What can you deduce about the height of a binary tree if you know that it has the following properties? (a) 26 leave nodes (b) 44 leave nodes(c) 64 leave nodes

Answer: ∠ 5

Step-by-step explanation:

I got you fam

Answer: D.

Step-by-step explanation:

Using a 0.05 significance level to test a claim that UFO sightings occur in different seasons with the proportions listed in the table the test statistic x² needed to test the claim is 11.562. The correct option is B.

To test the claim that UFO sightings occur in different seasons with the proportions listed in the table, we can use a chi-square goodness-of-fit test.

The null hypothesis is that the observed frequencies in each season are equal to the expected frequencies based on the proportions listed in the table.

The expected frequency for each season can be calculated by multiplying the total number of sightings by the proportion listed in the table. For example, the expected frequency for spring is:

Expected frequency for spring = Total number of sightings × Proportion for spring

= 420 × 0.25

= 105

Similarly, the expected frequencies for summer, fall, and winter are 126, 210, and 105, respectively.

The chi-square test statistic can be calculated as:

χ² = ∑ [(O - E)² / E]

where O is the observed frequency and E is the expected frequency.

Using the observed frequencies from the table and the expected frequencies calculated above, we get:

χ² = [(150-105)²/105] + [(120-126)²/126] + [(100-210)²/210] + [(50-105)²/105]

   = 11.562

The degrees of freedom for the chi-square test is (number of categories - 1), which in this case is 4 - 1 = 3.

Using a chi-square distribution table with 3 degrees of freedom and a significance level of 0.05, the critical value is 7.815.

Since the calculated chi-square value (11.562) is greater than the critical value (7.815), we reject the null hypothesis and conclude that there is evidence of a difference in UFO sightings across seasons. Therefore, the test statistic x² needed to test the claim is 11.562.

The correct answer is (B) 11.562.

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The graph of the given line  2 x + y = 4 is a straight line and the coordinates present above the line will be ( 0, 4) and ( 2, 0) hence option (C) will be correct.

We know, that,

A line section that can connect two places is referred to as a segment.

In other words, a line segment is just part of a big line that is straight and going unlimited in bdirections.

The line is here! It extends endlessly in both directions and has no beginning or conclusion.

A coordinate that is present in the line will always satisfy the equation of the line.

In the given option the coordinate  (0, 4) and (2, 0) is satisfying the given equation by substituting the value  2 x + y = 4 hence option (C) will correct.

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To find the cumulative probability distribution function (CDF) F(y), we need to integrate the given PDF f(y) from 0 to y:

F(y) = integral of f(y) dy from 0 to y

= integral of c*y*(1-y)^2 dy from 0 to y   (substituting c=30 from part a)

= 30*integral of y*(1-y)^2 dy from 0 to y

To integrate this, we can use integration by substitution. Let u = 1 - y, then du/dy = -1 and y = 1 - u. Substituting, we get:

F(y) = 30*integral of (1-u)*u^2 * (-du) from 0 to 1-y

= 30*integral of u^2 - u^3 du from 0 to 1-y

= 30*[u^3/3 - u^4/4] evaluated at 0 and 1-y

= 10*(1 - (1-y)^3 - 3(1-y)^4/4),   0 <= y <= 1

Therefore, the cumulative probability distribution function (CDF) of Y is:

F(y) = {

        0,                             y < 0

        10*(1 - (1-y)^3 - 3(1-y)^4/4), 0 <= y <= 1

        1,                             y > 1

      }

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The theoretical probability that the coin will land tails up is 1/2 = 0.5 or 50%.

A probability is calculated as the division of the desired number of outcomes by the total number of outcomes in the context of a problem/experiment.

In this problem, we have a fair coin, meaning that in any throw, the coin is equally as likely to land in one of the two outcomes, which are heads up or tails up.

Hence the probability is given as follows:

p = 1/2 = 0.5 = 50%.

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The newspaper's estimate is not a reasonable approximation of the actual attendance of the football game.

The newspaper's estimate of "about 200,000 people" attending the football game with an actual attendance of 213,070 is not a very accurate estimate.

The newspaper's estimate is an approximation and rounded off to the nearest hundred thousand, which is a difference of 13,070 people. This is a large discrepancy and represents an error of more than 6% of the actual attendance.

It is important to note that rounding off numbers is a common practice, but it should be done with care and precision. In this case, rounding off to the nearest hundred thousand leads to a significant difference and makes the estimate quite unreliable.

Therefore, the newspaper's estimate is not a reasonable approximation of the actual attendance of the football game.

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Answer:

-12

Step-by-step explanation:

First substitute

Then after evaluating collect the like terms

After collecting the like terns simplify the Numbers

And finally evaluate the answer

Answer: 2x-64x+18x = –44x

Step-by-step explanation:

Answer:

[tex]\huge\boxed{\sf \$400}[/tex]

Step-by-step explanation:

Value of phone = $500

Loss in price = 1/5 of total price

= 1/5 × 500     (of means to multiply)

= 1 × 100

= $100

= Actual price - loss

= 500 - 100

[tex]\rule[225]{225}{2}[/tex]

The p-value for a sample of different sales promotions with 5 different promotions and 10 samples with all 5 is equals to the 0.1060.

Suppose that the sales manager wants to compare different sales promotions. Here, number of different promotion choosen by him = 5

Number of random sample of each different promotion= 10

The F value = 3.4

We have to determine the p-value by using JMP. Now, n = 10, k = 5 so, degree of freedom = n - k= 5

Computing the p value using approximate method, [tex]P-value = P( F_{k - 1, n-k} > 3.4 ) [/tex]

[tex]= P( F_{4, 5}> 3.4 ) [/tex]

Using Excel command, value of F is calculated, = F.dist.RT( 3.4,4,5)

= 0.105954

Hence, required value is 0.1060.

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Answer: The equation is 5 - (3/5)cot(x) = (25 + √3)/5.

First, we can simplify the right-hand side by dividing both sides by 5:

(25 + √3)/5 = 5 + √3/5

Next, we can use the identity cot(x) = 1/tan(x) to rewrite the left-hand side:

5 - (3/5)cot(x) = 5 - (3/5)(1/tan(x)) = 5 - 3tan(x)/5

Now we have the equation 5 - 3tan(x)/5 = 5 + √3/5.

Subtracting 5 from both sides, we get:

-3tan(x)/5 = √3/5

Multiplying both sides by -5/3, we get:

tan(x) = -√3/3

Taking the arctangent of both sides, we get:

x = arctan(-√3/3)

Since the range of arctan is (-π/2, π/2), we need to add π to get the other solutions:

x = arctan(-√3/3) + π

x = arctan(-√3/3) + 2π

Using a calculator, we find that arctan(-√3/3) is approximately -0.5236 radians, so the solutions are:

x ≈ 2.6179 radians, 5.7596 radians, 8.9013 radians

Since we are looking for solutions between 0 and 2π, we can add or subtract multiples of 2π to get:

x ≈ 2.6179 radians, 5.7596 radians, 8.9013 radians, 11.0430 radians, 14.1847 radians, 17.3264 radians

These are the solutions to the equation 5 - (3/5)cot(x) = (25 + √3)/5 between 0 and 2π.

Step-by-step explanation:

Answer:

perseveration

Step-by-step explanation:

The term you are looking for is "perseveration."

The local truncation error incurred in the approximation of y(2.01) using the next term in the corresponding Taylor series is O(0.0001)

We can use the Taylor series method of order three to estimate y(2.01) in one step. Let's first write the Taylor series expansion of y(x) about x=2 up to the third derivative:

[tex]y(x) = y(2) + (x-2)y'(2) + \frac{(x-2)^{2} }{2!} y''(2) + \frac{(x-2)^{3} }{2!} y'''(2) + O((x-2)^{4} )[/tex]

where  [tex]y'(x) = 3x^{2} y(x), y''(x) = 6xy(x) + 3x^{2} y'(x), y'''(x) = 9x^{2} y'(x) + 18xy'(x) + 6x^{2} y''(x).[/tex]

(a) To estimate y(2.01) in one step, we need to evaluate the above expression at x=2.01. Using y(2) = 3 and [tex]y'(2) = 3(2)^{2} (3) = 36[/tex], we get:

[tex]y(2.01) = y(2) + (2.01-2)y'(2) + \frac{(2.01-2)^{2} }{2!} y''(2)[/tex]

[tex]= 3 + 0.01(36) + \frac{(0.01)^{2} }{2!} (6(2)(3) + 3(2)^{2} (3)(3))[/tex]

=3.1089

Therefore, y(2.01) =3.1089.

(b) The local truncation error is given by the next term in the Taylor series expansion, which is O((x-2)⁴) in this case. Evaluating this term at x=2.01, we get:

O((2.01-2)⁴) = O(0.0001)

Therefore, the local truncation error incurred in the approximation of y(2.01) using the next term in the corresponding Taylor series is O(0.0001).

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The housing supply function is given by h(I,R) = a log1 + bR + cR log1. The housing supply responds to changes in I with a rate of a, and to changes in R with a rate of b + c log1.

Based on the given equation, the housing supply (h) is determined by two variables: I and R. The equation shows that h is a function of R, with a log-linear relationship. The variable I only appears as a constant (a) in the equation, so changes in I do not directly affect the supply of houses.
On the other hand, changes in R (or OR, which is the same variable) do affect the supply of houses. Specifically, an increase in R leads to an increase in the supply of houses. The magnitude of this increase depends on the values of b and c in the equation.
To see this, we can take the partial derivative of h with respect to R:
dh/dR = b + cR/(ln(10))
This equation tells us how much the housing supply changes in response to a change in R. The derivative is positive (i.e. the supply increases) as long as c is positive. The larger c is, the greater the increase in supply for a given increase in R.
Therefore, the correct answer is:
b + cR/(ln(10))

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The distance between the foot of the ladder and the foot of the building is 2.6 ft

Part 1) The general form of a circle is given as x²+y² +4x - 12y + 4 = 0.

(a)What are the coordinates of the center of the circle?

(b)What is the length of the radius of the circle?

x²+y² +4x - 12y + 4 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(x²+4x)+(y²- 12y)=-4

Complete the square twice. Remember to balance the equation by adding the same constants to each side

(x²+4x+4)+(y²- 12y+36)=-4+4+36

Rewrite as perfect squares

(x+2)²+(y-6)²=36--------> (x+2)²+(y-6)²=6²

center (-2,6)

radius 6

the answer Part a) is

the center is the point (-2,6)

the answer Part b) is

the radius is 6

Part 2)

see the picture attached N 1 to better understand the problem

we know that

sin ∅=opposite side angle ∅/hypotenuse

opposite side angle ∅=9.2 ft

hypotenuse=10 ft

so

sin ∅=9.2/10-----> 0.92

∅=arc sin (0.92)------> ∅=66.93°-----> ∅=67°

the answer Part a) is

67°

Part b)

see the picture attached N 2 to better understand the problem

cos 75=adjacent side angle 75/hypotenuse

adjacent side angle 75=AC

hypotenuse=10 ft

so

cos 75=AC/10---------> AC=10*cos 75----> AC=2.59 ft----> AC=2.6 ft

the answer Part B) is

The distance between the foot of the ladder and the foot of the building is 2.6 ft

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The probability of a randomly selected hair salon rating having at most 2 stars is 0.44,

The probability of having more than 3 stars is 0.47.

We have,
(a) To find the probability that the randomly selected hair salon rating has at most 2 stars, we need to add the probabilities for 1-star and 2-star ratings.

Based on the provided probability distribution,

P(X=1) = 0.25 and P(X=2) = 0.19.

The probability of a rating having at most 2 stars.
P(X ≤ 2) = P(X=1) + P(X=2)

= 0.25 + 0.19

= 0.44

(b)

To find the probability that the randomly selected hair salon rating has more than 3 stars, we need to add the probabilities for 4-star and 5-star ratings.

Based on the provided probability distribution, P(X=4) = 0.21 and P(X=5) = 0.26.

The probability of a rating having more than 3 stars.
P(X > 3) = P(X=4) + P(X=5)

= 0.21 + 0.26

= 0.47

Thus,
The probability of a randomly selected hair salon rating having at most 2 stars is 0.44, and the probability of having more than 3 stars is 0.47.

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The A value from the given equation is CE = (io^0.118)/10.

To find the A value from the equation 0.242 = log of  CRnx CF ICF Rn= 1.334X10 CE=?, we need to isolate the variable A on one side of the equation. We can start by using the definition of logarithms, which states that log of CRnx CF ICF Rn= A is equivalent to CRnx CF ICF Rn= io^A.

Substituting the given values, we get:

1.334X10 CE= io^A

Taking the logarithm of both sides with base 10, we get:

logio (1.334X10 CE) = logio (io^A)

Using the logarithmic identity logio (a^b) = b*logio (a), we can simplify the left-hand side to:

logio (1.334X10 CE) = logio (1.334) + logio (10 CE)

Now we can substitute the given value of logio CRnx CF ICF Rn= 0.242:

0.242 = logio (1.334) + logio (10 CE)

Solving for logio (10 CE), we get:

logio (10 CE) = 0.242 - logio (1.334)

logio (10 CE) = 0.242 - 0.124

logio (10 CE) = 0.118

Finally, we can solve for CE by exponentiating both sides with base 10:

10 CE = io^0.118

CE = (io^0.118)/10

Therefore, the A value from the given equation is CE = (io^0.118)/10.

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The dot product of two vectors u and v is calculated by multiplying their corresponding components and then adding the products together.

Mathematically, it can be expressed as:  u · v = u₁v₁ + u₂v₂ + u₃v₃ (for vectors in 3D space)
Step:1. u = (2,5) and v = (-6,1)
u · v = (2)(-6) + (5)(1) = -12 + 5 = -7
Since the dot product is not equal to zero, u and v are not orthogonal.
Step:2. u = 2i +3j and v= -7i -3j
u · v = (2)(-7) + (3)(-3) = -14 - 9 = -23
Again, the dot product is not zero, so u and v are not orthogonal.
Step:4. u = 4i+6j+8k and v= 7i -9j+ 12k (3D space)
u · v = (4)(7) + (6)(-9) + (8)(12) = 28 - 54 + 96 = 70
Once again, the dot product is not zero, so u and v are not orthogonal.
Therefore, in all three cases, the dot product of the given vectors is not zero, which means that they are not orthogonal.

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The simplified expression is (8x² - 7x - 4) / [(4x + 1)(x - 1)(4x - 1)].

We have,

To simplify the expression

2(x - 1) / (4x² - 3x - 1) + (x + 2) / (4x² + 7x - 2)

we need to find the least common denominator (LCD) of the two denominators:

(4x² - 3x - 1) and (4x² + 7x - 2).

To find the LCD, we need to factor in both denominators.

We can factor the first denominator as:

4x² - 3x - 1 = (4x + 1)(x - 1)

We can factor the second denominator by using the quadratic formula or by factoring by grouping:

4x² + 7x - 2 = (4x - 1)(x + 2)

Therefore, the LCD is the product of the factors of both denominators, with each factor appearing once at most:

LCD = (4x + 1)(x - 1)(4x - 1)(x + 2)

To get each fraction to have the same denominator, we need to multiply the numerator and denominator of the first fraction by (4x - 1) and the numerator and denominator of the second fraction by (x - 1):

2(x - 1)(4x - 1) / [(4x + 1)(x - 1)(4x - 1)] + (x + 2)(x - 1) / [(4x + 1)(x - 1)(4x - 1)]

Now that both fractions have the same denominator, we can add the numerators and simplify:

[2(x - 1)(4x - 1) + (x + 2)(x - 1)] / [(4x + 1)(x - 1)(4x - 1)]

Multiplying out the numerator and simplifying, we get:

[8x^2 - 7x - 4] / [(4x + 1)(x - 1)(4x - 1)]

Therefore,

The simplified expression is (8x² - 7x - 4) / [(4x + 1)(x - 1)(4x - 1)]

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The additional fact would prove that quadrilateral WXYZ is a parallelogram is M∠Y ≅ m∠W . The option D is correct.

To prove that quadrilateral WXYZ is a parallelogram, we need to show that both pairs of opposite sides are parallel.

Option A, which states that XY=YZ, does not provide information about the parallelism of the sides, and it is not sufficient to prove that WXYZ is a parallelogram. Option B, which states that the sum of angles X and Y is 180 degrees, suggests that WXYZ may be a straight line, but it does not necessarily mean that the opposite sides are parallel.

Option C, which states that YZ=WX, suggests that the opposite sides may be equal in length, but again, it does not necessarily mean that they are parallel. Option D, which states that angle Y is congruent to angle W, provides information about the opposite angles of the quadrilateral, and this is enough to prove that the opposite sides are parallel. This is because in a parallelogram, opposite angles are congruent, and therefore, the fact that M∠Y ≅ m∠W proves that WXYZ is a parallelogram. Option D is the correct answer as it provides sufficient information to prove that WXYZ is a parallelogram.

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For using substraction, in Janice's account balance with beginning of $467 amount, the ending bank balance of his account after some withdraw through checks and ATM is equals to $371.08.

We have Janice's bank balance account data. In Begining bank balance of his account = $467

Amount that she withdrawal through ATM = $30

The 4 checks'amount are the following $16.80, $22.74, $12.38, and $14. We have to determine the her ending bank balance.. We use substraction arithmetic operation for determining the ending bank balance. First we add all withdraw amounts from account to calculate total withdraw. So, total withdraw from account = $16.80+ $22.74 + $12.38 + $14 + $30 = $95.92

Now, the ending bank balance= $467 - $95.92 = $371.08

Hence, required bank balance is $371.08.

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The percentage of people's IQ over 80 is 9.18%, the percentage of people's IQ under 90 is 25.14% and the percentage of people's IQ between 112 and 132 is 8.23%
Then,
a) Over 80:
The z-score for 80 is (80-100)/15 = -1.33
Using a standard normal distribution table , we can evaluate that the area under the normal curve to the right of -1.33 is approximately 0.9082.
Therefore, the percentage of people's IQs that will be over 80 is approximately
(1-0.9082) x 100%
= 9.18%.

b) Under 90:
The z-score for 90 is (90-100)/15 = -0.67
Using a standard normal distribution table, we can evaluate that the area under the normal curve to the left of -0.67 is approximately 0.2514.
Therefore, the percentage of people's IQs that will be under 90 is approximately
0.2514 x 100%
= 25.14%.
c) Between 112 and 132:
The z-score for 112 is (112-100)/15 = 0.8
The z-score for 132 is (132-100)/15 = 2.13
Using a standard normal distribution table, we can calculate that the area under the normal curve between these two z-scores is approximately 0.0823.
Therefore, the percentage of people's IQs that will be between 112 and 132 is approximately
0.0823 x 100%
= 8.23%.
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The volume of the solid generated by revolving the region bounded by the lines and curves about the x-axis is 2π(1 - e⁻¹) cubic units.

To find the volume of the solid generated by revolving the region bounded by the lines and curves about the x-axis, we need to use the method of cylindrical shells.

The volume can be calculated using the following formula:

V = ∫[a,b] 2πx f(x) dx

where a=0, b=1, and f(x) = e^(-x).

Substituting the given values, we get:

[tex]V = \int[0,1] 2\pi x e^{(-x)} dx[/tex]

Using integration by parts, we can solve this integral and get:

[tex]V = 2 \pi[e^{(-x)} - x e^{(-x)}][/tex] from 0 to 1

Simplifying this, we get:

V = 2π(1 - e⁻¹)

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The slope of the graph is 50, and it represents the rate of change of the total cost of the gym membership per month.

To write an equation for C, the total cost of the gym membership, we can use the slope-intercept form of a linear equation, which is y = mx + b. In this case, y represents the total cost, m represents the slope, x represents the number of months, and b represents the y-intercept (the initial cost of joining the gym).

From the graph, we can see that the initial cost of joining the gym is $700 (the y-intercept), and the monthly fee is $50 (the slope of the line connecting the dots). So, the equation for C is:

C = 50t + 700

where t is the number of months.

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The five-number summary for the data set is:

Minimum value = 10

Q1 = 14

Median = 18.5

Q3 = 24

Maximum value = 28.

The box and whisker plot is given.

We have,

To find the five-number summary, we need to first sort the data set in ascending order:

10, 12, 14, 15, 16, 18, 22, 24, 25, 28

Minimum value:

The smallest value in the data set is 10, so this is the minimum value.

Q1 (first quartile):

This is the value that separates the bottom 25% of the data from the top 75%.

To find Q1, we need to find the median of the lower half of the data.

The lower half of the data consists of the values 10, 12, 14, 15, and 16.

The median of these values is 14, so Q1 is 14.

Median (Q2):

This is the value that separates the bottom 50% of the data from the top 50%.

To find the median, we take the average of the two middle values.

The middle values are 18 and 19, so the median is (18+19)/2 = 18.5.

Q3 (third quartile):

This is the value that separates the bottom 75% of the data from the top 25%.

To find Q3, we need to find the median of the upper half of the data.

The upper half of the data consists of the values 22, 24, 25, and 28.

The median of these values is 24, so Q3 is 24.

Maximum value:

The largest value in the data set is 28, so this is the maximum value.

Therefore,

The five-number summary for the data set are minimum value = 10,

Q1 = 14, median = 18.5, Q3 = 24, maximum value = 28.

The box and whisker plot is given.

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The probability that at least one WST111 student is in time for the 7h30 lecture on a Tuesday morning is 0.9961.

1. First, let's find the probability that a randomly selected student is on time for the lecture. Since the probability that a student is late is 0.25, the probability that a student is on time is 1 - 0.25 = 0.75.

2. Now, we need to calculate the probability that all five randomly selected students are late for the lecture. Since punctuality is independent, we can simply multiply each student's probability of being late: 0.25×0.25×0.25×0.25× 0.25 = 0.0009765625.

3. Finally, we want to find the probability that at least one student is on time. To do this, we'll subtract the probability that all students are late from 1:

1 - 0.0009765625 = 0.9961.

So, the probability that at least one WST111 student is in time for the 7h30 lecture on a Tuesday morning is 0.9961.

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The option that shows trigonometric functions of the same angle is:

Option C: cosY = 8 / 17, cotY = 8 / 15, secY = 17 / 8

The three primary trigonometric ratios are:

sin x = opposite/hypotenuse

cos x = adjacent/hypotenuse

tan x = opposite/adjacent

Here,

cosY = 8/17, cotY = 8/15, secY = 17 / 8

We know that in trigonometric ratios that:

cosY = 1 / SecY

Thus:

8 / 17 = 1 / secY

secY = 17 / 8

Now, using pythagoras theorem, we have:

P = √[17² - 8²]

P = 15

Thus:

Cot Y = 8 / 15

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If the solution is indeed n = -2, then step 8 would be unnecessary, and the last line of the justification would be as stated above. The last line of the justification would typically be "Therefore, n = -2 is a solution to the equation 4n + 2 = 2n + 3 and the solution has been verified."

The justification would likely involve the following steps:

Start with the equation 4n + 2 = 2n + 3.

Simplify the equation by subtracting 2n from both sides: 2n + 2 = 3.

Subtract 2 from both sides: 2n = 1.

Divide both sides by 2: n = 1/2.

Check the solution by substituting n = -2 back into the original equation: 4(-2) + 2 = 2(-2) + 3.

Simplify: -8 + 2 = -4 + 3.

Further simplify: -6 = -1.

Since the equation is not true when n = -2, but instead it is true when n = 1/2, the solution of n = -2 is not correct and needs to be revised.

However, if the solution is indeed n = -2, then step 8 would be unnecessary, and the last line of the justification would be as stated above.

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The simplified answer after Simplification of (1/2 - 1/3)(4/5 - 3/4) / (1/2 + 2/3 + 3/4) is 7/36.

To solve this expression, we need to follow the order of operations, which is parentheses, multiplication/division, and addition/subtraction.

First, we simplify the expression inside the parentheses:

(1/2 - 1/3)(4/5 - 3/4) = (1/6)(1/5) = 1/30

Next, we add up the denominators in the denominator of the entire expression:

1/2 + 2/3 + 3/4 = 6/12 + 8/12 + 9/12 = 23/12

Finally, we divide the simplified expression inside the parentheses by the fraction in the denominator:

(1/30) / (23/12) = (1/30) x (12/23) = 4/230 = 2/115 = 7/36

Therefore, the simplified answer is 7/36.

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To find the coordinates of the endpoints of the image A'B' (A9B9) after dilation of AB by a scale factor of 2 centered at (3,5), follow these steps:

Step 1: Use the given scale factor (2) and center of dilation (3,5).

Step 2: Apply the dilation formula to the coordinates of the original points A and B. The formula for dilation with scale factor k centered at (h,k) is:

A'(x', y') = (h + k(x - h), k + k(y - k))

Step 3: Substitute the given options for A9 and B9 into the dilation formula and check which pair of coordinates satisfy the formula.

After applying the formula, it is determined that the coordinates of the endpoints of the image A9B9 after dilation with a scale factor of 2 centered at (3,5) are:

A9(21, 6) and B9(7, 4).

Option (2) is correct.

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