What information is needed to calculate the gravitational force of an object? (1 point)
the mass of the two objects
O the distance between the two objects
the mass of the object and the planet's gravitational acceleration
O the mass of the object subtracted from the distance between the object and the planet's core
Answers
Answer:
C
Explanation:
the mass of the object and the planet’s gravitational acceleration
Answer:
1)the mass of the object and the planet’s gravitational acceleration
2)2.6 times less force
3)The Earth has a greater gravitational attraction than the Moon.
4)980 N
5)The force would need to be greater, so they would not perform as well.
I did it and have a 5/5 100%
Related Questions
A cyclist passes a race check point at +5.5m/s and then accelerates at a constant rate of +0.55m/s2. The cyclist forgot to check in at the check point, and after 20.0s turns around to head back. How far did the cyclist move from the check point to the point of turning back?
Answers
The cyclist has moved 115.5 meters from the check point to the point of turning back.
As, we can see, the acceleration is constant,
We can use equation of motion,
S = ut + 1/2at²
Where s is the displacement,
u is the initial velocity,
t is the time taken,
a is the acceleration,
In the question it is given,
Initial velocity is 5.5m/s,
Acceleration is 0.55m/s²,
Time taken is 20 seconds,
Here, S is the distance between the cyclist's check point and the returning point,
Putting all the values,
S = 5.5x20 + 1/2x0.55x20
S = 110 + 5.5
S = 115.5 meters.
Hence, the distance between the check point and returning point is 115.5 meters.
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1
A manufacturer of garden syringes is testing a new range of
plastic syringes with variable size nozzles. The nozzles can be
removed and replaced with another nozzle of a different size.
The syringe used in these tests is shown in Figure 1.
Figure 1
2
3
4
piston
This is the method used:
1 Attach a 0.5 mm diameter nozzle onto the syringe.
Fill the syringe with 150 ml of water.
Press the piston into the syringe.
Measure the distance the water flows from the end
of the nozzle.
nozzle
5
Records the results in a table.
6 Repeat with other sizes of nozzle.
Name a piece of apparatus that could be used to take
measurements in these tests.
Answers
figure 3
would be the answer
The length of a vector represents what :TimeMagnitude Distance Direction
Answers
Vector quantities can be said to be physical quantities that have a number of units(magnitude) and direction.
Vector quantities include the following: Velocity, torque, displacement.
The length of a vector can be said to be the magnitude.
The length of a vector represents the magnitude and the direction of the quantity is the direction which the vector is pointing.
The magnitude of a vector is the length of the vector.
The magnitude is denoted as |v|.
ANSWER:
Magnitude.
A person weighing 490 Newtons stands on a scale in an elevator. The elevator slows down at -2.2 m/s^2 as it reaches the proper floor. What does the scale read?
Answers
The scale would read 490 Newtons because that is the force that the person is exerting on the scale. The acceleration of the elevator does not affect the reading on the scale.
What is newton?
The International System of Units' (Symbol: N) unit of force is the newton (SI). The force that causes a mass of one kilogramme to accelerate by one metre per second. Per second is known as 1 kgm/s². It bears Isaac Newton's name in honour of his contributions to classical mechanics, particularly Newton's second rule of motion. A newton is equal to 1 kg/m² (it is a derived unit which is defined in terms of the SI base units). As a result, one newton is the force required to accelerate one kilogramme of mass at a rate of one metre per square second per second per second.
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1. You are viewing a bug under a magnifying glass. If the focal length of the glass is 5cm and thebug is placed 2cm from the glass, how many times bigger does the bug appears to be?
Answers
Given:
The focal length of the magnifying glass is f = 5 cm
The object distance is u = -2 cm
Required:
The magnification of the bug.
Explanation:
First, we need to find the image distance using the lens formula
The image distance will be
[tex]\begin{gathered} \frac{1}{v}-\frac{1}{u}=\frac{1}{f} \\ \frac{1}{v}=\frac{1}{f}+\frac{1}{u} \\ =\frac{1}{5}+\frac{1}{-2} \\ v=-\frac{10}{3}\text{ cm} \\ =-3.33\text{ cm} \end{gathered}[/tex]The magnification can be calculated as
[tex]\begin{gathered} m\text{ = }\frac{v}{u} \\ =\frac{-10}{3}\times\frac{1}{-2} \\ =\text{ 1.67 } \end{gathered}[/tex]Thus, the magnification of the bug is 1.67.
Final Answer: The bug appears 1.67 times bigger.
What is the difference between the conservation of mechanical energy and the no conservation of mechanical energy?
Answers
Conservation of mechanical energy only holds in a frictionless environment where all collisions are perfectly elastic. It shows that the sum of the kinetic and potential energies of an isolated system becomes a time-independent constant.
Energy conservation states that the sum of all energies not only kinetic and potential but also heat chemical energy etc. in an isolated system is constant. The former is a special case of the latter, and the latter is a universal law, but it is often inapplicable because it must account for all of the observable universes.
According to the law of conservation of mechanical energy the total mechanical energy of the system is conserved. That is, energy is neither created nor destroyed. The internal transformation from one form to another is possible only if the forces acting on the system are of a conservative nature. Mechanical energy is not conserved unless non-conservative forces are acting as friction and other dissipative forces directly convert work or ME into thermal energy.
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An 825-kg cannon rests on a frictionless surface and fires a 1.12-kg projectile at 124 meters per second to the right. What is the velocity of the cannon immediately after the projectile is fired?(a) 0.124 m/s to the left. (b) 0.152 m/s to the left.(c) 0.168 m/s to the left.(d) 0.174 m/s to the left.
Answers
Given,
Mass of the cannon, m₁=825 kg
Mass of the projectile, m₂=1.12 kg
The velocity of the projectile, v₂=124 m/s
According to the law of conservation of momentum, the momentum of the projectile fired should be equal to the momentum of the cannon.
i.e.,
[tex]m_1v_1=m_2v_2[/tex]Therefore the velocity of the cannon is given by,
[tex]v_1=\frac{m_2v_2}{m_1}[/tex]On substituting the known values in the above equation,
[tex]v_1=\frac{1.12\times124}{825}=0.168\text{ m/s}[/tex]Therefore the velocity of the cannon immediately after the projectile is shot is 0.168 m/s
Speeding up slowing down, and going around curves are all examples of what
Answers
Speeding up slowing down, and going around curves are all examples of acceleration .
What is acceleration ?A definition of acceleration is the speed at which velocity varies with respect to time.
Since acceleration has both a magnitude and a direction, it is a vector quantity. Additionally, it is the first derivative of velocity with respect to time or the second derivative of position with respect to time.
The acceleration is given by the formula ,
a = v/t
where , a =acceleration
v = velocity
t = time
the unit of acceleration is m/s² .
What is average acceleration ?The overall change in velocity during the specified interval divided by the total amount of time required for the change is the definition of average acceleration over a particular period of time. It is represented as for a specific amount of time.
a = Δv/Δt
What is instantaneous acceleration ?The definition of instantaneous acceleration is the ratio of velocity change during a specified period of time such that the period of time ends.
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A gust of wind blows an apple from a tree. As the apple falls, the force of gravity on the apple is 9.13 N downward, and the force of the wind on the apple is 1.31 N to the right. What is the magnitude of the net external force on the apple? Answer in units of N.
Answers
Answer: See the diagram,from the vevtor addition we can say,net force acting on the apple is =
√
2.25
2
+
1.05
2
+
2
⋅
2.25
⋅
1.05
cos
90
=
2.48
N
And,this resultant force makes an angle of
tan
−
1
(
1.05
2.25
)
or,
25
degrees w.r.t vertical
The construction of ship is based on ----------.A. Archimedes' principleB. Newton's lawC. Joule's law
Answers
A. Archimedes principle.
Archimedes' principle states that a body that is completely or partially submerged in a fluid is acted upon by an upward force, called buoyant force, the magnitude of which is equal to the weight of the fluid displaced.
From the principle, we can say that, if the weight of water displaced when the sip enters the water is at least equal to the weight of the ship, then the ship will float.
Thus the correct answer is option A.
. dv/dt = a and dx/dt = v(t) where a is constant.Find v(t) in terms of v(0), and a.a.b. Find x(t) in terms of x(0), v(0) and a.
Answers
Given:
[tex]\begin{gathered} \frac{dv}{dt}=a \\ \frac{dx}{dt}=v \end{gathered}[/tex]a is a constant
To find:
(a) v(t) in terms of v(0), and a
(b) x(t) in terms of x(0), v(0) and a
Explanation:
(a) We can write,
[tex]dv=adt[/tex]Integrating both sides we can write,
[tex]\begin{gathered} \int_{v(0)}^{v(t)}dv=\int_0^tadt \\ v(t)-v(0)=at \\ v(t)=v(0)+at \end{gathered}[/tex]Hence, the velocity is,
[tex]v(t)=v(0)+at[/tex](b)
We can also write,
[tex]\begin{gathered} \frac{dx}{dt}=v(t) \\ dx=v(t)dt \end{gathered}[/tex]Integrating both sides we get,
[tex]\begin{gathered} \int_{x(0)}^{x(t)}dx=\int_0^tv(t)dt \\ \int_{x(0)}^{x(t)}dx=\int_0^t[v(0)+at]dt \\ x(t)-x(0)=v(0)t+\frac{1}{2}at^2 \\ x(t)=x(0)+v(0)t+\frac{1}{2}at^2 \end{gathered}[/tex]Hence,
[tex]x(t)=x(0)+v(0)t+\frac{1}{2}at^2[/tex]When a sound wave bends around a barrier, so that you can still hear thesound even though you cannot see the source, the sound wave hasundergone:O A. diffraction.O B. compression.C. refraction.D. reflectionSUBMIT
Answers
Diffraction
Explnation":The bending of waves around obstacle in its path is called diffraction.
When a sound wave bends around a barrier whose dimensinn is lesser than or equal to its wavelength, this phenomenon is referred to as diffraction.
The sound can be heard even though the source of the sound cannot be seen. e
A car will skid to halt at a uniform rate of -9.4 m/s^2. If you measure skid marks that are 34 m long, with what speed was the car going just before the driver slammed the brakes?
Answers
The speed with which the car going just before the driver slammed the brakes is 25.28 m / s, if the car skids to halt at a uniform rate of -9.4 m/s^2.
v² = u² + 2 a s
v = Final velocity
u = Initial velocity
a = Acceleration
s = Displacement
v = 0
a = - 9.4 m / s²
s = 34 m
0 = u² + ( 2 * - 9.4 * 34 )
u² = 639.2
u = 25.28 m / s
Deceleration is the slowing down of an object. It can be negative acceleration or positive acceleration. Deceleration is negative if the object moves in positive direction and it is positive if the object moves in negative direction.
Therefore, the speed with which the car going just before the driver slammed the brakes is 25.28 m / s
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You are interested in retrieving a souvenir from a shipwreck located 115 feet below the water. The path of your dive is modeled by the equation y = 0.05x2 - 4x - 38. Assuming you can hold your breath for the duration of the dive, will you be able to retrieve your souvenir? why?
Answers
In order to find out if we will be able to retrieve the souvenir, let's use y = -115 (negative because it's below the water) in the equation and calculate the value of x.
If there is at least one real solution, we will be able to retrieve the souvenir.
To solve this quadratic equation, let's use the quadratic formula:
[tex]\begin{gathered} y=0.05x^2-4x-38 \\ -115=0.05x^2-4x-38 \\ 0.05x^2-4x-38+115=0 \\ 0.05x^2-4x+77=0 \\ a=0.05,b=-4,c=77 \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ x_1=\frac{-(-4)+\sqrt[]{(-4)^2-4\cdot0.05\cdot77}_{}}{2\cdot0.05} \\ x_1=\frac{4+\sqrt[]{16-15.4}_{}}{0.1} \\ x_1=\frac{4+0.77}{0.1}=47.7 \\ x_2=\frac{4-0.77}{0.1}=32.3 \end{gathered}[/tex]Since there are real solutions for x, the answer is YES.
Which picture correctly shows the path of the reflected light ray given an object inside the focal point?
Answers
The reflective surface of a concave mirror is curved inward and away from the light source. Concave mirrors focus light inward to a single focal point.
picture B correctly shows the path of the reflected light ray given an object inside the focal point.
What is concave mirror?The reflective surface of a concave mirror is curved inward and away from the light source. Concave mirrors focus light inward to a single focal point. In contrast to convex mirrors, the image formed by a concave mirror changes depending on the distance between the object and the mirror.Concave mirrors are widely used as reflectors in automobile and motor vehicle headlights, torchlights, railway engines, and so on. The light source is placed at the focal point of the mirror, so that after reflection, the light rays travel over a large distance as parallel high-intensity light beams.To learn more about : Concave mirrors
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A 1500 kg car, moving at a speed of 20 m/s comes to a halt. How much work was done by the brakes?
Answers
Word done by brakes: -300,000J
Explanation:
Data:
mass of car : m = 1,500 kg
initial velocity of car: v1 = 20 m/s
final velocity of car: v2 = 0 m/s (car at halt)
kinetic energy at v1 : k1 = ?
kinetic energy at v2 : k2 = ?
Formula:
[tex]k\text{ = }\frac{1}{2}\cdot\text{ m }\cdot v^2_1[/tex][tex]\begin{gathered} k1\text{ = }\frac{1}{2}\cdot\text{ 1500}\cdot20 \\ k1\text{ = 300,000 J} \end{gathered}[/tex][tex]\begin{gathered} k2\text{ = }\frac{1}{2}\cdot1500\cdot0 \\ k2\text{ = 0 J} \end{gathered}[/tex][tex]\begin{gathered} \text{Force done by brakes:} \\ k2\text{ - k1 = 0 - 300000 = -300,000 J} \end{gathered}[/tex]Calculate the energy stored in the stretched wire. With an extension of 0.30mm a steel wire with a length of 4.0m and a cross sectional area of 2.0x 10^6m*
Answers
Given data,
Change in length,
[tex]\Delta L=0.\text{30 mm}[/tex]Length of the steel wire,
[tex]L=4.0\text{ m}[/tex]Area,
[tex]A=2.0\times10^{-6}m^2[/tex]Young modulus,
[tex]\text{young modulus=2}.1\times10^{11}\text{ pa}[/tex]Calculate the strain in the wire,
[tex]\begin{gathered} \text{Strain}=\frac{\Delta L}{L} \\ Strain=\frac{0.30\times10^{-3}^{}\text{ m}}{\text{4.}0\text{ m}} \\ Strain=0.075\times10^{-3}\text{ m} \end{gathered}[/tex]Calculate the stress in the wire,
[tex]\begin{gathered} \text{Stress}=young\text{ modulus}\times strain \\ \text{Stress}=2.1\times10^{11}\times0.075\times10^{-3} \\ \text{Stress}=0.1575\times10^8Nm^{-2} \end{gathered}[/tex]Calculate the volume of the wire,
[tex]\begin{gathered} V=2\times10^{-6}\times4 \\ V=8\times10^{-6}m^3 \end{gathered}[/tex]Calculate the elastic potential energy stored.
[tex]\begin{gathered} U=\frac{1}{2}\times stress\times strain\times\text{volume} \\ U=\frac{1}{2}\times0.1575\times10^{8\times}0.075\times10^{-3}\times\text{8}\times10^{-6} \\ U=0.004725\text{ J} \end{gathered}[/tex](ii) The car accelerates for 6.05.
The velocity of the car increases from, 15 m/s to 24 m/s.
Calculate the acceleration of the car,
18
Answers
Answer:
1.5 m/s²
Explanation:
Acceleration a is defined as Δv/Δt
where
Δv = change in velocity
Δt = change in time
Here Δv = 24 - 15= 9 m/s
Δt = 6 secs
So a = 9/6 = 1.5 m/s²
What does the word kinetic mean?A. MotionB. At restC. GravityD. Potential
Answers
Given:
The word 'kinetic'
To find:
The meaning of the word
Explanation:
The word kinetic is related to the movement of any object.
Hence, the word kinetic means Motion.
A penny is dropped from a building and it takes 7.00 seconds to hit the ground. a) How tall is the building in meters?
Answers
The pen's final speed before it touches the earth is 68.6 meters per second.
What is the pen's impact velocity as it lands on the ground?
Simply said, velocity is the rate of motion of an object in a specific direction.
Using the initial motion equation
v = u + gt
where g is the acceleration caused by gravity (g = 9.8m/s2), v is the end velocity, u is the beginning velocity, t is the passing of time, and
Given the information in the query;
Prior to the drop, the pen was initially at rest (starting velocity u = 0; elapsed time t = 7.00s).
Final speed v = ?
Input the variables into the formula and solve for v to get the pen's final velocity before it reaches the ground.
v = u + gt
v = 0 + ( 9.8m/s² × 7.00s )
v = 9.8m/s² × 7.00s
v = 68.6m/s
The final speed is 68.6 meters per second as a result.
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A wave period 10ms travels through a medium. The graph shows the variation of particle displacement with distance for the wave.
What is the average speed of a particle in the
medium during one cycle?
Answers
A wave period 10ms travels through a medium. The graph shows the variation of particle displacement with distance for the wave. The average speed of a particle in the medium during one cycle is (v)= 20 m/s.
What is velocity?The velocity is a physics term that means a matter that covers a distance in a particular time. its a vector quantity. It can be measured in m/s or cm/s.
How can we calculate the velocity of the wave?To calculate the average velocity we are using the formula is,
v=d/t
Here we are given,
According to the picture the wave start from +4.0 displacement and goes decreasing at -4.0 and then comes back at +4.0 and completes the full cycle and complete the amount of distance is (d)= 20cm = 0.2m
The period of the wave is (t)= 10ms = 10*10⁻³ s
We have to calculate the average speed of a particle in the medium during one cycle= v m/s.
Now we put the values in the above equation we get,
v=d/t
Or, v= 0.2/ 10*10⁻³
Or, v= 20 m/s
So from the calculation we can say that, The average speed of a particle in the medium during one cycle is (v)=20 m/s.
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A student increases the temperature of a 457 cm3 balloon from 270 K to 585 K.Assuming constant pressure, what should the new volume of the balloon be?Round your answer to one decimal place.
Answers
Given:
The initial volume of the balloon, V₁=457 cm³=457×10⁻⁶ m³
The initial temperature of the balloon, T₁=270 K
The final temperature of the balloon, T₂=585 K
To find:
The new volume of the balloon.
Explanation:
From Charle's law,
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]Where V₂ is the new volume of the balloon.
On substituting the known values,
[tex]\begin{gathered} \frac{457\times10^{-6}}{270}=\frac{V_2}{585} \\ \Rightarrow V_2=\frac{457\times10^{-6}}{270}\times585 \\ =990\times10^{-6}\text{ m}^3 \\ =990\text{ cm}^3 \end{gathered}[/tex]Final answer:
Thus the new volume of the balloon is 990 cm³
What is the volume of a cube whose side is 10 cm?1) 10–3 m32) 10 m33) 102 m34) 103 m3
Answers
Given data:
* The side of the cube is 10 cm.
Solution:
The volume of the cube is,
[tex]V=a^3[/tex]where a is the side of cube,
Substituting the known values
[tex]\begin{gathered} V=(10\times10^{-2})^3 \\ V=(10^{-1})^3 \\ V=10^{-3}m^3 \end{gathered}[/tex]Thus, first option is the correct answer.
The force diagram shown here describes the forces that external objects (the surface andEarth) exert on a woman (in this scenario, the force diagram does not change with time). Describe three different types of motion of the woman that are consistent with the force diagram.
Answers
The three different motions are;
The upward motion of the woman is constantThe downward motion of the woman is also constantThe horizontal motion of the woman is zero.What is force diagram?
Force diagram is a pictorial or graphical illustration of different forces acting on object.
In this given question, there two forces acting on the woman as depicted in the force diagram.
The first force is surface force (Fs)The second force is force of Earth (FE)In the given force diagram, the woman is in equilibrium, this implies that the surface force and the Earth force are equal.
The three different types of motion of the woman that are consistent with the force diagram include the following;
The upward motion of the woman is constantThe downward motion of the woman is also constantThe horizontal motion of the woman is zero since there is no horizontal force on the woman.Learn more about force diagram here: https://brainly.com/question/3624253
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Why does this graph have a positive slope through the first 4.5 seconds or so and then approximately zero slope till roughly 11.5 seconds?
Answers
The slope of the graphical curve in terms of change in variable along y-axis and the change in the variable along the x-axis is,
[tex]\text{slope=}\frac{Change\text{ in force of tension}}{\text{Time}}[/tex]The change in force of tension in terms of final and its initial value is,
[tex]\text{Change in force= Final value of force - Initial value of force}[/tex]As the value of force is increasing for the first 4.5 seconds.
Thus, the final value of force of is more than the initial value of force.
The change in force for the first 4.5 seconds is,
[tex]\text{change in force > 0}[/tex]Thus, the slope of the curve for the first 4.5 seconds is,
[tex]\text{Slope > 0}[/tex]Hence, the slope is positive for first 4.5 seconds.
For the further time till 11.5 seconds,
There is no change in the value of force which means the final value of force is equal to the initial value of force.
The change in force is,
[tex]\text{change in force = 0}[/tex]Hence, the slope of the c
A crate resting on a horizontal floor (s = 0.6, k = 0.11 ) has a horizontal force F = 82 Newtons applied to the right. This applied force is the maximum possible force for which the crate does not begin to slide. If you applied this same force after the crate is already sliding, what would be the resulting acceleration (in meters/second2)?
Answers
Force static = [tex]m_{s}n[/tex]
[tex]S_{2}[/tex] = 0.6 x N
N = 82/0.6 = 136 . 67N
[tex]m_{k}[/tex] = 0.11
N - 136.67 N
Kinetic = [tex]m_{k}N[/tex]
= 0.11 * 1.36 .67N
= 15. 0337N.
The acceleration of an object is equal to the net force acting on the object divided by its mass. A change in the velocity of an object is an increase or decrease in velocity or a change in direction of motion. Examples of acceleration include falling apples, orbiting the moon, and stopping a car at a traffic light.
Rocket acceleration is based on an applied force known as thrust, an example of Newton's second law of motion. Another example of Newton's second law is that when an object falls from a certain height, it accelerates due to gravity. An initial positive acceleration corresponds to a change in velocity away from zero in the first step. A constant walking motion then produces an acceleration that oscillates from positive to negative averaging to zero.
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Can you give me the answers with being very organized Ans just explain goood
Answers
Explanation
the equation is base ond the Pythagorean theorem,it states that the sum of the squares on the legs of a right triangle is equal to the square on the hypotenuse (the side opposite the right angle)
[tex]a^2+b^2=c^2[/tex]so,
Step 1
if
[tex]undefined[/tex]An object travels east from the starting position of (0, 0). A position versus time graph is shown below.
A Position versus Time graph is shown with y-axis labeled position in centimeters up to 5.0 and x-axis labeled time in seconds up to 8. A line connects points 0, 0 and 4, 4.0. A horizontal line connects points 4, 4.0 and 8, 4.0, through the point 6, 4.0.
This object was moving at a velocity of 1.0 m/s east at the end of 4.0 seconds. Determine the average and instantaneous velocities in m/s at 8.0 seconds.
Average = 1.0 m/s east; instantaneous = 4.0 m/s east
Average = 4.0 m/s east; instantaneous = 8.0 m/s east
Average = 1.0 m/s east; instantaneous = 0 m/s
Average = 0.50 m/s east; instantaneous = 0 m/s
Answers
The average and instantaneous velocities in m/s at 8.0 seconds would be 0.5 m/s and 0 m/s respectively, therefore the correct answer is option D.
What is Velocity?The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object.
As given in the problem, this object was moving at a velocity of 1.0 m/s east at the end of 4.0 seconds.
The average velocity of the object = ( 4 - 0 ) / (8 -0)
The instantaneous velocity of the object = 0 m/s
Thus, the average and instantaneous velocities in m/s at 8.0 seconds would be 0.5 m/s and 0 m/s respectively, therefore the correct answer is option D.
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The energy released when 0.375 kg of uranium are converted into energyis equal toa. 2.35 x 1014 Jb. 3.38 x 1016 JC. 4.53 x 1016 Jd. 7.69 x 1016 j
Answers
Given that the mass of uranium is m = 0.375 kg = 375 g.
We have to find the energy.
First, we need to find the number of moles.
The number of moles can be calculated as
[tex]\begin{gathered} \text{Number of moles =}\frac{Given\text{ mass}}{atomic\text{ mass}} \\ =\frac{375}{235} \\ =1.59\text{ } \end{gathered}[/tex]Next, we have to convert the number of moles into the number of atoms.
The number of atoms will be
[tex]\begin{gathered} \text{Number of atoms=1.59}\times\text{6.022}\times10^{23} \\ =\text{ 9.57}\times10^{23} \end{gathered}[/tex]One atomic mass unit releases 931.5 MeV energy.
The energy can be calculated as
[tex]\begin{gathered} E=\text{ number of atoms}\times931.5MeV\times atomic\text{ mass of uranium} \\ =9.57\times10^{23}\times(931.5\times10^6eV)\times235 \\ =\text{ }2.095\text{ }\times10^{35}eV\text{ } \\ =\text{ 2.095}\times10^{35}\times1.6\times10^{-19}\text{ J} \\ =\text{ 3.35 }\times10^{16\text{ }}J \end{gathered}[/tex]
What is the gravitational for between Maria whose mass is 45 Kg and Jose whosemass is 70 kg if they are 8 m apart from each other? Use G = 6.67X10^-11Nm^2/kg 2.
Answers
Given:
The mass of Maria, m=45 kg
The mass of Jose, M=70 kg
The distance between Maria and Jose, d=8 m
The gravitational constant, G=6.67×10⁻¹¹ Nm²kg⁻²
To find:
The gravitational force of attraction.
Explanation:
From Newton's law of gravitation, the gravitational force of attraction between two objects is proportional to the product of the masses of the objects and inversely proportional to the square of the distance between the objects.
Thus the force between Maria and Jose is given by,
[tex]F=\frac{GMm}{d^2}[/tex]On substituting the known values,
[tex]\begin{gathered} F=\frac{6.67\times10^{-11}\times70\times45}{8^2} \\ =3.3\times10^{-9}\text{ N} \end{gathered}[/tex]Final answer:
Thus the correct answer is option B.
