What else would need to be congruent to show that ABC=AXYZ by SAS?
A
B
OA. ZB=LY
B. BC = YZ
OC. C= LZ
OD. AC = XZ
с
X
Z
Given:
AB XY
BC=YZ

Answer:

f(x)=5/(x-6)

Step-by-step explanation:

f(x)=(5x-5)/(x^2-7x+6)

f(x)=[5(x-1)]/[(x-1)(x-6)]

f(x)=5/(x-6)

Answer:

Step-by-step explanation:

To format and solve the equation "f(x) - 4" with the given function "f(x) = 2x + 1," we substitute the function into the equation and solve for x. Here's how it can be done:

f(x) - 4 = 2x + 1 - 4

Simplifying further:

f(x) - 4 = 2x - 3

To answer the question "f(4)" using the function f(x) = 2x + 1, we substitute x = 4 into the function:

f(4) = 2(4) + 1

Simplifying further:

f(4) = 8 + 1

f(4) = 9

Therefore, the value of f(4) is 9 when using the function f(x) = 2x + 1.

The area of the segment is 9( π-2) units²

The area of a figure is the number of unit squares that cover the surface of a closed figure.

A segment is the area occupied by a chord and an arc. A segment can be a major segment or minor segment.

Area of segment = area of sector - area of triangle

area of sector = 90/360 × πr²

= 1/4 × π × 36

= 9π

area of triangle = 1/2bh

= 1/2 × 6²

= 18

area of segment = 9π -18

= 9( π -2) units²

therefore the area of the segment is 9(π-2) units²

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Step-by-step explanation:

The coordinates and vertices

which reflected over the y- axis are

r(-2,0) , s(2,-3) , and t(2,3).

Rounding to the nearest tenth of a meter, the distance from marker A to marker B (side AB) is approximately 5.7 meters.

To find the distance from marker A to marker B in triangle ABC, we need to calculate the length of side AB.

The distance between two points (x1, y1) and (x2, y2) can be found using the distance formula:

d = √[tex]((x2 - x1)^2 + (y2 - y1)^2)[/tex]

In this case, let's assume that the coordinates of marker A are (x1, y1) and the coordinates of marker B are (x2, y2).

Given that the coordinates of marker A are not provided in the question, we would need the coordinates of both marker A and marker B to calculate the distance between them accurately.

Once we have the coordinates of marker A and marker B, we can substitute them into the distance formula to calculate the distance AB.

For example, if the coordinates of marker A are (x1, y1) = (3, 4) and the coordinates of marker B are (x2, y2) = (7, 8), we can calculate the distance as follows:

d = [tex]\sqrt{((7 - 3)^2 + (8 - 4)^2)}[/tex]

= √[tex](4^2 + 4^2)[/tex]

= √(16 + 16)

= √32

≈ 5.66

Rounding to the nearest tenth of a meter, the distance from marker A to marker B (side AB) is approximately 5.7 meters.

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The solution to the equation [tex]3^x + 3^(4-2x) = 1 + 3^(4-x) is x = 2.[/tex]

To solve the equation [tex]3^x + 3^(4-2x) = 1 + 3^(4-x),[/tex] we can simplify the equation and then apply some algebraic techniques to isolate the variable x.

First, let's simplify the equation step by step:

1. Notice that [tex]3^(4-2x)[/tex] can be rewritten as[tex](3^4) / (3^2x)[/tex], using the property of exponentiation.

2. Now the equation becomes 3[tex]^x + (81 / 9^x) = 1 + 3^(4-x).[/tex]

3. We can simplify further by multiplying both sides of the equation by 9^x to eliminate the denominators.

  This gives us [tex]3^x * 9^x + 81 = 9^x + 3^(4-x) * 9^x.[/tex]

4. Simplifying the terms, we have [tex](3*9)^x + 81 = 9^x + (3*9)^(4-x).[/tex]

  Now we have [tex](27)^x + 81 = 9^x + (27)^(4-x).[/tex]

5. Notice that [tex](27)^x and (27)^(4-x)[/tex] have the same base, so we can set the exponents equal to each other.

  This gives us x = 4 - x.

6. Simplifying the equation, we get 2x = 4.

7. Dividing both sides of the equation by 2, we have x = 2.

Therefore, the solution to the equation [tex]3^x + 3^(4-2x) = 1 + 3^(4-x) is x = 2.[/tex]

Using simple language, we simplified the equation step by step and isolated the variable x by setting the exponents equal to each other. The final solution is x = 2.

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Answer:

Mean = 59.1, Median = 61

(there might have been a mistake in calculation (a lot of numbers!))

Step-by-step explanation:

The sample size is 40,

Now, the formula for the mean is,

Mean = (sum of the sample values)/(sample size)

so we get,

[tex]Mean = (49+63+78+22+41+39+75+61+63+65+58+37+45+52+81+75+78+72+68+59+72+85+63+61+75+39+41+48+59+55+61+25+61+52+58+71+75+82+49+51)/40\\Mean = 2364/40\\Mean = 59.1[/tex]

To find the median, we have to sort the list in ascending (or descending)order,

we get the list,

22,25,37,39,39,41,41,45,48,49,

49,51,52, 52,55,58, 58, 59, 59, 61,

61, 61, 61, 63, 63, 63, 65, 68, 71, 72,

72, 75, 75, 75, 75, 78, 78, 81, 82, 85

Now, we have to find the median,

since there are 40 values, we divide by 2 to get, 40/2 = 20

now, to find the median, we takethe average of the values above and below this value,

[tex]Median = ((n/2+1)th \ value + (n/2)th \ value )/2\\where, \ the\ (n/2)th \ value \ is,\\n/2 = (total \ number \ of \ samples) /2\\n/2=40/2\\(n/2)th = 20\\Hence\ the (n/2)th \ value \ is \ the \ 20th \ value[/tex]

And the (n+1)th value is the 21st value

Now,

The ((n/2)+1)th value is 61 and the nth value is 61, so the median is,

Median = (61+61)/2

Median = 61

Answer:   there are 20 people who claimed to be neither CDO partisans nor ANC partisans.

Step-by-step explanation:

To determine the number of people who are none of these two parties, we need to subtract the total number of people who claimed to be CDO partisans, ANC partisans, and those who claimed to be both from the total number of people surveyed.

Total surveyed people = 130

Number claiming to be CDO partisans = 80

Number claiming to be ANC partisans = 60

Number claiming to be both ANC and CDO = 30

To find the number of people who are none of these two parties, we can calculate it as follows:

None of these two parties = Total surveyed people - (CDO partisans + ANC partisans - Both ANC and CDO)

None of these two parties = 130 - (80 + 60 - 30)

None of these two parties = 130 - 110

None of these two parties = 20

(i) Correcting the figures to 3 decimal places:

-0.005627 ≈ -0.006

0.0056 ≈ 0.006

-0.0049327 ≈ -0.005

0.0049 ≈ 0.005

-0.001342 ≈ -0.001

(ii) Correcting the figures to 3 significant figures:

-0.005627 ≈ -0.00563

0.0056 ≈ 0.00560

-0.0049327 ≈ -0.00493

0.0049 ≈ 0.00490

-0.001342 ≈ -0.00134

(i) When rounding to 3 decimal places, we look at the fourth decimal place and round the figure accordingly. If the fourth decimal place is 5 or above, we round up the preceding third decimal place. If the fourth decimal place is less than 5, we simply drop it.

(ii) When rounding to 3 significant figures, we consider the digit in the third significant figure. If the digit in the fourth significant figure is 5 or above, we round up the preceding third significant figure. If the digit in the fourth significant figure is less than 5, we simply drop it.

Rounding to the correct number of decimal places or significant figures is important to maintain precision and accuracy in calculations and measurements. It helps to ensure that the reported values are appropriate for the level of precision required in a given context.

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Two sets that contain exactly the same elements are called "equal sets" or "identical sets."

In set theory, the concept of equality between sets is defined by the axiom of extensionality, which states that two sets are equal if and only if they have the same elements.

To illustrate this concept, let's consider two sets: Set A and Set B. If every element of Set A is also an element of Set B, and vice versa, then we say that Set A and Set B are equal sets. In other words, the sets have the exact same elements, regardless of their order or repetition.

For example, if Set A = {1, 2, 3} and Set B = {3, 2, 1}, we can observe that both sets contain the same elements, even though the order of the elements is different. Therefore, Set A is equal to Set B.

In summary, equal sets refer to two sets that possess exactly the same elements, without considering the order or repetition of the elements. The concept of equality is fundamental in set theory and forms the basis for various operations and theorems in mathematics.

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Answer:

I wish you good luck in finding your answer

Part A: The interest earned if the interest is compounded quarterly is $2,768.40.

Part B: The interest earned if the interest is compounded continuously is $2,695.92.

Part C: The difference in the amount of interest earned is approximately $72.48.

Part A: To calculate the interest earned when the interest is compounded quarterly, we can use the formula for compound interest:

[tex]A = P(1 + r/n)^(^n^t^)[/tex]

Where:

A = the final account balance

P = the principal amount (initial investment)

r = the annual interest rate (4.75% or 0.0475 as a decimal)

n = the number of times the interest is compounded per year (4 times for quarterly)

t = the number of years (42 months divided by 12 to convert to years)

Plugging in the values:

A = $15,000(1 + 0.0475/4)^(4 * (42/12))

A = $15,000(1.011875)^(14)

A ≈ $15,000(1.18456005)

A ≈ $17,768.40

The interest earned is the difference between the final account balance and the principal amount:

Interest earned = $17,768.40 - $15,000

Interest earned ≈ $2,768.40

Part B: When the interest is compounded continuously, we can use the formula:

[tex]A = Pe^(^r^t^)[/tex]

Where:

A = the final account balance

P = the principal amount (initial investment)

e = the mathematical constant approximately equal to 2.71828

r = the annual interest rate (4.75% or 0.0475 as a decimal)

t = the number of years (42 months divided by 12 to convert to years)

Plugging in the values:

A = $15,000 * e^(0.0475 * 42/12)

A ≈ $15,000 * e^(0.165625)

A ≈ $15,000 * 1.179727849

A ≈ $17,695.92

The interest earned is the difference between the final account balance and the principal amount:

Interest earned = $17,695.92 - $15,000

Interest earned ≈ $2,695.92

Part C: Comparing the interest earned for each account, we find that the interest earned when the interest is compounded quarterly is approximately $2,768.40, while the interest earned when the interest is compounded continuously is approximately $2,695.92.

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Answer:

Step-by-step explanation:

Step 1.   Determine the dollar amount of the markup

          175 - 79 = 96

Step 2:   Divide the markup Amount by the Cost

          96/79 = 1.215

Step 3:   Multiply by 100 and add the % sign

           1.215 x 100 = 121.5%

There are 70 ways a person can order a two-course meal from the given restaurant.

To determine the number of ways a person can order a two-course meal from a restaurant that offers 10 appetizers and 7 main courses, we can use the concept of combinations.

First, we need to select one appetizer from the 10 available options.

This can be done in 10 different ways.

Next, we need to select one main course from the 7 available options. This can be done in 7 different ways.

Since the two courses are independent choices, we can multiply the number of options for each course to find the total number of combinations.

Therefore, the number of ways a person can order a two-course meal is 10 [tex]\times[/tex] 7 = 70.

So, there are 70 ways a person can order a two-course meal from the given restaurant.

It's important to note that this calculation assumes that a person can choose any combination of appetizer and main course.

If there are any restrictions or limitations on the choices, the number of combinations may vary.

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The expression that represents the statement "Divide the difference of 27 and 3 by the difference of 16 and 4" is (27 - 3) / (16 - 4), which simplifies to 2.

The statement "Divide the difference of 27 and 3 by the difference of 16 and 4" can be represented using algebraic expressions.

To find the difference between two numbers, we subtract one from the other. So, the difference of 27 and 3 is 27 - 3, which can be expressed as (27 - 3). Similarly, the difference of 16 and 4 is 16 - 4, which can be expressed as (16 - 4).

Now, we need to divide the difference of 27 and 3 by the difference of 16 and 4. We can use the division operator (/) to represent the division operation.

Therefore, the expression that represents the given statement is:

(27 - 3) / (16 - 4)

Simplifying this expression further, we have:

24 / 12

The difference of 27 and 3 is 24, and the difference of 16 and 4 is 12. So, the expression simplifies to:

2

Hence, the expression (27 - 3) / (16 - 4) is equivalent to 2.

In summary, the expression that represents the statement "Divide the difference of 27 and 3 by the difference of 16 and 4" is (27 - 3) / (16 - 4), which simplifies to 2.

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Answer:

(x^3+2x-1) * (x^4-x^3+3)

Step-by-step explanation:

To simplify this expression, we can multiply each term in the first expression by each term in the second expression and combine like terms:

(x^3)(x^4) + (x^3)(-x^3) + (x^3)(3) + (2x)(x^4) + (2x)(-x^3) + (2x)(3) + (-1)(x^4) + (-1)(-x^3) + (-1)*(3)

Simplifying further:

x^7 - x^6 + 3x^3 + 2x^5 - 2x^4 + 6x - x^4 + x^3 - 3

Combining like terms:

x^7 - x^6 + 2x^5 - 3x^4 + 4x^3 + 6x - 3

Therefore, the expression representing the product of (x^3+2x-1) and (x^4-x^3+3) is x^7 - x^6 + 2x^5 - 3x^4 + 4x^3 + 6x - 3.

Answer:

See attachment for the graph of the hyperbola.

Step-by-step explanation:

Given equation:

[tex](x-7)^2-\dfrac{(y-4)^2}{9}=1[/tex]

As the x²-term of the given equation is positive, the transverse axis is horizontal, and so the hyperbola is horizontal (opening left and right). Note, if the y²-term was positive, the hyperbola would have been vertical.

The general formula for a horizontal hyperbola (opening left and right) is:

[tex]\boxed{\begin{minipage}{7.4 cm}\underline{Standard equation of a horizontal hyperbola}\\\\$\dfrac{(x-h)^2}{a^2}-\dfrac{(y-k)^2}{b^2}=1$\\\\where:\\\phantom{ww}$\bullet$ $(h,k)$ is the center.\\ \phantom{ww}$\bullet$ $(h\pm a, k)$ are the vertices.\\\phantom{ww}$\bullet$ $(h\pm c, k)$ are the foci where $c^2=a^2+b^2.$\\\phantom{ww}$\bullet$ $y=\pm \dfrac{b}{a}(x-h)+k$ are the asymptotes.\\\end{minipage}}[/tex]

Comparing the given equation with the standard equation:

To find the value of c, use c² = a² + b²:

[tex]\begin{aligned}c^2&=a^2+b^2\\c^2&=1+9\\c^2&=10\\c&=\sqrt{10}\end{aligned}[/tex]

The center is (h, k). Therefore, the center is (7, 4).

The formula for the loci is (h±c, k). Therefore:

[tex]\begin{aligned}\textsf{Loci}&=(h \pm c, k)\\&=(7 \pm \sqrt{10}, 4)\\&=(7- \sqrt{10}, 4)\;\;\textsf{and}\;\;(7 +\sqrt{10}, 4)\end{aligned}[/tex]

The formula for the vertices is (h±a, k). Therefore:

[tex]\begin{aligned}\textsf{Vertices}&=(h \pm a, k)\\&=(7 \pm 1, 4)\\&=(6, 4)\;\;\textsf{and}\;\;(8, 4)\end{aligned}[/tex]

The asymptotes are:

[tex]\begin{aligned}y&=\pm \dfrac{b}{a}(x-h)+k\\\\y&=\pm \dfrac{3}{1}(x-7)+4\\\\y&=\pm 3(x-7)+4\\\\\implies y&=3x-17\\\implies y&=-3x+25\end{aligned}[/tex]

Therefore:

The graph of the hyperbola (x - 7)² - (y - 4)²/9 = 1 is attached below

The graph of a hyperbola is a curve that consists of two separate branches, each resembling a symmetrical curve. The general equation for a hyperbola in standard form is:

[(x - h)² / a²] - [(y - k)² / b²] = 1

The center of the hyperbola is represented by the coordinates (h, k). The parameters a and b determine the size and shape of the hyperbola.

Based on the standard form equation, there are two types of hyperbolas:

1. Horizontal Hyperbola:

When the major axis is parallel to the x-axis, the hyperbola is horizontal. The equation in this case is:

[(x - h)² / a²] - [(y - k)² / b²] = 1

The graph of a horizontal hyperbola opens left and right. The branches are symmetric about the x-axis and the center (h, k) is the midpoint between the branches.

2. Vertical Hyperbola:

When the major axis is parallel to the y-axis, the hyperbola is vertical. The equation in this case is:

[(y - k)² / b²] - [(x - h)² / a²] = 1

The graph of a vertical hyperbola opens up and down. The branches are symmetric about the y-axis and the center (h, k) is the midpoint between the branches.

The graph of the given hyperbola is attached below.

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The parametric equation of the line passing through P1(2, 4, -3) and P(3, -1, 1) is:

x = 2 + t

y = 4 - 5t

z = -3 + 4t

To find the parametric equation of the line passing through points P1(2, 4, -3) and P(3, -1, 1), we can use the vector equation of a line.

Let's denote the direction vector of the line as d = (a, b, c). Since the line passes through P1 and P, the vector between these two points can be used as the direction vector.

d = P - P1 = (3, -1, 1) - (2, 4, -3) = (1, -5, 4)

Now, we can express the parametric equation of the line as follows:

x = x0 + at

y = y0 + bt

z = z0 + ct

where (x0, y0, z0) is a point on the line and (a, b, c) is the direction vector.

Let's choose P1(2, 4, -3) as the point on the line. Substituting the values, we get:

x = 2 + t

y = 4 - 5t

z = -3 + 4t

Therefore, the parametric equation of the line passing through P1(2, 4, -3) and P(3, -1, 1) is:

x = 2 + t

y = 4 - 5t

z = -3 + 4t

where t is a parameter that varies along the line.

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Answer: Nope

Step-by-step explanation:

No, receiving a 20% discount followed by an additional 30% discount does not result in a total discount of 50%.

To understand why, let's consider an example with an item priced at $100.

If there is a 20% discount applied initially, the price of the item would be reduced by 20%, which is $100 * 0.20 = $20. So the new price after the first discount would be $100 - $20 = $80.

Now, if there is an additional 30% discount applied to the $80 price, the discount would be calculated based on the new price. The 30% discount would be $80 * 0.30 = $24. So the final price after both discounts would be $80 - $24 = $56.

Comparing the final price of $56 to the original price of $100, we can see that the total discount is $100 - $56 = $44.

Therefore, the total discount received is $44 out of the original price of $100, which is a discount of 44%, not 50%.

Hence, receiving a 20% discount followed by an additional 30% discount does not result in a total discount of 50%.

The value of x is 5625 when √x + √y=138 and x-y=1656.

To solve for x using the given equations, we will use the method of substitution. Let's go through the steps:

Start with the equation √x + √y = 138.

We want to express y in terms of x, so solve for y in terms of x by isolating √y:

√y = 138 - √x

Square both sides of the equation to eliminate the square root:

(√y)² = (138 - √x)²

y = (138 - √x)²

Now, substitute the expression for y in the second equation x - y = 1656:

x - (138 - √x)² = 1656

Expand the squared term:

x - (138² - 2 * 138 * √x + (√x)²) = 1656

Simplify the equation further:

x - (19044 - 276 * √x + x) = 1656

Combine like terms and rearrange the equation:

-19044 + 276 * √x = 1656

Move the constant term to the other side:

276 * √x = 20700

Divide both sides of the equation by 276 to solve for √x:

√x = 20700 / 276

√x = 75

Square both sides to solve for x:

x = (√x)²

x = 75²

x = 5625

Therefore, the value of x is 5625.

By substituting this value of x back into the original equations, we can verify that √x + √y = 138 and x - y = 1656 hold true.

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Answer:

Relative frequency of selecting a 2 = 8/50 = 0.16 = 16%

Step-by-step explanation:

You are selecting a random number between 1 and 5, and you perform this task 50 times.

Out of these 50 times, the outcome "2" appears 8 times.

Therefore the relative frequency of selecting the number 2 is:

f(2) = 8/50 = 0.16 which is 16%

Answer:

It's 7.81

Step-by-step explanation:

Answer:  Choice A

The single squiggly symbol means "similar".

A squiggly line over top an equals sign is the congruence symbol.

The evaluation of the constraints with regards to the production of the polo and t-shirts, and to maximize the profit, using linear programming indicates that we get;

a. x = The number of polo shirts produced, y = The number of t-shirts produced

b. The inequalities representing the constraints are;

2·x + y ≤ 84

x + 2·y ≤ 106

x ≤ 36

x ≥ 0, y ≥ 0

c. P = 30·x + 22·y

d. Please find attached the graph of the feasible region

To maximize profit, the company should produce;

21 polo shirts and 43 t-shirts

Linear programming is a method used for optimizing (maximizing or minimizing a value) operations with some specified constraints.

a. The details indicates that the question is related to linear programming. Let x represent the number of polo shirt produced, and let y represent the number of t-shirts produced.

x = The number of polo shirt produced

y = The number of t-shirts produced

b) The constraints are;

Pattern and cutting section; 2·x + y ≤ 84

Sewing section; x + 2·y ≤ 106

Sales constraints; x ≤ 36

The values of x and y are non negative, numbers, therefore;

x ≥ 0, y ≥ 0

c) The objective of the company is to maximize profit, P, therefore, the objective function is; P = 30·x + 22·y

d) The graph can be plotted from the constraint inequalities, by making y the subject in the inequalities that includes both x and y as follows;

2·x + y ≤ 84, therefore; y ≤ 84 - 2·x

x + 2·y ≤ 106, therefore; y ≤ 53 - x/2

x ≤ 36

Please find attached the graph of the inequalities, showing the feasible region which is the polygon with boundaries which are the lines representing the constraints.

The objective function evaluated at the vertices of the feasible region indicates that we get;

[tex]\begin{tabular}{ | l | l | c | }\cline{1-3}(x, y)& 30\cdot x + 22\cdot y & P(\$) \\ \cline{1-3}(0, 53 & 30\times 0 + 22\times 53 & 1166 \\\cline{1-3}(21, 42.5 & 30\times 21 + 22\times 42.5 & 1565 \\\cline{1-3}(32, 12) & 30\times 36 + 22\times 12 & 1344 \\\cline{1-3}(36, 0) & 30\times 36 + 22\times 0 & 1080 \\\cline{1-3}(0, 0) & 30\times 0 + 22\times 0& 0 \\\cline{1-3}\end{tabular}[/tex]

The feasible region and the objective function indicates that the values of x and y that maximizes the profit is; (x, y)  = (21, 42.5)

Therefore, to maximize profit, the number of polo and t-shirts the company should produce are 21, and 42.5 ≈ 43 respectively.

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The linear rule for the sequence is f(n) = 7/20 + 3/20(n - 1)

From the question, we have the following parameters that can be used in our computation:

35/100,5/10,65/100

In the above sequence, we can see that 15/100 is added to the previous term to get the new term

This means that

First term, a = 35/100

Common difference, d = 15/100

The nth term is then represented as

f(n) = a + (n - 1) * d

Substitute the known values in the above equation, so, we have the following representation

f(n) = 35/100 + 15/100(n - 1)

So, we have

f(n) = 7/20 + 3/20(n - 1)

Hence, the explicit rule is f(n) = 7/20 + 3/20(n - 1)

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The distance from point A to point B is approximately 16.64 units. None of the given options (A, B, C, D) match this value exactly, so there seems to be an error in the options provided.

To find the distance from point A to point B, we can use the distance formula in Euclidean geometry. The distance formula between two points (x1, y1) and (x2, y2) is given by:

distance = sqrt((x2 - x1)^2 + (y2 - y1)^2)

In this case, point A is (-8, -3) and point B is (6, 6). Plugging these values into the distance formula, we have:

distance = sqrt((6 - (-8))^2 + (6 - (-3))^2)

= sqrt((6 + 8)^2 + (6 + 3)^2)

= sqrt(14^2 + 9^2)

= sqrt(196 + 81)

= sqrt(277)

≈ 16.64

Thus, the distance between points A and B is roughly 16.64 units. Since none of the available options (A, B, C, or D) exactly match this value, there appears to be a problem with the options.

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The length of BD is 22.

In the given scenario, let's consider the following information.

AD = 8

AE = 6

EC is 12 more than BD.

To find the length of BD, we can utilize the Intercepted Arcs Theorem, which states that when two secants intersect outside a circle, the measure of an intercepted arc formed by those secants is equal to half the difference of the measures of the intercepted angles.

From the given information, we know that AD = 8 and AE = 6.

Since these are the lengths of the secants, we can use them to calculate the intercepted arcs.

First, let's find the intercepted arc corresponding to AD:

Intercepted Arc ADB = 2 [tex]\times[/tex] AD = 2 [tex]\times[/tex] 8 = 16

Similarly, we can find the intercepted arc corresponding to AE:

Intercepted Arc AEC = 2 [tex]\times[/tex] AE = 2 [tex]\times[/tex] 6 = 12

Now, we know that EC is 12 more than BD.

Let's assume the length of BD as x.

BD + 12 = EC

Now, let's consider the intercepted arcs theorem:

Intercepted Arc ADB - Intercepted Arc AEC = Intercepted Angle B - Intercepted Angle C

16 - 12 = Angle B - Angle C

4 = Angle B - Angle C.

Since Angle B and Angle C are vertical angles, they are congruent:

Angle B = Angle C.

Therefore, we can say:

4 = Angle B - Angle B

4 = 0

However, we have reached an inconsistency here.

The equation does not hold true, indicating that the given information is not consistent or there may be an error in the problem statement.

As a result, we cannot determine the length of BD based on the given information.

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The values of L and M in the triangle displayed are 55 and 60 respectively.

The value of angle L can be obtained thus :

125 + L = 180 (sum of angles in a triangle)

L = 180 - 125 = 55°

B.

The value of L can be calculated thus:

55 + (2x - 10) + 65 = 180 (sum of internal angles of a triangle)

120 + 2x - 10 = 180

110+2x = 180

2x = 180-110

x = 35

M = 2(35) -10 = 60°

Therefore, L = 55 and M = 60.

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The total volume of the dill spears is 425 cm³.

To find the total volume of the dill spears, we can subtract the volume of the pickle juice from the volume of the jar.

The jar is in the shape of a cylinder with a base area of 45 cm² and a height of 13 cm. Therefore, the volume of the jar can be calculated using the formula:

Volume of the jar = base area * height

Volume of the jar = 45 cm² * 13 cm

Volume of the jar = 585 cm³

Now, we know that the measuring cup collected 160 cm³ of pickle juice. So, we subtract this volume from the total volume of the jar to find the volume of the dill spears.

Volume of the dill spears = Volume of the jar - Volume of the pickle juice

Volume of the dill spears = 585 cm³ - 160 cm³

Volume of the dill spears = 425 cm³

Therefore, the total volume of the dill spears is 425 cm³.

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