What are the products of hydrolysis when the polypeptide is treated with chymotrypsin?

Answers

Answer 1

The products of hydrolysis when the polypeptide is treated with  chymotrypsin are endo-peptidases.

What is chymotrypsin?

Chymotrypsin is a digestive enzyme that breaks down protein in the  form of  small intestine .This  enzyme is a substance that speeds up certain chemical reactions in the body.

A digestive enzyme is a specialized protein that breaks down  the substances in the digestive tract by catalyzing  biochemical reactions.

The chymotrypsin active site consists of aspartic acid, serine, and histidine amino acid residues.

Chymotrypsin works primarily due to its hydrophobic pocket in the active site.

Products of hydrolysis  when the polypeptide is treated with chymotrypsin are endo-peptidases.

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Related Questions

How many moles of potassium hydroxide are contained in 750. ml of 5. 00 m potassium hydroxide solution?

Answers

Number of moles of KOH present in solution is 3.75.

What do you mean by mole concept?

The term "mole" refers to a mole's atomic mass, which is expressed in grams. A mole is an element's gram-atomic mass, or mass.

The mole idea equates the mass of a single atom or molecule (measured in a.m.u.) to the mass (measured in grams) of a large collection of equivalent molecules.

To calculate moles of potassium hydroxide in 750 ml of 5.00 m of KOH solution -

Mathematically molarity  is expressed as,

Molarity =no. of molecules of solute/volume of solution

Given: Molarity of solution = 5.00 M

Volume of solution = 750 ml = 0.750 l

∴ 5 = no. of moles/0.750

∴ number of moles = 3.75

Hence, number of moles of KOH present in solution is 3.75.

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If 5. 20 g of HCl is added to enough distilled water to form 3. 00 l of solution. What is the molarity of the solution?

Answers

The molarity of the solution is 0.43 M

What is molar concentration or molarity?

A solute's concentration in a solution, specifically the quantity of it per unit volume of solution, is measured by its molar concentration, which is a chemical word. The amount of moles per litre, denoted by the unit sign mol/L or mol/dm3 in SI units, is the most often used unit denoting molarity in chemistry.

Calculation of molarity:

Initially, we must change grams of hydrogen chloride into moles.

Moles of solute per L of solution are known as molarity.

                        M = n/v

where, M=molar concentration,

n = moles of solute,

v= litres of solution

We must divide by the molecular mass to go from grams to moles.

5.20 g of HCl * (1 mole/36.46 g of HCl) = 1.14 moles of HCl

3.0 L x 0.143 moles = 0.429 M HCl ≈ 0.43 M HCl

Therefore it is concluded from the above solution that the molarity of the solution is 0.43 M HCl.

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How many fe(ii) ions are there in 20. 0 g of feso4 (molar mass=151. 9 g/mol) ? avogadro number=6. 0225x 1023

Answers

20 g of [tex]FeSO_4[/tex] contains [tex]7.94 \times 10^{22}[/tex] ions of [tex]Fe^2^+[/tex]

What is Mole?

A mole is a unit to measure an amount of any substance which contains as many elementary particles as there in 12 g of Carbon 12.

A mole contains  [tex]6.02214 \times 10^{23}[/tex] particles and this fixed number is called Avogadro’s number.

No. of moles is given by,

[tex]n =\frac{m}{M}[/tex]

where m = Given mass in grams

M = Molar mass

Here,

[tex]FeSO_4 \rightarrow Fe^2^+ + SO_4^2^-[/tex]

No. of moles of  [tex]FeSO_4[/tex]  = [tex]\frac{20g}{151.9gmol^-^1}[/tex] = 0.132 moles

No. of molecules of  [tex]FeSO_4[/tex] = 0.132 x 6.022 x [tex]10^2^3[/tex] = 7.94 x [tex]10^2^2[/tex]

No. of molecules of  [tex]FeSO_4[/tex] = no. of ions of [tex]Fe^2^+[/tex] = no of ions of [tex]SO_4^2^-[/tex]

Thus, no. of ions  [tex]Fe^2^+[/tex] in 20 g of  [tex]FeSO_4[/tex]  is 7.94 x [tex]10^2^2[/tex]

 

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Select the correct answer.
Two charged objects, A and B, are exerting an electric force on each other. What will happen if the charge on A is increased?
A. The charge on B will decrease.
B. The charge on B will increase.
C. The electric force between A and B will decrease.
D. The electric force between A and B will increase.

Answers

According to Coulomb's law of  electrostatic forces, as the charge of a body  increases, the force exerted also increases. Hence, The electric force between A and  B increases as the charge of A increases.

What is Coulomb's law ?

Coulomb's law states that, the electrostatic force between two charges is directly proportional to the magnitude of their charges and inversely proportional to the distance between them.

The mathematical expression for Coulomb's law is written as follows:

F = k q1 q2/r²

where, q1 and q2 be the charges r be the distance between them, k is the proportionality constant.

Therefore, as the charge of A increases, irrespective whether the force is attractive or repelling, the electric force between them A and B increases.

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Which of the following has the greatest
mass?
pls look at options

Answers

Answer:

C.) One mole of mercury

Explanation:

You can determine which has the greatest mass by identifying each of their atomic masses. The atomic mass represents the mass of an element per 1 mole.

Gold (Au): 196.97 g/mol

Mercury (Hg): 200.59 g/mol

Barium (Ba): 137.33 g/mol

In this case, one mole of mercury has the greatest mass.

If ionizing radiation interacts with a human cell, causing it to die after one or more divisions, it is classified as:____.

Answers

If ionizing radiation interacts with a human cell, causing it to die after one or more divisions, it is classified as mitotic death.

Hence, Option C is correct answer.

What is Ionizing radiation ?

Ionizing radiation is a form of energy which is released by atoms that travels in the form of electromagnetic waves.

Examples: Heat or light from the Sun.

What is Mitotic Death ?

Radiation damage to the cell death occurs when cells to attempt to divide with the damaged DNA.

Thus from the above conclusion we can say that If ionizing radiation interacts with a human cell, causing it to die after one or more divisions, it is classified as mitotic death.

Hence, Option C is correct answer.

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Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: If ionizing radiation interacts with a human cell, causing it to die after one or more divisions, it is classified as

(A) interference of function

(B) mitotic delay

(C) mitotic death

(D) reproductive death

Each gas dissolved in the blood diffuses between the blood and its surroundings based on differences in the partial pressure between the locations. Diffusion occurs until ___________

Answers

Each gas dissolved in the blood diffuses between the blood and its surroundings based on differences in the partial pressure and diffusion occurs until equilibrium is reached.

What is the gas exchange in bloodstream?

The gas exchange refers to the process by which oxygen is absorbed by red blood cells and carbon dioxide is removed through the respiratory system.

The process of gas exchange is carried out due to the differential diffusion rates of gases in the bloodstream (O2 and CO2), which facilitates the transference of these gases.

In conclusion, each gas dissolved in the blood diffuses between the blood and its surroundings based on differences in the partial pressure and diffusion occurs until equilibrium is reached.

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1.0 mole of a gas is enclosed in a 12.3 liter cylinder with a moveable piston at 300 K and 2.0 atm. Half of the gas is removed, leaving 0.50 mole in the cylinder and the system is warmed to 900 K. The cylinder changes volume to maintain constant pressure. What is the volume in the final system?

Answers

The volume in the final system that was initially enclosed in a 12.3 liter cylinder with a moveable piston at 300 K and 2.0 atm is 36.9L.

How to calculate volume?

The volume of a given amount of gas can be calculated by using the combined gas law formula as follows;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressureP2 = final pressureT1 = initial temperatureT2 = final temperatureV1 = initial volumeV2 = final volume

According to this question, 1.0 mole of a gas is enclosed in a 12.3 liter cylinder with a moveable piston at 300 K and 2.0 atm.

However, half of the gas is removed, leaving 0.50 mole in the cylinder and the system is warmed to 900 K. The volume in the final system can be calculated as follows:

2 × 12.3/300 = 2 × V2/900

0.082 = 2V2/900

73.8 = 2V2

V2 = 73.8 ÷ 2

V2 = 36.9L

Therefore, the volume in the final system that was initially enclosed in a 12.3 liter cylinder with a moveable piston at 300 K and 2.0 atm is 36.9L.

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Answer:

Explanation:

it's 18.45, my sister just got the guestion right! hope it helps :)

Determine the ph of a 1. 0 l buffer prepared by adding 0. 100 moles of naoh to 0. 250 moles of hf. ka for hf = 3. 5 × 10−4

Answers

The pH of a 1. 0 l buffer prepared by adding 0. 100 moles of NaOH to 0. 250 moles of HF. ka for HF = 3. 5 × 10−4 is 3.86.

What is Henderson hasselbalch equation?

The Henderson hasselbalch equation can be expressed as

pH = pKa + log [base]/ [acid]

Firstly we will calculate the value of pKa

pKa = -logKa

Given,

Ka = 3. 5 × 10−4)

pKa = -log(3. 5 × 10−4)

pKa = 3.46

Now, we will calculate the value of log [base]/ [acid]

Given,

[base] = 0.10m

[acid] = 0.25m

log [base]/ [acid] = log(0.10/0.25)

= 0.4

Putting the values in handerson hasselbalch equation,

pH = 3.46+0.4

= 3.86

Thus, we find that the value of pH of a 1. 0 l buffer prepared by adding 0. 100 moles of NaOH to 0. 250 moles of HF is 3.86.

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A mixture of reactants and products for the reaction shown below is at
equilibrium in a 2.0 L container. What would most likely happen to the
equilibrium if the volume of the container were increased to 4.0 L?
N₂(g) + 3H₂(g)—2NH₂(g)
A. More NH3 would be produced.
B. Less N₂, H₂, and NH3 would be produced.
C. More N₂, H₂, and NH3 would be produced.
D. More N₂ and H₂ would be produced.

Answers

If the volume of the container were increased to 4.0 L, more N₂ and H₂ would be produced (Option D)

What is chemical equilibrium?

This is simply defined as a state in a chemical system where there is no observable change in the properties of the system with time.

Principle of chemical equilibrium

A French scientist postulated a principle which helps us to understand a chemical system in equilibrium.

The principle states as follow:

If a an external constraint such as change in temperature, pressure or concentration is imposed on a system in equilibrium, the equilibrium will shift so as to neutralize the effect.

How to determine what will happen if the volume of the container is increased from 2 L to 4 L

From the principle given above, we can see that volume does not affect equilirium position.

However, from Boyle's law, we understood that pressure and volume are in invest relationship.

Thus, increasing volume simply means decreasing pressure.

A decrease in pressure will favors the side where there is an increase in volume.

Let us consider the equation from the question:

N₂(g) + 3H₂(g) <=> 2NH₃(g)

Volume of reactants = 1 + 3 = 4 LVolume of products = 2 L

Thus, we can conclude that increasing the volume (i.e decreasing the pressure) of the reaction will favors the backward reaction, hence, more N₂ and H₂ would be produced.

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Which pair of aqueous solutions can create a buffer solution if present in the appropriate concentrations?.

Answers

HF and NaF - If the right concentrations of aqueous solutions are present, they can produce a buffer solution.

What are buffer solutions and how do they differ?The two main categories of buffers are acidic buffer solutions and alkaline buffer solutions. Acidic buffers are solutions that contain a weak acid and one of its salts and have a pH below 7. For instance, a buffer solution with a pH of roughly 4.75 is made of acetic acid and sodium acetate.Describe buffer solution via an example.When a weak acid or a weak base is applied in modest amounts, buffer solutions withstand the pH shift. A buffer made of a weak acid and its salt is an example. It is a solution of acetic acid and sodium acetate CH3COOH + CH3COONa.

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For a typical titration, 0. 010 m naoh is the titrant (in the buret). if the initial buret reading is 2. 45 ml, and the final buret reading is 18. 70 ml, how much naoh was used for the titration?

Answers

16.25 ml NaOH was used for the titration.

Titration:

"The process of calculating the quantity of a material A by adding measured increments of substance B, the titrant, with which it reacts until exact chemical equivalency is obtained (the equivalence point)" is the definition of titration.

A titration is a method for figuring out the concentration of an unknown solution by using a solution with a known concentration. Until the reaction is finished, the titrant (the known solution) is typically added from a buret to a known volume of the analyte (the unknown solution).

0. 010 m NaOH is the titrant (in the buret).

The initial buret reading is 2. 45 ml

The final buret reading is 18. 70 ml

The volume of NaOH = 18.70ml - 2.45 ml

                                    = 16.25 ml

Therefore, 16.25 ml NaOH was used for the titration.

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How many moles are in 18.8 grams of NaOH

Answers

There arw 4 moles mhmmnm

Consider the combustion reaction for octane (C8H18), which is a primary component of gasoline.
2C8 H18 + 25O₂…..16CO2+18H2O

How many moles of CO₂ are emitted into the atmosphere when 16.6 g C8H18 is burned?
CO₂ emitted:

Answers

Answer:

1.16 moles CO₂

Explanation:

To find the moles of CO₂, you need to (1) convert grams C₈H₁₈ to moles (via the molar mass) and then (2) convert moles C₈H₁₈ to moles CO₂ (via the mole-to-mole ratio from equation coefficients). It is important that the conversions/ratios are arranged in a way that allows for the cancellation of units. The final answer should have 3 significant figures like the given value.

Molar Mass (C₈H₁₈): 8(12.011 g/mol) + 18(1.008 g/mol)

Molar Mass (C₈H₁₈): 114.232 g/mol

2 C₈H₁₈ + 25 O₂ -----> 16 CO₂ + 18 H₂O
^                                    ^

16.6 g C₈H₁₈            1 mole            16 moles CO₂          
--------------------  x  -----------------  x  -------------------------  = 1.16 moles CO₂  
                              114.232 g          2 moles C₈H₁₈          

Write the empirical formula for at least four ionic compounds that could be formed from the following ions

Answers

Answer:

NH₄CN,  NH₄IO₃,  Fe(CN)₃,  Fe(IO₃)₃

Explanation:

Cations (positively charged ions) can only form ionic bonds with anions (negatively charged ions). However, you can't just simply put one cation and one anion together to form a compound. Each compound needs to been neutral, or have an overall charge of 0. When cations and anions do not have charges that perfectly cancel, you need to modify the amount of each ion in the compound.

1.) NH₄CN

-----> NH₄⁺ and CN⁻

-----> +1 + (-1) = 0

2.) NH₄IO

-----> NH₄⁺ and IO₃⁻

-----> +1 + (-1) = 0

3.) Fe(CN)

-----> Fe³⁺ and CN⁻

-----> +3 + (-1) + (-1) + (-1) = 0

4.) Fe(IO)

-----> Fe³⁺ and IO₃⁻

-----> +3 + (-1) + (-1) + (-1) = 0

Look at the two question marks between zinc (zn) and arsenic (as). at the time, no elements were known with atomic weights between 65.2 and 75. but mendeleev predicted that two elements must exist with atomic weights in this range. what led mendeleev to predict that two undiscovered elements existed in that range?

Answers

Mendeleev positioned elements in the periodic table in increasing order of their atomic numbers, such that elements having identical chemical properties and characteristics plunge into the same group.

What is Mendeleev's periodic table called?

In order to represent similarities and patterns in the behavior of elements, Mendeleev created the periodic table, which is an arrangement of elements in an increasing atomic mass order in tablet form.Mendeleev stated that "Element characteristics are a periodic function of their atomic weight" in his renowned periodic law.The Periodic Table of Mendeleev is a table that Mendeleev created to list elements in the order of their atomic weights.

Mendeleev discovered that there were two elements with atomic weights between 65.2 and 75 because he found it very satisfying that the properties of the elements were more similar and closer to this level.He also imagined having other elements with possessions similar to those of these other elements.In the periodic table, he left a blank for these two elements until they were finally discovered in their true existence.

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When hydrochloric acid reacts with magnesium metal, hydro- gen gas and aqueous magnesium chloride are produced. what volume of 5.0 m hcl is required to react completely with 3.00 g of magnesium?

Answers

The volume of 5.0 m hcl is required to react completely with 3.00 g of magnesium is 20 L.

Chemical equation:

Mg + 2HCl -----MgCl2 + H2

Given,

Molar mass of Mg = 24g/mol

Mole = Given mass/ Molar mass

Mole= 3/24

= 0.125 mol

From the given equation we get to know that

Mol ratio of Mg and HCl is 1:2.

Therefore,

mol of HCl = (2/1) × mol of Mg

=2× 0.125

= 0.25

Molarity = m× V

= M/m

= 5/0.25

= 20L

Thus, we find that the volume of 5.0 m hcl is required to react completely with 3.00 g of magnesium is 20 L.

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Two molecules of mercury oxide decompose into 2 molecules of mercury and 1 molecule of oxygen gas. Which of the following
equations correctly describes this reaction?
(A) Pro(s)-> Pr(s) + O(g)
(B) Mc₂O(s)-> 2 Mc(s) + O(g)
(C) 2 MnO(s)-> 2 Mn(s) + 20(g)
(D) 2 HgO(s)-> 2 Hg(1) + O₂(8)
Select one:
O a. A
O b. B
OC. C
O d. D

Answers

the answer is B bdvausr

Answer:

D

Explanation:

Mercury is Hg.  Most of these reaction do not involve Hg.  Only D correctly shows a balanced equation with mercury (Hg).

(A) Pro(s)-> Pr(s) + O(g)                                  

(B) Mc₂O(s)-> 2 Mc(s) + O(g)

(C) 2 MnO(s)-> 2 Mn(s) + 20(g)

(D) 2 HgO(s)-> 2 Hg(1) + O₂(8)

What is the ph of a buffer made by combining 45. 0 ml of 0. 150 m nitrous acid and 20. 0 ml of 0. 175 m sodium nitrite? the ka of nitrous acid, hno2, is 4. 5×10^–4?

Answers

The pH of the buffer made by combining Nitrous acid and Sodium Nitrite will be 3.06.

pH can be defined as the medium of expressing the acidity or alkalinity of any solution. It is the potential of hydrogen atoms.

Buffers are the solutions that resist any change in the pH when an acid or base is added to them.

According to the question,

0.150 M nitrous acid (HNO₂) = 45 ml

0.175 M sodium nitrate (NO₂⁻)= 20 ml

Kₐ of nitrous acid (HNO₂) = 4.5 × 10⁻⁴

Total volume of buffer = 45 ml + 20 ml = 65 ml

Concentration of HNO₂ = (45) (0.150) / 65 = 0.103 M

Concentration of NO₂⁻ = (20) (0.175) / 65 = 0.054 M

                     HNO₂  ⇒ H⁺ + NO₂⁻

Initial :          0.103        0     0.054

Change:         -x             +x       +x

Equilibrium: 0.103-x        x       0.054+x

Kₐ = x(0.054+x) / 0.103-x = 0.054x / 0.103 = 0.524x

Also, Kₐ = 4.5 × 10⁻⁴

Therefore, 4.5 × 10⁻⁴ = 0.524x

                              x = 8.58 × 10⁻⁴ M

H⁺ = x = 8.58 × 10⁻⁴ M = 8.6 × 10⁻⁴ M

Therefore, pH = -log ( 8.6 × 10⁻⁴ M)

                 pH = 3.06

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What volume of H2 gas will be produced if 60 L of ammonia, NH3, is decomposed into H2 and N2, assuming that all conditions are at STP?

a)

30 L

b)

90 L

c)

60 L

d)

120 L

e)

150 L
need answer ASAP!!

Answers

Answer:

I think the answer is c I'm not sure but probaly dont put c if your. ot sure try looking up the answers that helps me alot through my word

The volume of H₂ gas produced is approximately 90 L, Option (b) is correct.

To find the volume of H₂ gas produced when 60 L of ammonia (NH₃) is decomposed, we use the balanced chemical equation for the decomposition of ammonia:

2 NH₃(g) → 3 H₂(g) + N₂(g)

According to the equation, 2 moles of ammonia produce 3 moles of hydrogen gas (H₂). At STP (Standard Temperature and Pressure), 1 mole of any gas occupies 22.4 liters.

First, calculate the moles of ammonia present in 60 L:

Moles of NH₃ = Volume / Molar Volume at STP = 60 L / 22.4 L/mol ≈ 2.68 moles

Using the stoichiometric ratio, 3 moles of H₂ are produced from 2 moles of NH₃. So, we can calculate the moles of H₂ produced:

Moles of H₂ = (3/2) * Moles of NH₃ ≈ (3/2) * 2.68 moles ≈ 4.02 moles

Now, find the volume of H₂ gas produced:

Volume of H₂ = Moles of H₂ * Molar Volume at STP = 4.02 moles * 22.4 L/mol ≈ 89.9 L

Rounded to one decimal place, the volume of H₂ gas produced is approximately 90 L, which corresponds to option b).

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What does summarizing involve?
A. Detailing every aspect of what was just read
B. Creating mental images of each idea in the text
C. Inferring the relationship between two characters in the text D. Stating the point of the text in a few brief statements ​

Answers

Answer:

The correct answer is D. Stating the point of the text in a few brief statements.

Explanation:

The whole idea of a summary is to effectively restate the text by only focusing on the main points.

Hope this helps:) Good luck!

D is the creator answer

What is the molality of a nh₄no₃ solution of 125 g of nh₄no₃ (80.0434 g/mol) in 275 g of water (18.0153 g/mol)?

Answers

The molality of the given solution is 5.67 mol/kg

You may calculate the molality of a solution to find out how many moles of solute you obtain per kilogram of solvent. Mol/kg is a typical molality measurement unit in chemistry. One molal is another way to refer to a solution with a concentration of 1 mol/kg. Molar mass must be represented in kg/mol rather than the more common g/mol or kg/kmol when using the unit mol/kg. The formula is as follows:

Molality = [tex]\frac{moles of solute}{kilogram of solvent}[/tex]

First we need to find moles of solute ;

moles of solutes = [tex]\frac{given mass}{molecular mass}[/tex]

moles = 125 / 80.0434

moles of solute = 1.56

Now, molality is ;

molality = 1.56 / 0.275

molality = 5.67 mol/kg

Therefore, The molality of the given solution is 5.67 mol/kg

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If 2. 0 x 1023 argon {ar) atoms strike 4. 0 cm2 of wall per second at a 90° angle to the wall when moving with a speed of 45,000 cm s-1, what pressure {in atm) do they exert on the wall?

Answers

If 2. 0 x 1023 argon {Ar) atoms strike 4. 0  [tex]cm^{2}[/tex]  of wall per second at a 90° angle to the wall when moving with a speed of 45,000  [tex]cm^{-1}[/tex].The pressure will be 0.295 atm.

The force delivered perpendicularly to an object's surface per unit area across which that force would be dispersed is known as pressure. In comparison to the surrounding pressure, gauge pressure defines the pressure. The units was using to express pressure vary.

Calculation of force:

Force excerted by the Ar atoms, (F) = Change in momentum for one Ar atom 7 / unit time × number of atom

F = 2mv /1s × number of atoms.

Putting the given data in above equation.

F = 2 × 39.95 amu × 450 m/s/ 1s × 1.66 × [tex]10^{-27}[/tex] kg /amu × 2 × [tex]10^{23}[/tex] atom

F = 11.94 N

Now, pressure can be calculated by using the formula:

P = Force exerted /area

P = 11.94 N/ 4.0 [tex]cm^{2}[/tex] ×  [tex]cm^{2}[/tex]/ [tex]10^{-4} m^{2}[/tex]

P = 0.295 atm

Therefore, the pressure will be 0.295 atm.

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Isotopes have question 2 options: a) a different number of neutrons in their nuclei. b) a different number of protons in their nuclei. c) a different number of electrons. d) different numbers of both protons and neutrons in their nuclei.

Answers

Answer:

A

Explanation:

Isotopes are atoms of the same element with the same number of protons and electrons but different numbers of neutrons.

Isotopes can also be defined as atoms of the same element with the same atomic number but different mass numbers e.g isotopes of chlorine, oxygen and so on.Oxygen for instance has three isotopes with the same atomic number,8 and different mass numbers,16,17 and 18.

What is the pH of a 1.00 M aqueous solution of a weak diprotic acid H2Y if its Ka1 is equal to 6.9x10-5 and Ka2 is equal to 5.4x10-12

Answers

The pH of the diprotic acid H2Y is =

6.15 × 10-17

Calculation of pH

A diprotic acid is a type of acid that contains two hydrogen atoms in its molecules which has the ability to be replaced when involved in a chemical reaction.

A weak diprotic acid is the type of acid that yields hydronium ions and bicarbonate ions in small amounts when involved in a chemical reaction.

The pH is defined as the degree of how acidic or how basic a substance is when measured against a scale.

The Ka1 of the weak diprotic acid = 6.9x10-5

The Ka2 of the weak diprotic acid = 5.4x10-12

Using the formula;

pH = (pKa1 + pKa2)/2

pH = (6.9x10-5 + 5.4x10-12)/2

pH= 12.3 ×10-5×10-12

pH= 12.3 × 10-17/2

pH= 6.15 × 10-17

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A student sets up the following equation to convert a measurement.
(The ? stands for a number the student is going to calculate.)
Fill in the missing part of this equation.
Note: your answer should be in the form of one or more fractions multiplied together.

Answers

Answer:

[tex]\frac{1 kJ}{1,000 J}[/tex]  ·  [tex]\frac{1,000 mmol}{1 mol}[/tex]

Explanation:

The final answer has a different set of units. In particular, millimoles (mmol) changes to moles (mol) and joules (J) changes to kilojoules (kJ). To make this change, you need to multiply the first value by proportions.

When writing these proportions, it is important that they are arranged in a way that allows for the cancellation of units. For instance, since J is located in the numerator, it must be located in the denominator of the conversion. Furthermore, since mmol is located in the denominator, it must be located in the numerator of the conversion.

Proportions:

1,000 J = 1 kJ

1,000 mmol = 1 mol

The full expression:

[tex]-1.3*10^4\frac{J}{mmol*^oC}[/tex]  ·  [tex]\frac{1 kJ}{1,000 J}[/tex]  ·  [tex]\frac{1,000 mmol}{1 mol}[/tex]  =  [tex]? \frac{kJ}{mol*^oC}[/tex]
                        ^           ^

As you can see, the old units cancel out and you are left with kJ in the numerator and mol in the denominator.

What volume would a 0. 250 mole sample of h2 gas occupy if it had a which a a pressure of 1. 70 atm and a temperature of 35 C?

Answers

The volume of  0. 250 mole sample of [tex]H_{2}[/tex] gas occupy if it had a pressure of 1. 70 atm and a temperature of 35 °C is  3.71 L.

Calculation,

According to ideal gas equation which is known as ideal gas law,

PV =n RT

P is the pressure of the hydrogen gas  = 1.7 atmVis the volume of the hydrogen gas = ?n is the number of the hydrogen gas = 0.25 moleR is the universal gas constant = 0.082 atm L/mole KT is the temperature of the sample = 35°C = 35 + 273 = 308 K

By putting all the values of the given data like pressure temperature universal gas constant and number of moles in equation (i) we get ,

1.7 atm×V = 0.25 mole ×0.082 × 208 K

V = 0.25 mole ×0.082atm L /mole K × 308 K /1.7 atm

V = 3.71 L

So, volume of the sample of the hydrogen gas occupy is  3.71 L.

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Why is the citric acid cycle considered part of aerobic metabolism even though oxygen does not appear explicitly in any reaction because?

Answers

Succinate dehydrogenase is the citric acid cycle considered part of aerobic metabolism even though oxygen does not appear.

The respiratory complex II, also known as succinate dehydrogenase (SDH), succinate-coenzyme Q reductase (SQR), or SDH, is an enzyme complex that is present in the inner mitochondrial membrane of eukaryotic and numerous bacterial cells. SDH converts succinate to fumarate as part of the citric acid cycle. SDH shares structural similarities with fumarate reductase, an enzyme that catalyzes the reverse process during anaerobic respiration in bacteria. (1997, Hagerhall). Succinic semialdehyde dehydrogenase impairment is brought on by ALDH5A1 gene mutations. Instructions for creating the succinic semialdehyde dehydrogenase enzyme are found in the ALDH5A1 gene.

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A student weighs out 0. 0422 g of magnesium metal. The magnesium metal is reacted with excess hydrochloric acid to produce hydrogen gas. A sample of hydrogen gas is collected over water in a eudiometer at 32. 0°c. The volume of collected gas is 43. 9 ml and the atmospheric pressure is 832 mmhg. Using the experimentally collected data, calculate r and the percent error.

Answers

The student weighs out 0.0422 grams of the metal magnesium, thus we can figure that the more's, the magnesium he used, is the mass of the magnesium over the more mass, which is 0.024422.That is approximately 0.001758. Furthermore, it claims that too much hydrochloric acid causes the metal magnesium to react, producing hydrogen gas. The volume of collected gas is 43.9 cc, the mastic pressure is 22 cc, and a sample of hydrogen gas is collected over water in a meter. Is it true that calculations made utilizing experimental and gathered data result in a percent error? Consequently, we are aware that magnesium and chloride react.We create 1 as the reaction ratio is 1:2. The hydrogen and 1 are more. Magnesium chloride is more. Therefore, based on this equation, we can infer that the amount of hydrogen that would be created in this scenario is greater than the amount of magnesium present here, or 0.001758 more. Among hydrogen, there is. \Once we convert the temperature from 32 Celsius to kelvin, we can tell you that the temperature is actually about 5.15 kelvin. The gas has a volume of 43 in m, which is equal to 0.0439 liter and indicates that the pressure is approximately 832 millimeter. Mercury, which is 2 times 13332 plus ca, or roughly 110922.24 par, is a mathematical constant.So, in this instance, we are aware that p v = n r t. The r in this case equals p v over n t, thus we want to determine the r. So p is 110922.24. The temperature is 305.15 and the V is 0.04  over the n is 0.001758. Let's proceed with the calculations right now. In this instance, you will discover that the solution is 9.077 times 10; that is all there is to it.

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This cement should string up and break approximately 1 inch from the slab. Group of answer choices Zinc Phosphate Zinc Oxide Intermediate restorative material Glass Ionomer

Answers

The given description details the methods that are used in Mixing Zinc Phosphate for Permanent Cementation,

The complete description contains the following details:

Personal protective equipment (PPE) is required for the healthcare team, and the student is required to identify and prepare the instrument setup.

Equipment and Supplies

• Glass slab (cool)• Spatula (flexible stainless steel)• Zinc phosphate powder and dispenser• Zinc phosphate liquid and dropper• 2 × 2-inch gauze pads

What is Cementation?

This refers to the use of cement to create a building structure that is used to keep things in place.

Hence, we can see that the Procedural Steps include:

Preparing the Mix

1. Dispense the powder toward one end of the slab and the liquid toward the opposite end.

2. Recap the containers.PURPOSE These materials can be affected by prolonged exposure to the humidity.

3. Divide the powder into small increments as directed by the manufacturer.

4. Incorporate each powder increment into the liquid.NOTE When increment sizes vary, smaller increments are used first. Mixing time per increment also varies; the time is approximately 15 to 20 seconds.

5. Spatulate the mix thoroughly, using broad strokes or a figure-8 movement over a large area of the slab.PURPOSE This aids in dissipating the heat generated during mixing.

6. Test material for appropriate cementation consistency. The cement should string up and break about 1 inch from the slab. Total mixing time is approximately 1 to 2 minutes

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