/3.60

                                      v= 14.0m/s

The centripetal force acting on the rider is,   [tex]F_{c}[/tex]=[tex]\frac{mv^{2} }{r}[/tex]

                                                          [tex]F_{c}[/tex]=55 * 14/8

                                                         [tex]F_{c}[/tex]=1.35*10³

The weight of the rider is,            W=mg

                                                       W=55*9.81

                                                       W=5.40*10²N

The force equilibrium at the top of the wheel is,

-F -W = - [tex]F_{c}[/tex]

F is the force that the ring pushes the rider.

Rewrite the equation in terms of the force that the ring pushes on the rider at the top. The force is,            F= [tex]F_{c}[/tex]-W

                                                           F=(1.35*10³N)-(5.40*10²N)

                                                            F=801N

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65 grams of coffee must evaporate.

Here, we use the formula of heat transfer

Heat loss by the system = heat gain by the system

We need to calculate the heat loss by the coffee and glass itself individually

Heat loss by glass

Heat loss by glass = mass of glass * specific heat capacity *change in temperature

= (120/1000 Kg)* (840)* (48 - 95)

= - 4737.6 J

Heat loss by the glass is -4737.6 J

Similarly we calculate heat loss by coffee

Heat loss by coffee = mass of coffee * specific heat capacity * change in temperature

= (750/1000 Kg) * ( 4184) *( 48 - 95)

= - 147486 J

Heat loss by coffee is -  147486 J

Total heat loss = Heat loss by coffee + Heat loss by glass

= -152223.6 J

evaporation of liquid  = Amount of heat loss

Mass of evaporation * Latent heat = 152223.6 J

Mass of evaporation = 152223.6 / 2340*1000

Mass of evaporation = 0.06505 Kg =  65.05 gram

Hence, 65 grams of coffee evaporates.

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Moment of inertia of thin cylindrical body = MR²/2 and Rotational kinetic energy= 1/2 × moment of inertia × (angular speed)²

a) As the angular acceleration If the style starts from rest.

Angular acceleration (in rad/s²) of the style if, starting from rest, it reaches a rotation speed of 12.0 rpm in 10.7s will be

angular acceleration= angular speed / time

angular acceleration= (12×2π)÷(10.7×60)

angular acceleration= 0.117 rad/s².

b) Angle (in rad) through which the style rotates to reach its final rotational speed after 10.7 seconds will be-

angle= 1/2 × angular acceleration × time²

angle = 1/2 × 0.117 × (10.7)²

angle = 6.697 rad.

c) The rotational kinetic energy (in j) of the 3.00 g style once it reaches its final rotational speed after 10.7 seconds will be-

Rotational kinetic energy= 1/2 × moment of inertia × (angular speed)²

and Moment of inertia of the cylindrical protrusion 5.00 mm in length and 0.800 mm in diameter style = (mass × radius²) ÷ 2

(Since moment of inertia of thin cylindrical shell = MR²/2)

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The time of flight of the stone when projected at the angle of 30 degrees is 5.102 s.

Since the stone is in a projectile motion, only the force of gravity acts upon the stone.

Angle of projection = θ = 30°

Height of the tower = 100 m

Initial velocity = u = 100 m/s

Acceleration due to gravity = g = 9.8 m/s²

The time of flight = T =

= T = usinθ /g

= T = 100 sin 30 / 9.8

= T = 50 / 9.8

= T = 5.102 s

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The correct option is : The sample of material chosen as the potential container material is the variable being tested, so it is the independent variable.

The height and cross-sectional area of the soil sample, the pressure measurements, the volume of the permeated water during the designated time interval, and the coefficient of permeability can all be used to calculate this.

Repeat the test three or more times, and then find the average coefficient to ensure accurate results.

In the laboratory, the constant head permeability test is used to assess the permeability of coarse-grained soils with high permeability.

The test's basic idea is to gauge the amount of water that percolates through a sample of soil in a specific amount of time, then apply Darcy's law to the discharge to determine the permeability.

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The force which the seat belt exerts on a passenger is - 3000 N. Here minus sign indicates force was against the motion.

Given ;  The velocity is v = 12 m/s

and the time = 0.24 sec

Since he crashes in the end , thus the final velocity = 0 m/s

Weight = 60 kg

To calculate : The average force

We will use the formula :

ΔP = FΔT

p = mv

that is initial momentum = final momentum

F = [tex]\frac{m(final velcoity - initial velocity)}{time}[/tex]

F = 60(0 - 12 ) / 0.24

On further solving we get

F = - 720 / 0.24

F = - 3000N

Thus the force which the seat belt exerts on a passenger is - 3000 N

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Therefore, the speed of the block as it crosses,

(a) The point when the spring is not stretched = 1.93 m / s

(b) 5.00 cm to the left of point in (a) = 1.93 m /s

KE = 1 / 2 m v²

U = 1 / 2 k x²

According to law of conservation of energy,

KEi + Ui = KEf + Uf

k = 100 N / m

m = 0.2 kg

a ) The point when the spring is not stretched,

vi = 0

xi = - 10 cm = - 0.1 m

xf = 0 m

1 / 2 m vi² - 1 / 2 k xi² = 1 / 2 m vf² + 1 / 2 k xf²

0 + ( 1 / 2 * 100 * ( -0.1 )² ) = 1 / 2 * 0.2 * vf² + 0

0.5 = 0.1 vf²

vf² = 5

vf = 2.2 m / s

b ) 5.00 cm to the left of point in (a),

Here, the final values of previous scenario becomes the initial value of this scenario.

xf = - 5 cm = - 0.05 m

xi = 0

vi = 2.2 m / s

1 / 2 m vi² + 1 / 2 k xi² = 1 / 2 m vf² + 1 / 2 k xf²

1 / 2 * 0.2 * 2.2² + 0 = 1 / 2 * 0.2 * vf² + 1 / 2 * 100 * ( -0.05 )²

0.5 = 0.1 vf² + 0.125

vf²  = 0.375 / 0.1

vf = 1.93 m / s

c ) 5.00 cm to the right of point in (a),

The velocity of the block at a distance 0.05 m to left of its equilibrium position, equals its velocity at the same distance to right of its equilibrium position .

vf = 1.93 m / s

Therefore, the speed of the block as it crosses,

(a) The point when the spring is not stretched = 2.2 m / s

(b) 5.00 cm to the left of point in (a) = 1.93 m /s

(c) 5.00 cm to the right of point in (a) = 1.93 m / s

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The tension in case 2 is greater than case 1 that is T2 > T1

Any physical object that is in contact with another one can apply forces to that object. Depending on the types of objects in touch, we label these contact forces differently. We refer to the force as tension if a rope, string, chain, or cable is one of the things applying the force.

In medium lengths, tension exerts its force, especially in flexible materials like rope or cord. The force of tension is still a gravitational force. The tension will be referred to as the T = W + ma if the body is moving upward. The thickness remains constant as the body descends, T = W - ma.

Case 1 : The tension can be calculated by :

F = 3ma

a = F/3 m

Thus the equation becomes

mass X acceleration =  F - T1

T1 = F - 2/3 F

T1 = F /3

Case 2: ma = 3ma - T2

T2 = 2ma = 2 X F/3m

the values are taken from the diagram

thus T2 = 2F/3

So we can conclude that T2 > T1

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When a current is established in a closed conducting loop , we use ammeter. Due to this resultant potential developed detected by voltmeter.

[tex]e= -\frac{d\beta }{dt}[/tex]

[tex]e=-L\frac{d\beta }{dt}[/tex]

[tex]i= i0 \left \{ {{y=0.63} \atop {x=t}} \right.[/tex]

i=0.63 io

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The magnitude of the force of kinetic friction between the block and the floor is 2.4N.

Kinetic friction is a force that exists between moving surfaces. A moving body on the surface is subjected to a force in the opposite direction of its movement. When two things rub against each other, the frictional force is turned into thermal energy, which in some situations causes fire. Kinetic friction is responsible for machine part wear and tear, so it is critical to lubricate the machine parts with oil.

F(x) = -kx, and k = 325 N/m for the spring.

0.250 kinetic coefficient of friction

From x = 0 to x = 0.70 metres, the spring compresses.

W net = 0 to 0.70 meter integral [- F spring - F friction] = 1/2 * (-k) * x2 - mu * mg * normal force x = 1/2 * (-325N/m) * (.70)2 - 0.250 * 6kg * 9.81m/s2 * 0.70 - 0

= - 89.93 Joules

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Yes, the current in the upper wire can hold the lower wire in suspension against the gravity.

There is one horizontal wire that carries a large current.

There is also second wire which carries the same current in the same direction but it is suspended below it. As the upper wire has a current in it, it will create a magnetic field in a circular manner.

Now, the second wire will be in the proximity of the magnetic field created by the upper wire and the current in the lower wire and the magnetic field will be perpendicular to each other.

Now, because of the current in the wire and the magnetic field there will be a force generated in the lower wire which will be directly opposite to the weight of the lower wire which will balance out the weight of the lower wire because it is said that the wire carries a large current.

So, here we can conclude that the current in the upper wire can hold the lower wire in suspension against the gravity.

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Some of the elements that are malleable and conducts electricity at STP are Copper, tin and silver.

STP is the abbreviated form of standard temperature and pressure. At STP, the temperature is 0 °C and pressure is 1 atm. Malleability is the ability of a material to be hammered / pressed into a shape without breaking or crackling.

The symbol for copper is Cu. The symbol for tin is Sn. The symbol for silver is Ag. The atomic number of copper is 29. The atomic number of tin is 50. The atomic number of silver is 47.

Therefore, some of the elements that are malleable and conducts electricity at STP are Copper, tin and silver.

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The magnitude of the total linear acceleration is null as angular acceleration is constant , i.e. α=0.

If you have the object's initial and final velocities as well as the amount of displacement and you are aware that acceleration is constant, you can solve for it instantly. Utilize the equation v² = u²+ 2as, where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the displacement.

The centripetal acceleration is calculated by taking the body's velocity (v) and squaring it, then dividing the result by the body's distance from the circle's center.

Let represent the necessary angular acceleration for the specified rotating wheel.

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3.04 ml of water needed to diluting by a factor of 50.

(initial concentration)(initial volume) = (final concentration)(final volume)

(50x)(X ml) = (12x)(4 ml)

X ml = (12x)(4 ml) / 50 x

X ml = 0.96 ml of 12x TBE

final volume - initial volume = volume of diluent

4 ml total - .96 ml of 10x TBE = 3.04 ml water

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A hair dryer has a power rating of 1,265 W at 220 V rms. The resistance of the heating element is 0.0261 ohm, the rms value of current is 4.078 A and maximum instantaneous power will be 632.5 W.

Given,

Power of the hair dryer, P = 1265 W

and Voltage, V = 220 V

The current in the hair dryer, I = P/V (from P=V×I)

I = 1265/220

= 5.75 Amp

The resistance (R) of the heating element can be calculated as;

P= [tex]V^{2}[/tex]/R

1265= [tex]220^{2}[/tex]/R

R=1265/[tex]220^{2}[/tex]

=0.0261 Ohm

(b) The rms value of current, [tex]I_{rms}[/tex] = I/[tex]\sqrt{2}[/tex]

= 5.75/[tex]\sqrt{2}[/tex]

=4.078 A

(c) Maximum instantaneous power that the resistance withstand can be calculated as;

P(t) = (VI)/2

=(220×5.75)/2

=632.5 W

Hence, the resistance of the heating element is 0.0261 ohm, the rms value of current is 4.078 A and maximum instantaneous power will be 632.5 W.

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In a planetary nebula, the shell of expelled material is glowing intensely due to the UV radiations being emitted from the center of the dying star.

What is a planetary nebula?

Rarefied gas with a density of typically makes up a typical planetary nebula. The highest densities, up to 106 particles per cm3, can be found in young planetary nebulae. The density of nebulae decreases with aging due to their expansion. From 0.1 to 1 solar masses is the mass range of planetary nebulae.

Gases are heated to temperatures of about 10,000 K by radiation from the central star. The temperature of the gas is typically 16,000–25,000 K higher in the central regions than it is in the outermost regions. The area around the central star is frequently filled with a very hot (coronal) gas with a temperature of about 1,000,000 K. Fast stellar wind, a gaseous component, is produced at the central star's surface.

Nebulae can be classified as radiation-bounded or matter-bounded. The visible nebula is fully ionized in the first scenario because there is not enough stuff in the nebula to absorb all of the UV rays released by the star. The latter occurs when the core star's UV photon output is insufficient to completely ionize the surrounding plasma, and an ionization front moves outward into the circumstellar envelope of neutral atoms.

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The magnitude of the average emf induced N= 220 in the coil is 4.10347 X 10⁻⁴ v.

Assume ,

N = 220

Area = 13 . 2 cm²

t = 4. 60 x 10⁻² sec

B = 6. 50 X 10⁻⁵ T

( a )

∅initial = NBA cosθ

=220 X 6 . 50 x 10⁻⁵ x 13 . 2 x 10⁻⁴x cosθ

1.8876X 10⁻⁵  T.m²

∅After= NBAcosθ

=220 X 6.50 x 10⁻⁵ x 13.2x 10⁻⁴x cob 90

( b )

∈=|-Δ∅B/Δt|

=1.8876 * 10⁻⁵/4. 60 x 10⁻²

=4.10347 X 10⁻⁴ v

An attribute of a mathematical object that determines whether it is bigger or smaller than other objects of the same kind is its magnitude or size. Formally speaking, an object's magnitude is the visible outcome of the class of objects it belongs to's ordered results.

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Spring brake would apply on the affected wheel.

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Simply how they share electrons distinguishes the various bond kinds. Polar bonds share unevenly, ionic bonds don't share at all, and covalent bonds share equally.

Simple electron sharing patterns distinguish the various bond types.Covalent bonds are created when electrons are shared. Despite the fact that both thermosetting plastics and thermoplastics are polymers, how they react to heat is different. Thermoplastics can melt in the presence of heat after curing, whereas thermoset plastics retain their  and remain solid in the presence of heat. Both their weight and chemical stability are low. excellent thermal insulation and low thermal conductivity. Glass fibers and mineral fillers are typically heavily incorporated into thermoset resins. Polymers called elastomers can be stretched far beyond their original length and can be quickly and compressed to almost their original dimensions.

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ATP is the energy currency of the cell and it is required almost everywhere.

4 cellular activities that would require the energy of ATP will be cellular respiration, ion transport, muscle contraction, nerve impulse.

What is the role of ATP ?

The role of ATP is providing energy where it  gets hydrolysed into ADP along with the phosphate ion where the reaction provides energy and this reaction brings about energy in the activity.

The cellular activities are the activities that take place inside the cell and various activities that will link to them in order to perform various functions. DNA synthesis, biochemical reactions, cellular respiration, cellular activities all takes place with the help of ATP.

Therefore, ATP is required almost everywhere in both cellular respiration activities and cellular activities.

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A population will overshoot / undershoot its carrying capacity more frequently and severely the faster its maximum growth rate is and the longer it takes for a population to react to its environment.

In any capacity refers to the ability to execute public duties without a formal or ongoing appointment (also known as a "de facto" public worker), with the nature of the relationship here between Public Administration and the person providing the service being irrelevant. The first example:

The ability to live freely is a trait of those with capacity. They are free to make their own decisions and might choose to heed or disregard others' suggestions. Generally speaking, when someone is capable of making a choice, they are able to accomplish all of following: comprehend the pertinent information.

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The moment of the weight of the rod about the pivot = 4.2 Nm

The tension in the thread required to hold the rod horizontally = 8.96 N

Tension is described as the pulling force transmitted axially by a cord, rope, chain, or similar object, or through the ends of a rod, truss member, or similar three-dimensional object. It can also be described as pairs of acting and reaction forces acting at each end of the element.

Moment of weight = weight × the perpendicular distance from the axis of rotation to the line of action

M = w × r

w = 14N

r = 30 cm or 0.3 m

M = 14 × 0.3

M = 4.2 Nm

Tension = Applied force × cosθ

T = mg  × cosθ

mg = 14N

θ = 50°

T = 14 × 0.64

T = 8.96 N

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The current best hypothesis search is based on the principle of consistency, which calls for maintaining a single hypothesis and making adjustments as new examples are discovered.

This theory therefore suggests the following:.

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You and your friend have identical cars. You drive your car north at 45 mph and your friend drives his car south at 45 mph. Your car and your friend's car will have same momentum and same kinetic energy.

Momentum is said to be the quantity of motion in a body.  It depends on the direction of the motion of the body. It is given by the formula, P = m*v

where, m is the mass

v is the velocity

Kinetic energy is the property of a moving body. It is given by the formula, K.E = 1/2 mv²

where, m is the mass

v is the velocity

As the mass and velocity for both the cars are the same, the kinetic energy and the momentum are also same for both the cars.

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The main difference between a radio wave and a light wave is its wavelength.

Gamma rays have extremely small wavelengths that are only a small portion of the size of atoms, whereas other wavelengths can extend as far as the universe because the relationship between wave frequency and wavelength is inverse. Although it isn't always stated explicitly, electromagnetic radiation's wavelengths are typically expressed in terms of the vacuum wavelength, regardless of the medium they are traveling through.

Electromagnetic radiation's behavior is influenced by its wavelength. wavelength x frequency equals the speed of light. Energy equals Planck's constant times frequency. Wave number in cm equals 1/wavelength. A rough estimate of the wavelength size is shown along with the wavelengths of various regions of the electromagnetic spectrum.

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The force for the car and the truck during the accident as a time - dependent 6.6 m/s².

In physics, a collision, which is also known as an impact, is the abrupt, violent coming together in close proximity of two substances, such as two pool cues, a golf club and just a ball, a hammering and just a nail, two wagons when linked, or a dropping object or a floor.

The term "colloid" refers to a homogenous, non-crystalline substance made up of huge molecules or ultra-small particles of one component scattered throughout another substance. Emulsions, gels, and sols are examples of colloids. Whole blood, plasma, & albumin are examples of natural colloids.

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