What are the variables in Gay-Lussac’s law

Answer:

In a chemical reaction, reactants contact each other, bonds between atoms in the reactants are broken, and atoms rearrange and form new bonds to make the products.

Explanation:

Answer:

See explanation below

Explanation:

In order to explain this, is neccesary to draw both confomers, the cis and trans, but in the chair conformation, because in that way we can see much better the bonds and the reason of why the cis reacts faster than trans.

As you can see in picture attached, the more stable conformer is the one where the H and Br are in the axial position, and the tert butyl group in equatorial position. In these positions, the cis isomer can undergo an E2 reaction, and the ethoxide would have no problem to substract the hydrogen atom from the molecule to eliminate the Bromide. This is because the t-butyl group in equatorial position, is not exerting steric hindrance, therefore is faster.

In the case of the trans, the t-butyl group is in the axial position as well as the hydrogen and bromide, therefore, when the E2 reaction undergoes, the hydrogen is substracted by ethoxide, but it will be slow because the t.butyl group exerts steric hindrance in the axial positions, therefore, the hydrogen will be substracted slower than in the cis position. This is the main reason for the cis to be faster.

As for the second part of the question, which will be the answer of the whole question, see picture attached 2 for the whole sentence, and the match of the words is the following:

1. Axial

2. More

3. Blank (No word there)

4. less

5. Blank

6. Cis

7. Trans

8. Cis

Answer:

A. Ductility, because it can be observed by altering the shape of the substance  

Explanation:

Changing the shape of a substance does not change its identity.

Answer:

see explaination

Explanation:

Case 1) When we consider vapor pressure of H2O;

Let the pressure is 1 atm OR 760 torr.

As H2 is collected over water, we have to consider the vapor pressure of H2O as well.

Using data i.e. vapor pressure of H2O at 40° C = 55.365 torr

So, pressure of H2 = P = 760 - 55.365 = 704.635 torr = 704.635/760 = 0.9272 atm

Volume of H2 = 80 ml = 0.08 liter

Temperature (T) = 40 + 273 = 313 K

Gas constant (R) = 0.0821 L atm/mol K

Let n is moles of H2. Applying ideal gas equation;

PV = nRT

n = PV/RT = 0.9272 * 0.08 / 0.0821 * 313

n = 0.00289 moles

Mass of H2 = moles * molar mass = 0.00289 * 2.016 = 0.00582 grams

OR 5.8*10^-3 grams ...Answer

----> Case 2) When we don't consider vapor pressure;

Pressure of H2 = 1 atm, all other parameters will remain same as in case 1.

So, mass of H2 = 6.3*10^-3 grams

But Case 1) is correct approach as in question it is mentioned that H2 is collected over water.

Answer:

0.2M

Explanation:

Step 1:

Data obtained from the question.

Volume of acid (Va) = 100mL

Molarity of the acid (Ma) = 0.026 M

Volume of base (Vb) = 13mL

Molarity of the base (Mb) =..?

Step 2:

The balanced equation for the reaction. This is given below:

HCl + KOH —> KCl + H2O

From the balanced equation above,

The mole ratio of the acid (nA) = 1

The mole ratio of the base (nB) = 1

Step 3:

Determination of the molarity of the base, KOH. This can be obtained as follow:

MaVa/MbVb = nA/nB

0.026 x100 / Mb x 13 = 1

Cross multiply to express in linear form

Mb x 13 = 0.026 x 100

Divide both side by 13

Mb = 0.026 x 100 / 13

Mb = 0.2M

Therefore, the molarity of the base, KOH is 0.2M

Answer:

0.2M

Explanation:

KOH(aq) + HCl(aq) ⇒  KCl(aq) + H2O(l)

We express the moles of analyte (HCl) and titrant based (KOH) on their molar concentration:

M1 * V1 = M2 * V2

The molarity of the solution is calculated with the following equation:

M2 = V1 x M1 / ​​V2

Where:

V2 = valued sample volume

V1 = volume of titrant consumed (measured with the burette)

M1 = concentration of titrant solution

M2 = concentration of sample

M2 = 100mL * 0.026M / 13mL = 0.2M

Answer:

$95

Explanation:

.75 x 120 = 90

90+5 = 95

Answer:

82.9 mL  

Explanation:

1. Volume of silver

[tex]\begin{array}{rcl}\text{Density}&=& \dfrac{\text{Mass}}{\text{Volume}}\\\\\rho&=& \dfrac{m}{V}\\\\V &=& \dfrac{m}{\rho}\\\\& = & \dfrac{\text{50.0 g}}{\text{10.49 g$\cdot$mL}^{-1}}\\\\& = & \text{4.766 mL}\\\end{array}\\\text{The volume of the silver is $\large \boxed{\textbf{4.766 mL}}$}[/tex]

2. Volume of gold

[tex]\begin{array}{rcl}V& = & \dfrac{\text{50.0 g}}{\text{19.30 g$\cdot$mL}^{-1}}\\\\& = & \text{2.591 mL}\\\end{array}\\\text{The volume of the gold is $\large \boxed{\textbf{2.591 mL}}$}[/tex]

3. Total volume of silver and gold

V = 4.766 mL + 2.591 mL = 7.36 mL

4 New reading of water level

V = 75.5 mL + 7.36 mL = 82.9 mL

Answer:

Check the explanation

Explanation:

Sample volume V= 10 mL/min x 17 h x 60 min/h / 1000 mL/L = 10.2 L

The concentration is increased

             10200 mL (sample volum) / 10 mL (eluted sample) = 1020 times.

57x10-9 M / 1020 = 5.6x10-12 M    

1.5 M HNO3 will contain ≤ 2ppm x (1.5M/15.7M ) ≤ 0.190 ppm ≤ 190 ppb

Ignoring this is reagent impurity and calculating for sea water

≤ 190 ppb /1020 = 0.186 ppb = 0.186 x 10-9g/mL = 0.186 x 10-6g/L =

0.186 x 10-6g/L / 56 g/mol = 0.003 x10-6 M = 3 nM

Answer:

A. cell wall

Explanation:

A cell wall is rigid and is the outermost layer. It also shapes the cell.

A cell membrane is the inner portion of the cell wall and very flexible, not rigid.

The nucleus is not a membrane, it is the center of cell containing genetic information.

The mitochondria is within the cell and it known as the "powerhouse" of the cell.

- Hope that helps! Please let me know if you need further explanation.

Answer:

Jesus loves you

Answer:

vent vapor concentration in the air to nearly zero. The effective diffusion coefficient of the solvent molecules in the polymer is 2 x 10^-6 cm^2/s

Explanation:

Answer:

THE NEW VOLUME OF THE NITROGEN GAS AT 500 mmHg IS 20 L

Explanation:

We will solve the question by using the Boyle's law equation;

P1V1 = P2V2

Write out the values of the variables involved in the question

P1 = 1000 mmHg

V1 = 10 L

P2 = 500 mmHg

V2 = ?

Substitute the values into the equation, we have;

V2 = PIV1 / P2

V2 = 1000 * 10 / 500

V2 = 10000 /500

V2 = 20 L

The new volume of the nitrogen gas at a pressure of 500 mmHg is 20 L.

Answer:

q1..no.2 and 4 are aromatic

Answer:

Explanation:

Hello,

In this case the molar fraction of sodium sulfide, whose molar mass is 78 g/mol, is 0.125, it means we have 0.125 moles of sodium sulfide per mole of solution, so we compute the mass of sodium sulfide and water as shown below:

[tex]m_{Na_2S}=0.125mol*\frac{78gNa_2S}{1molNa_2S} =9.75 gNa_2S\\\\m_{H_2O}=(1-0.125)molH_2O*\frac{18gH_2O}{1molH_2O} =15.75gH_2O[/tex]

Then, we can calculate the eight/weight % as follows:

[tex]w/w \%=\frac{9.75g}{9.75g+15.75g}*100\% \\\\w/w \%=38\%[/tex]

Regards.

Answer: 38

Explanation:

Answer:

See explaination

Explanation:

Please kindly check attachment for the step by step solution of the given problem

Answer:

Actual yield reduces the more.

Explanation:

An actual yield of the course of a chemical reaction is the mass of a product actually obtained from the reaction.

In practice you see it and It is usually less than the theoretical yield.

Various reasons may come up to explain this away but here is one:

• incomplete reactions, simply put here some of the reactants do not react to form the product.

The same applies in the question about the actual yield will reduce significantly in molar mass now that insufficient amount of reagent are used.

Answer:

The answer is 2

Explanation:

The equation that represent the conservation of charge is Option 2.

The following information should be considered:

Learn more; https://brainly.com/question/11833983?referrer=searchResults

Answer:

It is [Xe] 4f14 5d10 6s2 6p3 and its atomic number is 83

Answer:

- Increase pressure .

Explanation:

Hello,

In this case, during the dissolution process, the solute's molecules rearrange in order to get together with the solvent's molecules, in this case water.

Now, since we are talking about a solid whose particles are intimately held together, the only way to separate them is by increasing the temperature because the molecules start moving so they can join water's molecules, decreasing particle size since they will be more likely to separate to each other and increasing stirring since the applied energy will break the solid's intramolecular forces.

In such a way, since pressure significantly affects gases and slightly affects liquid, it is not able to modify a solid, just extreme pressures such as it needed to produce diamonds, is able to affect a solid. For that reason, increasing the pressure will not increase the solid's solubility.

Best regards.

Answer:

[tex]M=1.1M[/tex]

Explanation:

Hello,

In this case, since we are mixing two NaOH solutions, the first step is to compute the total moles once the mixing is done, by using the volumes and concentrations of each solutions and subsequently adding them:

[tex]n_T=2.0L*0.60\frac{mol}{L}+495mL*\frac{1L}{1000mL}*3.0\frac{mol}{L}= 2.7molNaOH[/tex]

Next, we compute the total volume by adding the volume of each solution:

[tex]V_T=2.0L+495mL*\frac{1L}{1000mL}= 2.495L[/tex]

Finally, we compute the molarity of the resulting solution by the division between the total moles and the total volume:

[tex]M=\frac{2.7mol}{2.495L}\\ \\M=1.1M[/tex]

Best regards.

Answer:

32.4 L

Explanation:

Note 1:

The Standard Temperature and Pressure (STP) is  defined by IUPAC as air at 0 gradius Celcius and 1 bar.

Note 2:

The Ideal Gas Law is used for solving this problem.

......

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

Answer:

The answer you are looking for is A

Answer:

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Answer:

A. Buffer strips

Explanation:

The practice that could help reduce erosion of water banks is buffer strips.

Erosion is the action of surface processes that removes soil, rock or dissolved material from one location on the Earth's crust, and then transports it to another location where it is deposited.

One of the practices that could be used to reduce the effect of erosion is buffer strips.

What buffer strips do is slow and filter storm runoff while helping to hold soil in place.

Learn more on buffer strips here; https://brainly.com/question/26872640

Answer:

Kindly check the attachment for the diagram representing the cell and showing all necessary components including: anode, cathode, electron flow, cation flow and anion flow.

Explanation:

So, the reaction in the concentration cell is given below as;

Cu2+(1.00 M) → Cu2+(0.0100 M).--(1).

The anode = Cu2+(0.0100 M) because it has lesser Concentration, thus, lesser potential value.

Cathode = Cu2+(1.00 M) because it has higher Concentration, hence higher potential value.

It must be noted that in the digaram depicting the Reaction, the electrons moves from the anode part of the cell to the cathode part of the cell and this is done through an external circuit. The following are the things that happens at each electrode;

At the Anode: in here is where oxidation occurs and Cu^2+ is released into the solution.

At the cathode: in here is where the reduction occur and the Cu^2+ moves in the direction to where the Cu electrode is, thus, causing the deposition of Cu.

Answer:

MRCORRECT has answered the question

Explanation:

Film photography is another example ofchemical reaction by light. In this example, the chemical compounds coated on the film go through a chemical reaction. ... These plates (usually made of aluminum) are coated with a photosensitive compound consisting of a polymer and a photosensitivechemical system.

Answer:

C

Explanation:

Answer:

I think its q

Explanation:

h is the Planck constant, c the speed of light

Answer:

Explanation:

Total mole of gases = 7.8 + 2.1 + .09 + .01 = 10

the partial pressures of the gases in a mixture

= mole fraction x Total pressure

mole fraction = mole of a gas in the mixture  / total mole

partial pressure of Ng = [tex]\frac{7.8}{10} \times 101.3 kPa[/tex]

= 79.014 kPa

partial pressure of O = [tex]\frac{2.1}{10} \times 101.3 kPa[/tex]

= 21.273 kPa .

partial pressure of  Ar = [tex]\frac{.09}{10} \times 101.3 kPa[/tex]

= .9117 kPa .

partial pressure of  Co = [tex]\frac{.01}{10} \times 101.3 kPa[/tex]

= .1013 k Pa .