what are the answers to these questions?

Answer:

3 days

Step-by-step explanation:

set up an equation 40+28x=124

solve for x

Jim needs a cardboard sheet with an area of at least 1440 square inches to make the box.

What is a rectangular prism?

A rectangular prism is a three-dimensional shape with six rectangular faces. It is also known as a rectangular parallelepiped or a rectangular cuboid.

To find out how much cardboard Jim needs to make the box, we need to calculate the total surface area of the box.

The rectangular prism has six faces, and we need to cut out each of these faces from the cardboard sheet.

The top and bottom faces are both 12x20 inches, so they have a combined area of 2(12x20) = 480 square inches.

The two side faces are both 12x15 inches, so they have a combined area of 2(12x15) = 360 square inches.

Finally, the front and back faces are both 15x20 inches, so they have a combined area of 2(15x20) = 600 square inches.

Therefore, the total surface area of the box is 480 + 360 + 600 = 1440 square inches.

Therefore, Jim needs a cardboard sheet with an area of at least 1440 square inches to make the box.

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Answer:

Step-by-step explanation:

if your on computer jus press refresh when your by the answer, it will show u for a split sec

The calculated value of the length of the segment HK is 7.8 units

Given the circle

And the intersecting chords IJ and GH

When two chords cross each other inside a circle, the product of the lengths of their respective line segments are equal.

In this particular circle, chords IJ and GH intersect at a point called K.

As a result, the product of the length of segments IK and KJ is equal to the product of the length of segments GK and HK.

So, we have

IK * KJ = GK * HK

This gives

6 * 26 = 20 * HK

This gives

HK = 7.8

Hence, the segment HK is 7.8 units long

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Answer:

Step-by-step explanation:

Answer: -78

-5(11)-23=?
-55-23= -78

Answer:

-78

Step-by-step explanation:

n = 11

Replace n with its given value in this expression:

[tex] - 5n - 23[/tex]

[tex] - 5 \times 11 - 23 = - 55 - 23 = - 78[/tex]

Answer:

Step-by-step explanation:

You want the formula for angle C in triangle ABC with area D.

The relevant formula for the area of the triangle is ...

  Area = 1/2ab·sin(C)

When the area is D, this is ...

  D = 1/2ab·sin(C)

You are being asked to rearrange the formula to give an expression for C.

  2D/(ab) = sin(C) . . . . divide by the coefficient of sin(C)

  [tex]C=\sin^{-1}\left(\dfrac{2D}{ab}\right)=\sin^{-1}\left(\dfrac{m}{n}\right)[/tex]

Comparing parts of the expressions, we see that ...

After answering the presented question, standard deviation t Lower bound = X - [tex](t * (s/\sqrt(n))) = 1271.89 - (1.860 * (34.753/\sqrt(9))) = 1238.94[/tex]

A statistic that expresses the variability or variation of a bunch of values is the standard deviation. A high standard deviation indicates that the values are more distributed, whereas a low standard deviation indicates that the numbers are closer to the set mean. The standard deviation is a measure of how far the data are from the mean (or ). When the standard deviation is small, the data tends to cluster around the mean; when it is great, the data is more spread. The standard deviation represents the average variability of the data collection. It displays the average deviation from the mean of each score.

Next, we need to find the t-value for a 90% confidence interval with 8 degrees of freedom (n-1):

t = t(0.05, 8) = 1.860

Now we can calculate the lower and upper bounds of the confidence interval:

Lower bound = X - [tex](t * (s/\sqrt(n))) = 1271.89 - (1.860 * (34.753/\sqrt(9))) = 1238.94[/tex]

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The 95% confidence interval for the average interval of violations per lawbreaker is (11.12, 18.88) and other solutions are below

a) To estimate the average interval of violations per lawbreaker, we need to calculate the sample mean and standard deviation of the 15 offenders.

Mean = (15+20+10+25+5+22+8+12+18+7+23+6+24+19+11)/15 = 15

Sample standard deviation, s = 7.01

To calculate the 95% confidence interval, we can use the formula:

CI = x ± t(α/2, n-1)*(s/√(n))

where, α= 1 - confidence level = 0.05 (for 95% confidence level)

t(a/2, n-1) = t(0.025, 14) = 2.145 (from t-table)

CI = 15 ± 2.145*(7.01/√(15))

CI = 15 ± 3.88

CI = (11.12, 18.88)

Therefore, the 95% confidence interval for the average interval of violations per lawbreaker is (11.12, 18.88)

b) To make the interval estimate of the proportion of offenders who violate the law exceed 20 times, we need to calculate the sample proportion and standard error.

Sample proportion,

p = number of offenders who violate the law more than 20 times / sample size

p = 4/15

Sample standard error,

SE = √(p*(1-p)/n)

SE = √(4/15 * 11/15 / 15) = 0.114

To calculate the 90% confidence interval, we can use the formula:

CI = p ± z(a/2)*SE

where, a= 1 - confidence level = 0.1 (for 90% confidence level)

z(a/2) = z(0.05) = 1.645 (from z-table)

CI = 4/15 ± 1.645*0.114

CI = (0.079, 0.455)

Therefore, the 90% confidence interval for the proportion of offenders who violate the law more than 20 times is (0.079, 0.455)

Using a graphing tool, we have

y = 0.89x - 0.69

r^2 = 0.9964

We can use the t-test.

The formula for the t-test is:

t = r*√(n-2) / √(1-r^2)

Also, we have

r^2 = 1 - (SSres/SStot)

Since r^2 = 0.9964, we can estimate

SSres/SStot = 0.0036

SStot = SSres/0.0036

Using these values, we can calculate the t-statistic:

t = r*√(n-2) / √(1-r^2)

t = 0.9964*√(6-2) / √(1-0.9964^2)

t = 23.51

Using a two-tailed test and a significance level of 0.05, the critical t-value with 4 degrees of freedom is ±2.101.

Since the calculated t-value (23.51) is greater than the critical t-value (2.101), we reject the null hypothesis and conclude that there is a significant correlation between the percentage increase in the number of lawyers and the percentage increase in revenue from the attorney's office.

Therefore, it is possible to predict Y using the equation y = 0.89x - 0.69. The equation is in the form of y = a + bx, where a is the y-intercept (-0.69) and b is the slope (0.89).

The equation tells us that for every 1% increase in the number of lawyers, there will be a predicted 0.89% increase in revenue from the attorney's office.

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Answer:

42° and 95°

Step-by-step explanation:

1

the inscribed angle EFD is half the measure of its intercepted arc , that is

∠ EFD = [tex]\frac{1}{2}[/tex] × DE = [tex]\frac{1}{2}[/tex] × 84° = 42°

2

ABCD is a cyclic quadrilateral.

the opposite angles sum to 180° , that is

∠ B + ∠ D = 180°

∠ B + 85° = 180° ( subtract 85° from both sides )

∠ B = 95°

a)The term 1-16t²represents the effect of gravity on the apple, which causes it to fall with increasing speed. The constant term 36 represents the initial height of the apple

b)Interpreting the domain, we can say that h(t) makes sense only for non-negative values of t. In other words, we can use the function h(t)to find the height of the apple at any time t a

what is gravity ?

Gravity is a fundamental force of nature that causes objects with mass to attract each other. It is the force that keeps planets in orbit around stars, and stars in orbit around the center of their galaxies.

In the given question,

a. The function h(t)=-16t²+36 represents the height of an apple above the ground at time t after falling off a tree. The term1 -16t² represents the effect of gravity on the apple, which causes it to fall with increasing speed. The constant term 36 represents the initial height of the apple when it fell off the tree.

b. The domain of h(t) in this situation is the set of all possible values of t that make sense in the context of the problem. Since h(t) represents the height of the apple at time t after it fell off the tree, the domain of h(t)is the set of all non-negative real numbers, or [0,\infty) This is because time cannot be negative, and the apple cannot fall for an infinite amount of time.

Interpreting the domain, we can say that h(t)makes sense only for non-negative values of t. In other words, we can use the function h(t) to find the height of the apple at any time t after it fell off the tree, as long as t is non-negative..

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The value of 0.52 represents the ratio of male babies to female babies born in the affected region in the seven years following the 1977 dioxin spill.

To conduct a hypothesis test to determine whether this ratio is different from the earlier ratio, we can set up the null and alternative hypotheses as follows:

Null hypothesis (H0): The ratio of male babies to female babies in the affected region did not change significantly after the 1977 dioxin spill.

Alternative hypothesis (Ha): The ratio of male babies to female babies in the affected region changed significantly after the 1977 dioxin spill.

We can use a one-sample proportion test to test this hypothesis. The test statistic is calculated as:

z = (p - P₀) / √(P₀ * (1 - P₀) / n)

where p is the sample proportion (0.52), P0 is the hypothesized population proportion (0.51), and n is the sample size (123).

Using a significance level of 0.05, we can compare the calculated test statistic to the critical value from the standard normal distribution. If the calculated test statistic falls outside the critical values, we reject the null hypothesis in favor of the alternative hypothesis.

A type II error in this context would occur if we fail to reject the null hypothesis when it is actually false. In other words, we would conclude that the ratio of male babies to female babies did not change significantly after the dioxin spill, when in fact it did. This means that we would fail to detect a real effect of dioxin exposure on the ratio of male to female births, which could have important implications for public health and environmental policy.

Steps:

1) State the null and alternative hypotheses

2) Choose a significance level (alpha)

3) Calculate the test statistic

4) Determine the critical value from the standard normal distribution based on the chosen alpha level

5) Compare the calculated test statistic to the critical value

6) Make a decision to either reject or fail to reject the null hypothesis

7) Interpret the results and draw conclusions, including the possibility of a type II error.

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Question:

In a study of the effects of a 1977 dioxin spell in Italy on the ratio of male babies to female babies born to humans, researchers wanted to know whether dioxin exposure affected the ratio in the seven years following the spill the researchers found that the of the 123 babies born to parents in the affected region 51 warm out the ratio of males to females in previous period during which exposure to dioxin was pretty presume to be absent.

What is 0.52 for the researchers conducted the hypothesis test to determine whether the later ratio is different from the earlier ratio? What does making a type two error mean in the context of this hypothesis test?

The elements of the sets are;

'D = { 4, 6 , 8}

C∪D = { 2, 3, 5, 7}

C∩'D = { }

A Venn diagram is defined as a widely used diagram style showing the logical relation between sets.

The different sets in a Venn diagram are determined with the symbols;

From the Venn diagram shown, we have that;

Universal set = {4, 6, 8}

C = { 7}

D = { 2, 3 , 5}

Then, we have that;

'D = { 4, 6 , 8}

C∪D = { 2, 3, 5, 7}

C∩'D = { }

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Answer:

1.52

Step-by-step explanation:

divide 152 by 100

The condensed expression in to a single logarithm is In(6x⁷).

Using the property of logarithms that states "the logarithm of the quotient is the difference of the logarithms", we can write:

In(6x⁹/x²)

Simplifying the expression within the parentheses, we get:

In(6x⁷)

Therefore, the condensed expression is In(6x⁷).

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The area of the region below y = x^2 + x + 4 and above y = 2 for 2 <= x <= 6 is 93.33 square units.

To find the area of the region below y = x^2 + x + 4 and above y = 2 for 2 <= x <= 6, we need to integrate the difference between the two functions with respect to x over the given interval.

The lower boundary of the region is y = 2, and the upper boundary is y = x^2 + x + 4. So, we can write the integral as:

∫[2,6] [(x^2 + x + 4) - 2] dx

Simplifying the integrand, we get:

∫[2,6] (x^2 + x + 2) dx

Integrating with respect to x, we get:

[(1/3)x^3 + (1/2)x^2 + 2x] evaluated from 2 to 6

Plugging in the upper and lower limits, we get:

[(1/3)(6^3) + (1/2)(6^2) + 2(6)] - [(1/3)(2^3) + (1/2)(2^2) + 2(2)]

Simplifying the expression, we get:

93

Therefore, the area of the region is 93.33 square units.

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The value of the set for the given value of set complement is n(X ∩ Y) = 92.

In set theory, a set's complement The set of all U elements that are not in A is known as A. In other words, all the components that are in U but not in A are in A'. A' is the set of odd numbers, for instance, if U is the set of integers and A is the set of even integers. In many mathematical and computational applications, the complement of a set is a crucial idea in set theory.

Given that, n(U) = 100, n(X) = 51, n(Y) = 63 and n(XUY)' = 8.

Using the formula of union of two sets we have:

n(XUY)' = n(U) - n(X ∩ Y)

Substituting the values we have:

8 = 100 - n(X ∩ Y)

n(X ∩ Y) = 100 - 8

n(X ∩ Y) = 92

Hence, the value of the set for the given value of set complement is n(X ∩ Y) = 92.

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Consequently, the equation of the line passing through (-6, 4) and perpendicular to the provided line is y = (7/8)x + 25/4.

We use the fact that parallel lines have the same slope to determine the equation of a line that is perpendicular to a given line and passes through a point. provided that it takes the form y = mx + b, where m is the slope, the provided line has a slope of -8/7. The parallel line will therefore similarly have a slope of -8/7.

The point-slope form of a line is used to determine the y-intercept of a parallel line: y - y1 = m(x - x1), where (x1, y1) is the point the line passes through. We obtain: y - 4 = (-8/7)(x + 6) by substituting (-6, 4) and -8/7 for m.

This equation can be simplified to y = (-8/7)x - 40/7.

We make use of the fact that perpendicular lines have opposing reciprocal slopes to determine the equation of a line that is perpendicular to the supplied line and passes through (-6, 4). provided that the provided line has a slope of -8/7, the perpendicular line will have a slope of 7/8.

Again using the point-slope representation of a line, we arrive at: y - 4 = (7/8)(x + 6)

This equation can be simplified to: y = (7/8)x + 25/4

Consequently, the equation of the line passing through (-6, 4) and perpendicular to the provided line is y = (7/8)x + 25/4.

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to get the equation of any straight line, we simply need two points off of it, let's use those two in the picture below

[tex](\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{4}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{4}-\stackrel{y1}{2}}}{\underset{\textit{\large run}} {\underset{x_2}{6}-\underset{x_1}{0}}} \implies \cfrac{ 2 }{ 6 } \implies \cfrac{ 1 }{ 3 }[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{2}=\stackrel{m}{ \cfrac{ 1 }{ 3 }}(x-\stackrel{x_1}{0})\implies {\Large \begin{array}{llll} y=\cfrac{ 1 }{ 3 }x+2 \end{array}}[/tex]

This is not true, so there is no point c in the interval  [tex](1, 8)[/tex] that satisfies the conclusion of the Mean Value Theorem for [tex]f(x) = x-3.[/tex]

To apply the Mean Value Theorem, we need to check that the function   [tex]f(x) = x-3[/tex] satisfies the following conditions:

f(x) is continuous on the closed interval [1, 8].

f(x) is differentiable on the open interval (1, 8).

Condition 1 is satisfied because f(x) is a polynomial function, and all polynomial functions are continuous everywhere.

To check condition 2, we can take the derivative of f(x) to get:

f'(x) = 1

The derivative is a constant function, so it is defined and continuous on the entire interval (1, 8).

Therefore, we can apply the Mean Value Theorem, which states that there exists a point c in the open interval (1, 8) such that:

[tex]f'(c) = (f(8) - f(1))/(8 - 1)[/tex]

Plugging in the values, we get:

[tex]1 = (8-3)/(8-1)[/tex]

Simplifying, we get:

[tex]1 = 5/7[/tex]

Therefore, This is not true, so there is no point c in the interval (1, 8) that satisfies the conclusion of the Mean Value Theorem for f(x) = x-3.

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The measure of the minor arc m∡rv = 111°

Recall that according to the principle of angle of intersecting secants, (a-b)/2 = c

Where a = ∡RV
b = ∡SU = 37°:

and c = ∠T (the angle between intersecting secants.

Thus, if (a-b)/2 = c, and b = c = 37 degrees, then we can substitute these values into the equation to get:

(a - 37) / 2 = 37

Multiplying both sides by 2 gives:

a - 37 = 74

Adding 37 to both sides gives:

a = 111

Therefore, a is equal to  m∡rv = 111°.

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We have demonstrated that the middle of a right triangle's hypotenuse is equally spaced from its three vertices, MA = MB = MC.

Let A be the vertex of the right angle, B and C be the other two vertices, and let their (x,y) coordinates be as follows:

A: (a,b)

B: (c,d)

C: (e,f)

The midpoint M of the hypotenuse BC can be found by averaging the (x,y) coordinates of B and C:

[tex]M: $\left(\frac{c+e}{2},\frac{d+f}{2}\right)$[/tex]

To calculate the lengths of MA, MB, and MC, we can use the distance formula:

[tex]MA = \sqrt{(a - \frac{c+e}{2})^2 + (b - \frac{d+f}{2})^2}$\\$MB = \sqrt{(c - \frac{c+e}{2})^2 + (d - \frac{d+f}{2})^2}\\$MC = \sqrt{(e - \frac{c+e}{2})^2 + (f - \frac{d+f}{2})^2}$[/tex]

Simplifying each of these equations, we get:

[tex]MA = \sqrt{(2a - c - e)^2 + (2b - d - f)^2}/2$\\$MB = \sqrt{(c - e)^2 + (d - f)^2}/2$\\$MC = \sqrt{(2e - c - e)^2 + (2f - d - f)^2}/2$[/tex]

We want to show that the midpoint M of the hypotenuse BC is equidistant from the three vertices, i.e., that MA = MB = MC.

Substituting the coordinates of M into the expressions for MA, MB, and MC, we get:

[tex]$MA = \sqrt{(2a - c - e)^2 + (2b - d - f)^2}/2$$MB = \sqrt{(c - e)^2 + (d - f)^2}/2$$MC = \sqrt{(2e - c - e)^2 + (2f - d - f)^2}/2$[/tex]

To simplify these expressions, notice that[tex]$(c+e)/2$[/tex]  is the x-coordinate of M, which is halfway between the x-coordinates of B and C. Similarly, [tex]$(d+f)/2$[/tex]  is the y-coordinate of M, which is halfway between the y-coordinates of B and C. Therefore, we can rewrite the expressions as:

[tex]MA = \sqrt{(a - \frac{c+e}{2})^2 + (b - \frac{d+f}{2})^2}\\MB = \sqrt{(c - \frac{c+e}{2})^2 + (d - \frac{d+f}{2})^2}\\MC = \sqrt{(e - \frac{c+e}{2})^2 + (f - \frac{d+f}{2})^2}[/tex]

Notice that these are the same expressions we obtained in step 3 for the lengths of the three segments.

Therefore, we have shown that MA = MB = MC, which means that the midpoint of the hypotenuse of a right triangle is equidistant from the three vertices.

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Answer:

[tex]m = \frac{10 - 3}{6 - 2} = \frac{7}{4} [/tex]

Answer:

7/4.

Step-by-step explanation:

Slope = rise / run

= (10-3)/(6-2)

= 7/4.

Step-by-step explanation:

To perform polynomial division of x^3 + 10x^2 + x + 10 by (x+1), we get the coefficients 1, 10-i, and -10i. This means that:

x^3 + 10x^2 + x + 10 = (x+1)(x^2 + (10-i)x - 10i)

Now we need to divide x^2 + (10-i)x - 10i by (x-1). We can use polynomial long division:

x + 11 - i

-----------------

x - 1 | x^2 + (10-i)x - 10i

- x^2 + x

-----------

(9-i)x - 10i

(9-i)x + 9-i

-------------

-i

Therefore, the resulting reduced polynomial is x - i.

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Therefore, the solution of the given problem of equation comes out to be adding 7x to both sides of the equation might be the initial step towards solving the equation 7x 5 = x + 3.

Variable words are often employed in complex algorithms to show consistency between two contradictory statements. Academic expressions called equations are used to show the equality of various academic figures. Think of the specifics with y + 7 proposals. In this situation, elevating results in b + 7 when building y + 7 is combined, in contrast to another method of splitting 12 equally sized pieces into two halves.

Here,

We can start by reducing the equation by using various algebraic operations in order to find the solution to the equation 7x 5 = x + 3.

The variable term on the right side of the equation would be eliminated, and the variable on the left side would be isolated, by adding 7x to both sides of the equation as a possible initial step:

=> -7x - 5 + 7x = x + 3 + 7x

Combining similar terms to make the left side simpler:

=> -5 = 8x + 3

After that, we may take 3 off of both sides:

=> -5 - 3 = 8x + 3 - 3

Making the right side simpler:

=> -8 = 8x

By multiplying both sides by 8, we may finally find the value of x:

=> x = -1

As a result, adding 7x to both sides of the equation might be the initial step towards solving the equation 7x + 5 = x + 3.

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The radius x for the circle is derived to be 10.92 using the Pythagoras rule for the right triangle.

Since the line with length 12 is tangent to the circle, then the triangle is a right triangle and the Pythagoras rule can be applied as follows:

x² + (x + 6)² = 12²

x² + x² + 12x + 36 - 144 = 0

2x² + 12x - 108 = 0

x² + 6x - 54 = 0

x² + 6x + 9 = 54 + 9 {completing the square}

(x + 3)² = 63

x + 3 = ±√63

x = 3 + √63 or x = 3 - √63

x = 10.92 or x = -4.92

Therefore, the radius x for the circle is derived to be 10.92 using the Pythagoras rule for the right triangle.

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The surface areas for each figures are:

1. The surface area of the cuboid is:

Top and bottom: 2(10 ft x 4 ft) = 80 ft²

Front and back: 2(10 ft x 5 ft) = 100 ft²

Sides: 2(4 ft x 5 ft) = 40 ft²

Total surface area = 80 + 100 + 40 = 220 ft²

2. The surface area of the cuboid is:

Top and bottom: 2(18 cm x 5 cm) = 180 cm²

Front and back: 2(18 cm x 5 cm) = 180 cm²

Sides: 2(5 cm x 5 cm) = 50 cm²

Total surface area = 180 + 180 + 50 = 410 cm²

3. The surface area of the prism is:

Top and bottom: 2(5 cm x 14 cm) = 140 cm²

Front and back: 2(5 cm x 12 cm) = 120 cm²

Sides: 2(12 cm x 14 cm) = 336 cm²

Total surface area = 140 + 120 + 336 = 596 cm²

4. The surface area of the stacked cuboids is:

Top and bottom of first cuboid: 2(6 cm x 7 cm) = 84 cm²

Front and back of first cuboid: 2(6 cm x 2 cm) = 12 cm²

Sides of first cuboid: 2(7 cm x 2 cm) = 28 cm²

Front and back of second cuboid: 2(7 cm x 2 cm) = 28 cm²

Sides of second cuboid: 2(2 cm x 4 cm) = 8 cm²

Front and back of third cuboid: 2(2 cm x 10 cm) = 40 cm²

Sides of third cuboid: 2(10 cm x 8 cm) = 160 cm²

Total surface area = 84 + 12 + 28 + 28 + 8 + 40 + 160 = 360 cm²

5. The surface area of the cylinder is:

Top and bottom: 2π(6 mm)² = 72π mm²

Side: 2π(6 mm)(5 mm) = 60π mm²

Total surface area = 72π + 60π = 132π mm²

6. The surface area of the cylinder is:

Top and bottom: 2π(1 ft)² = 2π ft²

Side: 2π(1 ft)(10 ft) = 20π ft²

Total surface area = 2π + 20π = 22π ft²

7. The surface area of the cylinder stacked on a cube is:

Top and bottom of cylinder: 2π(5 m)² = 50π m²

Side of cylinder: 2π(5 m)(8 m) = 80π m²

Surface area of cube: 6(10 m x 13 m) = 780 m²

Total surface area = 50π + 80π + 780 = (130π + 780) m²

8. The surface area of the cylinder is:

Top and bottom: 2π(9 in)² = 162π in²

Side: 2π(9 in)(4 in) = 72π in²

Therefore, the total surface area of the cylinder is:

2(162π in²) + 72π in² = 396π in²

So the surface area of the cylinder is 396π square inches.

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Image transcribed:

Find the surface area of each figure.

10 ft

18 cm

5 cm

4 ft

5 ft

3.

4.

6 cm

7 cm

2 cm

5 cm

12 cm

14 cm

4 cm

10 cm

8 cm

Find the surface area of each cylinder. Leave your answer in terms of π.

5.

6 mm

6.

1 ft

5 mm

10 ft

7.

5 m

8.

4 in.

8 m

10 m

9 in.

13 m

11 m

247

Journal and Practice Workbook

Geometry

Answer:

The interest portion of the first payment is $433.20.

Step-by-step explanation:

To find out how much of your first payment will go to interest, we need to calculate the monthly interest rate and then use it to calculate the interest portion of the monthly payment.

First, we need to calculate the monthly interest rate by dividing the annual interest rate by 12. 

Annual interest rate = 13%

Monthly interest rate = 13%/12 = 0.01083

Next, we can use the monthly payment amount and the monthly interest rate to calculate the interest portion of the payment:

Interest portion of payment = Monthly interest rate x Remaining loan balance

To calculate the remaining loan balance after the first payment, we can use the formula for the present value of an ordinary annuity:

Remaining loan balance = Present value of remaining payments

Present value of remaining payments = Monthly payment x (1 - (1 + monthly interest rate)^-n) / monthly interest rate

where n is the total number of payments over the term of the loan.

n = 12 years x 12 months/year = 144 payments

Present value of remaining payments = $450 x (1 - (1 + 0.01083)^-144) / 0.01083 = $44,373.68

Remaining loan balance after first payment = $44,373.68 - $40,000 = $4,373.68

Finally, we can calculate the interest portion of the first payment:

Interest portion of payment = 0.01083 x $40,000 = $433.20

Therefore, the interest portion of the first payment is $433.20.

Answer:

No

Step-by-step explanation:

(x,y)=(2,7) is the solution for y=3x+1, but not for y=2x+5, so (2,7) isn't the solution to the system of equations.