Answer:
if the object does not weighs it would stay on top of the surface of the water but if the object has weight it would sink
Five gas molegules are choosen at random are found to have speed of 500,600,700, 800 and 900 m/s. Find the rms speed. Is it ghe same as average speed
Answer:
Explanation:
The rms speed:
Vrms = (500 + 600 + 700 + 800 + 900) / 5 = 700 m/s
Why does a power plant generator produce alternating current and not direct
current?
A power plant generator does easily generate alternating current and not direct
current simply because the AC current is far cheaper to produce.
Why is a power plant generator cheaper to generate alternating current?The simple reason why a power plant generator generate an alternating current cheaply is because the plant loses a very few energy when electricity is being transmitted with it through a long distance. Whereas, the direct current usually, frequently and most of the time loses more energy.
So therefore, we can now deduce from above that it is easy to generate alternating current from a power plant.
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What has to happen with the time to have the smallest force to stop a moving body.
Answer:
You can only stop (or start) your body moving through space if you can cause an external force to be applied to it.
Explanation:
can someone pls help me
Answer:
The first one is the right answer
Explanation:
This is because a period is only completed when there is the completion of only one oscillation
how long (in seconds) would it take a Narwhal to accelerate from rest down a 30 meter long ravine with an acceleration of 2.2 m/s^2
The time (in seconds) it will take the Narwhal to accelerate from rest down a 30 meter long ravine is 5.2 s
How do I determine the time?We know from equations of motion that distance, acceleration and time are related according to the following formula:
s = ut + ½at²
Where
s is the distanceu is the initial velocitya is the accelerationt is the timeWith the above formula, we can obtain the time as follow:
Initial velocity (u) = 0 m/sDistance (s) = 30 mAcceleration(a) = 2.2 m/s²Time (t) = ?s = ut + 1/2at²
30 = (0 × t) + (½ × 2.2 × t²)
30 = 0 + (1.1 × t²)
30 = 1.1 × t²
Divide both side by 1.1
t² = 30 / 1.1
Take the square root of both side
t = √(30 / 1.1)
t = 5.2 s
Thus, the time taken is 5.2 s
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What is the total mechanical energy of a 3 kg object traveling at 7 m/s if its potential energy is 42 J? (1 point)
247.8 J
115.5 J
31.5 J
73.5 J
A 3 kilogram object traveling at 7 m/s and possessing a 42 J potential energy has a mechanical energy of 115.5 J.
How much mechanical energy does the thing possess?Performing a specific task results in the accumulation of mechanical energy. It is the total of an object's potential energy and kinetic energy. It is stated as;
Potential and kinetic energy are the components of mechanical energy.
Given the information in the query;
The object's mass is 3 kg.
The object's speed is 7 m/s.
Object's potential energy is 42 J.
Calculate the object's kinetic energy.
Kinetic energy = 1/2 × mass × ( velocity )²
Insert the specified values.
Kinetic energy is = 1/2 x 3 kg x 7 m/s2.
Kinetic energy = 0.5 x 3 kg x 49 m2/s2.
Kinetic energy = 73.5 kg/m2/s2.
Kinetic energy = 73.5 J.
Now, the object's mechanical energy will be;
Potential energy plus kinetic energy equals mechanical energy.
Put the values in.
Mechanical energy = 42J + 73.5J
Mechanical energy = 115.5 J.
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Sleeping with an even a small amount of light can cause negative changes to peoples metabolism. for example, a studies shown that those who slept in dim light had more trouble _______ the next morning.
A) processing sugar
B) maintaining posture
C) slowing down their heart rate
D) avoiding devices like smart phones
PLS HELP 50 PO IN TS
Answer: A
Explanation: The research mentions both the insulin resistance and the increased heart rate. But one thin I noticed is that the increased heart rate happens at night while they sleep, but the question asks for the next morning, so A.
There’s really no exact citation found but this is as close as I can get you.
A car is traveling 20m/s around a right hand curve. The passenger is at a radius of 5m and the driver is at radius of 6m. What is the centripetal acceleration felt by each?
The exact centripetal acceleration experienced by passenger ∝ₙ and driver ∝ⁿ is 80m/s² & 66.67m/s² respectively.
Mathematically , Centripetal acceleration ∝= v²/r
In the given question velocity will be same for passengers and driver because of common frame.
But the radius is different since distance from each points of frame to the Centre of road will vary. so their centripetal acceleration will differ.
∝= v²/r using this we can find out the exact centripetal acceleration experienced by passenger ∝ₙ and driver ∝ⁿ
∝ₙ= 20²/5= 80m/s²
∝ⁿ=20²/6= 66.67m/s²
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Astronauts in training are subjected to extreme acceleration forces by the centripental forces in againt centrifuge the radius of the centrifuge appriximately 5m calculate the approximate centripetal force on an astronaut of mass 80Kg if the centrifuge rotates once every 2s
The approximate centripetal force on an astronaut of mass 80Kg if the centrifuge rotates once every 2s is 3.94 KN
ac = v² / r
v = 2 π r / T
ac = Centripetal acceleration
v = Linear / Tangential velocity
T = Time period
r = Radius
r = 5 m
T = 2 s
v = 2 * 3.14 * 5 / 2
v = 15.7 m / s
ac = 15.7 * 15.7 / 5
ac = 49.298 m / s²
Fc = m ac
m = Mass
m = 80 kg
Fc = 80 * 49.298
Fc = 3943.8 N
Fc = 3.94 KN
Therefore, the approximate centripetal force on the astronaut is 3.94 KN
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1. What is the definition of work done?
2. What is the unit for energy?
3.
The engine of Tilly's car exerts a force of 750N. How much
energy would be transferred by the engine if the car moved a
distance of 100m?
4.
Rehana is holding an object of weight 50N is raised by a height
of 200cm. What is the work done in raising the object?
5.
700J of energy is used by Ikram to move a distance of 10m.
What is the force exerted by the person as they walk the
distance?
6. Hifza has a weight of 200N. Aymen has a weight of 350N. If
1000) of energy is used to raise each object, which object will
gain the most height?
The combination of a force's constituent acting inside the displacement's direction as well as its magnitude would be known as the work done mostly via force.
1) Work is done when an applied force produces mobility in a body.
Mathematically , Work = Force x displacement
2) Unit for energy is Joule.
3) Energy can be calculated by such as:
Work = F s
750 x 100 = 75000J would be transferred by engine if car moved a distance of 100m.
4)For the case of Rehana : 200 cm converted to 2m .
again using same concept , W=FS
50 x 2=100J of work done in raising the object.
Energy consumed = 700 J
Distance (Displacement) = 10 m
7) We know work done is also a type of energy which tells the energy consumed by anything in order to move a distance, We know
⇒ Work done = Force × Displacement
⇒ 700 = F × 10
⇒ F = 70 newton
Hence, The force exerted by the person as walked the distance is 70 newton.
6) For the hifza case:- 200N will take more height because it is lighter than 350N so we can do it upward and downward as it is lighter and the energy used is 1000J .
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How fast would the moon need to travel in order to escape the gravitational pull of Earth, if Earth has a mass of 5.98 x 10^24 kg and the distance from Earth to the moon is 3.84 x 10^8 m?
Answer: 14.41*10^2 m/s
Explanation:
let, V be the escape velocity of the moon.
M be the mass of the earth.
r be the distance between the moon and the earth.
G be the universal gravitational constant.
And G = 6.67428*10^-11 m^3kg^-1 s^-2
here, given in the question that
The earth has a mass of 5.98*10^24 kg.
so, M = 5.98*10^24 kg.
And the distance from the earth to the moon is 3.84*10^8 m.
so, r = 3.84*10^8 m.
now, we know,
V = √2GM/r
V = √(2 * 6.67428*10^-11* 5.98 * 10^24 )/ 3.84*10^8
V = √79.82*10^13/3.84*10^8
V = √20.78*10^5
V = 14.41*10^2 m/s
A television uses a current of 1.5A at 120V. The television is used for 2 hours. Calculate
the power used in kW and the energy used in kWh.
Answer:
the power used is 0.18kW and the energy used is 0.36kWh
Explanation:
from power= current × voltage
power= 1.5A × 120V
power= 180W or 0.18kW
energy used = power × time
= 0.18kW ×2h
energy used = 0.36kWh
A detailed graph of angular velocity versus time is shown. What is the angular displacement, in radians, during the time interval from 0.75 s to 14.2 s?
0.116 rad/s is the angular speed in radians, during the time interval from 0.75 s to 14.2 s
ω=Δθ/Δt
Δθ= 90° = 1.571rad
Δt=13.45
ω=1.571/13.45
ω=0.116 rad/s
The rate of change of angular displacement, or the angle a body travels along a circular path, is the definition of angular speed. Calculating angular speed involves dividing the quantity of rotations or revolutions made by a body by the amount of time required. Omega is a Greek letter that represents angular speed. The SI's angular speed unit is rad/s.
As is well known, angular speed is determined by dividing the rate of displacement change by the time. As a result, the angular speed equation is = /t. Despite the procedure stated above, a different and more well-liked formula is used to determine angular speed in competitive testing. As ω = θ/t
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The diagram shows object N placed one on top of object M. M has a mass of 4 kg and N has a mass of 2 kg. Assume that all the contact surfaces are frictionless, what is the acceleration of N when M is
pulled by a force of 20 N?
A. 0 m/s²
B. 4 m/s²
C. 3.3 m/s²
D. 10 m/s²
If N placed one of these on top of item M, the acceleration when M is dragged by a force od 20 N is 10 m/s. N weighs 2 kg, but M is 4 kg in weight.
The correct answer is D
What happens during acceleration?Acceleration is the rate at which the direction and speed of a moving object change over time. Anything is said to be accelerated when it goes straighter and faster or slower. Therefore, even though the speed is constant, travel on a circle increases due to the constant change in direction.
Is a gradual incline good?Slow acceleration can be dangerous as well as unpleasant, especially when entering a busy state road when you must accelerate rapidly to avoid being rear-ended. When you are moving slowly up a slope while driving, acceleration can sometimes be a hassle.
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Two wires are 16 m and 24 m long. The wires are to be cut into pieces of equal length. a) Find the maximum length (in m) of each piece. b) What is the total number of such pieces formed from the two wires?
Answer:
A. The maximum is 8cm. B. 5 pieces of wire.
Explanation:
To find each pieces' length we need to find what can divide both wires = 8cm
A. The maximum is 8cm.
The amount of pieces = 16m/8m = 2 pieces and 24m/8m = 3 pieces. 2 pieces + 3 pieces = 5 pieces of wire.
B. 5 pieces of wire.
Calculate the answer to the correct
number of significant digits.
-3.22
x5.1
You may use a calculator. But remember, not every digit the
calculator gives you is a significant digit!
Enter
The number of significant digits is 6.
What is significant figures?The crucial or important digits that accurately represent the meaning of a certain number are known as the significant figures of that number. 6.658, for instance, has four significant digits. These huge amounts give the numbers accuracy. Additionally, they are known as significant digits.
Given that: -3.22 x 5.1.
The product of -3.22 and 5.1 is 16.442.
In the number 16.442, there have 6 significant figures. Hence, The number of significant digits is 6.
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Two small plastic spheres having positive electrical charges are given. When they are 60.00cm apart, the repulsive force between them has the magnitude 0.250N.calculate the charge on each sphere
Answer:
3.16 × 10‐⁶
Explanation:
through coulomb's law
the force of attraction or repulsion of charges is given by the relation
F = k.q1.q2/r²
where your k = 9 × 10⁹
Answer:
Charge 3.16 mkC microcoulomb
Explanation:
Given:
q₁ = q₂ = q - Electrical charges
r = 60.00 sm = 0.60 m - Distance between charges
F = 0.250 N - Repulsive force between charges
___________________
q - ?
F = k·q₁·q₂ / r² = k·q·q / r² = k·q² / r²
Charge:
q = √ (F·r² / k )
q = r·√ (F / k )
q = 0.60· √ (0.250 / 9·10⁹) ≈ 3.16·10⁻⁶ C or:
q = 3.16 mkC (microcoulomb)
URGENTTTT
Referring to the graph in the section header, what was his displacement between 100 and 300 seconds?
Referring to the graph in the section header, what was the runner's velocity during segment D?
The displacement of the runner according to the graph is obtained as 250 m.
What is the displacement?The term displacement has to do with the distance that is covered in a specified direction. The difference between distance and displacement is that displacement is a vector while distance is a scalar quantity.
Thus we bring the direction into play when we are talking about the displacement of the object. Now we have a graph that shows the displacement of the runner in the vertical axis and then shows the time that is taken in the horizontal axis.
Given the graph as we have it, we can be bale to pick out the following from the graph;
1) Displacement of the runner at 100 s = 500 m
2) Displacement of the runner at 300 s = 750 m
Therefore;
Displacement of the runner between 100 and 300 seconds;
750 m - 500 m = 250 m
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do you believe that doubting is thinking?yes or no then why?
Answer:
yes
Explanation:
Because doubting is thinking something is
wrong
Aside from density, what other information from the table of planetary data can help someone decide if a planet is terrestrial, jovian, or dwarf?
Jovian planets are less dense than terrestrial planets.
The ratio of these two characteristics—an object's mass divided by its volume is that determines its density.The Jovian planets lack solid surfaces, in contrast to the terrestrial planets that make up our inner solar system—Mercury, Venus, Earth, and Mars. They are made mostly of hydrogen and helium instead, with minute amounts of other gases like methane, ammonia, water, and others in their atmospheres.
Terrestrial planets formed from metal and rock-based planetesimals, but they were ultimately too small to hold much of the solar nebula's rich hydrogen and helium gas. The Jovian planets, on the other hand, originated distant from the Sun where there were abundant ices and rocks.
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What is the approximate tangential speed of an object orbiting Earth with a radius of 1.8 × 108 m and a period of 2.2 × 104 s?
The approximate tangential speed of an object orbiting Earth with a radius of 1.8 × 108 m and a period of 2.2 × 104 s is 5.34 m/sec.
What is speed?
The speed of an object is the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.
Given in the question an object orbiting Earth with a radius of 1.8 × 108 m and a period of 2.2 × 104 s, tangential speed is ,
v = [tex]2\pi*r[/tex]/t
v = 2*3.14*1.8*108/2.2*104
v = 5.34 m/sec.
The approximate tangential speed of an object orbiting Earth with a radius of 1.8 × 108 m and a period of 2.2 × 104 s is 5.34 m/sec.
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A feather is dropped onto the surface of the moon. How far will the feather have fallen if it reaches the surface in 9.00 seconds? Given: g on moon = -1.63 meters/second2
[tex]66.015 \mathrm{~m}[/tex] will the feather have fallen if it reaches the surface in 9.00 seconds.
Given:
[tex]$$\begin{aligned}&t=9 \mathrm{~s} \\&a=1.63 \mathrm{~m} / \mathrm{s}^2\end{aligned}$$[/tex]
The distance traveled by the feather onto the surface of the moon can be computed using the following equation:
[tex]d=\frac{1}{2} a t^2=(0.5)\left(1.63 \mathrm{~m} / \mathrm{s}^2\right)(9 \mathrm{~s})^2=66.015 \mathrm{~m}$$[/tex]
Kinematics in classical mechanics explains the motion of a specific item in a system. We're looking at the motion of a feather on the moon's surface.
Kinematics is the study of mechanical points, bodies, and systems in their motion without regard for their related physical qualities or the forces acting on them. The discipline is known as geometry of motion, and it mathematically describes these motions using algebra.
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A crowbar of 200 cm long is pivoted about to its other end to displace a load of 600 N. 0.5 m Calculate MA, VR and efficiency of the crowbar.
The mechanical advantage of the crow bar is 3 while the velocity ratio is 4. The efficiency of the machine is 75%.
What is the efficiency of the crow bar?We know that a machine is any device that can be used to make work a lot much easier. Thus, the machine is the object that could make less effort to be applied in making a greater work to be done as we can see in this case we have here.
From the question, the pieces of information that we can get are;
Distance moved by Effort = 200 cm
Distance moved by load = 0.5 m or 50 cm
Velocity ratio = Distance moved by Effort/Distance moved by load
= 200 cm /50 cm
= 4
Mechanical advantage is found to be; Load/Effort
= 600 N/200 N
= 3
Efficiency = Mechanical advantage/ Velocity ratio * 100/1
= 6/4 * 100/1
=3/4 * 100/1
= 75%
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Lucy is cruising through space in her new spaceship. As she coasts along, a tiny spacebug drifts into her path and bounces off the window.
Consider several statements concerning this scenario. Evaluate each statement according to the law of momentum conservation and match it to the appropriate category.
TRUE: The total change in momentum for this interaction is zero.
FALSE: The change in the space bug's momentum is greater than the change in the spaceship's momentum.
UNDETERMINED: If the space bug had stuck to the spaceship instead of bouncing off, momentum would not have been conserved for this interaction.
Two protons (charge q= 1.602·10-19 C) move at the same speed v= 1.4 ·106 m/s in opposite directions parallel to the x-axis. At the instant when they are at the same x-position, the proton moving in the negative direction is at distance r= 0.7 mm in the positive y-direction with respect to the one moving in the positive direction.
What is the magnitude of the magnetic field at the point of the proton moving in the negative direction?
B=
What is the magnetic force direction experienced by the proton moving in the negative direction?
FB=
(a) The magnitude of the magnetic field at the point of the proton moving in the negative direction is 2.1 x 10⁻⁹ T.
(b) The magnetic force direction experienced by the proton moving in the negative direction is 4.71 x 10⁻²² N.
What is the magnetic field due to the proton?
The magnitude of the magnetic field at the point of the proton moving in the negative direction is calculated as follows;
F = qvB = kq²/r²
qvB = kq²/r²
B = kq²/qvr²
B = kq/vr²
where;
k is coulomb's constantq is the magnitude of charge of the protonsr is the distance between the protonsv is the speed of the protonB = (9 x 10⁹ x 1.602 x 10⁻¹⁹) / (1.4 x 10⁶ x 0.7 x 10⁻³ x 0.7 x 10⁻³ )
B = 2.1 x 10⁻⁹ T
The magnetic force direction experienced by the proton moving in the negative direction is calculated as follows;
F = qvB
F = 1.602 x 10⁻¹⁹ x 1.4 x 10⁶ x 2.1 x 10⁻⁹
F = 4.71 x 10⁻²² N.
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Planets A and B have the same mass, but planet
is nait the
Which statement correctly explains the
weight you would experience on each
planet?
O A. You would weigh less on planet A because the distance between
you and the planet's center of gravity would be smaller.
•
B. You would weigh the same on both planets because the masses
of the planets are the same.
• C.
You would weigh more on planet A because the distance between
you and the planet's of center of gravity would be smaller.
both planets because your mass
D. You would weigh the same on
would be the same on both.
b
Statement is accurate C. You would weight more on planet A because the distance between you and the planet's of center of gravity would be smaller.
What is the proper statement's justification?You would weigh less on planet A due to a closer proximity to the planet's center of gravity, which is the statement that best represents your weight on each planet.
According to Newton's rule of universal gravitation, "the force of gravity between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distances between them,"
Given that weight is a function of both mass and gravity, objects on planets with stronger gravitational pull will have heavier masses.
The weight will be lighter since there is less space between the individual and the planet's center.
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A 15 kg dog running at 4 m/s picks up a 1 kg stationary bone and continues to run what is the speed of the dog as it runs with its newfound treasure?
0
2.5
3.75
5.83
A bouncy ball has 30 J of kinetic energy before it collides with the floor. If the collision is perfectly elastic, what is the kinetic energy of the bouncy ball after it collides with the floor?
0
30
65
200
Answer: (1) C, (2) B
Explanation: I took the test, but to solve question 1 use the inelastic collision formula m1v1+m2v2 = (m1+m2)v2 to get the answer. Question 2 is b because it states that the ball is perfectly elastic as it collides with the floor. A perfectly elastic collision is when objects collide and no net energy is lost, hence the bouncy ball still has 30 J worth of kinetic energy.
The speed of the dog as it runs with its newfound treasure is 3.75 m/sec.
The kinetic energy of the bouncy ball after it collides with floor is 30 J.
What is speed?The speed of an object is the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.
According to the given in question,
a.) Using inelastic collision formula
[tex]m_1v_1+m_2v_2 = (m_1+m_2)v_2[/tex]
[tex]v_2[/tex] = 60/16 m/sec = 3.75 m/sec
b.) Because it states that the ball is perfectly elastic as it collides with the floor. A perfectly elastic collision is when objects collide and no net energy is lost, hence the bouncy ball still has 30 J worth of kinetic energy.
The speed of the dog as it runs with its newfound treasure is 3.75 m/sec.
The kinetic energy of the bouncy ball after it collides with floor is 30 J.
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Which of the following is not one of the rules that must be followed regarding animal research? A. Animal research must have a clear scientific purpose. B. Animal research can acquire its animals illegally. C. Animal research must provide humane care and housing. D. Animal research must ensure the least amount of suffering possible. Please select the best answer from the choices provided A B C D
On research on animals they must given proper care and housing. And the purpose of the research must have a scientific reason. Thus option B is correct.
What is animal research?Animal research includes various scientific investigation on animals such as testing various doses of some drugs, effect of various chemicals, level of toxicity of some compounds etc.
According to the research ethics, no animals can be used to conduct any unscientific works. There must be a scientific purpose which is very important to conduct any animal research.
If any animals irrespective of its nature,it must be provided proper care, food and housing. No harmful things must be there which make them more suffering. Hence, option B is correct.
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For one length of wire the potential difference across the wire was 1.68 V The current in the wire was 0.70 A calculate the resistance of the of this length of wire  
For one length of wire the potential difference across the wire was 1.68 V . The current in the wire was 0.70 A . The resistance of the of this length of wire will be 2.4 ohm
using ohm's law
V = IR
I = current
R = resistance
R = V/I
= 1.68 / 0.70 = 2.4 ohm
The resistance of the of this length of wire will be 2.4 ohm
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A .50 kg mass attached to an ideal spring of spring constant 80N/c oscillate on horizontal frictionless surface , the mechenical energy is .12j , the greatest energy from y to x is
The greatest energy or the greatest extension from its equilibrium positions is equal to 0.12 J.
What is mechanical energy?Mechanical energy is the sum of potential energy and kinetic energy that is used to do work. Mechanical energy defines the energy of a system because of its motion or position.
The total mechanical energy is conserved as we know the energy can neither be created nor destroyed. The mechanical energy of a system can only be changed from one form to another whenever the forces used to do work are conservative in nature.
The energy is stored in the form of potential energy in a compressed string. If the elastic potential energy is changed into kinetic energy as it is used to accelerate the mass.
The total mechanical energy required to compress the spring is the maximum amount of elastic potential energy stored in the spring. The greatest energy of the spring will be at the maximum displacement. Therefore, the spring will have the greatest potential energy at equilibrium positions equal to 0.12 J.
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