What average power would a 1000 kg speedboat need to go from rest to 20.0 m/s in 5.00 s, assuming the water exerts a constant drag force of magnitude fd = 500 N and the acceleration is constant.

Answers

Answer 1

The average power required by a 1000 kg speedboat to go from rest to 20.0 m/s in 5.00 s is 60000 Watts.

The average power required to accelerate an object is equal to the force required to overcome resistance multiplied by the velocity gained. In this case, the drag force fd opposes the acceleration of the speedboat, and so the net force on the boat is equal to the difference between the force applied to the boat and the drag force:

Fnet = Fapplied - fd = ma - fd

where m is the mass of the boat (1000 kg) and a is the acceleration. The acceleration can be calculated from the velocity gained and the time taken:

a = (vf - vi) / t = (20 m/s - 0 m/s) / 5.00 s = 4 m/s^2

So, the net force is:

Fnet = ma - fd = 1000 kg * 4 m/s^2 - 500 N = 3000 N

The power required to overcome the drag force and accelerate the speedboat is equal to the net force multiplied by the velocity gained:

P = Fnet * v = 3000 N * 20 m/s = 60000 Watts

Therefore, the average power required is 60000 Watts.

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Related Questions

if the car maintains its constant acceleration, how much additional time does it take the car to reach a velocity of 39.0 m/s ?

Answers

The additional time it takes for the car to reach a velocity of 39.0 m/s is equal to 39.0/a, where a is the constant acceleration.

To calculate the additional time it takes for the car to reach a velocity of 39.0 m/s with a constant acceleration, you can use the equation t = (Vf - Vi)/a, where Vf is the final velocity, Vi is the initial velocity, and a is the acceleration.

Assuming the initial velocity is 0 m/s and the acceleration is constant, the additional time it takes for the car to reach a velocity of 39.0 m/s can be calculated as follows:

t = (39.0 - 0)/a

t = 39.0/a

Therefore, the additional time it takes for the car to reach a velocity of 39.0 m/s is equal to 39.0/a, where a is the constant acceleration.

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Question: Consider three spheres all caring charge Q uniformly distributed over the volume. Sphere #1 is of radius R/2; Sphere #2 is of radius R; sphere #3 is of radius 2R. 1. Rank electric field created by these spheres at distance R/2 from the center, greatest first: a. 1; 2; 3 b. 3; 2; 1 c. 2; 1;3 d. 1=2; 3 e. Electric field is the same for all. Rank electric field created by these spheres at distance R from the center, greatest first: a. 1; 2; 3 b. 3; 2; 1 c. 2; 1;3 d. 1=2; 3 e. Electric field is the same for all. 3. Rank electric field created by these spheres at distance 2R from the center, greatest first: a. 1; 2; 3 b. 3; 2; 1 c. 2; 1;3 d. 1=2; 3 e. Electric field is the same for all.

Answers

The electric field formed by a charged sphere at a distance R/2 from the center is proportional to the charge on the sphere and inversely proportional to the square of the radius of the sphere.

As a result, at R/2 distance from the center, the electric field produced by sphere #1 (of radius R/2) will be bigger than the electric field produced by sphere #2 (of radius R), which will be greater than the electric field produced by sphere #3. (of radius 2R). As a result, the correct answer is: b. 3; 2; 1 The electric field formed by a charged sphere at a distance R from the center is proportional to the charge on the sphere and inversely proportional to the square of the radius of the sphere. As a result, at distance R from the center, the electric field produced by sphere #3 (of radius 2R) will be smaller than that produced by sphere #2 (of radius R), which will be less than that produced by sphere #1 (of radius R/2). As a result, the correct answer is: a. 1; 2; 3 The electric field formed by a charged sphere at a distance of 2R from the center is proportional to the charge on the sphere and inversely proportional to the square of the radius of the sphere. As a result, at a distance of 2R from the center, the electric field formed by sphere #3 (of radius 2R) will be less than the electric field created by sphere #2 (of radius R), which will be less than the electric field created by sphere #1 (of radius R). greater than the electric field produced by sphere #1 (of radius R/2). As a result, the correct answer is: a. 1; 2; 3.

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an acceleration vector has components of 17 m/s2 eastward and 23.5 m/s2 southward. what is the magnitude of the vector?

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The magnitude of the vector of an acceleration vector has components of 17 m/s2 eastward and 23.5 m/s2 southward is 29.0 m/s².

Acceleration is the measure of how quickly an object's velocity changes with relation to time. Accelerations are vector quantities since they have both a magnitude and a direction. The direction of an object's acceleration is determined by the direction of the net force acting on it. Newton's Second Law states that the combined effect of two factors determines how much an item accelerates:

The size of the net balance of all external forces acting on the object is, in accordance with the materials used

to create it, inversely proportional to its mass, And the magnitude of resulting force is directly proportional to net force.

From the given data,

A1 = 17 m/s²

A2 = 23.5 m/s²

magnitude = |A|

To calculate the magnitude of the vector,

|A|² =(A1)² + (A2)²

|A|² = (17 m/s²)² + (23.5 m/s²)²

|A|²= 841.25 m/s²

|A| = 29.0 m/s²

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how to calculate the resolution of a speedometer

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The resolution of a speedometer is defined as the smallest increment that the instrument can display. It is calculated by dividing the full scale reading (FSC) by the number of divisions on the scale.

The higher the number of divisions, the higher the resolution.

For example, if the speedometer has a full scale reading of 100 mph and the scale has 500 divisions, the resolution would be 100/500 = 0.2 mph.

This means the speedometer can display increments of 0.2 mph.

To improve the resolution, the number of divisions can be increased. It is important to note that the resolution of a speedometer should match the accuracy of the instrument to ensure accurate readings.

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When the object of mass m2 has descended a distance h, the potential energy of the system has decreased by a) (mx-ma)gh b) (magh) c) (mu+ma)gh d) % (mi+mzigh e) o

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Correct option (m2 - m1)gh. When work is performed on a system, its total energy (kinetic plus potential) rises; conversely, when work is performed by the system, it falls.

When a spring is compressed or extended, work is done against the restoring force. Work is done against the gravitational force of attraction when moving a body against gravity. This indicates that the system's potential energy increases in all three scenarios. However, the system functions so that the potential energy of the system reduces when the bubble rises in the direction of the upthrust force. As the system travels, energy is lost by m2 over a distance of h and gained by m1 over the same distance h, but some of this energy is converted to KE, resulting in a net loss of U. For this loss, just take the U2 - U1 and deduct. 

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something underwater that does not float and does not sink is

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Positively buoyant refers to that which does not float and does not sink.

According to the archimedes' principal, when an object is immersed in a liquid, the liquid exerts an upward force called buoyant force on the object. In floating state this force is equal to the weight of the volume of the liquid displaced by the object.

Positive buoyant : When the buoyant force is more than the weight of the object.

Negative buoyant: When the buoyant force is less than the weight of the object.

Neutral buoyant: When the buoyant force is equal to the weight of the object.

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two wooden members of uniform rectangular cross section are joined by the simple glued scarf splice shown. knowing that p = 11 kn, determine the normal and shearing stresses in the glued splice.

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The normal stress is 518kpa and the shear stress is 518kpa.

Any object or body that experiences an external force that is perpendicular to the cross-sectional area undergoes stress in order to restore its original shape. The stress created in this way by a force acting perpendicularly on a particular area is known as normal stress.

The tension that is created in an item when a force applies parallel to its surface area is known as shear stress. The force F is acting parallel to the surface area ABCD, creating shear stress in the item, as shown in the drawing above.

F=11×cos45

F=7.77KN

V=11×sin45

V=7.77KN

Calculate the area at the section.

A=[tex]\frac{0.15\times0.075}{cos45}[/tex]

A=0.015

Normal stress=[tex]\frac{7.77}{0.015}[/tex]

=518kpa

Therefore, the normal stress at the section is 518 kpa

Shear stress =[tex]\frac{7.77}{0.0159}[/tex]

=518kpa

Therefore, the shear stress at the section is518 kpa.

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A student is writing a short essay about forces for her science class. Which of the following statements can she use to describe the characteristics of all types of forces?
A. Forces act in pairs.
B. Forces only pull objects together.
C. Only one force can act on an object at a time.
D. Forces cause objects to move faster, but not slower.

Answers

The statement that she can use to describe the characteristics of all types of forces is forces act in pairs. The correct option is A.

What is force?

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force.

The third law of motion by Newton states that equal but diametrically opposed forces always act in pairs.

There is an equal but opposite reaction to every action, to put it another way. This means that when you push against a wall, the wall pushes back against you with an equal amount of force.

Thus, the correct option is A.

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in dynamics v=ds/dt (velocity) and a=dv/dt (acceleration) are called equations of motion where the distance s is a function of time t. given: v=t-2. find the maximum/minimum distance.

Answers

The required distance when the relation between velocity and time is given  is calculated to be at t = 0, 2 sec.

As given in the problem, v = ds/dt

ds = v dt

Taking integral on both sides, we have,

∫ ds = ∫ v dt

Replacing v by t-2 in the above equation.

∫ ds = ∫ (t - 2) dt

S = t²/2 - 2t

The minimum distance is when S = 0, t²/2 - 2t  = 0

t( t/2 - 2) = 0

At t = 0, 2 sec, it is the minimum distance covered.

Thus, the required answer is t = 0, 2sec.

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with the two conductors in contact with each other and the charged rod far away what is the net charge of the two conductors?

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The net charge of two conductors in contact with each other is zero because electrons will redistribute themselves until there is no longer an excess of charge on either conductor, which equalizes the potential between the two conductors, leaving them with no net charge.

The net charge of two conductors in contact with each other is zero due to the behavior of electrons. When two conductors come into contact with each other, the electrons will redistribute themselves until there is no longer an excess of charge on either conductor, equalizing the potential between the two.

As a result, the net charge between the two conductors is zero. This principle can be applied to many situations, ensuring that charge remains balanced and neutralized.

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B
Vo = 30 m/s
m = 0.150 kg
Calvin
catches the
ball

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According to his second law, a force is defined as the change in momentum (mass times velocity) per change in time.Force is equal to 0.15 x 9.8 x 1.47 Newton.

Find the solution ?

According to his second law, a force is defined as the change in momentum (mass times velocity) per change in time.

The mass m of an object times its velocity V is how momentum is calculated.

One of the most crucial principles of physics is Newton's second law.

For a body whose mass m is fixed, the equation F = ma can be used, where F (for force) and a (for acceleration) are both vector values.

A body is accelerated according to the equation if it is subject to a net force.

The only force acting on the ball will be gravity because we are ignoring air resistance.

Newton's second rule states that F = ma, where m is the ball's mass (0.15 kg) and an is the acceleration due to gravity (9.8 m/sec2).

To obtain the force, substitute:Force is equal to 0.15 x 9.8 x 1.47 Newton.

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astronaut x of mass 50kg floats next to astronaut y of mass 100kg while in space, as shown in the figure. the positive direction is shown. astronaut x applies a force against astronaut y such that the kinetic energy of each astronaut as a function of time is shown in the graph. what is the change in momentum of the two-astronaut system and the change in momentum of each astronaut from immediately before the force was applied to immediately after the force was applied? responses

Answers

The two-astronaut system's and each astronaut's momentum changed from before to after the force was applied as follows:

The change in momentum of "the system" is 0 (kg.m/s).The change in momentum of "astronaut X" is -100 (kg.m/s).The change in momentum of "astronaut Y" is 100 (kg.m/s).

The change in momentum of a system is equal to the net force acting on the system, multiplied by the time over which the force is applied. In this scenario, the two astronauts apply forces on each other, but the net force acting on the system (Astronauts X and Y) is 0, therefore, the change in momentum of the system is also 0.

The change in momentum of astronaut X is calculated as the force applied by X on object Y, multiplied by the time over which the force is applied. The force applied is equal to the mass of Y (100 kg) multiplied by the acceleration of Y (-100 m/s^2). The change in momentum of Astronaut X is -100 kg * m/s.

The change in momentum of astronaut Y is equal to the force applied by X on Y, multiplied by the time over which the force is applied. The force applied is equal to the mass of X (50 kg) multiplied by the acceleration of X (100 m/s^2). The change in momentum of Astronaut Y is 100 kg * m/s.

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If the average speed of a person was 1.2 meters/second, does this mean that their speed was exactly 1.2 meters/second the whole time? Is the average speed related to the maximum or minimum speed of the person? Explain why you think so.

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No, the average speed of a person does not necessarily mean that their speed was exactly 1.2 meters/second the whole time.

Average speed is calculated by dividing the total distance traveled by the total time elapsed. In simple words, Average speed is distance divided by the time interval for the distance traveled. So, if a person's speed varies over time, their average speed will be a reflection of all the different speeds they traveled at during that time period.

The average speed is not related to the maximum or minimum speed of a person. It's the measure of the average rate at which an object covers distance over time. It can be different from the maximum or minimum speed that an object has reached during that time.

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what is the smallest area that the window could be? express your answer with the appropriate units and with the appropriate number of significant figures.

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The smallest area that the window could be is 10200cm^2.

How do you find the area of a window?

To find the area of a window, you need to measure its length and width, and then multiply them. The formula is:

Area = Length x Width.

We can see that the smallest area that the window could be would look at the lower values of the length and the width of the window so we would have;

Lower part of the length = 150 cm

Lower part of the width = 68 cm

Then the area would be now;

150 cm * 68 cm

= 10200cm^2

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Students want to design an experiment to study gravity. They decide they will drop four objects with the same mass from the top of their school’s bleachers. They will time how long each object takes to reach the ground. How can they improve confidence in the experiment’s results?

A. Let a different student time the drop of each object.
B. Randomly select the order in which the objects are dropped.
C. Drop each object 10 times and use the average of each object’s fall times.
D. Drop all four objects at once.

Answers

Answer: Drop each object 10 times and use the average of each object’s fall times

Explanation: Drop each object 10 times and use the average of each object’s fall times

Answer:

(Question)  Melissa is working on the roof of her house. She drops a hammer and a nail. Why do both objects hit the ground at the same time?

(Answer)  Earth’s gravity causes both objects to fall at the same rate.

(Question)  Which of the following statements about gravitational mass is true?

(Answer)  Gravitational acceleration is irrespective of mass.

(Question)  Two objects fall from an apartment window sill at the same time. Object 1 lands on the sidewalk in 3.6 seconds. Object 2 lands on the sidewalk in 3.3 seconds. What can be concluded about the objects?

(Answer)  Object 1 has more surface area than Object 2

(Question)  A company uses drones to fly food to people in regions that have experienced natural disasters. The food is packed in boxes that are attached to parachutes. How can the company change the design of its parachute to reduce the number of boxes that are damaged when they hit the ground?

(Answer)  The company can design a parachute with more surface area

(Question)  Students want to design an experiment to study gravity. They decide they will drop four objects with the same mass from the top of their school’s bleachers. They will time how long each object takes to reach the ground. How can they improve confidence in the experiment’s results?

(Answer)  Drop each object 10 times and use the average of each object’s fall times

Explanation:

I just finished the quick check UwU

correct answerrrrr is ?

Answers

The electricity cost in the month is AED 43.

What is electric power?

The speed at which electrical energy is carried over an electric circuit is known as electric power. The watt, or one joule per second, is the SI unit of power.

Voltage of the circuit is = 240 volt.

Resistance of the circuit is = 12 ohm.

The electric power of the circuit is  = V²/R = 240 × 240 /12 = 4800 W.

Total electrical energy is = 4800 × 30 Wh

= 144 kWh

Hence, total coast is = 144 × AED 0.30 = AED 43.

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the transmission time from when a signal first leaves a satellite and then arrives at a ground station is called

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The transmission time from when a signal first leaves a satellite and then arrives at a ground station is called round-trip delay time.

The round-trip delay time is the total amount of time it takes for a signal to travel from a satellite to a ground station and back. It is an important metric used in satellite communications to determine the quality of the link between the satellite and the ground station and to correct for any transmission delays that may affect the accuracy of the data being transmitted.

The delay time is affected by several factors, including the distance between the satellite and the ground station, the altitude of the satellite, and the atmospheric conditions along the signal path.

By measuring the round-trip delay time, engineers can make necessary adjustments to the satellite and ground station equipment to ensure reliable and efficient communication.

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Object A of mass 19 kg travels to the east at 4.2 m/s and object B of mass 24 kg travels to the south at 3.6 m/s. They collide and stick together in a perfect inelastic collision as shown below. What is the magnitude and direction (with respect to the horizontal) of the velocity of the two objects after the collision?

Answers

The velocity of the two objects after the collision is 0.1535 m/s in south direction.

What is law of conservation of momentum?

The law of conservation of momentum asserts that, unless an external force is applied, the total momentum of two or more bodies operating upon one another in an isolated system remains constant.

From the law of conservation of momentum, it can be written that:

Total initial momentum = total final momentum

19 kg × 4.2 m/s + 24 kg × (-3.6) m/s = (19 kg + 24 kg)× v

v = [19 kg × 4.2 m/s + 24 kg × (-3.6) m/s] ÷  (19 kg + 24 kg)

v = - 0.1535 m/s

Hence,  the velocity of the two objects after the collision is 0.1535 m/s in south direction.

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two speakers are in a plane, 5 m apart, playing the same frequency in phase. you stand 12 m in front of the plane, centered between them so you hear a maximum intensity. as you walk parallel to the plane of the speakers you hear a minimum intensity when you are directly in front of one of the speakers (but still 12 m away). what is the lowest possible frequency of the sound in hz?

Answers

The lowest possible frequency of the sound in Hz is 24.3 Hz.

The lowest possible frequency of the sound in Hz can be calculated using the principle of constructive and destructive interference of waves.

The condition for minimum intensity is when the path difference between the two waves is equal to half a wavelength. The path difference between the two waves is equal to the difference in distance between the source and the observer.

Let "f" be the frequency of the sound waves. Then, the wavelength "λ" can be calculated using the equation:

λ = v/f, where "v" is the speed of sound in air.

The path difference between the two waves is equal to 12 m - 5 m = 7 m.

So, half the wavelength is equal to λ/2 = 7 m.

Therefore, the lowest possible frequency can be calculated using the equation:

f = v/λ = v/2*(7 m) = v/14 m.

The speed of sound in air is approximately 340 m/s, so the lowest possible frequency is:

f = 340 m/s / 14 m = 24.3 Hz.

Hence, the lowest possible frequency of the sound in Hz is 24.3 Hz.

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convert to 2.77 atm to torr

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To convert 2.77 atm(Atmospheric Pressure) to torr, multiply 2.77 by 760, which gives us 2,108 torr.

Atmosphere (atm) and torr are both units of pressure measurement. Torr is a unit of pressure in the centimeter-gram-second (CGS) system, while atm is a unit of pressure in the International System of Units (SI).

The conversion from atm to torr involves multiplying the atm value by a conversion factor of 760. This is because 1 atm is equal to 760 torr.

To convert 2.77 atm to torr, multiply 2.77 by 760, which gives us 2,108 torr. It is important to keep in mind that these units are used in different systems of measurement, so it is important to know the correct conversion factor when converting between them. In conclusion, 2.77 atm is equal to 2,108 torr.

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considering evidence from all three given spectra, which structural features most likely account for the two signals around 175 ppm in the 13c nmr spectrum?

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the structural properties that account for the two signals at 175 ppm in the 13C NMR spectrum. The 13C NMR spectrum provides information .about the chemical environment of carbon atoms.

in a molecule, but additional information and analysis are required to determine the exact structural features that account for a particular signal, such as knowledge of the molecule's chemical structure, other NMR spectra (such as 1H NMR), and an understanding of the coupling between carbon and proton nuclei. To develop an educated assessment of the signals in the 13C NMR spectrum, it is critical to analyze all of the available information from the three spectra. This might entail comparing the signals in the 13C NMR spectra. to those in the 1H NMR and/or other spectra, as well as an evaluation of the chemical shifts and coupling patterns of the signals under examination. Furthermore, the molecule structure, solvent, and sample conditions can all have an impact on the appearance of the NMR spectra, thus these parameters should be considered as well.

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when you meet an oncoming large vehicle (truck, bus, etc.) on a two-lane country road, what should you do to avoid the turbulence created by this heavy vehicle?

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When we meet an oncoming large vehicle on a two-lane country road, then the best thing which should be done to avoid turbulence created is lane-right position.

What is Turbulence?

Turbulence is one of the most unpredictable of all the weather phenomena which are of significance to the pilots of the aircraft. Turbulence is an irregular motion of the air which is resulting from the eddies and the vertical currents.

Turbulence may be an insignificant phenomena as a few annoying bumps or severe enough to momentarily throw on an airplane which is out of control or to cause the structural damage. Turbulence is associated with the fronts, wind shear, thunderstorms, etc.

When we meet an oncoming large vehicle on a two-lane country road, then the best thing to do to avoid turbulence is to lane-right position.

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Point charges q1 = 41 µC and q2 = −17 µC are placed 2.5 m apart. Where must q3 = 23 µC be placed (on the x-axis, in m) so that the net force on it is zero? (Assume that q1 is at x = 0 and q2 is at x = 2.5 m.)x = ________ m

Answers

The net amount of electricity being used in Q3 is zero.

SO\sF13 + F23

KQ1Q3/=KQ2Q3/(X-2.5)

2\sQ1/X2=Q2/(X2-2.5)

2\s41/X2=17/(X-2.5)2

We obtain X = 7.02 m by solving the equation above.

The charge must be placed 0.859 m distant from the negative charge on the side that faces the positive charge.

Between the charges, at a distance of 0.141 m from the 5.00 C charge The distance between the charges from the 3.0 C charge can also be represented as 0.109 m. Because of this, the electric field at a location is discontinuous if there is a charge there and continuous if there isn't.

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the voltage of a 100-kw, 250-volt shunt generator rises to 260 volts when the load is removed. what is the full-load current does the machine deliver, and what is its percent regulation?

Answers

The full load current is calculated to be 400 A and the percentage regulation is calculated to be 4 %.

The power of a generator is given as 100 kW.

The voltage of the generator when there is full load is 250 V (v fl).

The voltage of the generator when load is removed is 260 V (v nl).

We know the expression for load current as,

Load current = Power/Voltage = (100 × 10³)/250 = 400 A

The percentage rise in the terminal voltage of the generator when the generator load is removed is given by,

% Voltage regulation = (v nl - v fl)/v fl × 100 = (260 - 250)/250 × 100 = 4 %

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marathon runner keep track of speed using units of pace - minutes/mile. olivia has a pace of 7 min/mile what is her speed in feet/ sec

Answers

The answer is 5280 / (9)(60) ft/sec. An intermediate runner should be able to finish a 1 km run in 7-8 minutes. For more seasoned runners, finishing 1 km in 6 minutes or less is a decent speed per kilometre.

Comparisons of Pace and Distance less than 4:21 minutes per kilometre (7 minute mile). If your goal is to complete a marathon in five hours or less, you should pace your run at an average of about 11:26 minutes per mile or 7:06 minutes per kilometer. The pace for a 9-minute mile is 5.35 minutes per kilometer, or around 6.7 miles per hour or 10.7 kilometers per hour; it should feel like a quick jog.

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are the observations explained by saying that the nail only contains one type of charge? _________________________________________________________________________________[1]

Answers

The nail is only temporarily charged positively/negatively since its initial state was neutral, but itcan only have one type of charge at a time.

Negatively charged things and neutral objects pull toward one another, as do positively charged objects and neutral objects. Physics instructors frequently illustrate this third interaction between charged and neutral objects, and students often have the opportunity to participate in such activities in the lab. While charging through conduction, both objects acquire the same kind of charge. When a neutral object is charged with a negative charge, both charged objects become negatively charged. A body is considered to have a negative charge if it contains more electrons than protons. A body, on the other hand, is considered to have a positive charge if it has more protons than electrons.

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State why in a three-phase system, transformers in the distribution and local substations must have a secondary winding connected as Y (start) rather than ∆ (delta)

Answers

Transformers in three-phase systems must have a secondary winding connected as Y (start) to provide a neutral point for the connection of single-phase loads like homes and small businesses.

Transformers in three-phase systems must have a secondary winding connected as Y (start) to provide a neutral point for the connection of single-phase loads like homes and small businesses, which are common in local distribution networks. Y connection also provides better voltage regulation and improves system stability. On the other hand, ∆ connection doesn't have a neutral point and is not suitable for connecting single-phase loads. The Y connection also offers a balanced load distribution and better protection for the connected loads. This makes Y connection the preferred choice for transformers in distribution and local substations in three-phase systems.

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Which of these statements best explains why it's often a good idea to pay more than the mont
hly amount due on an amortized loan?
(2 Points)
O Every time you pay extra, the lender will reduce the interest rate they're charging by a small amount
The extra payment will be applied to the principal amount you owe, which will pay down your debt
more quickly
The extra payment will be applied to the interest you owe, which will reduce the overall cost of your
loan
Amortized loans typically have much higher interest rates than credit cards, so they're the best place to
put your extra cash

Answers

Answer:

The extra payment will be applied to the principal amount you owe, which will pay down your debt more quickly.

a male african elephant has a mass of 6800 kg and can reach a running speed of 25 km/hr. calculate the momentum of the male elephant? how fast would a field mouse (50.2 g) have to travel to have the same momentum? (47,222 / 940,681.7176)

Answers

The momentum of the male African elephant is 47222.22 kg-m, and a filed mouse has to travel at the speed of 940681.7176 m /s, to have the same momentum.

The mass of the elephant, M1 = 6800 kg

The velocity of the elephant, v1 = 25 km/h or 25×5/18 = 6.94 m/s

The mass of the field mouse, M3 = 50.2 gm or 0.0502 kg

Let the speed of the mouse to have the same momentum is v2.

Momentum of the elephant = 6800 × 6.944 = 47222.22 kg-m

Momentum of elephant = momentum of mouse

6800 × 6.94 = 0.0502 × v2

v2 = (6800×6.94)/0.0502

v2 = 940681.7176 m/s

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What is the weight in newtons of a person who has a mass of 50 kg?

Answers

The weight of an object with a mass of 50kg is 490 N. The gravitational force of the earth on an object is referred to as its weight.

How much do I weigh in Newtons on the moon?

The gravitational constant on Earth is 9.81 N/Kg (Newtons per kilogram). You would weigh less standing on the Moon because it has around one-sixth the gravity of Earth. The gravitational constant on the moon is 1.622 N/Kg.

Mass: What is it?

The amount of matter in a particle or object is represented by its mass, which is denoted by the symbol m. In the International System (SI), the kilogram serves as the default unit of mass (kg).

Given:

Mass (m) = 50 Kg

To find the weight of an object, you simply multiply its mass by the gravitational force.

m = 50kg; g = 9.8

Therefore:

w = mg

= 50 x 9.8

= 490 N

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