what are the units of the constant k in coulomb’s law in terms of kg, m, s, and c? group of answer choices a. (kg m)/(s2 c2) b. (kg m3)/(s2 c) c. (kg m3)/(s2 c2) d. (kg m3 c2)/(s2 )

The distance between the centers of the two oxygen molecules is 1.21 x 10⁻⁸ cm  is the 1.21 × 10⁻¹nm.

The distance between the centers of two oxygen molecule is as :

=  1.21 x 10⁻⁸ cm

The nm = nanometer

The 1 cm is equals to 10000000 nanometers, the nanometer is used to measure the length in the metric system. The nanometer is the unit that is equals to the one billionth of the meter.

The distance in nanometer is as follows :

The distance , 1.21 x 10⁻⁸ cm  = 1.21 x 10⁻⁸ × 10⁷

The distance , 1.21 x 10⁻⁸ cm = 1.21 × 10⁻¹nm.

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(a) The chiral carbons in stilbene dibromide total to two. Two additional stereoisomers are enantiomers (b). Both are enantiomers of one another (c) (mirror images) (d) These are diastereomers because they are stereoisomers of one another but not mirror images of one another.

Trans-stilbene is primarily converted to meso-1,2-dibromo-1,2-diphenylethane (also known as meso-stilbene dibromide) by bromination, in accordance with a mechanism involving a cyclic bromonium ion intermediate of a typical electrophilic bromine addition reaction; cis-stilbene results in a racemic mixture of the two enantiomers. An established procedure used as an illustration of an electrophilic addition reaction of alkenes is the reaction of bromine with (E)-stilbene. A double bond anti addition makes the reaction stereospecific. A bromine solution in methylene chloride, which has a relatively high toxicity, is used in the conventional reaction.

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The molality of a 2.89 mass aqueous solution of sodium chloride is 0.0494 mol/kg .

Molality is a measure of the concentration of a solute in a solution, expressed as the number of moles of solute per kilogram of solvent. It is a unit of concentration that is useful in calculations involving solutions with non-ideal properties. Molality is related to molarity, which is the number of moles of solute per liter of solution. The difference between the two is that molarity takes the volume of the solution into account, while molality does not.

The molality can be calculated using the equation: molality = (mass of solute / volume of solution) / molar mass of solute. In this case, the mass of solute is 2.89 g, the volume of the solution is 1 mL, and the molar mass of sodium chloride is 58.44 g/mol. Plugging these values into the equation, we get molality = (2.89 g / 1 mL) / 58.44 g/mol = 0.0494 mol/kg. Therefore, the molality of the 2.89 mass aqueous solution of sodium chloride is 0.0494 mol/kg.

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a. Dispersion in London b. Dipole-dipole interaction The intermolecular interactions that contribute to the formation of a CO2 solution in C6H6 are as follows: Because CO2 is a non-polar molecule.

this is the sole intermolecular force that exists between CO2 and C6H6. Dipole-dipole interactions: Because CO2 is a polar molecule, it might interact with C6H6 via dipole-dipole interactions if C6H6 was similarly polar. However, because C6H6 is a non-polar molecule, dipole-dipole interactions do not contribute to the formation of a CO2 solution in C6H6 H-bonding: An H-bonding interaction is a sort of dipole-dipole interaction in which a hydrogen atom is connected to a strongly electronegative atom (such as N, O, or F). Because CO2 has no hydrogen atoms, there is no H-bonding between CO2.

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When a drop of ink is added to a beaker of water, the ink molecules become randomly dispersed throughout the water. This is an example of an increase in entropy by diffusion process.

Ink flows around the water and gradually mixes with it due to the motion of the ink molecules in the water. Overall, a diffusion process occurs between the water and ink particle populations.

Entropy is the measurement of the amount of thermal energy per unit of temperature in a system that cannot be used for productive work. Entropy is a measure of a system's molecular disorder or unpredictability since work is produced by organized molecular motion.

The overall entropy of a system may only ever increase or stay constant during spontaneous processes, according to the second law of thermodynamics.

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Answer:

To find the concentration of bromide ion in the resulting solution, we need to calculate the total moles of bromide ion in the final solution and divide by the total volume of the solution.

First, we can find the number of moles of bromide ion in the initial solution of cabr2 by multiplying the volume of the solution (100.0 mL) by the concentration (0.500 M):

moles = (100.0 mL) * (0.500 M) = 50.0 moles

And also in Nabr by multiplying the volume of the solution (50.0 mL) by the concentration (1.00 M)

moles = (50.0 mL) * (1.00 M) = 50.0 moles

Next, we add the total moles of bromide ion of the two solutions, which would be 50.0 moles + 50.0 moles = 100.0 moles

The final volume of the solution is 150.0 ml

Then, we divide the total number of moles by the total volume of the solution to find the concentration:

concentration = moles / volume = 100.0 moles / 150.0 mL = 0.667 M

So the concentration of bromide ion in the resulting solution is 0.667 M (in units of Molarity)

The mole fraction of each substance in the vapor phase depends on its vapor benzene pressure. The vapor pressure of a substance in a mixture is proportional to its mole fraction in the liquid phase, and the total pressure in the system is the sum of the vapor pressures of the individual components. Therefore, the mole fraction of each substance in the vapor phase can be calculated using the following equation:

where X_i is the mole fraction of substance i in the vapor phase, P_i is its vapor pressure, and P_benzene and P_toluene are the vapor pressures of benzene and toluene, respectively. To determine the values of P_benzene and P_toluene, the Antoine equation or other vapor pressure models can be used.

Note that this calculation assumes that the vapor phase is in equilibrium with the liquid phase, which may not always be the case depending on the conditions of the system.

Benzene, also known by the chemical formulas C6H6, PhH, and benzol, is an organic chemical compound that is a colorless, flammable liquid with a sweet odour. Benzene consists of 6 carbon atoms forming a ring, with 1 hydrogen atom bonded to every 1 carbon atom. Benzene is a type of cyclic aromatic hydrocarbon with a fixed pi bond. Benzene is a component of petroleum, and is one of the most basic petrochemicals and an important solvent in the world's industry. Because it has a high octane number, benzene is also an important ingredient in gasoline. Benzene is also a basic ingredient in the production of pharmaceuticals, plastics, gasoline, artificial rubber, and dyes. In addition, benzene is a natural ingredient in petroleum, but is usually obtained from other compounds found in petroleum. Because it is carcinogenic, its use other than non-industrial fields is very limited.

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The amount of heat needed to boil the given mass of acetic acid is 72.212 kJ.

Based on the provided information,

The mass of acetic acid = 120 g

The number of moles of acetic acid = Mass of acetic acid/molar mass of acetic acid

The molar mass of acetic acid = 60.052 g/mol

Hence,

The number of moles of acetic acid = 120/60.052 = 1.998 moles

The initial temperature of acetic acid = 16.7 °C = 16.7 + 273.15 = 289.85 K

The standard boiling temperature of acetic acid = 118.1 °C = 118.1 + 273.15 = 391.25 K

The change in temperature of acetic acid ΔT = 391.25 – 289.85 = 101.4 K

The enthalpy of vaporization of acetic acid ΔH = 23.7kJ/mol

The heat capacity of acetic acid c = 2.043 J/g.K

The amount of heat needed to increase the temperature from 16.7 ° C to boiling point is:

q = mcΔT = 120*2.043*101.4 = 24.859 kJ

The amount of heat need for the given mass,

q = ΔH*number of moles = 23.7*1.998 = 47.353 kJ

Hence, the total amount of heat needed to boil the given mass of acetic acid = 24.859 + 47.353 = 72.212 kJ

Note: The question is incomplete. The complete question probably is: Calculate the amount of heat needed to boil 120.g of acetic acid (HCH3CO2), beginning from a temperature of 16.7°C.

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Answer:

To determine the mass of an object that has a volume of 23.0 ml and a density of 0.788 g/cm3, we can use the equation:

mass = density x volume

First, we need to convert the volume from milliliters to cubic centimeters (cm^3) since the density is given in g/cm^3.

1 mL = 1 cm^3

so

volume = 23.0 ml = 23.0 cm^3

Next, we can substitute the density and volume into the equation above:

mass = 0.788 g/cm^3 x 23.0 cm^3 = 18.204 g

Therefore, the mass of the object is 18.204 grams.

The amount of water  that is produced is 3.46 moles of water.

We have to note that we have to apply the stoichiometry of the reaction so that we can be able to get the amount of the water that can be produced in the reaction.

We know that the reaction is; 2H2 + O2 ---->2H2O

Number of moles of the oxygen = 55.44 grams/32 g/mol

= 1.73 moles

If 1 mole of oxygen produces 2 moles of water

1.73 moles of oxygen would produce 1.73 * 2/1

= 3.46 moles of water.

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The temperature rise of the water as it leaves the collector is 5.32 °C

The solar collector area=[tex]4\times8=32[/tex]feet

According to the inverse square law of light intensity, the amount of light that an object emits and reflects toward an observer when they are both stationary is inversely proportional to the square of their distance from the object. Imagine being in a station when a train is approaching. The inverse square law is supported by the train's light, which becomes brighter as it draws nearer. The light increases brighter by a factor of one over the square of the distance between the train and the viewer, if the varying light intensity from the train were measured.

Intensity of exposure of sunlight=300[tex]\frac{BTU}{ft^{2}hr }[/tex]

The heat which is getting absorbed by heater per minute= [tex]\frac{exposure\times area}{60}[/tex]

The heat which is getting absorbed by heater per minute=[tex]\frac{300\times32}{60}[/tex]

=160[tex]\frac{BTU}{min}[/tex]

Now, heat get transfer to water,

Q=50% of 160

Q=80[tex]\frac{BTU}{min}[/tex]

The volume that is heated of water = 1[tex]\frac{gallon}{min}[/tex]

Volume=3.79 [tex]\frac{L}{min}[/tex]

Now, to find the mass of water

Heated=volume ×density=3.79×1=3.79[tex]\frac{kg}{min}[/tex]

Heat=8.36[tex]\frac{lb}{min}[/tex]

Heat capacity of water, C= 1[tex]\frac{BTU}{lb}F[/tex]

Let temperature rise be [tex]\triangle A[/tex]

[tex]mc\triangle T=Q[/tex]

[tex]8.36\times1\times \triangle T=80[/tex]

[tex]\triangle T=[/tex]9.57°F

[tex]\triangle T=[/tex]5.32 °C

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The structure for (E)-2-hydroxy-4-hexen-3-one is given below. Stereochemistry is is a trans-configurated molecule with the hydroxyl group (OH) located on the stereogenic center.

This means that the higher priority groups, as determined by the Cahn-Ingold-Prelog system, are on opposite sides of the double bond. The "-" signs in the structure indicate the location of the double bond. the higher priority groups (double bond and carbonyl group) in the trans orientation. This molecule has a chiral center and can exist as two stereoisomers, but it is specifically the (e) isomer. Stereoisomers are molecules with the same chemical formula and atomic arrangement but with a different spatial arrangement of their atoms. Enantiomers and diastereomers are the two primary categories of stereoisomers. Stereoisomers known as enantiomers are mirror images of one another and cannot be overlaid.

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The density of the metal is 1 g/ml.

To calculate the density of the metal, we need to determine the mass and volume of the metal. If the water level in the graduated cylinder rose to 60 ml after adding the metal pellets.

We can assume that the volume of the metal is equal to the volume of water displaced, which is 60 ml. We can then use the equation of density, which is:

density = mass/volume

Since the volume is known (60 ml), to find the mass we can use the conversion factor: 1 ml of water has a mass of 1 g.

So, the mass of the metal is 60 g.

Now we can substitute the mass and volume into the equation for density:

density = 60 g / 60 ml = 1 g/ml

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The total pressure in the flask is determined by the ideal gas law which is 4.00 atm.

This law states that the pressure of a gas is equal to its number of moles times its temperature divided by its volume. For this question, we need to calculate the number of moles of each gas before the reaction.

Methane has a molar mass of 16.04 g/mol, so 177 mL of methane would be 1.106 moles. Chlorine has a molar mass of 35.45 g/mol, so 911 mL of chlorine would be 2.587 moles. Thus, the total number of moles in the flask is 3.693.

Next, we need to calculate the number of moles that have reacted. 72.5% of the reaction has been completed, so 0.725 moles of the 3.693 moles have reacted.

Finally, the total pressure in the flask is equal to the number of moles times the temperature divided by the volume. This gives a pressure of 4.00 atm.

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The curve is called a meniscus

If the line is in the middle of two lines you add a .5 decimal

Explanation:

The mass of ascorbic in grams is actually when used if the 4.061 g is weighed out and the  95.7 % (w/w) is 3.88 g.

The total mass weighed out = 4.061 g

The w/w % = 95.7 %

The expression for the  w/w % is as follows :

w/w %  = (mass of ascorbic / total weighed ) × 100 %

95.7 % =  (mass of ascorbic / total weighed ) × 100 %

0.957 = mass of ascorbic / 4.061 g

Mass of the ascorbic = 0.957 × 4.061 g

Mass of the ascorbic = 3.88 g

Thus, the mass of ascorbic is 3.88 g.

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Soap reacts with FeCl3 to produce iron soap and a salt.

Soap is made up of long chain molecules of fatty acids that have a polar, or charged, end and a non-polar, or non-charged, end. When soap is added to a solution of iron(III) chloride (FeCl3), the polar ends of the soap molecules are attracted to the charged iron ions in the solution, while the non-polar ends are repelled. This creates a complex between the soap and the iron ions, called iron soap.

The salt that is produced in the reaction is chloride ions that have been separated from the iron ions in the FeCl3. Chloride ions are negatively charged, so they will not form a complex with the soap. Instead, they will remain in solution as separate ions.

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1. The nucleus contains the gene that codes for the protein. This gene is translated into mRNA, which leaves the nucleus through pores.
2. On ribosomes found on the surface of the rough endoplasmic reticulum, the protein is built as the mRNA is translated.
3. The rough endoplasmic reticulum is able to modify proteins and store them for short periods of time.
4. From the endoplasmic reticulum to the Golgi apparatus, the protein is transported by transitional vesicles.

What is protein?
A macronutrient called protein is necessary for gaining muscle growth. Although it can also be found in other sources like nuts and legumes, it is more frequently found in animal products. Amino acids, which are organic molecules formed of carbon, hydrogen, nitrogen, oxygen, or sulfur, are the chemical building blocks of protein.

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This significant change in the Earth's atmosphere is marked by the emergence of redbeds, sediments that contain oxidised iron.

The release of oxygen into the atmosphere led to the formation of minerals on land (continental redbeds). Since the created oxygen was absorbed by rocks for a very long time, as seen in Banded Iron Formations (BIFs) and continental red beds, it did not accumulate in the atmosphere for very long. The majority of the oxygen created over time is still preserved in the historic "banded rock" and "red bed" formations. The growth of oxygen may have been significantly influenced by the oxidation of the mantle rocks. It has been suggested that the shift from subaerial to mostly submerged volcanoes may also have resulted in a decline in volcanic emission of decreased gases.

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A 0.15 M solution of the NaOH is used to titrate the 200.0 mL of 0.15 M HCN. The pH at the equivalence point is 9.3.

The molarity of HCN = 0.15 M

The Ka value = 4.9 × 10⁻¹⁰

The pH expression is given as :

pH = pka + log [base] / [acid]

where .

The pka = - log (ka)

pka = - log(4.9 × 10⁻¹⁰)

[base]  = 0.15 M

[acid] = 0.15 M

pka = 9.3

pH = 9.3 + log [0.15] / [0.15]

pH = 9.3

Thus, the pH at the equivalence point of the solution is 9.3.

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Is it not ok to use the micropipette to dispense the more liquid than its maximum calibrated volume. The correct option is 2) Not ok to use .

If we use a micropipette to dispense the more liquid than its maximum calibrated volume then it can damage the instrument. So, never use the volume 200 µl - 1000 µl pipette to dispense the volumes below the 200 µl. The micropipette is the essential instrument in the laboratory. That is used to accurately and the precisely transfer the volumes of the liquid in the microliter range.

Thus, it harmful to use the micropipette to dispense the more liquid than its maximum calibrated volume.

This question is incomplete, the complete question is :

Is it ever ok to use a micropipette to dispense more liquid than its maximum calibrated volume? Why or why not? Select all that apply.

1) Ok to use

2) Not ok to use

3) More information required to answer this.

4) Depends on you

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Answer:

5 points are mine

.....................................

Medium fresh orange because  in a medium fresh orange only contains 0-3 mg sodium (Alternative B).

Sodium is a type of mineral that you can easily find in various foods, especially salt. Salt itself is known as sodium chloride and is the most abundant source of sodium, up to 40% with the remainder consisting of chloride.

People use salt as a flavor enhancer so that food is not bland. Salt also functions as a binder for food components as well as a stabilizer and food preservative.

a. one cup of canned vegetable soup. On average, canned soup has 700 mg of sodium.

b.a medium fresh orange. sodium in a medium fresh orange only contains 0-3 mg of sodium.

c. 4-ounces of 100 percent tomato juice contain about 1200 mg of sodium.

d. hotdogs. a hotdog contains about 1250 mg of sodium.

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Expendable molds must be formed of expanding mold materials since the mold must flex throughout the cooling process. Molds that are permanent are fixed and do not permit any kind of distortion.

For low volume or one-off production, the method of disposable mold casting uses reusable molds to create metal components. Friction, slush, poor, and vacuum casting processes are the four basic categories.

Using an one reusable mold, permanent mold casting produces a huge number of castings. Simply pour molten into a mold, where it heats up and hardens, is the casting process. The casting is then taken out of the mold, which is then opened and utilized again.

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Titanium phosphide (TiP) is a kind of chemical compound made of titanium and phosphorus. It is a metal compound that has a very high melting point, so it is often found in the form of a gray powder.

Titanium(III) phosphide is metallic. When it comes in contact with water or stomach acid, it breaks down into phosphine gas. Phosphine is a colorless, flammable, and explosive gas.

Titanium phosphide is a type of phosphide that contains more metal atoms than other types of phosphides. This makes it more resistant to breaking down into its parts, which makes it a good choice for things like jewelry.

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Option C is correct. The right response is 1.4. The Henderson-Hasselbalch equation is written as pH=pKa +log([A][HA])

A weak base will react with the H+ from a strong acid to create the weak acid HA when a strong acid is put to a buffer: H+ + A- HA. The pH only minimally changes because the H+ is absorbed by the A- rather than forming H3O+ (H+) by interacting with water. pH is calculated as follows: pH = pKa + log [Salt] / [Acid]. Any acidic buffer solution will always have a pH below 7, while any basic buffer solution will always have a pH above 7. Option C is correct.

The right response is 1.4.

The Henderson-Hasselbalch equation is written as pH=pKa+log([A][HA])

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To raise the temperature of 20 grams of water from 30 degrees Celsius to 40 degrees Celsius requires approximately 8.4 joules of heat.

This can be calculated using the equation Q = mcΔT, where m is the mass of the water (20 grams), c is the specific heat capacity of water (4.184 J/g°C), and ΔT is the change in temperature (10°C). Therefore, the required heat is 8.4 J.

The equation can be used to calculate the amount of energy required to raise the temperature of a given mass of a substance from one temperature to another. For example, if we wanted to calculate the amount of energy required to raise the temperature of 20 grams of water from 30 degrees Celsius to 40 degrees Celsius, we would use the following equation: Q = (20 grams)(4.184 J/g°C)(10°C) = 8.4 J.

This means that 8.4 joules of energy are required to raise the temperature of 20 grams of water from 30°C to 40°C.

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Circle b represents the solution after 300 mL of solvent has been added.

Volume percent = {Volume of solute / volume of solution} x 100

After adding the solution, the volume of solution increases but volume of solute remains the same. For same volume of solute, the volume percent is high for once which has the volume of solution is low.

In 100 mL the visually represented solution has 12 balls for solute. When 300 mL of solution is added to the solute, the total volume is 400 mL volume is increased 4 times. Then 12/4 = 3 is the number of solute present in the circle. Circle b represents the solution.

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Explanation:

To calculate the molarity of a solution, we need to know the number of moles of solute (in this case, KCl) and the volume of the solution in liters.

First, we need to calculate the number of moles of KCl. We can do this by using the formula: moles of KCl = (mass of KCl in grams) / (molar mass of KCl in grams/mole)

The molar mass of KCl is 74.5513 g/mol, so we can use this to calculate the number of moles of KCl in the solution:

moles of KCl = (0.93 g) / (74.5513 g/mol) = 0.01239 moles

Next, we can use this number of moles to calculate the molarity of the solution. Molarity is defined as moles of solute per liter of solution, so we can use the following formula to calculate the molarity of the solution:

molarity of solution = (moles of KCl) / (volume of solution in liters)

In this case, the volume of the solution is 0.75 L, so we can substitute these values into the formula:

molarity of solution = (0.01239 moles) / (0.75 L) = 0.0165 moles/L or approximately 0.0165 M

After weighing a powder on a weigh boat and transferring it to a beaker, it is important to, the correct option is, (c) Remove any clumps in the powder by stirring with a glass rod.

In order to ensure accurate measurement of the powder, it is important to remove any clumps that may have formed during transfer from the weigh boat to the beaker. Stirring the powder with a glass rod helps to break up any clumps, leading to a more uniform and representative sample. This step is especially important when the powder is being used in an experiment or reaction, as clumps can affect the accuracy and reproducibility of the results. Heating the contents of the beaker can also lead to degradation or loss of the powder, so it is generally not recommended.

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